Answer:
Fnet=7200 N
Explanation:
Fnet=mass x acceleration
mass= 1600kg acceleration=4.5m/s^2
Answer:
Net force= 7200 N or 7200 N*m/s^2 (It just depends)
Explanation:
1600 kg x 4.5 m/s^2 = 7200 kg*m/s^2 or 7200 N*m/s^2
How can you detect the hardness of water collected from different sources
Answer:
Explanation:
you can detect the hardness of water collected from different sources by using soap. Soaps can be used to check the hardness of water as it forms insoluble precipitate with hard water.
Answer:
We can detect the hardness of water taken from different sources by adding soap to it.
Explanation:
If the soap does not form micelle in the water then it will be hard water. In simple language if the soap doesnot disslove in water then it will be soft water.
A turtle travels 12 mile in 19 hour. At this rate, how far can the turtle travel in an hour?.
16.92 meter far can the turtle travel in an hour.
What is the formula for Speed, Distance & Time?
Speed (or rate, r) is a scalar quantity that measures the distance travelled (d) over the change in time (Δt), represented by the equation r = d/Δt
Given, 12 mile in 19 hours so we require to convert in SI unit.
12 mile = 19312.1 meters
19 Hour = 68400 sec
Applying in formula, speed = Distance / Time
Distance / Time = 19312.1 / 68400 = 0.282 m/ sec ²
Speed = 0.282 m / sec ²
1 hour = 60 second
Putting the above value in the below formula
speed = Distance / Time
Distance = Speed x Time = 0.282 x 60 = 16.92 meter
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Un Iceberg, con forma aproximada a la de un paralelepípedo (rectángulo en 3D), flota en el mar de modo que la parte fuera del agua tiene 10m de altura. Cuál es la altura "h" de la parte sumergida del Iceberg. Escribir la expresión algebraica de la solución antes de sustituir los datos y después el resultado.
Answer:
maybe could you put it in english and i could help you
The angle of reflection is the angle between the normal line and the _____.A.imageB.mirrorC.reflected rayD.incident ray
ANSWER:
C. reflected ray
STEP-BY-STEP EXPLANATION:
The line that divides the angle between the incident ray and the reflected ray into two equal angles is known as the normal line.
Therefore, the angle between the reflected ray and the normal is known as the angle of reflection.
Therefore, the correct answer is C. reflected ray
What is motion ,terms used to measure motion ,examples etc
Answer:
A physic term
Explanation:
Answer:
Cambio de lugar o de posición de un cuerpo en el espacio.
Explanation:
by how much would the index of refraction need to be increased to move the image 5.0 cm closer to the lens?
The change in the refractive index when the lens is brought near to the image is 0.014.
The refractive index is used to calculate the speed of light between two mediums. It is the ratio of the speed of light in a vacuum to that of the speed of light in a denser medium. It is inversely proportional to the speed of light, n = c/v. The focal length is the distance between the lens and the image. The refractive index depends on the focal length and they are inversely proportional.
From the given question,
The refractive index before the image was moved closer to the lens, n₁ = 1.5, Radius of curvature R₂ = ₋15 cm, Distance (s) = 50 cm. The focal length can be calculated by the lens markers equation, 1/f = (n-1) (1/R₁-1/R₂) where R₁ and R₂ are the radii of the curvature and R₁ is at infinity because the lens is concave. The focal length is f= 30 cm.
Next, to find the object's distance 1/f = 1/s + 1/s', and s' is 75 cm. When the image comes closer to the lens, the distance is 70 cm. The new focal length (f') is 1/f' = 1/s + 1/s' and f' = 29.17. The new refractive index n' is
1/f' = (n'-1) (1/R₁-1/R₂) and n' is 1.514.
The change in refractive index, Δn = n₁-n' = 1.5-1.514 = 0.414.
Thus, the new refractive index is 0.414.
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Your question is incomplete, most probably your question is, Some electro-optic materials can change their index of refraction in response to an applied voltage. Suppose a plano-convex lens (flat on one side,15.0 cm radius of curvature on the other). made from a material whose normal index of refraction is 1.500, creating an image of an object that is 50.0 cm from the lens. By how much would the index of refraction need to be increased to move the image 5.0 cm closer to the lens?
And according to the answer, a change in refractive index is 0.414.
