what happened to charton heston in the first planet of theapes movie was be caught in time warp caused by a big nuclear explosion

The answers are- (a) 2 soft drinks. (b) Uncertain. (c) Not necessarily.

(d) No bliss point. and, (e) Steeper indifference curves.

(a) If Elmo has 4 quarters and 2 dimes in his pockets, he can buy 2 soft drinks. Since each soft drink requires two quarters and a dime, having double the amount of each coin allows him to make two purchases.

(b) Elmo's preferences between dimes and quarters may or may not be convex. Convex preferences imply that as Elmo increases the quantity of one type of money (quarters or dimes), the marginal utility he derives from each additional unit of that money diminishes. If Elmo's preference for soft drinks is based solely on the ability to purchase them and not on any diminishing marginal utility of the coins themselves, then his preferences may not exhibit convexity.

(c) Elmo does not necessarily always prefer more of both kinds of money to less. Given the specific context of the Coke machine, Elmo's only concern is to have the exact change required to obtain a soft drink. As long as he has the necessary combination of two quarters and a dime, having additional coins does not increase his utility further.

(d) Elmo does not have a bliss point in this scenario. A bliss point refers to the combination of goods or factors that maximizes an individual's utility or satisfaction. Since Elmo's sole objective is to purchase soft drinks from the Coke machine, his utility is maximized when he has the exact change required (two quarters and a dime). Having more coins does not enhance his utility beyond being able to buy a single soft drink.

(e) If Elmo had arrived at the Coke machine on a Saturday, with the drugstore across the street open, his preferences would change. Instead of being limited to the specific combination of two quarters and a dime, he could now use any combination of quarters and dimes to purchase as much Coke as he wants at a price of 4 cents per ounce.

In this case, Elmo's indifference curves between quarters and dimes would exhibit a downward slope, indicating that he is willing to trade off some quantity of one coin for a corresponding increase in the other, while still maintaining the same level of utility. The indifference curves would be steeper than the ones in the previous scenario, as Elmo can now acquire more soft drinks by having a larger combination of quarters and dimes.

These new indifference curves reflect Elmo's preference for more quarters and dimes, as they enable him to buy more Coke at the drugstore. The curves demonstrate that Elmo is willing to sacrifice some quantity of quarters to obtain additional dimes or vice versa, as long as the overall combination allows him to maximize the quantity of Coke he can purchase.

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a) The amplitude of a Compound Motor Action Potential (CMAP) changes when stimulus intensity is increased because higher stimulus intensity leads to the recruitment of more motor units.

Motor units are the functional units of muscle contraction, consisting of a motor neuron and the muscle fibers it innervates. When a stimulus is applied to a muscle, initially only a small number of motor units are activated. As the stimulus intensity increases, more motor units are recruited, resulting in a larger overall muscle response and a higher CMAP amplitude.

The small difference in the minimum voltage needed to evoke a CMAP between the stimulus sites may be due to variations in nerve fiber excitability and electrode placement. Nerve fibers may have different thresholds for activation, and the location and positioning of the stimulating electrode can influence the effective stimulus intensity at different sites along the nerve pathway. These factors can contribute to slight variations in the minimum voltage required to elicit a CMAP response.

The calculated conduction velocity of the ulnar nerve may differ from the literature value of 60 m/s due to several reasons. One plausible explanation is the presence of a conduction block or nerve injury along the ulnar nerve pathway. A conduction block occurs when there is interruption or impairment of nerve conduction, resulting in a slower conduction velocity. This can be caused by nerve compression, inflammation, demyelination, or other pathological conditions.

If such a conduction block exists in the ulnar nerve of the subject being tested, it could lead to a deviation from the expected conduction velocity and a lower calculated value. Further diagnostic tests, such as nerve conduction studies or imaging, could help identify and evaluate the underlying cause of the deviation.

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Answer:

C. Hawaiian

Explanation:

Ego's father and all male relatives in his generation have the same kin name. Ego's mother and all female relatives in her generation are referred to by the same kin term.

Similarly, all brothers and male cousins are linked by giving them the same kin term. Sisters and all female cousins are also referred to by the same term.  

Answer:

When metals react with non-metals, electrons are transferred from the metal atoms to the non-metal atoms, forming ions. The resulting compound is called an ionic compound.

