Answer:
Option (A)
Explanation:
Displacement of a particle on a velocity time graph is represented by the area between the line representing velocity and x-axis (time).
Displacement of a particle from t = 0 o t = 40 seconds = Area of ΔAOB
Area of triangle AOB = \(\frac{1}{2}(\text{Base})(\text{height})\)
= \(\frac{1}{2}(40)(4)\)
= 80 m
Similarly, displacement of the particle from t = 40 to t = 80 seconds = Area of ΔBCD
Area of ΔBCD = \(\frac{1}{2}(40)(4)\)
= 80 m
Total displacement of the particle from t = 0 to t = 80 seconds,
= 80 + 80
= 160 m
Option (A) will be the answer.
A truck brakes from 15 m/s to 2 m/s in 15 seconds. What is its acceleration?
This question is typical on some driver’s license exams: A car moving at 45 km/h skids
17 m with locked brakes.
How far will the car skid with locked brakes
at 112.5 km/h? Assume that energy loss is
due only to sliding friction.
The distance of the skid at a speed of 112.5 km/h is determined as 106.1 m.
What is the distance travelled by the car?The distance traveled by the car is calculated by applying the following method.
v² = u² + 2as
where;
v is the final velocity of the caru is the initial velocity of the cara is the acceleration of the cars is the distance traveled by the carv = 45 km/h = 12.5 m/s
a = v²/2s
a = ( 12.5²) / ( 2 x 17)
a = 4.6 m/s²
The distance of the skid at a speed of 112.5 km/h is calculated as follows;
112.5 km/h = 31.25 m/s
s = (31.25²) / (2 x 4.6)
s = 106.1 m
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Part 1: How many "pathways" are in this circuit?
Part 2: Therefore, is this a series or parallel circuit?
Part 1: Zero pathways
Part 1: One pathway
Part 1: Two pathways
Part 1: Three pathways
Part 1: Four pathways
Part 1: Five pathways
Part 2: Series circuit
Part 2: Parallel circuit
Part 1: The number of pathways in a circuit determines the possible routes for electric current to flow.
There are maximum of five pathways in this circuit, depending on its complexity and the arrangement of components.
Part 2: Determining whether the circuit is series or parallel requires more information.
In a series circuit, components are connected in a single path, and the current flows through each component sequentially.
If the circuit has only one pathway (zero or one pathway), it suggests a series circuit.
However, if the circuit has multiple pathways (two or more pathways), it indicates a parallel circuit.
To conclusively determine the circuit's nature, we need to analyze the circuit diagram or obtain additional details regarding the component connections and their interactions.
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A force of F= 45 N is used to drag a crate 3 m across a floor.
ANSWER:
(a) 108 J
(b) 0 J
(c) 108 J
STEP-BY-STEP EXPLANATION:
(a)
Express the relation between horizontal component of work done and force on the crate:
\(W_h=F_h\cdot d\)Here Wh is the horizontal component of the work done on the crate and Fh is the horizontal component of force and d is the distance of the crate across the floor.
Replacing:
\(\begin{gathered} W_h=36\cdot3 \\ W_h=108\text{ J} \end{gathered}\)(b)
Express the relation between vertical component of work done and force on the crate:
\(W_v=F_v\cdot d\)Here Wv is the vertical component of the work done on the crate and Fv is the vertical component of force and d is the distance of the crate across the floor.
Replacing:
\(\begin{gathered} W_h=27\cdot0 \\ W_h=0\text{ J} \end{gathered}\)(c)
Express the relation for total work done by the 45 N force:
\(\begin{gathered} W_{\text{total}}=W_h+W_v \\ \text{ replacing} \\ W_{\text{total}}=108+0 \\ W_{\text{total}}=108\text{ J} \end{gathered}\)can someone pls help me create a lab trying to prove steam is hotter than boiling water.
Answer:
More energy
Explanation:
Steam is hotter than boiling water because it contains more energy
A jet plane emits 5.0 x 10^5 j of sound energy per second. what is the sound level 25 m away?
The correct answer is 66.99dB
I=5×10−6Wm−2;Io=1×10−12W.m−2
The sound intensity level in
dBis :(10dB)log10(5×10−6Wm−21×10−12Wm−2)=66.99dB
What is Threshold of Hearing.?Humans can hear sounds in such a wide range of intensities ( spans 13 orders of magnitude). The Threshold of Hearing is the level at which even the tiniest sound becomes heard.
