Answer:
Baking Brownies
Explanation:
when the brownie is baked, the kind of matter changes and a new substance is formed. A chemical change is a change that cannot be reversed.
The answer baking brownies/A because before, the brownies were just a mixture and when it bakes it actually make a new substance
When a radio telescope observes a region of space between two stars, it detects electromagnetic radiation that has a wavelength of 0.21 m. This radiation was emitted by hydrogen atoms in the gas and dust located in that region.
Required:
What is the frequency of this radiation?
Answer:
14.3 x 10^8Hz
Explanation:
Using
Frequency= speed of light /wavelength
Then substituting
3*10^8m/s / 0.21m
= 14.3 x10^8 Hz
As you stand by the side of the road, a car approaches you at a constant speed, sounding its horn, and you hear a frequency of 76 Hz. After the car goes by, you hear a frequency of 65 Hz. What is the speed of the car
The speed of the car is approximately 266 m/s.
The observed change in frequency of the sound as the car approaches and passes by is known as the Doppler effect. The Doppler effect occurs when there is relative motion between a sound source and an observer.
In this case, as the car approaches, the sound waves emitted by the car are compressed, resulting in a higher frequency (higher pitch) being heard by the observer. After the car passes by, the sound waves are stretched, resulting in a lower frequency (lower pitch) being heard.
To calculate the speed of the car, we can use the formula for the Doppler effect:
v = f * (v_s / v_o - 1)
where:
v is the speed of the car,
f is the frequency observed,
v_s is the speed of sound (approximately 343 m/s),
v_o is the original frequency emitted by the car's horn.
Given that the frequency observed when the car approaches is 76 Hz and the frequency observed when it passes by is 65 Hz, we can plug in these values into the formula and solve for v:
v = 76 * (343 / 76 - 1)
v = 76 * (4.5 - 1)
v = 76 * 3.5
v = 266 m/s
Therefore, the speed of the car is approximately 266 m/s.
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A group of tourists drives through a state park in Maine. While arguing about whether the animal they've just seen is an Elk or a Moose, a chipmunk darts across the park road. The driver, who was traveling 6.7 m/s through the park slams on their breaks and comes to a stop. If the car has an acceleration of -8.3 m/s2, how long does it take the car to stop?
Answer:
0.8 second
Explanation:
Given data
Speed v=6.7m/s
Deceleration = - 8.3m/s²
Initial velocity u= 0m/s
We can solve for the distance covered upon breaking the speed using the expression
v=u +at
6.7=0-(8.3)t
6.7=8.3t
Divide both sides by 8.3
6.7/8.3=t
t=6.7/8.3
t=0.8 second
A skier starts from rest at the top of a hill that is inclined at 10.5° with the horizontal. The hillside is 200.0 m long, and the coefficient of friction between the snow and the skis is 0.075. At the bottom of the hill, the snow is level and the coefficient of friction is unchanged. How far does the skier move along the horizontal portion of the snow before coming to rest? Show all of your work.
Answer:
2000
Explanation:
ddoes rest : add the components
You walk 6.7 km to the east and then 10.9 km to the west.
What is your displacement from where you started?
Answer:
4.2 km West of the start
Explanation:
Displacement is a vector quatitiy which means it has direction adn magnitude. It is the distance you are at the very end of the journey from the start.
We can assign one way as a positive direction and the other a negative and then add them
I will say that West is positive and East is negative:
(10.9) + (-6.7) = 4.2km
which of these galaxies is most likely to be the oldest? (a) a galaxy in the local group (b) a galaxy observed at a distance of 5 billion light-years (c) a galaxy observed at a distance of 10 billion light-years
A galaxy in the local group is most likely to be the oldest.
How many light years old is the cosmos?As a result, the cosmos is estimated to be around 25 billion light years across. In 1958, Alan Sandage reduced the Hubble's constant value once more, but he still came up with an age range for the universe between 15 and 25 billion years.It is exactly because of the expanding cosmos that we can see things that are up to 46.1 billion light-years away. There will always be restrictions on the items we can view and the objects we might be able to access, regardless of how much time passes.Our own Milky Way galaxy, according to astronomers, is 13.6 billion years old. The most recent galaxy that we are aware of originated about 500 million years ago.To learn more about galaxy refer to:
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Two blocks of masses 2 kg and 3 kg approach each other on a horizontal plane at velocities of 4 and 1.5 m/s, respectively. if the blocks collide and remain together, calculate the joint velocity after collision.
