what is 40 times 60 equalsssssss

Answer:

-15x+6

you multiply -3 and 5 so you get negitive 15 becuase a negative times positive is negative then you multiply -3 times -2 and you get positive 6 because negitive times negitive is a positive

Answer:

a)  5.9

b)  4.2

Step-by-step explanation:

Plot the data points on the number line (see attached).

Part (a)

\(\begin{aligned}\textsf{Distance between Ben and Kloee} & = \sf \left| Ben - Kloee \right|\\& = \sf \left|-2.65-3\frac{1}{4}\right|\\& = \sf \left|-2.65-3.25\right|\\& = \sf \left|-5.9\right|\\& = \sf 5.9\end{aligned}\)

Part (b)

\(\begin{aligned}\textsf{Distance between Middle school and Football field} & = \sf \left| Middle\:school-Football\:field\right|\\& = \sf \left| 1.5-5.7\right|\\& = \sf \left| -4.2 \right|\\& = \sf 4.2\end{aligned}\)

Answer:

Father=36 years old

Step-by-step explanation:

5 people 4 children and a father

average age=12

add the ages

3+5+6+10=24

24+12=36

check the work

36 +24=60

60/5=12

answer=36

Answer:

36 years old

Step-by-step explanation:

The average age of father and four children can be expressed in mathematics as:

\(\displaystyle \large{\dfrac{f+c_1+c_2+c_3+c_4}{5}}\)

The above expression is what you call average value or mostly known as mean - the mean value is sum of all data values divided by number of data values. The formula reference for mean/average value is:

\(\displaystyle \large{\dfrac{x_1+x_2+x_3+...+x_n}{n} = \dfrac{1}{n} \sum_{i=1}^n x_i}\)

Determine or let the following be:

It is also given in the question that children’s ages are 3, 5, 6 and 10. Hence:

\(\displaystyle \large{\dfrac{f+3+5+6+10}{5} = 12}\)

From above, it is also given that average of father’s age and children’s age is 12 years old - that now gives us an equation. What we have to do now is to solve for f.

First, multiply 5 both sides to get rid of denominator.

\(\displaystyle \large{\dfrac{f+3+5+6+10}{5} \cdot 5 = 12 \cdot 5}\\\\\displaystyle \large{f+3+5+6+10=60}\)

Evaluate 3+5+6+10 which equals 24.

\(\displaystyle \large{f+24=60}\)

Next, subtract both sides by 24 to isolate f-term.

\(\displaystyle \large{f+24-24=60-24}\\\\\displaystyle \large{f=36}\)

Finally, we have received the value of term which is f = 36. We know that the term represents father’s age and therefore, father’s age is 36 years old!

If you have any doubts, please let me know in the comment!

Answer:

Car 1

Step-by-step explanation:

Answer: Car 1

Step-by-step explanation:

Notice that the speed of each car is the slope of the line that represents its average speed.

Since the graph of the speed of Car 1 passes through (0,0) and (4,256), we get that its slope is:

256/4 = 64

Therefore the average speed of Car 1 is 64 mi/h.

 Now, since the equation that represents the average speed of Car 2 is in slope-intercept form, we get that its slope is 55.

Therefore the average speed of Car 2 is 55 mi/h.

Answer: Car 1.

If Idil drove 12 miles in 1/5an hour on average, then she drove at an average speed of 60 miles per hour.

To calculate the average speed of Idil's car in miles per hour, we need to divide the distance she drove (12 miles) by the time it took her to drive that distance (1/5 hour):

Average speed = distance ÷ time

Average speed = 12 miles ÷ (1/5) hour

To divide by a fraction, we can multiply by its reciprocal, so:

Average speed = 12 miles × 5/1 hour

Average speed = 60 miles per hour

Therefore, Idil drove at an average speed of 60 miles per hour.

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Answer:

it would be .1111111111

Hope this helps

Answer:

.1 repeating

Step-by-step explanation:

.1 repeating= .11111111111

Hope this helps.

Answer:

b

Step-by-step explanation:

Pattern A: 3, 10, 17, 24, 31

Pattern B: 3, 7, 11, 15, 19

Answer: $50,750

Step-by-step explanation: To get the percentage of a number, you need to turn the percent into a decimal, then multiply it with the number you need the percentage of. 35% translates into 0.35. Then you would multiply 145,000 by 0.35, getting 50,750 as your answer!

