Identification of sweet potato germplasm resistant to pathotypically distinct isolates of Meloidogyne enterolobii from the Carolinas
The study aimed to address the issue of nematode infestation in sweet potato crops by identifying and evaluating resistant germplasm. The researchers collected different sweet potato genotypes and conducted experiments to determine their resistance to pathotypically distinct isolates of Meloidogyne enterolobii found in the Carolinas region.
Through careful screening and evaluation, the study identified several sweet potato germplasm lines that exhibited resistance to the nematode. These resistant lines could serve as valuable resources for breeding programs and crop improvement strategies to develop sweet potato varieties that are more resistant to Meloidogyne enterolobii infestation.
By identifying and characterizing sweet potato germplasm with resistance to specific nematode strains, the study contributes to the development of sustainable and resilient sweet potato varieties. This research is important for the agricultural industry in the Carolinas and beyond, as it offers potential solutions to mitigate the negative impacts of nematode infestation on sweet potato production.
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which one of the following statements about the proteins encoded by the major histocompatibility complex (mhc) is correct? a. antigens presented by class i mhc proteins enable cytotoxic t lymphocytes to detect virus-infected and cancerous cells. b. receptors on cytotoxic t lymphocytes bind to antigens presented by class ii mhc molecules. c. receptors on helper t lymphocytes bind to antigens presented by class i mhc molecules. d. all cells in the body except red blood cells express mhc ii proteins on their surfaces. e. mhc proteins stimulate the release of complement from macrophages.
The following assertions about the proteins that are encoded by the major histocompatibility complex (MHC) are accurate: Antigens given by class I MHC proteins enable cytotoxic T lymphocytes to detect virus-infected and cancerous cells. The correct answer is (A).
There are three categories of MHC-produced protein products: class I, class II, and class III molecules, both of which are involved in the presentation of antigens. The presentation of peptide antigen to the T-cell receptor is the primary function of Class I and II proteins, which are essential components of the immune system.
Since non-self, typically allogeneic organs from one person are transplanted into another, the function of MHC is particularly crucial in organ transplantation. Immunological rejection of transplants can take many forms when MHC presents an antigen.
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"
Final answer:MHC I and MHC II are major histocompatibility complex molecules that play crucial roles in the immune system. MHC I presents antigens derived from intracellular pathogens to CD8+ T cells, while MHC II presents antigens derived from extracellular pathogens to CD4+ T cells. The steps of extracellular antigen processing and presentation involve the uptake of pathogens by antigen-presenting cells, processing of antigens into peptides, and loading of peptides onto MHC II molecules. On the other hand, endogenous antigen processing and presentation involve the production of antigens within the cell, degradation of antigens into peptides, and loading of peptides onto MHC I molecules. These processes are essential for the activation of T cells and the initiation of an immune response.
Explanation:MHC I and MHC II: Roles in Immunity and Antigen Presentation
The Major Histocompatibility Complex (MHC) molecules, specifically MHC I and MHC II, play crucial roles in the immune system by presenting antigens to T cells. These molecules are involved in the recognition and activation of the immune response against pathogens.
MHC IMHC I molecules are found on the surface of all nucleated cells. They play a vital role in presenting antigens derived from intracellular pathogens, such as viruses and intracellular bacteria. The main function of MHC I molecules is to present peptides derived from these pathogens to CD8+ T cells, also known as cytotoxic T cells or killer T cells.
The process of MHC I antigen presentation involves several steps:
Intracellular pathogens are typically broken down into smaller protein fragments within the infected cell. These protein fragments, known as antigens, are transported into the endoplasmic reticulum (ER) of the cell. In the ER, the antigens are further processed and loaded onto MHC I molecules. The MHC I molecules, now presenting the antigenic peptides, are transported to the cell surface. CD8+ T cells recognize the antigenic peptides presented by MHC I molecules and initiate an immune response against the infected cell. MHC IIMHC II molecules are primarily found on antigen-presenting cells, including dendritic cells, macrophages, and B cells. They are responsible for presenting antigens derived from extracellular pathogens, such as bacteria and parasites. MHC II molecules present antigens to CD4+ T cells, also known as helper T cells.
