what is the equivalent to 18/18?

Answer:

3x-y=15 should be the answer

Answer:

4

Step-by-step explanation:

this line is congruent to EC on the base

Answer:

a) \(\sqrt{56\) → Definitely not undefined because 56 is a positive real number

b) \(-\sqrt{56\) → Definitely not undefined because 56 is a positive real number (and the negative sign is not under the square root)

c) \(\sqrt{-56\) → Definitely undefined because -56 is a negative number

__

We know that there is no real square root of a negative number because nothing multiplied by itself results in a negative number.

__

d) \(\sqrt h\) → Could be undefined because we don't know the value of \(h\); it could be positive or negative

e) \(-\sqrt {h\) → Could be undefined because we don't know the value of \(h\); it could be positive or negative (and the negative sign doesn't affect this because it is outside the square root)

f) \(\sqrt{-h\) (when \(h\) is positive) → Definitely undefined because the value inside of the square root is negative (a negative times a positive is a negative)

No, rectangle DABC is not the result of a dilation of rectangle HEFG with a center of dilation at the origin.

Dilation is a geometrical transformation that changes the size of a shape or figure. It is one of the four basic transformations of geometry alongside translation, rotation, and reflection. Dilation involves resizing a shape by a scale factor and keeping its overall shape intact. The scale factor is the ratio of the size of the image to the size of the original figure.

Dilation involves a scaling of a shape, where each point on the shape is moved away from or closer to the center of dilation, proportional to its distance from the center. In this case, the angles of rectangle DABC are different from the angles of rectangle HEFG, so it is not the result of a dilation. The angles of rectangle HEFG are ∠2, ∠33, ∠EDC, whereas the angles of rectangle DABC are ∠ADB, ∠BDC, and ∠CDB.

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Answer:

Marcy's math class starts at 9:35.

Step-by-step explanation:

11:55

 -50  = 11:05     This gets rid of 50 minutes of math class.

11:05

  -30 = 10:35     This gets rid of the 30 minutes of recess.

Now subtract one more hour to subtract the remainder of math class, and you get 9:35. Marcy's math class starts at 9:35.

In other words, the triangles are consistent if the hypotenuse and one of the legs of one right triangle agree with the hypotenuse and one of the legs of another right triangle.

Congruent triangles are two triangles that are the same size and shape. Two congruent triangles remain congruent even if we flip, turn, or rotate one of them. Two triangles must have the same angles and, as a result, must be congruent if their sides are the same.

Two right triangles are supposed to be consistent on the off chance that they are of a similar shape and size. All in all, two right triangles are supposed to be consistent in the event that the proportion of the length of their comparing sides and their relating points is equivalent.

Right triangles are harmonious in the event that both the hypotenuse and one leg are a similar length. These triangles are harmonious by HL or hypotenuse leg.

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The correct statement are:

Based on the given information, we can make the following conclusions:

A. The interquartile range for high school students is smaller than college students.

The statement is False

B. The mean for high school students is smaller than college students.

The statement is False because the mean of College is 25.28 and mean for High school is 30.4.

C. The range for high school students is larger than college students.

The statement is True .

D. The college median is equal to the high school median.

The statement is True because the median for both is 24..

E. The mean absolute deviation is larger for college students than high school students.

The statement is False.

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The spatial scale at which the data was collected is the distance from the shore of Lake Erie.

We can see that the data shows a gradual decline in snowfall totals with increasing distance from the shore of Lake Erie. The decline starts at around 425 cm at 0 km and decreases to 375 cm by 30 km. It then decreases more quickly over the next 20 km before declining relatively consistently out to 100 km, where the snowfall is 150 cm.

The graph shows the declining snowfall totals with increasing distance from the shore of Lake Erie, starting from 0 km and ending at 100 km. The data points are measured in increments of 10 km, with the total snowfall measured in cm.

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Answer:

  (d)  vertical angles theorem

Step-by-step explanation:

Vertical angles have a common vertex and are formed from opposite rays.

__

Angles RQT and PQS share vertex Q, Rays QR and QP are opposite, creating line RP. Rays QT and QS are opposite, creating line ST. Hence angles RQT and PQS are vertical angles. The vertical angles theorem says those angles are congruent.

Answer:

Step-by-step explanation:

Solve for

y

y

.

Tap for more steps...

y

=

−

9

+

3

x

y

=

-

9

+

3

x

Rewrite in slope-intercept form.

