What is the length of sides of the square shown below?
45
90⁰
A
B. 4-2
C. 1
D. 2.2
E 2
OF. 4

Answer:

23/26 1 3/26

Step-by-step explanation:

you make to where all the denmanters are the same and add

The minimum sample size required to be 75% confident that the sample mean is within 20 units of the population mean is 24.

To determine the minimum sample size required for 75% confidence that the sample mean is within 20 units of the population mean, you will need to use the formula for sample size calculation in a normally distributed population:
n = (Z * σ / E)^2
where:
n = sample size
Z = Z-score corresponding to the desired confidence level (75%)
σ = population standard deviation (327.8)
E = margin of error (20 units)
First, find the Z-score for a 75% confidence level. This value is 1.15 (you can find it in a Z-table or using statistical software).
Next, plug in the values into the formula:
n = (1.15 * 327.8 / 20)^2
n ≈ 23.27
Since the sample size should be a whole number, round up to the nearest whole number:
n = 24

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Answer:

5000.

Step-by-step explanation:

It is given that Michael put aside a fixed amount of money every month to pay off his debt. He also puts the entirety of his bonus towards paying off his debt.

He gets signing bonus once. So, there is no effect of month on amount of bonus.

The expression which represents the size of his debt after m months is

\(36,700-(5000+500m)\)

Here,

m is number of months.

500 is fixed amount of money every month to pay off his debt.

36,700 is student debt.

5000 is signing bonus.

Therefore, number 5000 describes the value of his signing bonus.

Answer:

y = 12x + -10

Step-by-step explanation:

sorry if its wrong i tried

Answer:

27

Step-by-step explanation:

The centroid divide a median in two parts, with ratio 1/3 and 2/3.

In particular the part between the centroid and the point where the median touches the side is 1/3 of the median.

We can build this proportion:

ST : 1/3 = IT : 3/3

9 : 1/3 = IT : 1

IT = 9 * 3 = 27

That means , Seth gain loss of  $261 on his selling stocks.

Last month, Seth made money by selling stocks. His investment income was $401 This month, Seth's investment income is −$261 What does this mean?

Profit(P)

The amount gained by selling a product for more than its cost price.

Loss(L)

The amount the seller incurs after selling the product less than its cost price is mentioned as a loss.

Cost Price (CP)

The amount paid for a product or commodity to purchase is called a cost price. Also, denoted as CP. This cost price is further classified into two different categories:

Fixed Cost: The fixed cost is constant, it doesn’t vary under any circumstances

Variable Cost: It could vary depending on the number of units and other factors

Selling Price (SP)

The amount for which the product is sold is called the Selling Price. It is usually denoted as SP. Also, sometimes called a sale price.

Marked Price Formula (MP)

This is basically labelled by shopkeepers to offer a discount to the customers in such a way that,

Discount = Marked Price – Selling Price

And Discount Percentage = (Discount/Marked price) x 100

Profit and Loss Formulas

Now let us find the profit formula and loss formula.

The profit or gain is equal to the selling price minus the cost price.

Loss is equal to the cost price minus the selling price.

Profit or Gain = Selling price – Cost Price

Loss = Cost Price – Selling Price

The formula for the profit and loss percentage is:

Profit percentage (P%) = (Profit /Cost Price) x 100

Loss percentage (L%) = (Loss / Cost price) x 100

Last month

Seth made money by selling stocks.

His investment income was $401

That means , Seth gain profit of $401 on his selling stocks.

This month

Seth's investment income is −$261

That means , Seth gain loss of  $261 on his selling stocks.

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1. The probability of selecting exactly one tank with high-viscosity material is 0.

2. The probability of selecting at least one tank with high-viscosity material is 1.

3. The probability of selecting exactly one tank with high-viscosity material and exactly one tank with high impurities is 0.25.

1. The probability of selecting exactly one tank with high-viscosity material is calculated by the binomial distribution formula, P(X = n) = (nCx)p^x(1-p)^n-x, where n is the number of trials, x is the number of successes, and p is the probability of success. In this case, n = 4, x = 1, and p = 24/24 = 1. Therefore, P(X = 1) = (4C1)1^1(1-1)^4-1 = 0.

2. The probability of selecting at least one tank with high-viscosity material is calculated by the complement rule, P(X > 0) = 1 - P(X = 0). In this case, P(X > 0) = 1 - (4C0)1^0(1-1)^4-0 = 1.

