what are equivalent fractions 1 2/3 1 2/3

The current weight of the truck is given as follows:

3496 kg.

The current weight of the truck is obtained applying the proportions in the context of the problem.

The initial weight of the truck is given as follows:

3796 kg.

The weight removed from the truck is given as follows:

6 x 50 = 300 kg.

Hence the current weight of the truck is given as follows:

3796 - 300 = 3496 kg.

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Answer: In order: 25, 15, 67.

Step-by-step explanation:

In picture

(a) Clicks Width of Door (inches)

1 3.3

2 3.63

3 3.99

4 4.39
(b) The function is y = 3  (1.1)ˣ.

(c) It would take about 15 clicks of the zoom-in button to make the door approximately 3 feet wide on the screen.

(d) It would take about 12 clicks of the zoom-out button to transform the display of the door from 3 feet wide back to a width of approximately 3 inches.

(a)

Clicks Width of Door (inches)

1 3.3

2 3.63

3 3.99

4 4.39

(b) Let x be the number of clicks and y be the width of the door on the screen. Then, we can write the algebraic rule as:

y = 3  (1.1)ˣ

(c) To make the door approximately 3 feet wide on screen, we need to convert 3 feet to inches, which is 36 inches. Then, we need to solve for x in the equation:

3 (1.1)ˣ = 36

Dividing both sides by 3, we get:

(1.1)ˣ = 12

Taking the logarithm of both sides (with base 1.1), we get:

x = log(12) / log(1.1) ≈ 14.7

So, it would take about 15 clicks of the zoom-in button to make the door approximately 3 feet wide on the screen.

(d) To transform the display of the door from 3 feet wide back to a width of approximately 3 inches, we need to find the number of clicks of the zoom-out button that will result in a width of approximately 3 inches. We can use the same formula as before, but with the initial width of 36 inches (since we are zooming out):

36 (0.9)ˣ = 3

Dividing both sides by 36, we get:

(0.9)ˣ = 1/12

Taking the logarithm of both sides (with base 0.9), we get:

x = log(1/12) / log(0.9) ≈ 11.5

So, it would take about 12 clicks of the zoom-out button to transform the display of the door from 3 feet wide back to a width of approximately 3 inches.

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Answer: 18.1666666667

Step-by-step explanation:

A set of numbers that can represent the side lengths, in centimeters, of a right triangle is any set that satisfies the Pythagorean theorem, where the square of the hypotenuse's length is equal to the sum of the squares of the other two sides.

A right triangle is a type of triangle that contains a 90-degree angle. According to the Pythagorean theorem, in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Let's consider a set of numbers that could represent the side lengths of a right triangle in centimeters.

One possible set could be 3 cm, 4 cm, and 5 cm.

To verify if this set forms a right triangle, we can apply the Pythagorean theorem.

Squaring the length of the shortest side, 3 cm, gives us 9. Squaring the length of the other side, 4 cm, gives us 16.

Adding these two values together gives us 25.

Finally, squaring the length of the hypotenuse, 5 cm, also gives us 25. Since both values are equal, this set of side lengths satisfies the Pythagorean theorem, and hence forms a right triangle.

It's worth mentioning that the set of side lengths forming a right triangle is not limited to just 3 cm, 4 cm, and 5 cm.

There are infinitely many such sets that can be generated by using different combinations of positive integers that satisfy the Pythagorean theorem.

These sets are known as Pythagorean triples.

Some other examples include 5 cm, 12 cm, and 13 cm, or 8 cm, 15 cm, and 17 cm.

In summary, a right triangle can have various sets of side lengths in centimeters, as long as they satisfy the Pythagorean theorem, where the square of the hypotenuse's length is equal to the sum of the squares of the other two sides.

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1) Number of participants whose headache remained is: 62

2) The probability of randomly selecting an individual whose headache remained is: 0.4133

3) The probability of randomly selecting an individual whose headache remained and took a placebo is: 0.2933

From the table, we have the parameters as:

Number of participants that took medicine and headache went away = 120

Number of participants that took placebo and headache went away = 68

Number of participants that took and headache remained = 18

Number of participants that took placebo and headache remained = 44

1) Number of participants whose headache remained = 18 + 44 = 62

2) The probability of randomly selecting an individual whose headache remained is:

62/(62 + 120 + 68)

= 62/150

= 0.4133

3) The probability of randomly selecting an individual whose headache remained and took a placebo is:

44/150 = 0.2933

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Answer:

Step-by-step explanation:

Step 1 is incorrect. It should be:

Correct answer option is B

its congruent by HL or RHSaxiom

Answer:

HL

Step-by-step explanation:

\( In\: right \triangle 's DAB \: \&\: CBA\\

\angle DAB \cong \angle CBA... (each 90\degree) \\ hypotenuse \: DB \cong hypotenuse \: CA. (given) \\

side AB \cong side BA.. (common) \\

\therefore \triangle DAB \cong \triangle CBA.. (By \: RHS\: or \: HL \: Postulate) \)

