What is the maximum kinetic energy and speed of an electron ejected from a Na surface, in a photo-electric effect apparatus, when the surface is illuminated by light of wavelength 410 nm ? The work function for sodium is 2.28eV. b) What is the critical frequency below which no electrons are ejected from sodium? c) What is the kinetic energy of electrons emitted when yellow light of λ=600 nm is incident on Na ? d) Sketch a graph of kinetic energy of the ejected electron vs. frequency of incident light for the photoelectric effect in sodium. Indicate the work function and critical frequency on your graph. What is the slope of the graph?
Answers
The maximum kinetic energy of the ejected electron is approximately \(\(4.51 \times 10^{-19}\, \text{J}\)\), and its maximum speed is approximately \(\(5.79 \times 10^5\, \text{m/s}\)\). the critical frequency below which no electrons are ejected from sodium is approximately \(\(9.27 \times 10^{14}\, \text{Hz}\)\).
The kinetic energy of electrons emitted when yellow light of \(\(\lambda = 600\)\) nm is incident on sodium is approximately \(\(2.15 \times 10^{-19}\, \text{J}\)\).
a) To calculate the maximum kinetic energy \((\(E_{\text{max}}\))\) and speed \((\(v_{\text{max}}\))\) of an electron ejected from a sodium surface in the photoelectric effect, we can use the following formulas:
\(\[E_{\text{max}} = h \cdot \nu - \phi\]\\\\\v_{\text{max}} = \sqrt{\frac{{2E_{\text{max}}}}{{m_e}}}\]\)
where:
\(\(h\) is Planck's constant (\(6.62607015 \times 10^{-34}\, \text{J}\cdot\text{s}\))\),
\(\(\nu\)\) is the frequency of the incident light \((\(\frac{c}{\lambda}\), where \(c\)\) is the speed of light and \(\(\lambda\)\) is the wavelength of the light),
\(\(\phi\)\) is the work function of sodium (in electron volts, eV),
\(\(m_e\)\) is the mass of an electron \((\(9.10938356 \times 10^{-31}\, \text{kg}\))\).
Given:
Wavelength of the incident light \((\(\lambda\))\) = 410 nm \((\(410 \times 10^{-9}\, \text{m}\))\),
Work function of sodium \((\(\phi\))\) = 2.28 eV \((\(2.28 \times 1.602176634 \times 10^{-19}\, \text{J}\))\).
First, calculate the frequency of the incident light:
\(\[\nu = \frac{c}{\lambda} = \frac{3 \times 10^8\, \text{m/s}}{410 \times 10^{-9}\, \text{m}} \\\\= 7.317 \times 10^{14}\, \text{Hz}\]\)
Now substitute the values into the equations to calculate \(\(E_{\text{max}}\) and \(v_{\text{max}}\)\):
\(\[E_{\text{max}} = (6.62607015 \times 10^{-34}\, \text{J}\cdot\text{s}) \cdot (7.317 \times 10^{14}\, \text{Hz}) - (2.28 \times 1.602176634 \times 10^{-19}\, \text{J})\]\\\v_{\text{max}} = \sqrt{\frac{{2 \cdot E_{\text{max}}}}{{9.10938356 \times 10^{-31}\, \text{kg}}}}\]\)
After evaluating the equations, we find:
\(\(E_{\text{max}} \approx 4.51 \times 10^{-19}\, \text{J}\)\)
\(\(v_{\text{max}} \approx 5.79 \times 10^5\, \text{m/s}\)\)
Therefore, the maximum kinetic energy of the ejected electron is approximately \(\(4.51 \times 10^{-19}\, \text{J}\)\), and its maximum speed is approximately \(\(5.79 \times 10^5\, \text{m/s}\)\).
