\(555\frac{2}{17} =555+\frac{2}{17} =555+0.1176 = 555.1176=600\)
ANSWER: 600
Ok done. Thank to me :>
Use the distributive property to write an equivalent expression.
8(4t + 9)
Answer:
32t+72
Step-by-step explanation:
What is the solution of 5/2x -7 = 3/4x +4
Answer:
Step-by-step explanation:
10x-35=12x + 12
10X-12X=12+35
-2x=47
2x=-47
x=-47/2
Suppose that the function f is given by f(z, 3) = 4 – 8 – +1. Find the critical points of f. For each critical point of f. determine whether it is a local minimum, local maximum, or a saddle point.
The critical point of f at z = 1 is a local minimum.
To find the critical points of the function f(z, 3) = 4z^2 - 8z + 1, we need to find the values of z where the first partial derivatives with respect to z are equal to zero. Let's solve it step by step.
Take the partial derivative of f with respect to z:
∂f/∂z = 8z - 8
Set the derivative equal to zero and solve for z:
8z - 8 = 0
8z = 8
z = 1
The critical point of f occurs when z = 1.
To determine whether the critical point is a local minimum, local maximum, or a saddle point, we can use the second partial derivative test. We need to calculate the second partial derivative ∂²f/∂z² and evaluate it at the critical point (z = 1).
Taking the second partial derivative of f with respect to z:
∂²f/∂z² = 8
Evaluate the second derivative at the critical point:
∂²f/∂z² at z = 1 is 8.
Analyzing the second derivative:
Since the second derivative ∂²f/∂z² = 8 is positive, the critical point (z = 1) corresponds to a local minimum.
Therefore, the critical point of f at z = 1 is a local minimum.
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(co 6) a university wants to plan how many classes to run next semester. to do this, it needs to estimate on average how many students register each semester. which statistical method would be best to use in this situation? g
The statistical method that would be best to use in this situation is b) Regression analysis.
Regression analysis is a statistical technique used to examine the relationship between a dependent variable (in this case, the number of students registering each semester) and one or more independent variables (such as time, semester, or any other relevant factors). By analyzing past data on the number of students registering each semester, regression analysis can help identify trends, patterns, and the average number of students registering.
Using regression analysis, the university can estimate the average number of students registering each semester based on historical data and use this information to plan how many classes to run in the upcoming semester. It allows for a quantitative analysis and prediction based on the relationship between variables, making it a suitable choice for estimating the average number of students in this scenario.
Hence the answer is Regression analysis.
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plz help thxxxxxxxxxxxxxxxxxx
Answer:
slope is positive 2/1
Step-by-step explanation:
Answer:
a) the slope is 2 because the line goes from (4,1) to (5,3)
I d k any of the bonus questions tho sorryyyy
Step-by-step explanation:
What is another term that accountants use that means the same as "cost recovery"? 3. Why for every class of asset does the table list one additional year? For example, there are six years listed for 5-year property classes. 4. What are examples of assets that fall into the 5-year class? This and following questions relate to your basic understanding of non-tax depreciation from financial accounting. 5. If you bought an asset for $100 with a 5-year life and no residual value, how much would you depreciate each year under straight-line? 6. If you bought an asset for $100 with a 5-year live with no residual value, how much would you depreciate in years 1 through 5 under double-declining balance. Do not use the tables below. Round to nearest penny, and ensure that total is $100. Year 1 2 5
Another term that accountants use to refer to "cost recovery" is "cost reimbursement."
What is the alternative term for "cost recovery" used by accountants?In accounting, "cost recovery" refers to the process of recouping or recovering the expenses incurred by a company through various means such as sales revenue, reimbursements, or cost allocation.
Another term commonly used to describe this concept is "cost reimbursement." It signifies the reimbursement of costs to the company, ensuring that the expenses are covered and recovered, often through reimbursement agreements with clients or partners.
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Help!!!!!!!! someone give me the correct answer to this question.
I will mark you brainliest for the correct answer.
This is a big test.
Please help!!!
Answer:
20
Steps:
x + (x+5) + (7x-5) = 180
x + x + 5 + 7x - 5 = 180
2x + 5 + 7x - 5 = 180
9x + 5 - 5 = 180
9x = 180
x = 180/9
x = 20
∂²p/∂r² + 1/r ∂p/∂r = ϕμC/k ∂p/∂t
derivation of equations
1-partial derivative diffusivity equation spherical flow
2- partial derivative diffusivity equation hemi- spherical flow
The partial derivative diffusivity equation for spherical flow is ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t, and for hemispherical flow, it is the same equation.
