What is the concentration of 156.3 grams of Magnesium Chloride in 500.0
milliliters of water? *

The IUPAC nomenclature of compound 1 is 5-bromo-2-methylchloridepent-2-ene and the name for structure 2 is 5-iodo-hex-2-ene

IUPAC nomenclature is the method of naming the organic chemical compounds by following certain rules and criteria given by IUPAC.

This nomenclature is based on naming a molecules longest chain of carbons connected by single bonds, whether in a continuous or in ring form. Everything else like multiple bonds or atoms are other than carbon and hydrogen are indicated by prefixes or suffixes according to a specific set of priorities.

In structure 1 we can see that we are number so that the double bond that is present gets the least priority and then the naming is done in the alphabetic order. so the name is 5-bromo-2-methylchloridepent-2-ene

In structure 2 the same thing is followed and the name of the structure is

5-iodo-hex-2-ene

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Temperature is usually defined as a measure of the warmth or coldness of an object or substance. Your answer is, correct do not worry.

The volume of O₂ produced when 8.52 g of Na₂O₂ is added to excess water is approximately 1.17 liters at STP.

When it comes to the ideal gas law, the underlying assumption is that the gas is in a state of thermodynamic equilibrium. This means that its molecules are not interacting with each other except through perfectly elastic collisions.

Equation:

We can use stoichiometry to determine the volume of oxygen gas produced from the reaction of 8.52 g of Na₂O₂.

First, we need to convert the mass of Na₂O₂ to moles using its molar mass:

8.52 g Na₂O₂ × (1 mol Na₂O₂ / 77.98 g Na₂O₂) = 0.1093 mol Na₂O₂

According to the balanced chemical equation, 1 mole of Na₂O₂ produces 1/2 mole of O₂:

2 Na₂O₂ + 2 H₂O → 4 NaOH + O₂

1 mol Na₂O₂ produces 1/2 mol O₂

So, the number of moles of O₂ produced is:

0.1093 mol Na₂O₂ × (1/2 mol O₂ / 1 mol Na₂O₂) = 0.05465 mol O₂

Finally, we can use the ideal gas law to determine the volume of O₂ produced at standard temperature and pressure (STP), which is defined as 0°C (273 K) and 1 atmosphere (1 atm) of pressure:

PV = nRT

At STP, the pressure and temperature are known, so we can rearrange the equation to solve for V:

V = nRT / P

Plugging the values, we get:

V = (0.05465 mol) × (0.08206 L atm mol⁻¹ K⁻¹) × (273 K) / (1 atm)

V ≈ 1.17 L

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Answer:

2.25 atm

Explanation:

Given data

Step 1: Convert the pressure of nitrogen to atm

We will use the relationship 1 atm = 101.325 kPa.

\(321kPa \times \frac{1atm}{101.325kPa} = 3.17 atm\)

Step 2: Convert the pressure of oxygen to atm

We will use the relationship 1 atm = 14.6959 psi.

\(74.0psi \times \frac{1atm}{14.6959psi} =5.04atm\)

Step 3: Calculate the partial pressure of hydrogen

The total pressure is the sum of the partial pressures.

P = pN₂ + pO₂ + pH₂

pH₂ = P - pN₂ - pO₂

pH₂ = 10.46 atm - 3.17 atm - 5.04 atm

pH₂ = 2.25 atm

Answer:

\(P_H=2.25atm\)

Explanation:

Hello,

IN this case, we can apply the Dalton's law in order to understand the pressure behavior of a mixture as the summation of all the pressures of the compounds in the mixture, in this case, nitrogen, oxygen and hydrogen:

\(P_T=P_O+P_N+P_H\)

So, since we are asked to compute the pressure of hydrogen, we simply solve for it:

\(P_H=P_T-P_O-P_N=10.46atm-74.0psi*\frac{1atm}{14.6959psi} -321kPa*\frac{1atm}{101.325kPa} \\\\P_H=2.25atm\)

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Answer:

6*10^14 s^-1

Explanation:

F=?

wavelength=500*10^-9 m

speed of light=3*10^8 ms^-1

F=speed of light/wavelength

F=3*10^8 ms^-1/500*10^-9 m

F=6*10^14

Answer:

oxygen-16 is a stable isotope of oxygen, having 8 neutrons and 8 protons in its nucleus. It has a mass of 15. u

Carbon-12 and Carbon-14 are considered isotopes of each other.

