uranus and neptune are like the other jovian planets because they:

Answers

Answer 1

Uranus and Neptune are like the other Jovian planets because they have a lot of gaseous composition, they lack a solid surface, and they are situated far from the sun.

The Jovian planets are four planets in the outer solar system that are gas giants, also known as the gas planets. They are Jupiter, Saturn, Uranus, and Neptune. In terms of the composition of Uranus and Neptune, they contain methane, ammonia, water, and other elements that form gas. Like the other Jovian planets, they lack a solid surface, and they are situated far from the sun.

The rings of Uranus and Neptune are fainter and less complex than the rings of Jupiter and Saturn, but they share certain features. Both Uranus and Neptune are thought to have a small rocky core surrounded by a mix of rock and ice, then a thick layer of metallic hydrogen, and an atmosphere mainly of molecular hydrogen and helium. So therefore because gaseous composition, lack a solid surface, and situated far from the sun, Uranus and Neptune are like the other Jovian planets.

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Related Questions

Which of these systems is not an isolated system to which conservation of momentum can be applied

Answers

Open system is not an isolated system to which conservation of momentum can be applied.In mechanics, an isolated system is a physical system that does not interact with its surroundings. Conservation of momentum is only valid for an isolated system. Momentum is conserved in such a system.

The closed system is a system in which there is no net transfer of mass between the system and its surroundings, but there may be transfer of energy. It is considered a more general concept than the isolated system, which does not allow any energy or matter transfer to and from the system.

Example: If a rocket is moving in space without any external force or effect then it is known as an isolated system.In open systems, both mass and energy can be exchanged with the environment. The open system is not an isolated system to which the conservation of momentum can be applied.Example: An aquarium containing fish, plants, and water is an example of an open system because the fish and plants breathe, the fish eat food and produce waste, and water evaporates.

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When the total energy exerted on a treadmill exercise is 430 n and the total distance traveled is 110 m, the total work performed is equal to _____.

Answers

When the total energy exerted on a treadmill exercise is 430 n and the total distance traveled is 110 m, the total work performed is equal to 47300 N·m.

When calculating the total work performed on a treadmill exercise, we can use the formula:

Work = Force × Distance

In this case, the total energy exerted on the treadmill exercise is given as 430 N (newtons) and the total distance traveled is 110 m (meters). We can plug these values into the formula to find the total work performed:

Work = 430 N × 110 m

Multiplying these values together, we get:

Work = 47300 N·m

Therefore, the total work performed is equal to 47300 N·m.


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Find the force of attraction between a 60 kg student and:A. Another student of mass 80 kg, 1.4 m away.B. A 130,000 kg blue whale, 10 m away.C. The Great Pyramid in Egypt, with an estimated mass of 5.22 x 109 kg, 1.0 km away.D. A 45 g golf ball, 95 cm away.

Answers

According to Newton's Law of Universal Gravitation, the force between to bodies of masses m and M separated by a distance r is:

\(F=G\frac{Mm}{r^2}\)

Where G is the gravitational constant:

\(G=6.67\times10^{-11}N\frac{m^2}{\operatorname{kg}^2}\)

In all cases, use M=60kg, and replace the values of the second mass m and the distance r accordingly.

A) m=80kg, r=1.4m

\(\begin{gathered} F=(6.67\times10^{-11}N\frac{m^2}{\operatorname{kg}^2})\times\frac{(60\operatorname{kg})(80\operatorname{kg})}{(1.4m)^2} \\ =1.6\times10^{-7}N \end{gathered}\)

B) m=130,000kg, r=10m

\(\begin{gathered} F=(6.67\times10^{-11}N\frac{m^2}{\operatorname{kg}^2})\times\frac{(60\operatorname{kg})(130,000\operatorname{kg})}{(10m)^2} \\ =5.2\times10^{-6}N \end{gathered}\)

