Step-by-step explanation:
y =40x
the distance traveled is 40 times the amount of time the eagle flew.
A card will be picked at random from a standard deck of 52 cards. What is the probability that the card is a king and a diamond? Enter your answer as a fraction.
Solution:
Given:
\(\begin{gathered} total\text{ cards}=52 \\ number\text{ of kings = 4} \\ number\text{ of diamonds = 13} \end{gathered}\)From the numbers, the number of king and diamond cards = 1
Hence, the probability that the card is a king and a diamond is;
\(P(King\text{ and diamond\rparen}=\frac{1}{52}\)Rebecca is unpacking a full box after moving. She removes a 6 in. x 12 in. x 16 in. computer from the box below. How much volume do the rest of the items in the box take up (in cubic inches)?
Answer:
i don't know if this is good for you but
Step-by-step explanation:
What are two possible sets of dimensions ( length, width, and height) of her shape? Alexandria's swimming pool can hold. 756 cubic feet
Answer:
5556 Step-by-step explanation:
6th grade math help me pleaseeee
Answer:
\( \sqrt{3} \)
Step-by-step explanation:
Irrational number.
For the transformation T, write the T-1. T: (x, y) ( 2x, y + 5) T -1 (x, y) (x - 2, y - 5) (2x - 1, y + 4) (½x, y - 5)
=====================================
Explanation:
The original transformation (2x, y+5) takes any x value and doubles it. So the inverse of this is to cut the x value in half. We can say x/2 since division is the opposite of multiplication. The value x/2 is the same as ½x
For the y coordinate, we add on 5 for the original transformation. Subtraction undoes addition meaning the inverse will have y-5.
Side note: the inverse notation \(T^{-1}\) can be written as T^(-1).
difer from the true proportion by more than 2% ? A previous study indicates that the proportion of lefthanded sclontists is 9%. Round up to the nearest whicie number. Duestion 13 A. 1.218 B. 1,109 C. 14 D.767
The total number of samples will be 1109 .
Given ,
Margin of error 0.02
Here,
According to the formula,
\(Z_{\alpha /2} \sqrt{pq/n}\)
Here,
p = proportions of scientist that are left handed
p = 0.09
n = number of sample to be taken
Substitute the values,
\(Z_{0.01} \sqrt{0.09 * 0.91/n} = 0.02\\ 2.33 \sqrt{0.09 * 0.91/n} = 0.02\\\\\\\)
n ≈1109
Thus the number of samples to be taken will be approximately 1109 .
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18< -3(4x-2) Solve for x. Please graph your solution if your not able to its fine but it will be appreciated
You may need to use the appropriate appendix table or technology to answer this question. Given that z is a standard normal random variable, compute the following probabilities. (Round your answers to four decimal places.) (a) P(z s-2.0) (b) P(Z Z-2) (c) P(Z 2-1.7) (d) P(-2.3 ≤ 2) (e) P(-3
Given that `z` is a standard normal random variable, we are to calculate the following probabilities using the appropriate appendix table or technology:
(a) `P(z ≤ -2.0)` (b) `P(Z > -2)` (c) `P(Z < 1.7)` (d) `P(-2.3 ≤ Z ≤ 2)` (e) `P(-3 < Z < -1.5)`.
From the normal distribution table, we can read the probability of a `z-score`. Using this table, we can calculate the following probabilities:
(a) P(z ≤ -2.0). The standard normal distribution table shows that the area to the left of a `z-score` of `2.0` is `0.0228`. Hence, P(z ≤ -2.0) = 0.0228.
Answer: `0.0228`
(b) P(Z > -2)P(Z > -2) = 1 - P(Z ≤ -2) = 1 - 0.0228 = 0.9772
Answer: `0.9772`
(c) P(Z < 1.7)P(Z < 1.7) = 0.9554
Answer: `0.9554`
(d) P(-2.3 ≤ Z ≤ 2)P(-2.3 ≤ Z ≤ 2) = P(Z ≤ 2) - P(Z ≤ -2.3)
We need to find `P(Z ≤ 2)` and `P(Z ≤ -2.3)` by referring to the standard normal distribution table:
P(Z ≤ 2) = 0.9772P(Z ≤ -2.3) = 0.0107
Therefore, P(-2.3 ≤ Z ≤ 2) = 0.9772 - 0.0107 = 0.9665
Answer: `0.9665`
(e) P(-3 < Z < -1.5)P(-3 < Z < -1.5) = P(Z < -1.5) - P(Z < -3)
We need to find `P(Z < -1.5)` and `P(Z < -3)` by referring to the standard normal distribution table:
P(Z < -1.5) = 0.0668P(Z < -3) = 0.0013
Therefore, P(-3 < Z < -1.5) = 0.0668 - 0.0013 = 0.0655
Answer: `0.0655`.
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you have started your position as transportation director in a small town called mountainside village. there is only one road in and out of town. today you can expect at peak traffic to see 35 cars per hour and the drive along the road with no traffic is 1 minute. assuming poisson arrival and exponential drive times, what is the current utilization of the road? (4 points)
The current utilization of the road is 0.5833 or 58.33%. To calculate the current utilization of the road, we need to use the formula:
Utilization = Arrival rate x Drive time
Since we are assuming Poisson arrival and exponential drive times, we can use the following formulas:
Arrival rate = λ = 35 cars per hour
Drive time = 1/μ = 1/60 hours (since the drive time is 1 minute)
Therefore,
Utilization = 35 cars per hour x (1/60 hours)
Utilization = 0.5833 or 58.33%
So the current utilization of the road in Mountainside Village is 58.33%.
Hi! As the transportation director of Mountainside Village, we can calculate the current utilization of the road using the given terms. The peak traffic rate is 35 cars per hour, and the drive time without traffic is 1 minute (or 1/60 hours).
Since we're assuming Poisson arrival and exponential drive times, we can calculate the utilization (ρ) using the formula:
ρ = λ / μ
Here, λ represents the arrival rate (35 cars/hour), and μ represents the service rate, which is the inverse of the average drive time (1/60 hours).
So, μ = 1 / (1/60) = 60 cars/hour
Now, we can calculate the utilization:
ρ = 35 cars/hour / 60 cars/hour = 0.5833 (rounded to 4 decimal places)
Thus, the current utilization of the road is 0.5833 or 58.33%.
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For any positive integer n, let An denote the surface area of the unit ball in Rn, and let Vn denote the volume of the unit ball in Rn. Let i be the positive integer such that Ai>Ak for all k k not equal to i. Similarly let j be the positive integer such that Vj>Vk for all k not equal to j. Find j−i.
To find the value of j - i, we need to determine the relationship between the surface areas (An) and volumes (Vn) of the unit ball in Rn for different positive integers n.
For the unit ball in Rn, the formula for surface area (An) and volume (Vn) are given by:
An = (2 * π^(n/2)) / Γ(n/2)
Vn = (π^(n/2)) / Γ((n/2) + 1)
where Γ denotes the gamma function.
To find the value of j - i, we need to identify the positive integers i and j such that Ai > Ak for all k not equal to i, and Vj > Vk for all k not equal to j.
First, let's analyze the relationship between An and Vn. By comparing the formulas, we can see that:
An / Vn = [(2 * π^(n/2)) / Γ(n/2)] / [(π^(n/2)) / Γ((n/2) + 1)]
= 2 / [n * (n-1)]
From this equation, we can deduce that An / Vn > 1 if and only if 2 > n * (n-1).
To find the positive integer i, we need to identify the highest positive integer n for which 2 > n * (n-1) holds true. We can observe that this condition is satisfied for n = 2. Therefore, i = 2.
Now, let's find the positive integer j. We need to identify the lowest positive integer n for which 2 > n * (n-1) does not hold true. We can observe that this condition is no longer satisfied for n = 3. Therefore, j = 3.
Finally, we can calculate j - i as follows:
j - i = 3 - 2 = 1
Therefore, j - i equals 1.
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What value of x makes 1/2(3x+4)=1/2x true. A.2. B.1. C-1. D.-2
PLZZ HURRY
Answer:
The answer is D, -2. brainliest pls! :D
Step-by-step explanation:
-2*3=-6
-6+4=-2
-2*1/2=-1
-1=1/2x
1/2*-2=-1
-1=-1
The value of x such that it will make the given expression (1/2)(3x+4)=(1/2)x true is x = - 2 therefore, option (D) will be correct.
What is an expression?A mixture of variables, numbers, addition, subtraction, multiplication, and division are called expressions.
An expression is a mathematical proof of the equality of two mathematical expressions.
As per the given expression,
(1/2)(3x+4)=(1/2)x
(3/2)x + 4/2 = x/2
3x/2 + 2 = x/2
3x/2 - x/2 = -2
(3x - x)/2 = -2
2x = -4
x = -2
Hence "The value of x such that it will make the given expression (1/2)(3x+4)=(1/2)x true".
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How to tell if a function is exponential.
Answer:
It is when it has factors and can be multiplied
I set z=t=0(x,y,z,t)
and I got a partial solution (0,1,0,0).
I solved two homogeneous matrices once for z=1
and t=0
, then for z=0
and t=1
and I got two solutions (1,1,1,0)
and (1,1,0,1).
Then, I got (0,1,0,0)+a∗(1,1,1,0)+b∗(1,1,0,1
)
Therefore, all possible results are (0,1,0,0),(1,0,1,0),(1,0,0,1),(0,1,1,1)
Would this be correct?
The correct set of possible results would be (0, 1, 0, 0), (1, 2, 1, 0) and (1, 2, 0, 1).
Your approach seems to be correct, but there seems to be a minor mistake in your final list of possible solutions. Let's go through the steps to clarify.
Given the initial conditions z=t=0, you obtained a partial solution (0,1,0,0).
Next, you solved the homogeneous equations for z=1 and t=0, which resulted in a solution (1,1,1,0).
Similarly, solving the homogeneous equations for z=0 and t=1 gives another solution (1,1,0,1).
To find the general solution, you combine the partial solution with the solutions obtained in the previous step, using parameters a and b.
(0,1,0,0) + a(1,1,1,0) + b(1,1,0,1)
Expanding this expression, you get:
(0+a+b, 1+a+b, 0+a, 0+b)
Simplifying, you obtain the following set of solutions:
(0, 1, 0, 0)
(1, 2, 1, 0)
(1, 2, 0, 1)
Therefore, the correct set of possible results would be:
(0, 1, 0, 0)
(1, 2, 1, 0)
(1, 2, 0, 1)
Note that (0, 1, 1, 1) is not a valid solution in this case, as it does not satisfy the initial condition z = 0.
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A certain forest covers an area of 2,000 square kilometers. Suppose that each year this area, decreases by 6%. What is the equation that best represents the area of the forest each year?
Hint: Use the formula y = P(1 + r)x.
y = 2,000(0.94)x
y = 2,000(1.06)x
y = 2,000(0.06)x
y = 2,000(1.94)x
Answer:
y = 2,000(0.94)x
Step-by-step explanation:
f(x) = P (1 + r) ^x
P = 2000
r = -0.06
f(x) = 2000 (1 - 0.06)^x
= 2000 (0.94)^x
Select the correct function. Select the function with an average rate of change of 3 over the interval [1, 3].
Answer:
Function g(x)
Step-by-step explanation:
Given
See attachment for functions
Required
Which has an average rate of 3 over [1,3]
The average rate of change (m) is calculated as:
\(m = \frac{f(b) - f(a)}{b -a}\)
Where:
\([a,b] = [1,3]\)
So, we have:
\(m = \frac{f(3) - f(1)}{3 -1}\)
\(m = \frac{f(3) - f(1)}{2}\)
From the table f(x), we have:
\(f(3) = 6\\ f(1) = -2\)
So:
\(m = \frac{6 - -2}{2}\)
\(m = \frac{8}{2}\)
\(m =4\)
From the graph of g(x), we have:
\(g(3) = 4\\ g(1) = -2\)
So:
\(m = \frac{g(3) - g(1)}{2}\)
\(m = \frac{4 - -2}{2}\)
\(m = \frac{6}{2}\)
\(m =3\)
Since only one of the function has an average rate of change of 3 over the given interval,
Then g(x) answers the question
Mrs. Perry is taking a group of students to the Clark Planetarium where tickets cost $7 each. The bus will cost $50 and she has a budget of $200. How many people can attend under these constraints?
PLEASE HELP
You have to create 3 functions to make hills on a grap
Requirements are in the photo.
(ignore graphs)
4. Write equations for three hills that do meet the requirements. Sketch them on one axis. (For the
purposes of this exercise, this is a sketch, so the steepness and minimums and maximums of the
graphs do not need to be exact). (6 points: 1 point for each equation, 1 point for each sketched curve)
Answer:
Hill 1: F(x) = -(x + 4)(x + 3)(x + 1)(x - 1)(x - 3)(x - 4)
Hill 2: F(x) = -(x + 4)(x + 3)(x + 1)(x - 1)(x - 3)(x - 4)
Hill 3: F(x) = 4(x - 2)(x + 5)
Step-by-step explanation:
Hill 1
You must go up and down to make a peak, so your function must cross the x-axis six times. You need six zeros.
Also, the end behaviour must have F(x) ⟶ -∞ as x ⟶ -∞ and F(x) ⟶ -∞ as x⟶ ∞. You need a negative sign in front of the binomials.
One possibility is
F(x) = -(x + 4)(x + 3)(x + 1)(x - 1)(x - 3)(x - 4)
Hill 2
Multiplying the polynomial by -½ makes the slopes shallower. You must multiply by -2 to make them steeper. Of course, flipping the hills converts them into valleys.
Adding 3 to a function shifts it up three units. To shift it three units to the right, you must subtract 3 from each value of x.
The transformed function should be
F(x) = -2(x +1)(x)(x -2)(x -3)(x - 6)(x - 7)
Hill 3
To make a shallow parabola, you must divide it by a number. The factor should be ¼, not 4.
The zeroes of your picture run from -4 to +7.
One of the zeros of your parabola is +5 (2 less than 7).
Rather than put the other zero at ½, I would put it at (2 more than -4) to make the parabola cover the picture more evenly.
The function could be
F(x) = ¼(x - 2)(x + 5).
In the image below, Hill 1 is red, Hill 2 is blue, and Hill 3 is the shallow black parabola.
I need help. ASAP. PLEASE.
Ok, so I got this formula from another answer and want someone to help me in explaining how they got to this formula. I understand where they got the constant from, where they got the a-value, but I don't understand where they got b = 2. Please help. We're dealing with a quadratic function here, in which the rate of change is generally -0.2. Thank you to anyone who responds.
Given 4x²-32x-20+k is a perfect square find k
Answer:
84
Step-by-step explanation:
\( {a} {}^{2} - 2ab + b ^{2} = (a - b) { }^{2} \)
Can you help me and answer it like the paper says
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the formula for the polar form of the given complex number
\(\begin{gathered} z=r\cos \theta \\ \text{where r is the radius} \\ \theta\text{ is the measure of angle in radians} \\ \text{Note that:} \\ \pi=180^{\circ} \end{gathered}\)STEP 2: Complete the table by substituting and solving for the unknown
\(\begin{gathered} z=r\cos \theta\Rightarrow r\cos \pi \\ To\text{ get }\theta\text{ in row 1} \\ r=3,\pi=180 \\ z=3\cos 180 \\ \\ To\text{ get r and }\theta\text{ in row }2 \\ z=rcis\theta\Rightarrow\frac{1}{2}cis2\pi \\ By\text{ comparison,} \\ r=\frac{1}{2},\theta=2\pi=2\times180^{\circ}=360^{\circ} \\ \\ To\text{ get r and }\theta\text{ in row }3 \\ z=rcis\theta\Rightarrow cis\frac{\pi}{4} \\ By\text{ comparison,} \\ r=2,\theta=\frac{\pi}{4} \\ \\ To\text{ get r and }\theta\text{ in row }4 \\ z=rcis\theta\Rightarrow cis\frac{\pi}{2} \\ By\text{ comparison,} \\ r=1,\theta=\frac{\pi}{2} \end{gathered}\)STEP 3: Complete the table
Triangle QRS is to be dilated using the rule D Subscript P, three-fourths.
Point P is the center of dilation. Triangle Q R S is shown. The length of P S is 8.
What will be the distance from the center of dilation, P, to the image S'?
2 units
4 units
6 units
8 units
The distance from the center of dilation, P, to.the image vertice S' is; 6 units.
What is the distance from the center of dilation, P, to the image S'?It follows from the task content that the center of dilation of the triangle QRS is point P and the length of segment PS in the pre-image is; 8 units.
Hence, since the dilation factor as given in the task content is; three-fourths, it therefore follows that the distance of point P to S' in the image is; (3/4) × 8 = 6units.
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Solve the system of equations and wright your answer as an ordered pair -5/4x-5/4y =25/41/5x+4/5y=1/5
(-7, 2)
STEP - BY - STEP EXPLANATION
What to find?
The solution to the given the system of equations .
Given:
\(\begin{gathered} -\frac{5}{4}x-\frac{5}{4}y=\frac{25}{4} \\ \\ \frac{1}{5}x+\frac{4}{5}y=\frac{1}{5} \end{gathered}\)To solve the above system of equations, we will follow the steps below:
Step 1:
Multiply through equation (1) by 4
\(-5x-5y=25\text{ ----------------------(2)}\)Step 2
Multiply through the second equation by 5.
\(x+4y=1\text{ -------------------------(3)}\)Step 3
Using substitution method to solve.
Make x the subject of formular.
\(x=1-4y-------------------(4)\)Step 4
Substitute equation(4) into equation (2).
\(-5(1-4y)-5y=25\)Step 5
Open the parenthesis.
\(-5+20y-5y=25\)Step 6
Collect like term.
\(\begin{gathered} 20y-5y=25+5 \\ 15y=30 \end{gathered}\)Step 7
Divide both-side of the equation by 15.
\(\begin{gathered} \frac{15y}{15}=\frac{30}{15} \\ \\ y=2 \end{gathered}\)Step 8
Substitute y=2 into equation (4) to determine the value of x.
\(\begin{gathered} x=1-4(2) \\ =1-8 \\ =-7 \end{gathered}\)Hence, x =-7 and y=2.
Therefore, the solution in ordered pair is (-7, 2)
For the following distribution, decide whether you expect the mean, median, or mode to give the best representation of the center of the distribution, and explain why. The number of times that people change jobs during their careers.
F
1) For variables like these, we most often use the mean that will compute all data points (in this case, the number of jobs a person had throughout his life ) for a central tendency measure.
2) Examining the options, then we can state that the answer is: F
and that is the answer.
A certain test preparation course is designed to help students improve their scores on the GRE exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 5 students' scores on the exam after completing the course: 6,14,12,23,0 Using these data, construct a 95% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal. Step 1 of 4 : Calculate the sample mean for the given sample data. Round your answer to one decimal place.
The sample mean for the given sample data is 11.0.(rounded to one decimal place). The mean of the sample means is the average of all sample means taken from the population. It is an estimate of the population mean. The sample mean is calculated by taking the sum of all values in the sample and dividing it by the sample size.
Step 1: Calculate the sample mean for the given sample data. Round your answer to one decimal place.
To calculate the sample mean, follow these steps:
1. Add up the net changes in scores for all the students: 6 + 14 + 12 + 23 + 0 = 55
2. Divide the sum by the number of students (n=5): 55 ÷ 5 = 11
The sample mean for the net change in students' scores is 11.0 (rounded to one decimal place).
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Suppose A = a speeding violation in the last year and B = a cell phone use while driving. A total of 800 people were surveyed in a study of drivers who received speeding violations in the last year, and who used a cell phone while driving. Out of the 800, 70 had a speeding violation and 730 did not; 310 used cell phones while driving and 490 did not. If A and B are statistically independent, what is the expected number of drivers who used a cell phone while driving and received speeding violations?
To find the expected number of drivers who used a cell phone while driving and received speeding violations, we can multiply the probabilities of each event occurring if A and B are statistically independent.
From the given information, we know that out of the 800 surveyed drivers with speeding violations, 70 had a speeding violation and 310 used a cell phone while driving.
If A and B are independent, the probability of a driver having a speeding violation and using a cell phone while driving is the product of the individual probabilities. The probability of having a speeding violation is 70/800 = 0.0875, and the probability of using a cell phone while driving is 310/800 = 0.3875.
Therefore, the expected number of drivers who used a cell phone while driving and received speeding violations can be calculated by multiplying the total number of drivers (800) by the product of the probabilities:
Expected number = 800 * (0.0875 * 0.3875) = 27.5
The expected number of drivers who used a cell phone while driving and received speeding violations is 27.5.
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Tyrese bought 35 tickets to use at the carnival. He used some of the tickets to ride the bumper cars and play some games. now he has 28 tickets left what is the percent of decrease in the number of ticket that he has?
Answer:
20%?
Step-by-step explanation:
Which answer is the best estimate of the correlation coefficient for the variables in the scatter plot?
Which equation represents the relationship between the step number, n, and the number of small squares, y, in each step. Step 1 Step 2 Step 3 f(x) = x² - 1 f(x) = x-2 f(x) = x2 + 1 f(x) = x²
From the diagram we can see:
\(\begin{gathered} step_{\text{ }}1\colon \\ 1_{\text{ }}square \\ step_{\text{ }}2\colon \\ 4\text{ }squares \\ step_{\text{ }}3\colon \\ 9\text{ }squares \end{gathered}\)Therefore, we can conclude that in every step the result is the square of the number of the step. So:
\(\begin{gathered} f(x)=x^2 \\ ---- \\ f(1)=(1)^2=1 \\ ---- \\ f(2)=(2)^2=4 \\ ---- \\ f(3)=(3)^2=9 \end{gathered}\)What is 88 + 99
Tyler said 88 cupcakes are with 99 pancakes
anyone p l a y r o b l o x
Answer:
187
Step-by-step explanation:
Can someone help me with this Question.
The formula we need to use is given above. In this formula, we will substitute the desired values. Let's start.
\(P=3W+D\)A) First, we can start by analyzing the first premise. The team has \(8\) wins and \(5\) losses. It earned \(8 \times 3 = 24\) points in total from the matches it won and \(1\times5=5\) points in total from the matches it drew. Therefore, it earned \(24+5=29\) points.
B) After \(39\) matches, the team managed to earn \(54\) points in total. \(12\) of these matches have ended in draws. Therefore, this team has won and lost a total of \(39-12=27\) matches. This number includes all matches won and lost. In total, the team earned \(12\times1=12\) points from the \(12\) matches that ended in a draw.
\(54-12=42\) points is the points earned after \(27\) matches. By dividing \(42\) by \(3\) ( because \(3\) points is the score obtained as a result of the matches won), we find how many matches team won. \(42\div3=14\) matches won.
That leaves \(27-14=13\) matches. These represent the matches team lost.
Finally, the answers are below.
\(A)29\)
\(B)13\)
Answer:
a) 29 points
b) 13 losses
Step-by-step explanation:
You want to know points and losses for different teams using the formula P = 3W +D, where W is wins and D is draws.
A 8 wins, 5 drawsThe number of points the team has is ...
P = 3W +D
P = 3(8) +(5) = 29
The team has 29 points.
B 54 pointsYou want the number of losses the team has if it has 54 points and 12 draws after 39 games.
The number of wins is given by ...
P = 3W +D
54 = 3W +12
42 = 3W
14 = W
Then the number of losses is ...
W +D +L = 39
14 +12 +L = 39 . . . substitute the known values
L = 13 . . . . . . . . . . subtract 26 from both sides
The team lost 13 games.
__
Additional comment
In part B, we can solve for the number of losses directly, using 39-12-x as the number of wins when there are x losses. Simplifying 3W +D -P = 0 can make it easy to solve for x. (In the attached, we let the calculator do the simplification.)
<95141404393>
Tekan-Tekan Sdn. Bhd. has order for 200 Model AS-120 calculator for delivery on day 200. The calculator consists of three parts. Components 2 and 3 form subassembly 1 . Sub-assembly 1 and component 4 form the final assembly. Following are the work centers and times of each operation. Table Q3(a) shows routine file of the operation. Assuming: - Only one machine is assigned to each operation - The factory works on 8-hour shift, 5 days a week - All parts move in one lot of 200. (a) Illustrate the backward schedule based on the information given above. (12 marks) (b) Identify when component 3 must be started to meet the delivery date. (2 marks)
Component 3 must be started on day 197 to meet the delivery date of day 200.
To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.
(a) Backward schedule:
Operation | Work Center | Time (hours) | Start Day
--------------------------------------------------------
Final Assembly | Work Center 1 | 1 | 200
Sub-assembly 1 | Work Center 2 | 2 | 199
Component 4 | Work Center 3 | 3 | 197
Component 2 | Work Center 4 | 4 | 196
Component 3 | Work Center 5 | 3 | ????
(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.
From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.
Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.
Hence, component 3 must be started on day 197 to meet the delivery date of day 200.
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