We should develop a scale to quantify sound intensity that falls between 0 and 100 because it is challenging to develop intuition for numbers in such a wide range. That is the decibel scale's intended use (dB).
The dB scale is based on logarithmic scaling since it has the property of taking big numbers and returning small numbers. This scale is set up so that the sound intensity at the Threshold of Hearing is equal to zero.
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A place kicker must kick a football from a point 31.5 m from a goal. As a result of the kick, the ball must clear the crossbar, which is 3.05 m high. When kicked the ball leaves the ground with a speed of 20.2 m/s at an angle of 53° to the horizontal.
(a) By how much does the ball clear or fall short of clearing the crossbar?
(b) Does the ball approach the crossbar while still rising or while falling?
(a) The ball cleared the crossbar by 10.23 m.
(b) The ball approaches the crossbar while falling.
What is the maximum height reached by the ball?
The maximum height reached by the ball is calculated by applying the following kinematic equation as shown below;
H = u² sin²θ / 2g
where;
u is the initial velocity of the ballθ is the angle of projection of the ballg is acceleration due to gravityH = (20.2² x (sin 53)²) / (2 x 9.8)
H = 13.28 m
ΔH = 13.28 m - 3.05 m = 10.23 m
The horizontal distance travelled by the ball is calculated as follows;
R = u² sin(2θ) / g
R = (20.2² sin(2 x 53) ) / (9.8)
R = 40 m
Thus, the ball cleared the crossbar and since the maximum height travelled by the ball is far greater than the height of the crossbar, the ball will approach the crossbar while falling.
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the song of lead me lord it is not evident why
How many atoms are in the compound NaNO3?
Explanation:
3 atoms are in the compound
how does size of an object affect its gravity
Answer:
the more particles packed together the faster it falls
Explanation:
the mass + the 1 constant g-force = the speed without adding air resistance
a spaceship has a payload of 50,000 kg, carries 2,000,000 kg of fuel, and is able to eject the propellant with a speed of 23.5 km/s, thus being able to reach a final speed of 87.3 km/s. if the fuel mass of the spaceship in halved to 1,000,000 kg, the final speed the spaceship can reach will be
If the fuel mass of the spaceship is halved, the final speed the spaceship can reach would be 1,362.75 kg.
If the fuel mass of the spaceship is halved to 1,000,000 kg, the final speed the spaceship can reach will be reduced to 43.6 km/s. This is because the fuel mass is used up to accelerate the spaceship to its final speed, and a smaller fuel mass means that the spaceship will not be able to achieve as much acceleration, resulting in a slower final speed.
The propellant ejected from the spaceship has a speed of 23.5 km/s, and the fuel mass of the spaceship is reduced to 1,000,000 kg, which means that the total mass of the spaceship and the propellant ejected would be: 1,000,000 kg + 2,000,000 kg
= 3,000,000 kg.
The final speed of the spaceship can be calculated using the following formula:
Final speed = (1/2) x (3,000,000 kg x 23.5 km/s) - 1,000,000 kg
Final speed = (1/2) x (3,000,000 x 23.5 km/s) - 1,000,000 kg
Final speed = (3,000,000/2) x 23.5 km/s - 1,000,000 kg
Final speed = 11.75 x 23.5 km/s - 1,000,000 kg
Final speed = 267.75 km/s - 1,000,000 kg
Final speed = 1,362.75 kg
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a sample is obtained from a normal population with σ = 20. if the sample mean has a standard error of 10 points, then the sample size is n = 4. True or False
The answer is False. The standard error (SE) of the sample mean is calculated as SE = σ/√n where σ is the population standard deviation and n is the sample size.
We are given that σ = 20 and SE = 10.
Substituting these values in the formula, we get:
10 = 20/√n
Squaring both sides, we get:
100 = 400/n
Multiplying both sides by n, we get:
100n = 400
Dividing both sides by 100, we get:
n = 4
So, the sample size is indeed 4.
However, the question asks us to determine whether the statement is true or false based on the given information. Therefore, the correct answer is false, as the statement is incomplete. Specifically, we need to know whether the sample mean is equal to, greater than, or less than the population mean. This is because the sample size required to achieve a given level of precision (i.e., a standard error of 10) depends on both the population standard deviation and the distance between the sample mean and the population mean.