The process of MHC II antigen presentation involves the following steps:
Extracellular pathogens are taken up by antigen-presenting cells through phagocytosis or endocytosis. Within the antigen-presenting cell, the pathogens are broken down into smaller protein fragments. These protein fragments, or antigens, are then loaded onto MHC II molecules in specialized compartments called MHC II compartments. The MHC II molecules, now presenting the antigenic peptides, are transported to the cell surface. CD4+ T cells recognize the antigenic peptides presented by MHC II molecules and initiate an immune response, activating other immune cells to eliminate the pathogen.Overall, MHC I and MHC II molecules play critical roles in the immune system by presenting antigens to T cells, which are essential for the activation of an immune response against intracellular and extracellular pathogens, respectively.
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I’m am small scale.
And I have scales.
I am an unusual reptile.
..That is, I have winged limbs.
What am I?
Answer:
I think it is the Draco lizard, buy I am not 100% sure
Explanation:
In a water molecule, the electronegativity of the oxygen atom is high where the
hydrogen is low.
Draw the directionality of the pull between the hydrogen and oxygen atoms.
O
Answer:
drawing
Explanation:
Draw:
Draw 2 water molecules, H2O. connect the Hydrogen to the Oxygen.
FILL IN THE BLANK the beta-hemolysis of blood agar observed with streptococcus pyogenes is due to the presence of _______.
FILL IN THE BLANK: the beta-hemolysis of blood agar observed with Streptococcus pyogenes is due to the presence of streptolysin O.
Beta-hemolysis refers to the complete lysis of red blood cells, resulting in a clear zone around the bacterial colonies on blood agar. Streptococcus pyogenes, a pathogenic bacterium responsible for various infections, produces an exotoxin called streptolysin O. Streptolysin O is a hemolysin that binds to cholesterol in the host cell membranes, forming pores that disrupt the integrity of the red blood cells. This lysis of the red blood cells leads to the characteristic beta-hemolytic appearance on blood agar plates. The presence of streptolysin O allows S. pyogenes to acquire essential nutrients from the lysed red blood cells and evade the host immune response.
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4. Decide whether sarcodines are more like ciliates or sporozoans. Explain.
Sarcodines are more like sporozoans because both do not have any external locomotory organs. Some of their species are parasitic in nature.
Sarcodines are the organisms of the superclass Sarcodina of the sub-phylum Protozoa. They are characterized by their ability to form pseudopodia for locomotion and entrapment of food. They are free-living as well as parasitic. The examples include: Amoeba, Entamoeba histolytica, etc.
Sporozoans are the organisms of the class Sporozoa. The organisms are identified for their endo-parasitic nature. They do not have locomotory organs and therefore are sessile. They have alternate sexual and asexual life cycle. The examples include: Plasmodium, Monocystis, etc.
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can you consider having wavy hair as a case of incomplete dominance pattern?why you say so?
Answer:
Explanation:
Hair type is an interesting case of something called incomplete dominance. What this means is that with hair type, if you have one of each version of the gene, you get a mix of the two or wavy hair. So for hair type, CC gives curly, Cs gives wavy and ss gives straight hair. Back to your specific situation.
Place the following terms or examples within the correct category.Hyaline Cartilage-Forms articular cartilage-Composes epiphyseal plates-Attaches to ribs of sternumFibrocartilage-Weight-bearing cartilage-Withstands compression-Forms intervertebral discs
Hyaline Cartilage:
Forms articular cartilage.Composes epiphyseal plates.Attaches to ribs of sternum.Fibrocartilage:
Withstands compression.Forms intervertebral discs.Weight-bearing cartilage.Hyaline cartilage is a type of cartilage that is found in many areas of the body, including the joints and the growth plates of bones. It is smooth and glossy and helps to cushion joints during movement. It is also important in bone growth, as it composes the epiphyseal plates. Additionally, hyaline cartilage attaches to the ribs of the sternum, forming the costal cartilage.
Fibrocartilage, on the other hand, is a type of cartilage that is designed to withstand compression and is found in weight-bearing areas of the body. It forms the intervertebral discs in the spine and is also found in the knee joint. Fibrocartilage is tough and durable, allowing it to resist wear and tear over time.