The joint velocity of the blocks after the collision is 2.5 m/s.
What are the initial velocities of the two blocks before the collision?To solve this problem, we can use the principle of conservation of momentum. The initial momentum of the system is equal to the final momentum, assuming there are no external forces acting on the system.
The initial momentum of the system is given by the sum of the individual momenta of the blocks. Block 1 has a mass of 2 kg and velocity of 4 m/s, giving it a momentum of 8 kg m/s. Block 2 has a mass of 3 kg and velocity of 1.5 m/s, resulting in a momentum of 4.5 kg m/s.
Since the blocks collide and stick together, their combined mass is 2 kg + 3 kg = 5 kg. The final momentum of the system is given by the joint velocity of the blocks after the collision, multiplied by the total mass.
Let the joint velocity after collision be V. Therefore, the final momentum is 5 kg * V kg m/s.
Using the principle of conservation of momentum, we equate the initial and final momenta:
8 kg m/s + 4.5 kg m/s = 5 kg * V kg m/s
Simplifying the equation, we get:
12.5 kg m/s = 5 kg * V kg m/s
Dividing both sides of the equation by 5 kg, we find:
V = 12.5 kg m/s / 5 kg = 2.5 m/s
The joint velocity of the blocks after the collision is 2.5 m/s.
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Write your answer as: base^exponent*base^exponent
The exponential form of the given number is (-7)⁴. 6⁵.
Exponent is the term used to describe a way to represent huge numbers using powers. In other words, the exponent describes how many times a number has been multiplied by itself.
A number that appears as a superscript over another number is the exponent. In other words, it means that the base has been elevated to a particular level of power. Other names for the exponent are index and power. mn indicates that m has been multiplied by itself n times if m is a positive number and n is its exponent which can be said as the m raised to n.
The given numbers are,
(-7) . (-7) . (-7) . (-7) . 6. 6 . 6 . 6 . 6
So, 7 is multiplied by itself 4 times and 6 is multiplied by itself 5 times.
Therefore, it can be written in the exponential form as,
(-7)⁴. 6⁵
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Shown below are the four terrestrial planets of our solar system. Assume that all the planets started out equally hot inside. Rank the planets based on their expected cooling rates, from fastest cooling to slowest cooling.MercuryMarsVenusEarth
The rank of the terrestrial planets based on their expected cooling rates, from fastest cooling to slowest cooling is as follows -
mercury , Mars, Venus, Earth
Mercury - It is the smallest terrestrial planet in the solar system. It has a thin atmosphere, which causes it to swing between burning and freezing temperatures.
Mars - It is less dense than Earth and has a smaller magnetic field, which is a indication of a solid core rather than a liquid one. Mars is known to have water ice and organics- some of the ingredients for living things.
Venus - It is about the same size as Earth and has a thick, toxic carbon-monoxide (CO) dominated atmosphere that traps heat, making it the hottest planet in the solar system.
Earth - Out of the four terrestrial planets, Earth is the largest and has regular seasons for much of it surface; regions closer to the equator tend to stay warm, while spots closer to the poles are cooler and in the winter, icy.
Therefore, the cooling rate of terrestrial planets is Mars, Earth, Venus, Mercury
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Where did Ford first see parts made from vanadium steel? What properties of this steel impressed Ford? Did Ford need to overcome any problems before going ahead with his plan?
Explanation:
Historical sources believe that Henry Ford first saw parts made from vanadium steel in Europe which were been used on racing cars and luxurious vehicles.
Ford was impressed due to the fact that Vanadium steel unlike normal steel was cheaper and at the same time stronger and lighter if it was used on automobiles.
Calculate the energy per photon (in J) associated with a frequency of 1260kHz Submit answer in scientific notation using the foat 0.00×10∧ 0(e.g.0.000123=1.23×10 ∧
−4). Omit units and spaces.
The energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.
To calculate the energy per photon, we can use the equation: E = hf, where E represents the energy, h is the Planck's constant (6.62607015 × 10^-34 J·s), and f is the frequency of the photon. Given that the frequency is 1260 kHz, we need to convert it to hertz (Hz) by multiplying it by 10^3:
Frequency = 1260 kHz × 10^3 = 1.26 × 10^6 Hz
Now, we can substitute the values into the equation:
E = (6.62607015 × 10^-34 J·s) × (1.26 × 10^6 Hz)
E = 8.33929859 × 10^-28 J
The answer is given in scientific notation as 8.34 × 10^-28 J. However, the question specifically asks for the answer in the format of 0.00×10^0. To achieve this, we can multiply the result by 10^3 and adjust the exponent accordingly:
E = (8.33929859 × 10^-28 J) × (10^3)
E = 8.33929859 × 10^-25 J
Thus, the energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.
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If the mirror moves at 1.5m/s towards Peter while Peter remains at rest, what will he observe? Explain your reasoning
Answer:
Peters image will grow bigger
Explanation:
In this situation, only Peter is at rest and the mirror is in motion at 1.5m/s heading towards Peter.
From afar, Peter will look small in the mirror that is his image will be small When the mirror is moved at 1.5m/s Peter being the observer will notice that his image grows bigger and bigger.
You are gardening in the peak of summer, it hasn't rained in a week, and your plants are looking rough. You decide to water the plants for an hour. The next day you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. With what you know from class, please try and explain what is happening to your plants.
In the peak of summer, it hasn't rained in a week, and the plants are looking rough, so watering the plants for an hour is a good idea.
However, the next day, you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. Plants absorb water through their roots. The root system of a plant is responsible for drawing water and nutrients from the soil. A plant's root system must be able to absorb water quickly in order for the plant to grow and thrive. When the soil around the root system is dry, the roots will stop growing and will not be able to absorb water.
It may even start to die. Watering plants during the peak of summer is important because it will help keep the soil moist and prevent the roots from drying out. However, watering a plant too much can be harmful. If a plant is overwatered, the water may not be able to penetrate the soil and reach the roots. Instead, it may just sit on top of the soil, causing the roots to rot and die. This can cause the plant to wilt and die.To summarize, if the soil around the plant is too dry, the roots may not be able to absorb the water you gave them, causing the plant to look worse than before. Conversely, overwatering can also be harmful because the water may not be able to penetrate the soil and reach the roots, causing the roots to rot and die.
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Part A What is the gravitational potential energy of the Earth-Sun system? Express your answer to two significant digits and include the appropriate units. μÀ ? U = Value Units Submit Previous Answe
The gravitational potential energy of the Earth-Sun system is -2.2 x 10^33 joules. The negative sign indicates that it is a bound system with the potential energy being negative.
The gravitational potential energy between two objects can be calculated using the formula U = -GM m/r, where U is the gravitational potential energy, G is the gravitational constant, M and m are the masses of the two objects, and r is the distance between their centers of mass.
For the Earth-Sun system, the mass of the Earth (M) is approximately 5.972 x 10^24 kg, the mass of the Sun (m) is approximately 1.989 x 10^30 kg, and the average distance between them (r) is approximately 1.496 x 10^11 meters.
Plugging these values into the formula, we get:
U = -(6.67430 x 10^-11 Nm^2/kg^2) * (5.972 x 10^24 kg) * (1.989 x 10^30 kg) / (1.496 x 10^11 meters) = -2.2 x 10^33 joules
The gravitational potential energy of the Earth-Sun system is -2.2 x 10^33 joules. The negative sign indicates that it is a bound system with the potential energy being negative.
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What is the first step needed to solve ? (1 point)
(03.04 LC)
What is the first step needed to solve (3/4)x - 3 = 18
Select one:
a. Add 3 to both sides
b. Subtract 18 from both sides
c. Multiply both sides by 3
d. Divide both sides by 4
Answer:
answer is add 3 to both sides
describe the reflection of the pulse from a fixed point
When a pulse encounters a fixed point, such as a wall or a rigid boundary, it undergoes reflection. Reflection occurs when the pulse bounces back upon reaching the fixed point.
During reflection, the pulse experiences a change in direction but retains its original shape and properties. The incident pulse approaches the fixed point and interacts with it. As a result, an equal and opposite pulse is generated and travels back in the opposite direction.
The behavior of the reflected pulse depends on the nature of the incident pulse and the properties of the medium it travels through. If the pulse is inverted (upside-down) before reflection, the reflected pulse will also be inverted. Similarly, if the incident pulse is right-side-up, the reflected pulse will maintain the same orientation.
The reflection process follows the law of reflection, which states that the angle of incidence (the angle between the incident pulse and the normal to the fixed point) is equal to the angle of reflection (the angle between the reflected pulse and the normal). This law ensures that energy and momentum are conserved during the reflection process.
In conclusion, when a pulse encounters a fixed point, it undergoes reflection, resulting in the generation of an equal and opposite pulse traveling in the opposite direction. The reflected pulse retains the same shape and properties as the incident pulse, following the law of reflection.
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Which of the following products will have elastic demand (alcohol, gasoline, travel souvenirs, cigarettes)
The product among alcohol, gasoline, travel souvenirs, cigarettes that will have elastic demand is cigarettes.
What is elastic demand?Elastic demand refers to a situation in which a change in the price of a good or service results in a more significant change in the amount demanded. When the percentage change in quantity demanded is greater than the percentage change in price, the demand for the product is said to be elastic.
When the quantity demanded of a product decreases significantly when the price rises, the demand for the product is said to be elastic. Similarly, when a slight change in price causes a significant change in quantity demanded, the demand is said to be elastic. Conversely, if a product's price increases by a small percentage, and the demand for the product decreases by a smaller percentage, the demand for the product is said to be inelastic.
Cigarettes, of all the products listed above, are likely to have an elastic demand.
This is because smokers who are addicted to cigarettes are more likely to quit smoking or reduce their consumption in response to an increase in the price of cigarettes compared to the other goods.
Thus, a slight increase in the price of cigarettes is likely to cause a significant decrease in the number of cigarettes consumed.
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1.
Which is an example of a roundworm that parasitizes humans?
a.Fluke
B.Tapeworm
C Annelid
d.Hookworm
Answer:
D Hookworm
Explanation:
3.455 grams of gas are placed into a 150.0 ml container at 25 °c. the pressure is measured at 867 mmhg. what is the molar mass of the gas?
The molar mass of the gas is approximately 2725 g/mol.
To calculate the molar mass of the gas, we need to use the ideal gas law: PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
First, we need to convert the given values to the appropriate units. The pressure is given in mmHg, so we need to convert it to atm (the unit of pressure used in the gas constant):
867 mmHg x (1 atm/760 mmHg) = 1.14 atm
The volume is given in mL, so we need to convert it to L:
150.0 mL x (1 L/1000 mL) = 0.1500 L
The temperature is given in Celsius, so we need to convert it to Kelvin:
25 °C + 273.15 = 298.15 K
Now we can plug in the values and solve for the number of moles:
n = PV/RT = (1.14 atm)(0.1500 L)/(0.082057 L·atm/mol·K)(298.15 K) ≈ 0.00127 mol
Finally, we can calculate the molar mass by dividing the mass of the gas by the number of moles:
molar mass = mass/number of moles = 3.455 g/0.00127 mol ≈ 2725 g/mol
Therefore, the molar mass of the gas is approximately 2725 g/mol.
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Pre-questioning identifies a purpose for reading.
Please select the best answer from the choices provided
OT
O F
help pleaseeeee !!
Answer:
True
Explanation:
Pre-questioning may help a reader focus on information s/he hopes to find in the reading selection.
Answer:
True!!
Explanation:
I took the practice thing on edge :))
Heinrich hertz used properties of which type of wave to support the idea that light is also made of waves?.
Answer:
Hertz extended Maxwell's idea that light is produced by the interaction of electromagnetic fields. Waves produced a diffraction pattern. Results supported the wave theory of light.
a belt is placed around a pulley 41 cm in diameter and rotating at 242 rpm, what is the linear speed in m/s of the belt
Given
d: diameter
d = 41 cm
We need radius information so we will calculate it:
r: radius
r = d/2
r = 41/2
r = 20.5 cm
Rotating speed
w = 242 rpm
Procedure
At a distance r from the center of the rotation, a point on the object has a linear speed equal to the angular speed multiplied by the distance r. The units of linear speed are meters per second, m/s.
\(v=\omega r\)But before using the formula we need to have all the units in the same system. So we need to go from rpm to rad/s and from cm to m
\(\begin{gathered} 242\cdot\frac{\text{rev}}{\min}\cdot\frac{2\text{ pi rad }}{1\text{ rev}}\cdot\frac{1\text{ min}}{60\text{ s}} \\ 25.34\text{ rad/s} \\ \\ 20.5\text{ cm}\cdot\frac{1m}{100\operatorname{cm}} \\ 0.205\text{ m} \end{gathered}\)Now we can calculate the linear velocity of the belt.
\(\begin{gathered} v=\omega r \\ v=25.34\text{ rad/s}\cdot0.205\text{ m} \\ v=5.1947\text{ m/s} \end{gathered}\)Answer
The linear velocity of the belt would be 5.2 m/s.
Is it resistant to mud fire
Dirt that you can not burn typically does no longer have any materials that are flammable at decrease temperatures. Mostly due to the fact it is full of water and non-burnable minerals. But a lot of what's in grime can certainly burn if it is dried. Dirt is made of many unique things.
yes
Explanation:
since they are extremely dense they lack the ability to trap air due to its structure
B.
An object thrown or shot vertically into the air reaches a maximum height after t secondsâ (when time is measured inâ seconds), where t is theâ k-coordinate of the vertex of the parabola.
The maximum height of an object thrown or shot vertically into the air is reached after t seconds, where t is the k-coordinate of the vertex of the parabola.
When an object is thrown or shot vertically, its motion can be modeled by a parabolic function.
The vertex of this parabola represents the highest point the object will reach, and the k-coordinate of the vertex represents the time it takes for the object to reach that height.
Hence, The maximum height of a vertically thrown or shot object is attained at the k-coordinate of the vertex of the parabola, which corresponds to the time t in seconds.
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Why is it important to try to use as many renewable resources as possible?
Answer:
It is important to use renewal resources because we use so many non- renewable resources that we may lose the ability to make a lot of things like gasoline or power for our cities.
In a heat engine, 2.00 mol of a monoatomic gas are carried through the cycle ABCDA. The segment AB represents an isothermal expansion, the segment BC is an adiabatic expansion, the segment CD is an isobaric compression, and DA is a constant volume process. The pressure and temperature at A are 5.00 atm and 600 K. The volume at B is twice the volume at A. The pressure at D is 1.00 atm.
a) What is the pressure at B?
b) What is the temperature at C?
c) Find the total work done by the gas in one cycle.
(a)The pressure at B is 0.1248 atm.
(b)The temperature at C is 727.1 K.
(c)The total work done by the gas in one cycle is -1979J
General calculation:
We can use the First Law of Thermodynamics to analyze the heat engine cycle:
ΔU = Q - W
where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system. For a complete cycle, ΔU = 0, so:
Q = W
We can also use the ideal gas law to relate the pressure, volume, and temperature of the gas:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature.
(a)How to find the pressure at B segment?
To find the pressure at B, we can use the fact that the segment AB is an isothermal expansion. This means that the temperature remains constant, so:
PV = nRT
PB = (nRT)/(2V) = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/(2V) = (0.0821 L·atm/mol)(600 K)/V
Since the pressure at A is 5.00 atm, we can use the fact that the temperature is constant to find the volume at A:
PV = nRT
VA = (nRT)/P = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/5.00 atm = 197.76 L
Since the volume at B is twice the volume at A, we have:
VB = 2VA = 395.52 L
Substituting into the expression for PB, we get:
PB = (0.0821 L·atm/mol)(600 K)/395.52 L = 0.1248 atm
Therefore, the pressure at B is 0.1248 atm.