:

Answer:

5 Pascal

Explanation:

Formula for pressure = \(\frac{Force Applied}{Area}\)

Plug in the numbers, it will be 25N divided by 5\(m^{2}\), whch is equal to 5 Pascal

Answer:

Explanation:

Friction is a force that opposes the motion or potential motion of two items that come into contact. The word "relative motion" emphasizes that friction resists the motion of the objects with respect to one other, and it emphasizes that friction specifically operates against the motion or potential motion between two objects in contact.

ohm's law is a formula used to calculate the relationship between voltage, current, and resistance in an electrical circuit. To students of electronics, ohm's law (e =ir) is as fundamentally important as einstein's relativity equation ( e= mc2) is to physicists. e = l x r. rest is on Goo gle

The Heron's fountain demonstrates the principles of fluid mechanics through the transfer of energy between containers. By applying conservation of energy and momentum, the calculations reveal the potential and kinetic energy involved in the system.

Introduction

The Heron’s fountain, named after Heron of Alexandria, a Greek inventor who lived in 1st century AD, is an ancient device that is often used for the purpose of explaining the basic principles of fluid mechanics.

It is a simple device that uses the force of gravity and the laws of physics to create a self-sustaining fountain. The basic idea behind the Heron’s fountain is that the weight of the water in the top container pushes down on the air in the bottom container, forcing the water to flow out of the spout and into the bottom container.

Methodology

The methodology of this experiment involves building a Heron’s fountain and then conducting various experiments to determine the amount of energy that is being transferred between the containers.

The basic components of the Heron’s fountain include three containers of varying sizes, a pump, a spout, and some tubing. The water is pumped into the top container and then flows out of the spout and into the bottom container. The air in the bottom container is then compressed, forcing the water back up into the top container.

Calculations

The calculations for this experiment will involve the use of the principles of conservation of energy and momentum. The basic idea is that the amount of energy that is being transferred between the containers is equal to the change in potential energy and kinetic energy of the water.

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Electric current is the rate of flow of electric charges measured in ampere (A).

Electric charge can be positive of negative. The rate of flow of electric charges is known as current, measured in units of ampere.

Q = It

where;

\(I = \frac{Q}{t}\)

Thus, electric current is the rate of flow of electric charges measured in ampere (A).

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Answer:

distance divided by time is the speed. Your welcome

Explanation:

lanthanide is another name for the rare earth

elements.

Answer:

use common sense

Explanation:

An organ pipe that can resonate at frequencies of 330 Hz and 550 Hz, and nothing in between is a type of resonator known as a standing wave or a harmonic. The 330 Hz and 550 Hz resonant frequencies are the first and third harmonic frequencies, respectively. It can be deduced that this type of pipe is a closed pipe with one closed end and one open end.

When sound waves enter the pipe, they encounter the closed end of the pipe, which creates a node, or a region with no movement. As a result, only odd-numbered harmonics of the fundamental frequency are allowed to resonate within a closed pipe with one closed end. In contrast, only even-numbered harmonics of the fundamental frequency are allowed to resonate within an open pipe. Harmonics are simply frequencies that are multiples of the fundamental frequency, and they represent standing waves within the pipe. The first harmonic is the fundamental frequency, followed by the second, third, and so on. In general, the frequency of the nth harmonic of a pipe is given by the formula: fn = n(v/2L)where v is the speed of sound and L is the length of the pipe. For a closed pipe with one closed end, only odd-numbered harmonics are allowed.

Thus, the resonant frequencies of the pipe are given by:

f1 = v/4L,

f3 = 3v/4L,

f5 = 5v/4L, and so on.

Since the pipe in question only resonates at 330 Hz and 550 Hz, we can deduce that the length of the pipe is such that the first harmonic frequency is 330 Hz and the third harmonic frequency is 550 Hz.

By equating these two expressions and solving for L, we get:

L = (3v/4f3)

= (v/4f1)

Using the given frequencies, we can solve for the speed of sound in air:

v = 4f1L

= 4(330)(L)

= 1320 L

= 1.1L

= (3v/4f3)

= (3/4)(1320)/(550)

= 1.2 m

Thus, the length of the pipe is 1.1 meters, which is consistent with a pipe that is closed at one end and open at the other. The fact that it only resonates at odd-numbered harmonics confirms this conclusion.