3. The probability of selecting exactly one tank with high-viscosity material and exactly one tank with high impurities is calculated by the binomial distribution formula, P(X = n) = (nCx)p^x(1-p)^n-x, where n is the number of trials, x is the number of successes, and p is the probability of success. In this case, n = 8, x = 2, and p = 24/24 = 1. Therefore, P(X = 2) = (8C2)1^2(1-1)^8-2 = 0.25.

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The length along the side of the barn of this rectangular plot is 150 feet.

The rectangle's area is the area enclosed by its perimeter and equals the product of its length and width. The space that is occupied within the boundaries of a rectangle is known as its area. It is calculated by finding the length divided by the width.

In order to maximize the area of the rectangular plot, the length of the fence will be twice the length of the width. Therefore, the width is 75 x 4 / 3 feet = 100 feet (since there are 75 sections of 4 feet each, and 3 sides of the rectangle are fenced, not just 2).

The length is twice the width, so the length is 2 x 100 feet = 200 feet.

Since the barn forms one side of the rectangle, the length along the barn is 150 feet (200 - 50 = 150).Thus, the length along the side of the barn of this rectangular plot is 150 feet.

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The measure of the central angle indicated is 270 degrees

The term "diameter" refers to a straight line segment that passes through the center of a circle or a sphere, connecting two points on the circumference or surface of the circle or sphere. In other words, it is the longest distance that can be measured between two points on the edge of the circle or sphere, passing through its center.

To find the measure of the central angle indicated, we need to first identify the endpoints of the diameter that contains points W, T, and X. Let's assume that this diameter is WX. Then, we can find the measure of the central angle WTX by finding the measure of the arc WT and dividing it by 2.

We know that the diameter WX passes through the midpoint of segment VT, which we can find by averaging the coordinates of V and T. Using the coordinates given in the diagram, we have:

V: (9x-2, 15x+10)

T: (15x+10, 9x-2)

Midpoint of VT: ((9x-2 + 15x+10)/2, (15x+10 + 9x-2)/2)

= (12x + 4, 12x + 4)

Since this midpoint lies on the diameter WX, we can find the coordinates of point X by reflecting the midpoint across the y-axis:

X: (-12x - 4, 12x + 4)

Now we can find the measure of the arc WT by finding the difference between the angles formed by radii WT and WX. Let's call the center of the circle O:

m∠WOT = 90 degrees (since WT is a diameter)

m∠WOX = 180 degrees (since WX is a diameter)

m∠TOX = m∠WOT - m∠WOX = -90 degrees

To convert this angle to a positive measure, we can add 360 degrees:

m(arc WT) = m∠WOT - m∠TOX + 360 degrees = 90 degrees - (-90 degrees) + 360 degrees = 540 degrees

Finally, we can find the measure of the central angle WTX by dividing the measure of arc WT by 2:

m∠WTX = m(arc WT)/2 = 540 degrees/2 = 270 degrees

Therefore, the measure of the central angle indicated is 270 degrees

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Answer:

420 69

Step-by-step explanation:

620 +90 = 42069

Answer: C. are perpendicular

Step-by-step explanation:

I took the test and got it right

Step-by-step explanation:volume = 0.5 * b * h * length , where b is the length of the base of the triangle, h is the height of the triangle, and length is prism length

Answer:

C

Step-by-step explanation:

Yes, ACD = BCD by AAS since they have 2 congruent angles & share a side.

The following are the solutions to the given problem:

a). Given the function,  f(x) = 2√x-3. Parent Function:  f(x)=√x. The 2 affects the function by: It affects the function vertically by vertically stretching it by a factor of 2.The -3 affects the function by: It affects the function horizontally by shifting it to the right by 3.

b). Given the function,  f(x)=+2. Parent Function:  g(x)=√x. The 2 affects the function by: It affects the function vertically by vertically shifting it upward by 2 units.

c). Given the function, f(x) = |x-1| +2. Parent Function:  f(x)=|x|. List all transformations: The -1 affects the function by: It affects the function horizontally by shifting it to the right by 1 unit. The 2 affects the function by: It affects the function vertically by shifting it upward by 2 units.

d). Given the function, f(x) = -2√x+3. Parent Function:  f(x)=√x. List all transformations: The -2 affects the function by: It affects the function vertically by vertically reflecting it and vertically stretching it by a factor of 2.The 3 affects the function by: It affects the function horizontally by shifting it to the right by 3 units.

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The average lengths of gestational periods differ between species A and B. The p-value is less than α, we reject the null hypothesis.

The null hypothesis and the alternative hypothesis are given as follows:

Null Hypothesis: H0: µA = µB, The average gestation periods of both species are equal.

Alternative Hypothesis: Ha: µA ≠ µB, The average gestation periods of both species are different.

Now we need to calculate the test statistic:

The formula for the test statistic is:

\(t = ( \bar x A - \bar x B) / √[(s^{2} A / n A) + (s^{2} B / n B)]\)

Where s²A and s²B are the sample variances.

Substituting the given values:

We have the test statistic as:

\(t = (11 - 17) /\sqrt{(3.8² / 15) + (2.4² / 24)} \approx -6.99\)

Since the sample sizes are greater than 30, we can assume normality of the distributions and use the standard normal distribution to find the p-value.

The p-value for a two-tailed test at a 0.01 level of significance is approximately less than 0.001.

Therefore, the p-value is p < 0.001.

Since the p-value is less than α, we reject the null hypothesis.

We can conclude that the average lengths of gestational periods differ between species A and B.

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The probability that the digit that is received (after having been transmitted across the 4 channels) is 0.3645

In communication systems, it is common to face the challenge of transmitting information accurately over a noisy channel. In this scenario, errors can occur during transmission, and it is essential to quantify the probability of receiving the correct information at the end of the channel.

In this problem, we are asked to calculate the probability that the digit received after transmitting a 0 across four channels is also a 0. We know that each channel can either transmit the digit correctly with probability 0.9 or incorrectly with probability 0.1. Therefore, we can use the concept of conditional probability to solve this problem.

Using Bayes' theorem, we can rewrite this as:

P(CCCC | 0 received) x P(0 received) / P(CCCC)

Here, P(CCCC | 0 received) represents the probability that all four channels transmitted the 0 correctly, given that a 0 was received. This probability can be calculated as:

P(CCCC | 0 received) = P(C) x P(C | C) x P(C | C | C) x P(C | C | C | C)

Substituting the given probabilities, we get:

P(CCCC | 0 received) = 0.9 * 0.9 * 0.9 * 0.9 = 0.6561

Similarly, we can calculate the probability of receiving a 0 in general as:

P(0 received) = P(CCCC | 0 received) x P(0) + P(IIII | 0 received) x P(1)

where P(IIII | 0 received) represents the probability that all four channels transmitted the digit incorrectly, given that a 0 was received. This probability can be calculated similarly as:

P(IIII | 0 received) = P(I) * P(I | I) x P(I | I | I) x P(I | I | I | I) = 0.1 x 0.1 x 0.1 x 0.1 = 0.0001

Substituting the given probabilities, we get:

P(0 received) = 0.6561 x 0.5 + 0.0001 x 0.5 = 0.3281

Finally, we can calculate the denominator P(CCCC) as:

P(CCCC) = P(CCCC | 0 received) x P(0) + P(CCCC | 1 received) x P(1)

where P(CCCC | 1 received) represents the probability that all four channels transmitted the digit correctly, given that a 1 was received. This probability can be calculated similarly as:

P(CCCC | 1 received) = P(I) x P(I | C) x P(I | C | C) x P(I | C | C | C) = 0.1 x 0.9 x 0.9 x 0.9 = 0.0729

Substituting the given probabilities, we get:

P(CCCC) = 0.6561 * 0.5 + 0.0729 * 0.5 = 0.3645

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                              1000/2000 will be 0.5 :)

\(\\ \sf\longmapsto \dfrac{1000}{2000}\)

\(\\ \sf\longmapsto \dfrac{100}{200}\)

\(\\ \sf\longmapsto \dfrac{10}{20}\)

\(\\ \sf\longmapsto \dfrac{1}{2}\)

\(\\ \sf\longmapsto 0.5\)

Answer:

16, 32, 64

Step-by-step explanation:

There is a common ratio between consecutive terms, that is

2 ÷ 1 = 4 ÷ 2 = 8 ÷ 4 = 2

Thus to obtain any term in the sequence multiply the previous term by 2

a₅ = a₄ × 2 = 8 × 2 = 16

a₆ = a₅ × 2 = 16 × 2 = 32

a₇ = a₆ × 2 = 32 × 2 = 64

After considering the given data we conclude that the the critical points of the function \(f(x)=3x+4x^3\)  are \(x=\pm \frac{1}{2}\)​, and the function is increasing on all intervals. Therefore, the critical points are neither local maxima nor local minima.

