what is the electron geometry for a molecule that has 1 single bond, 1 double bond and 1 lone pair around the central atom group of answer choices

55.845 g/mol of the mass of cans in the box we brought had a mass of 23kg. 411.74 mol moles we have.

To determine the number of moles of tin cans you have, we need to know the molar mass of the metal that the cans are made of. Tin cans are usually made of steel, which is an alloy made primarily of iron and carbon, with small amounts of other elements.

To convert the mass of the cans (23 kg) to moles, we need to use the following formula:

moles = mass / molar mass

moles = 23,000 g / 55.845 g/mol = 411.74 mol

Therefore, the number of moles of iron in the 23 kg of tin cans is approximately 411.74 mol.

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Answer:

D

Explanation:

molecules have potential energy and kinetic energy.

Tempreture is defined as the average kinetic energy and internal energy is PE+KE. Pptential energy in particles or molecules is just there position relative to one another. A gas which has seperated particles will have a greater potential energy than a solid/liquid.

Answer:

group # = # valence electrons

group 2= 2 valence electrons

Explanation:

Mg is in group #2 and subsequently has 2 valence electrons (electrons on the outermost shell)

Answer:

B. Potassium Sulfate

Explanation:

SO4=sulfate

-2 charge cancels

Answer:

B. Potassium Sulfate

Explanation: for clever users /plato

The energy needed to start a chemical reaction is called activation energy. The correct option is (3).

Activation energy refers to the minimum amount of energy required for a chemical reaction to begin or proceed. It acts as a barrier that needs to be overcome for reactant molecules to transform into products.

In order for a reaction to occur, the reactant molecules must have sufficient energy to surpass this energy barrier. Activation energy can be thought of as the "hurdle" that reactant molecules must jump over to initiate a chemical reaction.

Once the reaction is initiated and the activation energy is surpassed, the reactants undergo a series of bond-breaking and bond-forming processes, releasing or absorbing energy in the form of heat. Activation energy is a critical factor in determining the rate of a chemical reaction. Therefore, the correct option is (3).

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Answer:

I guess option d

hope I am correct

Answer:

1.1 mol of O2

Explanation:

First we need the balance chemical equation which is

2 H2O2 -------> 2 H2O + O2

This is important because in stoichiometry you can go from units of one thing to other by using mole ratios, here the mole ratio is 2 mol of H2O2  for one mole of O2.

\(2.2 mol H2O2 \frac{1mol O2}{2 mol H2O2}\) = 1.1 mol of O2

Her calculated density of aluminum from the experimental data will be 2.488 g/ml.

Density, denoted by ρ, is the property of a substance which determines whether it will sink or float. It is the ratio between the mass of the substance and its volume. It can be calculated using the formula below.

ρ = m/v

where ρ = density

m = mass

v = volume

Given that the volume of an aluminum with a mass of 14.93 g is 6.0 ml, plug in the values and solve for the density of the aluminum.

ρ = m/v

ρ = 14.93 g / 6.0 ml

ρ = 2.488 g/ml

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Answer:

C

Explanation:

I would say C Low Density

SORRY IF I AM WRONG

HOPE IT HELPS :D

Answer:

a) 0.13 bar

b) 5.05 L

Explanation:

Let us take the mass of the mixture to be 100 g. Hence, 70% by weight of dioxygen corresponds to 70 g

Mass of dihydrogen = 100g - 70 g = 30g

Number of moles of dioxygen = 70g/32 g/mol = 2.2 moles of dioxygen

Number of moles of dihydrogen = 30g/2g/mol = 15 moles of dihydrogen

Total number of moles = 2.2 + 15 = 17.2 moles

Mole fraction of dioxygen = 2.2/17.2 = 0.13

Partial pressure = mole fraction * total pressure

Partial pressure of dioxygen = 0.13 * 1 = 0.13 bar

ii) number of moles in 8.8 g of CO2 = 8.8g/44g/mol = 0.2 moles

T = 31.1 + 273 = 304.1 K

P = 1 bar

V= ?

R = 0.083 bar L K-1 mol-1

From

PV=nRT

V = nRT/P

V= 0.2 * 0.083 * 304.1/1

V= 5.05 L

Freebase is defined as a method of preparing cocaine as a chemical substance so that it can be smoked because is is extracted or deduced from the natural source which is plant

Freebase is a that is use while producing cocaine in other to free or extract the base from the natural source which is plant and after which it is grinded into powder so that it can be smoked or sniffed.

