What is the atomic number?
pls help.

What Is The Atomic Number?pls Help.

Answers

Answer 1

Answer:

8

Explanation:


Related Questions


Write 1/5 as an equivalent fraction with 500 in the denominator?

I need help please

Answers

Answer:

100 / 500

Explanation:

100 / 500 is equivalent to 1 / 5.

4. Hydrogen bonds, ionic bonds, dipole-dipole attractions, dispersion forces are types intermolecular forces.Indicate the major type of intermolecular forces that occur between particles in the following substances: 6 pts(a) OBr2 =(b) LICI(c) H20 -(d) HBr -(e) CHCI) =( 1Br =

4. Hydrogen bonds, ionic bonds, dipole-dipole attractions, dispersion forces are types intermolecular

Answers

Answer:

a) Dipole-Dipole

b) Ionic Bond

c) Hydrogen Bond

d) Dipole-Dipole

e) Dipole- Dipole

f) Dispersion Forces

Explanation:

Here, we want to get the type of intermolecular forces that exist in the given molecules

Hydrogen bond exists when we have hydrogen being bonded to highly electronegative atoms.

Ionic Bonds exist between electropositive and electronegative atoms in a molecule

Dipole-Dipole interaction is a weak type of intermolecular force arising from induced diploes

Dispersion forces forms from temporary dipoles and they are weak

The molecules and their type of intermolecular forces are as follows:

\(\begin{gathered} a\text{ \rparen OBr}_2\text{ - Dipole - Dipole Interaction} \\ b)\text{ LiCl - Ionic Bond} \\ c)\text{ H}_2O\text{ - Hydrogen Bond} \\ d)\text{ HBr - Dipole -Dipole Interaction} \\ c)\text{ CHCl}_3\text{ - Dipole-Dipole Interaction} \\ f)\text{ IBr - Dispersion Forces} \end{gathered}\)

We should note that Dipole-Dipole forces occur between atoms that are electronegative

How many liters at STP of Na›SiO; can react with 0.8000 grams of HF?

Answers

The volume of Na2SiO3 that can react with 0.8000 grams of HF at STP is approximately 0.9663 liters.

How many lñiters can react?

To calculate the volume of Na2SiO3 (sodium silicate) that can react with 0.8000 grams of HF (hydrofluoric acid) at standard temperature and pressure (STP), we need to use stoichiometry and the ideal gas law.

Write the balanced chemical equation for the reaction between Na2SiO3 and HF:

Na2SiO3 + 6HF → Na2SiF6 + 3H2O

Determine the molar mass of HF:

The molar mass of HF is:

H (hydrogen) = 1.008 g/mol

F (fluorine) = 18.998 g/mol

So, the molar mass of HF = 1.008 + 18.998 = 20.006 g/mol

Convert the given mass of HF to moles:

Mass of HF = 0.8000 g

Molar mass of HF = 20.006 g/mol

Moles of HF = Mass of HF / Molar mass of HF

Moles of HF = 0.8000 g / 20.006 g/mol

Moles of HF = 0.03999 mol (rounded to five decimal places)

Use the stoichiometry of the balanced equation to determine the molar ratio between Na2SiO3 and HF:

From the balanced equation, we can see that 6 moles of HF react with 1 mole of Na2SiO3.

Use the ideal gas law to calculate the volume of Na2SiO3 at STP:

The ideal gas law is given by:

PV = nRT

where:

P = Pressure (at STP, P = 1 atm)

V = Volume

n = Number of moles of gas (in this case, moles of Na2SiO3)

R = Ideal gas constant (0.0821 L atm / mol K)

T = Temperature (at STP, T = 273.15 K)

Rearrange the formula to solve for volume (V):

V = nRT / P

Plugging in the values:

n = 0.03999 mol (from step 3)

R = 0.0821 L atm / mol K

T = 273.15 K (at STP)

P = 1 atm (at STP)

V = 0.03999 mol * 0.0821 L atm / mol K * 273.15 K / 1 atm

V = 0.9663 L (rounded to four decimal places)

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If a gas has a proportionality constant of 4.32 x 10-4 mol at room temperature for a particular solvent, what will the
solubility of the gas be in that solvent when it exerts a partial pressure of 92.4kPa?
LkPa
• Your answer should have three significant figures.

Answers

\(0.0467 X 10^{-4} M/kPa\) is the solubility of the gas when it exerts a partial pressure of 92.4kPa.

What is Henry's law?