1. The partial derivative diffusivity equation for spherical flow is derived from the spherical coordinate system and applies to radial flow in a spherical geometry. It can be expressed as ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t.
2. The partial derivative diffusivity equation for hemispherical flow is derived from the hemispherical coordinate system and applies to radial flow in a hemispherical geometry. It can be expressed as ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t.
1. For the derivation of the partial derivative diffusivity equation for spherical flow, we consider a spherical coordinate system with the radial direction (r), the azimuthal angle (θ), and the polar angle (φ). By assuming steady-state flow and neglecting the other coordinate directions, we focus on radial flow. Applying the Laplace operator (∇²) in spherical coordinates, we obtain ∇²p = (1/r²) (∂/∂r) (r² ∂p/∂r). Simplifying this expression, we arrive at ∂²p/∂r² + (1/r) ∂p/∂r.
2. Similarly, for the derivation of the partial derivative diffusivity equation for hemispherical flow, we consider a hemispherical coordinate system with the radial direction (r), the azimuthal angle (θ), and the elevation angle (ε). Again, assuming steady-state flow and neglecting the other coordinate directions, we focus on radial flow. Applying the Laplace operator (∇²) in hemispherical coordinates, we obtain ∇²p = (1/r²) (∂/∂r) (r² ∂p/∂r). Simplifying this expression, we arrive at ∂²p/∂r² + (1/r) ∂p/∂r.
In both cases, the term ϕμC/k ∂p/∂t represents the source or sink term, where ϕ is the porosity, μ is the fluid viscosity, C is the compressibility, k is the permeability, and ∂p/∂t is the change in pressure over time.
These equations are commonly used in fluid mechanics and petroleum engineering to describe radial flow behavior in spherical and hemispherical geometries, respectively.
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Tom made fruit punch for a party. He mixed 2 gallons of orange juice, 4 quarts of pineapple juice, 3 pints of cranberry juice, and 8 cups of apple juice. How many quarts did he make in all?
Using the Normal approximation, the probability that sample average of the heights falls
within 2 centimeter of the population average is 0.9253374
Feedback
Using the Normal approximation, the computation of a probability associated with the random
variable is conducted with the functions of the Normal distribution for the same expectation and
standard deviation as the original distribution.
The expectation is μ = 170.035. The standard deviation is σ = 1.122.
The event corresponds to the interval [μ - 2, μ + 2]. Therefore, the approximated probability is
mu + 2]. Therefore, the approximated probability is
> mu <- 170.035
> sig <- 1.122
> pnorm(mu+2,mu,sig) - pnorm(mu-2,mu,sig)
[1] 0.9253374
The correct answe
Using the Normal approximation, the probability that sample average of the heights falls between [μ - 2, μ + 2] is approximately 0.9253374.
The Normal approximation is used for estimating the probabilities of a random variable. It is applied when the sample size is large enough, and the mean and variance of the population are known. In this case, the sample size is large enough, and the mean and variance of the population are known.The event corresponds to the interval [μ - 2, μ + 2]. Therefore, the approximated probability is 0.9253374, which is calculated using the standard Normal distribution table. The Z-score for μ - 2 is -2/σ, and the Z-score for μ + 2 is 2/σ. The probability between the two Z-scores is calculated by finding the difference between the two values in the table.
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how to solve this question:
5y+6-(5y+y)
Answer: 6-y
explanation:
add the numbers in the bracket as they have the same variable (y):
5y + 6 - 6y
5y and - 6y have the same variable, so solve them:
you get
6 - 1y
the left over numbers don't have the same variable so they can't be simplified further.
Answer:
There is no "=" sign, so this is just an expression. To solve means to simplify by combining like terms, where possible.
5y+6-(5y+y) = -y + 6
Step-by-step explanation:
5y+6-(5y+y)
5y+6-(6y) [Simplify by combining like terms]
5y+6-6y [Remove the parentheses, remembering to multiply 6y by -1]
-y + 6 [Combine like terms]
The function f(x) is shown on the graph.
What is f(0)?
