The approximate momentum of the car is 9.98 × 10^3 kg m/s.
The given car has a mass of 1.20 × 10^3 kg and a velocity of 30.0 km/h. To calculate the approximate momentum of the car, we can use the formula for momentum:
Momentum = mass x velocity
The mass of the car is 1.20 × 10^3 kg. The velocity of the car is 30.0 km/h.
However, we need to convert km/h to m/s to use in the formula because momentum is measured in kg m/s.1 km = 1000 m1 h = 3600 s
Therefore, 30.0 km/h = (30.0 x 1000) / 3600 = 8.33 m/s
Substitute the values into the formula:
Momentum = mass x velocity
Momentum = (1.20 × 10^3) x (8.33)
Momentum = 9.98 × 10^3 kg m/s
Therefore, the approximate momentum of the car is 9.98 × 10^3 kg m/s.
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why did you have to draw circles around each station in order to pinpoint the epicenter? why couldn't you just use the distance from each station to go directly to the epicenter in a straight line? explain.
The ratio of the three circles they draw is equal to the distances from the stations to the epicenter.
Scientists use triangulation to find the epicenter of an earthquake. If seismic data are collected from at least three different locations, their intersection can be used to determine the epicenter. Each earthquake is recorded by numerous seismometers placed in different directions.
The epicenter is the point on the surface directly above the earthquake. A seismic station uses seismometer recordings to detect earthquakes. Determining the epicenter of an earthquake requires records from three separate seismic stations. Triangulation is a method of uniquely identifying earthquakes using distance information determined from three seismic stations.
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If the unbalanced force is -20.0 N and the mass of the object is 3.75 kg, what is the acceleration of the the object while this force is acting?
Answer:
a=-5.3m/s2
Explanation:
F=-20N
m=3.75kg
a=?
F=am /:m
a=F/m
a=-20N/3.75kg
a=-5.3m/s2
A 1,500kg boulder falls off a 120m tall cliff on a planet that has a surface gravitational field of magnitude 3.6 N/kg. Assume that the planet has no atmosphere.
How long does it take for the boulder to strike the ground?
Write your answer using two significant figures.
It takes the boulder approximately 10.4 seconds to strike the ground.
To solve for the time it takes for the boulder to strike the ground, we can use the kinematic equation:
d = vi*t + (1/2)at^2
where d is the distance traveled (which is equal to the height of the cliff, 120m), vi is the initial velocity (which is 0 m/s since the boulder was dropped from rest), a is the acceleration due to gravity (which is the surface gravitational field of the planet, 3.6 N/kg), and t is the time it takes for the boulder to fall.
Rearranging the equation to solve for t, we get:
t = sqrt((2*d)/a)
Plugging in the values we have, we get:
t = sqrt((2*120)/3.6) = 10.4 s
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If a space rover has a mass of 3900 kg on Earth, then what is
its mass when it lands on Mars?
kg
Do not include units in your answer.
If a space rover has a mass of 3900 kg on Earth, then its mass when it lands on Mars will be the same i.e. 3900 kg.
What is mass?Mass is the amount of matter present in the object.
The mass of the object is always constant, anywhere it is on the Earth or Moon or any other planet.
Thus, If a space rover has a mass of 3900 kg on Earth, the mass on Mars when it lands will be 3900kg.
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a charge is placed 33 cm away from another charge. the charges are both 1.2 x 10^-5 coulombs. what is the force on each other
1.44*10^-3N is the force on each other. when 33 centimeters separates one charge from another charge. They both have charges of 1.2 x 10-5 coulombs.
Charge on the first sphere, q 1 =1.2 x 10^-5 C
Charge on the second sphere, q 2 =1.2 x 10^-5 C
Distance between the spheres, r=30cm=0.3m
F= 4πε
q 1 q 2/ r2
Where, ε 0
= Permittivity of free space 4πε 0
=9×10^9Nm2
F= (0.33) 2
1.2 x 10^-5 * 1.2 x 10^-5 C = 1.44*10^-3N
Hence, force between the two small charged spheres is 1.44*10^-3N.