b) The critical frequency \((\(\nu_{\text{c}}\))\) is the threshold frequency below which no electrons are ejected. It can be calculated using the formula:
\(\[\nu_{\text{c}} = \frac{{\phi}}{{h}}\]\)
Substituting the values into the formula:
\(\[\nu_{\text{c}} = \frac{{2.28 \times 1.602176634 \times 10^{-19}\, \text{J}}}{{6.62607015 \times 10^{-34}\, \text{J}\cdot\text{s}}}\]\)
After evaluating the equation, we find:
\(\(\nu_{\text{c}} \approx 9.27 \times 10^{14}\, \text{Hz}\)\)
Therefore, the critical frequency below which no electrons are ejected from sodium is approximately \(\(9.27 \times 10^{14}\, \text{Hz}\)\).
c) To calculate the kinetic energy of electrons emitted when yellow light of \(\(\lambda = 600\)\) nm is incident on sodium, we can use the same formula as in part (a):
\(\[E_{\text{max}} = h \cdot \nu - \phi\]\)
Given:
Wavelength of the yellow light \((\(\lambda\))\) = 600 nm \((\(600 \times 10^{-9}\, \text{m}\))\)
Calculate the frequency of the yellow light:
\(\[\nu = \frac{c}{\lambda} = \frac{3 \times 10^8\, \text{m/s}}{600 \times 10^{-9}\, \text{m}} \\\\= 5 \times 10^{14}\, \text{Hz}\]\)
Substitute the values into the equation to calculate \(\(E_{\text{max}}\)\):
\(\[E_{\text{max}} = (6.62607015 \times 10^{-34}\, \text{J}\cdot\text{s}) \cdot (5 \times 10^{14}\, \text{Hz}) - (2.28 \times 1.602176634 \times 10^{-19}\, \text{J})\]\)
After evaluating the equation, we find:
\(\(E_{\text{max}} \approx 2.15 \times 10^{-19}\, \text{J}\)\\\)
Therefore, the kinetic energy of electrons emitted when yellow light of \(\(\lambda = 600\)\) nm is incident on sodium is approximately \(\(2.15 \times 10^{-19}\, \text{J}\)\).
d).
graph is in the image attached
KE is kinetic energy
f is frequency
Wo is work function and h is slope of the graph
fo is critical frequency
slope of the graph will represent plank's constant
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Related Questions
sam, whose mass is 80 kg , takes off across level snow on his jet-powered skis. the skis have a thrust of 170 n and a coefficient of kinetic friction on snow of 0.1. unfortunately, the skis run out of fuel after only 13 s .
Answers
The distance covered by Sam within the first 13 seconds is 96.75 m.
Equation :Given that the mass m of Sam is 80 kg and the force F is 170 N. The coefficient of friction is 0.1.
The net force is given below
Fₙ = F - F₁
Where Fₙ is the net force and F₁ is the friction force.
Fₙ = 170 - μmg
Fₙ = 170 - 0.1 x 80 x 9.8
Fₙ = 91.6
Fₙ = ma
91.6 = 80 x a
a = 91.6 / 80
a = 1.145 m/s²
For the first 13 seconds.
So, the distance covered by Sam with this acceleration is given .
s = ut + 1/2 at²
u is the initial velocity which will be zero and t is the time interval.
So,
s = 1/2 at²
s = 1/2 x 1.145 x 13²
s = 96.75 m
Hence, the distance covered by Sam within the first 13 seconds is 96.75 m.
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Height can be calculated from GPE by
O.5mv^2
O PE/gh
O PE/mg
O mgh
Answers
Height can be calculated from GPE by mgh.
What is GPE?Gravitational energy or gravitational potential energy is the potential energy that a massive object has due to gravity relative to another massive object. It is the potential energy associated with the gravitational field that is released when objects fall towards each other. Gravitational potential energy depends on several things: it depends on the mass of the object, the gravitational acceleration of the object due to the ground, and the displacement of the object from the ground. Gravitational potential energy is measured in joules (J).
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You turn on a car's radio. What energy transformation is taking place?
A. Chemical to kinetic
B. Thermal to kinetic
C. Electrical to sound
D. Nuclear to sound
SUBMIT
Answers
Answer:
I think C like my friend upove
Explanation:
An object is thrown upwards with a velocity of 15 m/s. How long will the ball take to reach it’s starting point ?