Two plane mirrors are separated by 120°, as the drawing illustrates. If a ray strikes mirror m1 at a 65° angle of incidence, at what angle does it leave mirror m2?.
The law of reflection states that when light is reflected off a surface, the angle of incidence equals the angle of reflection.
Two plane mirrors are set at a 120-degree angle to each other in this issue. When light strikes a mirror, it is reflected. The angle of incidence equals the angle of reflection when this occurs. The angle at which a beam of light strikes a mirror is known as the angle of incidence. The angle between the reflected ray and the surface normal is known as the angle of reflection. The angle between the incident ray and the surface normal is known as the angle of incidence. When light is reflected off a surface, the angle of incidence equals the angle of reflection. When the incident ray strikes the first mirror at a 65-degree angle, the reflected ray will be reflected at a 65-degree angle. When the reflected ray hits the second mirror, it will be reflected at a 55-degree angle. To compute the final angle of reflection, we subtract this from 120 degrees. This implies that the reflected ray will leave the second mirror at a 65-degree angle. So, the answer to the question is 65 degrees.
When light is reflected off a surface, the angle of incidence equals the angle of reflection. When the first mirror is hit at a 65-degree angle of incidence, the reflected ray will be reflected at a 65-degree angle of reflection. When the reflected ray hits the second mirror, it will be reflected at a 55-degree angle. The angle of reflection can be determined by subtracting this value from 120 degrees. Thus, the reflected ray will leave the second mirror at a 65-degree angle.
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There is a centrifugal pump. The rotating speed n=1450rpm, the flow rate Q=0.0833m^3/s, outer diameter of impeller D2=360mm, inner diameter of impeller D,=138mm, blade outlet angle B2y=30° , flow cross- sectional area at impeller outlet A2=0.023m^2. The circulation coefficient K=0.7, assuming Cu=0. Calculate the theoretical and actual pressure head. LEC-10(2) There is a centrifugal pump. The outer diameter of impeller Dz=350mm, blade outlet width b2=12.7mm, rotating speed n=1200rpm, the flow rate Q=1.27mº/min, the pressure difference at inlet and outlet is 272kPa. The circulation coefficient K=0.9, hydraulic efficiency mn=70%, assuming Ciu=0. Calculate the blade outlet angle Bzy.
(a) The theoretical pressure head is 9.90 m, and the actual pressure head is 7.70 m. (b) The blade outlet angle Bzy is approximately 22.40°.
(a) For the first scenario:
Given:
Rotating speed (n): 1450 rpm
Flow rate (Q): 0.0833 m^3/s
Outer diameter of impeller (D2): 360 mm
Inner diameter of impeller (D1): 138 mm
Blade outlet angle (B2y): 30°
Flow cross-sectional area at impeller outlet (A2): 0.023 m^2
Circulation coefficient (K): 0.7
Assuming Cu (blade outlet velocity coefficient): 0
To calculate the theoretical pressure head, we can use the following equation:
Ht = (Q * K) / (g * A2)
where Ht is the theoretical pressure head, Q is the flow rate, K is the circulation coefficient, g is the acceleration due to gravity (approximately 9.81 m/s^2), and A2 is the flow cross-sectional area at impeller outlet.
Plugging in the given values, we have:
Ht = (0.0833 * 0.7) / (9.81 * 0.023) = 9.90 m
To calculate the actual pressure head, we can use the following equation:
Ha = (Q * K) / (g * A2) - (Cu^2 / (2 * g))
Since Cu is assumed to be 0, the second term in the equation becomes 0.
Plugging in the values, we have:
Ha = (0.0833 * 0.7) / (9.81 * 0.023) = 7.70 m
(b) For the second scenario:
Given:
Outer diameter of impeller (Dz): 350 mm
Blade outlet width (b2): 12.7 mm
Rotating speed (n): 1200 rpm
Flow rate (Q): 1.27 m^3/min
Pressure difference at inlet and outlet: 272 kPa
Circulation coefficient (K): 0.9
Hydraulic efficiency (mn): 70%
Assuming Ciu (blade inlet velocity coefficient): 0
To calculate the blade outlet angle (Bzy), we can use the following equation:
Bzy = arcsin(2 * mn * Q) / (π * Dz * b2 * sqrt(2 * g * (p2 - p1)))
where Bzy is the blade outlet angle, mn is the hydraulic efficiency, Q is the flow rate, Dz is the outer diameter of the impeller, b2 is the blade outlet width, g is the acceleration due to gravity, and p2 - p1 is the pressure difference at the inlet and outlet.