Mathematically, we can get this from Henry's law

From Henry law;

Concentration = Henry constant × partial pressure

Thus Henry constant = \(\frac{Concentration}{partial \;pressure}\)

Henry constant = \(\frac{4.32 \;X \;10^{-4} mol}{92.4kPa}\)

\(= 0.0467 X 10^{-4} M/kPa\)

Hence, \(0.0467 X 10^{-4} M/kPa\) is the solubility of the gas when it exerts a partial pressure of 92.4kPa.

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PLEASE HELP ME THERES 100 POINTS ON THE LINE

PLEASE HELP ME THERES 100 POINTS ON THE LINE
PLEASE HELP ME THERES 100 POINTS ON THE LINE

Answers

Answer:

1.93 2.86

Explanation:

exactly the reason for the above text

3) A car traveling at a constant velocity of 35 km/h North comes to a full stop 15 seconds
after the driver applies the brakes. What is the acceleration of the car?
A. 2.3 m/s 2
B. -2.3 m/s 2
C. -0.43 m/s 2
D. 0.43 m/s 2

3) A car traveling at a constant velocity of 35 km/h North comes to a full stop 15 secondsafter the driver

Answers

The acceleration of the car is -2.3m/s².

Explain what an acceleration is.

Acceleration is the rate at which the direction and speed of motion change over time. It is said to have been accelerated when something changes its direction and moves faster or slower. Motion on a circle accelerates even when the speed is constant because the direction is constantly changing.

Velocity is the rate at which displacement changes. The rate at which speed changes is known as acceleration. Because it consists of both magnitude and direction, velocity is a vector quantity. Since acceleration is merely the rate at which velocity changes, it too is a vector quantity.

v = u +at

0 = 35 + a×15

15a = -35

a = -35/15

a = -2.3m/s².

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Answer:

B. -2.3 m/s²

Explanation:

To answer this question, we have to use the following formula:
\(\boxed{a = \frac{v - u}{t}}\),

where:

• a ⇒ acceleration

• v ⇒ final velocity

• u ⇒ initial velocity

• t ⇒ time taken for the change in velocity to occur

From the question, we know that initially, the car was travelling at 35 km/h. Therefore, u = 35 km/h. The question also tells us that the car comes to a full stop, meaning its final velocity is 0 m/s. Therefore, v = 0 km/h. It takes the car 15 seconds to stop, so t = 15 s.

Using the information above and substituting it into the formula, we can calculate the acceleration of the car:

\(a = \frac{0 - 35}{15}\)

  = -2.3 m/s²

Therefore, the acceleration of the car is -2.3 m/s², and the correct answer is B.

AP chem. Sublevels!!!!!!!!!!!

AP chem. Sublevels!!!!!!!!!!!

Answers

Answer:

2d

Explanation:

The lowest d is 3d.

Hope this helps!

How many molecules are in 5 moles of O2?

Answers

Answer: 6.02 × 10^24

Explanation:

Which statement describes an important role of carbon dioxide in Earth’s atmosphere? *

Animals breathe carbon dioxide.
Plants use carbon dioxide to make food.
Carbon dioxide helps animals make proteins.
Carbon dioxide forms clouds that produce rain.

Answers

Answer:

Plants use carbon dioxide to make food.

Explanation:

Answer:B

Explanation: i did it

Duncan takes a break from studying and goes to the gym to swim laps if swimming burns, 615,000 cal per hour, how many kilojoules does swimming burn in the same amount of time?

Answers

2570 kilojoules (1 cal = 4.18 joules)

Describe echolocation. Give an example of an animal that uses echolocation.

Answers

dolphin and whales use echolocation

1. The equation for the reaction between zinc and aqueous copper(II) sulfate is shown.

Zn + Cuso, → ZnSO, + Cu

Which statement is correct?

a. The oxidation state of the oxidising agent has changed from 0 to +2.

b. The oxidation state of the reducing agent has changed from 0 to +2.

c. The oxidation state of the reducing agent has changed from +2 to 0

d. This is not a redox reaction. The solution changes from colourless to blue.

1. The equation for the reaction between zinc and aqueous copper(II) sulfate is shown.Zn + Cuso, ZnSO,

Answers

Answer:

The oxidation state of the reducing agent has changed from 0 to +2.

Explanation:

reducing agent is anything that loses electron or gains oxygen

in this case, zinc

How many molecules are in 50.0 grams of NaOH?

