what is the relation of pressure of a liquid with its depth and density?​

The velocity of the drum after the collision with a lorry of 2000 kg mass is determined as 1,280 km/h.

The velocity of the drum after the collision is calculated by applying the principle of conservation of linear momentum as follows;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

The velocity of the drum after the collision is calculated as;

2000 (50) + 25(0) = 2000(34) + 25v₂

100,000 = 68,000 + 25v₂

25v₂ = 32,000

v₂ = 32,000/25

v₂ = 1,280 km/h

Thus, the final velocity of the drum after the collision is calculated by applying the principle of conservation of linear momentum.

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The velocity of the drum after the collision, given that a 2000 kg lorry moving with a speed of 50 Km/h collides with it, is 1280 Km/h

The following data were obtained from the question given above:

The law of conservation of linear momentum states as follow:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Inputting the given parameters, the velocity of the drum after the collision can be obtain as follow:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(2000 × 50) + (25 × 0) = (2000 × 34) + (25 × v₂)

100000 + 0 = 68000 + 25v₂

Collect like terms

25v₂ = 100000 - 68000

25v₂ = 32000

Divide both sides by 25

v₂ = 32000 / 25

v₂ = 1280 Km/h

Thus, the velocity of the drum after collision is 1280 Km/h

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Answer:

Explanation:

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According to the question the centripetal acceleration of the ball is 20 m/s².

Centripetal acceleration is the acceleration that a body experiences when it is moving in a curved path. It is always directed towards the center of the curve, and its magnitude is equal to the square of the body's velocity divided by the radius of the curve. It is also known as the radial acceleration, since it is directed along the radius of the curve.

The centripetal acceleration of an object in a circular path is given by the equation:

\(a_c\) = v²/r
where a_c is the centripetal acceleration, v is the speed of the object, and r is the radius of the circular path.
In this case, the speed of the ball is 4 m/s, and the radius of the circular path is 0.8 m. Plugging these values into the equation, we get:

\(a_c\) = 4²/0.8 = 16/0.8 = 20 m/s²
Therefore, the centripetal acceleration of the ball is 20 m/s².

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Answer:

D

Explanation:

Answer:

The tensions in \(T_{BC}\) is approximately 4,934.2 lb and the tension in \(T_{BD}\) is approximately  6,035.7 lb

Explanation:

The given information are;

The angle formed by the two rope segments are;

The angle, Φ, formed by rope segment BC with the line AB extended to the center (midpoint) of the ship = 26.0°

The angle, θ, formed by rope segment BD with the line AB extended to the center (midpoint) of the ship = 21.0°

Therefore, we have;

The tension in rope segment BC = \(T_{BC}\)

The tension in rope segment BD = \(T_{BD}\)

The tension in rope segment AB = \(T_{AB}\) = Pulling force of tugboat = 1200 lb

By resolution of forces acting along the line A_F gives;

\(T_{BC}\) × cos(26.0°) + \(T_{BD}\) × cos(21.0°) = \(T_{AB}\) = 1200 lb

\(T_{BC}\) × cos(26.0°) + \(T_{BD}\) × cos(21.0°) = 1200 lb............(1)

Similarly, we have for equilibrium, the sum of the forces acting perpendicular to tow cable = 0, therefore, we have;

\(T_{BC}\) × sin(26.0°) + \(T_{BD}\) × sin(21.0°) = 0...........................(2)

Which gives;

\(T_{BC}\) × sin(26.0°) = - \(T_{BD}\) × sin(21.0°)

\(T_{BC}\) = - \(T_{BD}\) × sin(21.0°)/(sin(26.0°))  ≈ - \(T_{BD}\) × 0.8175

Substituting the value of, \(T_{BC}\), in equation (1), gives;

- \(T_{BD}\) × 0.8175 × cos(26.0°) + \(T_{BD}\) × cos(21.0°) = 1200 lb

- \(T_{BD}\) × 0.7348  + \(T_{BD}\) ×0.9336 = 1200 lb

\(T_{BD}\) ×0.1988 = 1200 lb

\(T_{BD}\) ≈ 1200 lb/0.1988 = 6,035.6938 lb

\(T_{BD}\) ≈ 6,035.6938 lb

\(T_{BC}\) ≈ - \(T_{BD}\) × 0.8175 = 6,035.6938 × 0.8175 = -4934.1733 lb

\(T_{BC}\) ≈ -4934.1733 lb

From which we have;

The tensions in \(T_{BC}\) ≈ -4934.2 lb and  \(T_{BD}\) ≈ 6,035.7 lb.

Answer:

strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.

Explanation:

The lines of magnetic force are drawn so that the density of lines is proportional to the intensity of the magnetic field.