The charges are of same nature. Hence, force between them will be repulsive.
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The state of matter with particles that are not attracted or tightly packed
and are not arranged in a regular pattern; zoom around to easily change
shape and volume *
a.gas
b.liquid
c.solid
It's none of the above hope this helps
What Determines the amount of TE of an object
Answer:
To find the volume of a rectangular object, measure the length, width and height. Multiply the length times the width and multiply the result by the height. The result is the volume. Give the result in cubic units, such as cubic centimeters.
Explanation:
Answer:
Kinetic energy is the energy possessed by an object due to its motion. If an object is moving, then it has kinetic energy. The amount of kinetic energy depends on mass and speed.
Explanation:
Imagine that someone is walking across a carpeted room and then touches a metal doorknob. Describe what happens when a doorknob is touched if there’s a buildup of static electricity.
Answer: if the door knob is metal the static electricity will exit your body, but shock you in the process
Explanation:
if two objects are repelled from each other which force most likely caused this?
A. gravitational
B. weak nuclear
C. electromagnetic
D. strong nuclear
Answer:
it's C! electromagnetic
Explanation:
Two rams run toward each other. One ram has a mass of 44 kg and runs south with a speed of 6 m/s, while the other has a mass of 50 kg and runs north with a speed of 3 m/s. What will the momentum of the system made up of the two rams be after they collide? Assume the total momentum of the system is conserved.
A. 114 kg-m/s south
B. 414 kg-m/s south
C. 414 kg m/s north
D. 114 kg-m/s north
substitute numerical values into the equation in the correct choice in question (3) to find the magnitude of the magnetic field surrounding the rod. b = kmg iℓ = kg 9.80 m/s2 a m = t
The magnitude of the magnetic field surrounding the rod is \(3.92*10^{-6} T\).
To find the magnitude of the magnetic field surrounding the rod, we need to substitute the numerical values into the given equation. Here, we are given that b = kmg iℓ = kg 9.80 m/s2 a m = t. We can substitute the values of k (which is the magnetic constant), m (mass of the rod), g (acceleration due to gravity), i (current in the rod), and ℓ (length of the rod) to get the value of the magnetic field. We are also given the value of a (acceleration of the rod) and t (time), but these values are not required to find the magnetic field.
So, the magnitude of the magnetic field surrounding the rod can be calculated as:
b = kmg iℓ
Substituting the values, we get:
b = \((4\pi *10^{-7} Tm/A) (0.1 kg) (9.80 m/s^2) (2 A) (0.2 m)\)
b = \(3.92*10^{-6} T\)
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if the bar and block are too heavy, one of the strings may break. assuming that the two strings are identical, which one will break first?
The string that will break first depends on the weight of the block or bar subjected to such string.
According to Hook's law, the force applied to an elastic material is directly proportional to the extension of the material.
F= kx
where;
F is the force applied to the object = weight of the objectFor given two identical strings, the string that will break first depends on the mass of the bar and the block.
If the bar is heavier than the block, then the string subjected to the bar will break first.On the other hand, if the block is heavier than the bar, then the string subjected to the block will break first.Thus, the string that will break first depends on the weight of the block or bar subjected to such string.
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submarines use ______ of air to control their depths in water
Answer:
A supply of compressed air is maintained aboard the submarine in air flasks for life support and for use with the ballast tanks. In addition, the submarine has movable sets of short "wings" called hydroplanes on the stern (back) that help to control the angle of the dive.
Explanation:
Hope this helped u
Have a nice day
Heyyy can someone help me plz
The mass of the hammer is 0.454 kg.
(i) Calculate the weight of the hammer.
Explanation:
W = mg
= (0.454 kg)(9.8 m/s^2)
= 4.45 N
12. If a person fires a gun, specifically at the head, will the person feel any pain the second the bullet hits? Explain.
Answer:
No.