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The maintenance of a self-sustaining ecosystem requires a
A.soil that is acidic
B.constant temperature
C.greater numberof herbivores than producers
D.cycling of materials between organisms and their environment
In order to safely bring the fossilized remains of a yeti down the side of a snowy mountain, they are strapped to a sled - the combination of which weighs 972 N - then carefully lowered down the 19.8∘ incline. To ensure the fossil is not damaged, it is brought down the snowy slope at a constant 1.92 m/s Although the runners of the sled are smooth, they are not free of friction; the coefficient of kinetic friction between the runners and the snow is 0.107. Assuming the rope is kept taut and parallel to the incline, what must be the tension (in newtons) in it
The tension in the rope is calculated as 33.7 N.
Weight of sled and fossil, w = 972 N Inclination angle of slope, θ = 19.8°
Speed of sled, v = 1.92 m/s
Coefficient of kinetic friction between sled runners and snow, μ = 0.107
To find:
Tension in the rope, T The forces acting on the sled are the gravitational force (Fg), the normal force (Fn) and the force of friction (Ff). The normal force is perpendicular to the slope and equal to the component of the gravitational force perpendicular to the slope. The force of friction is parallel to the slope and opposite the direction of motion.
The net force acting on the sled is given by the expression:
F net = ma
Since the sled moves with constant velocity, a = 0.
Therefore, F net = 0. F net = Fg sinθ - Ff = 0⇒ Fg sinθ = Ff
Since the speed of sled is constant, work done by tension in the rope is equal to work done by frictional force.
Hence, T = Ff = μFn
Where F n = Fg cosθ = w cosθ
Putting all the values,
T = μw cos θ sinθ= sin 19.8°cos 19.8°= 0.3365T = 0.107 × 972 × 0.3365T = 33.7 N
The rope is 33.7 N. The given problem is related to the tension in the rope. The tension in the rope is calculated as 33.7 N.
To bring down the fossil safely down the slope, the tension in the rope is 33.7 N. The gravitational force is acting perpendicular to the slope and the force of friction is acting parallel to the slope. The normal force is the component of gravitational force acting perpendicular to the slope. The sled moves down the slope with a constant velocity. The force acting on the sled is equal and opposite to the force of tension in the rope. The force of friction is given by the expression,
Ff = μFn,
where Fn = Fg cosθ = w cosθ.
Therefore, the tension in the rope is calculated as 33.7 N.
To bring down the fossil safely down the slope, the tension in the rope must be 33.7 N.
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why does the malaria disease persist in the human population
Malaria persists in the human population due to the complexity of the parasite’s life cycle, the endemic nature of the disease in many parts of the world, drug resistance, and human movement.
Malaria is a life-threatening disease caused by parasites transmitted to humans through the bites of infected female Anopheles mosquitoes. The malaria parasite can also be transmitted through blood transfusions, organ transplantation, and from mother to her fetus before or during delivery.Malaria persists in the human population due to various reasons.
Firstly, the malaria parasite has a complex life cycle, which allows it to evade the host’s immune system. The parasite has different stages of development, some of which occur inside the mosquito and others in the human host.
The parasite undergoes genetic recombination to generate new strains, making it difficult for the host’s immune system to develop long-term immunity against the disease.
Secondly, the disease is endemic in tropical and subtropical regions of the world, where people have little or no access to medical care and preventative measures.
Poverty, conflict, and poor infrastructure make it difficult to implement malaria control strategies, such as the use of insecticide-treated bed nets, indoor residual spraying, and effective drugs.
Furthermore, the malaria parasite has developed resistance to many drugs, including chloroquine and sulfadoxine-pyrimethamine. This makes treatment of the disease more difficult and costly, as more expensive drugs are required.
Finally, human movement, including migration and travel, contributes to the spread of malaria. People infected with malaria can carry the parasite to other areas and infect mosquitoes in those areas, thereby spreading the disease.
In conclusion, malaria persists in the human population due to the complexity of the parasite’s life cycle, the endemic nature of the disease in many parts of the world, drug resistance, and human movement. It is important to continue research efforts to develop effective vaccines and drugs to control the disease.
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is an endonuclease, encoded by cas genes in the bacterial genome, that cleaves invasive viral dna.
Cas endonuclease, encoded by cas genes in bacterial genomes, is an enzyme that specifically cleaves invasive viral DNA to protect bacteria from viral infections.
Cas endonuclease is a part of the CRISPR-Cas system, which functions as an adaptive immune defense mechanism for bacteria and archaea. The cas genes, present in the bacterial genome, encode various Cas proteins, including the endonuclease. When a viral infection occurs, the CRISPR-Cas system captures snippets of viral DNA, incorporating them into CRISPR arrays within the bacterial genome.