(b) How to find the temperature at segment C?To find the temperature at C, we can use the fact that the segment BC is an adiabatic expansion. This means that no heat is added or removed from the system, so:
\(PV^\gamma\)= constant
where γ is the ratio of specific heats (for a monoatomic gas, γ = 5/3). We can use the fact that the volume at C is equal to the volume at A to find the pressure at C:
\(PAV^\gamma = PCV^\gamma\)
PC = \(PA(V/A)^\gamma\) = 5.00 atm\((1/2)^(^5^/^3^)\) = 1.556 atm
Since the segment BC is adiabatic, the temperature changes but no heat is added or removed from the system. Using the ideal gas law, we can relate the pressure, volume, and temperature:
PV = nRT
TC = (PCVC)/(nR) = (1.556 atm)(197.76 L)/(2.00 mol)(0.0821 L·atm/mol·K) = 727.1 K
Therefore, the temperature at C is 727.1 K.
(c) How to find the total work done by the gas in one cycle?The total work done by the gas in one cycle is the sum of the work done in each segment of the cycle:
W = WAB + WBC + WCD + WDA
For segment AB, the work done is:
WAB = -QAB = -∫PdV = -nRT∫(1/V)dV = -nRT ln(VB/VA) = -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2) = -602 J
For segment BC, the work done is:
WBC = -QBC = -∫PdV = -nγRT∫(1/V)dV = -nγRT
We know that VB = 2VA and VC = 2VD, so we can express the ratio VB/VC in terms of VA/VD:
VB/VC = (2VA)/(2VD) = VA/VD
Substituting into the expression for WBC, we get:
WBC = -nγRT ln(VA/VD)
For segment CD, the work done is:
WCD = -QCD + PCDΔV = -nCpΔT + PCDΔV
where Cp is the specific heat at constant pressure, ΔT is the change in temperature, and ΔV is the change in volume. We know that the segment CD is isobaric, so ΔV = VB - VA = (2VA) - VA = VA. We can also use the ideal gas law to relate the pressure, volume, and temperature:
PV = nRTPC = (nRT)/VDSubstituting into the expression for WCD, we get:
WCD = -nCpΔT + (nRT/VD)VA = -nCp(TC - TD) + (nRT/VD)VA
For segment DA, the work done is:
WDA = -QDA + ΔU = -nCvΔT
where Cv is the specific heat at constant volume. We know that the segment DA is isovolumetric, so ΔV = 0. Using the First Law of Thermodynamics, we know that ΔU = 0 for a complete cycle, so:
QDA = -WDA = nCvΔT
Substituting into the expression for WDA, we get:
WDA = -nCvΔT
Adding up the work done in each segment, we get:
W = WAB + WBC + WCD + WDA
= -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(Cp)(TC - TD) + (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(Cv)(TC - TA)
We know that Cp and Cv for a monoatomic gas are related by Cp = Cv + R, so we can express Cp in terms of Cv:
Cp = Cv + R = (3/2)R + R = (5/2)R
Substituting and simplifying, we get:
W = (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(727.1 K)+ (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(600 K)
W = -966.2 J - 4957 J - 7476 J + 5154 J
= -1979 J
Therefore, the total work done by the gas in one cycle is -1979 J
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Local winds and global winds are generally a result of which of the following?
O Earth's tilted axis.
O Unpredictable changes in the atmosphere.
O Variations in the energy received from the sun.
O Unequal heating of Earth's surface.
Answer: Unequal heating of Earth's surface
Explanation:
name two advantages and disadvantages of a physical vapor deposition thin film technique like electrodeposition and a chemical vapor deposition technique like atomic layer deposition
Advantages of Physical Vapor Deposition (PVD) thin film technique like electrodeposition:
High purity: PVD techniques, such as electrodeposition, allow for the deposition of thin films with high purity and controlled composition. This is advantageous in applications where impurities can negatively affect the performance or properties of the thin film.
Versatility: PVD techniques offer a wide range of options for deposition materials, including metals, alloys, and compounds. This versatility allows for the deposition of thin films with tailored properties to suit specific applications.
Disadvantages of Physical Vapor Deposition (PVD) thin film technique like electrodeposition:
Limited scalability: PVD techniques like electrodeposition are typically more suitable for small-scale applications or laboratory settings. Scaling up the process for large-scale production can be challenging and may require additional optimization.
Equipment and maintenance costs: PVD techniques often require specialized equipment and infrastructure, which can be costly to acquire and maintain. The need for vacuum systems, target materials, and power supplies adds to the overall expenses.