If the sample mean is close to the population mean, then a smaller sample size may suffice to achieve a given level of precision. If the sample mean is far from the population mean, then a larger sample size may be necessary to achieve the same level of precision.
Therefore, In summary, the correct answer is false.
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A wave produced by an earthquake appears in the diagram below:
A second wave leaves the center of an earthquake at the same time. The second wave is a longitudinal wave. After 10 seconds, will the two waves travel the same distance?
answer choices
a. Yes, because both waves are longitudinal waves.
b. Yes, because all waves travel at the same speed in similar mediums.
c. No, because only one type of wave can travel through a medium at a time.
d. No, because transverse waves travel at different speeds than longitudinal waves.
A longitudinal wave makes up the second wave. The two waves will have traveled the same distance after 10 seconds since they are both longitudinal waves. Option a is Correct.
In the graphic below, an earthquake wave is depicted: An earthquake's second wave simultaneously emerges from the epicenter. They are in particular to blame for the terrible noises that follow powerful earthquakes. These waves move along the path of wave travel at a speed of around 5 miles per second, causing the crustal rock to shake.
These waves in a solid medium might either be longitudinal waves or transverse waves. P waves (for "principal" waves) denote longitudinal or compressional seismic waves through bulk material, whereas S waves denote transverse seismic waves ("secondary" ). Option a is Correct.
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Correct Question:
A wave produced by an earthquake appears in the diagram below:
A second wave leaves the center of an earthquake at the same time. The second wave is a longitudinal wave. After 10 seconds, will the two waves travel the same distance?
answer choices
a. Yes, because both waves are longitudinal waves.
b. Yes, because all waves travel at the same speed in similar mediums.
c. No, because only one type of wave can travel through a medium at a time.
d. No, because transverse waves travel at different speeds than longitudinal waves.
4. Explain A girl is jumping on a trampoline. When she is at the top of her jump, her mechanical energy is in what form? Explain why.
Mechanical energy is of two types,
1. Kinetic energy
2. Potential energy
When the girl is at the top of her jump, the speed of the girl becomes zero.
Thus, the kinetic energy of the girl at the top of her jump is,
\(K=\frac{1}{2}mv^2\)where m is the mass of the girl and v is her speed,
Substituting the known values,
\(K=0\text{ J}\)Thus, the kinetic energy of the girl is zero at the top of her jump.
The potential energy of the girl at the top of her jump is,
\(U=\text{mgh}\)where g is the acceleration due to gravity and h is the height of the girl,
Thus, the potential energy of the girl at the maximum height is maximum.
Hence, the mechanical energy of the girl at the top is in potential energy form because her kinetic energy is zero at the top of her jump.
Please Help!!!!
A scientist defects an earthquake wave traveling at a speed of 6.5 km/s in rock with a density of 2.8 g/cubic cm. Based on the data, a scientist can BEST conclude that the wave is traveling through which type of rock?
Answers choices:
A. limestone
B. shale
C. anhydrite
D. dolomite
What will be net force be if net forces are unbalanced?
Answer: If the forces on an object are balanced, the net force is zero. If the forces are unbalanced forces, the effects don't cancel each other. Any time the forces acting on an object are unbalanced, the net force is not zero, and the motion of the object changes.
. explain what the mass-to-light ratio is and why it is smaller in spiral galaxies with regions of star formation than in elliptical galaxies.
The mass-to-light ratio is the ratio of the total mass of a celestial object, such as a galaxy, to the amount of light it emits. The mass-to-light ratio is smaller in spiral galaxies with regions of star formation compared to elliptical galaxies.
The mass-to-light ratio provides insights into the composition and stellar populations of galaxies. In spiral galaxies, regions of active star formation contribute to the decrease in the mass-to-light ratio. This is because star formation produces young, massive stars that are brighter and emit more light compared to older, lower-mass stars. Therefore, the light output of a spiral galaxy with active star-forming regions is relatively high compared to its total mass, resulting in a lower mass-to-light ratio.
On the other hand, elliptical galaxies typically have little to no ongoing star formation and consist mainly of old stars. These old stars have lower luminosity and emit less light per unit mass compared to the young, massive stars found in spiral galaxies. Consequently, the mass-to-light ratio in elliptical galaxies tends to be larger due to the relatively lower amount of light emitted for a given mass.
