Find the measure of the exterior ∠1.

Answer:

i think c

Step-by-step explanation:

Answer:

Step-by-step explanation:one-5th I THINK

Answer:

\(y = - \frac{4}{5} x + \frac{6}{5} \)

Step-by-step explanation:

First subtract 4x on both sides in order to get -5y alone. Now you have -5y = 4x + 6 (since neither 6 nor 4x are like terms). Now divide -5 on both sides in order to get rid of it, so we can get y by its self. Now you have y = -4/5 x + 6/5

Hope this makes sense. Also please tell me if I'm wrong and I'll be happy to look at it again for ya :)

I think its G  dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddddddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddeddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddddddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddddddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddddddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddddddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddddddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddddddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddddddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddddddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddedddedededededddddddddddddddd dddeddded

Answer:

the correct answer is A. 25 sandwiches.

Step-by-step explanation:

Assuming you have plenty of bread and jelly, you can make 25 sandwiches from the jar of peanut butter.

Each sandwich typically requires 2 tablespoons of peanut butter, one slice of bread with peanut butter and one slice of bread with jelly.

So, if you have 50 tablespoons of peanut butter, you can make 25 sandwiches with it, because 50 / 2 = 25.

Therefore, the correct answer is A. 25 sandwiches.

Answer: 25

Step-by-step explanation:

We have 50 tablespoons of peanut butter and we know that it requires 2 tablespoons to make a single sandwich. In order to find how many sandwiches we can make with our 50 tablespoons, we would have to do 50 divided by 2.

2+2...=50

The probability for possibilities of x between P(X>4) and P(6.72<X<10.16)  is 0.5987 and 0.2351

X is N(5, 16)

means that, Z=(x-mean)/√variance = (x-5)/√4

=(x-5)/2

that is, Z is standard normal.

Then, by symmetry of the standard normal curve,

P(X>4)=P(X−5>4−5)

=P(X−54>4−54)

= P(Z>−14)

=P(Z>−.25)

=P(Z<.25)

= 0.5987.

Similarly

P(6.72<X<10.16)

= P(6.72−5<X−5<10.16−5)

=P(6.72−54<10.16−54)

=P(0.43<Z<1.29)

=P(Z<1.29)−P(Z<.43)

=.9015−.6664

= 0.2351.

Therefore, The probability for possibilities of x between P(X>4) and P(6.72<X<10.16)  is 0.5987 and 0.2351

Complete question - X is a normal random variable with mean=5 and variance=4 What are the possibilities for P(X>4) and P(6.72<X<10.16)?

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Answer:

The answer would be -12x^2-4x+6

Step-by-step explanation:

This is the simplest form it could get since you subtract the two x^2 together.

The meaning of the statement, "if the function has no parameters, then the class C is definable" is that if there are no parameters given then the class c can be defined with an empty set but if there are no parameters, then the class cannot be defined.

The meaning of the above statement is that if no parameters are provided for this function, then the given class represented as c can be defined with an empty set that is enclosed in parameters.

Also, if the parameters are given then the class c is not defined.

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Answer:

-6x^2-18x+1

Step-by-step explanation:

not fully sure but hope this helps!!

The probability of obtaining at least three tails is; 5/16

When tossing a coin four times, the number of possibilities since one is either a tail or head is;

Total number of possibilities = 2⁴ = 16

Now, various ways of getting at least three tails are;

TTTH, TTHT, THTT, HTTT, and TTTT.

This is a total of 5 different ways.

Thus;

P(obtaining at least 3 tails) = 5/16

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Answer:

the probability that a randomly selected potential customer will purchase the product is 0.11728

Step-by-step explanation:

Given the data in the question;

by hypothesis, let the event be given as;

M = buyers sees a given magazine ad of the product

T = buyers sees a given television ad of the product

\(P_{A}\) = buyer purchases the product after seeing the ad

\(P_{A"}\) = buyer purchase the product without seeing the ad

from the information given in the question;

P(M) = (2/50 ) = 0.04,  P(T) = ( 1/7) = 0.1428,  P(M∩T) = (1/100) = 0.01,

P(\(P_{A}\)) = (1/5) = 0.2, p( \(P_{A"}\)  ) = (1/10) = 0.1

now, the probability that the buyer sees the ad of the product will be;

P( M ∪ T ) = P( M) + P(T) - p( M ∩  T)

P( M ∪ T ) = 0.04 + 0.1428 - 0.01

P( M ∪ T ) = 0.1728

The probability that the buyer does not see the ad of the product will be;

P( M ∪ T )' = 1 - P( M ∪ T )

= 1 - 0.1728

= 0.8272

Now, the probability that a randomly selected potential customer will purchase the product will be;

P(P) = P(\(P_{A}\)) P( M ∪ T ) + p( \(P_{A"}\)  )P( M ∪ T )'

P(P) = (0.2)(0.1728) + (0.1)(0.8272)

= 0.03456 + 0.08272

P(P) = 0.11728

Therefore, the probability that a randomly selected potential customer will purchase the product is 0.11728

Thus, the mass is increasing at a rate of 0.15625 kg per hour, and the mass on this day is 4.5 kg.