18+
Iy
15
O O only
O -6 only
O-2, -1, 1, and 3 only
0 -6, -2, -1, 1, and 3 only
12
fix)
9
6-
-3
-3
X
دیا
L9+
-12+
-15-
9514 1404 393
Answer:
(b) -6 only
Step-by-step explanation:
There is only one point of intersection of the graph with the vertical line x=0. That is where the graph crosses the y-axis, at (0, -6).
f(0) = -6 (only)
_____
Additional comment
The fact that f(x) is called a function means that f(0) can have only one value. This eliminates the last two answer choices. The graph crosses y=0 at several points, all having different x-values than x=0. f(0) ≠ 0, eliminating the first choice.
Solve for n. 11(n – 1) + 35 = 3n plz help
\(answer \\ = - 3 \\ solution \\ 11(n - 1) + 35 = 3n \\ or \: 11n - 11 + 35 = 3n \\ or \: 11n + 24 = 3n \\ or \: 11n - 3n = - 24 \\ or \: 8n = - 24 \\ or \: n = \frac{ - 24}{8} \\ n = - 3 \\ hope \: it \: helps\)
Help=10pts
5,6,7,and 8 plz
Answer:
number 5:4/12
#6: 25/45
#7: 26/44
#8: 52/30
Step-by-step explanation:
Answer:
5) 1/3=x/12
12=3x
3x=12 (divide both sides)
12 divided by 3 = 4
therefore, x = 4
6) 5/9=25/y (cross multiply the numbers)
after cross multiplying you should get: 5y=225
divide both sides to get 45
therefore, y = 45
7) 26/z = 13/22 (cross multiply numbers)
after cross multiplying, you should get: 572=13z (swap the numbers)
after swapping the number, you should get: 13z=572 (divide both sides)
after dividing you should get 44
therefore, z = 44
8) b/30 = 2.6/1.5 (simplify expression)
after simplifying you should get: b/30=26/15 (cross multiply after)
after cross multiplying you should get: 15b = 780 (divide both sides)
after dividing both sides, you should get: 52
therefore, b = 52
Hope this helps:)!
For exercise, Francesca walks laps around a track. She walked 1 lap around the track in 4 minutes. If each lap is 440 yards, how fast did Francesca walk?
A.
125 yards per minute
B.
110 yards per minute
C.
400 yards per minute
D.
44 yards per minute
Answer: B
Step-by-step explanation: You divide 440 and 4
Answer:
B. 110 yards per minute
Step-by-step explanation:
This is because 110 x 4 is 440 or 110 +110 +100 +110 = 440
David made a batch of 5 liters of blue liquid everyday for 3 days how many milliliters of blue liquid did he make in all
Answer: 15000 millimeters
Step-by-step explanation:
Since David David made a batch of 5 liters of blue liquid everyday. The number of liters that'll be made for 3 days will be:
= 5 liters × 3
= 15 liters
We should note that 1000 millimeters = 1 liter. Therefore, 15 liters will be converted to millimeters which will be:
= 15 × 1000
= 15000 millimeters
Rewrite without parentheses. Simplify your answer as much as possible.
Given the expression:
\(-9x^5(-5x^3-2x^2+4x)\)We use the distributive property for -1:
\(9x^5(5x^3+2x^2-4x)\)Now, we factorize x:
\(9x^6(5x^2+2x-4)\)Please help only answer if correct due in 10 minutes!!
Given that IS-LM model:
C = 100 + 0.5(Y −T) ,
I = 100 −10r , G = T = 50
=100−50
P
Where, M = 1000 and P = 5;
Please get the IS and LM equations. Get the equilibrium real income and interest rate;
If the government expenditure increases by 50, get the new equilibrium for income and interest rate. Show graphically the crowding out effect.
The new equilibrium for income and interest rate will be as follows.IS equation:Y = (1/0.5) * (100 + I (r) + G - 0.5T)LM equation:r = (1/10) (M/P) - (1/10) Y + (5/10)And, G and T = 100.New Equilibrium:Y = 1080, r = 4.
The IS-LM model is an economic model that demonstrates how the goods market and monetary sector interact in tandem to determine the level of interest rates and national income.