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An ideal spherical speaker is resting in the middle of an open field, playing a constant 900 Hz
tone. It's a windy day with a 5 m/s
breeże blowing from the north to the south. A cat is running towards the speaker from the south to the north at 10 m/s. Which of the following mathematical models would correctly solve for the frequency the cat would hear from the speaker (where
v is the speed of sound in still air, v.wind is the wind speed, and V.s and v.o are the speeds of the source and observer, as usual)?
a. f.0 = (f.s)(v+v.wind+v.o)/(v+v.wind)
b. f.0 = (f.s)(v+v.wind+v.o)/(v-v.wind)
c. f.0 = (f.s)(v-v.wind+v.o)/(v-v.wind)
d. f.0 = (f.s)(v-v.wind+v.o)/(v+v.wind)
The mathematical model which would correctly solve for the frequency the cat would hear from the speaker is a. \(f_0 = (f_s)\frac{v+v.wind+v.o}{v+v.wind}\).
We can use the formula for the Doppler effect of sound waves to calculate the frequency heard by the cat. The formula is:
\(f_o = f_s \times \frac {v \pm v_o}{v \pm v.s}\)
where \(f_o\) is the frequency heard by the observer (cat), \(f_s\) is the frequency emitted by the source (speaker), v is the speed of sound in still air, \(v_o\) is the speed of the observer (cat) relative to the air (positive if moving towards the source, negative if moving away from the source), and \(v_s\) is the speed of the source (speaker) relative to the air (positive if moving away from the observer, negative if moving towards the observer).
In this case, the speaker and the cat are both moving with respect to the air due to the wind. The wind is blowing from the north to the south, so its direction is opposite to the direction of the cat's motion (from south to north). Therefore, the speed of the observer relative to the air is \(v_o = 10\ m/s - (-5 \ m/s) = 15 \ m/s\) (positive because the cat is moving towards the speaker). The speed of the source relative to the air is v.s = 5 m/s (because the speed of air is 5 m/s). The speed of sound in still air is v = 340 m/s. The frequency emitted by the speaker is f.s = 900 Hz.
Substituting these values into the formula, we get:
\(f_o = (900 \times (340 + 15)) / (340 + 5)\)
\(f_0 = 926.08 \ Hz\)
Therefore, the frequency heard by the cat from the speaker is approximately 926.08 Hz. The correct formula that solves this frequency is option a. \(f_0 = (f_s)\frac{v+v.wind+v.o}{v+v.wind}\).
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A car is moving east at 28.8 m/s before applying it’s breaks. The car comes to a stop after 74 meters. How long does it take for the car to stop?
Answer:
Below
Explanation:
AVERAGE velocity = ( 28.8 - 0 ) / 2 = 14.4 m/s
74 m / 14.4 m/s = 5.14 s
A 1,286-kg car is skidding to a stop along a horizontal surface. The car decelerates from 26.9 m/s to rest in 9.36 seconds. How far did the car skid before coming to rest?
Answer:
Explanation:
Given:
M = 1 260 kg
V₀ = 26.9 m/s
V = 0 m/s
Δt = 9.36 s
___________
L - ?
1)
Vehicle acceleration:
a = (V - V₀) / Δt ) = (0 - 26.9) / 9.36 ≈ - 2.87 m/s²
2)
Braking distance of the car:
L = (V² - V₀²) / (2·a)
L = ( 0² - 26.9²) / (2·(-2.87)) ≈ 121 m
in any chemical reaction or physical change the mass of the product is ___ The mass of the reactant
a. The relationship cannot be determined by the amount of information given
b. equal to or the same
c. twice is greater than
d. twice as less than
Answer: b. equal to or the same
In Law of Conservation of mass, the mass of the product equals the mass of the reactant. A reactant is the chemical reaction of two or more elements to make a new substance, and a product is the substance that is formed as the result of a chemical reaction.
pls mark brainliest! i really need one :(
Write down whether quantity of potential kinetic and total energy
Potential energy is the power that a thing possesses as a result of where it is in relation to other objects.
What is Potential energy?The earth can pull you down through the force of gravity while doing work in the process, being at the top of a stairwell gives you more potential energy than standing at the bottom.
Two magnets have more potential energy when they are held apart than when they are near to one another. They will migrate near each other and begin working if you let them go.
The force acting on the two objects affects the potential energy formula. P.E. = mgh, where m is the mass in kilograms and g is the acceleration due to gravity, is the formula for gravitational force.