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The magnitude of the electric field is 1.77 x 10⁶ N/C, under the condition that the  distance is  25.00 cm

The electric field at a distance of 25 cm from the axis of the cylinder can be calculated using Gauss's law. The electric field at a point outside a uniformly charged cylinder is given by

E = (ρ × r) / (2 × ε0),

here

ρ = charge density,

r = distance from the axis of the cylinder

ε0 = permittivity of free space.

Now, we have a non-uniform volume charge density of

ρ = 4 × r²C/m³

r = 25 cm

= 0.25 m

Staging these values in the above equation

E = (ρ × r) / (2 × ε0) = (4 × r³) / (2 × ε0)

= (2 × r³) / ε0

E = (2 × (0.25 m)³) / ε0

= 1.77 x 10⁶ NN/C

Therefore, the magnitude of the electric field at a distance of 25 cm from the axis of the cylinder is 1.77 x 10⁶ N/C.

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The current in each resistor is 4 A, 2 A, and 4 A, respectively. The voltage drop across each resistor is 12 V.

When three resistors are connected in series with a six resistor and a 12-volt battery, the total resistance of the series circuit is R = R1 + R2 + R3 + ...

The current flowing through the circuit is the same at every point. So, if we want to know the current flowing through each resistor, we need to use Ohm's law, I = V/R, where V is the voltage of the battery and R is the resistance of each resistor.

I1 = V/R1 = 12/3 = 4 AI2 = V/R2 = 12/6 = 2 AI3 = V/R3 = 12/3 = 4 A. The voltage drop across each resistor can be calculated using Ohm's law, V = IR.

V1 = I1R1 = 4 x 3 = 12 VV2 = I2R2 = 2 x 6 = 12 VV3 = I3R3 = 4 x 3 = 12 V.

Therefore, the current in each resistor is 4 A, 2 A, and 4 A, respectively. The voltage drop across each resistor is 12 V.

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The speed of transverse waves on a wire can be calculated using the equation v = sqrt(T/μ), where v is the speed of the waves, T is the tension in the wire, and μ is the linear mass density of the wire.

First, we need to calculate the linear mass density of the wire. Linear mass density (μ) is equal to the mass per unit length. To find this, we divide the mass of the wire (5.00 g) by its length (1.250 m):

μ = mass/length = 5.00 g / 1.250 m = 4.00 g/m.

Next, we can substitute the given values into the equation for the speed of the waves:

v = sqrt(T/μ) = sqrt(650.0 N / 4.00 g/m).

To make the units consistent, we need to convert the grams to kilograms:

4.00 g/m = 4.00 x 10^(-3) kg/m.

Now we can substitute the values into the equation:

v = sqrt(650.0 N / (4.00 x 10^(-3) kg/m)).

Evaluating this equation gives us the speed of transverse waves on the wire.

Please note that in order to provide an accurate numerical value for the speed of transverse waves, the equation would need to be evaluated. However, as a text-based AI, I am unable to perform calculations.

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Answer:

The amount of heat needed to vaporize 33.3 grams of ethyl alcohol at its boiling point of 78.0°C is approximately 2.84 × 10^4 Joules.

Explanation:

The heat required for vaporization can be calculated using the formula: q = m * ΔHvap, where q is the heat, m is the mass, and ΔHvap is the latent heat of vaporization.

Substituting the given values, we have:

q = 33.3 g * 857 J/g = 2.8491 × 10^4 J.

Rounding to three significant figures, the amount of heat needed is approximately 2.84 × 10^4 Joules.

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Answer:

k = 44000 N/m

Explanation:

Given the following data;

Maximum gravitational potential energy = 770 J

Elastic potential energy = 14% of 770 J = 14/100 * 770 = 107.8 J

Extension, x = 42 - 35 = 7cm to meters = 7/100 = 0.07 m

To find the spring constant, k;

The elastic potential energy of an object is given by the formula;

\( E.P.E = \frac {1}{2}kx^{2}\)

Substituting into the equation, we have;

\( 107.8 = \frac {1}{2}*k*0.07^{2}\)

\( 107.8 = \frac {1}{2}*k*0.0049 \)

Cross-multiplying, we have;

\( 215.6 = k*0.0049 \)

\( k = \frac {215.6}{0.0049} \)

k = 44000 N/m

The spring constant of the tendon is 44000 N/m.

The following can be depicted from the question:

Elastic potential energy will be:

= 14% × 770J = 107.80 Joule.