Isotopes are any of two or more forms of an element where the atoms have the same number of protons, but a different number of neutrons within their nuclei.

This means that isotopes have the same atomic number but a different mass number.

According to this question, carbon-12 has a mass number of 12 while carbon-14 has a mass number of 14. The atomic number of both isotopic forms remain 12.

Therefore, it can be said that both carbon atoms are isotopes of one another.

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1. The constituent gases of air are:

2. The surrounding air is not seen with the eyes because it is transparent. Air molecules are not visible to the na-ked eye, and they do not scatter or absorb visible light significantly. Therefore, air appears colorless and transparent.

3. To prove that air supports burning, you can perform an experiment with a burning candle. Place a glass jar or bell jar over a lit candle, ensuring that the jar is airtight. As the candle burns, it consumes oxygen from the air inside the jar. Eventually, the candle flame will go out due to the lack of oxygen, proving that air (specifically oxygen) is necessary for burning.

4. To show that air occupies space, you can perform a simple experiment using a plastic bottle or syringe. Fill the bottle or syringe with water, ensuring there are no air bubbles. Then, cover the opening tightly and try to compress the air inside. You will find that it is not possible to compress the air significantly, indicating that air occupies space.

5. To prove that air has weight, you can use a sensitive balance or scale. Weigh an airtight container or balloon, and then fill it with air. The weight of the container or balloon with the added air will be greater than its initial weight, demonstrating that air has weight.

6. Air is useful to us in various ways. Three points highlighting the importance of air are:

7. Three properties of air include:

Air exerts force in various ways. For example, air pressure allows objects like airplanes to fly by providing lift. Air resistance or drag opposes the motion of objects moving through the air, creating a force that can affect their speed and trajectory.

8. Four effects of air pollution include:

9. Causes of pollution:

10. Two control measures for air pollution include:

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Answer:

The pH of the solution is 1.68.

Explanation:

Hope this helped!

Answer:

C

Explanation:

Jailah should try an element from the same group as lithium.

The elements are those in the same group or column of the periodic table that have mostly similar chemical properties. Elements are placed in vertical groups that have the same valence electrons and similar chemical properties.

On the periodic table, the vertical columns are called groups because of their similar chemical behavior. All the members of a group  (1 to 18) of elements have similar chemical properties.

Since Lithium, sodium, and potassium are all Group 1A metals, they all have most similar chemical properties. The electronic configuration of the lithium is 1s²2s¹. Lithium has one electron in its outermost shell. All the elements in group 1 have one electron in their valence shell.

Therefore, she should replace lithium with an element of group 1 of the periodic table.

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475 g is the correct response to the query. This is true because the combined mass of two solutions with masses of 450 g and 350 g equals 800 g. 125 g of solid crystals are created and fall to the bottom of the container as a result of a chemical reaction.

As a result, the mass of the residual solution is equal to 475 g, or 800 g less 125 g. It is significant to observe that the masses of the two solutions that were combined originally do not equal those of the solid crystals or the leftover solution.

This is because the two solutions' chemical reaction when combined results in a transition of the matter that is resulting in the production of a new substance.

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Answer:

Anything which occupy space and have mass between them are called matter.

One possible reason for cooler air temperatures in Christchurch during El Niño years is the shift in atmospheric circulation patterns.

During El Niño years, Christchurch may experience cooler air temperatures due to several factors associated with the El Niño phenomenon.

El Niño is characterized by the abnormal warming of the surface waters in the eastern tropical Pacific Ocean, which has global climatic implications. While El Niño is primarily associated with changes in oceanic conditions, its effects can extend to atmospheric patterns, leading to altered weather patterns and temperature variations.

One possible reason for cooler air temperatures in Christchurch during El Niño years is the shift in atmospheric circulation patterns. El Niño can disrupt the normal global atmospheric circulation, resulting in changes in the positioning and intensity of weather systems.

This can lead to the advection of cooler air masses from the south or southeast towards Christchurch, resulting in cooler temperatures.