Tap for more steps...

y

=

3

x

−

9

y

=

3

x

-

9

Use the slope-intercept form to find the slope and y-intercept.

Tap for more steps...

Slope:

3

3

y-intercept:

−

9

-

9

Any line can be graphed using two points. Select two

x

x

values, and plug them into the equation to find the corresponding

y

y

values.

Tap for more steps...

x

y

2

−

3

3

0

x y 2 -3 3 0

Graph the line using the slope and the y-intercept, or the points.

Slope:

3

3

y-intercept:

−

9

-

9

x

y

2

−

3

3

0

x y 2 -3 3 0

image of graph

Answer:

10) -1.5

11) 1

Step-by-step explanation:

Hope this helps! Pls give brainliest!

=============================================

Work Shown:

(zinc)/(copper) = 3/14

(x grams of zinc)/(574 grams of copper) = 3/14

x/574 = 3/14

14x = 574*3

x = 574*3/14

x = 123 grams of zinc

Given that a card is drawn at random from a standard deck of cards. We are asked to find the probabilities of

1) A queen or a spade.

2) A black or a face card.

3) A red queen.

This can be seen below;

Explanation

The formula for the probability of an event is given as;

For a given deck of cards, the number of total possible outcomes is 52 different cards. Next, we find the number of events for each case

Therefore we can find the probability in each case. Recall that "or" in probability implies we will add the values of the probabilities we are comparing.

1) A queen or a spade

Answer

2) A black or a face card

Answer:

3) A red queen

Answer

Answer: nope!

Step-by-step explanation: there are 4 quarts in a gallon and we can see by adding the mango juice, there will be no space!

Water (2 quarts) mango juice (2 quarts) equals a gallon

Ginger ale = one gallon

That’s already 2 gallons and we still have the 2 pints of pineapple juice!

The final step when solving the given math problem is:

Take the fifth root of both sides: x = \(((y^2)/19)^(^1^/^5)\)

To solve √19x^5 for x, follow these steps:

Isolate the square root term: \(\sqrt{19x^5}\) = y (Let y be the other side of the equation)

Square both sides: \((y^2) = 19x^5\)

Divide both sides by 19: \((y^2)/19 = x^5\)

Take the fifth root of both sides: x = \(((y^2)/19)^(^1^/^5^)\)

The square root of a number is a value that, when multiplied by itself, gives the original number. It is denoted by the symbol √ and can be found using mathematical operations.

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a. The number of disappointed customers is 157. b. Unsold dolls = 135. c. The dolls needed per week is 660. d. The price of $0.63 will make the supply of the doll tight. e. The price at which the demand and supply will be at equilibrium is $3.20.

A mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable). In mathematics, functions exist everywhere, and they are crucial for constructing physical links in the sciences.

a. The supply and the demand associated from the graphs are:

Supply: 95(2.50) - 60 = 178

Demand: -130(2.50) + 660 = 335

Subtracting the Demand and supply:

335 - 178 = 157

The number of disappointed customers is 157.

b. For unsold dolls set the equation for supply and demand:

Supply: 95(3.80) - 60 = 301

Demand: -130(3.80) + 660 = 166

Subtract the value of demand and supply:

301 - 166 = 135

Unsold dolls = 135

c. To give the dolls away, the cost of the doll is $0.

The demand equation thus becomes:

y = -130(0) + 660

y = 660

The dolls needed per week is 660.

d. Let the supply be 0.

y = 95x - 60

0 = 95x -60

x = $0.63

The price of $0.63 will make the supply of the doll tight.

e. The supply an demand will be in equilibrium when Demand = Supply, that is:

95x - 60 = -130x + 660

95x + 130x = 720

225x = 720

x = $3.20

The price at which the demand and supply will be at equilibrium is $3.20.

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Answer:

temperature ≤ 6

Step-by-step explanation:

The highest temperature in February was 6°F. Write and graph an inequality to represent this situtation.

If the maximum temperature was 6, then the temperature reached no more than six, while still reaching 6.  Thus, the inequality should be

temperature ≤ 6

The graph would be a filled dot on the 6 pointing towards the left side of the graph (towards the -10 side)

\( \frac{b}{4} + 2 = - 1\)

\( \frac{b}{4} = - 1 - 2 = - 3\)

\(b = - 3 \times 4 = - 12\)

Answer: -12

ok done. Thank to me :>

The vector  is parallel to the plane the vector <3, -1, 2> is not orthogonal to the normal vector of the plane 6x - 2y + 4z = 1

To determine if the vector <3, -1, 2> is parallel to the plane 6x - 2y + 4z = 1, we need to check if the vector is orthogonal (perpendicular) to the normal vector of the plane.