This process generates a genetic memory of the invader. If the same virus infects again, the CRISPR-Cas system uses the stored information to guide Cas endonucleases to specifically target and cleave the invasive viral DNA, thus neutralizing the viral threat and protecting the bacterial cell.
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dna is coiled tightly around histones prokaryotic or eukaryotict/f
In eukaryotic cells, DNA is coiled tightly around histone proteins, forming a structure known as nucleosomes.
This compact arrangement allows the long DNA molecules to fit within the nucleus of the cell. Histones play a crucial role in organizing the DNA and regulating gene expression.
Prokaryotic cells, on the other hand, do not have a nucleus, and their DNA is not organized into chromosomes as it is in eukaryotic cells. Instead, prokaryotic DNA is typically arranged in a single, circular molecule called a plasmid. While prokaryotes lack histones, they do have other proteins that help compact and organize their DNA, but the overall structure is less complex than that found in eukaryotes.
In summary, the statement that DNA is coiled tightly around histones is true for eukaryotic cells, while prokaryotic cells have a simpler DNA organization without histones. The difference in DNA packaging and organization is one of the key distinctions between these two types of cells.
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What green algal group are you not likely to find in fresh water? Ulvophyceae Charophyceae Chlorophyceae Embryophyccae Which of these is not a shared, derived characteristic (synapomorphy) of land plants (Embryophytes), chlorophyll b antheridia and archegonia with sterie jacket layers multicololar embryos ability to make sporopolenha-walled spores.
The group of green algae that are not likely to be found in fresh water is Charophyceae.
Charophyceae, a class of green algae, are mostly found in freshwater habitats but are also found in soil or other damp places. A distinct feature of Charophyceae is their sporophyte with foot, seta, and capsule. There are multicellular sex organs, antheridia and archegonia with a sterile jacket layer, which is not present in other green algae.
Land plants (Embryophytes) have many characteristics that they do not share with green algae. Chlorophyll b is a shared, derived characteristic of land plants (Embryophytes), while multilayered embryos, sporopollenin-walled spores, and gametangia with a sterile jacket layer are also unique to them.
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How does the optimum pH and optimum temperature can affect the enzyme function?
2. How are prokaryotic cells different in size in comparison to eukaryotic cells?
Answer: prokaryotic are smaller than eukaryotic cells
Explanation: prokaryotic are smaller because they have no nucleus, and they lack organelles.
How do feedback mechanisms help maintain homeostasis?
it involves negative feedback loop
Explanation:
the loop allows living organisms to maintain homeostasis
At the end of _____ and cytokinesis, haploid cells contain chromosomes that each consist of two sister chromatids. at the end of _____ and cytokinesis, haploid cells contain chromosomes that each consist of two sister chromatids. interphase metaphase ii telophase i telophase ii telophase submit
At the end of meiosis II and cytokinesis, haploid cells contain chromosomes that each consist of two sister chromatids. Meiosis II is the second division of meiosis and it follows meiosis I. During meiosis II, the two sister chromatids of each chromosome are separated from each other, resulting in the production of haploid daughter cells.
The process of meiosis involves two rounds of cell division, each consisting of different stages. In meiosis I, the homologous chromosomes pair up and exchange genetic material in a process called crossing over. The chromosomes are then separated, resulting in the production of two haploid daughter cells that each contain a mix of genetic material from both parents.
In meiosis II, the sister chromatids of each chromosome are separated from each other. This results in the production of four haploid daughter cells, each containing a single set of chromosomes that each consist of two sister chromatids. These haploid daughter cells can then go on to participate in sexual reproduction, combining with another haploid cell to form a new, genetically diverse individual.
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At the end of Telophase I and cytokinesis, haploid cells contain chromosomes that each consist of two sister chromatids. At the end of Telophase II and cytokinesis, haploid cells contain chromosomes that each exist independently.
Explanation:The question is asking about the specific stages in meiosis where haploid cells contain chromosomes that each consist of two sister chromatids. At the end of Telophase I and cytokinesis, haploid cells contain chromosomes that each consist of two sister chromatids. This happens because during Telophase I, chromosome pairs reach the poles of the cell, and the cytoplasm divides. Each resulting haploid cell, therefore, has the half number of chromosomes, and each chromosome consists of two sister chromatids. On the other hand, at the end of Telophase II and cytokinesis, haploid cells contain chromosomes that each exist independently, not as sister chromatids, because during Anaphase II, the sister chromatids separate.
