To write the expression in the terms requested, you will subtract multiples of 2π from the argument to obtain an angle in the range [0, 2π].csc [-(23π/4)] = csc [(5π/4) - 2π] = -csc (5π/4)csc (3π/2) = -1,sec 12π - sec 0 = -csc (5π/4) - (-1) = -csc (5π/4) + 1.
To solve this problem, you need to know the cofunction identity which states that sec θ
= csc (π/2 - θ). The problem requires you to write an expression equal to sec 12π - sec 0.Using the cofunction identity above, sec 12π - sec 0
= csc [(π/2) - 12π] - csc [(π/2) - 0]
Since π radians is half of a circle, 12π is equivalent to 6 full circles. Therefore, [(π/2) - 12π] is equivalent to [(π/2) - 6(2π)]
= [(π/2) - 12π].π/2 is equal to 6π/4.
Thus, [(π/2) - 0]
= [(6π/4) - 0]
= (3π/2).Substituting the values in the equation above,sec 12π - sec 0
= csc [(π/2) - 12π] - csc [(π/2) - 0]
= csc [-(23π/4)] - csc (3π/2)
Note that the trigonometric function has period 2π. To write the expression in the terms requested, you will subtract multiples of 2π from the argument to obtain an angle in the range [0, 2π].csc [-(23π/4)]
= csc [(5π/4) - 2π]
= -csc (5π/4)csc (3π/2)
= -1,sec 12π - sec 0
= -csc (5π/4) - (-1)
= -csc (5π/4) + 1.
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Do this for me please!!
Use a row level button to collapse worksheet rows to display only subtotals and the grand total. Then, use a show details button to display individual records for the Appliances subcategory of data (the second show details (+) symbol).
To collapse worksheet rows to display only subtotals and the grand total, and then display individual records for the Appliances subcategory, follow these steps:
Step:1. Select the range of data in your worksheet that you want to collapse, including the headers, subcategory rows, and subtotal rows.
Step:2. Go to the Data tab in the Excel toolbar.
Step:3. Click on the Group button (located in the Outline section) and choose the Group option from the drop-down menu.
Step:4. Excel will create row level buttons with minus (-) symbols to the left of your data. Click on the row level button with the number "2" to collapse the rows and display only the subtotals and grand total.
Step:5. Locate the subtotal row for the Appliances subcategory. To the left of this row, you should see a show details button with a plus (+) symbol.
Step:6. Click on the show details button to display individual records for the Appliances subcategory.
By following these steps, you have successfully collapsed the worksheet rows to display only subtotals and the grand total, and then used the show details button to display individual records for the Appliances subcategory.
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Look at the picture please
Answer:
3rd one
Step-by-step explanation:
Range goes to the y-values
The y values are 16 19 and 16
So the range will be (16,19)
and D are noncoplanar. △ABC,△ABC,△ACD, and △ABD are equilateral. X and Y are midpoints of AC¯¯¯¯¯¯¯¯ and and AD.Z is a point on AB¯¯¯¯¯¯¯¯. What kind of triangle is △XYZ? Explain.
ΔXYZ will also be an equilateral triangle.
What is equilateral triangle?
An equilateral triangle in geometry is a triangle with equal-length sides on all three sides. In the well-known Euclidean space, an equilateral triangle also is equiangular, meaning that each of its three internal angles is 60 degrees and congruent with the others. It's also referred to it as a regular triangle because it is a regular polygon.
As X,Y,Z are the midpoints of sides of equilateral triangle so when we will join the X,Y,Z we will find that distances XY=YZ=XZ are three are equal because this is proved by similarity of triangles which in itself is a detailed and vast topic
Hence XYZ will also be an equilateral triangle
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a teacher is experimenting with computer-based instruction. in which situation could the teacher use a hypothesis test for a population mean? group of answer choices
The teacher could use a hypothesis test for a population mean in the following situation:
The teacher wants to determine if computer-based instruction has a statistically significant effect on the average test scores of students in the class. The teacher can collect a sample of test scores from students who received computer-based instruction and a sample of test scores from students who did not receive computer-based instruction. Then, the teacher can use a hypothesis test for the population mean to compare the mean test scores of the two groups and determine if the difference is statistically significant.
