what is 260 add 212 multiplied by 234 minus 1000

Answer: 26.457 cm

Explanation:

First, the height of an equilateral triangle of side length a is:

\(h = \frac{\sqrt{3} }{2}*a\)

In this case, the side-length of the triangles is a = 10cm, then the height will be:

\(h = \frac{\sqrt{3} }{2}*10cm = 8.66cm\)

Now we can think on a triangle rectangle such that:

Point A and point F are vertexes of the triangle.

The line we want to find, the line from A to F, is the hypotenuse.

One cathetus is a the height of the triangle, that comes down from point A, the length of this cathetus is 8.66cm

The other cathetus is equal to half the side length of the triangles (5cm) plus the segments BD and DF (of 10cm each)

Then the length of this cathetus is 10cm + 10cm + 5cm = 25cm

Now, we can remember the Pythagorean theorem.

If H is the hypotenuse, and A and B are the catheti, then we have:

A^2 + B^2 = H^2

In this case, we know the length of both cathetus, and want to know the length of the hypotenuse, then:

(25cm)^2 + (8.66cm)^2 = H^2

√( (25cm)^2 + (8.66cm)^2) = H = 26.457 cm

Then the line from A to F is 26.457 cm

Answer:

I think it's -0.4 but tell me if I'm wrong

Answer:

x=30

Step-by-step explanation:

x/5-16=-10

x/5=-10+16

x/5=6

x=6×5

x=30

 The sample we collect plays a cruciThe sample we collect can significantly affect our understanding of a population,

especially when it comes to making generalizations or drawing conclusions about the entire population based on the sample data. The key aspect in this regard is whether the sample is representative of the population.

A representative sample is one that accurately reflects the characteristics, diversity, and distribution of the population from which it is drawn. When our sample is representative, we can have greater confidence in generalizing the findings from the sample to the larger population. However, if our sample is not representative, our understanding of the population may be biased or limited.

In the provided example, the given data represents different age groups and their reported time spent with friends per day. If we were to collect a sample from this population, it would be crucial to ensure that the sample includes individuals from each age group in proportion to their representation in the population. This would help ensure that our sample accurately reflects the age distribution of the population.

If our sample is not representative, it may lead to inaccurate conclusions. For instance, if we only surveyed individuals from the age group 55-64 and ignored the other age groups, our understanding of the population's time spent with friends would be limited to that specific age group. We wouldn't be able to generalize our findings to the entire population because we would have missed important variations in behavior across other age groups.

To improve the representativeness of our sample, we could use random sampling techniques, such as simple random sampling or stratified sampling, to ensure that individuals from all age groups are included in the sample. By doing so, we can enhance our understanding of the population as a whole and make more accurate inferences.

In conclusion, the sample we collect plays a crucial role in shaping our understanding of a population. A representative sample enables us to make valid generalizations and draw reliable conclusions about the entire population. It ensures that the characteristics and diversity of the population are properly reflected in the sample, allowing for more accurate insights and informed decision-making.al role in shaping our understanding of a population

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48397*15%*5= 36297.75

answer = 36397.75

Shor's Algorithm Efficiency of Shor’s algorithm in the general case, when r does not divide 2, is calculated as follows:

Shor's algorithm is an effective quantum computing algorithm for factoring large integers. The algorithm calculates the prime factors of a large number, using the modular exponentiation, and quantum Fourier transform in a quantum computer.In this algorithm, the calculation of the quantum Fourier transform takes O(N2) quantum gates, where N is the number of qubits required to represent the number whose factors are being determined.

To calculate the Fourier transform efficiently, the number of qubits should be set to log2 r. The general form of Shor's algorithm is given by the following pseudocode:

1. Choose a number at random from 1 to N-1.

2. Find the greatest common divisor (GCD) of a and N. If GCD is not 1, then it is a nontrivial factor of N.

3. Use quantum Fourier transform to determine the period r of f(x) = a^x mod N. If r is odd, repeat step 2 with a different value of a.

4. If r is even and a^(r/2) mod N is not -1, then the factors of N are given by GCD(a^(r/2) + 1, N) and GCD(a^(r/2) - 1, N).