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diphtheriae and pyogenes are gram-positive bacteria that have toxic properties due to proteins on their cell walls.
Corynebacterium diphtheriae and Streptococcus pyogenes are gram-positive bacteria that have toxic properties due to proteins on their cell walls.
Gram positive Bacteria- The color that gram-positive microbes acquire when stained is used to identify them. Hans Christian Gram created the staining method in 1884. The crystal violet dye employed in the staining procedure is retained by the thick peptidoglycan cell wall seen in gram-positive organisms.
Peptidoglycan- The cytoplasmic membrane of the majority of bacterial species is covered in a dense substance known as peptidoglycan. It protects bacterial cells from environmental stress and aids in maintaining cell shape throughout the life cycle. Peptidoglycan synthesis plays a crucial part in regulating bacterial cell cycle.
The given question is incomplete, find below the complete question.
------------diphtheriae and -------------pyogenes are gram-positive bacteria that have toxic properties due to proteins on their cell walls.
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The part of the brain that helps you keep from falling is the _______.
how did a rock of the great plains get to the rocky mountains?
Answer:
Hi, so the Great Plains are made of sedimentary rock and were subducted and melted to magma which cooled to igneous rock, was uplifted and then formed the Rocky Mountains.
Explanation:
Basically it melted then cooled into igneous rock then was lifted and formed the rocky mountains!
-Hailey :)
During the secondary stage of lymphogranuloma venereum, the causative agent enters the lymphatic vessels, replicates in the lymph nodes, and causes them to develop into ____a. buboesb. Chlamydiac. Chancresd. sporozoite
The correct answer is option A.
During the secondary stage of lymphogranuloma venereum, the causative agent enters the lymphatic vessels, replicates in the lymph nodes, and causes them to develop into buboes.
Buboes are a characteristic feature of the disease and play a significant role in its diagnosis. They are tender and may be accompanied by other symptoms such as fever and malaise. It is important to note that lymphogranuloma venereum is a sexually transmitted infection caused by certain serovars of Chlamydia trachomatis, and if left untreated, it can progress to severe complications affecting various organs and systems in the body.
In conclusion, the causative agent for lymphogranuloma venereum is the bacteria Chlamydia trachomatis. Chancres are typically associated with syphilis, and sporozoites are a type of protozoan parasite.
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1. The cestodes or tapeworms have a complex life cycle in which____ are released and pass out of human host in feces. Intermediate host like farm animals become infected via contaminated food and-or water. Humans become host again by consuming ____.
A. proglottids; larvae in undecooked meat
B. fertilized eggs; mature worms in undercooked meat
C. larvae; mature worms in undercooked meat
D. Proglottiids; mature worms in undercooked meat
Tapeworms have a life cycle in which proglottids are released in feces, farm animals become infected by consuming contaminated food or water, and humans become hosts again by consuming undercooked meat containing larvae. The correct answer to the question is: A. proglottids; larvae in undercooked meat.
The cestodes, also known as tapeworms, have a complex life cycle. In this life cycle, proglottids or segments of the tapeworm are released from the human host and passed out in feces. These proglottids contain fertilized eggs. The intermediate host, such as farm animals, can become infected by ingesting contaminated food or water that contains these eggs. Once inside the intermediate host, the eggs develop into larvae.
Humans can become hosts again by consuming undercooked meat that contains the mature worms. When a person consumes the undercooked meat, the larvae from the meat will develop into mature worms inside their intestines, completing the life cycle of the tapeworm.
The proglottids, containing the fertilized eggs, are released from the human host and passed out in feces. The intermediate host, such as farm animals, become infected by consuming contaminated food or water that contains these proglottids. Humans become hosts again by consuming undercooked meat that contains the larvae. The larvae then develop into mature worms in the human intestines.
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In bacterial transformation what is the purpose of heat shock.
Answer:
Heat shock transformation uses a calcium rich environment provided by calcium chloride to counteract the electrostatic repulsion between the plasmid DNA and bacterial cellular membrane. A sudden increase in temperature creates pores in the plasma membrane of the bacteria and allows for plasmid DNA to enter the bacterial cell.
Explanation:
does this help you???
Which country did Brown Swiss originate from?