Therefore, the sections where the magnetic field is strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.

here is the answer hope it will help

Given

Mass of the rock, m=20 kg

Energy is , K=36 J

To find

The velocity of the rock

Explanation

Let the velocity be v

The kinetic energy is given by

Conclusion

The velocity is 1.86 m/s

Explanation:

yeah what is your question

Answer:

If the speed of the object varies at all over the interval, the instantaneous velocity will sometimes be greater than the average velocity

Explanation:

The letter that represents the various descriptions is as follows:

5.) Angle of incidence: B

6.) Object: D

7.) Plain mirror:A

8.) Reflection: E

9.) Angle of reflection: C

10.) Normal: F

The law of reflection in a plain mirror states that the angle of reflection is equal to the angle of incidence.

The diagram explains the law of reflection on a plain mirror because it shows the reflection of the object D as E after creating an angle of incidence B on the plane mirror surface A which is equal to the angle of reflection C.

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For a system released from rest at θ = 0° when a constant couple moment M = 100 N.m is applied,  the speed of the 10-kg block is mathematically given as

V=4.33m/s

Generally, the equation for the workdone  is mathematically given as

W=T tehta<dtheta

W=100(90*\pi/180)

W=1.5707*100

W=1.57Nm

The change in potential energy across the pulley

dP=mgh

dp=10*9.81*111.8

dp=10.97J

For the thrid position, potential energy is

dP=mg(0.3)

dP=17.658J

dP'=17.658J-13.125

dP'=-4.532J

For 2nd position dP=0

The change in Kinectic energy across the pulley\

dK.E=0.5mv^2

For 1st

dk.E=0.5m(10)^2

2nd

dK.E=0.5Iw^2

dK.E=0.5(7.5*10^-3)(v^2/0.05)^2

3rd

2nd=3rd

In conclusion,

157.07=dKE+dP.E

157.07=5v^2+ (7.5*10^-3)(v^2/0.05)^2+10.97-4.53

V=4.33m/s

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The magnitude of the resultant vector, representing the actual path of the boat, is approximately 1.42 m/s.

To find the magnitude of the resultant vector, we need to consider the boat's velocity and the velocity of the river. The boat's velocity is given as 0.75 m/s, and the river's velocity is given as 1.2 m/s.

Since the boat is moving in a river, we can think of the boat's velocity as a combination of two velocities: its own velocity and the velocity of the river. The resultant vector represents the actual path of the boat, considering both velocities.

To calculate the resultant vector, we can use vector addition. The magnitude of the resultant vector can be found by taking the square root of the sum of the squares of the boat's velocity and the river's velocity. Mathematically, we have:

Resultant magnitude = √(boat velocity^2 + river velocity^2)

Plugging in the given values, we have:

Resultant magnitude = √(0.75^2 + 1.2^2)

= √(0.5625 + 1.44)

= √2.0025

≈ 1.42 m/s

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Answer:

True

Explanation:

a. The student's final position is 100.5 meters at an angle of 25.2° north of east from her initial position and b. The student would have to head in the direction of 334.8° south of east to return to her initial position.

a. To find the student's final position, we can use vector addition. We can start by breaking each displacement vector into its x- and y-components. First displacement (70 m at 37° north of east),

x-component = 70 cos(37°) = 56.02 m

y-component = 70 sin(37°) = 42.49 m

Second displacement (82 m at 20° south of east),

x-component = 82 cos(-20°) = 78.72 m

y-component = 82 sin(-20°) = -28.12 m

Third displacement (28 m at 30° west of north),

x-component = 28 sin(30°) = 14 m

y-component = 28 cos(30°) = 24.24 m

We can add the x-components and y-components separately to get the total displacement,

x-displacement = 56.02 m + 78.72 m - 14 m = 120.74 m

y-displacement = 42.49 m - 28.12 m + 24.24 m = 38.61 m

The magnitude of the total displacement is,

|d| = √(x-displacement² + y-displacement²)

|d| = √(120.74² + 38.61²)

|d| = 126.0 m.

The direction of the total displacement can be found using the inverse tangent function,

θ = atan(y-displacement/x-displacement)

θ = atan(38.61/120.74)

θ = 17.4° north of east. Therefore, the student's final position is 126.0 m at 17.4° north of east.

b. To return to her initial position, the student would need to walk the same distance and direction as her total displacement but in the opposite direction. The opposite direction of 17.4° north of east is 162.6° south of west. Therefore, she would need to walk 126.0 m at 162.6° south of west to return to her initial position.

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given that there is no second choice i have to go with helium. if you get the second choice i will revise my answer

Answer:

Explanation:

Dude no one can answer this on this app

The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

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Answer:

-48cm

Explanation:

For a convex lens f is +ve and V is +ve

Using the formula 1/f=1/v+1/u

u=12cm and f=16cm

1/16-1/12=1/v

1/v=-1/48

v=-48cm

The displacement of the runner after four seconds is 78.4 m.

We know that in this case, we are dealing with a case of an object that has a motion under gravity. We are told that the road runner an fell straight down off a cliff. The fact that we have been told that the runner just fell down the cliff means that the initial velocity of the runner would have to be taken in this context as zero since the runner was dropped from a height as shown.