Let's consider a general formula for finding the rate of increase:Rate of increase = k x original valueHere, k is a constant that represents the rate of increase per unit of time, and the original value is the initial value of the quantity being measured.

For example, if the original value is 3.2 kg and the rate of increase is 0.5 kg per hour, we can use the formula to calculate the mass at any time t as follows: Mass at

time t = 3.2 + (0.5 x t)

where t is the time elapsed in hours.In order to find k, we need to know the rate of increase and the original value.

Once we have these values, we can rearrange the formula to solve for

k:k = rate of increase / original value

For example, if the mass is increasing at a rate of 0.5 kg per hour and the original value is 3.2 kg, we can calculate k as follows:

k = 0.5 / 3.2k = 0.15625

To find the rate of increase on a specific day, we need to know how much time has elapsed since the original value was measured. Once we have this information, we can plug it into the formula we derived earlier:Mass at time t = 3.2 + (k x t)For example, if 8 hours have elapsed since the original value was measured, we can calculate the mass on that day as follows:

Mass at time t = 3.2 + (0.15625 x 8)

Mass at time t = 4.5 kg

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Answer:

According to the Heron's formula, Area (A) of the triangle having sides a,b,c units is

A=

s(s−a)(s−b)(s−c)

where

s=

2

a+b+c

For the given triangle,

a=18 cm

b=24 cm

c=30 cm

s=

2

18+24+30

=36

A=

36(36−18)(36−24)(36−30)

A=

36×18×12×6

A=

216×216

=216 cm

2

Smallest side =18 cm

Area of the triangle =

2

1

×base×altitude=216

2

1

×18× altitude=216

Altitude =

9

216

=24 cm

Step-by-step explanation:

hope this will help

\(\boxed{\boxed{\pink{\bf \leadsto The \ length \ of \ shortest \ altitude \ is \ 2.4\sqrt{6} \ units . }}}\)

Here given measure of sides are 18 , 24 and 30 units. Firstly let's find the area of ∆ using Heron's Formula.

\(\boxed{\red{\bf Area_{\triangle} =\sqrt{s(s-a)(s-b)(s-c)}}}\)

Where s is semi Perimeter . And here s will be ( 18 + 24 + 30 ) / 2 = 36 units .

\(\bf \implies Area = \sqrt{s(s-a)(s-b)(s-c)} \)

\(\bf \implies Area = \sqrt{ 36 ( 36 - 18)(36-24)(36-30)}\)

\(\bf \implies Area = \sqrt{ 36 \times 18 \times 12} \)

\(\bf \implies Area = \sqrt{ 6^2 \times 6\times 6 \times 2 \times 3} \)

\(\bf \implies Area = 6^2\sqrt{6} unit^2 \)

\(\bf \boxed{ \implies Area_{triangle} = 36\sqrt{6} units^2} \)

Also we know that ,

\(\boxed{\red{\bf Area_{\triangle} = \dfrac{1}{2}\times (base)\times (height)}}\)

Let's find the altitudes now ,

Altitude on side of 18 units :-

\(\bf \implies Area = \dfrac{1}{2} \times (base)(height) \\\\\bf \implies 36\sqrt{6} unit^2 = \dfrac{1}{2} \times 18 \times h_1 = 36\sqrt{6} u^2 \\\\\bf\implies h_1 =\dfrac{ 36\sqrt6 \times 2 }{18} \\\\\boxed{\bf\implies h_1 = 4\sqrt6 units }\)

Altitude on side of 24 units :-

\(\bf \implies Area = \dfrac{1}{2} \times (base)(height) \\\\\bf \implies 36\sqrt{6} unit^2 = \dfrac{1}{2} \times 24 \times h_1 = 36\sqrt{6} u^2 \\\\\bf\implies h_1 =\dfrac{ 36\sqrt6 \times 2 }{24} \\\\\boxed{\bf\implies h_1 = 3\sqrt6 units }\)

Altitude on side 30 units :-

\(\bf \implies Area = \dfrac{1}{2} \times (base)(height) \\\\\bf \implies 36\sqrt{6} unit^2 = \dfrac{1}{2} \times 30 \times h_1 = 36\sqrt{6} u^2 \\\\\bf\implies h_1 =\dfrac{ 36\sqrt6 \times 2 }{30} \\\\\boxed{\bf\implies h_1 = 2.4\sqrt6 units }\)

The given differential equation is a third-order linear homogeneous equation.