Answer: 924

Step-by-step explanation:

1. Use the combination formula nCr = n!/(n-r)!r!

Using this formula gets you 16 (n) C 6 (r) = 12!/6!6! Which is also 12 • 11 • 10 • 9 • 8 • 7 • 6 • 5 • 4 • 3 • 2 • 1 / 6 • 5 • 4 • 3 • 2 • 1 • 6 • 5 • 4 • 3 • 2 • 1

2. Cancel out matching multiples that are in the numerator and denominator

This gets you 12 • 11 • 10 • 9 • 8 • 7 / 6 • 5 • 4 • 3 • 2 • 1 or 665280/720 when you simplify which leads you to the answer 924

Hope this helps!

Answer:

924

Step-by-step explanation:

Answer:

 \(\mu_{x} = 0.8\)

   \(\sigma  =  0.095  \)  

  The shape of this sampling distribution is approximately normal

Step-by-step explanation:

From the question we are told that

  The population proportion is \(p = 0.8\)

  The sample size is  n = 100

Generally the expected value of this sampling distribution is mathematically represented as

          \(\mu_{x} = p = 0.8\)

Generally the standard deviation of this sampling distribution is mathematically represented as

    \(\sigma  =  \sqrt{ \frac{p(1- p )}{n } } \)

=>  \(\sigma  =  \sqrt{ \frac{0.8 (1- 0.8 )}{100 } } \)    

=>  \(\sigma  =  0.095  \)      

Generally given that the sample is  large (i.e  n  >  30 ) and the standard deviation is finite then the shape of this sampling distribution is approximately normal

The statement is False.

If the equation of the regression line that relates hours per week spent in the lab, x, to GPA, y, is

y = 2.1 + 0.28x

If a student never goes to the lab (x=0), then the best prediction for their GPA would be y = 2.1 + 0.28*0 = 2.1.

A collection of statistical techniques known as regression analysis is used to estimate the associations between a dependent variable and one or more independent variables. It may be used to simulate the long-term link between variables and gauge how strongly the relationships between them are related.

The relationship between dispersed data points in any collection is shown by a regression line. When there is a linear pattern, it displays the relationship between the dependent y variable and independent x variables.

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Answer:give her brainlist she is right

Step-by-step explanation:

Answer:

x - 1 = y

Step-by-step explanation:

Answer: Minnie: 17x, 10y                        

              Mickey: 20x, 0y

Step-by-step explanation:

For Minnie, if you divided 350 by 20 it equals 17.5 but since it has to be a whole number we take 0.5 times 20 and that equals 10 so she has to pay off 10 more dollars. For Mickey, we take 200 and divide it by 10 and that equals 20 weeks and since theres no qouteint left there is no more money needed to be paid.

Hope This Helps!

Answer:

6

Step-by-step explanation:

It is true, Mai can conclude that the diagonal WY bisects the angles ZWX and ZYX

Since Mai has proven triangles WYZ and WYX to be congruent by the SSS triangle Congruence Theorem, she can conclude that:

Diagonal WY bisects angles ZWX and ZYX because:

all corresponding parts of both triangles are congruent. (Option A).

If two triangles are proven to be congruent to each other, it means that all three pairs of corresponding sides and angles of both triangles are congruent and equal to each other.

Thus, since Mai has proven triangles WYZ and WYX to be congruent by the SSS Triangle Congruence Theorem, therefore, all corresponding parts of both triangles are congruent.

If this is so, then Mai can conclude that angles ZWX and ZYX are bisected by diagonal WY. (Option A is correct).

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Answer:

\(8 {x}^{2} - 6x - 5 = x\)

\(8 {x}^{2} - 7x - 5 = 0\)

x = (7 + √((-7)^2 - 4(8)(-5)))/(2×8)

= (7 + √(49 + 160))/16

= (7 + √209)/16

= -.4661, 1.3411 (to 4 decimal places)

if you want it a a whole number, it would be for every 34$ 85 bucks for jimmy .

The annuity provide each week is $547.59 (approx.)

Define Annuity

A fixed sum of money paid to someone each year, typically for the rest of their life.

Given,

Dajon already knows that he will have $500,000 when he retires.

P = $500,000

Next, he sets up a payout annuity for 15 years in an account paying 2.05% interest.

r = 2.05 % or 0.0205

t = 15 years

Since, annuity provide each week then

n = 52 weeks (in a year)

The Annuity formula is,

P = d [ ( 1 + r/n)^nt - 1 ] / (r/n)

where, d = regular deposit

Now, plug in the values and find the value of d

P = d [ ( 1 + 0.0205/52)^52*15 - 1 ] / (0.0205/52)

Calculate the value it gives,

P = $547.5936993 or 547.59

Hence, the annuity provide each week is $547.59 (approx.)

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Answer:

Slope (m) = -1/2 or -0.5

Hope that helps ! ^^

Answer:

m= - 1/2

The step-by-step explanation is in the screenshot below!

Answer:

yes

Step-by-step explanation:

12+3=5x-3+3

15=5x

15=5(3)

15=15

Answer:

77

Step-by-step explanation:

There are 415 third graders and 338 second grades the question is asking how many more third graders are there than second graders, so its asking for the difference between them:

415 - 338 = 77

There are 77 more third graders than second graders

Answer:

yeah

Step-by-step explanation:

I failed 3rd grade

The Nearest tenth of a second, the flag is in the air for approximately 0.1 seconds before Zack catches it.

To determine the time the flag is in the air before Zack catches it, we can use the kinematic equation for vertical motion:

h = 16t^2 + vt + s

Where:

h is the height of the flag,

t is the time in seconds,

v is the initial vertical velocity of the flag,

s is the initial height of the flag.

In this case, the flag is thrown into the air from a height of 5 feet (s = 5) with an initial vertical velocity of 30 feet per second (v = 30). Zack catches it at a height of 7 feet (h = 7).

We can rewrite the equation as:

7 = 16t^2 + 30t + 5

To find the time (t) when the flag is at a height of 7 feet, we can rearrange the equation and solve for t. However, since this is a quadratic equation, we can also use the quadratic formula.

The quadratic equation in this case is:

16t^2 + 30t + 5 - 7 = 0

16t^2 + 30t - 2 = 0

Now, we can use the quadratic formula:

t = (-b ± √(b^2 - 4ac)) / (2a)

Applying the values from the quadratic equation, we have:

t = (-30 ± √(30^2 - 4 * 16 * (-2))) / (2 * 16)

Simplifying further:

t = (-30 ± √(900 + 128)) / 32

t = (-30 ± √1028) / 32

Using a calculator, we find two solutions:

t ≈ -1.08 seconds or t ≈ 0.06 seconds

Since time cannot be negative in this context, we discard the negative solution.

Therefore, to the nearest tenth of a second, the flag is in the air for approximately 0.1 seconds before Zack catches it.

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Answer:

I believe it is 14 mm, hope i helped

Both A and D have 2 pairs of parallel sides

A quadrilateral is a polygon with four sides and four angles. A parallelogram is a quadrilateral with two pairs of parallel sides.

A trapezoid is a quadrilateral with one pair of parallel side. A square is a quadrilateral with two pairs of parallel sides and all sides have the same measure.

Both A and D have 2 pairs of parallel sides

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Answer:

f−1(x) = \(\frac{4x}{6}\)

Step-by-step explanation:

f(x) = 0.25(6)x, find f−1(x).

f(x) = 0.25(6)x

f(x) = \(\frac{6}{4}\)x = \(\frac{6x}{4}\)

f(x) = y

y =  \(\frac{6x}{4}\)

Substitute y for an x & x for a y

x = \(\frac{6y}{4}\)

Multiply both sides by 4

4( x ) = 4( \(\frac{6y}{4}\) )

4x = 6y

Divide both sides by 6 to solve for y

\(\frac{4x}{6}\) = y

y = \(\frac{4x}{6}\)

so f−1(x) = \(\frac{4x}{6}\)

Answer:

chahana

durgam

utar

shrutisambhinarthak

a. The hypothesis to be tested are given as follows:

b. The p-value is of: 0.0047.

c. The decision is of: Reject the null hypothesis.

d. The conclusion is of: There is enough evidence to conclude that the mean rate is less for people who exercise regularly.

At the null hypothesis, it is tested if there is not enough evidence to conclude that the heart rate is less, than is, if the difference is not negative, hence:

\(H_0: \mu_d \leq 0\)

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the heart rate is less, that is, if the difference is negative, hence:

\(H_1: \mu_d > 0\)

The parameters to the p-value are given as follows:

We have a left-tailed test, as we are testing if the mean is less than a value, hence, using a t-distribution calculator, the p-value is of:

0.0047.

Since the p-value is less than the critical value, the decision and the conclusion are given as follows:

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Answer:

D or O

E'

Step-by-step explanation:

Because the runner is a sprinter and the number is odd, the runner is an example of S and O. Therefore, it is also an example of E′ (not even) and D OR O.

For sprinter numbered 1 is outcome of S, D and O events.

Events to be determine that contain sprinter number 1. We have number of events that is for sprinter, distance runner, odd numbered, even numbered as S,D,O and E respectively.
Sample space = (1, 2, 3, 4, 5).

Probability can be defined as the possibility of the desired event to be happened.

Here, Numbered 1 is odd number, a sprinter and also a distance runner.
So, Numbered 1 is contain in S, D and O.

Thus, for sprinter numbered 1 is outcome of S, D and O events.

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