What does the pressure at a point in a fluid depend on? select all that apply.
Answers
The pressure at a point in a fluid depends on depth of the point in the fluid, density of the fluid, gravity, acceleration at the point
When we talk about fluids, pressure is defined as the force exerted per unit area by the molecules in motion. The pressure of a fluid at a particular point depends on many factors. These include the density of the fluid, depth of the point in the fluid, gravity, and acceleration at the point. The deeper a point is, the higher the pressure is, since the weight of the fluid above it increases.
As the density of the fluid increases, the pressure also increases. The acceleration at the point can affect pressure since it can alter the pressure gradient within the fluid. The formula for calculating pressure at a point in a fluid is P = ρgh. Here, P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth of the point in the fluid. So therefore the pressure at a point in a fluid depends on the depth of the point in the fluid, the density of the fluid, gravity and acceleration at the point
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Related Questions
Select the correct answers from the list.(1 point) A black hole begins to form as an aging star abruptly collapses when it ceases__________ . This occurs after the star has consumed its component elements in this order___________.
Answers
A black hole forms as a star collapses when it ceases emitting radiation from fusion reactions. This occurs after the star has consumed hydrogen, helium, then through iron.
Star evolution refers to the process by which stars evolve (change) over time.
A black hole can be defined as a collapsed star where the gravitational field in its nucleus becomes greater than particles cannot escape from it.
In consequence, black holes are cosmic bodies in which gravity is so powerful that nothing (i.e., particles, radiation, light, etc.) can escape from them.
Nuclear fusion refers to the energy reactions produced by the fusion of hydrogen at the core of a star, thereby becoming helium.
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According to the equivalence principle, which of the following observers is equivalent to an inertial observer who experiences no acceleration?
A) Any non-inertial observer.
B) A freely falling observer.
C) An observer who is static in a gravitational field.
D) An observer who is being accelerated by gravity as well as other forces simultaneously.
Answers
A freely falling observer is equivalent to an inertial observer who experiences no acceleration according to the equivalence principle (option B)
What is the equivalence principle?The equivalence principle establishes that the gravitational force encountered in a localized region is indistinguishable from the pseudo-force perceived by an observer situated within a non-inertial (accelerated) frame of reference.
Consequently, an observer in free fall within a gravitational field undergoes no discernible acceleration, mirroring the experience of an inertial observer.
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A 67.3-kg climber is scaling the vertical wall of a mountain. His safety rope is made of a material that, when stretched, behaves like a spring with a spring constant of 1.23 x 103 N/m. He accidentally slips and falls freely for 0.921 m before the rope runs out of slack. How much is the rope stretched when it breaks his fall and momentarily brings him to rest
Answers
Answer:
\(d=0.59m\)
Explanation:
From the question we are told that:
Mass \(m=67.3 kg\)
Spring constant \(\mu=1.23 * 10^3 N/m\)
Fall Height \(h=0.921m\)
Generally the Energy theorem equation for momentum is mathematically given by
Change in KE=Work done by gravity + work done by spring
\(0=mg*(h + d) - \frac{\mu d^2}{2}\)
\(0=(67.3 * 9.81 (0.921 + d)) -\frac{(1.23 * 10^3 * d^2}{ 2}\)
\(0=608.1-660.213d-615d^2\)
Solving Quadratic equation
\(d=0.59m\)
The warming of a car in the sun is an excellent analogy for the greenhouse effect of our atmosphere. Complete the analogy with the words and phrases then place the sentences in order. Drag the text blocks below into their correct order. visible light с The car windows allow and infrared radiation to pass into the car. Similarly, our atmosphere allows infrared radiation and to pass through. none polar ice caps The car's interior, like the Earth's absorbs and infrared radiation then emits infrared radiation back out.
Answers
The car's interior, like the Earth's, absorbs visible light and infrared radiation, then emits infrared radiation back out.
c. Visible light and infrared rays can enter the car through the windows. Similar to how visible light and infrared radiation can pass through our atmosphere. a. Similar to how a car's exterior reflects some incoming radiation, the polar ice caps do the same. b. Just like the Earth, the interior of the car collects visible light and infrared radiation before reemitting it. d. The automobile gets hotter since none of the radiation can get through the windows. Similar to how part of the radiation that the Earth emits is trapped in the atmosphere, global warming results.
Order correctly: Visible light and infrared radiation can enter the car through the windows.
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Mr. Hughes' 450 kg race car accelerates from 0 to 88 m/s in 4 seconds.
A)How much work does the engine do?
B)How much power does it have?
C)How much kinetic energy does it have after 4 seconds?
Please help
Answers
The engine does 1,358,400 Joules of work. The engine has a power of 340 kW. The car has 1,412,800 Joules of kinetic energy after 4 seconds.
How to calculate work, power, and kinetic energy of the engine?A) The work done by the engine can be calculated using the work-energy theorem, which states that the work done on an object is equal to its change in kinetic energy. Therefore, the work done by the engine can be calculated as follows:
\(Work = (1/2) \times m \times v^2 - (1/2) \times m \times u^2\)
where m is the mass of the car, v is the final velocity, and u is the initial velocity. Substituting the given values, we get:
\(Work = (1/2) \times 450 \times (88)^2 - (1/2) \times 450 \times (0)^2 = 1,358,400 J\)
Therefore, the engine does 1,358,400 Joules of work.
B) The power of the engine is the rate at which it can do work. It can be calculated using the formula:
Power = Work / time
Substituting the values, we get:
Power = 1,358,400 J / 4 s = 339,600 watts or 340 kW (rounded to two significant figures)
Therefore, the engine has a power of 340 kW.
C) The kinetic energy of the car after 4 seconds can be calculated using the formula:
Kinetic energy = \((1/2) \times m \times v^2\)
Substituting the given values, we get:
Kinetic energy =\((1/2) \times 450 \times (88)^2\) \((1/2) \times 450 \times (88)^2\) = 1,412,800 J
Therefore, the car has 1,412,800 Joules of kinetic energy after 4 seconds.
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A .530 kg block slides on a frictionless horizontal surface with a speed of 1.10 m/s. The block encounters an unstretched spring and compresses it 20.0 cm before coming to rest. Part A) What is the force constant of this spring? k=________N/m
Part B) For what length of time is the block in contact with the spring before it comes to rest?
t=________sec
Part C) If the force constant of the spring is increased, does the time required to stop the block increase, decrease, or stay the same.
Choices:
A) Increases
B) Decreases
C) Stays the same
Answers
The force constant of this spring is 16.03N/m; the length of time block is in contact with the spring before it comes to rest is 1.14s; If the force constant of the spring is increased, the time required to stop the block will decrease.
What happens if a block slides on a frictionless horizontal surface?
When a block slides over a horizontal surface without friction, it has kinetic energy. Before coming to rest, it runs into an untensioned spring and compresses it.
The energy is purely kinetic when the mass first comes into contact with the spring. Energy is transformed into spring potential energy as the spring is squeezed. To find the spring force constant, equate the energies. One-fourth of a period is represented by the motion. A stiffer spring will result in a smaller stopping distance for the mass, which will result in a faster stopping time.
(a)Equations: Conservation of energy using a spring.
Ei=Ef
1/2mvo2 = 1/2kA2
A= vo√m/k
K is force constant
k is 16.03N/m
(b) Time
T = 2∏√m/k
T = 1.14s
(c) The time to stop reduces as the force constant rises. A stronger spring and a greater stopping force result from a higher force constant, and a shorter stopping time follows. The compressed spring contains all of the energy left behind after the spring has stopped the block. The block will be accelerated back the way it came when the spring pushes back on it. The block will leave the spring moving in the opposite direction from where it first came into contact with it, but at the same speed. Equal to the stopping time is the accelerating time.
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Scientists measure mass with a(n)
Answers
There are a couple of ways to measure mass. The most common method is to use a balance. Hey, wait a minute! (you should be saying) People weigh stuff all the time with a balance! Think about it. If you go to a different planet, the balance weights change by the same factor as the object you are measuring. Your mass measured with a balance would be the same on the moon as it is on Earth. There are a couple of other neat tricks, but they only really work perfectly in no-gravity, no-friction environments. For example imagine a big rock floating in space. Give it a slap with a calibrated hand so you know exactly how much energy you gave it. Now measure how fast the rock is moving. That new speed is proportional to its mass. In space you weigh nothing, but your mass is the same, so a space bully can still shove the 98 pound weakling even though they both weigh 0 pounds.
If a car is moving on a straight line with a velocity of 40 m/s and it changes its velocity to 60 m/s in 4 seconds, calculate its acceleration.
Answers
Answer:
5m/s²
Explanation:
Initial Velocity= 40m/s
Final Velocity=60m/s
Time = 4s
a=(v-u)/t
a=60-40/4
a=20/4
a=5m/s²
Sound energy is converted into nerve impulses by the ____________ located inside of the ______________________.
Answers
Sound energy is converted into nerve impulses by the cilia located inside of the cochlea.
What is cochlea?The cochlea is a hollow, spiral-shaped bone discovered in the inner ear that plays an important role in hearing as well as participates in the auditory transduction process.
Sound waves are converted into electrical impulses, which the brain interprets as individual sound frequencies.
Cilia inside the ear can serve a number of purposes. One type of cilia aids hearing and detection of sound.
Even though they capture sound signals and send them to the brain for processing, cilia damage in the ear can cause significant hearing loss.
Thus, the answer for the given scenario is cilia and cochlea respectively.
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How many miles does the Earth travel around the Sun in a year?
Answers
In one year, the Earth travels approximately 584 million miles (940 million kilometers) around the Sun. This distance is known as the Earth's orbital circumference or its annual orbit.
The Earth follows an elliptical path around the Sun, with the Sun located at one of the foci of the ellipse. The average distance between the Earth and the Sun is about 93 million miles (150 million kilometers), known as an astronomical unit (AU).
To calculate the distance traveled, we need to consider that the Earth's orbit is not a perfect circle but rather an ellipse. Therefore, the distance traveled varies throughout the year. The Earth's speed is not constant either, as it follows Kepler's laws of planetary motion.
By using Kepler's second law, which states that the line connecting the Earth to the Sun sweeps out equal areas in equal times, and the average distance of 93 million miles, we can estimate the Earth's total distance traveled in one year to be approximately 584 million miles.
It's important to note that this value is an approximation, as factors such as the gravitational influences of other celestial bodies can cause slight variations in the Earth's orbit.
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A particle is confined to move on the surface of a circular cone with its axis on the vertical z axis, vertex at the origin (pointing down), and half-angle a. (a) Write down the Lagrangian L in terms of the spherical polar coordinates r and 0. (b) Find the two equations of motion. Interpret the 0 equation in terms of the angular momentum tz, and use it to eliminate 4 from the r equation in favor of the constant fz. Does your r equation make sense in the case that = 0? Find the value ro of r at which the particle can remain in a horizontal circular path. (c) Suppose that the particle is given a small radial kick, so that r(t) = ro E(t), where E(t) is small. Use the r equation to decide whether the circular path is stable. If so, with what frequency does r oscillate about r0?
Answers
The Lagrangian is then given by L = T - V.
(a) Writing down the Lagrangian (L): The Lagrangian is the difference between the kinetic and potential energies of the system.
In this case, the particle is confined to move on the surface of a circular cone, so we need to express the kinetic and potential energies in terms of the spherical polar coordinates (r, θ).
The kinetic energy can be expressed as T = (1/2) m (dr/dt)^2 + (1/2) m r^2 (dθ/dt)^2, where m is the mass of the particle.
The potential energy can be expressed as V = m g r cosθ, where g is the acceleration due to gravity.
The Lagrangian is then given by L = T - V.
(b) Finding the equations of motion: The equations of motion can be obtained by applying the Euler-Lagrange equations to the Lagrangian L.
This involves taking partial derivatives of L with respect to the generalized coordinates (r, θ) and their derivatives (dr/dt, dθ/dt), and then solving the resulting equations.
One of the resulting equations of motion will be related to the angular momentum tz. It can be interpreted as the conservation of angular momentum around the z-axis.
The r equation of motion can be used to eliminate θ from the r equation, in favor of a constant fz.
The r equation should make physical sense even when θ = 0.
To find the value ro of r at which the particle can remain in a horizontal circular path, you would need to analyze the equilibrium conditions of the system and solve for r.
(c) Analyzing stability and frequency of oscillation: By assuming r(t) = ro + E(t), where E(t) is a small radial perturbation from the equilibrium position ro, you can substitute this expression into the r equation of motion to determine whether the circular path is stable.
Stability can be determined by examining the behavior of the perturbation E(t) over time.
The frequency of oscillation about ro can be obtained by analyzing the form of the solution E(t) and determining the frequency at which it oscillates.
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a microwave with a frequency of 5.0 x 10 2 hertz has a period of
Answers
Hello,
QUESTION)✔ We have: T = 1/f; with T in s, and f in Hz
T = 1/5,0 x 10² Hz T = 2,0 x 10⁻³ sThe period of the microwave is therefore 2 ms.
Answer:
2.0x10^-11
Explanation:
T=1/f
T=1/5.0x10^10
T= 2.0x10^-11
Clyde takes a flight from Bellingham to Seattle, which is a distance of 90-miles,
at a constant speed of 180-mi/hr. He then rents a car and drives to a friend's house in Mt.
Vernon at 60-mi/hr. Mt Vernon is 30-miles from Bellingham.
What is trip distance?
Answers
Mrs. Cadillac's class pulls with a force of 50.4 N. Mrs. Barr's class pulls with a force of 48.8 N. What is the net force?
Answers
The net force on the rope will be equal to 1.6 N.
What is the net force?The net force can be defined as the vector sum of forces acting on a body. The net force can be described as a single force providing same the effect as the original forces on the body's motion.
The net force acting on an object becomes the resultant force. The net force has the same effect on the motion as all actual forces taken together by the object.
Given, the applied force by Mrs. Cadillac's class = 50.4 N
The applied force by Mrs. Barr's class = 48.8 N
The net force = 50.4 N + (-48.8N) = 1.6 N
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How many plants must be on the new settlement to provide enough oxygen for 20 adult humans to survive
Answers
Answer:
nasaan po yung problem?
Explanation:
picture kailangan kooo
the total energy of a system is 300j. if the potential energy is 40j what is the kinetic energy if the object started 300m above the ground?
Answers
Answer:
43.3 m/s.
Explanation:
Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:
Total energy = Potential energy + Kinetic energy
Kinetic energy = Total energy - Potential energy
Kinetic energy = 300 J - 40 J = 260 J
However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:
Potential energy = mgh
40 J = m(9.81 m/s^2)(300 m)
m = 0.137 kg
Now we can use the kinetic energy to find the velocity:
Kinetic energy = (1/2)mv^2
260 J = (1/2)(0.137 kg)v^2
v^2 = (2*260 J) / 0.137 kg
v = 43.3 m/s (rounded to one decimal place)
Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.
Question 15 (1 point
[01.03)
Which statement is true going
Oo
Ос
Gravity is the force of attraction between two dojeas with mask and is tecedent on the distance been these objes
Granty is the force that resesto dojects that have opposite charges. It is dependent upon the charges of the objec
Greity is a force that keeps dojects moving in space. The less the objects wegs, the former out in space gauty will pull the
Object
Gravity is the force of resistance to a change in position. The greater the distance been objects, the greater tis force will
Oo
Answers
Explanation:
The true statement about gravity is that it is the force of attraction between two objects with masses and also, based on the distance between these objects.
Gravity is a force of attraction.
The best scientific overview of the force of gravity is given by the Newton's law of universal gravitation which states that "the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them",
So, gravitational force of attraction is dependent on mass and the distance between two bodies.
What does the presence of molecular bands in the spectrum of a star indicate?a. The star has a low surface temperature.
b. The star has a high surface temperature.
c. The star is about to go supernova.
d. The star is spectral type G.
e. The star is spectral type TiO.
Answers
The presence of molecular bands in the spectrum of a star indicates that the star is spectral type TiO. Option e is the answer.
Molecular bands in the spectrum of a star indicate the presence of molecules in the star's atmosphere. TiO (titanium oxide) is a molecule that is commonly found in the atmospheres of cool stars, such as red giants and M-type stars.
The presence of TiO bands in a star's spectrum is a strong indicator that the star is of spectral type TiO. The other options listed in the question (low surface temperature, high surface temperature, about to go supernova, spectral type G) are not necessarily associated with the presence of molecular bands in a star's spectrum. Correct choice is option e.
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how to find the volume of a triangular pyramid calculator
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Finding the volume of a triangular pyramid is a straightforward process that requires finding the area of the base, the height, and then plugging those values into the formula for the volume of a pyramid.
To find the volume of a triangular pyramid calculator, we need to use a specific formula. The formula is:
V = (1/3) × B × h
Where V is the volume of the pyramid, B is the area of the base, and h is the height of the pyramid.