The efficiency of the algorithm is determined by the number of gates needed to execute it. Shor's algorithm has an exponential speedup over classical factoring algorithms, but the number of qubits required to represent the number whose factors are being determined is also exponentially large in the number of digits in the number.

In the general case when r does not divide 2, the efficiency of Shor's algorithm is reduced. However, the overall performance of the algorithm is still better than classical factoring algorithms.

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Based on the number of years in a century, we can calculate that the 4 centuries before 1965 was 1565.

A century refers to a period of 100 years.

If we are looking for a period of 4 centuries therefore, this would be:

= 4 x 100

= 400 years

4 centuries before 1965 would therefore be:

= 1965 - 400

= 1565

In conclusion, the answer is 1565.

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The equation defines function f is f(x) = - 1/4 x + 2.

To find the equation of function f, we need to eliminate the constant term of 14 in the equation y = f(x) + 14.

One way to do this is to subtract 14 from both sides of the equation:

y - 14 = f(x)

Now we can compare this with the given options for f(x):

A. f(x) = - 1/4 * x - 12

B. f(x) = - 1/4 * x + 16

C. f(x) = - 1/4 * x + 2

D. f(x) = - 1/4 * x - 14

We see that option C matches our equation: y - 14 = f(x) = - 1/4 x + 2. Therefore, the answer is:

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Answer:

What's the question?

Step-by-step explanation:

Using the remainder theorem, the value of k in f(x) = 3x^2 + kx - 7 is 10

The given parameters are:

f(x) = 3x^2 + kx - 7

Divisor = x - 4

Remainder = 81

To solve for k, we use the remainder theorem

Set the divisor to 0

x -4 = 0

Add 4 to both sides of the above equation

x - 4 + 4 = 0 + 4

This gives

x = 4

Substitute x = 4 in the function f(x) = 3x^2 + kx - 7

f(4) = 3(4)^2 + k * 4 - 7

Evaluate the exponents

f(4) = 3 * 16 + k * 4 - 7

Evaluate the products

f(4) = 48 + 4k - 7

So, we have:

f(4) = 41 + 4k

The remainder is 81.

So, we have

41 + 4k = 81

Subtract 41 from both sides

4k = 40

Divide both sides of the above equation by 4

4k/4 = 40/4

Evaluate the division

k = 10

Hence, the value of k in f(x) = 3x^2 + kx - 7 is 10 using the remainder theorem

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The expected probability that the next flip is a head given the results of the previous 25 coin flips is 0.6 or 60%.

The expected probability of a head coming up next given the results of the 25 coin flips is 15/25 = 0.6.

This is due to the fact that 15 of the 25 flips were heads, so the probability of the next head is 15 out of the 25 total flips which is equal to 0.6 or 60%.

However, since the probability of heads (m) is unknown, the expected probability of a head coming up next is still unknown.

Therefore, the expected probability that the next flip is a head given the results of the previous 25 coin flips is 0.6 or 60%.

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Let the weight (in kg) of a large box be 'x' and the weight of a small box be 'y'.

Given that the weight of 2 large boxes and 3 small boxes is 78 kg,

Also given that the weight of 6 large boxes and 5 small boxes is 180 kg,

Here we will apply the Elimination Method to solve both the equations.

Consider the three times the first equation being subtracted from the second equation,

Simplify the terms,

Substitute this value in the first equation,

Thus, the larger box weighs 18.75 kg while the small box weighs 13.5 kg

Answer:

170 Degrees.

Step-by-step explanation:

If an interior angle is 170 degrees, that's your best bet.

Let's denote the cost of a Douglas Fir tree as 'D' and the cost of a Noble Fir tree as 'N'. We can create a system of equations to represent the given information: 5 Douglas Fir trees and 4 Noble Fir trees, earning a total of $493 and 24 Douglas Fir trees and 17 Noble Fir trees, earning a total of $2,219.