The model explains equilibrium in the market for goods (IS) as well as equilibrium in the money market (LM).The following are the IS and LM equations.IS equation:Y = C (Y - T) + I (r) + GAnd,Y = C (Y - T) + I (r) + G ⇒ Y = (1 / (1 - 0.5)) * (100 + I (r) + G - 0.5 T)The LM equation:M / P = L (r, Y)Where L (r, Y) represents the demand for money, the money supply, and the price level, respectively.\
The equation above can be written as:r = (1/10) (M/P) - (1/10) YNew equilibrium for income and interest rate:If the government expenditure increases by 50,
the new equilibrium for income and interest rate will be as follows.IS equation:Y = (1/0.5) * (100 + I (r) + G - 0.5T)LM equation:r = (1/10) (M/P) - (1/10) Y + (5/10)And, G and T = 100New Equilibrium:Y = 1080, r = 4.
In conclusion, the IS-LM model is an economic model that demonstrates how the goods market and monetary sector interact to determine the level of interest rates and national income. By determining the equilibrium in the market for goods (IS) and the money market (LM), the model helps to explain how changes in government expenditure can impact the equilibrium for income and interest rates. The crowding-out effect is a phenomenon where an increase in government expenditure leads to an increase in interest rates, resulting in a reduction in private investment.
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Carol purchased one basket of fruit consisting of 4 apples and 2 oranges and another basket of fruit consisting of 3 apples and 5 oranges. Carol is to select one piece of fruit at random from each of the two baskets. What is the probability that one of the two pieces of fruit selected will be an apple and the other will be an orange
Answer:13/24
Step-by-step explanation 1. the desired probability is the sum of the probabilities of two disjoint events. In the first event, an apple is selected from the first basket and an orange is selected from the second basket; the probability of this event is (4/6)(5/8)=20/48. 2. In the second event, an orange is selected from the first basket and an apple is selected from the second basket; the probability of this event is (2/6)(3/8)=6/48. Therefore, the desired probability is 20/48+6/48=26/48=13/24.
john and jane go rock-climbing together. john climbs a height of $(x 5)$ miles in $(x-1)$ hours and jane climbs a height of $(x 11)$ miles in $(x 1)$ hours. if john and jane were climbing at the same speed, what must have been their speed, in miles per hour?
Given that John climbs a height of \($(x + 5)$\) miles in \($(x - 1)$\) hours and Jane climbs a height of \($(x + 11)$\) miles in \($(x + 1)$\) hours. We know that the distance covered by both John and Jane are equal.
Distance covered by John = Distance covered by Jane
Therefore, \($(x + 5) = (x + 11)$\)
Thus, x = 6
Now, we need to find the speed of both, which is given by the formulae:
Speed = Distance / Time
So, speed of John = \($(x + 5) / (x - 1)$\) Speed of John =\($11 / 5$\) mph
Similarly, speed of Jane = \($(x + 11) / (x + 1)$\)
Speed of Jane = \($17 / 7$\) mph
Since both have to be equal, Speed of John = Speed of Jane Therefore,
\($(x + 5) / (x - 1) = (x + 11) / (x + 1)$\)
Solving this equation we get ,x = 2Speed of John = \($7 / 3$\) mph
Speed of Jane = \($7 / 3$\) mph
Thus, their speed was \($7 / 3$\) mph.
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you would use a ---select--- test to determine if sample data provide evidence that hypothesized proportions are not correct for a single categorical value from a single population.
You would use a Chi-square test to determine if sample data provide evidence that hypothesized proportions are not correct for a single categorical value from a single population.
You would use a hypothesis test to determine if sample data provide evidence that hypothesized proportions are not correct for a single categorical value from a single population. This type of hypothesis test is commonly used in statistics to evaluate the significance of differences between observed and expected frequencies.
The test involves selecting a sample from the population of interest, calculating the sample proportions, and comparing them to the hypothesized proportions using statistical methods. If the observed proportions are significantly different from the hypothesized proportions, then there is evidence to suggest that the hypothesized values are not correct.
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You would use a one-sample proportion test to determine if sample data provide evidence that hypothesized proportions are not correct for a single categorical value from a single population.
In this test, we compare the observed proportion (based on the sample data) to a hypothesized proportion (based on the null hypothesis) using a test statistic and a p-value. If the p-value is less than the chosen significance level (e.g., 0.05), we reject the null hypothesis and conclude that the observed proportion is significantly different from the hypothesized proportion.
This test is often used in quality control, market research, and public opinion polling to test whether a particular proportion (such as the proportion of defective products or the proportion of people who support a particular policy) is consistent with a hypothesized value.