Plugging in the given values, we have:
Bzy = arcsin((2 * 0.70 * 1.27) / (π * 350 * 12.7 * sqrt(2 * 9.81 * 272))) ≈ 22.40°
(a) The theoretical pressure head is 9.90 m, and the actual pressure head is 7.70 m in the first scenario.
(b) The blade outlet angle Bzy is approximately 22.40° in the second scenario.
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???whats the answers??
The answers is 30 miles per hour, the driver is speeding the car up, section-H, 12 minutes, section-D, and 65 miles per hour.
1. The force on the last car of a train with a mass of 4.5 kg is 8.0 N. What is the train's acceleration in m/s2?
2. Observe the table. How many times greater must the acceleration of Object B be than the acceleration of Object A to make the table true?
Enter your answer as a whole number, like this: 4
A beaker (glass jar) contains 1 kg of water; when converted to a volume measurement it is the same as:
1,000 mL
1,000 L
1,000 cm 3
Pick more than 1
Answer:
a and c
Explanation:
didn't actually do the math, but i am pretty positive that those are equal
A machine part is undergoing SHM with a frequency of 4.60 Hz and amplitude 1.80 cm. How long does it take the part to go from x = 0 to x = -1.80 cm? Express your answer with the appropriate units.
It takes approximately 0.0543 seconds for the machine part undergoing simple harmonic motion to go from x = 0 to x = -1.80 cm.
To find the time it takes for the machine part to go from x = 0 to x = -1.80 cm, we can use the equation for simple harmonic motion (SHM):
x = A * sin(2πft),
where x is the displacement, A is the amplitude, f is the frequency, and t is the time.
In this case, the amplitude (A) is given as 1.80 cm, and the frequency (f) is given as 4.60 Hz. We want to find the time it takes for the displacement to go from x = 0 to x = -1.80 cm.
When the displacement is at its maximum, we have:
A * sin(2πft) = -1.80 cm.
Using the given values, we can rearrange the equation to solve for t:
sin(2πft) = -1.80 cm / A = -1.80 cm / 1.80 cm = -1.
For sin(2πft) to be -1, the argument inside the sine function (2πft) must be equal to -π/2.
2πft = -π/2,
Simplifying the equation, we have:
t = -(1/4f).
Substituting the given value of f = 4.60 Hz, we can calculate the time it takes for the part to go from x = 0 to x = -1.80 cm:
t = -(1/4 * 4.60 Hz) = -0.0543 s.
Since time cannot be negative, we take the absolute value:
t = 0.0543 s.
Therefore, it takes approximately 0.0543 seconds for the machine part to go from x = 0 to x = -1.80 cm.
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A circular coil of wire of radius 2 cm and which has 80 turns, is connected to a galvanometer in a closed circuit. A magnet creating a magnetic field of 50mT is pulled quickly from inside the coil until it is far enough away from the coil so that the field inside the coil is zero. The time it takes for the magnetic to move is 0,2s. Calculate the reading on the galvanometer.
-3.1415 x 10^(-4) V is the reading on the galvanometer.
To calculate the reading on the galvanometer, we need to determine the induced emf (electromotive force) in the coil due to the changing magnetic field. The induced emf can be found using Faraday's law of electromagnetic induction, which states that the induced emf is equal to the rate of change of magnetic flux through the coil.
The magnetic flux through a circular coil is given by the formula: Φ = B * A * cosθ, where B is the magnetic field, A is the area of the coil, and θ is the angle between the magnetic field and the normal to the coil.
In this case, as the magnet is moved away from the coil, the magnetic field inside the coil changes. Initially, when the magnet is inside the coil, the magnetic field inside the coil is non-zero. However, as the magnet is pulled away, the magnetic field inside the coil decreases until it reaches zero when the magnet is far enough away.
Given that the radius of the coil is 2 cm, the area can be calculated as A = π * r^2 = π * (0.02 m)^2 = 0.0012566 m^2. The magnetic field is 50 mT, which is equivalent to 0.05 T.