C) m=5.22*10^9kg, r=1000m

\(\begin{gathered} F=(6.67\times10^{-11}N\frac{m^2}{\operatorname{kg}^2})\times\frac{(60\operatorname{kg})(5.22\times10^9\operatorname{kg})}{(1000m)^2} \\ =2.1\times10^{-5}N \end{gathered}\)

D) m=0.045kg, r=0.95m

\(\begin{gathered} F=(6.67\times10^{-11}N\frac{m^2}{\operatorname{kg}^2})\times\frac{(60\operatorname{kg})(0.045\operatorname{kg})}{(0.95m)^2} \\ =2.0\times10^{-10}N \end{gathered}\)

Which feature of this rock demonstrates that it is a clastic sedimentary rock?

visible crystal formations
variation of colored sediments
visible rock fragments
distribution of organic materials

Answers

Answer:

visible rock fragments

Explanation:

sedimentary rocks start as sediments carried in rivers and deposited in lakes and oceans then get buried so the sediments lose water and become cemented to form the rock.

Answer:

c

Explanation:

What does the concentration of damaging earthquakes indicate about the underlying rock structure of the area?

Answers

Answer:it is unstable and may be fragmented or lie along a fault line

Explanation:

Where loads are likely to be ON for 4 hours, the computed load for sizing branch-circuit conductors and OCPDs must be calculated by multiplying the actual load current times ___.

Answers

We have to multiply the actual load current times by 1.25 (2017 NEC: 210.20(A)).

NEC 210.20(A) Continuous and Noncontinuous Loads:

The rating of the overcurrent device must be no less than the noncontinuous load plus 125 percent of the continuous load when a branch circuit delivers continuous loads or any combination of continuous and noncontinuous loads.

With one exception, the ampere rating of the overcurrent device may not be less than the total of the continuous load and the noncontinuous load when the assembly, including the overcurrent devices safeguarding the branch circuit(s), is rated for operation at 100% of its rating.

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A ball is dropped from the top of a tower 40 m high. What is its velocity when it has covered 20 m? What would be its velocity when it hits the ground? Take g= 10 m/s²

Answers

Given :

Height from which ball is dropped , h = 40 m .

Acceleration due to gravity , g= 10 m/s² .

Initial velocity , u = 0 m/s .

To Find :

Velocity when ball covered 20 m and velocity when it hit the ground .

Solution :

Now , height when ball covered 20 m distance is , 40 - 20 = 20 m .

By equation of motion :

\(v^2=u^2+2gh\\\\v=\sqrt{2\times 10\times 20}\ m/s\\\\v=20\ m/s\)

Now , distance covered when body reaches ground is , 40 m .

Putting value h = 40 m in above equation , we get :

\(v=\sqrt{2\times 10\times 40}\ m/s\\\\v=20\sqrt{2}\ m/s\)

Hence , this is the required solution .

Which type of electromagnetic radiation could be described using the wave model? a)X-raysb)Radio wavesc)all of these

Answers

All types of light (EM radiation) can be represented using the wave model. X-rays and radio waves are both light (in different wavelength ranges), therefore they can both be represented by the wave model.

Answer: c) all of these

What is the maximum number of electrons any orbital can hold?.

Answers

Answer:

2n^2

Explanation:

depends on n

if first orboit n = 1

and so on

Is it speed, velocity, or acceleration of a football just after being kicked?

Answers

It is velocity of a football just after being kicked. Velocity is the speed and direction of an object, and it is a vector quantity, meaning it has both magnitude and direction.

When a football is kicked, it has a certain velocity in a particular direction, which can be measured using a speedometer or other measuring device. Acceleration, on the other hand, refers to the rate of change of velocity, so it would only be relevant if the football's velocity was changing after being kicked (for example, if it were slowing down due to air resistance or gravity).

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2. a car traveling at 27 m/s runs out of gas while traveling up a slope. if the car coasts 85 m up the slope before starting to roll back down, what is the angle of incline?

