What type of plot can be used to visualize a one-way contingency table? Select one: O a. Histogram O b. Boxplot c. Side-by-side bar plot O d. Stacked bar plot O e. Bar plot

The price of the watch before the discount is calculated to be £24.44.

As the total price of the watch and a pair of trainers is £53. 55 and the price of the trainer before the discount was £38, we first calculate the price of the trainers after the discount as follows;

discount on a pair of trainers = 15/100 × 38 =  £5.7

cost of trainers after discount =  £38 - 5.7 =  £32.3

Now the price of the watch after the discount can be calculated by subtraction as follows;

price of watch after discount = total price - price of trainers after discount

price of watch after discount =  £53. 55 - £32.3

price of watch after discount = £21.25

Now the price of the watch before the discount can be calculated as follows;

price of watch before discount = £21.25 × 15/100

price of watch before discount = £21.25 + £3.1875

price of watch before discount = £24.44

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(a) No, a triangle cannot have two obtuse angles. (b) No, a triangle cannot have two right angles.
(c) If no angle of a triangle measures more than 60°, then the triangle is an acute triangle.


(a) In a triangle, the sum of all three angles must be 180°. Since two obtuse angles would sum to more than 180°, it is not possible for a triangle to have two obtuse angles.
(b) In a triangle, the sum of all three angles must be 180°. Since two right angles would sum to 180°, it is not possible for a triangle to have two right angles.
(c) In an acute triangle, all three angles are less than 90°. If no angle of a triangle measures more than 60°, then all three angles are less than 90°, making it an acute triangle.

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Answer:

39.50$

Step-by-step explanation:

You multiply 39.50 by .15, then you multiply that by 7

Answer:

Step-by-step explanation:

The function must be factorable.

For example, x^2 + x - 6= 0  factors to (x + 3)(x - 2) = 0 so the roots are -3 and 2.

x^2 + x - 7 = 0  will not factor so you need another method to solve this.

Answer:

oi 5. 16

Step-by-step explanation:

Answer:

5. 6a^2 + 10a

6. 21h^2 - 9h

Step-by-step explanation:

(2a*3a) + (2a*5) = 6a^2 + 10a

(-3h)*(-7h) + (-3h)*3 = 21h^2 - 9h

The set S = {(0, 0, 0), (3, 1, 4), (4, 5, 3)} is not a basis for the vector space R^3.

To determine if S is a basis for R^3, we need to check if the vectors in S are linearly independent and if they span R^3.

First, we check for linear independence. If the only solution to the equation c1(0, 0, 0) + c2(3, 1, 4) + c3(4, 5, 3) = (0, 0, 0) is c1 = c2 = c3 = 0, then the vectors are linearly independent. However, in this case, we can see that c1 = c2 = c3 = 0 is not the only solution. We can choose c1 = c2 = c3 = 1, and the equation still holds true. Therefore, the vectors in S are linearly dependent.

Since the vectors in S are linearly dependent, they cannot span R^3. A basis for R^3 must consist of linearly independent vectors that span the entire space. Therefore, S is not a basis for R^3.

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The unindent error in Python generally indicates that there is a problem with the code indentation.When you get this error, double-check the indentation of the code. The correct indentation format for Python code is four spaces.

This error message occurs in Python when there is an issue with the indentation of the code. This error message could be fixed by properly indenting the code to match the outer indentation level.Python is a high-level, object-oriented programming language used to build a variety of applications, including web applications, scientific computing, data analysis, artificial intelligence, and more. Python code can be written in an IDE (Integrated Development Environment) such as PyCharm, IDLE, and others.The syntax of Python is straightforward and easy to comprehend, but Python is a whitespace-sensitive language. The syntax of Python uses white space (tabs or spaces) to establish code blocks; therefore, proper indentation is critical. If the code isn't correctly indented, a syntax error occurs with an error message like "unindent does not match any outer indentation level."Make sure you use the proper amount of whitespace when indenting your code blocks to ensure that it runs correctly.In conclusion, this error message indicates that there is an issue with the indentation of the code. It could be fixed by appropriately indenting the code to match the outer indentation level.

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Ans .: The dimensions of the container that will minimize the cost are a base with sides of length 16.7 cm and a height of 8.35 cm.