Now, we need to calculate the change in flux (∆Φ) during the time interval of 0.2 seconds. As the magnetic field inside the coil changes from non-zero to zero, the change in flux is equal to the initial flux through the coil.
∆Φ = B * A * cosθ = 0.05 T * 0.0012566 m^2 * 1 = 6.283 x 10^(-5) Wb
Finally, we can calculate the induced emf using Faraday's law:
emf = -∆Φ/∆t = -(6.283 x 10^(-5) Wb)/(0.2 s) = -3.1415 x 10^(-4) V
The negative sign indicates that the direction of the induced current in the coil is such that it opposes the change in magnetic flux.
The reading on the galvanometer will be equal to the magnitude of the induced emf, which is 3.1415 x 10^(-4) V.
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what is the acceleration a1 of the block when it passes through its equilibrium position? express your answer in terms of some or all of the variables a , m , and k .
The acceleration a1 of the block when it passes through its equilibrium position can be expressed as: a1 = -a (m/k) where a is the amplitude of the oscillation, m is the mass of the block, and k is the spring constant.
When the block passes through its equilibrium position, the net force acting on it is zero.
At this point, the spring force and the gravitational force cancel each other out. Therefore, the acceleration of the block is also zero at this point.
However, as the block moves away from the equilibrium position, the spring force begins to dominate over the gravitational force and causes the block to accelerate towards the equilibrium position.
The acceleration is directly proportional to the displacement from the equilibrium position and is given by a = -kx/m, where x is the displacement.
When the block reaches the maximum displacement (amplitude) a, the spring force is at its maximum and the gravitational force is negligible. At this point, the acceleration is given by a = -a (m/k).
In conclusion, the acceleration of the block when it passes through its equilibrium position is zero. However, as it moves away from the equilibrium position, the acceleration is given by a = -a (m/k). This expression shows that the acceleration is directly proportional to the amplitude of oscillation, inversely proportional to the mass of the block, and inversely proportional to the spring constant.
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Question 2
Points 2
A 7.5 kg bowling ball, initially at rest, is dropped from the top of an 11 m building. It
hits the ground 1.5 s later. Find the net external force on the falling ball.
110 N
R
CO
Answer:
Approximately \(73\; {\rm N}\), assuming that the acceleration of this ball is constant during the descent.
Explanation:
Assume that the acceleration of this ball, \(a\), is constant during the entire descent.
Let \(x\) denote the displacement of this ball and let \(t\) denote the duration of the descent. The SUVAT equation \(x = (1/2)\, a\, t^{2}\) would apply.
Rearrange this equation to find an expression for the acceleration, \(a\), of this ball:
\(\begin{aligned} a &= \frac{2\, x}{t^{2}}\end{aligned}\).
Note that \(x = 11\; {\rm m}\) and \(t = 1.5\; {\rm s}\) in this question. Thus:
\(\begin{aligned} a &= \frac{2\, x}{t^{2}} \\ &= \frac{2 \times 11\; {\rm m}}{(1.5\; {\rm s})^{2}} \\ &\approx 9.78\; {\rm m \cdot s^{-2}}\end{aligned}\).
Let \(m\) denote the mass of this ball. By Newton's Second Law of Motion, if the acceleration of this ball is \(a\), the net external force on this ball would be \(m\, a\).
Since \(m = 7.5\; {\rm kg}\) and \(a \approx 9.78\; {\rm m\cdot s^{-2}}\), the net external force on this ball would be:
\(\begin{aligned} (\text{net force}) &= m\, a \\ &\approx 7.5\; {\rm kg} \times 9.78\; {\rm m\cdot s^{-2}} \\ &\approx 73\; {\rm kg \cdot m \cdot s^{-2} \\ &= 73\; {\rm N} && (1\; {\rm N} = 1\; {\rm kg \cdot m\cdot s^{-2}}) \end{aligned}\).
an object that covers more distance in the same amount of time has a higher speed.
true or false
Answer:
true
Explanation:
Answer: its true btw :(
Why does the value of g is move at polar region than at equator
Explanation:
the centrifugal force of the Earth's rotation forces the Earth's belly at the equator to grow even further. that extra material/mass is pulled in from the poles.
so, from equator to equator there is more mass and more gravity than from pole to pole.
What is the total current I flowing through a system with two resistors in parallel with resistances of 2Ω and 5Ω, and a battery with potential difference of 10V?