Answer:

Step-by-step explanation:

5x-4+7x-8=180

12x-12=180

12x=192

x = 16

5(16)-4= 80-4= 76 degrees

7(16)-8= 112-8= 104 degrees

9y  +  5 = 104

9y = 99

y = 11

9(11) + 5 = 99 + 5 = 104

Answer:

x= 95 duhhhhhhh lol jk but its 95

Step-by-step explanation:

Answer:

x = 95° by the Vertical Angles are congruent theorem

Hope this helps!

They provide a clear and concise way to demonstrate the validity of a claim, relying on known facts and logical reasoning

Candice's proof is a direct proof because it establishes the truth of a statement by providing a logical sequence of steps that directly lead to the conclusion. In a direct proof, each step is based on a previously established fact or an accepted axiom. The proof proceeds in a straightforward manner, without relying on any other alternative scenarios or indirect reasoning.

Candice's proof likely involves stating the given information or assumptions, followed by a series of logical deductions and equations. Each step is clearly explained and justified based on known facts or established mathematical principles. The proof does not rely on contradiction, contrapositive, or other indirect methods of reasoning.

On the other hand, Joe's proof is also a direct proof for similar reasons. It follows a logical sequence of steps based on known facts or established principles to arrive at the desired conclusion. Joe's proof may involve identifying the given information, applying relevant theorems or formulas, and providing clear explanations for each step.

Direct proofs are commonly used in mathematics to prove statements or theorems. They provide a clear and concise way to demonstrate the validity of a claim, relying on known facts and logical reasoning. By presenting a direct chain of deductions, these proofs build a solid argument that leads to the desired result, without the need for complex or indirect reasoning.

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The standard form of this equation will be 3z^4 + 2z^3 - z^2 + 5z.

The equations formed with variables, exponents, and coefficients are called as polynomial equations. It can have different exponents, where the higher one is called the degree of the equation. We can solve polynomials by factoring them in terms of degree and variables present in the equation.

here, we have,

we know,

What is not a polynomial:

Polynomials cannot contain fractional exponents. Terms containing fractional exponents (such as 3x+2y1/2-1) are not considered polynomials. Polynomials cannot contain radicals. For example, 2y2 +√3x + 4 is not a polynomial.

now, we have,

given that, 5z + 2z^3 - z^2 + 3z^4

so, The standard form of this equation will be 3z^4 + 2z^3 - z^2 + 5z.

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Answer:

8th: 23

11th: 32

15th: 44

22nd: 65

18th: 53

Step-by-step explanation:

The pattern is adding 3 each time:

2, 5, 8, 11, 14, 17, 20, 23, 26, 29, 32, 35, 38, 41, 44, 47, 50, 53, 56, 59, 62, 65

Hope it helps!

Grouping symbols exponents multiply and divide add and subtract represent the order of mathematical operations/calculations.

In mathematics, grouping symbols, exponents, multiplication and division, and addition and subtraction are the order of operations used to simplify mathematical expressions. The order of operations is a set of rules that dictate the order in which different operations are performed when evaluating an expression. The acronym PEMDAS is often used to help remember the order of operations:

P - Parentheses: Expressions inside parentheses should be evaluated first

E - Exponents: Exponents (such as "2^3" or "5^2") should be evaluated next

MD - Multiplication and Division: Multiplication and division should be done next, working from left to right

AS - Addition and Subtraction: Finally, addition and subtraction should be done, working from left to right.

It is important to follow the order of operations to ensure that mathematical expressions are evaluated correctly.

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(b) By solving the dual problem graphically, we find that the optimal solution occurs at the vertex (0, 2) with a minimum value of W = 10. The shadow price for resource 1 (x1 + x3 ≤ 3) in the primal problem is 10. This means that an additional unit of resource 1 would increase the objective function value by 10. The shadow price for resource 2 (x2 + 2x3 ≤ 5) in the primal problem is 0. This indicates that the optimal solution is not sensitive to changes in resource 2.

(a) To construct the dual problem, we will assign dual variables y1 and y2 to the constraints of the primal problem and convert the objective function to the dual form. The dual problem has two constraints corresponding to the resources in the primal problem. The objective function in the dual problem represents the costs or prices associated with the resources.

(b) To solve the dual problem graphically, we will plot the feasible region and find the optimal solution.

Constraint 1: y1 + y2 ≥ 2

Rearranging the inequality, we get:

y2 ≥ 2 - y1

Constraint 2: y1 + 2y2 ≥ 6

Rearranging the inequality, we get:

y2 ≥ (6 - y1) / 2

The feasible region is the intersection of the two constraint inequalities, taking into account the non-negativity constraints y1 ≥ 0 and y2 ≥ 0.