Answers

The angle of inclination is 25.92°. The gravitational force is equal and opposite to the force component parallel to the inclined surface on a block placed on an inclined surface.

We can find the angle of inclination by using this information. This can be illustrated with the following formula;

mg sin θ = f

Here, m = Mass of car = 1,000 kg

g = acceleration due to gravity = 9.8 ms⁻²

sin θ = Opposite / Hypotenuse

= Height / Length

f = Force component parallel to slope

= Weight × sin θ

= mg sin θ

We'll need to utilize the following data:

Initial velocity, u = 27 m/s

Displacement, S = 85 m

Acceleration, a = -9.8 m/s²

By using the kinematic equation of motion, the time it takes to travel up the slope can be calculated;

v² = u² + 2as,

Where, v = Final velocity = 0 m/s

u = Initial velocity = 27 m/s

a = Acceleration = -9.8 m/s²

s = Displacement = 85 m.

After calculating for t, we can use this time value to calculate the angle of inclination by utilizing the aforementioned formula.

mg sin θ = f

Here, m = 1,000 kg,

g = 9.8 ms⁻²,

f = mgsinθsinθ = f / mg.

Now, solve for f, f = ma

Therefore, f = 1,000 kg × 9.8 m/s² × sin θ

The angle of inclination can now be calculated:

sinθ = f / mg

= 1,000 kg × 9.8 m/s² × sin θ / 1,000 kg × 9.8 m/s²

= sin θ= (u² - v²) / 2as

= (27 m/s)² / 2(-9.8 m/s²)(85 m)

= 25.92°

Therefore, the angle of inclination is 25.92°.

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A balloon filled with 2.00 L of helium initially at 1.75 atm of pressure rises into the atmosphere. When the surrounding pressure reaches 360 mmHg, the balloon will burst. If 1 atm = 760 mmHg, what volume will the balloon occupy in the instant before it bursts?

Answers

Volume of the balloon occupy in the instant before it bursts is 7.39 litres and can be find out by boyle's law.


Boyle’s law:

This law gives the relationship between initial and final pressure and volumes for an ideal gas.


Initial condition

Let the volume of the balloon is V1=2.00 L

And, the initial pressure is P1=1.75 atm

Final condition

Let the volume of balloon before it bursts is V2

final pressure is P2=360 mmHg

                                =360/760 atm

                                =0.7368 atm
                           (1atm=760mmHg)

Now, according to boyle’s law

P1V1=P2V2

V2=P1V1/P2

V2=1.75*2.00/0.47368 L

V2=1.39L


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How do you properly hydrate?.

Answers

A simple way to measure your fluid balance is to look at the color of your urine. If your urine is dark and has a strong odor, you are definitely dehydrated and need to increase your water intake. If your urine is completely clear, you probably drank too much.

It usually takes about two hours for the body to fully rehydrate after drinking a significant amount of water. Water is best because you need to stay hydrated. Sports drinks like Gatorade can help athletes who need to replenish their electrolytes.

Research shows that milk is one of the best drinks for hydration better than water and sports drinks. Researchers attribute its effectiveness to milk's natural electrolytes carbohydrates and proteins. can take as little as 5-15 minutes. However, if you are dehydrated with an empty bladder it can take up to 8-9 hours before you need to urinate.

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What are organs made of?
O Organs are made of colections of tissues,
O Organs are made of cells, but not tissues.
O Organs are made of collections of other
O Organs are made of muscle and bone.
DONE

Answers

Organs are made of tissues

Tissues are made of cells though so it’s kinda a weird question lol

Answer:

Organs are made of collections of tissues, which are groups of cells.

Explanation:

(5 points) old-fashioned cathode ray tube monitors and television sets contain electron guns which accelerate electrons between two charged plates. assume that the plate separation is 1.2 cm and that a 25,000 v potential difference is established between them. a hole in the negatively charged plate allows an electron to enter the electron gun with zero initial speed and a hole in the positive plate allows the electron to exit at high speeds. using an energy approach, calculate the speed of the electron as it exits the electron gun (passes through the hole in the positive plate).