Find the normal vector of the plane.
The normal vector of a plane is given by the coefficients of x, y, and z in the equation of the plane. In this case, the normal vector is <6, -2, 4>.

Check if the given vector is orthogonal to the normal vector.
Two vectors are orthogonal if their dot product is equal to 0. Let's compute the dot product between the given vector <3, -1, 2> and the normal vector <6, -2, 4>:

Dot product = (3 * 6) + (-1 * -2) + (2 * 4) = 18 + 2 + 8 = 28

Since the dot product is not equal to 0 (28 ≠ 0), the given vector <3, -1, 2> is not orthogonal to the normal vector of the plane.

The vector <3, -1, 2> is not orthogonal to the normal vector of the plane 6x - 2y + 4z = 1, which means it is parallel to the plane.

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The individual values contained in an array are known as elements.

An array is a data structure that allows you to store multiple values of the same data type in a single variable. Each value within the array is assigned a unique index or position, starting from 0 for the first element. These elements can be accessed and manipulated using their respective indices.

By organizing related data into an array, it becomes easier to perform operations on the entire set of values or access specific elements based on their positions. Elements in an array can be of any data type, such as numbers, characters, or objects, depending on the programming language used.

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The general solution of equation y''+4y=sec(2z) is

y = c₁cos2z + c₂sin2z + \(\frac{cos2z}{4}\) ln(cos2z) + \(\frac{z sin2z}{2}\).

Given differential equation is,

y'' + 4y = sec(2z)

Characteristic equation of this equation is

(D²+4)=0

⇒ D² = -4

    D =  ±2i

Therefore the roots are imaginary.

D₁=2i ⇒ y₁ = e⁰cos2z = cos2z

D₂=-2I⇒ y₂ = e⁰sin2z = sin2z

yn= c₁cos2z + c₂sin2z

Noe to solve yp, first we need to solve Wronskian

y₁= cos2z ,   y₂=sin2z

y₁'= -2sin2z , y₂'=2cos2z

⇒ W = \(\left[\begin{array}{ccc}y1&y2\\y1'&y2'\\\end{array}\right]\) = \(\left[\begin{array}{ccc}cos2z&sin2z\\-2sin2z&2cos2z\\\end{array}\right]\)

                              = (cos2z)(2cos2z)-(-2sin2z)(sin2z)

                              = 2cos²2z + 2sin²2z

                              =2 (cos²2z + sin²2z)

                              = 2 ≠ 0

yp = - y₁\(\int\ {\frac{y2 g(z)}{W} } \, dz\) + y₂\(\int\ {\frac{y1 g(z)}{W} } \, dz\)

    = -(cos2z)\(\int\ {\frac{(sin2z)(sec2z)}{2} } \, dz\) + (sin2z)\(\int\ {\frac{(cos2z)(sec2z)}{2} } \, dz\)

    = - (cos2z)\(\int\ {\frac{sin2z/cos2z}{2} } \, dz\) + (sin2z)\(\int\ {\frac{cos2z/cos2z}{2} } \, dz\)

    = - \(\frac{cos2z}{2}\)\(\int\ {tan2z} \, dz\) + \(\frac{sin2z}{2}\)\(\int\ \,dz\)

    =  - \(\frac{cos2z}{2}\)(-\(\frac{1}{2}\) ln (cos2z)) + \(\frac{sin2z}{2}\) (z)

    =  \(\frac{cos2z}{4}\)ln(cos2z) + \(\frac{zsin2z}{2}\)

Now the general equation will become

y = yn + yp

y = c₁cos2z + c₂sin2z +\(\frac{cos2z}{4}\)ln(cos2z) + \(\frac{zsin2z}{2}\)    .

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The derivative of F(x) is F'(x) = 2x³ - 8x² + 4x.

A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output.

To find the derivative of the given function F(x), we will apply the fundamental theorem of calculus and differentiate the integral with respect to x.