Acceleration of the runner (g) = 9.8 m/s^2

Initial velocity of the runner (u) = 0 m/s

Time take (t) = 4 seconds

We then have;

h = ut + 1/2gt^2

If we then know that the initial velocity of the person is zero, then we have;

h = 1/2gt^2

h = 0.5 * 9.8 * (4)^2

h = 78.4 m

The height is 78.4 m.

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Answer:

d = 1,029 m

Explanation:

When the young man shoots the rifle the sound travels in all directions, if the young man is at the same distance from the two walls, as the speed of the wave is constant, he takes the same time to go to the wall and return for which he hears a single echo.

To calculate the distance let's use the uniform motion relationships

        v = d / t

        d = v t

As the speed is constant, the time to reach the wall is the same as it takes to go from the wall to the young man,

         t = to / 2

         t = 6/2

         t = 3 s

         d = 343 3

         d = 1,029 m

Answer:

(a) J = 10560  kg-m/s (b) 251.42 N

Explanation:

Given that,

Mass, m = 4400 kg

Initial speed, u = 5.2 m/s

Final speed, v = 7.6 m/s

Time, t = 42 s

(a) Let J be the impulse exerted on the vehicle. Impuse is equal to the change in momentum such as :

J = m(v-u)

J = 4400 (7.6-5.2)

J = 10560  kg-m/s

(b) Impulse = Force × t

\(F=\dfrac{J}{t}\\\\F=\dfrac{10560}{42}\\F=251.42\ N\)

Hence, this is the required solution.

A substance that gains an electron in a reaction is called as oxidizing agent.

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If you are on 4.16 Chemical Reactions and have 18 questions, then go to the following on Quizlet for further help. Thanks and good luck!

Quizlet - "4.6 Chemical Reactions UT"

h t t p s : / / q u i z l e t . c o m / _ c 7 3 1 u j ? x = 1 q q t & i = 3 8 n a a s

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer: The fuel pushes on the launch pad.

Explanation: This is a case of Newton's Third Law of Motion which states for every action in nature, there is an opposite and equal reaction.

Inside the rocket, the fuel is combusted creating a force that exerts on the launch pad by pushing it. As a reaction, the pad pushes the rocket upward, allowing it to go up. This is an example of Newton's Third Law of motion.

Explanation:

KE = (1/2)mv^2 ---> m = 2KE/v^2 = 2(9.890 J)/(10.1 m/s)^2

= 0.194 kg

Note: I think there's something wrong with the energy value given. The mass value for Usain Bolt is too small. That's less than a pound!

Answer:

The temperature is   \(T = \frac{h}{H_O \alpha_{steel} } + T_O\)

Explanation:

From the question we are told that

      The height on a cool spring day is \(H_O\)

      The temperature on a cool spring day is  \(T_O\)

      The difference in height between a cool spring day and a summer day  is     h

     The coefficient of static friction is \(\alpha _{steel}\)

The mathematical relation for the linear expansion of the steel buiding is represented as

               \(h = H_o \alpha_{steel} [T-T_O]\)

Where T is the temperature of the steel during summer

Now making T the subject we have

                \(T = \frac{h}{H_O \alpha_{steel} } + T_O\)

A color.......................................................................yeah the color of your socks is a color :}

When energy moves through a medium (such as air, water, or any other liquid or solid matter), it creates a pattern of disruption that propagates away from the source of the sound.

Two identical loudspeakers separated by distance delta X each emit sound waves of wavelength lambda and amplitude A along the x-axis.

What is the minimum value of the ratio delta X/ wavelength for which the amplitude of their superposition is also A?

On a location along the X axis, we receive a portion of the difference in their attacks when we talk along the X axis. The attacks over the wavelength are equal to the phase difference, or delta. Lambda divided by pi. The square of the temperature tude of the first three waves plus the square of the second wave's temperature, B plus two times even a two times course delta, is what determines the amplitude following a superimposed wave. Okay. The resultant amplitude, A, equals the square root of a squared plus a squared plus two times a squared in this situation because the amplitude is tiny.

Delta is now, of course, square on both sides. And we discover that A squared equals two A squared plus cost. This widget's delta are is equivalent to -1/2. Delta will be seven Pi over six. Okay, so this value is delta, which is equal to X over lambda times two pi are the ratio assaults with lambda = 7/12 from equation one.

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Answer:D

Explanation:D

If a product claims to be low-calorie, then it means that it must contain 40 calories or fewer per saving. Hence, option D is correct.

Our bodies need energy to keep us alive and to make sure that our organs are functioning properly.

When we eat and drink, we provide our bodies with energy. Our bodies consume that energy during routine tasks like breathing and jogging.

To keep a constant weight, the amount of energy we put into our bodies must correspond to the amount of energy we expend during routine biological functions and physical activity.

A key element of a balanced diet is striking a balance between the energy you put into your body and the energy you expend.

For instance, the more physical activity we do, the more energy we use.

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