What characterizes static stretching? A. having a partner hold limbs in a stretch position B. assuming and holding a stretch position C. bouncing while in a stretch position D. using a tool or object to increase a stretch Please select the best answer from the choices provided. A B C D

The distance travelled by Arthur is 7 km and his displacement is 5 km.

The distance travelled by Arthur during the entire motion is determined by summing the entire path covered during the motion.

Distance = 3 km + 4 km

Distance = 7 km

The displacement of Arthur during the entire motion is obtained by calculating the length of the shortest path between the initial and final position.

d = √(a² + b)

where;

d = √(3² + 4²)

d = 5 km

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A star will become a white dwarf when its nuclear fuel is finished because of no more emission of heat and light.

When the end of the nuclear burning stage of a star comes, such a star expels most of its outer material creating a planetary nebula until only the hot core remains. When this core settles down, it will become a young white dwarf.

So we can conclude that a star will become a white dwarf when its nuclear fuel is finished because of no more emission of heat and light.

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Answer:

is this a check all that apply or a single answer?

Temperature is a measure of the average kinetic energy  energy of particles in a substance.

Temperature and kinetic energy have a directly proportional relationship.

Kelvin, Celsius, and Fahrenheit are three types of Temperature scales.

The average kinetic energy of the particles in a substance is measured by temperature. The overall kinetic energy of the particles in a substance is measured by its thermal energy. The temperature and thermal energy of a substance increase with particle mobility.

The average kinetic energy of a substance's particles is directly proportional to the substance's temperature.

The three temperature scales that are now in use are Kelvin, Celsius, and Fahrenheit.

Typically, calories or joules per gramme per degree Celsius are used as the units of specific heat. For instance, water has a specific heat of 1 calorie (or 4.186 joules) per gramme per degree Celsius.

Temperature is a measurement of that energy in substances, whereas kinetic energy is the energy of motion.

Temperature is a measurement of that energy in substances, whereas kinetic energy is the energy of motion. According to Zoe, a material has a temperature of 12 degrees Celsius. What does this indicate to Zoe regarding the substance? It has an average kinetic energy of 12 Celsius.

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Temperature is a measure of the average kinetic energy  energy of particles in a substance.

Temperature and kinetic energy have a directly proportional relationship.

Kelvin, Celsius, and Fahrenheit are three types of Temperature scales.

The average kinetic energy of the particles in a substance is measured by temperature. The overall kinetic energy of the particles in a substance is measured by its thermal energy. The temperature and thermal energy of a substance increase with particle mobility.

The average kinetic energy of a substance's particles is directly proportional to the substance's temperature.

The three temperature scales that are now in use are Kelvin, Celsius, and Fahrenheit.

Typically, calories or joules per gramme per degree Celsius are used as the units of specific heat. For instance, water has a specific heat of 1 calorie (or 4.186 joules) per gramme per degree Celsius.

Temperature is a measurement of that energy in substances, whereas kinetic energy is the energy of motion.

Temperature is a measurement of that energy in substances, whereas kinetic energy is the energy of motion. According to Zoe, a material has a temperature of 12 degrees Celsius. What does this indicate to Zoe regarding the substance? It has an average kinetic energy of 12 Celsius.

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Answer:

The answer is D.

Explanation:

Answer:

4.  wavelength (λ)

5.  slit distance (d)

Explanation:

I assume you did a double-slit experiment?  If so, then:

The number of bands observed on the screen depends on the wavelength (λ) and the slit distance (d), while the screen distance (L) does not directly affect the number of bands.

Wavelength (λ): The number of bands is directly proportional to the wavelength. When the wavelength increases, the fringe separation on the screen increases, resulting in a greater number of bands.

Slit distance (d): The number of bands is inversely proportional to the slit spacing (distance). When the slit spacing increases, the fringe separation on the screen decreases, resulting in a smaller number of bands.

Screen distance (L): The screen distance does not directly affect the number of bands. It primarily affects the size and overall pattern of the interference fringes but does not change the number of bands.