Now, let's plot the feasible region on a graph:

Starting with the y-axis, plot points (0, 2) and (0, 3) to represent the non-negativity constraint y2 ≥ 0.

Next, draw a line with a slope of -1 passing through the point (0, 2).

Draw another line with a slope of -0.5 passing through the point (0, 3).

The feasible region is the area bounded by these two lines and the y-axis.

To find the optimal solution, we need to evaluate the objective function at the vertices of the feasible region.

Vertices of the feasible region:

(0, 2)

(0, 3)

Now, substitute these vertices into the objective function:

For (0, 2):

W = 3(0) + 5(2) = 10

For (0, 3):

W = 3(0) + 5(3) = 15

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Answer:

(x+4)(3x-2)(x+1)

Step-by-step explanation:

Answer:

The question is not showing what we are supposed to find.

b+3b+10

The number of fiction books in the library is equal to 16

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given the ratio of fiction to nonfiction books in a classroom, the library is 2 to 3, and then the total ratio of both books will be 2+3 = 5. If there are 24 books non-fiction books in the library, to get the number of fiction books that are there we will follow the following steps.

First, we will calculate the total number of books in the shelf;

3/5  x Total number of books = total non fiction books

3/5 * Total number of books = 24

3*Total number of books = 5*24

3*Total number of books = 120

Total number of books = 120/3

Total number of books = 40

Therefore there are 40 total books on the shelf.

Total number of fiction books = 2/5 * 40

Total number of fiction books = 2* 8

Total number of fiction books = 16 books

Hence there are 16 fiction books on the shelf.

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9514 1404 393

Answer:

  D.) a+2b

Step-by-step explanation:

The integers 'a' and 'b' can be any, so you can choose a couple and evaluate these expressions to see what you get. For example, we can let a=1 and b=0. For these values, the offered expressions evaluate to ...

  A) 3(0) = 0 . . . even

  B) 1 +3 = 4 . . . even

  C) 2(1+0) = 2 . . . even

  D) 1 +2(0) = 1 . . . odd

_____

Additional comment

These rules apply to even/odd:

Then A is (odd)(even) = even; B is (odd)+(odd) = even; C is (even)(whatever) = even; D = (odd)+(even) = odd.

Answer:

170$

Step-by-step explanation:

There is nothing inherently wrong with any of the statements in question 21. Sampling rate and sound frequency both use hertz (Hz) as their unit of measurement.

The sample rate is a setting that can be adjusted during the digitization process, as is the sound frequency. It is also true that a higher sampling rate does not necessarily result in a higher pitch.

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The 90% confidence interval is: (2.51, 3.22)

It is a boundary of values which is eventually to comprise a population value with a certain degree of confidence. It is usually shown as a percentage whereby a population means lies within the upper and lower limit of the provided confidence interval.

We have the following information :

The level of significance is calculated as:

\(\alpha =1-c\\\\\alpha =1-0.90\\\\\alpha =0.10\)

The degrees of freedom for the case is:

df = n - 1

df = 15 - 1

df = 14

The 90% confidence interval is calculated as:

=x(bar) ±\(t_\frac{\alpha }{2}\), df \(\frac{s}{\sqrt{n} }\)

= 2.86 ±\(t_\frac{0.10 }{2}\), 14 \(\frac{0.78}{\sqrt{15} }\)

= 2.86 ± 1.761 × \(\frac{0.78}{\sqrt{15} }\)

= 2.86 ± 0.3547

= (2.51, 3.22)

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Answer:

Yes, 0.3 is the multiplicative inverse of 3 1/3 since 0.3 * 3/13 = 1.

Step-by-step explanation:

Multiplicative inverses, also called reciprocals, are two numbers whose product is 1.

What number multiplied by 3 1/3 equals 1?

3 1/3 * x = 1

10/3 x = 1

3/10 * 10/3 x = 1 * 3/10

x = 3/10 = 0.3

Answer: Yes, 0.3 is the multiplicative inverse of 3 1/3 since 0.3 * 3/13 = 1.

Answer:

a=8

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

7 * 8 = 56

56 + 5 = 61

The number of llamas in the petting zoo has 13, and the number of kangaroos is 34.

Let the number of llamas in the petting zoo be x, and the number of kangaroos in the petting zoo be y.