To minimize the cost of the container, we need to find the dimensions that will use the least amount of material. Let's call the length of one side of the square base "x" and the height of the container "h".

The volume of the container is given as 2000 cm^3, so we can write:

V = x^2h = 2000

We need to find the dimensions that will minimize the cost, which is determined by the amount of material used. We know that it costs twice as much per square centimeter to make the top and bottom as it does the sides.

Let's call the cost per square centimeter of the sides "c", so the cost per square centimeter of the top and bottom is "2c". The total cost of the container can then be expressed as:

Cost = 2c(x^2) + 4(2c)(xh)

The first term represents the cost of the top and bottom, which is twice as much as the cost of the sides. The second term represents the cost of the four sides.

To minimize the cost, we can take the derivative of the cost function with respect to "x" and set it equal to zero:

dCost/dx = 4cx + 8ch = 0

Solving for "h", we get:

h = -0.5x

Substituting this into the volume equation, we get:

x^2(-0.5x) = 2000

Simplifying, we get:

x^3 = -4000

Taking the cube root of both sides, we get:

x = -16.7

Since we can't have a negative length, we take the absolute value of x and get:

x = 16.7 cm

Substituting this into the equation for "h", we get:

h = -0.5(16.7) = -8.35

Again, we can't have a negative height, so we take the absolute value of "h" and get:

h = 8.35 cm

Therefore, the dimensions of the container that will minimize the cost are a base with sides of length 16.7 cm and a height of 8.35 cm.

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Answer:

x = 10/3 or x = -16/3

Step-by-step explanation:

3x+3 = 13

3x =10

x = 10/3

3x+3 = -13

3x = -16

x = -16/3

480 Ways can the letters be arranged.

What is the meaning of probability ?

First letter can't be n or l

=   4! × \(5P_{3}\)

=    24 × 5! /3!

=     24 × 5 × 4

=         480

Therefore, 480 ways can the letters be arranged.

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Answer: 480 ways

Step-by-step explanation:

Answer:  Food is Food

Step-by-step explanation:

Answer:

The LCM of 25 and 200 is 200.

Explanation:

Find the prime factorisation of 25

25 = 5 × 5

Find the prime factorisation of 200

200 = 2 × 2 × 2 × 5 × 5

Multiply each factor the greater number of times it occurs in steps 1 or 2 above to find the LCM:

LCM = 2 × 2 × 2 × 5 × 5

LCM = 200

Answer:

the HCF of 25 and 200 is 25 because it divides both of them and is maximum factor of them.

LCM of 25 and 200 is 200 because it can be divided by both 200 and 25

Answer:

percent of students who have pet = 4/5 × 100%

= 4×20%

So, percent of students who have pet is 80%.

Answer:

Step-by-step explanation:

ISSA PARADE INSIDE MY CITY YEAHHHHH

Polynomials are algebraic expressions consisting of terms that include real numbers, variables, and positive integer exponents. Each term in a polynomial has a variable raised to a non-negative integer power, and the coefficient of each term is a real number. Polynomials are classified by the degree of their highest power. If two or more terms in a polynomial have the same variable raised to the same power, they can be combined into a single term.

1. -x² + x - x² + 1

Combine like terms: -x² + x - x² + 1 = -2x² + x + 1

This polynomial has degree 2 because the highest power of the variable is 2.

2. x² + x + 2x³ - x

Rearrange terms: 2x³ + x² + x - x = 2x³ + x²

This polynomial has degree 3 because the highest power of the variable is 3.

3. 4x + x + x - 2

Combine like terms: 4x + x + x - 2 = 6x - 2

This polynomial has degree 1 because the highest power of the variable is 1.

4. 3x² + 4 - 3x² - 1

Combine like terms: 3x² - 3x² + 4 - 1 = 3

This polynomial has degree 0 because there is no variable term.

Therefore, the four given polynomials have degrees 2, 3, 1, and 0, respectively.

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Answer:

x = 30°

Step-by-step explanation:

l₁ // l₂ and t is transversal. So, corresponding angles are congruent.

         3x - 10 = 2x + 20

Add 10 to both sides,

              3x  = 2x + 20 + 10

             3x  = 2x + 30

Subtract 2x from both sides,

       3x - 2x = 30

               x = 30°

The total cost before the sales tax was 19.828 pounds.

For a party, Jordan purchased 3.8 pounds of turkey, 2.2 pounds of cheese, and 3.6 pounds of egg salad.

We have to determine the total cost before sales tax.

As per the question, we have prices as:

cost of turkey = 3.95 per pound

cost of egg cheese = 1.3 per pound

cost of egg salad = 0.89 per pound

The total cost of turkey = 3.8 × 3.95  = 15.01 pounds

The total cost of cheese = 2.2 × 1.3 = 2.86 pounds

The total cost of egg salad = 2.2 × 0.89 = 1.958 pounds

The total cost before sales tax = 15.01 + 1.958 +2.86

Apply the addition operation, and we get

The total cost before sales tax = 19.828 pounds

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The question seems to be incomplete the correct question would be:

Jordan bought 3.8 pounds of turkey, 2.2 pounds of cheese, and 3.6 pounds of egg salad for a party. If prices are 3.95 per pound turkey, 1.3 per pound cheese and 0.89 per pound egg salad What was the total cost before sales tax?

The average shearing stress in the bolts is approximately 796 psi for the leftmost and rightmost bolts, and 177 psi for the middle bolt.

To determine the average shearing stress in the bolts, we need to first find the force acting on each bolt.

For the leftmost bolt, the force acting on it is the sum of the vertical shear forces on the left plank (which is 2500 lb) and the right plank (which is 0 lb since there is no load to the right of the right plank). So the force acting on the leftmost bolt is 2500 lb.

For the second bolt from the left, the force acting on it is the sum of the vertical shear forces on the left plank (which is 2500 lb) and the middle plank (which is also 2500 lb since the vertical shear force is constant along the beam). So the force acting on the second bolt from the left is 5000 lb.

For the third bolt from the left, the force acting on it is the sum of the vertical shear forces on the middle plank (which is 2500 lb) and the right plank (which is 0 lb). So the force acting on the third bolt from the left is 2500 lb.

We can now find the average shearing stress in each bolt by dividing the force acting on the bolt by the cross-sectional area of the bolt.

For the leftmost bolt:

Area = (π/4)(2 in)^2 = 3.14 in^2

Average shearing stress = 2500 lb / 3.14 in^2 = 795.87 psi

For the second bolt from the left:

Area = (π/4)(6 in)^2 = 28.27 in^2

Average shearing stress = 5000 lb / 28.27 in^2 = 176.99 psi

For the third bolt from the left:

Area = (π/4)(2 in)^2 = 3.14 in^2

Average shearing stress = 2500 lb / 3.14 in^2 = 795.87 psi

Therefore, the average shearing stress in the bolts is approximately 796 psi for the leftmost and rightmost bolts, and 177 psi for the middle bolt.

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Answer:

69.08 yd

Step-by-step explanation:

22 times 3.14 = 69.08 yd

Answer:

Apx 7.79$

Step-by-step explanation:

Please brainliest

The area bounded by f(x) =sin x + 1 is 2 + π on the interval [0,pi]

What is a interval?

Given that:

x-axis on the interval [0,pi]

f(x) = sin x + 1

     = integral 0 - integral π (sin x) dx + integral 0 - integral π (1) dx

     = [- cos π + cos 0] + [π - 0]

     = [-(-1) + 1 ] + π

     = 2 + π

Therefore, the area bounded by f(x) =sin x + 1 is 2 + π on the interval [0,π]

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Answer:

x = 62

Step-by-step explanation:

the angle between a tangent and the radius at the point of contact = 90°

then Δ PTO is right

the sum of the 3 angles in the triangle = 180° , so

x = 180 - 90 - 28 = 180 - 118 = 62

Answer:

Step-by-step explanation:

TP is a tangent to the circle at centre O

means

TP is perpendicular to TO

Then

m∠OTP = 90°

Then

OTP is a right triangle

Then

x = 90 - 28

  = 62

The roots of a polynomial are the values of x for which the polynomial evaluates to 0.

A complex root is a root for which the real and imaginary parts are not both 0. If a polynomial has a complex root, that means that there is at least one value of x for which the polynomial evaluates to 0.