Here is how to calculate the volume of a triangular pyramid:
Step 1: Find the area of the base of the pyramid. You can use the formula for the area of a triangle, which is
A = (1/2) × b × h, where A is the area of the triangle, b is the base of the triangle, and h is the height of the triangle.
Step 2: Find the height of the pyramid. You can use the Pythagorean theorem to find the height. The Pythagorean theorem is:
a² + b² = c²,
where a and b are the legs of the right triangle, and c is the hypotenuse. In a triangular pyramid, the height is the length of the altitude from the apex to the base of the pyramid.
To find the height, you need to draw an altitude from the apex to the base of the pyramid, forming a right triangle.
Step 3: Plug in the values you found for the base area and the height into the formula for the volume of a triangular pyramid, which is
V = (1/3) × B × h.
Step 4: Simplify the expression to find the volume of the pyramid.
Step 5: Explanation
The volume of a triangular pyramid is V = (1/3) × B × h. This formula tells you that the volume of a pyramid is one-third the product of the base area and the height. If you know the area of the base and the height of the pyramid, you can use this formula to find the volume of the pyramid.
Step 6: Conclusion: In conclusion, finding the volume of a triangular pyramid is a straightforward process that requires finding the area of the base, the height, and then plugging those values into the formula for the volume of a pyramid.
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What happens to the molecules when the solid changes phase?
Answers
they begin to move quickly and can break away from other molecules
Answer:
When solid changes atoms/molecules begin to speed up and move around. Compared to when they are in the solid phase, where they barely move and are slow and are compacted.
why is storing hazardous waste in barrels and burying them deep in the ground a bad idea? How might that aproach be made safer.
Answers
Answer:
Explanation:
If you pour hazardous household waste in ditches, storm drains, or gutters, it can poison plants and wildlife, contaminate the soil, and harm children and adults who come in contact with it. When it rains, the hazardous household waste travels directly to nearby streams, rivers, and lakes.
Answer:
Buried in the garden – dangerous chemicals and poison can leach into the surface or groundwater. This can affect the soil, plants and water for a long time. ... It may also pollute waterways and drinking water if sent to normal landfills. Hazardous waste should only be stored in specially designed landfills.
Explanation:
putting it somewhere else is safer
BRAINLIEST?It takes a runner 320 s to travel a final position of +1000 m at a velocity of +2.5 m/s. What was the runner's initial position
Answers
The position of the runner up traveling at a velocity of +2.5 m/s is -200 m.
What is position?Position is the location of the object (whether it's a person, a ball, or a particle) at a given moment in time.
To calculate the initial position of the runner up, we use the fomula below.
Formula:
d = vt-D.......... Equation 1Where:
d = Initial position of the runner upv = Velocity of the runner upt = TimeD = Final position of the runner upFrom the question,
Given:
v = 2.5 m/st = 320 sD = 1000 mSubstitute these values into equation 1
d = (2.5×320)-1000d = 800-1000d = -200 mThe position of the runner up is -200 m.
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An object’s weight depends upon the ____ and the object’s mass.
Answers
Answer:
Gravity
Explanation:
Weight is dependent on the objects mass and the gravitational pull on it.
a 30 kg cart is travelling in a zero friction environment at a constant velocity of 5m/s. It's about to go up a very steep hill. How high will the cart be when the velocity changes to zero? PLEASE HELP
Answers
Answer:
1.27551m
Explanation:
This is a simple energy convertion problem. Since there is no friction, and assuming no air drag and other external factors, mechanical energy should be conserved in this system.
Thus, we get:
\(KE_{initial} + PE_{initial} = KE_{final} + PE_{final}\)
We also know that the gravitational potential energy is equal to mgh, while the KE can be calculated using \(\frac{1}{2}mv^2\)
One thing to note here, is that the final KE will be 0, as there is no velocity at the end. Furthermore, we also can set the initial PE as 0 as we are looking at relative height, and at the start it is at h=0.
\(KE_{initial} = PE_{final}\)
Plugging in:
\(\frac{1}{2}*30*5^2 = 30*9.8*h\)
Solving for h, we get 1.27551m
114 If V is a finite dimensional inner product space over C and T is a normal transformation on V, show that im(T) ker(T) = 0. Hence show that every generalised eigenvector of T is actually an eigenvector, thereby showing that T is diagonalisable.