In the morning, the troop sold 5 Douglas Fir trees and 4 Noble Fir trees, earning a total of $493. This can be represented by the equation:

5D + 4N = 493

In the afternoon, the troop sold 24 Douglas Fir trees and 17 Noble Fir trees, earning a total of $2,219. This can be represented by the equation:

24D + 17N = 2219

To solve this system of equations, we can use various methods such as substitution, elimination, or matrices. By solving the system, we can find the values of 'D' and 'N', which represent the cost of a Douglas Fir tree and a Noble Fir tree, respectively.

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To find the population at any given term n, continue to apply the recursive rule.
Pₙ = Pₙ₋₁ + 50
Using this recursive rule and the initial population, you can find the population at any given term n.

We are given a population growth model with a recursive rule and an initial population. Let's break down the information and find the population at any given term n.

Recursive rule: Pₙ = Pₙ₋₁ + 50
Initial population: P₀ = 30

Now let's find the population at any term n, using the recursive rule:

Step 1: Determine the base case, which is the initial population.
P₀ = 30

Step 2: Apply the recursive rule to find the next few terms.
P₁ = P₀ + 50 = 30 + 50 = 80
P₂ = P₁ + 50 = 80 + 50 = 130
P₃ = P₂ + 50 = 130 + 50 = 180

Step 3: To find the population at any given term n, continue to apply the recursive rule.
Pₙ = Pₙ₋₁ + 50

Using this recursive rule and the initial population, you can find the population at any given term n.

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Answer:

v8 x v18 = v²144

Step-by-step explanation:

v x v = v²

18 × 8 = 144

so the answer is v²144

Answer:

V8 x V18

=V144

HOPE IT HELPED U,

MARK AS THE BRAINLIEST

^_^

Let:

The slope m is given by:

Using the point-slope equation:

since the area is above the line, and the line is continuous:

Step-by-step explanation:

(i) Using the law of cosines, we can find that

\(cos(O) = \frac{8^{2}+8^{2} - 7^{2}}{8*8*2}\) ≈ 0.62, so O ≈ 0.9

(ii) Since the whole pie has 2π radians (or 360 degrees), we can divide 0.9 by 2π to get around 6.9 slices from the pie

(iii) The area of the shaded segment can be found by finding sector OAB and subtracting triangle OAB from that. Sector OAB can be found by finding the area of the pie (π*8², since 8 is the radius) and dividing that by 6.9, so we get 64π/6.9 ≈ 29. Then, the area of the triangle is √p(p-a)(p-b)(p-c), with p being the perimeter and a, b, and c being the sides. Plugging 7, 8, and 8 in, we get 25.1781 as our area, so the difference is around 3.8

The number of busy beavers is found as 33.

The given ratio:

busy beavers/ chatty chipmunks = 11/ 12

For, 48 chatty chipmunks

busy beavers/ 48 = 11/ 12

busy beavers/ 48 = 11/ 12

busy beavers = 11*3

busy beavers = 33

Thus, the number of busy beavers is found as 33.

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The data includes a concave mirror with a radius of curvature of +31.5 cm and magnification of m = 3.40. The formula for magnification is m = v/u, and the focal length is f = r/2. Substituting the values, we get u = v/m, and using the mirror formula, the distance of the object from the mirror is 10.15 cm.

Given data: Radius of curvature of a concave mirror, r = +31.5 cm Magnification produced by the mirror, m = 3.40

We know that the formula for magnification is given by:

m = v/u where, v = the distance of the image from the mirror u = the distance of the object from the mirror We also know that the formula for the focal length of the mirror is given by :

f = r/2where,f = focal length of the mirror

Using the mirror formula:1/f = 1/v - 1/u

We know that a concave mirror has a positive focal length, so we can replace f with r/2.