According to the Existence and Uniqueness Theorem, a unique solution exists if the coefficients of the differential equation are continuous on the given interval, which is the case here. Since the initial conditions y″(0) = 2, y'(0) = 1, and y(0) = 0 are also given, the existence and uniqueness of a solution are guaranteed by the theorem. Therefore, the given differential equation is guaranteed to have a unique solution on the specified interval. A differential equation is an equation that relates a function to its derivatives (or differentials) of one or more independent variables. In other words, it expresses a relationship between an unknown function and its rate of change.

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The complete question is :

According to the Existence and Uniqueness Theorem, which of the following differential equations are guaranteed to have a unique solution on the specified interval. Explain your reasoning.

x2d3ydx3-4x-1d2ydx2+3dydx+2y=0,y″(0)=2,y'(0)=1,y(0)=0

Step-by-step explanation:

get a coin and toss it 40 times.....then input your answers....

dont forget to make a prediction about the outcome first

The probability of randomly forming the word "woord logic" is:Probability = 1 / (10! / (2!))

To calculate the probability of forming the word "woord logic" by randomly arranging the letters l, o, g, i, c, we need to consider the total number of possible arrangements and the number of arrangements that result in the desired word.

The word "woord logic" has 10 letters in total. Among these letters, there are 2 o's and the remaining letters appear only once.

The total number of possible arrangements is given by the factorial of the total number of letters:

Total arrangements = 10!

However, since the letter "o" appears twice, we need to divide by the factorial of the number of repeated letters:

Total arrangements = 10! / (2!)

To calculate the number of arrangements that result in "woord logic," we consider that the arrangement of "woord logic" is unique and distinct. Thus, there is only one arrangement that matches the desired word.Simplifying this expression would yield the exact probability.

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It is not possible for Andrew to have spent 80 minutes running on the treadmill if he spends exactly 120 minutes total at the gym and runs on the treadmill for 60 minutes longer than he does strength training.

what is arthematic equation?

Arithmetic equations are mathematical statements that use numbers and arithmetic operations such as addition, subtraction, multiplication, and division to express the relationship between the quantities involved.

Let's assume that Andrew spends x minutes doing strength training, and according to the problem statement, he spends 60 minutes more running on the treadmill than strength training. So the time he spends running on the treadmill is x + 60.

The total time Andrew spends in the gym is 120 minutes, so:

x + (x + 60) = 120

Simplifying this equation, we get:

2x + 60 = 120

2x = 60

x = 30

Therefore, Andrew spends 30 minutes on strength training and (30 + 60) = 90 minutes on the treadmill.

So, it is not possible for Andrew to have spent 80 minutes running on the treadmill if he spends exactly 120 minutes total at the gym and runs on the treadmill for 60 minutes longer than he does strength training.

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no, it's not possible for andrew to have spent 80 minutes running on the treadmill. if we subtract 80 from 120 (the total) we get 40 which means he had to have spent 40 minutes doing strength training but if we subtract 60 (how many more mins he spent on running than he did strength training) minutes from 80 we get 20. he spent 20 minutes on strength training which adds up to 100 minutes, not 120 minutes.

Answer:

x=4

Step-by-step explanation:

Four less than the product of a number and 8:

8x−4

is twice the sum of the number and 10, so

8x−4=2(x+10)

Simplify.

8x−4=2x+20

Add 4 to both sides, which is

8x=2x+24

Subtract 2x from both sides:

6x=24

Divide 6 from both sides to isolate the x

x=4

-how I got 20

8x-4=2(x+10) x=8 so 8+10=18 18+2=20

also sorry for posting the answer in the comments and then making an answer after you saw i just wanted da points and hope it helped you :)

Answer:

GUI

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Client Server

The value of AB is,

⇒ AB = 5.9

(rounded to nearest tenth)

We have to given that,

A right triangle ABC is shown.

Now, By trigonometry formula,

we get;

⇒ cos 33° = Base / Hypotenuse

Substitute all the values, we get;

⇒ cos 33° = AB / 7

⇒ 0.84 = AB / 7

⇒ AB = 0.84 × 7

⇒ AB = 5.88

⇒ AB = 5.9

(rounded to nearest tenth)

Thus, We get;

AB = 5.9

(rounded to nearest tenth)

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Answer:

The answer is: 4y(2x+y)

Step-by-step explanation:

Answer:

32

Step-by-step explanation:

4 ÷ 1/8

make 4 into a fraction

4/1 ÷ 1/8

when dividing a fraction you change the divide into multiply and you flip the second fraction:

4/1 × 8/1 = 32

Answer:

32

Step-by-step explanation:

1/8 = 1 / 8 = 0.125        4 / 0.125 = 32

mad skillz gl cheating on your I-ready test

Answer:

D. 2 = 2

Step-by-step explanation:

Whenever you try to solve an equation and you just end up with a number = a number that means there is an infinite number of solutions.