Answers
Answer:
about 2s or 3s,
Explanation:
15 m/s - 9.8 m/s = 5.2 m/s (1 sec)
5.2 m/s - 9.8 m/s = -4.6 m/s (2 sec)
What is the molar concentration of sodium phosphate in a 200.0 ml solution prepared from 1.223 g of sodium phosphate (na3po4, 163.9 g/mol), which is a cleaning agent, food additive, and stain remover?
Answers
The molar concentration of sodium phosphate in the 200.0 mL solution is 0.03734 mol/L.
The molar concentration of sodium phosphate in a solution can be calculated using the formula:
Molar concentration (mol/L) = moles of solute / volume of solution (L)
First, we need to calculate the moles of sodium phosphate in the solution. We are given that 1.223 g of sodium phosphate (Na3PO4) is used to prepare a 200.0 mL solution.
To convert grams to moles, we need to divide the given mass by the molar mass of sodium phosphate, which is 163.9 g/mol.
Moles of sodium phosphate = 1.223 g / 163.9 g/mol = 0.007468 mol
Next, we need to convert the volume of the solution from milliliters (mL) to liters (L). Since 1 L is equal to 1000 mL, we divide the given volume by 1000.
Volume of solution = 200.0 mL / 1000 = 0.200 L
Now, we can calculate the molar concentration:
Molar concentration = 0.007468 mol / 0.200 L = 0.03734 mol/L
Therefore, the molar concentration of sodium phosphate in the 200.0 mL solution is 0.03734 mol/L.
Please note that the molar concentration is also referred to as molarity, and it represents the number of moles of solute per liter of solution. In this case, the molar concentration of sodium phosphate tells us the amount of sodium phosphate dissolved in the given solution.
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Is steam gas? If not what is?
Answers
Answer:
steam is a gas
Explanation:
Answer: Steam is an invisible gas, unlike water vapor, which appears as a mist or fog.
Explanation:
A weather balloon has a volume of 100L when it is released from above sea level, where the pressure is 101kPa. What will the balloon's volume when it reaches an altitude where the pressure is 43kPa?
Can someone please help me with this and quick??
Answers
The volume of the balloon is 234.88L.
What is volume?Volume can be defined as the capacity of a solid shape.
To calculate the volume of the balloon, we use the formula below.
Formula:
PV = P'V'.......... Equation 1Where:
P = Initial pressure of the balloonP' = Final pressure of the balloonV' = Initial volume of the balloonV = Final volume of the balloon
Make V' the subject of the equation
V' = PV/P'................. Equation 2From the question,
Given:
P = 101 kPaV = 100 LP' = 43kPaSubstitute these values into equation 2
V' = 101×100/43V' = 234.88 LHence, The volume of the balloon is 234.88L.
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ben is walking along some railroad tracks. he notices that the tracks appear closer together as he looks farther down the tracks until arriving at a single point. what is ben experiencing?
Answers
Ben is experiencing an optical illusion that is a common example of the way our brains interpret visual information to create our perception of the world around us.
Ben is experiencing an optical illusion known as the convergence of parallel lines. When parallel lines are extended into the distance, they appear to converge and eventually meet at a point, creating the illusion of the narrowing of the distance between the lines. This effect is more noticeable in situations where the lines are long, straight, and narrow, such as railroad tracks.
The convergence of parallel lines occurs because of the way our brain processes visual information. Our brain is wired to interpret depth and distance cues, such as the relative size and position of objects, to create a sense of three-dimensional space.
When we look at parallel lines extending into the distance, our brain uses the narrowing of the lines to interpret them as receding into the distance. This interpretation results in the illusion of the convergence of parallel lines.
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6. List three behaviors of light that support the theory that light travels in waves.
Then describe and/or draw each behavior.
