This statement is not necessarily true.
A real matrix can have real or complex eigenvalues.
A real matrix can have real or complex eigenvalues. The number of real eigenvalues of a matrix may be even or odd, and there is no general rule that determines the parity of the number of real eigenvalues.
For example, the 5x5 real matrix
```
[ 0 1 0 0 0 ]
[ 1 0 0 0 0 ]
[ 0 0 0 1 0 ]
[ 0 0 1 0 0 ]
[ 0 0 0 0 1 ]
```
has two real eigenvalues (1 and -1), which is an even number.
On the other hand, the 5x5 real matrix
```
[ 1 1 0 0 0 ]
[ 1 1 0 0 0 ]
[ 0 0 1 1 0 ]
[ 0 0 1 1 0 ]
[ 0 0 0 0 0 ]
```
has three real eigenvalues (2, 0, and -1), which is an odd number.
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27°
15
Solve for b.
40°
b
b = [ ?
Round your final answer
to the nearest tenth.
10.59 is the value of the given side b.
In our case, we know that side A has a length of 15 units and is opposite angle A, which measures 27 degrees.
Using the sine rule, we can write:
b/sin(27°) = 15/sin(40°)
To find the value of b, we can rearrange the equation:
b = (15 * sin(27°)) / sin(40°)
evaluate the trigonometric functions and calculate b:
b ≈ 10.59
Therefore, using the sine rule of the triangle, we find that the value of side b is approximately 10.59 units.
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The weight of corn chips dispensed into a 12-ounce bag by the dispensing machine has been identified as possessing a normal distribution with a mean of 12.5 ounces and a standard deviation of 0.2 ounce. What proportion of the 12-ounce bags contain more than the advertised 12 ounces of chips
The proportion of 12-ounce bags that contain more than the advertised 12 ounces of chips is 0.
The proportion of 12-ounce bags that contain more than the advertised 12 ounces of chips can be determined by finding the area under the normal distribution curve to the right of the mean.
To find this proportion, we can use the z-score formula:
z = (x - mean) / standard deviation
In this case, we want to find the proportion of bags that contain more than 12 ounces, so x = 12 ounces.
z = (12 - 12.5) / 0.2
z = -2.5 / 0.2
z = -12.5
Next, we need to find the cumulative probability associated with the z-score. We can use a standard normal distribution table or a calculator to find this probability.
Looking up the z-score of -12.5 in the table or using a calculator, we find that the cumulative probability is approximately 0.
Therefore, the proportion of 12-ounce bags that contain more than the advertised 12 ounces of chips is 0.
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Michael swipes his debit card for $17.25 on the purchase of 4 identical bags of potato chips. How much does a bag of potato chips cost?
Answer:
4.31 r 1
Step-by-step explanation:
We have to divide $17.25 into 4. 17.25 ÷ 4 = 4.31 r 1. Asnwer: every potato chip bag cost 4 dollars with 31 cents, with a penny (value: 0.01) to spend.
What is the probability of landing on a number on the spinner that is less than 3?
1/4
3/8
5/8
1/2
Answer: 1/4
Step-by-step explanation:
Reword the problem. It says what is the probability of landing on 2 or 1. That is 2 possibilities out of 8 so 2/8 = 1/4
The velocity v that an object r units from earth's center must have in order to escape earth's gravity is given by v ^ 2 = (2gm)/r , where g is a constant . solve for the object's mass m.
The equation (v²* r) / (2g) represents the object's mass, m.
To solve for the object's mass, m, in the equation v = (2gm)/r, we can rearrange the equation to isolate the variable m.
1. Start with the equation v²= (2gm)/r.
2. Multiply both sides of the equation by r to eliminate the denominator: v² * r = 2gm.
3. Divide both sides of the equation by 2g: (v² * r) / (2g) = m.
The equation (v²* r) / (2g) represents the object's mass, m. This is the answer to the question.
To further understand the equation, let's break it down. The equation v² = (2gm)/r is derived from the principle of escape velocity, which is the minimum velocity needed for an object to escape the gravitational pull of the Earth.
In the equation, v represents the velocity of the object, r is the distance from the center of the Earth to the object, and g is the acceleration due to gravity. The constant g is approximately 9.8 m/s².
By solving for the object's mass, we can determine the mass required for the object to have a specific velocity at a given distance from the Earth's center.