Another factor is the influence of El Niño on regional rainfall patterns. El Niño often leads to drier conditions in the South Island of New Zealand, including Christchurch.

Reduced cloud cover and less moisture in the air can contribute to cooler temperatures as there is less insulation from the sun's radiation and less evaporative cooling. Additionally, the absence of significant rainfall can result in less moisture in the soil, leading to cooler conditions as less energy is used for evaporation.

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Answer:

An increase in pressure would cause less volume and vice versa. They are inversely proportional.

Explanation:

This is due to Boyle's Law (and because an increase in pressure would increase the force on the container, however, if it's a closed container, it would burst)

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There are approximately 2.8939 x\(10^2^4\) carbon atoms in 0.37 mol of procaine.  The molecular formula of procaine (C₁₃H₂₀N₂₀₂), one can see that there are 13 carbon atoms (C13) in one molecule of procaine.

Avogadro's number (6.022 x \(10^2^3\)) represents the number of particles (atoms, molecules, or formula units) in one mole of a substance

The number of molecules of procaine in 0.37 mol:

Number of molecules = 0.37 mol x (6.022 x\(10^2^3\) molecules/mol)

Number of carbon atoms = Number of molecules x 13 carbon atoms/molecule

Number of molecules = 0.37 mol x (6.022 x \(10^2^3\)molecules/mol)

= 2.22614 x \(10^2^3\)molecules

Number of carbon atoms = 2.22614 x \(10^2^3\) molecules x 13 carbon atoms/molecule

= 2.8939 x \(10^2^4\)carbon atoms

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Explanation: The concentration of a solution helps us to determine the collision speed between particles in a molecule or compound. Knowing the concentrations of components in solutions can help determine the health of the world.

Ribosomes are attached to the membrane of the ER, making it “rough.” The RER is also attached to the nuclear envelope that surrounds the nucleus. This direct connection between the perinuclear space and the lumen of the ER allows for the movement of molecules through both membranes.Answer:

Explanation:

TRUST

Explanation:

A moon orbits in a roughly circular path around a planet with a mass of 8.6 x 1023 kg. The distance from the center of the moon to the center of the planet is 7.04 x 106 meters. Calculate the speed of the moon in m/s.

Answer:

30.0 mol CO₂

Explanation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

To answer this problem we need to convert moles of C₃H₈ into moles of CO₂: We'll do that by using the stoichiometric coefficients, using a conversion factor that has C₃H₈ moles in the denominator and CO₂ moles in the numerator:

10.0 mol C₃H₈ * \(\frac{3molCO_2}{1molC_3H_8}\) = 30.0 mol CO₂

answer:

5.4moles

Explanation:

from the equation 2 moles of C2H6 will react to give 6 moles of H2O

COMPARING

2 --- 6

1.8--- X moles

cross multiply

you get

X = (6×1.8)/2

= 5.4moles

Answer:

6.22 × 10⁻⁵

Explanation:

Step 1: Write the dissociation reaction

HC₆H₅COO ⇄ C₆H₅COO⁻ + H⁺

Step 2: Calculate the concentration of H⁺

The pH of the solution is 2.78.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -2.78 = 1.66 × 10⁻³ M

Step 3: Calculate the molar concentration of the benzoic acid

We will use the following expression.

Ca = mass HC₆H₅COO/molar mass HC₆H₅COO × liters of solution

Ca = 0.541 g/(122.12 g/mol) × 0.100 L = 0.0443 M

Step 4: Calculate the acid dissociation constant (Ka) for benzoic acid

We will use the following expression.

Ka = [H⁺]²/Ca

Ka = (1.66 × 10⁻³)²/0.0443 = 6.22 × 10⁻⁵

The element with the electron configuration, 1s2 3s2 3p6 3s2 3p6 3d6 4s2, will be iron.

In the electronic configuration of elements, the number of electrons possessed by the element is shared into the orbitals according to their energy levels.

The electrons are first shared in orbitals in the same energy level before pairing starts.

Also for neutral atoms, the number of electrons is equivalent to the number of protons. The number of protons in itself represents the atomic number of elements.

Thus, considering this electron configuration, 1s2 3s2 3p6 3s2 3p6 3d6 4s2; the total number of electrons in all the orbitals is 26. The element with the atomic number of 26 is iron.