Summary:

Wavelength (λ) is directly proportional to the number of bands.

Slit distance (d) is inversely proportional to the number of bands.

Screen distance (L) does not directly affect the number of bands.

This same statement expresses the fact that to the furthest item is 80 cm distant.

The combination of objects known as an object class may be characterised in by the traits that all of its members share. So all e-mail systems get some characteristics, generic e-mail, for instance, may be an object class.

The left item has travelled about 1/4 of the distance contrasted to the centre object, which means that if the centre object were to be pushed half as far as the right object, it would be pretty far away (20 cm). Consequently, add 4 to the centre object's distance.

It is 80 cm distant from the furthest item.

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The complete question is-

If the nearest object is 10 cm from the observer, approximately how far away is the farthest object?

________cm

Answer:

36 Newtons

Explanation:

The force of attraction or repulsion between two charges can be given by Coulomb's Law:

\(F = \frac{kq_1q_2}{r^2}\)

where,

F = Force

k = Coulomb's Constant

q₁ = magnitude of first charge

q₂ = magnitude of second charge

r = distance between charges

Hence, the charges with opposite signs will produce a result with a negative value. While, the charges with same sign will produce positive result of force value.

Hence, the force between two charges with the same sign will be 36 Newtons

Satellite mass is 1.69 x 10²² kg; Distance to Corus is 6,760 km; Gravitational acceleration is 3.77 m/s²; Gravitational force is 1.26 x 10¹⁰ N; Minimum orbit speed is 3.25 km/s.

To estimate the mass of the satellite, we can use the formula for the period of a satellite's orbit, which is given by \(T=2\pi \sqrt(r^{3} /GM)\), where T is the period, r is the distance between the satellite and the center of Corus, G is the gravitational constant, and M is the mass of Corus.

We know that the period of the satellite is 15 Earth days, which is approximately 1.296 x 106 seconds. We also know that the distance between Corus and the satellite is the sum of the radius of Corus and the altitude of the satellite.

Assuming the altitude of the satellite is 500 km, which is similar to the altitude of the International Space Station, we can estimate the distance to be 6,760 km.

To calculate the satellite's mass, we can rearrange the formula to solve for M, which gives \(M=(4\pi ^{2} r^{3} )/(GT^{2} )\). Substituting the known values, we get M = 1.69 x 1022 kg.

Using the formula for gravitational acceleration,\(g = G (M/r^{2} )\), we can calculate the gravitational acceleration towards the core of Corus. Substituting the known values, we get g=3.77 m/s².

To calculate the gravitational force between the satellite and Corus, we can use the formula for gravitational force, \(F=G(Mm/r^{2} )\) , where m is the mass of the satellite. Substituting the known values, we get F = 1.26 x 1010 N.

Finally, to calculate the minimum speed of the satellite to orbit Corus, we can use the formula for circular velocity, \(v=\sqrt(GM/r)\). Substituting the known values, we get v = 3.25 km/s.

In summary, a suitable mass for the satellite is approximately 1.69 x 1022 kg, the distance between the satellite and Corus's surface is approximately 6,760 km, the gravitational acceleration towards the core of Corus is approximately 3.77 m/s².

The gravitational force between the satellite and Corus is approximately 1.26 x 1010 N, and the minimum speed of the satellite to orbit Corus is approximately 3.25 km/s.

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Complete Question:

A new planet called "Corus" was discovered by a team of astronomers that is 60 x 106 km away from Earth: A satellite was launched by a rocket from Earth to reach Corus. At a specific distance from Corus, the rocket releases the satellite to the orbit of the planet The satellite makes one complete revolution around Corus in 15 Earth days. If Corus has a similar mass to Mars, propose a suitable mass of the satellite and estimate:

i. Distance between the satellite and the Corus's surface

ii. Satellite's gravitational acceleration towards the core of Corus

iii. Gravitational force between the satellite and the Corus

iv. Minimum speed of the satellite to orbit Corus

Answer:

You dont need BRAINLY there is an app called slader where you scan the textbook barcode and it shows you the answers for the question in the textbook.