Answers

Answer:

7.53 × 10²³ molecules NaOH

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:

Step 1: Define

50.0 g NaOH

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Na - 22.99 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of NaOH - 22.99 + 16.00 + 1.01 = 40 g/mol

Step 3: Convert

Set up:                              \(\displaystyle 50.0 \ g \ NaOH(\frac{1 \ mol NaOH}{40 \ g \ NaOH})(\frac{6.022 \cdot 10^{23} \ molecules \ NaOH}{1 \ mol \ NaOH})\)Multiply:                                                                                                           \(\displaystyle 7.5275 \cdot 10^{23} \ molecules \ NaOH\)

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

7.5275 × 10²³ molecules NaOH ≈ 7.53 × 10²³ molecules NaOH

if 13.5mol Zn and 3.5mol S are mixed together and heated, what mass of ZnS will be produced?

Answers

If the 13.5 mol of the Zn and 3.5 mol of S are mixed together and the heated, the mass of the ZnS will be produced is 93.97 g.

The chemical equation is as :

Zn + S -->  ZnS

The moles of the zinc, Zn the = 13.5 mol

The moles of the sulfur, S = 3.5 mol

1 mole of the Zn produces the 1 mole of the ZnS

1 mole of the S produces the 1 mole of the ZnS

The S is the limiting reactant. The production of the ZnS is depends on the the sulfur.

1 mole of the S produces the 1 mole of the ZnS

The moles of the ZnS = 3.5 mol

The mass of the ZnS = moles × molar mass

The mass of the ZnS = 3.5 × 97.47

The mass of the ZnS = 93.97 g

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besides caffeine what other compound are found in tea leaves?​

Answers

Answer:

Tea also contains two substances related to caffeine: theobromine and theophylline

Answer: Tea also contains two substances related to caffeine: theobromine and theophylline. Finally, it provides a rather unique amino acid called L-theanine, which has some very interesting effects on the brain. This article discusses these 4 stimulates in tea.

What will be produced at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2

Answers

Answer:

At the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

Explanation:

At cathode, reduction reaction takes place.

The dissociation of MgI2 in aqueous solution is Mg2+(aq) and 2I−(aq)

Here, the Iodine reduces to 2I−(aq) from state of 0 (MgI2) to state of -1 (2I−(aq))

Hence, at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

Answer:

During electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced at the cathode

Explanation:

Electrolysis is a process whereby ionic compound is broken down or degraded into smaller substances when electric current flow through it.

During electrolysis of magnesium iodide, At the cathode reduction reaction occur .

MgI2 is dissociated to is Mg2+(aq) and 2I−(aq)

Then Iodine is reduced to 2I−(aq) which is 0 in (MgI2) then change to -1 (2I−(aq))

Therefore;

During electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced at the cathode.

Is SO3 ionic or ionic using the stock system or molecular

Answers

Answer:

Molecular

Explanation:

Using the rules for the nomenclature for naming binary covalent (molecular) compounds, the compound SO3 is named sulfur trioxide. The prefix tri- indicates that the oxygen has a subscript of 3 and that a molecule of sulfur trioxide has three oxygen atoms.

A paleontologist finds a fish fossil in a desert. What might the paleontologist learn from this?

Answers

Answer:

sometime back there might be a water body there

Answer:

Paleontologists can identify organisms that may be ancient relatives of those living today. By looking at fossils from the same layer of rocks, they can also suggest how these organisms lived together in their ancient habitat.

Also, he/she can find out that there was water there millions of year ago.

What happens to the amount of solution when we add food colour to it?

Answers

Answer:

We need more? What else is in the question? This is unanswerable.

Explanation:

1. What type of organic compounds are the reactants in an esterification reaction?

Answers

Esterification is the process that turned salicylic acid and acetic acid into acetylsalicylic acid.

Thus,  The process of creating esters from carboxylic acids is known as esterification. When a carbon is linked to two oxygen atoms, an ester results from one of the oxygens being double-bonded to the carbon while the other oxygen is linked to another carbon.

The letter "R" stands for a carbon chain in the following generic formula for an ester.

Esterification occurs when a carboxylic acid reacts with an alcohol. This reaction can only occur in the presence of an acid catalyst and heat. It takes a lot of energy to remove the -OH from the carboxylic acid, so a catalyst and heat are needed to produce the necessary energy.

Thus, Esterification is the process that turned salicylic acid and acetic acid into acetylsalicylic acid.

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hello HELP ME pLS ANYONE with this question I will give u 18 points pls I need real help here:((​

 hello HELP ME pLS ANYONE with this question I will give u 18 points pls I need real help here:((

Answers

Answer:

Boiling - The process of a liquid changing to gas.

Boiling point - The temperature at which a liquid boils.

Condensing - The process of a gas changing to a liquid.

Distillate - The liquid collect from the condenser.

Residue - The liquid left behind in the distillation flask.

Vapour - Another name for gas.