Advantages of Chemical Vapor Deposition (CVD) thin film technique like atomic layer deposition (ALD):
Precise control and uniformity: ALD allows for precise control of film thickness at the atomic level, resulting in excellent thickness uniformity across complex substrates. This enables the deposition of thin films with precise control of properties, such as thickness, composition, and surface roughness.
Conformal coating: CVD techniques, including ALD, can deposit thin films with excellent conformal coverage, even on highly complex and three-dimensional structures. This is advantageous for applications where uniform coverage on irregular surfaces is essential.
Disadvantages of Chemical Vapor Deposition (CVD) thin film technique like atomic layer deposition (ALD):
Slow deposition rates: CVD techniques, including ALD, often have slower deposition rates compared to some other thin film deposition methods. This can be a limitation when high throughput or fast production is required.
Complexity and cost: CVD techniques typically involve more complex processes, including precursor delivery, gas flow control, and temperature control. The complex equipment and process requirements can increase the overall cost and complexity of the thin film deposition process.
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e angle changes 70° in a time interval of 0.2s. alculate the: 5 Magnitude of the emf induced in the coil. Current induced in the coil if it has an effective resistance of 20 S
The magnitude of the emf induced in the coil is 0.096 volts, and the current induced in the coil, considering an effective resistance of 20 ohms, is 0.0048 amperes.
Faraday's law of electromagnetic induction states that when a magnetic field changes in intensity or when a conductor moves in a magnetic field, an electromotive force (emf) is induced in the conductor. This induced emf is proportional to the rate of change of the magnetic field or the rate at which the conductor cuts the magnetic field lines.
Now, let's calculate the values requested:
a. To calculate the magnitude of the emf induced in the coil, we can use the formula:
emf = N * A * B * sin(θ)
Where:
N = number of turns in the coil = 100 turns
A = area of each turn of the coil = 4.8 x 10^(-4) m²
B = magnetic field strength = 4 x 10^(-4) T
θ = angle between the magnetic field and the normal to the plane of the coil = 30°
Plugging in the values:
emf = 100 * 4.8 x 10^(-4) * 4 x 10^(-4) * sin(30°)
Calculating this expression will give you the magnitude of the emf induced in the coil.
b. To calculate the current induced in the coil, we can use Ohm's Law:
emf = I * R
Where:
emf = electromotive force induced in the coil (calculated in part a)
R = effective resistance of the coil = 20 ohms
Rearranging the formula:
I = emf / R
Substituting the values calculated in part a:
I = (emf calculated in part a) / 20 ohms
Calculating this expression will give you the current induced in the coil.
a. Using the formula for the magnitude of the induced emf:
emf = 100 * 4.8 x 10^(-4) * 4 x 10^(-4) * sin(30°)
emf = 100 * 4.8 x 10^(-4) * 4 x 10^(-4) * 0.5
emf = 0.096 volts
Therefore, the magnitude of the emf induced in the coil is 0.096 volts.
b. Using Ohm's Law:
I = emf / R
I = 0.096 volts / 20 ohms
I = 0.0048 amperes
So, the current induced in the coil, considering an effective resistance of 20 ohms, is 0.0048 amperes.
Hence, The magnitude of the induced emf in the coil is 0.096 volts, and the current induced in the coil is 0.0048 amperes, assuming an effective resistance of 20 ohms.
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29.92 inches of mercury and 101,325 pascals are both equivalent to 1 atmosphere of pressure. Calculate the number of pascals equivalent to 1 inch of mercury.
The number of pascal equivalent to 1 inch of mercury is 3386.53 pascal
From the question given above, we were told that:
29.92 inches of mercury = 1 atm
101325 pascal = 1 atm
Thus,
29.92 inches of mercury = 101325 pascal
With the above information, we can obtain the number of pascal equivalent to 1 inch of mercury. This can be obtained as follow:29.92 inches of mercury = 101325 pascal
Therefore,
1 inches of mercury = 101325 / 29.92
1 inches of mercury = 3386.53 pascalThus, the number of pascal equivalent to 1 inch of mercury is 3386.53 pascal
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