Therefore, Potential energy is the power that a thing possesses as a result of where it is in relation to other objects.
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an object weighting 100g is thrown upwards from the ground at a speed of 100 m/s.where will the potential energy of the object be two thirds of the kinetic energy?
Answer:
333.3 m
Explanation:
Given
\(m =100g\ =\ 0.1kg\\v = 100 m/s\\g = 10 m/s ^2\)
Potential energy =\(\frac{2}{3}\ of\ Kinetic\ energy\)......Equation(1)
We know that
Potential energy=mgh
Kinetic energy =\(\frac{1}{2} mv^{2}\)
Now From the Equation(1)
\(mgh=\frac{2}{3}*\frac{1}{2} mv^{2}\\ gh=\frac{v^{2} }{3} \\10 * h=\ \frac{10000}{3}\\ h=\ \frac{1000}{3} \\h=333.3\ m\)
if darth maul could survive being cut in half, why couldn't sidious survive being thrown into some electric chamber?
In the case of Darth Maul, his survival after being cut in half is attributed to his strong connection to the dark side of the Force, his determination, and his cybernetic enhancements.
In the Star Wars universe, characters' survival and abilities are determined by the narrative and creative decisions made by the writers and filmmakers. While it is true that Darth Maul survived being cut in half, it's important to remember that each character's resilience and capacity for survival can vary.
In the case of Darth Maul, his survival after being cut in half is attributed to his strong connection to the dark side of the Force, his determination, and his cybernetic enhancements. These factors, combined with his sheer willpower, allowed him to endure and ultimately return in later storylines.
On the other hand, Emperor Palpatine, also known as Darth Sidious, met his demise when he was thrown into the electric chamber on the second Death Star in "Star Wars: Episode VI - Return of the Jedi." The circumstances and outcome of his death were a pivotal part of the story and reflected the narrative arc and resolution of the conflict between the light and dark sides of the Force.
It's worth noting that in the Star Wars universe, Force users' abilities, resilience, and survival can vary depending on various factors such as their connection to the Force, their training, their physical condition, and the circumstances surrounding their encounters. Ultimately, the specific events and outcomes are determined by the creative choices made within the Star Wars storytelling.
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what's the maximum amount of electrons that will fit on an outermost shell of an atom?
The maximum number of electrons that can fit in the outermost shell of an atom is typically eight, but there are exceptions based on the element's position in the periodic table.
The maximum number of electrons that can fit in the outermost shell, also known as the valence shell, of an atom depends on the atom's position in the periodic table. The valence shell is the outermost energy level of an atom where electrons are primarily located.
For most elements in the periodic table, the maximum number of electrons that can occupy the valence shell is eight. This is known as the octet rule, which states that atoms tend to gain, lose, or share electrons in order to achieve a stable electron configuration with eight electrons in the valence shell. This stable configuration is similar to the electron configuration of the noble gases, which have full valence shells.
However, there are exceptions to the octet rule. Elements in the first row of the periodic table, such as hydrogen and helium, can only hold a maximum of two electrons in their valence shell. Elements beyond the second period, in the third row and beyond, can have expanded valence shells that can hold more than eight electrons due to the presence of d and f orbitals.
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A force of 10 N is applied perpendicular to the end of a bar of
length 0.2 m. Calculate the torque produced by the force.
The torque produced by the force is 2 Nm
Torque
This is the turning effect of a force.
The torque of a force is given by τ = Fd where
F = force applied and d = perpendicular distance of force from action pointSince τ = Fd,
F = force applied = 10 N and d = length of bar = 0.2 mSubstituting the values of the variables into the equation, we have
τ = Fd
τ = 10 N × 0.2 m
τ = 2 Nm
So, the torque produced by the force is 2 Nm
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What are you guys biggest fear?
Answer:
Dying
Explanation:
I know I am scared
i will mark brainliest if you get it right.
Answer:
Satellite D
Explanation:
It has more mass
how many types Of Ornital does the atomic orbital have ?
Answer:
There are four types of orbitals that you should be familiar with s, p, d and f (sharp, principle, diffuse and fundamental). Within each shell of an atom there are some combinations of orbitals
How does the energy of the cosmic microwave background compare to the energy radiated by all the stars and galaxies that ever existed
Answer:the universe will expand forever. there are small ripples in the microwave background, the seeds of galaxies.
Explanation: