what energy is released in the - decay of 99mo, given its mass is 98.907711 u?

Answer:

Saturn is B, Neptune is D, Jupiter is A, and Uranus is C

Explanation:

Each one is different and if you do some research on each planet the question is not that hard.

The decay constant of a radioactive nuclide is 4.6 × 10-3 s-1. the half-life of the nuclide is approximately 2.5 minutes.

To determine the half-life of the radioactive nuclide with a decay constant of 4.6 × 10⁻³ s⁻¹, we can use the following formula:

Half-life (T½) = ln(2) / decay constant

Where ln(2) is the natural logarithm of 2, which is approximately 0.693.

Now, plug in the given decay constant:

T½ = 0.693 / (4.6 × 10⁻³ s⁻¹)

T½ ≈ 150.65 seconds

To convert seconds to minutes, divide by 60:

T½ ≈ 150.65 / 60

T½ ≈ 2.51 minutes

So, the half-life of the nuclide is approximately 2.5 minutes.

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Answer:

The velocity of the cricket ball is 17.32 m/s

Time is taken by the ball to reach the highest point = 0.8660 seconds

Explanation:

The cricket ball can be seen and treated as a projectile in this case

The maximum height attained by a projectile in motion can be calculated using the formula:

\(h = \frac{v^2 sin^2 \theta }{2g}\)

In any projectile problem, once we know see that the object was released vertically upwards, we need to know that this means that the angle of projection is 90 degrees, and sin 90 is = 1

hence, h will be modified to become

\(h = \frac{v^2 }{2g}\)

\(v = \sqrt{2gh}\)

We are given that h = 15m and g = 10m/s2

\(v = \sqrt{2 \times 10 \times 15} = 17.32m/s\)

The velocity of the cricket ball is 17.32 m/s

B. We can get the time it took to reach the highest point by dividing

time = distance/speed

Time = 15/17.32 = 0.8660 seconds

If the resistance remains constant and the voltage doubles, the power will increase by a factor of 4 (option E)

The following data were obtained from the question:

P = V² / R

Resistance is constant, we have

V₁² / P₁ = V₂² / P₂

V² / P = (2V)² / P₂

V² / P = 4V² / P₂

Cross multiply

V² × P₂ = P × 4V²

Divide both side by V²

P₂ = P × 4V² / V²

P₂ = P × 4

From the above, we can conclude that the power will increase by a factor of 4 (option E)

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The impulse applied to an object can be calculated using the equation:

Impulse = Change in momentum

The momentum (p) of an object is defined as the product of its mass (m) and velocity (v):

Momentum = mass × velocity

Given:

Mass of the football (m) = 0.430 kg

The initial velocity of the football = 0 m/s (since it was initially at rest)

The final velocity of the football (v) = 5.00 m/s

The change in momentum (∆p) is equal to the final momentum (p_f) minus the initial momentum (p_i):

∆p = p_f - p_i

Since the initial momentum (p_i) is zero, the change in momentum (∆p) is equal to the final momentum (p_f):

∆p = p_f

Substituting the values into the equation, we have:

∆p = (mass × final velocity) - (mass × initial velocity)

∆p = (0.430 kg × 5.00 m/s) - (0.430 kg × 0 m/s)

∆p = (2.15 kg·m/s) - (0 kg·m/s)

∆p = 2.15 kg·m/s

Therefore, the magnitude of the impulse applied to the football is 2.15 kg·m/s.

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Answer:

33.3m

Explanation:

Recall that for a regular wave, the relationship between, wavelength, frequency  and velocity (speed) is given by :

v = fλ,

where:

v = velocity (speed) of the wave = 50m/s

f = frequency of the wave = 1.5 Hz

λ = wavelength (we are asked to find this)

simply substitute the given values into the equation:

v = fλ

50 = 1.5 λ,

λ = 50/1.5

λ = 33.3m

Answer: If you apply force to an object the velocity changes. But it doesn't work the other way around apply velocity and the force (no!)  Velocity does not change on an object.   A force pushes or pulls on an object, but velocity is simply something an object has I hope this makes sense to you. Hope this helps :)

Explanation:

Option C. is correct. The recurrent nova has the potential to build up its mass over time and eventually reach the critical threshold for a Type I supernova.

Recurrent novae are binary star systems where a white dwarf accretes material from a companion star. When the accreted material reaches a critical mass, a thermonuclear explosion occurs on the surface of the white dwarf, resulting in a nova outburst. Unlike classical novae, recurrent novae experience multiple eruptions over time.

As a recurrent nova continues to accrete material, the mass of the white dwarf gradually increases. If the mass surpasses the Chandrasekhar limit of about 1.4 times the mass of the Sun, a Type I supernova can occur. In a Type I supernova, the white dwarf undergoes a catastrophic explosion, completely destroying the star.

Therefore, the recurrent nova has the potential to build up its mass over time and eventually reach the critical threshold for a Type I supernova.

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Answer:

B or D

Explanation:

I wanna say B but I don't really know if it's a trick question

my explanation for D is that anvils are usually 110 decibles and ear drums usually are damaged when exposed to 82dbs or higher at a consistant rate so I'd imagine that'd be the answer I hoped this helped

Answer:

the answer is B

Explanation:

Any harmful noises can be bad. yes, an Anvil and Hammer can be bad but so can explosions and gun fire and having music to loud

Answer:

Generally, when thermal energy is transferred to a material, the motion of its particles speeds up and its temperature increases. There are three methods of thermal energy transfer: conduction, convection, and radiation. ... Convection transfers thermal energy through the movement of fluids or gases in circulation cells.Convection. When a fluid, such as air or a liquid, is heated and then travels away from the source, it carries the thermal energy along. This type of heat transfer is called convection. The fluid above a hot surface expands, becomes less dense, and rises.

The time required to drop the pressure of one of the gases from 2.0 atm to 0.25 atm at 389 K is 288 hours, or Option (D).

For a first order reaction, the change in pressure of a gas is proportional to its initial concentration and to the rate constant of the reaction. The half-life of a first order reaction is defined as the time required for the concentration of a reactant to decrease to half its initial value.

The rate constant (k) of a first order reaction can be related to its half-life (t1/2) as follows:

k = 0.693 / t1/2

We can use this relationship to find the rate constant for our reaction:

k = 0.693 / 24 hours = 0.0289 h^-1

Next, we can use the rate constant to find the time required for the pressure of one of the gases to decrease from 2.0 atm to 0.25 atm:

P = P0 * e^(-kt)

ln(P/P0) = -kt

-t = ln(P/P0) / k

where P0 is the initial pressure, P is the final pressure, t is the time, and e is the base of natural logarithms.

Plugging in the values, we get:

-t = ln(0.25/2.0) / 0.0289 h^-1

t = 288 hours

Therefore, the time required to drop the pressure of one of the gases from 2.0 atm to 0.25 atm at 389 K is 288 hours, or Option D).

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Explanation:

Thermal conductivity is a measure that refers to the rate at which heat is transferred by conduction through a unit cross-section area of a material.

or in simpler terms how well a substance conducts heat.

its formula is seen in the attachment. hope this helps.

Answer:

c

Explanation:

J. J. Thomson used a cathode-ray tube to calculate the charge-to-mass ratio of the electron. The deflection of cathode rays towards the positively charged surface proved that they are negatively charged particles.

In 1897, J.J Thomson performed a cathode ray tube experiment to determine the charge-to-mass ratio of electrons.

Due to high flow of voltage, a beam of particles was allowed to flow from the negatively charged end to the positively charged end of the tube.

An end of the tube was painted with phosphorous and when electrons struck that end, a green spark was observed which confirmed the presence of negatively charged particles i.e. electrons.

To put it simply, cathode rays came from the cathode tube and deflected towards a positively charged plate showing that they are negatively charged particles.

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From the core concept introduced by Al-Haytham, modern cameras are created.

To find the answer, we have to know about the Camera Obscura.

Thus, we can conclude that, from the core concept introduced by Al-Haytham, modern cameras are created.

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Answer:

They can be replanted.

Explanation:

Renewable sources can be found again and again, similar to how you can plant a tree again to receive food sources and heat production, which in turn is useful to humans.

When The trees are considered a renewable resource because They can be replanted. The correct option is 'B'.

When Renewable sources can be found, again and again, similar to how you can plant a tree again to receive food sources and also heat production, they are in turn useful to humans.

When the renewable resources are resources, generally naturally happening, they can replenish to the rate that they can return the used volume and also be swallowed.

A renewable resource will either produce itself naturally through automatic approaches to that resource or through human interaction and guidance.

Therefore, The correct option is 'B'.

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Answer:

\(5.8\; {\rm kg\cdot m \cdot s^{-1}}\).

Explanation:

If the mass of an object is \(m\) and the velocity of that object is \(v\), the linear momentum of that object would be \(m\, v\).

Assume that the initial velocity of the mass is positive (\(6.0\; {\rm m\cdot s^{-1}}\).) However, the direction of the velocity is reversed after the impact. Thus, the sign of the new velocity of the object would be negative- the opposite of that of the initial velocity. The new velocity would be \((-4.0\; {\rm m\cdot s^{-1}})\).

Thus, the change in the velocity of the mass would be:

\(\begin{aligned}& (\text{Change in Velocity}) \\ =\; & (\text{Final Velocity}) - (\text{Initial Velocity}) \\ =\; & (-4.0\; {\rm m\cdot s^{-1}}) - (6.0\; {\rm m\cdot s^{-1}}) \\ =\; & (-10\; {\rm m\cdot s^{-1})\end{aligned}\).

The change in the linear momentum of the mass would be:

\(\begin{aligned} & \text{change in momentum} \\ =\; & (\text{mass}) \times (\text{change in velocity}) \\ =\; & 0.58\; {\rm kg} \times (-10\; {\rm m\cdot s^{-1}}) \\ =\; & (-5.8\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}\).

Thus, the magnitude of the change of the linear momentum would be \(5.8\; {\rm kg \cdot m \cdot s^{-1}}\).

Answer:

9 m/s

Explanation:

speed = distance ÷ time

27÷3

=9

I would choose the option B.

F = ma

a = 75 / 25 = 3 m/s^2

The acceleration of the given object will be equal to 3 m/s². Therefore, option (B) is correct.

Acceleration of an object can be explained as the change in the velocity of an object with respect to time. The acceleration is a vector quantity as it exhibits magnitude and direction. Acceleration can be calculated from the 2nd derivative of the position of the object w.r.t. time.

The force is the product of the mass and acceleration, according to Newton's second law of motion.

F = ma

And,   a = F/m

From the above formula, we ca say that the acceleration is inversely proportional to mass.

Given, the force acting on the object, F = 75 N

The mass of the object, m = 25.0 Kg

The acceleration of the given object, a = 75/25 =3 m/s²

Therefore, the acceleration of the object is equal to 3 m/s².

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Answer:

3.5 hours

Explanation:

A projectile is launched at an angle of 33⁰ above the horizontal, then the projectile launched at an angle of 90 - 33 = 57⁰ will have the same range as the projectile launched at 33⁰. The correct option is (B) 57⁰.

In the absence of air resistance, a projectile launched at an angle of 33 above the horizontal will have the same range as a projectile launched at an angle of 57⁰.

The range of a projectile can be determined by using the range formula.

R = ((v^2 * sin(2θ))/g) Where

R is the range of the projectile,

v is the velocity of the projectile,

θ is the angle at which the projectile is launched, and

g is the acceleration due to gravity.

In the absence of air resistance,

the horizontal component of velocity of a projectile remains constant throughout the flight.

So, the range of a projectile depends only on its initial velocity and the angle at which it is launched.

If a projectile is launched at an angle θ,

the time of flight of the projectile can be calculated by using the following formula:

T = (2v * sin(θ))/g

The maximum height reached by the projectile is given by the formula:

H = (v^2 * sin^2(θ))/2gIf a projectile is launched at an angle θ, then the range of the projectile will be the same as the range of the projectile launched at an angle of (90 - θ).