In conclusion, to find the object's mass (m) in the equation v² = (2gm)/r, you can use the formula (v² * r) / (2g). This equation allows you to calculate the mass of an object required to achieve a certain escape velocity at a given distance from the Earth's center.
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Find 39.2% of 448.Round to the nearest hundredth.
Answer:
175.62
Step-by-step explanation:
39.2•448=17561.6
17561.6/100=175.616
=175.62
Find the slope of the tangent to the parametric curve at the indicated point. (Round your answer to two decimal places.) x = t + cos(πt), y = −t + sin(πt)
The slope of the tangent to the parametric curve at the indicated point is -1 + πcos(πt)
Given parametric equations:
x = t + cos(πt)
y = -t + sin(πt)
To find the slope of the tangent, we need to differentiate x and y with respect to t.
Differentiating x with respect to t:
dx/dt = d/dt(t + cos(πt))
= 1 - πsin(πt) [Using the chain rule]
Differentiating y with respect to t:
dy/dt = d/dt(-t + sin(πt))
= -1 + πcos(πt)
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please i need help wit this i’ll give u a brainliest if yk the correct answer
Find the angle between vector bold lower u equals 3 bold lower I plus start root 3 end root bold lower j and vector bold lower v equals negative 2 bold lower I minus 5 bold lower j to the nearest degree. A. 82° B. 38° C. 142° D. 98°
Answer:
C. 142°
Step-by-step explanation:
You want the angle between vectors u=3i+√3j and v=-2i-5j.
AngleThere are a number of ways the angle between the vectors can be found. For example, the dot-product relation can give you the cosine of the angle:
u•v = |u|·|v|·cos(θ) . . . . . . where θ is the angle of interest
You can find the angles of the vectors individually, and subtract those:
u = |u|∠α
v = |v|∠β
θ = α - β
When the vectors are expressed as complex numbers, the angle between them is the angle of their quotient:
\(\dfrac{\vec{u}}{\vec{v}}=\dfrac{|\vec{u}|\angle\alpha}{|\vec{v}|\angle\beta}=\dfrac{|\vec{u}|}{|\vec{v}|}\angle(\alpha-\beta)=\dfrac{|\vec{u}|}{|\vec{v}|}\angle\theta\)
This method is used in the calculation shown in the first attachment. The angle between u and v is about 142°.
A graphing program can draw the vectors and measure the angle between them. This is shown in the second attachment.
__
Additional comment
The approach using the quotient of the vectors written as complex numbers is simply computed using a calculator with appropriate complex number functions. There doesn't seem to be any 3D equivalent.
The dot-product relation will work with 3D vectors as well as 2D vectors.
<95141404393>
Find the roots of the equation: (5.1) z 4
+16=0 and z 3
−27=0 (5.2) Additional Exercises for practice are given below. Find the roots of (a) z 8
−16i=0 (b) z 8
+16i=0
Given equations are (5.1) z 4 +16=0 and z 3 −27=0.(5.1) z 4 +16=0z⁴ = -16z = 2 * √2 * i, 2 * (-√2 * i), -2 * √2 * i, -2 * (-√2 * i)Therefore, the roots of the equation are z = 2^(3/4) * i, 2^(1/4) * i, -2^(3/4) * i, -2^(1/4) * i.(5.2) z 8 −16i=0z⁸ = 16i z = 2^(1/8) * i, 2^(3/8) * i, 2^(5/8) * i, 2^(7/8) * i, -2^(1/8) * i, -2^(3/8) * i, -2^(5/8) * i, -2^(7/8) * i
Therefore, the roots of the equation are:
z = 2^(1/8) * i, 2^(3/8) * i, 2^(5/8) * i, 2^(7/8) * i, -2^(1/8) * i, -2^(3/8) * i, -2^(5/8) * i, -2^(7/8) * i. z 8 +16i=0z⁸ = -16i z = 2^(1/8) * i, 2^(3/8) * i, 2^(5/8) * i, 2^(7/8) * i, -2^(1/8) * i, -2^(3/8) * i, -2^(5/8) * i, -2^(7/8) * i
Therefore, the roots of the equation are:
z = 2^(1/8) * i, 2^(3/8) * i, 2^(5/8) * i, 2^(7/8) * i, -2^(1/8) * i, -2^(3/8) * i, -2^(5/8) * i, -2^(7/8) * i.
First of all, we need to know that a polynomial equation of degree n has n roots and they may be real or imaginary. Roots are also known as zeros or solutions of the equation.If the degree of the polynomial is n, then it can be written as an nth degree product of the linear factors, z-a, where a is the zero of the polynomial equation, and z is any complex number. Therefore, the nth degree polynomial can be factored into the product of n such linear factors, which are known as the roots or zeros of the polynomial.In the given equations, we need to find the roots of each equation. In the first equation (5.1), we have z⁴ = -16 and z³ = 27. Therefore, the roots of the equation:
z⁴ + 16 = 0 are:
z = 2^(3/4) * i, 2^(1/4) * i, -2^(3/4) * i, -2^(1/4) * i.
The roots of the equation z³ - 27 = 0 are:
z = 3, -1.5 + (3^(1/2))/2 * i, -1.5 - (3^(1/2))/2 * i.
In the second equation (5.2), we need to find the roots of the equation z⁸ = 16i and z⁸ = -16i. Therefore, the roots of the equation z⁸ - 16i = 0 are:
z = 2^(1/8) * i, 2^(3/8) * i, 2^(5/8) * i, 2^(7/8) * i, -2^(1/8) * i, -2^(3/8) * i, -2^(5/8) * i, -2^(7/8) * i.
The roots of the equation z⁸ + 16i = 0 are also the same.
Thus, we can find the roots of polynomial equations by factoring them into linear factors. The roots may be real or imaginary, and they can be found by solving the polynomial equation.
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Sammy Speedster drives a truck for the Quick 'N Fast Delivery
Service. Every day he drives a route from Houston to San Antonio, a
distance of 200 miles. In his logbook, he keeps a record of the
amount of time it takes to drive the route.
what's a reasonable domain and range?
In this scenario, the domain would be the set of all possible values for the amount of time it takes Sammy Speedster to drive from Houston to San Antonio. Since he is driving on a daily basis, the domain could be considered a continuous range from zero to some maximum value, perhaps 10 hours.
It's possible that Sammy could complete the trip in less than 3 hours if he were driving at a very high speed, but this would not be a common occurrence. Therefore, a reasonable domain could be considered to be between 3 and 10 hours.
The range, on the other hand, would be the set of all possible distances that Sammy could drive in the allotted time. Since we know that the distance is a constant 200 miles, the range would simply be 200 miles. It's possible that Sammy could drive more than 200 miles in a day if he were assigned additional routes, but this would not be relevant to this scenario.
In summary, a reasonable domain for Sammy's logbook would be between 3 and 10 hours, and the range would be a constant 200 miles.
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HELP i’m confused can someone explain this please?
Answer:
intersecting lines will cross at the point
a stick has a length of $5$ units. the stick is then broken at two points, chosen at random. what is the probability that all three resulting pieces are shorter than $3$ units?
A stick has a length of 5 units and the stick is then broken at two points, chosen at random, then the probability that all three resulting pieces are shorter than 3 units is 16%.
Total length of the stick = 5 units
The stick is broken into pieces = 3
The equal length of the stick = 5/3
The equal length of the stick = 1.67
The probability that all three resulting pieces are shorter than 3 units = 2/5 × 2/5
The probability that all three resulting pieces are shorter than 3 units = 4/25
The probability that all three resulting pieces are shorter than 3 units = 0.16
The probability that all three resulting pieces are shorter than 3 units = 16%
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Test the claim that the proportion of people who own cats is significantly different than 70% at the 0.02 significance level. The null and alternative hypothesis would be: 0.7 Hop 0.7 Hop - 0.7 H:P < 0.7 HP >0.7 HP 0.7 HOP The test is: right tailed left-tailed two-tailed Based on a sample of 500 people, 62% wned cats The p-value is:
Test the claim that the proportion of people who own cats is significantly different than 70% at the 0.02 significance level. The p-value is 0.024.
The null and alternative hypotheses for the claim that the proportion of people who own cats is significantly different than 70% at the 0.02 significance level are:
H0: p = 0.7 (null hypothesis
)H1: p ≠ 0.7 (alternative hypothesis)
The test is a two-tailed test because the alternative hypothesis includes not equal to (<>) which means either p is less than 0.7 or greater than 0.7
Based on a sample of 500 people, 62% owned cats.
This means that the sample proportion, p = 0.62.
To calculate the p-value, we will use the z-test statistic.
The formula for calculating the z-test statistic is given as:
z = (p - P) / √(PQ/n) where P is the hypothesized proportion (P = 0.7), Q is the complement of P (Q = 1 - P), and n is the sample size.