Let's compute F'(x):

F(x) = ∫[1 to x²] (t³ - 4t² + 2) dt

To differentiate the integral with respect to x, we'll use the Leibniz integral rule:

F'(x) = d/dx ∫[1 to x²] (t³ - 4t² + 2) dt

According to the Leibniz integral rule, we have to apply the chain rule to the upper limit of the integral.

F'(x) = (x²³ - 4x²² + 2) d(x²)/dx - (1³ - 4(1)² + 2) d(1)/dx   [applying the chain rule to the upper limit]

F'(x) = (x²³ - 4x²² + 2) (2x) - (1 - 4 + 2) (0)  [using the power rule for differentiation]

F'(x) = 2x(x²³ - 4x²² + 2)

F'(x) = 2x³ - 8x² + 4x

Therefore, the derivative of F(x) is F'(x) = 2x³ - 8x² + 4x.

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The theorem that we are referring to is likely a theorem related to the existence and uniqueness of solutions to differential equations.

When we say that theorem a implies that the problem has a unique solution on some interval |x − x0| ≤ h, we mean that the conditions of the theorem guarantee the existence of a solution that is unique within that interval. The point (x0, y0) likely represents an initial condition that is necessary for solving the differential equation. It is possible that the theorem requires the function to be continuous and/or differentiable within the interval, and that the initial condition satisfies certain conditions as well. Essentially, the theorem provides us with a set of conditions that must be satisfied for there to be a unique solution to the differential equation within the given interval.
Theorem A implies that a unique solution exists for a problem on an interval |x-x0| ≤ h for the points (x0, y0) if the following conditions are met:
1. The given problem can be expressed as a first-order differential equation of the form dy/dx = f(x, y).
2. The functions f(x, y) and its partial derivative with respect to y, ∂f/∂y, are continuous in a rectangular region R, which includes the point (x0, y0).
3. The point (x0, y0) is within the specified interval |x-x0| ≤ h.
If these conditions are fulfilled, then Theorem A guarantees that the problem has a unique solution on the given interval |x-x0| ≤ h.

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a) Since E is closed, its complement F\ E is contained in F, so the intersection of {U_i1, U_i2, ..., U_in} with E is still a finite subcover of E. Thus, E is compact.

b) The union of all these finite subcovers is a finite subcover of {U_i} that covers K, showing that K is compact.

(a) To show that E is compact, we need to show that any open cover of E has a finite subcover. Let {U_i} be an open cover of E. Since E is closed in F, its complement F\E is open in F. Thus, {U_i} and F\ E together form an open cover of F. Since F is compact, there exists a finite subcover {U_i1, U_i2, ..., U_in, F\ E}. Since E is closed, its complement F\ E is contained in F, so the intersection of {U_i1, U_i2, ..., U_in} with E is still a finite subcover of E. Thus, E is compact.

(b) Let K1, K2, ..., Kn be a finite collection of compact subsets of S. Let {U_i} be an open cover of their union K= K1∪ K2 ∪ ... ∪ Kn. Then each Ki is contained in K, so {U_i} is also an open cover of each Ki. Since each Ki is compact, there exists a finite subcover {U_i1, U_i2, ..., U_ik_i} of {U_i} for each Ki. Thus, we have a finite collection of sets {U_i1, U_i2, ..., U_ik_1}, {U_i1, U_i2, ..., U_ik_2}, ..., {U_i1, U_i2, ..., U_ik_n} that covers K1, K2, ..., Kn respectively. The union of all these finite subcovers is a finite subcover of {U_i} that covers K, showing that K is compact.

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Answer:

Step-by-step explanation:

c.)because it gives more options of numbers and about half the rolls is 90

Answer:y=2x+8

Step-by-step explanation:

Answer:2.55 in fraction form is 51/20.

Step-by-step explanation:

Answer:

m∠B = 59°

Step-by-step explanation:

From ΔADC,

m∠DAC = 31°

By triangle sum theorem,

m∠ADC + m∠DAC + m∠DCA = 180°

90° + 31° + m∠DCA = 180°

m∠DCA = 180° - 121°

             = 59°

m∠ACB = m∠ACD + m∠BCD

90° = m∠ACD + 59°

m∠ACD = 90° - 59°

              = 31°

In ΔCDB,

m∠CDB + m∠DBC + m∠DCB = 180°

90° + m∠DBC + 31° = 180°

m∠DBC = 180° - 121°

             = 59°

Therefore, measure of angle B = 59°.