Hope it helps :)

 hello HELP ME pLS ANYONE with this question I will give u 18 points pls I need real help here:((

When traveling through a different medium, light waves _________.
refract
reflect
speed up
stop moving

Answers

Answer: Refract

Explanation:

How many Noble gases we have in Periodic Table???

Answers

Answer:

Six

Explanation:

6.

The six naturally occurring noble gases are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and the radioactive radon (Rn).

0.386g to milligrams

Answers

Answer:

386 milligrams

Explanation:

Hey there! The answer is:

386 milligrams

Explanation:

To figure this out multiply 0.386 by 1000 because a milligram is 1000x bigger than a gram.

0.386 x 1000 = 386

Also, because it is 1000 times bigger, you can move the decimal over 3 places because there are 3 zeros in 1000.

Let me know if you have any questions! :)

Describe the fractionating column

Answers

Answer:

i dont see it

Explanation:

Answer:

A fractionating column or fractional column is an essential item used in the distillation of liquid mixtures to separate the mixture into its component parts, or fractions, based on the differences in volatilities.

Explanation:

Alka seltzer and water from

Answers

Answer:

ph2h2o

Explanation:

not quite sure explain

What is an isotope and how does their abundance in nature differ from element to element

Answers

Answer:

isotopes, there elements with a diffrent type atomic weight then the original, usally due to a higher amout of neutrons than the original. Some Isotopes are just as useable as the normal versions, but in some cases, such as Uranium, they can be even more radioactive than the original form

During an experiment, a student combines 5.0 g of Reactant A with 5.0 g of Reactant B in a flask. The student observes a reaction taking place. It produces a gas, and the flask feels warm to the touch. When the reaction is complete, the student measures the mass of the contents of the flask and determines it to be 9.3 g. The student claims the balance is broken.

Answers

Based on the law of conservation of mass, the apparent loss in mass of the product is due to the gas evolved.

What is the statement of the law of conservation of mass?

The law of the conservation of mass states that matter cannot be created or destroyed but can be transformed from one form to another.

The law of conservation of mass is applied in chemical reaction.

Based on the law of conservation of mass, the sum of the masses of the reactants is equal to the sum of the masses of the products in a chemical reaction.

Considering the give reaction:

A student combines 5.0 g of Reactant A with 5.0 g of Reactant B in a flask.

Sum of masses of reactants = 10.0 g

Mass of reactant as shown on the balance after the reaction = 9.3 g

Since the reaction produced a gas, the apparent loss in mass of the product is due to the gas evolved.

Hence, the balance is not broken.

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Part C
How many grams of H₂ are needed to produce 12.13 g of NH3?

Answers

Grams of H\(_{2}\) are needed to produced 12.13 g of NH\(_{3}\) are 2.13 g

The balanced chemical equation is :

N\(_{2}\)  +   3H\(_{2}\)  ------>  2NH\(_{3}\)

H = 1 g/mol   and N =14 g/mol

NH\(_{3}\) = 17 g/mol =

6g of H\(_{2}\) ( 3×2)  = 34 g of  NH\(_{3}\) (2× 17)

mass of hydrogen in coumpond ( % mass )  = 6 / 34

                                                                        = 0.1764 or 17.64%

mass of H\(_{2}\) required = % mass × mass of ammonia

                                  = ( 0.1764 × 12.13 ) g

                                  2.13 g

Thus , Grams of H\(_{2}\) are needed to produced 12.13 g of NH\(_{3}\) are 2.13 g

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A student dissolves of aniline in of a solvent with a density of . The student notices that the volume of the solvent does not change when the aniline dissolves in it. Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits.

Answers

Answer:

Molarity: 0.21M

Molality: 0.20m

Explanation:

...dissolves 3.9g of aniline (C6H5NH2) in 200.mL of a solvent with a density of 1.05 g/mL...

To solve this question, we need to find the moles of aniline in 3.9g using its molar mass. Then, we need to find the kg and Liters of solution in order to find molarity (Moles/L solution) and molality (Moles/kg of solvent):

Moles aniline:

Molar mass:

6C: 6* 12.01g/mol = 72.06g/mol

7H: 7*1.008g/mol = 7.056g/mol

N: 1*14.007g/mol = 14.007g/mol

72.06g/mol+7.056g/mol+14.007g/mol = 93.123g/mol

Moles of 3.9g: 3.9g * (1mol / 93.123g) = 0.04188moles

Liters solution:

200mL * (1L / 1000mL) = 0.200L

kg solvent:

200mL * (1.05g/mL) * (1kg/1000g) = 0.210L

Molarity:

0.04188mol / 0.200L = 0.21M

Molality:

0.04188mol / 0.210L =0.20m

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