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Answer: 252

Explanation:

# turn F to C

C=(F-32)5/9

C=(-5-32)5/9

C=-37 × (5/9)

C= -21

# turn C to K

K=C+273

K=(-21)+273

K=252

Answer:

253 Kelvins

Explanation:

We want to convert -5°F to Kelvins.

First, we must convert -5°F to Celsius. The formula is:

°C= (°F - 32) * 5/9

Plug -5 in for °F.

°C= (-5-32) * 5/9

Solve inside the parentheses first. Subtract 32 from -5.

°C= (-37) * 5/9

Multiply -37 and 5/9.

°C= -20.5555556

-5° F is equal to -20.5555556° C.

Next, convert Celsius to Kelvins. The formula is:

K= °C + 273.15

Plug -20.5555556 in for °C.

K= -20.5555556 + 273.15

Add -20.5555556 and 273.15.

K= 252.594444

Round to the nearest whole number. The 5 in the tenth place tells us to round 252 to 253.

K ≈ 253

-5°F is equal to about 253 Kelvins.

As a result, the ideal gas law is applied, and the pressure of the gas in the container is 1.44 atm.

The Kelvin temperature and hence the volume are going to be in direct proportion when the pressure on a sample of a dry gas is held constant, according to the definition of the Charles Law Formula. PV = k is the law's equation, and k might be a constant.

This issue can be resolved by applying the ideal gas law:

PV = nR

T = -52 °C + 273.15 = 221.15 K

n = 0.642 mol

V = 8.6 L

T = 221.15 K

\(R = 0.0821 L·atm/mol·K (gas constant for ideal gases)\)

PV = nRT

P = nRT/V

P = (0.642 mol)(0.0821 L·atm/mol·K)(221.15 K)/(8.6 L)

P = 1.44 atm

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The decomposition of aspirin (acetylsalicylic acid,\(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)).

The decomposition of aspirin (acetylsalicylic acid, \(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)). To determine the moles of each product formed, we need to consider the balanced chemical equation for the reaction:

\(C_{9} H_{8} O_{4} = > C_{7} H_{6}O_{3} +CH_{3} COOH\)

From the equation, we can see that for every 1 mole of aspirin, 1 mole of salicylic acid and 1 mole of acetic acid are produced.

Therefore, the moles of salicylic acid and acetic acid formed will be equal to the number of moles of aspirin that decomposes. If we know the amount of aspirin in moles, we can directly calculate the moles of each product based on stoichiometry.

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Na, C, and O so the answer is c. 3

0.0956 grams of helium will occupy a volume of 575 mL at 760 mmHg and 20°C

To calculate the mass of helium that will occupy a given volume at a specific temperature and pressure, we need to use the ideal gas law equation: PV = nRT. Here's how you can solve the problem:

Convert the volume to liters: 575 mL = 575/1000 = 0.575 L.

Convert the pressure to atmospheres: 760 mmHg = 760/760 = 1 atm.

Convert the temperature to Kelvin: 20°C = 20 + 273.15 = 293.15 K.

Plug the values into the ideal gas law equation: (1 atm) * (0.575 L) = n * (0.0821 L·atm/(mol·K)) * (293.15 K).

Rearrange the equation to solve for n (the number of moles): n = (1 atm * 0.575 L) / (0.0821 L·atm/(mol·K) * 293.15 K).

Calculate the value of n: n = 0.0239 moles.

To find the mass, we need to know the molar mass of helium, which is approximately 4 grams per mole.

Multiply the molar mass by the number of moles: 4 g/mol * 0.0239 moles = 0.0956 grams.

Therefore, approximately 0.0956 grams of helium will occupy a volume of 575 mL at 760 mmHg and 20°C.

Note: The ideal gas law assumes ideal gas behavior, and the calculated result may not be accurate under extreme conditions or for gases that deviate significantly from ideal behavior.

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Answer:

The plant and animal cells are eukaryotic and contain well developed cellular organelles. 

The cell membrane, cytoplasm, chromosomes, and mitochondria are the structures that are present in both the plant and the animal cells. 

The cell wall and chloroplast are present only in the plant cell. 

Mitochondria

Because it is right next to the nucleau