To determine the critical points and intervals of increase and decrease for the function \(f(x)=3x+4x^3\)
we need to find the first derivative of the function and set it equal to zero to find the critical points.
\(f'(x)=3+12x^2\)
Setting f'(x)=0, we get:
\(12x^2+3=0\)
Solving for x, we get:
\(x=\pm \frac{1}{2}\)These are the critical points of the function.
To determine the intervals of increase and decrease, we need to test the sign of the first derivative in the intervals between and around the critical points.
Testing the interval \(\left(-\infty,-\frac{1}{2}\right)\)
, we choose a test point x=-1
\(f'(-1)=3+12(-1)^2=15 > 0\)
Therefore, the function is increasing on the interval \(\left(-\infty,-\frac{1}{2}\right)\)
Testing the interval \((-\frac{1}{2}, \frac{1}{2} \right))\) , we choose a test point x=0
\(f'(0)=3+12(0)^2=3 > 0\)
Therefore, the function is increasing on the interval \(\left(-\frac{1}{2},\frac{1}{2}\right)\)
Testing the interval \(\left(\frac{1}{2},\infty\right)\)
\(f'(1)=3+12(1)^2=15 > 0\)
Therefore, the function is increasing on the interval \(\left(\frac{1}{2},\infty\right)\)
Since the function is increasing on all intervals, the critical points are neither local maxima nor local minima.
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Answer:8^1/3 and 5^-2

Step-by-step explanation:

8^1/3=2

5^-2=1/25 or 0.04

Answer:

She earned $20 in tips.

Step-by-step explanation:

First, you need to work out how much pay she'd get for 12 hours work:

12 x $11.25 = $135 for 12 hours work

Then, find out 2/5 of $11.25 to find out how much she would get for the 2/5 of an hour she worked:

2/5 of $11.25 = $4.50

Add both these sums together to get her total pay for hours worked:

$135 + $4.50 = $139.50

Subtract that sum from her total pay to find out how much money she earned in tips:

$159.50 - $139.50 = $20

Answer:

y = 8.7

Step-by-step explanation:

Assuming we can use decimal places, y is equal to 8.7.

In programming, += is often used as a substitute for y = y + x (example)

Therefore, y = y + 3.7, and since y = 5, y = 5 + 3.7, y = 8.7

We can conclude that no nontrivial linear combination of v1, v2, ..., vm equals the zero vector, which proves that the list v1, v2, ..., vm is linearly independent.

To prove that the list of vectors v1, v2, ..., vm is linearly independent, given that the list v1 + 0, v2 + 0, ..., vm + 0 is linearly independent, we need to show that no nontrivial linear combination of v1, v2, ..., vm equals the zero vector.

Since the list v1 + 0, v2 + 0, ..., vm + 0 is linearly independent, it implies that no nontrivial linear combination of v1 + 0, v2 + 0, ..., vm + 0 equals the zero vector. We can express this as:

c1(v1 + 0) + c2(v2 + 0) + ... + cm(vm + 0) = 0

Expanding the above expression, we get:

(c1v1 + c2v2 + ... + cmvm) + (c10 + c20 + ... + cm0) = 0

Since the list v1, v2, ..., vm is linearly independent, it implies that the first term c1v1 + c2v2 + ... + cmvm must be the zero vector. However, the second term (c10 + c20 + ... + cm0) is zero since all the constants are multiplied by zero.

Therefore, we can conclude that no nontrivial linear combination of v1, v2, ..., vm equals the zero vector, which proves that the list v1, v2, ..., vm is linearly independent.

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It is incorrect to say that the sum of a rational and an irrational number is always irrational (A) or always rational (B). Similarly, it is incorrect to say that the sum is never irrational (C). The correct statement is that the sum of a rational and irrational number is sometimes a rational number (D).

The correct answer is D. The sum of a rational and irrational number is sometimes a rational number.

To understand why, let's consider an example. Let's say we have a rational number, such as 2/3, and an irrational number, such as √2.

When we add these two numbers together: 2/3 + √2

The result is a sum that can be rational or irrational depending on the specific numbers involved. In this case, the sum is approximately 2.94, which is an irrational number. However, if we were to choose a different irrational number, the result could be rational.

For instance, if we had chosen π (pi) as the irrational number, the sum would be:2/3 + π

In this case, the sum is an irrational number, as π is irrational. However, it's important to note that there are cases where the sum of a rational and an irrational number can indeed be rational, such as 2/3 + √4, which equals 2.

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Answer:

D. (2 , 1)

Step-by-step explanation:

STEP 1: Replace all occurrences of \(y\) with \(-3x+7\) in each equation.

\(-x+14=12\\y=-3x+7\)

STEP 2: Solve for \(x\) in the first equation.

\(x=2\\y=-3x+7\)

STEP 3: Replace all occurrences of \(x\) with \(2\) in each equation.

\(y=1\\x=2\)

We integrate each component separately over the given limits of t. Evaluating the integral for each component will yield the final result of the line integral of F along the line segment C from (0, 0, 0) to (4, 3, 2).

A line integral is a way to calculate the work done by a force along a curve. In this case, we have the vector field F = xeyz and the curve C, which is the line segment from (0, 0, 0) to (4, 3, 2). The line integral of F along C can be written as ∫CF · dr, where dr is the differential vector along the curve.

To evaluate this line integral, we parameterize the curve C. Since C is a line segment, we can use a linear parameterization. Let's denote the parameter as t, ranging from 0 to 1. We can express the coordinates of C as x = 4t, y = 3t, and z = 2t.

Next, we need to find the differential vector dr along curve C. Taking the derivatives of the parameterized equations with respect to t, we obtain dx = 4dt, dy = 3dt, and dz = 2dt. Hence, dr = (dx, dy, dz) = (4dt, 3dt, 2dt).

Substituting these values into the line integral, we have ∫CF · dr = ∫CF(x, y, z) · (4dt, 3dt, 2dt). Simplifying the expression, we get ∫C(4xeyz dt, 3xeyz dt, 2xeyz dt).

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The Volume of the Pyramid=19.19in³

Surface Area of  the Pyramid=48.65in²

Volume is a unit of measurement for the area occupied in three dimensions. It is widely quantified and measured using SI-derived units, alternative imperial units, or US standard units (such as the gallon, quart, cubic inch). Volume and length (cubed) have a similar meaning.

First, volume was calculated using naturally occurring vessels with a similar shape, and then using standardized containers. Calculating the volume of numerous common three-dimensional forms is made simple by arithmetic formulas. The volumes of increasingly complicated shapes can be calculated using integral calculus.

Given that,

Height of the pyramid =4.7

Pyramid's slant height= 5.2

Base of pyramid is a square with side=3.5

Volume of the pyramid=(1/3)(3.5×3.5)×(4.7)

=19.19 in³

The surface area of a pyramid=((1/2)×(4×3.5)×5.2)+(3.5×3.5)

=18.65in²

Therefore, the volume of the pyramid=19.19 in³

And the surface area of the pyramid=18.65in²

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The expressions when simplified are -9 - 2i and x = ±8i

From the question, we have the following parameters that can be used in our computation:

(6 -7i) - (8 - 5i) - 7

When evaluated, we have

(6 -7i) - (8 - 5i) - 7 = -9 - 2i

Here, we have

6x² = -384

Divide by 6

x² = -64

Take the square roots

x = ±8i

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The measurement closest to this value is 4,289.3 m³, which is approximately equal to 4,289,300,000 cubic inches.

A mathematical constant is a fixed number that has a specific mathematical value and is used in mathematical calculations. Some of the well-known mathematical constants include:

π (pi): the ratio of the circumference of a circle to its diameter, approximately equal to 3.14159.

2.71828 is a close approximation for the mathematical constant e, often known as Euler's number. It is utilized in various branches of mathematics, such as statistics, probability, and calculus.

i, stands for the imaginary unit, which is -1 squared.

The diagram for the sphere indicates that its radius is 8 meters. However, the answer choices are given in cubic inches. Therefore, we need to convert the units of measurement from meters to inches before calculating the volume of the sphere.

1 meter is equal to 39.37 inches, so the radius of the sphere in inches is:

8 meters * 39.37 inches/meter = 314.96 inches

The following formula can be used to determine a sphere's volume:

V = (4/3) * π * r³

where V is the volume, r is the radius, and (pi) is a mathematical constant that equates to roughly 3.14159.