Therefore, Freebase is defined as a method of preparing cocaine as a chemical substance so that it can be smoked because is is extracted or deduced from the natural source which is plant

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Answer:

Iconic

Explanation:

hope this helps :) x

The wavelength-λ = 6.12 x 10⁻⁷ m

Radiation energy is absorbed by photons

The energy in one photon can be formulated as

\(\large{\boxed{\bold{E\:=\:h\:.\:f}}}\)

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

f = c / λ

c = speed of light

= 3.10⁸  m/s

λ = wavelength

The wavelength of radiation with a frequency of 4.9 ×10¹⁴/s :

\(\tt \lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3.10^8}{4.9\times 10^{14}}\\\\\lambda=6.12\times 10^{-7}~m\)

Answer: Hydrogen and carbon

Explanation:

The intermolecular forces are in the solid NaCl salt is ion - ion forces or the dipole - dipole forces of the interaction.

The Na is the metal and is capable of the donating the electrons and the Cl is the non metal and have capability of accepting the electrons. This makes the Na to form the cation and the Cl to make the anion. The dipole - dipole forces are present in the molecule which contains the oppositely charged ions one is positively charged ion and the other is the negatively charged ion.

Thus , the NaCl solid has the ion - ion intermolecular forces of the interaction .

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H3PO4 is the molecular formula (hill method) of phosphoric acid.

Phosphoric acid, also known as orthophosphoric acid, monophosphoric acid, or phosphoric(V) acid, is an inorganic solid with the chemical formula H3PO4 that contains phosphorus. It is frequently found as an 85% aqueous solution, which is a syrupy liquid that is colorless, odorless, and non-volatile. It is a significant industrial chemical that is used in numerous fertilizers.

This substance is an acid. The phosphate ion PO3^4- is produced when all three H+ ions are removed. Dihydrogen phosphate ion H2PO 4 and hydrogen phosphate ion HPO2^4- are produced, respectively, by removing one or two protons. Organophosphates are esters created by phosphoric acid.

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Protein, peptide and amine-based hormones have amino acids in common. Amino acids are the building blocks of protein. The synthesis of these hormones takes place in the endocrine glands which are responsible for producing and releasing hormones into the bloodstream.

The amino acids which make up these hormones, are linked together to form a long chain of amino acids, which can be broken down into smaller peptides. These peptides are then modified in various ways to produce the final hormone. The modification can include the addition of carbohydrates, lipids, and other molecules.

The hormones are then transported through the bloodstream to their target cells where they bind to specific receptors on the surface of the cell. Once bound, the hormone can either activate or inhibit certain cellular functions which results in a specific physiological response.In conclusion, the correct answer is that protein-, peptide-, and amine-based hormones have amino acids in common.

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A substantial imbalance between demand and response capability under conditions in which failure has important consequences refers to STRESS. It may affect the functioning of a biological system.

Homeostasis refers to the state of internal (steady) equilibrium, which is required for the normal functioning of a biological system.

Conversely, stress can be defined as any environmental factor (e.g., excessive temperature condition) which is directly affecting the normal functioning of an organism.

Stress may lead to the loss of the homeostatic state when conditions cannot be supported by the organism.

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9.  The slope for the given equation 3- y ≤ -5x is 5 and intercept is 3.

Slope-intercept form (y=mx+b) of linear equations highlights the slope (m) and y-intercept (b) of line. The slope intercept formula y = mx + b is used when you know the slope of line that is to to be examined and point given is also the y intercept (0, b). In this formula, b represents y value of the y intercept point.

The slope intercept for of linear equation is: y = mx +b

m is slope and b is y intercept.

So, y = 5x + 3

Now m = 5 ; so the slope is 5

b = 3 ; hence y-intercept is 3

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Answer: there could be two lunar eclipses per year

Explanation:

Antoine Lavoisier is the answer

Answer:

Antoine Lavoisier is the father of chemistry

Explanation:

Antoine-Laurent de Lavoisier, also Antoine Lavoisier after the French Revolution, was a French nobleman and chemist who was central to the 18th-century chemical revolution and who had a large influence on both the history of chemistry and the history of biology.

Forming an Ion Ionic bonds are a class of chemical bonds that result from the exchange of one or more valence electrons from one atom, typically a metal, to another, typically a nonmetal. This electron exchange results in an electrostatic attraction between the two atoms called an ionic bond.

The total amount of energy released when forming the two H-H bonds in two molecules of the product H₂ is approximately 104,000 kJ.

The energy released when forming two H-H bonds in two molecules of the product H2 can be calculated using the bond energy of the H-H bond and the stoichiometry of the reaction. The bond energy of the H-H bond is the energy required to break one mole of H-H bonds in gaseous H₂ molecules.

When two H-H bonds are formed in two molecules of H₂, the stoichiometry of the reaction tells us that four hydrogen atoms combine to form two molecules of H₂. Therefore, the energy released in forming two H-H bonds is equal to the bond energy of two H-H bonds times the Avogadro constant, since only two H₂ molecules are formed:

Energy released = (436 kJ/mol) x (6.02 x 10²³ molecules/mol) / 2

= 1.04 x 10⁵ kJ

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Ammonia and phosphoric acid are the reactants for the reaction 9, for the formation of Ammonium Phosphate.