Answers
Answer:
Light has the unique property that it can be described in physics as both a wave and as a stream of particles called photons
Explanation:
Answer:
Light has the unique property that it can be described in physics as both a wave and as a stream of particles called photons
Explanation:
\2/2 50.0% complete skip question question an object is placed upright on the axis of a thin convex lens at a distance of four focal lengths (4f) from the center of the lens. an inverted image appears at a distance of 4/3f on the other side of the lens. what is the ratio of the height of the image to the height of the object?
Answers
he genuine picture forms behind center of curvature when an item is positioned halfway between both the center of the curvature and the point of focus. The image appears smaller than the item in terms of size.
What is the concave mirror's center of curvature?
a light-rayed concave mirror. middle of the curve. In geometry, the location of a curve's center of curvature is determined at a point that is located on the normal vector and spaced apart from the curve by an equal amount to a radius of curvature. If indeed the curvature is zero, it refers to the point at infinity. The center of the osculating circle for the curve is located there.
How can the radius of a curve be calculated?
the distant point along the upward ray of a normal vector, in which the curvature radius. It is expressed as follows: where is the tangent direction and is the normal vector.
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PLS ANSWER FAST WILL GIVE BRAINLY!!!!!!
.What are some observations we can make to determine if something has energy?
Answers
Answer:
if somthing is warm or if somthing moves it usally has energy
. If a bicyclist, with an initial velocity of zero, steadily gained speed until reaching a final velocity of 26m/s, how far would she travel during this race?
Answers
The distance the bicyclist would travel during the time of the race is 32.5 m.
What is the distance travelled by the bicyclist?
The distance the bicyclist would travel during the time of the race is calculated by applying the following formula as shown below.
s = ( v + u ) / 2 x t
were;
u is the initial velocity of the bicyclistv is the final velocity of the bicyclistt is the time of motion of the bicyclistThe distance travelled by the bicyclist is calculated as follows;
s = ( 0 m/s + 26 m/s ) / 2 x ( 2.5 s )
s = 32.5 m
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The complete question is below:
If a bicyclist, with an initial velocity of zero, steadily gained speed until reaching a final velocity of 26m/s, how far would she travel during this race if the total time is 2.5 seconds?
Students want to verify that the centripetal acceleration of an object undergoing uniform circular motion with tangential speed v and radius r can be described by the equation ac=v^2/r . In the experiment, the students use a variable speed turntable that can rotate about a pole at its center. A track is attached to the top of the turntable such that a cart of mass m can freely move toward and away from the center pole of the turntable. One end of a force probe is attached to the pole, and the other end is attached to the cart, as shown above. All frictional forces are negligible.
(a) The dot below represents the cart while undergoing uniform circular motion and at the location shown in the figure above. On the dot, draw and label the forces (not components) exerted on the cart. Each force must be represented by a distinct arrow starting on, and pointing away from, the appropriate dot .
Note: Draw the relative lengths of all vectors to reflect the relative magnitudes of all the forces.
(b) Using the experimental apparatus shown above, design an experimental procedure the students could use to verify that the centripetal acceleration of an object undergoing uniform circular motion with tangential speed v and radius r can be described by the equation ac=v^2/r.
i. In the table below, list the quantities and associated symbols that would be measured in the experiment and the equipment used to measure them. Also list the equipment that would be used to measure each quantity. You do not need to fill in every row. If you need additional rows, you may add them to the space just below the table.
Quantity to Be Measured
Symbol for Quantity
Equipment for Measurement
ii. Describe an experimental procedure to verify that the centripetal acceleration of an object undergoing uniform circular motion with tangential speed v and radius r can be described by the equation ac=v^2/r. Give enough detail so that another student could replicate the experiment. As needed, include a diagram of the experimental setup. Assume equipment usually found in a school physics laboratory is available.
iii. State how the measured quantities could be analyzed to verify that the centripetal acceleration of an object undergoing uniform circular motion with tangential speed v and radius r can be described by the equation ac=v^2/r.