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find the volume of the region bounded by z=2-sqrt(x^2 y^2) and z=sqrt(1 x^2 y^2)
D is the unit disk centered at the origin. To find the volume of the region bounded by the surfaces z = 2 - sqrt(x^2 + y^2) and z = sqrt(1 - x^2 - y^2),
we can set up a triple integral over the region in the xy-plane where these surfaces intersect.
Let's denote the region in the xy-plane as D. To determine the boundaries of D, we can set the expressions inside the square roots equal to each other:
2 - sqrt(x^2 + y^2) = sqrt(1 - x^2 - y^2)
Solving this equation, we find x^2 + y^2 = 1. Hence, D is the unit disk centered at the origin.
The volume can then be calculated by integrating the height difference between the two surfaces over D:
V = ∬D (sqrt(1 - x^2 - y^2) - (2 - sqrt(x^2 + y^2))) dA
Integrating in polar coordinates, the volume simplifies to:
V = ∫[0 to 2π] ∫[0 to 1] (sqrt(1 - r^2) - (2 - r)) r dr dθ
Evaluating this integral will give you the desired volume of the region bounded by the given surfaces.
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Maisie bought a house.
The value of the house decreased by 10% in 2016.
For three consecutive years, 2017, 2018 and 2019 the value of the house
increased.
Each year the percentage increase in value was the same each time.
The value of the house at the end of 2019 was 55.52% more than he paid for
the house.
Calculate the percentage increase in value of the house for each of the three
consecutive years.
The percentage increase in the value of the house each of the three years is 11.49%.
What is the percentage increase in the value of the house?The equation that can be used to represent the percentage change in the value of the house is:
(100x - 10%) + 3x% = 55.52%
90% + 3x = 55.52%
90% - 55.52% = 3x
34,48% = 3x
x = 34.48/3
x = 11.49%
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What are the 6 trigonometric functions calculator?
The 6 trigonometric functions are sine, cosine, tangent, cotangent, secant, and cosecant. These functions are all ratios of the sides of a right triangle, and they are all periodic, meaning that they repeat themselves over a fixed interval.
The 6 trigonometric functions are sine, cosine, tangent, cotangent, secant, and cosecant.Sine (sin): This is the ratio of the length of the side opposite an angle to the length of the hypotenuse in a right triangle. It is denoted by sin x and is equal to the y coordinate of a point on the unit circle. The formula for sine is y = sin x = opposite/hypotenuse. Cosine (cos): This is the ratio of the length of the adjacent side to the length of the hypotenuse in a right triangle. It is denoted by cos x and is equal to the x coordinate of a point on the unit circle. The formula for cosine is x = cos x = adjacent/hypotenuse.Tangent (tan): This is the ratio of the length of the opposite side to the length of the adjacent side in a right triangle. It is denoted by tan x and is equal to the slope of a line passing through the origin. The formula for tangent is y/x = tan x = opposite/adjacent.Cotangent (cot): This is the ratio of the length of the adjacent side to the length of the opposite side in a right triangle. It is denoted by cot x and is equal to the inverse of the slope of a line passing through the origin. The formula for cotangent is x/y = cot x = adjacent/opposite.Secant (sec): This is the ratio of the length of the hypotenuse to the length of the adjacent side in a right triangle. It is denoted by sec x and is equal to the reciprocal of the x coordinate of a point on the unit circle. The formula for secant is 1/x = sec x = hypotenuse/adjacent.Cosecant (csc): This is the ratio of the length of the hypotenuse to the length of the opposite side in a right triangle. It is denoted by csc x and is equal to the reciprocal of the y coordinate of a point on the unit circle. The formula for cosecant is 1/y = csc x = hypotenuse/opposite.
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use Laplace transforms to solve the following differential equation
y' + 3y = f(t), y(0) = α, α is a constant.
The solution to the differential equation y' + 3y = f(t), y(0) = α using Laplace transforms is y(t) = αe⁻³ᵗ + F(s)/(s+3), where F(s) is the Laplace transform of f(t).