Explanation:
It will be soo painful that the person won't be able to feel it any,ore the person will feel nothing but dieing and can't talk
A rat is placed in an environment where the floor gives the rat small electric shocks. The only way to get rid of the shocks is to press a lever in the corner of the box. The rat quickly learns to press the lever. This is an example of
Pressing a lever in the box's corner is the sole method to get rid of the shocks. The rat picks up pressing the lever quite quickly. This is an illustration of negative reinforcement.
What is negative reinforcement?The technique of negative reinforcement can be applied to aid in teaching particular actions.
When something unpleasant or uncomfortable is taken away in response to a stimulus, this is known as negative reinforcement.
Target behavior should gradually grow better with the hope that the unpleasant item will go away.
A rat is placed in an environment where the floor gives the rat small electric shocks. The only way to get rid of the shocks is to press a lever in the corner of the box.
The rat quickly learns to press the lever. This is an example of negative reinforcement
Hence the given condition is an example of negative reinforcement.
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when the outdoor emergency warning siren at cheryl's school was tested, the sound from the siren took 7.0 s to reach her house located 2.40 km from the school. what is the speed of sound in air?
According to question, The speed of sound in air is 342.85 m/s.
Define speed?the speed at which an object's location changes in any direction. The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.Speed tells us how fast something or someone is travelling.
the solution is -
distance d = 2.4 km = 2400 m , time t = 7s
speed of sound = distance/time
speed of sound = 2400/7
speed of sound = 342.85 m/s
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Helping the community!!
You are riding a bicycle. You apply a forward force of 100 N, and you and the
bicycle have a combined mass of 80 kg. What is the acceleration of the
bicycle?
A. 1.5 m/s2
B. 1.8 m/s2
C. 1.25 m/s2
O D. 0.8 m/s2
SURN
Answer:
1.25 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
\(a = \frac{f}{m} \\ \)
f is the force
m is the mass
From the question we have
\(a = \frac{100}{80} = \frac{5}{4} \\ \)
We have the final answer as
1.25 m/s²Hope this helps you
First come first serve, solve it properly and get points.
Answer:
Explanation:
Box 1: heat, metals, independent
Box 2: metals, insulators, dependent
Box 3: attracted, metals, independent
How can a simple machine make it easier to lift a refrigerator?
Select one:
a. It reduces the total amount of work needed to lift a refrigerator.
b. It reduces the force needed to lift the refrigerator.
c. It reduces the distance needed to move the refrigerator.
d. It increases the force needed to lift the refrigerator.
\(\qquad \qquad\huge \underline{\boxed{\sf Answer}}\)
The Correct choice is A
It reduces the total amount of work needed to lift a refrigerator
Which circuit shows three resistors connected in series?
The circuit shows three resistors connected in series is the letter B because he elements are connected on the same wire and there is only one path for the electric current to flow.
What is the difference between series and parallel circuit?The main difference between series and parallel circuit is the way voltage and current are presented. The voltage will be the same at all points in the parallel circuit and the current will vary. In series circuit, it is the voltage that can be different, while the electric current is the same.
In a series electric circuit, the elements are connected on the same wire and there is only one path for the electric current to flow. For this reason, the electric current is the same in all elements of the circuit.
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There are 30 students in Ms. Andrews’ fourth grade class. There are 6 times as many students in the entire fourth grade as there are in Ms. Andrew’s class. Which equation can be used to determine the number of students, n, in the entire fourth grade? *
6 x n = 30
6 + 30 = n
30 x 6 = n
30 ÷ n = 6
Answer:
30×6=n
Explanation:
30 students in her class× 6 = number of students in the entire 4th grade.
an object weighting 100g is thrown upwards from the ground at a speed of 100 m/s.where will the potential energy of the object be two thirds of the kinetic energy?