So, if a projectile is launched at an angle of 33⁰ above the horizontal, then the projectile launched at an angle of 90 - 33 = 57⁰ will have the same range as the projectile launched at 33⁰.

Therefore, the correct option is (B) 57⁰.

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To find the expressions and sketch the waveforms for the voltage, power, and stored energy in a 100 mH inductance, given that the current is given by 0.5 sin(1000t)a, we can follow these steps
 
The stored energy in an inductor can be calculated using the formula W = (1/2) * L * I^2, where L is the inductance and I is the current.
Substituting the values, we get W = (1/2) * 0.1 * (0.5 sin(1000t)a)^2.
 Simplifying the expression, we have W = 0.0125 sin^2(1000t)a.
 
 The voltage across the inductor is given by V = 50 cos(1000t)a. The power in the inductor is given by P = 12.5 sin(2 * 1000t)a.The stored energy in the inductor is given by W = 0.0125 sin^2(1000t)a. To sketch the waveforms, plot the values of V, P, and W against time (t) for the range 0 to 3π ms, using the given expressions. Remember to scale the axes appropriately to represent the waveforms accurately.

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The correct prediction about the angular momentum and rotational kinetic energy of the sphere-rod system immediately before the collision and immediately after the collision is: Before the collision, the sphere has linear momentum (mass mo multiplied by velocity to) while the rod has zero angular momentum since it is at rest.

After the collision, the sphere and rod form a single system, and the conservation of angular momentum dictates that the final angular momentum of the system should equal the initial angular momentum of the sphere. Therefore, the sphere-rod system will have non-zero angular momentum after the collision.

Regarding rotational kinetic energy, before the collision, the sphere has linear kinetic energy (1/2 mo * to²) and the rod has zero rotational kinetic energy. After the collision, the sphere-rod system will have rotational kinetic energy (as they both rotate around the pivot with a common angular velocity). Due to the inelastic nature of the collision, some linear kinetic energy from the sphere will be converted to rotational kinetic energy in the sphere-rod system, but not all of it, as some energy will be lost as heat and sound during the collision.

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Answer:

2 seconds lol im just a kid but I know these lol who has tiktok

Thermal energy absorption or release can cause a change in the state of matter.

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The emf power supply should be used for a 0.75 A recharging current is 2.25 V.

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

Given is the battery having 1.5 V open circuit potential and internal resistance of 1 ohm.

From the Ohm's law, V =IR

R = V/I

Here, R is the proportionality constant.

To charge current I = 0.75 A

Voltage V = 0.75A x 1 ohm = 0.75 V

Total potential required is

= 1.5 +0.75

= 2.25 V

Thus, the emf power supply should be used for a 0.75 A recharging current is 2.25V.

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Answer:

-3.33m/s^2

Explanation:

From the graph, we can read that the object between segments C and D changed its velocity from 10m/s to 0m/s over 3 seconds.

(0m/s - 10m/s) / 3s = -10 / 3 * m/s^2 = -3.3333... m/s^2

The weight of the object in the newly heavenly body is 3000 N.

In science and engineering, the weight of an object is the pressure performed on the item due to gravity. a few widespread textbooks outline weight as a vector quantity, the gravitational pressure performed on the item. Others define weight as a scalar quantity, the significance of the gravitational pressure.

Given,

mass of earth = M

mass of new heavenly body = 12 M

the radius of the earth = r

the radius of the new heavenly body = 4r

mass of the object = m (mass always remains constant)

\(\frac{mM}{r^2}\)

using the formula of gravity,

G₁ = g\(\frac{mM}{r^2}\)

G₂ = g\(\frac{m12M}{4r^2}\)

comparing G₁  and G₂

G₁ = 1000 N given

G₁ / G₂ = M × 4r² /  12 M r²

G₂ = 1000 × 12 / 4

     = 3000 N

The measure of the pressure of gravity performing on a frame. The method for weight is given by using: w = mg. As weight is a force its SI unit is also the same as that of pressure, the SI unit of weight is Newton (N).

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Answer:

B

Explanation: