Using the following information, calculate the theoretical yield for the dehydration of 100.16 g of cyclohexanol. molar mass (g/mol) density (g/mL) cyclohexanol 100.16 0.948 cyclohexene 82.15 0.811

Answer:

4 M

Explanation:

See the steps and explanation in the picture

Answer:

please rate my answer 5 Star

Explanation:

Using Boyle's Law,

The pressure exerted by a gas is inversely proportional to the volume the gas is occupying provided the temperature is constant

p*v = constant

100*1000*7.5 = p * 11

p = 750000/11

When the pressure decreases from left to right, the acceleration also decreases.

This is defined as the rate at which velocity changes with time and it has a direct relationship with pressure.

This however means that when pressure decreases there will be a corresponding decrease in acceleration and vice versa.

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There are only two electrons that could posses the quantum numbers as shown.

We now that it is often common to seek to describe the probability of finding the electrons in the atom. While it is know that the electron is not a given point in the atom. The probability of finding the electron in the atom is given by the help of the quantum numbers that can be used to describe the position of the electron as shown.

In tis case, we have an electron that has the quantum numbers; n = 3, l = 2, ml = -2. This describes an orbital and there are two electrons in a given orbital.

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Answer: C. investigations are usually wrong

Explanation: Because investigation are usually wrong and then that leads to more  and more questions

Answer:

1.125 moles of hydrogen are needed.

Explanation:

Given data:

Number of moles of ammonia formed = 0.75 mol

Number of moles of hydrogen needed = ?

Solution:

Chemical equation:

N₂  + 3H₂      →       2NH₃

Now we will compare the moles of ammonia and hydrogen.

                  NH₃         :           H₂  

                    2           :             3

                 0.75         :           3/2×0.75 = 1.125 mol

1.125 moles of hydrogen are needed.

1) The equilibrium concentration of sulfate ion in a saturated silver sulfate solution is 0.75 × 10⁻² M.

2) The equilibrium concentration of calcium ion in a saturated calcium sulfite solution is 1.54 × 10⁻³  M.

1) The chemical equation is as :

Ag₂SO₄ ⇄ 2Ag⁺  +  SO₄²⁻

The expression for the Ksp is as :

Ksp = [Ag⁺]²[SO₄²⁻]

Where,

The Ksp of the Ag₂SO₄ = 1.7 × 10⁻⁶

Ksp = [Ag⁺]²[SO₄²⁻]

1.7 × 10⁻⁶ = (2s)² × s

1.7 × 10⁻⁶ = 4s³

s³ = 1.7 × 10⁻⁶/ 4

s³ = 0.75 × 10⁻² M

The concentration of the silver sulfate solution is  0.75 × 10⁻² M.

2) The chemical equation is as :

CaSO₄ ⇄ Ca⁺  +  SO₄²⁻

The Ksp expression is as :

Ksp = [Ca⁺] [SO₄²⁻]

Where,

Ksp = 2.4 × 10⁻⁵

Ksp = [Ca⁺] [SO₄²⁻]

2.4 × 10⁻⁶ = s²

s = 1.54 × 10⁻³ M

The concentration of calcium ion in a saturated calcium sulfite solution is  1.54 × 10⁻³ M.

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As a falling rocket plunges toward the event horizon, an observer in the orbiting rocket would see that the falling rocket speeding up.

The horizon is that the line that separates the world from the sky. There 2 main sorts of horizons—Earth-sky horizons and celestial horizons. each Earth-sky and celestial horizons have completely different sub-types of horizons. The native horizon, geographic horizon, and lowland horizon are all Earth-sky horizons

A rocket is a vehicle that uses reaction propulsion to accelerate while not victimisation the encompassing air. A rocket produces thrust by reaction to exhaust expelled at high speed. Rocket engines work entirely from propellant carried within the vehicle; so a rocket will fly within the vacuum of area.

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The amount of 0.110 M sulfuric acid are required to neutralize exactly 25.0 mL of 0.0840 M NH3 solution is 9.55mL.

A neutralisation reaction is a chemical process in which an acid and a base combine to produce salt and water as the end products. H+ ions and OH- ions combine to generate water during a neutralisation process.

2 NH3(aq) + H₂SO4 (aq) → (NH4)2SO4(aq)

moles of NH3 = (25ml x 1L/1000mL) x 0.084M

=> 2.1x 10^(-3) moles

The mole ratio of NH3 to H₂SO4 in the given reaction

=> moles of H₂SO4 = 2.1 x 10^(-3) moles of NH3 x 1 molesH₂SO4/2 moles

                                                                                                                  NH3

=> 1.05 x 10^(-3) moles

Volume = moles/molarity

=> 1.05  10^(-3) moles/0.110M

=> 9.55 x 10^(-3) L = 9.55mL

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This technique has been used to identify the presence of gases such as oxygen, methane, and carbon dioxide in the atmospheres of exoplanets.  

i) To estimate the frequency of the violet (leftmost) emission, we can use the equation v = c/λ, where v is frequency, c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the emission in meters. The wavelength of the violet emission is 400 nm or 400 x 10^-9 m, so the frequency can be calculated as v = (3.00 x 10^8 m/s) / (400 x 10^-9 m) = 7.50 x 10^14 Hz.

ii) To estimate the energy of the violet emission, we can use the equation E = hv, where E is energy, h is Planck's constant (6.63 x 10^-34 Js), and v is frequency in Hz. Substituting the frequency calculated in part (i), we get E = (6.63 x 10^-34 Js) x (7.50 x 10^14 Hz) = 4.97 x 10^-19 J.

b. The spectral lines are produced by the electrons within the atoms of this element, which can absorb or emit specific amounts of energy to move between different energy levels. These energy transitions result in the emission or absorption of photons with specific wavelengths and frequencies, giving rise to the observed emission spectrum.

c. The violet emission line represents the photon with the most energy since it has the shortest wavelength (400 nm) and highest frequency (7.50 x 10^14 Hz) among the lines shown. This highest energy does not necessarily represent the energy of the valence electrons, but rather corresponds to the specific energy transitions occurring within the atoms of the element.

d. Emission spectra can be used to determine the gases present in the atmosphere of a far-away planet by analyzing the specific wavelengths of the emitted or absorbed light from the planet. Each gas has a unique emission or absorption spectrum, allowing scientists to identify the gases present in the planet's atmosphere.

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Answer:

a. Speed up, lose

Explanation:

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Answer:

b. speed up, gain

Explanation:

Answer:

All organisms begin life as a single cell

Explanation:

Single cell also did you know 15 minutes can save you 15% more on car insurance

Based o the percentage masses of the elements, the empirical formula of epinephrine is C₉H₁₃O₃N.

The empirical formula of epinephrine is calculated below as follow:

Mole ratio of the elements are determined:

Carbon = 59% / 12

Carbon = 0.049 moles

Hydrogen = 7.1% / 1

Hydrogen = 0.07 moles

Oxygen = 26.2% / 16

Oxygen = 0.016

Nitrogen = 7.7% / 14

Nitrogen = 0.0055

The simplest whole-number ratio will be:

C = 0.049/0.0055

C = 9

Hydrogen = 0.07/0.0055

H = 13

Oxygen = 0.016/0.0055

Oxygen = 3

Nitrogen = 0.0055/0.0055

Nitrogen = 1

The empirical formula = C₉H₁₃O₃N

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INFORMATION:

We know that:

- An aqueous solution is 15.0% methanol (CH4O) by mass and has a density of 0.998 g/mL

And we must calculate molarity, molality and Xa

STEP BY STEP EXPLANATION:

First, we must analyze the given information:

15.0% methanol (CH4O) by mass means,

mass of methanol = 15 g

mass of water (solvent) = 85 g = 0.085 kg

mass of solution = 100 g

Now, we can calculate:

a. Molarity

To calculate it, we must use the following formula

The solution has a density of 0.998 g/mL

Using that,

Now, calculating no. of moles

Finally, replacing the values in the formula for Molarity

b. Molality

To calculate it, we must use the following formula

Now, replacing the values in the formula

c. Xa (mole fraction)

Now, the total moles would be

Then, the mole fraction

ANSWER:

a. 3.2495 mol/L

b. 3.8306 m

c. 0.0645

There are 3.4 milliliters of the active ingredient in the cough syrup bottle.

To calculate the volume of the active ingredient in the cough syrup bottle, we need to multiply the total volume of the bottle by the percentage of the active ingredient.

Given:

Total volume of the bottle = 68.0 mL

Percentage of active ingredient = 5.00%

First, we convert the percentage to a decimal by dividing it by 100:

Percentage of active ingredient = 5.00% = 5.00/100 = 0.05

Next, we calculate the volume of the active ingredient:Volume of active ingredient = Total volume of the bottle × Percentage of active ingredient

Volume of active ingredient = 68.0 mL × 0.05

Volume of active ingredient = 3.4 mL

Therefore, there are 3.4 milliliters of the active ingredient in the cough syrup bottle.

It's important to note that the calculation assumes a homogeneous distribution of the active ingredient throughout the solution.

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Answer:

NO + O2 NO2

Explanation:

Answer:

answer 7.4 atm

Explanation:

i did this and got it correct

• In order to determine how many moles of CO2 could be produced from 0.05 moles of CO( Carbon monoxide)

• We need to determine the mole ratio first :

2CO + O2 → 2CO2

2 : 1 : 2

0.05moles : 0.025 : 0.05

• We can see that, 0.05 moles of CO will produce 0.05 mole of CO2 , their mole ratio is 2:2 which is the same as 1: 1, they are equal.

Answer:

2-methylene propylbenzene

Explanation:

The Wittig Reaction is a reaction that converts aldehydes and ketones into alkenes through reaction with a phosphorus ylide.

The ketone in this case is 1-phenylpropan-1-one. The provided phosphonium ylide is shown in the image attached. The reaction involves;

i) alkylation  

ii) addition

The product of the major organic product of the reaction is 2-methylene propylbenzene.

1) List the known and unknown values

Final conditions

Volume: 7.8 L

Temperature: 100 K

Initial conditions

Temperature: 435 K

Unknown

Volume:

2) set the equation

Charles' law

3) Plug in the known values

Answer:

A substance is a form of matter that will have a constant composition of evenly distributed products.

Explanation:

(Has to be the same everywhere)

The answer is 3,294,000 m/h.

Explanation: There are 3,600 seconds in an hour, so you would multiply 915 by 3,600.

To convert the speed from m/s to mph, multiply the speed in m/s by the conversion factor of 2.23694.

To convert the speed from meters per second (m/s) to miles per hour (mph), you can use the conversion factor of 2.23694. Multiply the speed in m/s by this conversion factor to get the speed in mph.

Let's calculate the speed in mph:

Speed in m/s = 915.0 m/s
Conversion factor = 2.23694

Speed in mph = 915.0 m/s x 2.23694 = 2044.3437 mph

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The formula form of the chemical reactions are given as follows:

A chemical equation is an equation which uses the symbols of elements to show the reaction that occur between substances to form products.

The formula form of the chemical reactions are given as follows:

In conclusion, the chemical reactions are represented by the equations.

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Carlon is modelling the strike slip fault .

Faults are known as displacement or fractures that occurs on Earth's crust arising from cracks as the movement of rocks continuosly slide against  each other. They can be tiny without causing any cracks or very large cause noticeable defects between the rock layers.

A strike slip fault is also known as a Lateral fault zone.

Here, The fault shows how  two blocks of  the earth's crustal plates   undergo a horizontally slip on a  fault plane. This slip can case cracks which extends  deep inside the crust causing continuos wear and tear as they rub on each other.

Most times this  stretches and eventually causes earthquakes

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Answer:

(850000) - (9.0 × 10^5) calculated with significant figures is -0.5 × 105, which contains 1 sig figs and 1 decimals. There are 2 steps to calculate (850000) - (9.0 × 10^5) with sig figs. To count the number of sig figs in -0.5 × 105, strip the leading insignificant digits (-0.) to get the significant digits (5).

ANswer is  1 (-0.5e5)

Answer: The formula of the hydrated alumina is  \(Al_2O_3.5H_2O\)

Explanation:

Decomposition of hydrated alumina is given by:

\(Al_2O_3.xH_2O\rightarrow Al_2O_3+xH_2O \)

Molar mass of \(Al_2O_3\) = 101.96 g/mol

According to stoichiometry:

(101.96+18x) g of  \(Al_2O_3.xH_2O\) decomposes to give 101.96 g of

\(Al_2O_3\)

Thus 5.000 g of   \(Al_2O_3.xH_2O\) decomposes to give=\(\frac {101.96}{(101.96+18x)}\times 5.000\) of H_2O

But it is given 5.000 g of a sample of hydrated salt \(Al_2O_3.xH_2O\) was found to contain 2.6763 g of unhydrated salt

Thus we can equate the two equations:

\(\frac{101.96}{(101.96+18x)}\times 5.000=2.6763\)

\(x=5\)

Thus the formula of the hydrated alumina is  \(Al_2O_3.5H_2O\)

Answer:

This would be 63 gallons :)

Explanation:

The Volume of water = 2.4 × 10² L

The Volume of water in gal = ?

The solution:  We know that one gal is equal to 3.785 litter.

So in conclusion, 2.4 × 10²L × 1 gal / 3.785 L

2.4 × 10²L × 0.264 gal. L⁻¹

0.634 × 10² gal

Hopefully this helps :3

63 gal

Answer:

See explanation

Explanation:

From the information given;

We convert the pressure from torr to atm as follows;

745 torr * 1 atm/760 torr = 0.98 atm

Initial pressure P1 =  0.98 atm - 0.0372 atm = 0.9428 atm

Initial volume V1=  283 mL

Initial temperature T1 = 28.0oC + 273 = 301 K

Final volume V2 = ??

Final Temperature T2 = 273 K

Final pressure P2 = 1 atm

From the general gas equation;

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 0.9428 * 283 * 273/1 *  301

V2 = 241.99 mL or 0.24 L

If 1 mole of gas occupies 22.4 L

x moles of gas occupies 0.24 L

x =  1 mole  * 0.24 L/ 22.4 L

x = 0.0107 moles

But number of moles = mass/molar mass

molar mass = mass/number of moles

molar mass = 905 * 10^-3g/0.0107 moles

molar mass = 84 g/mol

The monoatomic gas is Krypton