This can happen in two ways: either the polynomial has a real root and an imaginary root, or it has two complex roots. In either case, the complex roots must be found in order to determine the polynomial's factorization.

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If the three numbers of a square in the complex plane are \(-19+32i,-5+12i and -22+15i\) , then the fourth complex number \(-2+19i\).

Given \(-19+32i,-5+12i and -22+15i\) are three numbers.

Complex numbers are those numbers which extends the real numbers with an imaginary i. In this \(i^{2}=-1\). Major complex numbers are in the form a+ bi where a and b are real numbers.

let the fourth complex numbers be \(x+yi\). Then according to question;

=\((-22+15i)-(-5+12i)\)

=(cos π/2+i sin π/2) \((x+yi)-(-5+12i)\)

\(-17+3i=-y+12\)\(+(x+5)i\)

Now solving for x and y by equating both sides.

x=-2 and y=29

Put the value of x and y in \(x+yi\)

Z=-2+29i

Hence if the three numbers which forms vertices of a square are \(-19+32i,-5+12i,-22+25i\) then the fourth complex numbers be \(-2+29i\).

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To find theta to the nearest tenth of a degree, we can use a calculator to find the inverse of the given trigonometric function. The inverse of a trigonometric function is denoted by a "-1" superscript.

For the first question, we have cos theta = 0.2442 with theta in QI. To find theta, we can use the inverse cosine function:
theta = cos^-1(0.2442) ≈ 75.7°

For the second question, we have cos theta = -0.7750 with theta in QII. To find theta, we can use the inverse cosine function:
theta = cos^-1(-0.7750) ≈ 139.2°
Since theta is in QII, we can subtract this angle from 180° to find the angle in QII:
theta = 180° - 139.2° ≈ 40.8°

For the third question, we have tan theta = 0.5860 with theta in QIII. To find theta, we can use the inverse tangent function:
theta = tan^-1(0.5860) ≈ 30.4°
Since theta is in QIII, we can add 180° to this angle to find the angle in QIII:
theta = 180° + 30.4° ≈ 210.4°

For the fourth question, we have cos theta = 0.2442 with theta in QI. This is the same as the first question, so the answer is the same:
theta = cos^-1(0.2442) ≈ 75.7°

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In terms of relative growth rate Exponential growth is characterized by a constant relative growth rate.

Exponential growth is the process of increasing quantity over time. Occurs when the instantaneous rate of change of a quantity over time is proportional to the quantity itself. The exponential growth model has the form

y (t) = C eᵏᵗ, where k is the rate constant.

Relative Growth Rate:Relative growth rate (RGR) is the rate of growth relative to size. That is, the rate of growth per unit time relative to the size at that point in time and y'(t)/y(t) is the relative growth rate of a function y at time t.

1/y dy/dt = 1/y d(C eᵏᵗ)/dt

= 1/y(kC eᵏᵗ)

= 1/y ( ky) ( since, y (t) = C eᵏᵗ)

= k

Therefore a constant relative growth rate.

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Complete question:

In terms of relative growth rate, what is the defining property of exponential growth? Choose the correct answer below.

A. The relative growth rate at time t is the slope of the exponential function at time t.

B. dy dt If y represents a population, then the relative growth rate can be represented by dy/dt

C. The relative growth rate is proportional to the size of the population

D. The relative growth rate is constant.

The degree 3 Taylor polynomial T3(x) for the function f(x) = \((-7x + 270)^{(5/4)\) at a = 2 is:

T3(x) = 32 - 7(x - 2) - (49/512\()(x - 2)^2\) + (-147/4194304)\((x - 2)^3\)

To find the degree 3 Taylor polynomial, we need to calculate the polynomial approximation of the function up to the third degree centered at the point a = 2. We can find the Taylor polynomial by evaluating the function and its derivatives at a = 2.

First, let's find the derivatives of the function f(x) = \((-7x + 270)^{(5/4)\):

f'(x) = \((-7/4)(-7x + 270)^{(1/4)\)

f''(x) = \((-7/4)(1/4)(-7x + 270)^{(-3/4)}(-7)\)

f'''(x) = \((-7/4)(1/4)(-3/4)(-7x + 270)^{(-7/4)}(-7)\)

Now, let's evaluate these derivatives at a = 2:

f(2) = \((-7(2) + 270)^{(5/4)\)

     = \((256)^{(5/4)\)

     = 32

f'(2) = \((-7/4)(-7(2) + 270)^{(1/4)\)

      = \((-7/4)(256)^{(1/4)\)

      = \((-7/4)(4)\)

      = -7

f''(2) = \((-7/4)(1/4)(-7(2) + 270)^{(-3/4)}(-7)\)

       = \((-7/4)(1/4)(256)^{(-3/4)}(-7)\)

       = (7/16)(1/256)(-7)

       = -49/512

f'''(2) = \((-7/4)(1/4)(-3/4)(-7(2) + 270)^{(-7/4)}(-7)\)

       = \((-7/4)(1/4)(-3/4)(256)^{(-7/4)}(-7)\)

       = (21/256)(1/16384)(-7)

       = -147/4194304

Now, let's write the degree 3 Taylor polynomial T3(x) using the above derivatives:

T3(x) = f(2) + f'(2)(x - 2) + f''(2)\((x - 2)^2\)/2! + f'''(2)\((x - 2)^3\)/3!

Substituting the values we calculated:

T3(x) = 32 - 7(x - 2) - (49/512)\((x - 2)^2\) + (-147/4194304)\((x - 2)^3\)

So, the degree 3 Taylor polynomial T3(x) for the function f(x) = \((-7x + 270)^{(5/4)\) at a = 2 is:

T3(x) = 32 - 7(x - 2) - (49/512)\((x - 2)^2\) + (-147/4194304)\((x - 2)^3\)

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Step-by-step explanation:

y-b=m(x-a)

y-10=-4(x--2)

y-10=-4(x+2)

y-10= -4x-8

y= -4x+2

Answer:

option (4)

Step-by-step explanation:

y = - 2x +7 → (1)

y = 4x - 5 → (2)

substitute y = 4x - 5 into (1)

4x - 5 = - 2x + 7 ( add 2x to both sides )

6x - 5 = 7 ( add 5 to both sides )

6x = 12 ( divide both sides by 6 )

x = 2

substitute x = 2 into either of the 2 equations and solve for y

substituting into (2)

y = 4(2) - 5 = 8 - 5 = 3

solution is (2, 3 )

\(\red{\boxed{ \green{\sf Option \: 4: (2 \: , 3)}}}\)

\( \\ \)

\( \sf First, \: we \: have \: to \: understand \: that: \\ \sf If \: \red{y} = \orange{a} \: and \: \red{y} = \blue{b}, \: then \: \orange{a} = \blue{b}.\)

\( \\ \)

\(\sf Let \: \orange{-2x+7} \: be \: \orange{a} \: and \: \blue{4x-5 \\ } \: be \: \blue{b}.\)

\(\star \: \sf Solve \: the \: equation \: \orange{a} = \blue{b}. \: \star\)

\( \\ \)

\( \sf \orange{a} = \blue{b} \\ \Longleftrightarrow \sf \orange{ - 2x + 7} = \blue{4x - 5} \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \diamond \: \sf Subtract \: 4x \: from \: both \: sides. \diamond \\ \\ \Longleftrightarrow \sf - 6x + 7 = - 5 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \diamond \: \sf Subtract \: 7 \: from \: both \: sides. \diamond \\ \\ \Longleftrightarrow \sf - 6x = - 12 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \diamond \: \sf Divide \: both \: sides \: by \: -6. \: \diamond \\ \\ \Longleftrightarrow \sf x = \dfrac{ - 12}{ - 6} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \Longleftrightarrow \boxed{\sf \purple{x = 2}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \)

\( \\ \)

\(\star \: \sf Remplace \: \purple{x} \: with \: \purple{2} \: in \: one \: of \: the \: given \: equations. \: \star\)

\( \\ \)

\( \sf \red{y }= - 2 \purple{x} + 7 \\ \implies \sf \red{y} = - 2 \purple{(2)} + 7 \: \: \: \: \: \: \\ \\ \implies \boxed{\sf \red{y= 3}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \)

\( \\ \)

Therefore, the point which is a solution to the system of equations is (2 , 3). This corresponds to option 4.