Substituting the value of the radius in inches, we get:

V = (4/3) * π * (314.96 inches) ³

V ≈ 4.18879 * 10⁹ cubic inches

Rounding this value to the nearest thousand, we get:

V ≈ 4,188,790,000 cubic inches

Therefore, the correct answer is: C) 4289.3 m³.

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The answer to the given linear programming problem, which is solved using the simplex method, is as follows:

The optimal solution to minimize the objective function Z = X1 + 2X2 is X1 = 20 and X2 = 0, with the objective function value Z = -100.

To solve the problem, we'll first convert the inequalities to equations by introducing slack and surplus variables. Then we'll set up the initial simplex tableau and iterate through the simplex algorithm until we reach an optimal solution.

⇒ Convert the inequalities to equations:

A. X1 + 3X2 + S1 = 90 (where S1 is the slack variable)

B. 8X1 + 2X2 + S2 = 160 (where S2 is the slack variable)

C. 3X1 + 2X2 + S3 = 120 (where S3 is the slack variable)

D. X2 + S4 = 70 (where S4 is the surplus variable)

⇒ Set up the initial simplex tableau:

        | X1 | X2 | S1 | S2 | S3 | S4 | RHS |

----------------------------------------------

Z       | -1 | -2 |  0 |  0 |  0 |  0 |  0  |

----------------------------------------------

S1      |  1 |  3 |  1 |  0 |  0 |  0 | 90  |

S2      |  8 |  2 |  0 |  1 |  0 |  0 | 160 |

S3      |  3 |   2 |  0 |  0 |  1 |  0 | 120 |

S4      |  0 |   1 |  0 |  0 |  0 | -1 | 70  |

⇒ a) Select the most negative coefficient in the Z row, which is -2. Choose the corresponding column as the pivot column (X2 column).

b) Find the pivot row by selecting the minimum ratio of the RHS value to the positive values in the pivot column. The minimum ratio is 70/1 = 70. Thus, the pivot row is S4.

c) Perform row operations to make the pivot element (1 in S4 row) equal to 1 and eliminate other elements in the pivot column:

  - Divide the pivot row by the pivot element (1/1 = 1).

  - Replace other elements in the pivot column using row operations:

    - S1 row: S1 = S1 - (1 * S4) = 90 - 70 = 20

    - Z row: Z = Z - (2 * S4) = 0 - 2 * 70 = -140

    - S2 row: S2 = S2 - (0 * S4) = 160

    - S3 row: S3 = S3 - (0 * S4) = 120

d) Update the tableau with the new values:

        | X1 | X2 | S1 | S2 | S3 | S4 | RHS |

----------------------------------------------

Z       | -1 |  0 |  0 |  0 |  2 | -2 | -140|

----------------------------------------------

S1      |  1 |  3 |  1 |  0 |  

0 |  0 | 20  |

S2      |  8 |  2 |  0 |  1 |   0 |  0 | 160 |

S3      |  3 |  2 |  0 |  0 |   1 |  0 | 120 |

S4      |  0 |  1 |  0 |  0 |   0 | -1 | 70  |

e) Repeat steps a to d until all coefficients in the Z row are non-negative.

  - Select the most negative coefficient in the Z row, which is -1. Choose the corresponding column as the pivot column (X1 column).

  - Find the pivot row by selecting the minimum ratio of the RHS value to the positive values in the pivot column. The minimum ratio is 20/1 = 20. Thus, the pivot row is S1.

  - Perform row operations to make the pivot element (1 in S1 row) equal to 1 and eliminate other elements in the pivot column.

  - Update the tableau with the new values.

f) The final simplex tableau is:

        | X1 | X2 | S1 | S2 | S3 | S4 | RHS |

----------------------------------------------

Z       |  0 |  0 |  0 |  0 |  1 | -3 | -100|

----------------------------------------------

X1      |  1 |  3 |  1 |  0 |  0 |  0 | 20  |

S2      |  0 | -22 | -8 |  1 |  0 |  0 | 140 |

S3      |  0 | -7 | -3 |  0 |  1 |  0 | 60  |

S4      |  0 |  1 |  0 |  0 |  0 | -1 | 70  |

⇒ Read the solution from the final tableau:

The optimal solution is X1 = 20 and X2 = 0, with the objective function value Z = -100.

To know more about the simplex method, refer here:

https://brainly.com/question/30387091#

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