We can now simplify the equation to get:1/(r/2) = 1/v - 1/u2/r = 1/v - 1/u

Also, from the given data, we have :m = v/u

Substituting the value of v/u in terms of m, we get: u/v = 1/m

So, u = v/m Substituting the value of u in terms of v/m in the previous equation, we get:2/r = 1/v - m/v Substituting the given values of r and m in the above equation, we get:2/31.5 = 1/v - 3.4/v Solving for v, we get: v = 22.6 cm Now that we know the distance of the image from the mirror, we can use the mirror formula to find the distance of the object from the mirror.1/f = 1/v - 1/u

Substituting the given values of r and v, we get:1/(31.5/2) = 1/22.6 - 1/u Solving for u, we get :u = 10.15 cm

Therefore, the distance of the mirror from the face is 10.15 cm. The units are centimeters (cm).Answer: 10.15 cm.

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Answer:

12/5 and 6/25

Step-by-step explanation:

9/10+9/100=.99

12/5+6/25=2.64

2.64>.99

Answer:

C

Step-by-step explanation:

Everything else can be simplified to 2/5, except for 9/20

Answer:

9/20 is not equivalent to the others

Step-by-step explanation:

9 is not divisible by 2

Hi there! Let me know if you have questions about my answer:

One shrub is $11.

One daylily is $4.

Step-by-step explanation:

To find the cost of each item, write a system of equations, one equation for what each person bought, and solve for each variable.

Define your variables.

let 'd' be the cost of one daylily

let 'r' be the cost of one shrub

Create a system using the variables and information from the question.

Write an equation for what Arjun bought:

5d + 7r = 97            5 daylilies, 7 shrubs, totaling $97

Write an equation for what Jessica bought:

2d + 11r = 129          2 daylilies, 11 shrubs, totaling $129

Solve the system.

I will solve the system algebraically, using the substitution method. Isolate one variable in one of the equations.

I will isolate 'd' in Jessica's equation:

\(2d + 11r = 129\)              Start with Jessica's equation

\(\frac{2d + 11r}{2} = \frac{129}{2}\)                  Divide everything in the equation by 2

\(d + \frac{11r}{2} = \frac{129}{2}\)                 Simplify

\(d = \frac{129}{2} - \frac{11r}{2}\)                 Isolate 'd' by subtracting \(\frac{11r}{2}\) from both sides.

Now you have an expression for 'd'.

Substitute Arjun's equation with the expression for 'd'. Solve for 'r' to find the cost of one shrub.

\(5d + 7r = 97\)                      Start with Arjun's equation

\(5(\frac{129}{2} - \frac{11r}{2}) + 7r = 97\)       Substitute 'd' for  \(d = \frac{129}{2} - \frac{11r}{2}\)

\(\frac{5*129}{2} - \frac{5*11r}{2} + 7r = 97\)      Distribute the 5

\(\frac{645}{2} - \frac{55r}{2} + 7r = 97\)            Simplify the numerators

\(\frac{645}{2} - \frac{55r}{2} + \frac{14r}{2} = 97\)          Change 7r to a fraction over 2

\(\frac{645}{2} - \frac{41r}{2} = 97\)                    Combine like terms, the terms with 'r'

\(\frac{645-41r}{2} = 97\)                       Simplify

\(645-41r = 194\)                 Multiply both sides by 2

\(-41r = 194-645\)              Subtract 645 from both sides

\(-41r = -451\)                     Divide both sides by –41

\(r = 11\)                                Solved for cost of one shrub

Substitute 'r' for 11 using either Arjun's or Jessica's equation. Then, isolate 'd' to solve for the cost of one daylily.

I will use Arjun's equation.

\(5d + 7r = 97\)                   Start with Arjun's equation

\(5d + 7(11) = 97\)              Substitute 'r' for r = 11

\(5d + 77 = 97\)                   Simplify. Subtract 77 from both sides.

\(5d = 20\)                           Divide both sides by 5.

\(d = 4\)                              Solved for the cost of one daylily

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Answer:

104

Step-by-step explanation:

There are two ways to do it, though we need to know how it is affected.

20+6=26

26+6=32

32+6=38

38+6=44

Thus, you are adding 6 for each term.

1. You do it manually...(yes.)

I'll number it one by one

1.20

2.26

3.32

4.38

5.44

6.50

7.56

8.62

9.68

10.74

11.80

12.86

13.92

14.98

15.104

The 15th term is 104.