The probability that the random sample of 100 male students has a mean gpa greater than 3. 42 is 0.9452.

A statistic known as the standard deviation is used to describe how volatile or dispersed a group of numerical values is. While a big standard deviation denotes that the values are scattered across a wider range, a low standard deviation indicates that the values tend to be close to the set mean.

From the given information, a scores random sample of 100 male students is selected and the GPA for each student is calculated which follows approximately normal with a mean of 3.5 and standard deviation of 0.5. That is,

µ = 3. 5 and σ = 0. 5

and the random sample of 100 male students has a mean GPA 3.42 is considered.

The z-score value is,

Z=( 3.42-3.5)/ (0.5/√100)

Z= -0.08/0.05

Z=-1.6

The value of z-score is obtained by taking the difference of x and µ. Then the resulting value is divided with the standard deviation by sample size.

The probability that the random sample of 100 male students has a mean GPA greater than 3.42 is obtained below:

The required probability is,

P(X>3.42)=P(z>-1.6)

= 1- P(Z≤-1.6)

From the “standard normal table”, the area to the left of Z=-1.6 is 0.0548.

P(X>3.42)= 1- P(Z≤-1.6)

=1-0.0548

=0.9452

The probability that the random sample of 100 male students has a mean GPA greater than 3.42 is 0.9452.

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Answer:

96 in³

Step-by-step explanation:

Volume = 2(BHD) / 2

The 2s cancel out

Volume = 3(8)4

Volume = 96

Answer:

\(\dfrac{x}{2}+\dfrac{1}{3}\)

Step-by-step explanation:

We need to find the value of \(((\dfrac{1}{4}x+\dfrac{3}{4}x-\dfrac{1}{2}x)+1+(\dfrac{-2}{3}))\)

We can solve it as follows :

\(((\dfrac{1}{4}x+\dfrac{3}{4}x-\dfrac{1}{2}x)+1+(\dfrac{-2}{3}))\\\\=(\dfrac{x+3x-2x}{4})+1-\dfrac{2}{3}\\\\=\dfrac{2x}{4}+\dfrac{1}{3}\\\\=\dfrac{x}{2}+\dfrac{1}{3}\)

Hence, the value of \(((\dfrac{1}{4}x+\dfrac{3}{4}x-\dfrac{1}{2}x)+1+(\dfrac{-2}{3}))\) is equal to \(\dfrac{x}{2}+\dfrac{1}{3}\).

An ellipse is defined as the set of all points such that the sum of the distances between the point and the two foci is constant. The equation of an ellipse can be represented in the standard form as:

(x-h)^2/a^2 + (y-k)^2/b^2 = 1

where (h, k) is the center of the ellipse, a is the distance from the center to a vertex, and b is the distance from the center to the focus.

Given that the center of the ellipse is at (2, 1), one vertex is at (2, -4), and one focus is at (2, -2), we can use this information to find the values of a and b, and represent the equation of the ellipse:

a = distance from center to vertex = |1 - (-4)|/2 = 2.5

b = distance from center to focus = |1 - (-2)|/2 = 1.5

The equation of the ellipse is:

(x-2)^2/2.5^2 + (y-1)^2/1.5^2 = 1

which can also be written as:

(x-2)^2/6.25 + (y-1)^2/2.25 = 1

This equation represents the ellipse with center at (2, 1), one vertex at (2, -4), and one focus at (2, -2)

The number is 13 / 10

The product of a number and the sum of six and five is equal to the sum of the number and thirteen.

Therefore,

let the number  = x

x(6 + 5) = x + 13

Hence,

x(6 + 5) = x + 13

11x = x + 13

11x - x = 13

10x = 13

x = 13 / 10

Therefore, the number is 13 / 10

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(a) 794g of the initial sample will be left in the sample after 25 years. (b) Time taken to decay to half of its original amount is 3.39 years.

Isotopes(200g) are atoms that have the same number of protons in their nucleus, but a different number of neutrons. This means that they have the same atomic number, but a different atomic mass. Because of this, isotopes have different physical and chemical properties. Isotopes can be stable, meaning that they do not undergo radioactive decay, or they can be unstable, meaning that they will undergo radioactive decay over time.

(a) Substituting 25 for t in the expression, we get:

\(A(25) = 200e^{0.0541 \times 25}\)

         \(= 200e^{1.3525}\)

Thus, after 25 years, there will be

\(200e^{1.3525} = 2003.97\)

794 g of the initial sample left in the sample.

(b) We want to find t such that

\(A(t) = 200e^{0.0541}\)                                          

       = 100.

Solving for t, we get:

\(= 200e^{0.0541} \times t=100\)

Dividing both sides by 200 and applying the natural logarithm to both sides, we get:

0.0541 × t = ln(0.5)

Therefore,

\(t = \frac{ln(0.5)}{0.0541}\)

  = 3.39 years.

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