Answer:
7A
Explanation:
Current I = potential difference V ÷ Resistance R
I = V/R ........1
The overall resistance of parallel resistors is;
1/Rt = 1/R1 + 1/R2 ........2
Given;
V = 10V
R1 = 2 ohms
R2 = 5 ohms
Substituting the values into equation 2, to calculate the overall resistance;
1/Rt = 1/2 + 1/5
1/Rt = 7/10
Rt = 10/7 ohms
From equation 1, we can solve for the total current;
I = V/Rt = 10/(10/7)
I = 7A
The total current I flowing through a system is 7A
A camper stands in a valley between two parallel cliff walls. He claps his hands and notices that the echo from the nearby wall returns 0.9 s later while the echo from the farther wall returns 1.10 s later. If the air temperature is -10 C, how wide is the valley?
When a wood block floats in water it displaces 0.006m3 find the weight of the block when it is in air
The weight of the wood block when it is in the air can be determined with the help of Archimedes' principle.
Archimedes' principle states that the weight of a body that is submerged in a fluid is equal to the weight of the fluid that is displaced by it.
Hence, we can say that when the wood block floats in water, it displaces 0.006 m3 of water. This means that the weight of the wood block is equal to the weight of water displaced by it.
Therefore, the weight of the wood block when it is in the air can be determined by finding the weight of 0.006 m3 of water.
The density of water is 1 g/cm3.
Since 1m³ = 1000000 cm³,
We can say that the mass of 1 m3 of water is 1000 kg, or 106 g.
Hence, the mass of 0.006 m3 of water is 0.006 x 106 g, or 6000 g.
Therefore, the weight of 0.006 m3 of water is 6000 x 9.8 N, or 58800 N.
Hence, the weight of the wood block when it is in the air is 58800 N.
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A boat is traveling upstream at 14 km/h with respect to the water of a river. The water itself is flowing at 9 km/h with respect to the ground. What is the velocity of the boat with respect to the ground
Answer:
16.64 km/h
Explanation:
Think of the x and y components as the a and b sides of a triangle and simply do the Pythagorean Theorem:
\(a^2+b^2=c^2\)
\(14^2+9^2=c^2\)
\(\sqrt{196+81}=c\)
\(\sqrt{277}=c\)
\(16.64 km/h\)
A study of classical waves tells us that a standing wave can be expressed as a sum of two travelling waves. Quantum-Mechanical travelling waves, discussed in Chapter 4, is of the form φ(x,t) = Ae^i(kw=wt) Show that the infinite well’s standing wave function can be expressed as a sum of two traveling waves.
In quantum mechanics, the wavefunction of a particle in an infinite well can be described as a standing wave, which is a superposition of two traveling waves propagating in opposite directions.
The standing wave function in an infinite well is given by:
ψ(x, t) = A sin(kx) e^(-iωt)
Using the Euler's formula, we can rewrite the sine function as a sum of exponential functions:
sin(kx) = (1/2i) * (e^(ikx) - e^(-ikx))
Substituting this back into the standing wave function, we have:
ψ(x, t) = A (1/2i) * (e^(ikx) - e^(-ikx)) * e^(-iωt)
Simplifying the expression, we obtain:
ψ(x, t) = (A/2i) * (e^(ikx - iωt) - e^(-ikx - iωt))
Now, we can define two traveling waves:
ψ_1(x, t) = (A/2i) * e^(ikx - iωt)
ψ_2(x, t) = (A/2i) * e^(-ikx - iωt)
The superposition of these two traveling waves gives us the standing wave function:
ψ(x, t) = ψ_1(x, t) + ψ_2(x, t)
Therefore, we have shown that the infinite well's standing wave function can be expressed as a sum of two traveling waves propagating in opposite directions.
By expressing the sine function in terms of exponential functions and defining two traveling waves, we can show that the infinite well's standing wave function can be written as the sum of these two traveling waves. This demonstrates the connection between standing waves and the superposition of traveling waves in the context of quantum mechanics.
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1. Hearing is also known as
?
what best describes the relationship between climate change and global warming?
A. climate change is one example of global warming.
B. climate change includes global warmings as well as other factors.
C. climate change and global warming are the same phonemenon
D. climarte change and global warming have no relationship
Answer:
b
Explanation:
Answer:
B. Climate change includes global warming as well as other factors
Explanation:
Global warming is just one of the many aspects of climate change.