Explanation:

The new volume of the balloon when heated to 48.0°C is approximately 1.95 L (option a).

To calculate the new volume of the balloon when it is heated, we can use the formula derived from Charles's Law, which states that for a given amount of gas at constant pressure, the volume is directly proportional to its temperature in Kelvin.

The formula is V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

First, we need to convert the temperatures from Celsius to Kelvin:

T1 = 24.0°C + 273.15 = 297.15 K
T2 = 48.0°C + 273.15 = 321.15 K

Now, we can plug in the values into the formula:

V1 = 1.80 L (given)
T1 = 297.15 K
T2 = 321.15 K

1.80 L / 297.15 K = V2 / 321.15 K

Solving for V2, we get:

V2 = (1.80 L * 321.15 K) / 297.15 K
V2 ≈ 1.95 L

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Answer:

Average speed = 13.5 m/s

Explanation:

Since the car is running at a speed of 27 m/s  and it stops after 3 seconds by applying the brake. Therefore, the initial speed of the 27 m/s and final speed is 0.

Use below formula to find the average speed :

Average speed = (Initial speed + final speed ) / 2  

Average speed = (27 + 0 ) / 2

Average speed = 13.5 m/s

Answer:

v = 14.32 m/s

Explanation:

According to the principle of conservation of linear momentum, both the momentum and kinetic energy of the system are conserved. Since the two balls are in the same direction of motion before collision, then;

\(m_{1} u_{1}\) + \(m_{2} u_{2}\) = (\(m_{1}\) + \(m_{2}\)) v

0.035 × 12 + 0.120 × 15 = (0.035 + 0.120) v

0.420 + 1.800 = (0.155) v

2.22 = 0.155 v

⇒ v = \(\frac{2.22}{0.155}\)

      = 14.323

The velocity of the balls after collision is 14.32 m/s.

The compound formed from aluminum and hydroxide is aluminum hydroxide. Its chemical formula is Al(OH)3.

Aluminum has a charge of +3, and the hydroxide ion (OH-) has a charge of -1. To balance the charges and create a neutral compound, three hydroxide ions are needed for every aluminum ion. Hence, the formula is Al(OH)3.

The formation of aluminum hydroxide is an example of a precipitation reaction, where two substances combine to form a solid that is insoluble in water. This reaction is important in chemistry and can be used to isolate and purify specific compounds or ions from a solution.

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In the Hubble Extreme Deep Field, the galaxies seen in the earliest (youngest) stages of their lives are typically the small, faint, and irregularly shaped galaxies.

The Hubble Extreme Deep Field is an image captured by the Hubble Space Telescope that shows a small, seemingly empty patch of sky that contains thousands of galaxies. These galaxies vary greatly in size, shape, and color, and they are located at different distances from us.

Some of these galaxies are very young, while others are much older. However, in general, the galaxies that are seen in the earliest (youngest) stages of their lives tend to be small, faint, and irregularly shaped. This is because they are still in the process of forming and have not yet had the chance to merge with other galaxies or grow in size.
In conclusion, the small, faint, and irregularly shaped galaxies are the ones that are typically seen in the earliest (youngest) stages of their lives in the Hubble Extreme Deep Field. As these galaxies evolve and grow, they may become more structured and take on different shapes and sizes.

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The time period for the given question would be 1/40 seconds.

Determining time period:

The frequency is 40 Hz. To find the period, t, we can use the formula: T = 1/f where T is the period and f is the frequency. Therefore, T = 1/40 seconds. An explanation is given below with the terms such as period, harmonic oscillations, amplitude, and wave.

What is the time period?

A time period is defined as the time that a wave takes to complete one full cycle of harmonic oscillations. It is the reciprocal of the frequency. The time period is a measure of time taken by a wave to complete one cycle of its motion. The amplitude of a wave is the maximum displacement of the wave from its equilibrium position. It is a measure of the strength of the wave.

What is a wave?

The wave is a disturbance that transfers energy through a medium. Waves are characterized by their frequency, wavelength, and amplitude. Harmonic oscillations are the regular and repeated motion of a system about its equilibrium position. They are periodic motions in which the system moves back and forth with a fixed frequency and amplitude.

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The motion of the bus during the 70 seconds shown on the graph includes an initial acceleration, followed by periods of steady speed and deceleration.

Based on the given velocity-time graph, the motion of the bus during the 70 seconds can be described as follows. Initially, the bus is at rest, indicated by the velocity of 0 m/s at the start of the time period. As time progresses from 0 to 10 seconds, the velocity increases steadily, reaching 20 m/s. This indicates that the bus is accelerating and gaining speed. From 10 to 20 seconds, the velocity decreases from 20 m/s to 15 m/s. This implies that the bus is decelerating, but it is still moving forward. During this time, the bus is slowing down but not coming to a complete stop. Between 20 and 40 seconds, the velocity remains constant at 15 m/s. This suggests that the bus is traveling at a steady speed without any acceleration or deceleration. It is maintaining a uniform velocity during this time period.From 40 to 50 seconds, the velocity decreases further to 10 m/s, indicating that the bus is decelerating again. This means the bus is slowing down once more. Finally, from 50 to 70 seconds, the velocity remains constant at 10 m/s, suggesting that the bus is traveling at a steady speed again.

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Explanation:

Power = work / time

Power = force × distance / time

P = (650 kg) (10 m/s²) (20 m) / (15 s)

P = 8667 W

Answer:

8000 J

Explanation:

There is a Quizlet made by a teacher with this answer.

This experiment help us understand their behavior as well as how the people will cop up with the rules and regulation the society wants to apply on them

In a two-week simulation of a prison setting, the Stanford prison experiment was meant to look at the impact of situational factors on participants' responses and behaviors.

Hence, this experiment allows us to better understand their behavior, as well as how individuals will respond to the laws and regulations imposed by society.

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Positive acceleration speeds the object up. Negative acceleration, aka deceleration, slows the object down. Zero acceleration means the object either keeps the same speed or isn't moving at all (we can say the speed is 0).

When an object speeds up, the positive acceleration occurs.

The acceleration is the time rate of change of velocity.

a = dv /dt

If the velocity is increased, the acceleration also increases, time remains same to cover a fixed distance.
Speeding up the object means positive acceleration.  Negative acceleration also called deceleration slows the speed. Zero acceleration represents that the object is moving with constant velocity.

Thus, the positive acceleration occurs.

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The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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Water: The motion of the water molecules initially decreased when the ice cubes were added to the water bottle, which caused the water to become cold.

As time passed during the hike, the motion of the water molecules may have increased due to exposure to higher temperatures and agitation during transport.

Ice: The ice cubes initially had a low motion of molecules due to being frozen solid. As time passed during the hike and the ice cubes were exposed to higher temperatures, their molecules began to gain more motion, causing the ice to melt.

Beans: The motion of the molecules in the beans increased as the pot was placed over the fire and heated. This caused the beans to become hot and cooked.

Hot dog: The motion of the molecules in the hot dog increased as it was heated over the fire. This caused the hot dog to become hot and cooked.

Lastly, Hot Chocolate: The motion of the molecules in the hot chocolate initially decreased as it cooled to room temperature. When Carly drank the cold hot chocolate, the motion of the molecules in her mouth may have increased due to the temperature difference, providing a warming sensation.

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Answer:

37.5 seconds

Explanation:

The given parameters are;

The mass of the block on the spring, m = 2.50 kg

The force with which the loaded spring launches the block, F = 450 N

The change in momentum of the block, Δp = 12.0 kg·m/s

We have;

Let the force with which the block was launched = The net force, \(F_{NET}\)

By Newton's second law of motion, we have;

F = \(F_{NET}\) = Δp × Δt

Where;

Δt = The time the block is in contact with the spring

Therefore;

\(\Delta t = \dfrac{F_{NET}}{\Delta p}\)

By plugging in the values for \(F_{NET}\) and Δp, we have;

\(\Delta t = \dfrac{450 \ N}{12.0 \ kg \cdot m/s} = 37.5 \ s\)

The time duration the block is in contact with the spring, Δt = 37.5 seconds.