O Holland
O Switzerland
O Scotland
O Canada
Answer:
Switzerland.
Explanation:
=)
In what way are lungs well ventilated?
Lungs ventilation is an automatic, apparently handy inspiratory growth and expiratory contraction of the chest cage.
Air flows due to pressure variations between the atmosphere and the gases in the lungs. Air, like different gases, flows from a region with higher stress to a region with decrease stress. Muscular respiration moves and cringe of elastic tissues create the changes in strain that result in ventilation.
Lung air flow is an important a part of breathing, accountable for the fuel trade between alveoli and the atmospheric air. It entails often replacing stale gases within the lungs with fresh gases from the environment.
Deep respiratory exercises may also help increase lung capacity. for instance, the British Lung foundation say that deep respiration can help clean mucus from the lungs after pneumonia, allowing extra air to flow into. This act of ordinary breathing has a rather consistent charge and inspiratory extent that collectively represent normal respiratory rhythm.
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Lungs are ventilated through Pulmonary Ventilation.
Pulmonary ventilation is the process through which air flows into the lungs i.e. Inhalation and air flows out of the lungs i.e. Exhalation.
These processes depend upon the volume change in the cavity of chest.
Inhalation: Process of taking air into lungs. It occurs due to the contraction of muscles in which Diaphragm contracts leading to increase in volume of thoracic cavity.
Exhalation: Process of letting air out from lungs. It occurs due to the relaxation of muscles in which Diaphragm relaxes leading to decrease in volume of thoracic cavity.
Proper ventilation helps to keep the air fresh maintaining a flow of fresh air inside and dirty air outside. Air travels through mouth and goes down into the trachea or windpipe through the pharynx.
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The turbidity of water measures how much _____is in the water?
The turbidity of water measures how much Suspended particles are present in the water
Meaning of TurbidityTurbidity can be defined as a method or approach that measures the level of transparency possessed by a liquid primarily water.
Turbidity ascertain that a liquid is clear or full of suspended particles in it by passing light through the liquid.
In conclusion, The turbidity of water measures the amount of Suspended particles present in the body of water
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According to the text, what is the procces by which water vapor in the air changes into liquid water?
A) water in the air
B) water sticks to specks
C) condensation
D) precipitation
Which two statements about gravity and the formation of the solar system are true? A. Gravity pushed the growing planets away from the Sun. B. Gravity pulls all matter in a growing planet toward its center. C. Gravity holds a new star in one place while its planets form. D. Gravity held the growing planets in orbit around the Sun,
Answer:
B and D
Explanation:
Describe one way that the marathon runner's body uses homeostasis.
Answer:
I will attempt to answer your question.
When the marathon runner begins to run there is the need for increased circulation for blood, nutrients,oxygen,etc to reach vital centers of the body, as an adaptation to the increased muscular activity. Baroreceptors in the coronary artery and the arch of the aorta detect the increase in blood pressure(this becomes the stimulus) and send signals to the brain (control center) that is the cardiac center located in the medulla oblongata. The motor response goes to the smooth muscles of the blood vessels to dilate and for the heart to beat faster. This is one way
Also, the respiratory rate needs to increase so that there will be enough supply of oxygen and removal of CO2 and this is controlled by the sympathetic division of the autonomic nervous system. So the person begins to breathe faster in order to produce more glucose. There is increased glycogenolysis to quickly convert glycogen (by glucagon) into glucose. This will avail enough energy for the brain and cardinal organs. This is two
Again, as the runner runs, excess heat build up must be reduced which is achieved through sweating so that the body begins to cool down or regulate it's temperature. This is three
There's a lot more...
Answer the following question. From the evolutionary tree for dogs and wolves, how many times do you infer that dogs were domesticated from wolves?
A. None; dogs were domesticated from coyotes
B. Once
C. More than once
When it comes to the evolutionary tree for dogs and wolves, it is inferred that dogs were domesticated from wolves. Dogs are the domesticated form of gray wolves, which have been domesticated at least once, but perhaps more than once. The answer is B.
Dogs are members of the Canidae family and are a subspecies of the gray wolf. Dogs are thought to have been domesticated from wolves between 20,000 and 40,000 years ago as hunting partners and guards.
They were bred for specific tasks, resulting in a diverse range of species. They have been used as herders, guardians, hunters, and companions in different cultures throughout history.
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