Answers

The speed of the electron as it exits the electron gun is approximately 5.2 x 10^7 m/s.

The initial kinetic energy of the electron as it enters the electron gun is zero. The potential difference of 25,000 V accelerates the electron towards the positively charged plate. The electron gains kinetic energy equal to the potential energy lost due to the potential difference. By conservation of energy, the kinetic energy gained by the electron must equal the potential energy lost, given by the formula:

K = eV

Where K is the kinetic energy gained, e is the charge of an electron, and V is the potential difference. Substituting the values, we get:

K = (1.6 × 10^-19 C) x (25,000 V) = 4 × 10^-16 J

The final speed of the electron can be calculated using the formula for kinetic energy:

K = (1/2)m\(v^{2}\)

Where m is the mass of the electron and v is its final speed. Rearranging the formula to solve for v, we get:

v = \(\sqrt{\frac{2K}{m} }\)

Substituting the values, we get:

v = sqrt((2 x 4 x 10^-16 J) / (9.1 x 10^-31 kg))

= 5.2 x 10^7 m/s

Therefore, the speed of the electron as it exits the electron gun is approximately 5.2 x 10^7 m/s.

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Find the field strength. Information given

Weight: 0, point, 96, N,0. 96N
Mass: 3, point, 3, g,3. 3g

Answers

Field strength is 0.03234 N/kg. The formula to determine the field strength is given by:

F = mg Here, F is the field strength, m is the mass, and g is the gravitational field strength.

Substituting the values given: Weight = 0.96 N Mass = 3.3 g = 0.0033 kg = 9.8 m/s² Therefore, F = mg = 0.0033 kg × 9.8 m/s² = 0.03234 N the field strength is the gravitational force acting on a unit mass. It is measured in newtons per kilogram. The field strength is an expression of the strength of a gravitational field. In this case, the mass of the object is 3.3 g, which can be converted to kilograms by dividing by 1000.

The weight of the object is given as 0.96 N. Using the formula

F=mg, where m is the mass and g is the gravitational field strength, we can calculate the field strength as 0.03234 N/kg.

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A discordant igneous intrusion
Select one:
a.
cuts across bedding planes.
b.
will consist dominantly of pyroclasts.
c.
parallels sedimentary rock layering.
d.
produces deadly explosions.

Answers

A discordant igneous intrusion cuts across bedding planes. Here is the detailed explanation of the given question:Explanation:The Discordant igneous intrusion is the formation of an igneous rock mass when magma is injected into a host rock and cools there.

This form of igneous intrusion does not conform to the stratification or layering of the existing rock mass because it cuts across it.Therefore, a discordant igneous intrusion cuts across bedding planes.Option (a) is correct. It is the only option that describes the features of discordant igneous intrusion. Hence, the correct answer is option (a).

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what temperature does water have its maximum temperature​

Answers

Answer:

39°F

Explanation:

At 39°F  water is the most dense. This is because the molecules are closest together at this temperature

Also: Liquid water can be hotter than 100 °C (212 °F) and colder than 0 °C (32 °F). Heating water above its boiling point without boiling is called superheating. If water is superheated, it can exceed its boiling point without boiling

Hope this helps ❤️

Why do clownfish rarely go far from their home

Answers

Answer:

In the wild, clownfish rarely leave their anemone home. In fact, part of its purpose is to defend the anemone from other fish. However, clownfish bred in aquariums (without an anemone home) may still have this instinct, but it’s much calmer than wild harvested species.

Explanation:

Clownfish have no defense mechanism of their own, which is one reason they never stray to far away from their anemone.