Answer:

V = 61.74m/s

Explanation:

Given the following data;

Acceleration due to gravity = 9.8m/s²

Time, t = 6.3 secs

Since it's a free fall, initial velocity = 0

Thus, to find the final velocity, we would use the first equation of motion;

\( V = U + at\)

Substituting into the equation, we have;

\( V = 0 + 9.8 * 6.3\)

V = 61.74m/s

Therefore, the final velocity is 61.74m/s

Answer:

angle of refraction is the same as angle of incidence

Explanation:

Answer:

The angle of reflection is 180 degrees because if you mapped it on a coordinate plane, both the real object and the image in the mirror will be on opposite sides.

The magnitude of the largest force p that can be applied to the 42 kg cart without causing one of the wheel reactions to be zero is approximately 13.8 kg·m/s².

The equilibrium circumstances of the 42 kg cart must be considered to find the greatest force p that can be applied without zeroing one of the wheel reactions at point A or point B. Let's find the greatest force p at point C. Maintaining cart balance prevents one wheel reaction from approaching zero. The cart's forces and moments must equal zero.

Considering the forces, we have:

Sum of vertical forces: N - mg = 0, where N is the normal force and mg is the weight of the cart.

N = mg

Now, considering the moments about point A:

Clockwise moment: (mg)(d) + (p)(D) = 0, where d is the distance from point A to the center of gravity of the cart and D is the distance from point A to point C.

Counterclockwise moment: Rb(b) = 0, where Rb is the reaction force at point B and b is the distance from point A to point B.

Since we want to prevent either Ra or Rb from becoming zero, we need to consider the worst-case scenario. In this case, we assume that Ra is at its minimum value and Rb is at its maximum value. This occurs when the cart is on the verge of tipping over.

To prevent tipping, the counterclockwise moment must be greater than or equal to the clockwise moment:

Rb(b) ≥ (mg)(d) + (p)(D)

Simplifying and substituting N = mg, we get:

Rb ≥ mg(b/d) + p(D/d)

To prevent Rb from becoming zero, we need to set the inequality as an equality: Rb = mg(b/d) + p(D/d)

Now, we substitute the values provided in the problem: m = 42 kg, g = 9.8 m/s², b = 0.5 m, d = 1 m, and D = 1.5 m.

Rb = (42 kg)(9.8 m/s²)(0.5 m / 1 m) + p(1.5 m / 1 m)

Simplifying:

Rb = 20.7 kg·m/s² + 1.5p

Since we want to find the maximum value of p, we want Rb to be as large as possible without becoming zero. Therefore, we set Rb equal to zero: 20.7 kg·m/s² + 1.5p = 0

Solving for p: p = -13.8 kg·m/s²

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Complete Question :-  

A.) Determine The Magnitude Of The Largest Force P That Can Be Applied To The 42-kg Cart, Without Causing One Of The Wheel Reactions, Either At A Or At B, To Be Zero. B.) What Is The Acceleration Of The Cart? The Center Of Mass Is At G.

Atlantic Ocean (salt water)

A magnet that is positively charged on one end and negatively charged on the other end is an example of D. polarity.

In the field of science, polarity can be described as a phenomenon in which the same substance has different charges in it. The electrical charges are separated inside the same substance or molecule as a result of polarity.

One part of a substance will be negative charges whereas the other will be positively charged as a result of polarity.

A magnet is an example of a substance that can easily gain or lose polarity. When the charges inside a molecule are separate at both ends, we will say that the magnet has gained polarity.

Although a part of your question is missing, you might be referring to this question:

A magnet that is positively charged on one end and negatively charged on the other end is an example of

A cohesion.

B adhesion.

C gravity.

D polarity.

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