Answers
If V is a finite-dimensional inner product space over C and T is a normal transformation on V. Then im(T) ker(T) = 0 and for every generalized eigenvector of T is actually an eigenvector, therefore T is diagonalizable.
The v be an element such that im(T) ∩ ker(T)
Since v ∈ im(T),
x in V such that T(x) = v
v ∈ ker(T), T(v) = 0
The inner product of v with itself,
⟨v, v⟩ = ⟨T(x), v⟩
The adjoint property of normal transformations,
⟨v, v⟩ = ⟨x, T(v)⟩
Since, T(v) = 0
⟨v, v⟩ = ⟨x, T(0)⟩ = ⟨x, 0⟩ = 0
Therefore, V must equal zero, since its inner product with itself is zero. Hence, im(T) ∩ ker(T) = {0}.
Suppose λ is an eigenvalue of T,
v is a generalized eigenvector corresponding to λ,
(T - λI)ˣ = 0 for some positive integer x,
and, I represent the identity transformation.
S = T - λI.
Applying S on both sides of the given equation:
S((T - λIˣ) = S(0)
(S(T - λI)ˣ) = 0
Since T is normal,
Therefore, S and (T - λI) commute:
((T - λI)ˣ)(S(v)) = 0
(T - λI)ˣ is a polynomial in T,
T is given as p(T),
p(T)(S(v)) = 0.
This shows that S(v) is a generalized eigenvector of T corresponding to eigenvalue 0.
If S(v) = 0, then,
T(v) = λv,
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of T
Hence, every generalized eigenvector of T is actually an eigenvector, showing that T is diagonalizable.
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Answer to 1, 2, and 3 please
Answers
Answer:
1. 1000000
2. 1000
3. 1000000
Explanation:
If there not right. I'm sorry.
i. What is the elasticity at point \( g \) ? ii. What is the elasticity at point \( h \) ? (As a first step, determine what the quantity is equal to at \( h \) )
Answers
i. The elasticity at point \( g \) is the measure of responsiveness or sensitivity of a quantity to changes in another variable at point \( g \).
ii. To determine the elasticity at point \( h \), we first need to establish what quantity we are referring to at point \( h \). Once we have identified the relevant quantity, we can then calculate its elasticity by measuring the responsiveness or sensitivity to changes in another variable at point \( h \).
i. To determine the elasticity at point \( g \), we need specific information about the variables and their relationship. Elasticity is typically calculated as the percentage change in one variable divided by the percentage change in another variable.
ii. Without additional information about the specific variables and their relationship at point \( h \), it is difficult to provide a precise answer. The concept of elasticity requires specific context and variables to be defined in order to calculate or describe it accurately.
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6. The speed of sound waves in air is 330 m/s. A sound wave has a frequency of 750 Hz.
a. What is its wavelength as it travels through air?
b. What is its period?
Answers
Answer:
Wavelength = 0.44 meter
Time period = 0.0013 seconds
Explanation:
Given:
Speed of sound = 330 m/s
Frequency = 750 Hz
Find:
Wavelength
Time period
Computation:
Wavelength = Velocity / Frequency
Wavelength = 330 / 750
Wavelength = 0.44 meter
Time period = 1 / Frequency
Time period = 1/750
Time period = 0.0013 seconds
Whatb19 ÷117= some help me with this
Answers
Answer:
0.16239316239316239316239
Explanation:
ang haba nang solve ko dito hehe
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In Video 2, you observed a "Frictionless Pendulum", the frictionless pendulum can only be simulated. Go back and see if you can observe any changes in motion. How would the motion of the pendulum change if that was a demonstration rather than a simulation? Use the CER (claim, evidence, reasoning) template to answer.
CLAIM: Write your answer to the question given: The motion of a real pendulum would ______________________ (describe how it would or would not change).
EVIDENCE: This is your example, model, observation, or idea demonstrating your claim, you could begin with “According to…” or “Based on...”, or "Watch how..."
REASONING: You could begin with, “This is because…” or “The fact that supports this evidence is…”. ONLY state science facts to support your example, do not guess, use opinion, or use inferences here.
Answers
Answer:
When the mass is drawn upwards and let go, the force of gravity accelerates it,
Explanation:
if you send me the video i can give you a better answer its just hard without seeing it