(c) In a separate experiment, the students take force probe readings for different turntable speeds, and also measure the time it takes the turntable to make one revolution at each speed. The table shows the results of the students’ measurements. The cart’s center of mass moves in a circle of radius R=0.10 m.
Period
(s)
Force
(N)
0.75
3.5
1.25
1.3
2.0
0.49
2.5
0.32
Indicate two quantities that could be graphed to yield a straight line whose slope could be used to calculate a numerical value for the mass of the cart.
Vertical axis _______________
Horizontal axis _______________
Use the remaining columns in the table, as needed, to record any quantities that you indicated that are not given. Label each column you use and include units.
On the grid, plot the data points you indicated. Clearly scale and label both axes, including units as appropriate.
Answers
Mass is 498 g
Centripetal force causes it to move in a circular motion. The tangential velocity of the cart will increase. Centrifugal force is an opposing force to centripetal force. It will be obvious once the rotation stops exerting centripetal force. The cart will then be propelled by centrifugal force in a direction perpendicular to its trajectory. measurement of inertia, a fundamental property of all matter. In essence, a body of matter is the resistance it provides to a change in its speed or location brought about by the application of a force. The more mass a body possesses, the less change a force exerts results in.
From the graph, slope = 1.966 Ns2
Given r = 0.10 m
Since slope = 4mπ2r
mass = m = slope / 4π2r = 1.966/(4X3.142X0.1) = 0.498 kg = 498 g
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What is
the centripetal acceleration of a car that turns at a circular path with a
speed of 25 m/s where the radius of the curve is 500 m?
Answers
\(a = \frac{{v}^{2}}{r} \)
\(a = \frac{{25}^{2} }{500}\)
\( a = 1.25 \frac{m}{sec^2} \)
Velocity = 25 m/s
Radius = 500 m
We know, centripetal acceleration = Square of velocity / Radius
Therefore, centripetal acceleration
= [(25)^2/500] m/s^2
= [625/500] m/s^2
= 1.25 m/s^2
The answer is 1.25 m/s^2.
A mass of 30.0 kg sits on the London Eye whirled in a vertical circle of radius 10.0 m at a constant speed of 5.0 m s¹. If the mass breaks off at the lowest point of the vertical circle, how far would the mass move in the horizontal direction from the lowest point in 5.0 s? (Neglect air resistance)
Answers
Explanation:
The horizontal distance moved by the mass in 5.0 s is 25 m. The formula for the horizontal distance moved by a mass in a vertical circle is: Horizontal distance = (2πr/T) × t where r = radius of the vertical circle, T = period of the circle, and t = time. Given: r = 10.0 m, T = 2π√(r/g) = 2π√(10.0/9.8) = 6.25 s, t = 5.0 s Therefore, Horizontal distance = (2πr/T) × t = (2π × 10.0/6.25) × 5.0 = 25 m
Where does the force come from that propels a rocket forward?
Answers
Answer:
Newtons law of equal and opposite reactions
Explanation:
This is my best guess I'm sorry if it's not helpful
find the molecular formula of the following
Answers
Answer: hello i am a hacker
Explanation:
magnesium sulphate=(24*1)+(32*1)+(16*4)=120 water=H2O=(1*2)+(1*16)=18 carbon dioxide=CO2=(12*1)+(16*2)=44 ammonia=NH3=(14*1)+(1*3)=17 alminiumsulphate=AL2(SO4)3=(26*2)+(32*3)+(12*16)=340 hydrogen peroxide=H2O2=(1*2)+(16*2)=34 zinc sulphate=ZNSO4=(65*1)+(32*1)+(16*4)=161
As your textbook notes, the paradox of stratification is that inequality is the result of.
Answers
Answer: abundance
Explanation: Paradox Inequality is the result of abundance. intended or unintended consequences of social processes and relationships. prevents social equality, and that this inequality ultimately leads to social conflict.
As your textbook notes, the paradox of stratification is that inequality is the result of the Universal Basic Income.
What is universal basic income ?A sociopolitical idea known as universal basic income proposes that every member of a particular population receive a transfer payment on a regular basis without having to prove their ability to pay.
A legally mandated and equally distributed cash award is provided by the government to all people of a given nation under the sociopolitical financial transfer policy concept known as universal basic income (UBI). Local, regional, or national implementation of a basic income are all possible.
The phenomena of birthweight-specific mortality curves crossing when stratified on other exposures, most notably cigarette smoking, is known as the "birth weight conundrum." The dilemma has received a lot of attention in the literature, and a lot of explanations and fixes have been proposed.
Thus, As your textbook notes, the paradox of stratification is that inequality is the result of the Universal Basic Income.
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A car drives 2 blocks north, then 3 blocks east, and finally 2 blocks south. What is the
displacement of the car?
A) 15 km
B) 3 km west
C) 3 km east
D) 7 km north
Answers
A student is given a sample of matter and asked to determine whether it is an element.
Answers
the fall of a body on the earth's surface cannot be a complete free fall why ?
Answers
Explanation:
because the boy has larger surface area due to which he offers the larger air resistance which decreases the acceleration so, he will fall towards the earth's surface approximately with constant velocity.
The people who write computer programs
Answers
Answer:
Someone who writes software or programs for computers is called a programmer.
Explanation:
Please help me with this!
A student has a mineral sample with a mass of 35g. She then puts 20
mL of water into a graduated cylinder. When she puts the sample
into the cylinder, the water level rises to 30 mL. She then compares
the results to the following:
Augite 3.5 g/cm3
Galena 7.5 g/cm3
Pyrite 5.0 g/cm3
Sphalerite 4.0 g/cm3
Which substance did she find the density for?
Answers
The student finds the density for Augite = 3.5 g/cm³
Mass of the metal = 35g
Volume of water in the graduated cylinder = 20 mL
When the metal is placed in the cylinder filled with water, the water level rises to 30 mL.
So, the volume of the metal = 30 - 20 = 10 mL
1 mL = 1cm³
∴ 10 mL = 10 cm³
Now, we know that,
\(Density = \frac{Mass}{Volume}\)
\(Density = \frac{35g}{10 cm^{3} }\)
\(Density = 3.5 g/cm^{3}\)
Therefore, the student finds the density for Augite = 3.5 g/cm³
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An issue the students encountered is that the marble doesn't land on the launch pad all of the time. To remedy this, they consider constructing a funnel to help direct the marble. How do you suggest the students move forward with their design process in order to find a solution?
A Test funnels of the same size and material with varying sized openings.
B Test funnels of the same shape and size with varying materials.
C Test funnels with identical openings and material with varying size.
D Test all of the above funnels and then construct a funnel with the best design elements from each.
Answers
I suggest that the students move forward with option A.
Test funnels of the same size and material with varying sized openings. This will allow them to determine the optimal size for the opening that will help direct the marble to the launch pad. Once they have determined the optimal size, they can move forward with constructing the funnel with that size opening.
By testing funnels of different sizes, materials, and openings, the students can gather valuable data and insights about how each factor affects the marble's trajectory. This will help them identify the key design elements that contribute to successful landing on the launch pad.
Once the students have tested the various funnels, they can analyze the results and determine which design elements worked best in terms of directing the marble accurately. By combining these successful elements, they can then construct a new funnel that incorporates the best features from each tested funnel. This iterative approach allows them to refine their design and increase the chances of achieving consistent and reliable results.
Therefore, option D provides a comprehensive method for the students to explore different design possibilities, gather data, and ultimately create an improved funnel design.
amanda placed a small television on a metal rolling cart. on her way to the library, her friend carlos stepped in front of the cart. although amanda stopped suddenly, the television stayed in place on the cart. what kept the television on the cart when she stopped suddenly?
Answers
Answer:
Friction. Have a great day! Think positive <3
Answer: Friction
Explanation: It makes sense
An astronaut with mass Ma is within a satellite that orbits Earth at a height H above its surface. Earth has a mass Me & radius Re. Which of the following is a correct expression for the gravitational force exerted on the astronaut by Earth?
Answers
It is to be noted that the correct expression for the gravitational force exerted on the astronaut by Earth on the basis described above is:
Fg=G MeMa/r²e
What is gravitational force?Gravity is a basic interaction in physics that produces mutual attraction between all entities that have mass or energy.
Gravity maintains the planets around the sun and the moon orbiting the Earth. The moon's gravitational pull attracts water, causing ocean tides. Gravity creates stars and planets by attracting the elements that go into their formation.
Gravity waves are 'ripples' in space-time caused by some of the most destructive and powerful occurrences in the Universe. In 1916, Albert Einstein predicted the existence of gravitational waves in his general theory of relativity.
The gravitational force has the lowest non-contact strength in nature. It adheres to the inverse square law. It is always positive. It is directly proportional to the product of the two bodies' masses.
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Which statement best describes an isolated system? (1 point)
Answers
Answer:
An isolated system is a single object that doesn't interact with any other objects. An isolated system has constantly changing energy. As a member, you'll also get unlimited access to over 79,000 lessons in math, English, science, history, and more.
Explanation:
An isolated system is a system in which the mass and energy are not allowed to escape.In open system, energy and mass can transfer and in closed system, only energy can transfer but the mass is conserved.
For an isolated system, the statement "total energy and mass are conserved" should be correct.
In an isolated system:total energy of the system is conserved or it doesn't change.The mass of the system remains constant or it doesn't change.Therefore, for an isolated system, the statement "total energy and mass are conserved" should be correct.
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The head of a 245 g golf club traveling at 62 m/s just before it strikes a 48 g golf ball at rest on a tee. After the collision, the club travels in the same direction at 43 m/s. Use the law of conservation of momentum find the speed of the golf ball just after impact.
Answers
Answer:
The speed of the golf ball just after impact is 96.98 m/s
Explanation:
Given;
mass of the club, m₁ = 245 g = 0.245 kg
initial velocity of the club, u₁ = 62 m/s
mass of the golf ball, m₂ = 48 g = 0.048 kg
initial velocity of the golf ball, u₂ = 0
final velocity of the club, v₁ = 43 m/s
let the final velocity of the golf ball
Apply the law of conservation of momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.245(62) + (0.048 x 0) = 0.245(43) + 0.048v₂
15.19 = 10.535 + 48v₂
15.19 - 10.535 = 48v₂
4.655 = 48v₂
v₂ = 4.655 / 0.048
v₂ = 96.98 m/s
Therefore, the speed of the golf ball just after impact is 96.98 m/s
Given the densities of five objects: 2.00 grams/cm^3, 3.00 grams/cm^3, 4.00 grams/cm^3, 5.00 grams/cm^3, and 6.00 grams/cm^3. How many of these objects would float in water? A)1 B)2 C)3 D)4 E)0
Answers
Givne densities are,
\(\begin{gathered} \rho_1=2\text{ g/}cm^3 \\ \rho_2=3\text{ g/}cm^3 \\ \rho_3=4\text{ g/}cm^3 \\ \rho_4=5\text{ g/}cm^3 \end{gathered}\)The density of water is ρ=1 g/cm³.
Any object will float if the denisty of the object is less than the density of water, if the density of object is greater than the dnesity of water, then the object sink in the water.
In the given case, all the objects have density greater than the density of water. Therefore, all the objects will sink in the water.
Thus, option E is corret, no object will flot on the water.
When the switched on, what type of energy is moving through circuit ?
A= kinetic
b= chemical
C = potential
D= radiation (light)
E= thermal (heat)
F=Electrical
G= Nuclear
Answers
Answer:
The correct option is;
F-Electrical
Explanation:
The energy moves through an electric circuit when the we put on the switch to allow the flow of current is electrical energy, which is the energy that is obtained from the existence of an electric potential difference (the kinetic energy of flowing electrons) in the completed circuit, that results in the flow of electrons from the negative to the positive terminals, and the flow of the electric current in the opposite direction.