2. This method is easier. As shown above, there is a pattern. We can apply it using this formula:
20+6(n-1)

You can get this formula from the facts that:
-you start off with an additional added 8

-you add 6 every time

-if we do it 6n then it would be incorrect, with an extra 6 for each

-the formula is correct; you can test it for terms 2,3,4,5 like this:

20+6=26

20+2x6=32

20+3x6=38

20+4x6=44

To find the 15th term, you can:

20+14x6=20+84=104.

The equation for the lower half of the parabola (y + 1)^2 = x + 4 can be represented as y = -sqrt(x + 4) - 1. Therefore, the equation for the lower half of the parabola is y = -sqrt(x + 4) - 1.

The given equation (y + 1)^2 = x + 4 represents a parabola. To find the equation for the lower half of the parabola, we need to solve for y.

Taking the square root of both sides of the equation, we have:

y + 1 = -sqrt(x + 4)

Subtracting 1 from both sides, we get:

y = -sqrt(x + 4) - 1

This equation represents the lower half of the parabola. The negative sign in front of the square root ensures that the y-values are negative or zero, representing the lower half. The term -1 shifts the parabola downward by one unit.

Therefore, the equation for the lower half of the parabola is y = -sqrt(x + 4) - 1.

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The probability that an individual would wait longer than 4 minutes to be served is approximately 0.08.

To find the probability that an individual would wait longer than 4 minutes to be served, we can use the exponential distribution formula

The exponential distribution is defined by the formula:

f(x) = λ * exp(-λx)

Where λ is the rate parameter (the reciprocal of the expected value).

In this case, the expected wait time is 10 minutes, so the rate parameter λ is equal to 1/10 = 0.1.

To find the probability that an individual would wait longer than 4 minutes (P(X > 4)), we integrate the exponential distribution function from 4 to infinity:

P(X > 4) = ∫[4,∞] λ * exp(-λx) dx

P(X > 4) = ∫[4,∞] 0.1 * exp(-0.1x) dx

To evaluate this integral, we can use the property that ∫a * exp(bx) dx = (1/b) * exp(bx) + C, where C is the constant of integration.

P(X > 4) = [-0.1 * exp(-0.1x)] evaluated from 4 to ∞

P(X > 4) = [-0.1 * exp(-0.1x)] from 4 to ∞

Since exp(-0.1x) approaches 0 as x approaches infinity, we have:

P(X > 4) ≈ [-0.1 * exp(-0.1x)] from 4 to ∞

P(X > 4) ≈ [-0.1 * 0] - [-0.1 * exp(-0.1 * 4)]

P(X > 4) ≈ 0 + 0.1 * exp(-0.1 * 4)

P(X > 4) ≈ 0.1 * exp(-0.4)

Using a calculator, we can calculate the approximate value:

P(X > 4) ≈ 0.1 * 0.08≈ 0.08

Therefore, the probability that an individual would wait longer than 4 minutes to be served is approximately 0.08.

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The interquartile range is 55.

The interquartile range is the difference between the upper quartile and the lower quartile. In example 1, the IQR = Q3 – Q1 = 87 - 52 = 35. The IQR is a very useful measurement. It is useful because it is less influenced by extreme values as it limits the range to the middle 50% of the values.

Interquartile range = higher quartile - lower quartile

Given data,    50,25,80,10

To arrange the given data in ascending order 10,25,50,80.

Now, we will find the median for the given data.

The median is obtained by first arranging the data in ascending order and applying the following rule.

If the number of observations is even, then the median is \(\frac{n}{2}th\) term.

In given data the number of observations is '4'(even)

If the number of observations is even, then the median is \(\frac{4}{2} th\) means 2nd term. So median for the given data is 25. It means the value of lower quartile is 25 .

Interquartile range = higher quartile - lower quartile

                                 = 80-25

                                = 55  

Thus, interquartile range  for the given data is 55.

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The above question is not complete.

Answer:

3084 sq. ft

Step-by-step explanation:

for the first three rooms,

area= 6l² = 6× 17² = 1734

for the next two rooms,

area= 6l² = 6×15² = 1350

total area = 3084