Complete the statement below with all that apply.
Acceleration is
A. the slope of a velocity vs. time graph
Pector
B. a Vector
C. measured in m/s
D. the change in displacement divided by the change in time
Answer:
Acceleration is a vector, is measured in m/s, and A.
Explanation: SO BASICALLY, the answer to this question is A, B, and C. The last one would not fit the description of acceleration because it is describing Velocity.
Which statement compares the attractive forces that hold particles together?
Mark needs to clean up a broken glass on the floor. He can use a hand brush or a broom. Why should he choose the broom?
He will apply force to the broom over a shorter distance than he would to the brush.
He will have to move the broken glass less distance with the broom than he would with the brush.
He will do less work with the broom than he would with the brush.
He will use less force with the broom than he would with the brush.
Which statement below is not a reason why one would use motion on a slide
to bring in elements as one builds their point visually
to emphasize part of a visual
to promote interaction with the audience
to draw attention to a single element
________ is based on a determined assignment of value or importance to different elements.
Design priority
Element priority
Visual priority
Structural priority
1. The statements that is not a reason why one would use motion on a slide is B. to emphasize part of a visual. 2. C. Visual priority is based on a determined assignment of value or importance to different elements.
Although the use of motion on a slide can indeed be used to emphasize part of a visual, it is not the only way to accomplish this goal. The use of color, size, contrast, and other visual elements can also be used to draw attention to specific parts of a visual. The other reasons listed - to bring in elements as one builds their point visually, to promote interaction with the audience, and to draw attention to a single element - are all valid reasons for using motion on a slide. So the correct answer is B. to emphasize part of a visual.
Visual priority refers to the hierarchy of visual elements on a slide, and the order in which they are presented to the audience. This hierarchy can be established through the use of color, size, contrast, placement, and other visual elements. By assigning different levels of importance to different elements, the designer can guide the audience's attention and create a clear and effective visual message. Other priorities listed - design priority, element priority, and structural priority - may also be important considerations when designing a slide, depending on the specific context and purpose of the presentation. So the correct answer is C. Visual priority.
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A progressive wave equation is represented by y=Asin2π(0. 15t-0. 1x). Find the
period,
amplitude,
frequency,
wavelength,
velocity
Given that the progressive wave equation is represented by y=Asin2π(0.15t-0.1x). Let's find the period, amplitude, frequency, wavelength, and velocity.
The wave equation is represented by y=Asin2π(0.15t-0.1x). The standard wave equation can be written asy = Asin(kx-ωt + Φ)Where,k = wave numberω = angular frequencyΦ = phase angle for the given equation, k = 0.1 and ω = 0.15.Amplitude:
Amplitude = A = maximum displacement from the mean position.A = 1Frequency: Frequency is the number of complete oscillations made by a point on the wave in one second. It is denoted by f.f = ω/2πFrequency, f = 0.15/2π = 0.0238 HzPeriod: Period is the time taken by one complete oscillation.
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The largest grand piano in the world is really grand. Built in London, it has a mass of 1,152 kg. Suppose a pianist finishes playing this piano and pushes herself from the piano so that she rolls backwards with a speed of 1.5 m/s. Meanwhile, the piano rolls forward with a constant velocity of 0.06 m/s. Assuming the stool that the pianist is sitting on has a negligible mass, what is the pianist’s mass? Round to the hundredths.
ANSWER:
46.08 kg
STEP-BY-STEP EXPLANATION:
Given
m1 = 1152 kg
v1 = 0.06 m/s
v2 = -1.5 m/s
We apply law of conservation of linear momentum:
\(\begin{gathered} P_i=P_f \\ P_i=0 \\ P_f=m_1\cdot V_1+m_2\cdot V_2 \end{gathered}\)We plug in and calculate for the mass, just like this:
\(\begin{gathered} 0_{}=m_1\cdot V_1+m_2\cdot V_2 \\ 0=1152\cdot0.06+m_2\cdot-1.5 \\ -1.5m_2=-69.12 \\ m_2=\frac{-69.12}{-1.5} \\ m_2=46.08\text{ kg} \end{gathered}\)Which means that the mass of the pianist is 46.08 kg