What are ionic reactions?

Ionic reaction is the reaction of ions that are anions and cations to form a compound in a medium in which they are dissolved. When ions of water-soluble salts interact with each other in aqueous medium results in the formation of water-insoluble salts.

9) 3NH₃ + H₃PO₃ → (NH₄)₃PO₄

10) CaCO₃ + HCl → CaCl₂ + H₂CO₃

11) SnO₂ + HCl → SnCl₂ + H₂O

12) Ca(OH)₂ + HNO₃ → Ca(NO₃)₂ + H₂O

13) C₃H₅O(COOH)₃ + 3KOH → C₃H₅O(COOK)₃ + 3H₂O

14) 2Mg + C₃H₅O(COOH)₃ → (C₃H₅O(COO)₃)Mg₂ + H₂

15) H₃PO₄ + 3KOH → K₃PO₄ + 3H₂O

Therefore, Ammonia and phosphoric acid are the reactants for the reaction 9, for the formation of Ammonium Phosphate.

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The order of decreasing reactivity towards electrophilic aromatic substitution is as follows: ortho > para > meta.

This is known as the "ortho-para-meta" rule. This is due to the electron-withdrawing effect of the substituents. The ortho and para positions are the least stable due to the presence of a strong electron-withdrawing group.

As a result, they are the most reactive towards electrophilic substitution. The meta position is the most stable due to the presence of an electron-donating group and is the least reactive.

So, the correct order of decreasing reactivity towards electrophilic aromatic substitution is as follows: ortho > para > meta.

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To obtain a 40% antifreeze solution, 1 quart of pure antifreeze needs to be added to the existing 2 quarts of a 10% antifreeze solution.

To solve this problem, we need to determine the amount of pure antifreeze that should be added to achieve the desired concentration of 40%.

The initial solution contains 2 quarts of a 10% antifreeze solution. This means that out of the 2 quarts, 10% or 0.1 quart is pure antifreeze (since 10% of 2 quarts is 0.2 quarts).

Let's denote the unknown amount of pure antifreeze to be added as "x" quarts. The final solution will have a total volume of 2 + x quarts. To achieve a 40% concentration, the amount of pure antifreeze in the final solution should be 40% of the total volume. Therefore, 40% of (2 + x) quarts should be pure antifreeze.

We can set up the equation:

0.1 + x = 0.4(2 + x)

Now we can solve for "x":

0.1 + x = 0.8 + 0.4x

0.6x = 0.7

x = 0.7/0.6

x ≈ 1.17

So, approximately 1.17 quarts of pure antifreeze should be added to the initial 2 quarts of a 10% antifreeze solution to obtain a 40% antifreeze solution.

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Answer:

2

Explanation:

bc the 2 that's after a bracket refers to both oxygen and nitrogen, making oxygen 6 bc it already has a 3(3×2=6)

Answer:

2

Explanation:

The acceleration of the mass is 8.0 m/s² when an unbalanced 16.0 N force is applied to a 2.0 kg mass.

To calculate the acceleration of the mass, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).

We know that the force acting on the object is 16.0 N, and the mass of the object is 2.0 kg. So, we can use the equation to solve for the acceleration:

a = F ÷ m

where, a = acceleration, F = force (16.0 N), m = mass (2.0 kg)

So,

a = 16.0 N ÷ 2.0 kg = 8.0 m/s²

Therefore, the acceleration of the mass is 8.0 m/s²

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To synthesize (3S,4R)-4-cyano-3-methylheptane as a single product, we can use the following substrate and nucleophile in a stereospecific nucleophilic substitution reaction:

Substrate: (3S,4S)-3-methyl-4-heptanone

Nucleophile: Cyanide ion (CN-)

To synthesize (3S,4R)-4-cyano-3-methylheptane as a single product, we can use the following substrate and nucleophile in a stereospecific nucleophilic substitution reaction:

Substrate: (3S,4S)-3-methyl-4-heptanone

Nucleophile: Cyanide ion (CN-)

Reaction conditions: The reaction is carried out in the presence of a base, such as sodium hydroxide (NaOH), in an aprotic solvent, such as dimethyl sulfoxide (DMSO). The reaction is typically performed under reflux conditions for several hours.

The overall reaction can be represented as follows:

```
(3S,4S)-3-methyl-4-heptanone + CN- → (3S,4R)-4-cyano-3-methylheptane + OH-
```

In this reaction, the CN- nucleophile attacks the carbonyl carbon of the ketone substrate from the less hindered side, leading to the formation of the (3S,4R)-stereoisomer as the major product. The reaction is stereospecific, meaning that it proceeds with retention of the stereochemistry at the carbon center bearing the methyl and cyano groups.
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