Thus, we can write two equations from the given conditions:

Equation 1: x + y = 47

Equation 2: 4x + 2y = 120

(since each llama has 4 legs and each kangaroo has 2 legs)

Simplifying equation 2:2x + y = 60

Now we have two equations with two unknowns.

To solve them, we can either use substitution or elimination.

Using substitution, we can solve equation 1 for y in terms of x:y = 47 - x

Now we substitute this expression for y in equation 2:2x + (47 - x) = 60

Simplifying: x + 47 = 60x = 13

Now we can use either equation 1 or 2 to find y:x + y = 47y = 47 - xy = 47 - 13y = 34

Therefore, the petting zoo has 13 llamas and 34 kangaroos.

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The measure of <YZX is 55.2 degree.

The area of mathematics that deals with particular angles' functions and how to use those functions in calculations. There are six popular trigonometric functions for an angle. Sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant are their respective names and acronyms (csc).

Given:

XY= 12.4 cm, YZ= 15.1 cm

In right ΔXYZ with hypotenuse XZ and opposite side XY to ∠YZX then

Using the sine ratio

sin <YZX= 12.4/ 15.1

sin <YZX = 0.8211

<YZX= 55.2

Hence, the measure of <YZX is 55.2 degree

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Answer: 55.2

Step-by-step explanation: just took it

Answer:

You need to put the fractions for us to answer but fractions that are greater than 1/2 include: 3/4 and  4/7  and  basically any fraction that has a value greater than 0.5

Step-by-step explanation:

Answer:

The temperature was;

6 °C

Step-by-step explanation:

Here, we want to know the temperature at 5 pm

For the first 6 hours, we have an increase of 3/4 degree per hour

so the temperature increase in the first 6 hours will be;

6 * 3/4 = 4.5 degrees

Then we had an increase of 1 1/2 degrees per hour for 5 hours

The increase after these 5 hours will be;

3/2 * 5 = 15/2 = 7.5 degrees

Total increase is 7.5 + 4.5 = 11 degrees

We subtract the initial -5 from here

So the present temperature will be;

-5 degree + 11 degree = 6 degrees celsius

The evaluations of the given functions at the indicated values are as follows.1. \(\(k(3-y)=-6y^3+9y^2+54y+81\)2. \(k(3+y)=6y^3+9y^2+54y+81\)3. \(k(-5+x)=-2x^3+15x^2-30x-25\)4. \(k(-3-y)=-6y^3-27y^2-54y-27\)\)

Given function is \(k(x)=2 x^{3}-3 x^{2}\) We have to evaluate the functions at the given values.

1. \(k(3-y)\)We need to replace x with \(3-y\).\(k(3-y)=2(3-y)^3 - 3(3-y)^2\)

Now let's expand the above equation,

\(\(k(3-y)=2(27-27y+9y^2-y^3)-3(9-18y+9y^2)\)\)

On further simplification, we get\(k(3-y)=-6y^3+9y^2+54y+81\)

2. \(k(3+y)\)We need to replace x with \(3+y\).\(k(3+y)=2(3+y)^3 - 3(3+y)^2\)

Now let's expand the above equation,

\(\(k(3+y)=2(27+27y+9y^2+y^3)-3(9+18y+9y^2)\)\)

On further simplification, we get\(\(k(3+y)=6y^3+9y^2+54y+81\)3. \(k(-5+x)\)We need to replace x with \(-5+x\).\(k(-5+x)=2 (-5+x)^3-3(-5+x)^2\)\)

Now let's expand the above equation,\(\(k(-5+x)=2(-125+75x-15x^2+x^3)-3(25-10x+x^2)\)\)

On further simplification, we get\(\(k(-5+x)=-2x^3+15x^2-30x-25\)4. \(k(-3-y)\)We need to replace x with \(-3-y\).\(k(-3-y)=2 (-3-y)^3 - 3(-3-y)^2\)\)

Now let's expand the above equation,\(\(k(-3-y)=2(-27-27y-9y^2-y^3)-3(9+6y+y^2)\)\)

On further simplification, we get\(k(-3-y)=-6y^3-27y^2-54y-27\)

Therefore, the evaluations of the given functions at the indicated values are as follows.\(1. \(k(3-y)=-6y^3+9y^2+54y+81\)2. \(k(3+y)=6y^3+9y^2+54y+81\)3. \(k(-5+x)=-2x^3+15x^2-30x-25\)4. \(k(-3-y)=-6y^3-27y^2-54y-27\)\)

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