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Complete question:
teacher is experimenting with computer-based instruction In which situation could the teacher use a hypothesis test for a ifference in two population means?
O The teacher uses a combination of treditional methods and computer based instruction She asks students # they lked computer based instruction better She wants to determine if the maorty prete the computer-based instruction
O She gives each student a pretest Then she teaches a lesson using a computer program Afterwards, she gives each student a postest The teacher wants to see f the difference in scores willshow an improvement 。
She ran om y d des the class into t goups One gup ecerves computer based instruction The other group recen es tradit na n rete wit t copters Ahe rst eten een student ha to solve a single problem. The teachers wants to compare the proportion of each group who can solve the problem 。She gives each student a pretest he then randomly dvides the class mto two groups.
Ο e group receves compte based i struct . The other go p eceves tradtind rst cto with t computers After instruction each student takes a post test. The teacher compares the improvement in scores (post test minus pretest) in the two groups
Japhet is making small rectangular tiles for a mosaic. each tile has an area of 7 cm 2 and is 1 1/4 cm wide. how long is each tile?
Answer:
28/5
Step-by-step explanation:
7 x 4/5 = 28/5
use keep, change, flip
Answer:
28/5
Step-by-step explanation:
just did it on khan academy.
refer to the function f= (7,2), (9,7), (4,9), (3,4)
Determine f(7)
f(7)=?
Since we are looking for the value of f(7), we need to find the corresponding output value when the input is 7. From the given function, we see that input 7 corresponds to output 2. f(7) = 2.
To determine the value of f(7), we need to look at the given function f and substitute 7 for the independent variable.
The function f is defined by the ordered pairs (7,2), (9,7), (4,9), and (3,4). The first value in each ordered pair represents the input, while the second value represents the output.
In summary, when we substitute 7 for the independent variable in the given function f = (7,2), (9,7), (4,9), (3,4), we find that f(7) = 2.
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what is the perimeter of triangle DFG. The perimeter of triangle DFG is 54 inches. The perimeter of triangle DFG is 27 inches. The perimeter of triangle DFG is 36 inches. The perimeter of triangle DFG is 52 inches
Determine which set of side measurements could be used to form a right triangle.
A: 2,4,10
B: 7,8,9
C: Square root of 6,8, Square root of 70
D: Square root of 28, Square root of 42, 70
The set of sides (Square root of 6,8, Square root of 70) could be used to form a right-angle triangle.
Option (C) is correct.
What is a Pythagorean Triplet?
Pythagorean triples are defined as a²+b² = c², where a, b, and c are positive integers. These triples are denoted as (a, b, c). The perpendicular is a the base is b, and the hypotenuse is c of a right-angled triangle. The most well-known and tiniest triplets are (3,4,5).
For option (C), the set of sides is (Square root of 6,8, Square root of 70).
Let the largest side in the above set is c = \(\sqrt{70}\)
so a = \(\sqrt{6}\) and b= 8,
Now by using the Pythagorean triplets property,
LHS = a² + b²
= \((\sqrt{6})^2 + 8^{2}\)
= 6 + 64
= 70 -----------------(I)
Now, RHS = c²
= \((\sqrt{70})^2\)
= 70 -----------------(II)
By using (I) and (II), we can say that, LHS = RHS,
So the given set of sides holds the property of Pythagorean triplets.
Hence, the set of sides (Square root of 6,8, Square root of 70) could be used to form a right-angle triangle.
Option (C) is correct.
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[ 7 11] [12 4 5 ]
Find C =AB, if A = [2 9] B = [3 6 1]
[ 10 6]
The exercise involves finding the product C = AB, where matrix A is given by [2 9] and matrix B is given by [3 6 1]. We need to perform the matrix multiplication to obtain the resulting matrix C.
Let's calculate the matrix product C = AB step by step:
Matrix A has dimensions 2x1, and matrix B has dimensions 1x3. To perform the multiplication, the number of columns in A must match the number of rows in B.
In this case, both matrices satisfy this condition, so the product C = AB is defined.
Calculating AB:
AB = [23 + 912 26 + 94 21 + 95]
[103 + 612 106 + 64 101 + 65]
Simplifying the calculations:
AB = [6 + 108 12 + 36 2 + 45]
[30 + 72 60 + 24 10 + 30]
AB = [114 48 47]
[102 84 40]
Therefore, the product C = AB is:
C = [114 48 47]
[102 84 40]
In summary, the matrix product C = AB, where A = [2 9] and B = [3 6 1], is given by:
C = [114 48 47]
[102 84 40]
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Solve 3+y=18 for y. Solve for y
Answer:
3 + y = 18
y = 18 - 3
y = 15
Step-by-step explanation:
brainliest plz
15 is the answer.
3+15=18
A pet store has three fish tanks, each holding a different volume of water and a different number of fish. Tank AAA holds 40\text{ L}40 L40, start text, space, L, end text and 555 fish. Tank BBB holds 100\text{ L}100 L100, start text, space, L, end text and 121212 fish. Tank CCC holds 180\text{ L}180 L180, start text, space, L, end text and 232323 fish.
Answer:
The tanks by volume per fish from least to greatest:
Tank C, Tank A, Tank B
Step-by-step explanation:
A pet store has three fish tanks, each holding a different volume of water and a different number of fish.
Order the tanks by volume per fish from least to greatest.
Tank A holds 40 L and 5 fish.
= 40L/5 fishes
= 8 volume per fish
Tank B holds 100 L and 12 fish
= 100L/12 fishes
= 8.3333333333 volume per fish
Tank C holds 180 L and 23 fish.
= 180L /23 fish
= 7.8260869565 volume per fish
The tanks by volume per fish from least to greatest
Tank C, Tank A, Tank B
Solve for x.
10[2x-4]=100
Answer:
x = 7Step-by-step explanation:
\(10[2x-4]=100\\\\\mathrm{Divide\:both\:sides\:by\:}10\\\frac{10\left(2x-4\right)}{10}=\frac{100}{10}\\\\Simplify\\2x -4=10\\\\\mathrm{Add\:}4\mathrm{\:to\:both\:sides}\\2x-4+4=10+4\\\\Simplify\\2x =14\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\frac{2x}{2}=\frac{14}{2}\\\\Simplify\\x = 7\)
Solve1 over 25 = 5x 4. X = negative 7 over 2 x = −6 x = 9 over 2 x = 2.
By solving the given equation, we have determined that x is equal to 1/500.
The given equation is "1/25 = 5x4". We need to solve this equation to find the value of "x".
To solve the equation, we will perform the following steps:
Step 1: Multiply both sides of the equation by 25 to eliminate the denominator:
(1/25) * 25 = (5x4) * 25
1 = 125x4
Step 2: Simplify the right-hand side of the equation:
1 = 500x
Step 3: Divide both sides of the equation by 500 to isolate x:
1/500 = x
Hence, the value of x is 1/500. Therefore, the correct option is x = 1/500.
Thus, by solving the given equation, we have determined that x is equal to 1/500.
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Each heet of metal on a roof i perpendicular to the top line of the roof. What can you conclude about the relationhip between the heet of roofing? Jutify your anwer
The sheets of metal on the roof must be parallel to each other in order to be perpendicular to the top line of the roof. This means that the sheets of metal are parallel to each other and that their relationship is one of parallelism. This parallelism is necessary so that the roof can maintain its structure and be waterproof.
The relationship between sheets of metal on a roof is one of parallelism. This is because each sheet must be perpendicular to the top line of the roof in order to maintain the structure and be waterproof. In order for the roof to remain secure and waterproof, the sheets must be parallel to each other. This parallelism is necessary in order for the roof to form one complete structure and for the sheets to remain secure. Without the parallelism of the sheets, the roof would be unable to maintain its structure and could easily be damaged by wind and rain. This is why the relationship between the sheets of metal on a roof is one of parallelism.
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x and y each take on values 0 and 1 only and are independent. their marginal probability distributions are: f(x) =1/3, if x = 0 and f(x) = 2/3 if x = 1
the joint probability distribution for x and y is as follows:
f(x, y): x=0, y=0: 1/9
x=0, y=1: 2/9
x=1, y=0: 2/9
x=1, y=1: 4/9
Based on the given information, we can determine the marginal probability distributions for x and y:
For x:
f(x=0) = 1/3
f(x=1) = 2/3
For y, since it is independent of x, the probabilities remain the same:
f(y=0) = 1/3
f(y=1) = 2/3
To find the joint probability distribution, we multiply the probabilities for x and y since they are independent:
f(x=0, y=0) = f(x=0) * f(y=0) = (1/3) * (1/3) = 1/9
f(x=0, y=1) = f(x=0) * f(y=1) = (1/3) * (2/3) = 2/9
f(x=1, y=0) = f(x=1) * f(y=0) = (2/3) * (1/3) = 2/9
f(x=1, y=1) = f(x=1) * f(y=1) = (2/3) * (2/3) = 4/9
Therefore, the joint probability distribution for x and y is as follows:
f(x, y):
x=0, y=0: 1/9
x=0, y=1: 2/9
x=1, y=0: 2/9
x=1, y=1: 4/9
This represents the probabilities for each possible combination of x and y.
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I WILL GIVE BRAINILY (20 PTS)
There are 15 questions, and John got an 84% on the quiz, how many questions did John get right and how many wrong?
Answer:
John got 13 questions right and 2 questions wrong.
Step-by-step explanation:
15 questions right equals 100%.
100 {divided by} 15 = % for each question right
Each question is worth (100 diveded by 15) 6.7%.
84% {diveded by} 6.7% = 12.5
100% - 84% = 16%
16% {divided by} 6.7% = 2.38
Because 12.5 has a higher dicimle value than 2.38 and when the amount he got right is added to the amount he got wrong it needs to equal 15, 12.5 becomes 13 and 2.38 becomes 2.
Answer:
\(\frac{n}{15} =\frac{84}{100}\)
\(n = \frac{21}{25}*5\)
\(n = \frac{21*15}{25}\)
\(n = \frac{315}{25}\)
\(n = \frac{63}{5} or 12.6\)
PLEASE ANSWER HURRY!!!!!
Answer:-1
Step-by-step explanation:
Help me pls how to do this
Answer:
tbh I don't know either that's what brainley is for ☺️
the x-intercept was substituted incorrectly
write the correct equation
an equation of the parabola is y =__________
Answer:
Step-by-step explanation:
let the eq. of parabola be
y=ax²+bx+c
points (-1,0),(2,0),(3,4) and (0,-2) lie on it.
0=a-b+c
0=4a+2b+c
subtract
3a+3b=0
a=-b
4=9a+3b+c
-2=0+0+c
c=-2
a-b-2=0
-b-b-2=0
-2b-2=0
b+1=0
b=-1
a=-b=-(-1)=1
eq. of parabola is
y=x²-x-2
A set of numbers is said to be COMMUTATIVE under the operation '+' if m + n = n + m, for any two numbers m and n of that set. Similarly, a set of numbers is said to be COMMUTATIVE under the operation '×' if m × n = n × m.
Which of the following sets is COMMUTATIVE under the operation '-'?
A)the set of integers
B)the set of natural numbers
C)the set of rational numbers
D)none of the above
Answer:
A) the set of integers is commutative under operation '-'
The commutative property holds for Addition and Multiplication, but not for subtraction and division.
So, option (D) is correct.
The commutative property states that the numbers on which we operate can be moved or swapped from their position without making any difference to the answer.
The commutative property holds for Addition and Multiplication,
Example, \(2+4=4+2\)
\(3*2=2*3\)
The commutative property does not holds for subtraction and division.
Example, \(3-2\neq 2-3\)
\(4/2\neq 2/4\)
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Explain, as clearly as you can, why 4/5 of 25 is 20.
⅘×25=20
of means times.
A puppy weighs534pounds.
how many ounces does the puppy weigh?
a.23 oz
b.46 oz
c.92 oz
ds.184 oz
Answer:
none of those answers are correct unless u mean 5 and 3/4
Step-by-step explanation:
True or False: In standard form, the coefficients of x and y do NOT need to be integers
Dolce Dornandiclar lines intersectat dacrocandles
Wut is 11.4 divided by 19. Please show work & be reasonable. Help a gurl out pls
Answer:
Simple do divide 11.4/19 = 0.6 It is your answerCormac has some sweets in a bag.
The sweets are lime flavoured or strawberry flavoured or orange flavoured.
In the bag
number of lime
flavoured sweets
number of strawberry
flavoured sweets
number of orange = 9:4:x
flavoured sweets
OC
9
4
Cormac is going to take at random a sweet from the bag.
3
The probability that he takes a lime flavoured sweet is
Work out the value of x.
The probability that Cormac takes a lime flavoured sweet is 9/16.
What is probability?Probability is the occurence of likely events. It is the area of mathematics that deals with numerical estimates of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1.
The following can be deduced:
number of lime = 9
number of strawberry = 4
number of orange = 3
Total = 16
Probability of picking a lime will be:
= Number of lime / Total
= 9/16
The probability is 9/16.
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Complete question
The sweets are lime flavoured or strawberry flavoured or orange flavoured.
In the bag
number of lime = 9
number of strawberry = 4
number of orange = 3
HELP I NEES ANSWER NOW PLS HELP IF YOU KNOW
Answer:
1. THERE S NO JI ON THE FIGURE???
2. 2/3 is scale factor
Step-by-step explanation:
pls mark brainliest and hope this helps :)
Find the variance for n = 170 and p = 0.7 when the conditions for the binomial distribution are met.
If the conditions for a binomial distribution are met, the variance, given the number of trials (n) and the probability of success(p) is given as:
\(\text{variance (}\sigma^2)\text{ = np(1-p)}\)Given:
n = 170
p = 0.7
Solution
By substituting the given values, the variance is:
\(\begin{gathered} \sigma^2\text{ = 170 }\times\text{ 0.7 }\times\text{ (1-0.7)} \\ =\text{ 35.7} \end{gathered}\)Answer: 35.7
NEED HELP ASAP ALGEBRA 2
Answer:
3√6
Step-by-step explanation:
\( {a}^{2} = {b}^{2} + {c}^{2} \)
\( = {1}^{2} + {( \sqrt{53} )}^{2} \)
\( = 1 + 53\)
\( {a}^{2} = 54\)
\(a = \sqrt{54} = 3 \sqrt{6} \)
Q1. A heavy general purpose truck costs $12,000 has a life of six years with a $2,000 SV. using the
MACRS with a GDS recovery period of five years. What is the BV of the equipment at the end of
(including) year four?
IN EXCEL WITH EXPLANATION PLEASE
Answer:
Therefore, the book value of the equipment at the end of year four (including year four) is $2,880.
Step-by-step explanation:
To calculate the book value of the equipment at the end of year four using the MACRS method with GDS recovery period of five years, we can use the following steps in Excel:
1. Open a new Excel spreadsheet and create the following headers in row 1: Year, Cost, Depreciation Rate, Annual Depreciation, Cumulative Depreciation, and Book Value.
2. Fill in the Year column with the years 1 through 6 (since the truck has a life of six years).
3. Enter the cost of the truck, $12,000, in cell B2.
4. Use the following formula in cell C2 to calculate the depreciation rate for each year:
=MACRS.VDB(B2, 5, 5, 1, C1)
This formula uses the MACRS.VDB function to calculate the depreciation rate for each year based on the cost of the truck (B2), the GDS recovery period of five years, the useful life of six years, the salvage value of $2,000, and the year (C1).
5. Copy the formula in cell C2 and paste it into cells C3 through C7 to calculate the depreciation rate for each year.
6. Use the following formula in cell D2 to calculate the annual depreciation for each year:
=B2*C2
This formula multiplies the cost of the truck (B2) by the depreciation rate for each year (C2) to get the annual depreciation.
7. Copy the formula in cell D2 and paste it into cells D3 through D7 to calculate the annual depreciation for each year.
8. Use the following formula in cell E2 to calculate the cumulative depreciation for each year:
=SUM(D$2:D2)
This formula adds up the annual depreciation for each year from D2 to the current row to get the cumulative depreciation.
9. Copy the formula in cell E2 and paste it into cells E3 through E7 to calculate the cumulative depreciation for each year.
10. Use the following formula in cell F2 to calculate the book value of the equipment for each year:
=B2-E2
This formula subtracts the cumulative depreciation for each year (E2) from the cost of the truck (B2) to get the book value.
11. Copy the formula in cell F2 and paste it into cells F3 through F7 to calculate the book value for each year.
12. The book value of the equipment at the end of year four (including year four) is the value in cell F5, which should be $2,880.