The spring constant will be calculated thus:

107.8 = 1/2 × k × 0.07²

107.8 = 0.5 × k × 0.0049

k = 215.6 / 0.0049

k = 44000 N/m.

Therefore, the spring constant of the tendon is 44000 N/m.

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Answer:

2.5 km/30min

Explanation:

Divide 5 by 2 because 30  min is half of 1 hour. when you do that you get 2.5

Answer:

Explanation below

Explanation:

Ice, mostly in the form of glaciers can create different landforms as it erodes the earth. In some areas with mountains, the glaciers move gradually downhill and across the land areas. When they move, the transport virtually everything on their path, ranging from small grains of sands to huge boulders.  

As these glaciers flow, the rocks being carried in the process scrape against the ground and erode both the ground and the rocks. Rocks are being ground up and oils are scrapped away.  

The main types of erosion created by the glaciers are abrasion and plucking.  

Answer:

Mining is the extraction of valuable minerals or other geological materials from the earth from an orebody, lode, vein, seam, or reef, which forms the mineralized package of economic interest to the miner. Ores recovered by mining include metals, coal, oil shale, gemstones, limestone, dimension stone, rock salt, potash, gravel, and clay.

Explanation:

Answer:

Three resources that are mined from earth's crust are:
-Coal
-Gold
-Iron ore

Some more are:
-Aluminum
-Copper
-Lime
-Phosphate rock
-Gypsum
-Sand
-Gravel
-Rock
etc.

Explanation:

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Answer:

An airplane is flying at an airspeed of 200 miles per hour headed on a SE bearing of 140°. A north wind (from north to south) is blowing at 16.2 miles per hour, as shown in Figure 8.8.1. What are the ground speed and actual bearing of the plane?

Explanation:

plss brainlieist me

θ = 205° - 105° = 100°

\(\tt R=\sqrt{L^2+M^2+2LMcos\theta}\\\\R=\sqrt{303^2+555^2+2.303.555cos100}\\\\R=584.32~m\)

Answer: Air

Explanation:

Roffns dn b bdd

Answer:

KE = 1/2 m v^2

Explanation:

Answer:

Explanation:

Conditions for equilibrium require that the sum of all external forces acting on the body is zero (first condition of equilibrium), and the sum of all external torques from external forces is zero (second condition of equilibrium). These two conditions must be simultaneously satisfied in equilibrium

Here initial speed u=0m/s    final speed v=26.5 m/s and acceleration due to gravity g=9.81 m/s^2

Where:

m = mass of the object (kg)

g = acceleration due to gravity (9.8 m/s^2)

h = height of the cliff (m)

We know the velocity of the object just before it hits the ground, which is 26.5 m/s. We can use this velocity to calculate the kinetic energy of the object just before it hits the ground.

KE = (1/2)mv^2

As the object is dropped from the cliff, its initial potential energy is converted to kinetic energy. Therefore, the initial potential energy is equal to the final kinetic energy.

GPE = KE

mgh = (1/2)mv^2

We can solve for h by rearranging the equation and substituting the known values for GPE, KE, m, and g.

Simply multiply the acceleration of gravity by the period of time since the object was released to determine the object's speed (or velocity). In other words, velocity is equal to -9.81 m/s2 * time, or V = gt. The item is just traveling downwards when there is a negative sign.

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To find the volume occupied by 11.0 grams of a gas at STP (standard temperature and pressure), we can use the ideal gas law:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature.

At STP, the pressure is 1 atm, the temperature is 273 K, and the ideal gas constant is 8.31 J/mol*K. We can therefore use the following equation to find the volume occupied by 11.0 grams of the gas:

V = (nRT)/P

To find the number of moles of gas, we can use the following formula:

n = m/M

Where m is the mass of the gas in grams and M is the molecular mass of the gas in grams/mol.

Substituting the given values into this formula, we find that the number of moles of gas is:

n = 11.0 g / 44.0 g/mol

= 0.25 mol

We can now substitute this value into the ideal gas law equation to find the volume occupied by the gas at STP:

V = (0.25 mol)(8.31 J/mol*K)(273 K)/(1 atm)

= 6.53 liters

Rounding this value to the nearest tenth of a liter, we find that the volume occupied by 11.0 grams of the gas at STP is approximately 6.5 liters