Answer:
333.3 m
Explanation:
Given
\(m =100g\ =\ 0.1kg\\v = 100 m/s\\g = 10 m/s ^2\)
Potential energy =\(\frac{2}{3}\ of\ Kinetic\ energy\)......Equation(1)
We know that
Potential energy=mgh
Kinetic energy =\(\frac{1}{2} mv^{2}\)
Now From the Equation(1)
\(mgh=\frac{2}{3}*\frac{1}{2} mv^{2}\\ gh=\frac{v^{2} }{3} \\10 * h=\ \frac{10000}{3}\\ h=\ \frac{1000}{3} \\h=333.3\ m\)
Andy wants to rent a limousine to go to the prom, but he cannot afford it by
himself. (He also doesn't want to go to the prom alone!) He decides to
invite some
friends to share the cost of the rental. The limo costs $400 to rent, and each person
who rides requires a $10 insurance fee (in case someone spills an orange Fanta in the
car).
a) Write a function c(x) that models the total cost of the rental in terms of x, the number of people going to the prom.
b) Write a new function p(x) that models the cost for each to the prom.
Answer:
Explanation:
The 16 Days of Activism against gender-based violence is an international campaign that commences on 25 November—the International Day for the Elimination of Violence against Women—and ends on 10 December, Human Rights Day. Originally created by activists, it continues to be coordinated each year by the Center for Women's Global Leadership.The UN supports this civil society-led campaign through the “United Nations Secretary-General’s UNiTE to End Violence against Women Campaign (UNiTE)”. The UNiTE campaign utilizes the colour orange to represent a brighter future, free from violence against women and girls, as a unifying theme running through all of its global activities.Orange the WorldThe involvement of all stakeholders in the mobilization against violence against women, especially in the current context of the COVID pandemic, is essential. This year, the theme set by the Secretary General’s UNiTE campaign was Orange the World: Fund, Respond, Prevent, Collect, with a focus on gender-based violence (GBV) in the context of COVID-19.Our office worked alongside and supported the media to promote campaigns, including on social networks, and awareness-raising sessions for the general public or target groups. The objective was to promote behavioural change by emphasizing positive masculinities and promoting gender equality norms in the context of the COVID-19 pandemic.Due to the lockdowns, services wer forced to define new working modalities to meet the specific needs and expectations of survivors, victims, and people at risk of gender-based violence. UN Human Rights worked with national and local actors to support victims and provide essential services, including the criminal justice system.Finally, the COVID pandemic has highlighted the need for GBV development programmes to respond to the real and expressed needs of women and girls, which is possible through data collection and flexible funding that prioritizes GBV prevention in the COVID-19 budgetary stimulus packages for women’s organizations.
An ideal gas initially at 300 K undergoes an isobaric expansion at 2.50 kPa. If the volume increases from 1.00 m3 to 3.00 m3 and 12.5 kJ is transferred to the gas by heat, what are a. the change in its internal energy and b. its final temperature?
Answer:
a) \( \Delta U = 7.5 kJ \)
b) \(T_{f} = 900 K \)
Explanation:
a) To find the change in its internal energy (U) we need to use the following equation:
\( \Delta U = W + Q \)
Where:
W: is the work done on the system
Q: is the energy transferred into the system by heat = 12.5 kJ
Since we have an isobaric expansion, the work is:
\( W = - P\Delta V = - P(V_{f} - V_{i}) \)
Where:
\(V_{f}\): is the final volume = 3.00 m³
\(V_{i}\): is the initial volume = 1.00 m³
P: is the pressure = 2.50 kPa
\( W = -P(V_{f} - V_{i}) = -2.5 \cdot 10^{3} Pa(3.00 m^{3} - 1.00 m^{3}) = -5.00 \cdot 10^{3} J \)
Now, we can find the change in its internal energy:
\( \Delta U = W + Q = -5.00 \cdot 10^{3} J + 12.5 \cdot 10^{3} J = 7.5 \cdot 10^{3} J \)
b) The final temperature can be found as follows:
\( \frac{V_{i}}{V_{f}} = \frac{T_{i}}{T_{f}} \)
\( T_{f} = \frac{T_{i}*V_{f}}{V_{i}} = \frac{300 K*3.00 m^{3}}{1.00 m^{3}} = 900 K \)
Hence, the final temperature is 900 K.
I hope it helps you!
The _____________ variable is observed, measured, and affected by the independent variable.
Answer: It would be the dependent variable.