A charge of 6.5 x 10-5 C is attracted by another charge with a force of 250 N when
they are separated by 0.15 m. Find the magnitude of the other charge.
8.65 X 105 C
9.62 × 10-2 C
6.15 x 10-6 C
O 9.62 x 10 c

Answers

Answer:

We can use Coulomb's law to solve this problem:

F = k * q1 * q2 / r^2

where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.

We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:

q2 = F * r^2 / (k * q1)

Substituting the values we have:

q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)

Simplifying:

q2 = 8.65 x 10^5 C

Therefore, the magnitude of the other charge is 8.65 x 10^5 C.

A beam of light of wavelength lambda = 541nm is normally incident on a diffraction grating which has 600 lines m * m ^ - 1 Determine the angle theta 2 at which the second order diffracted beam is seen.

Answers

Answer:

Angle of diffraction for second order maxima is θ = 18.941°

Explanation:

From the question it is given that

wavelength of incident light = λ = 541 nm = 541 x \(10^-^9 m\)

order of maxima = n =2

diffraction grating has 600 lines per mm

⇒ distance between two slit is \(\frac{1mm}{600}\) = 1.66 x \(10^-^6\) m

using the relation of Braggs diffraction formula i.e.,

2dsinθ = nλ ..................................(1)

where, d = distance between two lines of grating

θ is the angle of diffraction

n= order of maxima

λ is the intensity of incident photon

on substituting the respected values in relation (1) we get,

2 x 1.66 x \(10^-^6\)m sinθ = 2 x 541 x \(10^-^9 m\)

⇒ sinθ = 0.3246

θ = \(sin^-^1(0.3246)\) = 18.941 °

The average person can hear sound waves ranging in frequency from about 20 Hz to 20 kHz. Determine the
wavelengths at these limits, taking the speed of sound to be 340 m/s.
Given:
Equation:
Solution:

The average person can hear sound waves ranging in frequency from about 20 Hz to 20 kHz. Determine thewavelengths

Answers

The wavelengths at the frequency limits of 20 Hz and 20 kHz are approximately 17 meters and 0.017 meters (or 17 mm), respectively.

To determine the wavelengths at the frequency limits of 20 Hz and 20 kHz, we can use the equation:

Wavelength = Speed of Sound / Frequency

Given:

Speed of Sound = 340 m/s

Frequency:

Lower Limit = 20 Hz

Upper Limit = 20,000 Hz (20 kHz)

For the lower limit:

Wavelength_lower = Speed of Sound / Frequency_lower

= 340 m/s / 20 Hz

= 17 meters

For the upper limit:

Wavelength_upper = Speed of Sound / Frequency_upper

= 340 m/s / 20,000 Hz

= 0.017 meters (or 17 mm)

Therefore, the wavelengths at the frequency limits of 20 Hz and 20 kHz are approximately 17 meters and 0.017 meters (or 17 mm), respectively.

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Plz help with these 5 The backbone is made up of 26 small bones called ___________. What are the characteristics of bones? (list 7) What role do joints play? What are the two types of joints? What are ligaments?

Answers

Answer:

The backbone, spine or vertebral column is made up of 26 small bones called the vertebrae.

The characteristics of bones include:

1. They are strong and rigid

2. They are composed of bone cells called osteocytes.

3. They are lightweight

4. They have a honeycomb-like matrix internally, which helps to give them rigidity.

5. They exist in various types and shapes.

6. They have the ability to grow and repair when damaged

7. They contain inorganic minerals such as calcium and phosphate

The two types of joints are the movable and immovable joints.

Ligaments are bands of tough elastic fibrous tissue around that found around the joints whose function is to link bone to bone, give support to joints as well as limit their movement.

Explanation:

The backbone, spine or vertebral column is made up of 26 small bones called the vertebrae. The 26 small bones include 24 separate vertebrae interspaced with cartilage, and then additionally the sacrum and coccyx. The vertebral column is divided into five regions: cervical, thoracic, lumbar, sacral and coccygeal regions.

A bone is a rigid tissue that is part of the skeleton in vertebrate animals. The characteristics of bones include:

1. They are strong and rigid

2. They are composed of bone cells called osteocytes.

3. They are lightweight

4. They have a honeycomb-like matrix internally, which helps to give them rigidity.

5. They exist in various types and shapes.

6. They have the ability to grow and repair when damaged

7. They contain inorganic minerals such as calcium and phosphate

Joints are the junctions where two bones meet. They serve various functions which include allowing for movement of the body and binding the skeleton together.

The two types of joints are the movable and immovable joints.

Ligaments are bands of tough elastic fibrous tissue around that found around the joints whose function is to link bone to bone, give support to joints as well as limit their movement.

Answer:

5. Vertebrae

Explanation:

A back bone made up of 26 small bones is called a vertebrae.

The Great Salt Lake is located in __________.
A.
Mississippi
B.
Arizona
C.
Florida
D.
Utah

Answers

Answer:

D

Explanation:

Also the capitol of Utah is Salt Lake City

Hope this helps!

Answer:

Utah

Explanation:

The Great Salt Lake, located in the northern part of the U.S. state of Utah, is the largest salt water lake in the Western Hemisphere, and the eighth-largest terminal lake in the world.

how much work is done lifting a 35 pound object from the ground to the top of a 45 foot building if the cable used weighs 2 pounds per foot?

Answers

24,576.11 joules work is done lifting a 35 pound object from the ground to the top of a 45 foot building if the cable used weighs 2 pounds per foot.

The work done while lifting a 35 pound object from the ground to the top of a 45-foot building using a 2-pound per foot cable can be determined by calculating the potential energy of the object at the top of the building.

The potential energy of an object is given by the formula;

Potential Energy = mgh

where m is the mass of the object in kilograms,

g is the acceleration due to gravity which is approximately 9.81 m/s², and

h is the height of the building in meters.

To begin, the 35-pound object needs to be converted to kilograms as follows:

1 pound = 0.45359237 kilograms

Therefore, 35 pounds = 35 x 0.45359237 = 15.875198 kg

The cable weighs 2 pounds per foot, and the height of the building is 45 feet.

Therefore, the total weight of the cable is:

2 pounds per foot x 45 feet = 90 pounds or 40.82331 kg

The total mass, M, of the object and the cable can be found by adding the mass of the object, m, to the mass of the cable,

C.M = m + C

Therefore,

M = 15.875198 + 40.82331M = 56.698508 kg

Now that the total mass of the object and the cable has been found, the potential energy of the object at the top of the building can be calculated.

Potential Energy = mgh

Potential Energy = (56.698508)(9.81)(45)

Potential Energy = 24,576.10561 joules

Therefore, the work done lifting the 35 pound object from the ground to the top of a 45-foot building using a 2-pound per foot cable is approximately 24,576.11 joules.

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It takes 3 minutes for Ann to run 800 meters without sandbags. If Ann runes 800 meters with sandbags it will take 2 more minutes. What is the speed for running with sandbags?

Answers

Ann's speed with sandbags is 400 meters in 5 minutes, or an average of 80 meters per minute.

In everyday use and in kinematics, the speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.Speed is defined as. The rate of change of position of an object in any direction. Speed is measured as the ratio of distance to the time in which the distance was covered. Speed is a scalar quantity as it has only direction and no magnitude.There are four types of speed which are uniform speed, variable speed, average speed, and instantaneous speed.

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An energy service company wants to use hot springs to power a heat engine. If the groundwater is at 95 Celsius, estimate the maximum power output if the mass flux is 0.2 kg/s. The ambient temperature is 20 Celsius. Enter the value in kW, use all decimal places and enter only the numerical value.

Answers

The estimated maximum power output of the heat engine using hot springs with a groundwater temperature of 95 °C and a mass flux of 0.2 kg/s is approximately 0.0128 kW.