We use the Laplace transform on both sides of the problem in order to solve the given differential equation. Let Y(s) and F(s) represent the Laplace transforms of y(t) and f(t), respectively. Taking the Laplace transform of both sides of the equation, we have:
sY(s) - y(0) + 3Y(s) = F(s)
Substituting y(0) = α, we get,
sY(s) - α + 3Y(s) = F(s)
Rearranging the equation and solving for Y(s), we have,
Y(s) = (F(s) + α)/(s + 3)
Now, we need to find the inverse Laplace transform of Y(s) to obtain y(t). Using the properties of Laplace transforms, we know that the inverse Laplace transform of Y(s) is y(t) = L⁻¹{Y(s)}. Applying the inverse Laplace transform, we find,
y(t) = αe⁻³ᵗ + L⁻¹{F(s)/(s+3)}
The term αe⁻³ᵗ corresponds to the initial condition y(0) = α. The remaining term L⁻¹{F(s)/(s+3)} represents the inverse Laplace transform of F(s)/(s+3), which depends on the specific function f(t) and its Laplace transform.
Therefore, the solution to the differential equation is y(t) = αe⁻³ᵗ + F(s)/(s+3), where F(s) is the Laplace transform of f(t).
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I don't know if im just putting it in wrong but ive tried numbers 1-20 positive and negative and it keeps telling me its wrong no matter what numbers im putting in please help this is 244 points of my grade
(a) If sup A < sup B, show that there exists an element b ∈ B that is an upper bound for A.
(b) Give an example to show that this is not always the case if we only assume sup A ≤ sup B.
(a) We have shown that there exists an element b ∈ B that is an upper bound for A.
(b) The statement in part (a) is not always the case if we only assume sup A ≤ sup B.
(a) If sup A < sup B, show that there exists an element b ∈ B that is an upper bound for A.
Proof:
1. By definition, sup A is the least upper bound for set A, and sup B is the least upper bound for set B.
2. Since sup A < sup B, there must be a value between sup A and sup B.
3. Let's call this value x, where sup A < x < sup B.
4. Now, since x < sup B and sup B is the least upper bound of set B, there must be an element b ∈ B such that b > x (otherwise, x would be the least upper bound for B, which contradicts the definition of sup B).
5. Since x > sup A and b > x, it follows that b > sup A.
6. As sup A is an upper bound for A, it implies that b is also an upper bound for A (b > sup A ≥ every element in A).
Thus, we have shown that there exists an element b ∈ B that is an upper bound for A.
(b) Give an example to show that this is not always the case if we only assume sup A ≤ sup B.
Example:
Let A = {1, 2, 3} and B = {3, 4, 5}.
Here, sup A = 3 and sup B = 5. We can see that sup A ≤ sup B, but there is no element b ∈ B that is an upper bound for A, as the smallest element in B (3) is equal to the largest element in A, but not greater than it.
This example shows that the statement in part (a) is not always the case if we only assume sup A ≤ sup B.
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Wally bought a television for $987. 0. The finance charge was $205 and she paid for it over 24 months.
Use the formula Approximate APR =(Finance Charge÷#Months)(12)Amount Financed
to calculate her approximate APR.
Round the answer to the nearest tenth.
10. 5%
10. 4% ← Correct answer
10. 2%
10. 1%
Approximate APR = (205 ÷ 24)(12)(987) = 0.1025 or 10.3%. Rounding to the nearest tenth, the answer is 10.4%.
To calculate Wally's approximate APR, we'll use the provided formula and given information:
Approximate APR = (Finance Charge ÷ #Months) * (12) ÷ Amount Financed
Plugging in the given values:
Approximate APR = ($205 ÷ 24) * (12) ÷ $987
Approximate APR = (8.5417) * (12) ÷ $987
Approximate APR = 102.5 ÷ $987
Approximate APR ≈ 0.1038
To express the result as a percentage and round to the nearest tenth, we'll multiply by 100:
Approximate APR ≈ 0.1038 * 100 = 10.38%
Rounded to the nearest tenth, Wally's approximate APR is 10.4%.
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Last week salazar played 13 more tennis games than perry. if they played a combined total of 53 games. How many games did salazar play?
If last week Salazar played 13 more tennis games than Perry and they played a combined total of 53 games, then Salazar played a total of 33 games.
Let the total number of games played by Perry be x.
It is given that, Salazar played 13 more tennis games than Perry.
⇒ Total games played by Salazar = x + 13
Also, Salazar and Perry played a combined of 53 games.
Hence, total number of tennis games played by Salazar and Perry = 53
⇒ Games played by Salazar + Games played by Perry = 53
⇒ x + (x + 13) = 53
2x + 13 = 53
2x = 53 - 13
2x = 40
x = 40 / 2
x = 20
Therefore, total number of games played by Salazar = x+13
= 20 + 13
= 33
Thus, Salazar played total 33 games.
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