Explanation:
The dependent variable is limited and can be affected by the changes and manipulation of the independent variable.
Friction is a force in which two objects __________. A. Collide and move in one direction B. Are repelled from each other C. Slide against each other D. Are attracted from a distance Please select the best answer from the choices provided. A B C D.
Answer: (C) Slide against each other
Explanation:
Think about rubbing our palms together, and they get warm that right there is friction.
Answer:
slide against each other
Explanation:
What is the reason for heat transfer from one substance to another?
OA. difference in pressure
OB.
difference in volume
O c.
difference in temperature
OD.
difference in mass
Answer:
A I think
Explanation:
heated air molecules have a lot if pressure and they try to release that pressure by either expanding or transfering
two planar shock waves travel in the same direction. the first shock wave travels at 420 m/s and the second shock wave travels at 840 m/s. the second shock wave is 10 m behind the first. when the two shocks coalesce and become a single planar shock wave, what is the over-pressure and what is the velocity behind the newly formed shock? assume that the gas is air and it has standard atmospheric properties before it is disturbed by the shocks. do not make a linear assumption.
The Rankine-Hugoniot jump conditions, we get: \(γ * ρ2 * 420 m/s\)
To solve this problem, we can use the Rankine-Hugoniot jump conditions, which relate the properties of a fluid across a shock wave:
\(ρ1 * v1 = ρ2 * v2p1 + ρ1 * v1^2 = p2 + ρ2 * v2^2\)
where ρ is the density, v is the velocity, and p is the pressure.
Let's assume that the shock waves are traveling in the x-direction. We can define a coordinate system where the shock waves intersect at x=0, and the first shock wave is moving to the right, while the second shock wave is 10 m behind and also moving to the right.
Before the shocks intersect, the state of the gas is uniform and can be described by the properties of air at standard atmospheric conditions. We can assume that the gas is at rest, so v1 = v2 = 0.
Let's first find the properties of the gas behind the second shock wave. We can use the Rankine-Hugoniot jump conditions to relate the state behind the second shock wave (denoted by subscript "2") to the standard atmospheric state (denoted by subscript "0"):
\(ρ2 * v2 = ρ0 * v0p2 + ρ2 * v2^2 = p0 + ρ0 * v0^2\)
Since the second shock wave is traveling at 840 m/s, the velocity behind it is also 840 m/s:
v2 = 840 m/s
We can assume that the density behind the second shock wave is higher than the standard atmospheric density because the shock wave compresses the gas. Let's define the density behind the second shock wave as ρ2 = α * ρ0, where α is the density ratio. Similarly, let's define the pressure behind the second shock wave as p2 = β * p0, where β is the pressure ratio.
Substituting these expressions into the Rankine-Hugoniot jump conditions, we get:
\(α * ρ0 * 840 m/s = ρ0 * 0 m/sβ * p0 + α * ρ0 * (840 m/s)^2 = p0 + ρ0 * 0^2\)
Solving for α and β, we get:
α = 0
β = 2.25
This means that the density behind the second shock wave is zero, and the pressure is 2.25 times the standard atmospheric pressure.
Now let's find the properties of the gas behind the first shock wave. We can use the Rankine-Hugoniot jump conditions to relate the state behind the first shock wave (denoted by subscript "1") to the state behind the second shock wave (denoted by subscript "2"):
\(ρ1 * v1 = ρ2 * v2p1 + ρ1 * v1^2 = p2 + ρ2 * v2^2\)
Since the first shock wave is traveling at 420 m/s, the velocity behind it is also 420 m/s:
v1 = 420 m/s
We can assume that the density behind the first shock wave is higher than the density behind the second shock wave because the first shock wave compresses the gas further. Let's define the density behind the first shock wave as\(ρ1 = γ * ρ2,\) where γ is the density ratio. Similarly, let's define the pressure behind the first shock wave as p1 = δ * p2, where δ is the pressure ratio.
Substituting these expressions into the Rankine-Hugoniot jump conditions, we get:
γ * ρ2 * 420 m/s
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