To estimate the maximum power output of the heat engine using hot springs, we can utilize the concept of the Carnot cycle, which provides an upper limit for the efficiency of a heat engine.

The Carnot efficiency is given by the formula:

η = 1 - (Tc/Th)

Where η is the efficiency, Tc is the temperature of the cold reservoir (ambient temperature), and Th is the temperature of the hot reservoir (groundwater temperature).

Given:

Tc = 20 °C = 293 K

Th = 95 °C = 368 K

The maximum power output can be calculated using the formula:

P = η * Q

Where P is the power output and Q is the heat transfer rate.

The heat transfer rate can be calculated using the formula:

Q = m * Cp * (Th - Tc)

Given:

m = 0.2 kg/s (mass flux)

Cp = specific heat capacity of water ≈ 4.18 kJ/kg°C

Let's calculate the maximum power output:

Tc = 293 K

Th = 368 K

m = 0.2 kg/s

Cp = 4.18 kJ/kg°C = 4.18 J/g°C = 4.18 * 10⁻³ J/kg°C

Q = m * Cp * (Th - Tc)

  = 0.2 kg/s * 4.18 * 10⁻³ J/kg°C * (368 K - 293 K)

  = 0.2 * 4.18 * 10⁻³ * 75

  = 0.0627 kW

η = 1 - (Tc/Th)

  = 1 - (293/368)

  ≈ 0.204

P = η * Q

  = 0.204 * 0.0627 kW

  ≈ 0.0128 kW

Therefore, the estimated maximum power output of the heat engine using hot springs with a groundwater temperature of 95 °C and a mass flux of 0.2 kg/s is approximately 0.0128 kW.

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At rest, a car's horn has a frequency of
395 Hz. Car A passes car B on the street
in the same direction. If car A is traveling
at 22.0 m/s and car B is traveling
at 19.5 m/s, what frequency does
car B hear when car A honks?

(Speed of sound = 343 m/s)
(Unit = Hz)

Answers

The frequency heard by car A is determined as 398.4 Hz.

What is the frequency heard by car A?

The frequency heard by car A is determined by applying the following equation.

f = fs(v - v₀) / (v - vs)

where;

v is the speed of sound = 343 m/sv₀ is the speed car B = 19.2 m/svs is the speed of car A = 22 m/sfs is the frequency of car A = 395 Hzf is the frequency of car B = ?

f = 395(343 - 19.2) / (343 - 22)

f = 395(1.0087)

f = 398.4 Hz

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estimate the cruising altitude of an airplane during a transatlantic flight. if you are a passenger in the plane when it is at this altitude, what is the percentage change in the gravitational energy of the system of you and the earth compared to when you were in the airport waiting to board the plane? for which of your two locations is the gravitational potential energy greater?

Answers

The cruising altitude of a transatlantic flight is typically between 35,000 and 40,000 feet (10,670 to 12,192 meters) above sea level. This altitude allows the airplane to fly above most weather systems and avoid turbulence while maximizing fuel efficiency.

How does we measure the gravitational energy ?

As a passenger on the plane at this altitude, the percentage change in the gravitational energy of the system of you and the earth compared to when you were on the ground waiting to board the plane would be very small. This is because the change in distance between you and the center of the earth is negligible compared to the radius of the earth. The difference in gravitational potential energy between the two locations would be negligible as well.

However, if we were to compare the gravitational potential energy of the system of you and the earth at the cruising altitude to that of the airport, the potential energy would be slightly greater at the airport due to its closer proximity to the center of the earth. As the airplane ascends, the gravitational potential energy of the system increases, and as it descends, the potential energy decreases.

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A rock has been sent on a journey down through the layers of the Earth until it reaches the inner core. Explain what happens to the atoms in the rock as it moves through each layer.

Answers

Answer:

erosion

Explanation:

grows into the eirth each year. the atmosphere and how the worldchanges every year

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