Using the given values in the formula, we have; z = (0.62 - 0.7) / √(0.7 × 0.3 / 500) = -2.52
The p-value for a two-tailed test at 0.02 level of significance is obtained from the standard normal table.
The area in both tails beyond the z-score of 2.52 is 0.012.
Therefore, the p-value is:
p-value = 2 × 0.012 = 0.024
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How many five-letter words (technically, we should call them strings, because we do not care if they make sense) can be formed using the letters A, B, C,
Total number of five letter strings formed by A,B,C and D with repetitions allowed
={4x4x4x4x4 = 4 power 5 = 1024
Now, fix BAD in a string at one place then we have 2 more places to be filled with 4 letters, total number of such strings
=4x4=16
Here, BAD can be at any of the 3 positions,
Hence the total number of strings with BAD in it
= 3 x 16=48
Now, The total number of strings not containing BAD
=1024-48
=976
Using 26 letters, the number of 5-letter words that can be formed when the letters are different is determined as follows: 26P5 = 26 × 25 × 24 × 23 × 22 = 7883600 different words.
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which of the following is the equation logx4=-2 written in exponential form
1. The exponential form of the equation \(log_{x} 4 = - 2\) will be;
⇒ x⁻² = 4
2. The value of √e⁷/e⁵ will be;
⇒ e
3. The equivalent expression of 3 will be;
⇒ ln e³
What is an expression?
Expression in math is defined as the collection of the numbers, variables and functions by using signs like addition, subtraction, multiplication, and division.
Given that;
1. The expression is the equation \(log_{x} 4 = - 2\).
2. The equation is √e⁷/e⁵.
3. The number is 3.
Now,
The exponential form of the equation \(log_{x} 4 = - 2\) is calculated as;
\(log_{x} 4 = - 2\)
By the definition of logarithmic, we get;
4 = x⁻²
Hence, The exponential form of the equation \(log_{x} 4 = - 2\) will be;
⇒ x⁻² = 4
2. The equation is √e⁷/e⁵.
Solve as;
√e⁷/e⁵ = √ e ⁷ ⁻ ⁵
= √ e²
= e
Thus, The value of √e⁷/e⁵ will be;
⇒ e
3. Since, by the definition of logarithmic;
\(ln_{e} e = 1\)
So, By option 1;
\(ln_{e} e^3\) = \(1 * 3\) = \(3\)
Thus, The equivalent expression of 3 will be;
⇒ ln e³
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The cafeteria offered an apple a fruit choice six days out of ten days. which equivalent form of decimal, fraction, and/or percent is equivalent to the fraction of days the cafeteria offered an apple as a fruit choice?
6/10 is the fraction of days the cafetaria offered an apple as a fruit choice. The equivalent form of decimal is 0.6, the equivalent form of percentage is 60%, and the equivalent form of fraction is 3/5.
How do you prove that?6/10 is equal to 3/5 because 3/5 is the simplified form of 6/10. To simplify the fraction, determine the greatest common factor (GCF) of the numerator 6 and the denominator 10 first.
factors of 6: 1, 2, 3, 6factors of 10: 1, 2, 5, 10The GCF of 6 and 10 is 2. Therefore, you divide the numerator and the denominator by 2 to get the simplified form, like this: \(\frac{6}{10}=\frac{6\div 2}{10\div 2}=\frac{3}{5}\).
You can convert 6/10 to a decimal using long division:
0.6
10 / 6 0
6 0 -
0
6 divided by 10 is equal to 0.6. This is the decimal form of the fraction 6/10.
Finally, to get the percentage form, you can multiply the fraction by 10/10: \(\frac{6}{10}=\frac{6}{10}\times \frac{10}{10}=\frac{60}{100}=60\%\).
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Susie bought 14 dolls this week. Last week she had 28 dolls. Which of the
following equations could be used to determine how many dolls Susie
has now?
A. 28 − 14 = x
B. 28 + 14 = x
C. x + 14 = 28
D. x + 28 = 14
Answer:
B. 28 + 14 = x
Step-by-step explanation:
Susie bought 14 dolls this week. Last week she had 28 dolls. determine how many dolls Susie has now.
using this info we know that we must find the sum of both numbers.
Hence, Answer B has the correct equation
I need help on questions two lol pls help me
what happens to an inequality sign when the inequality is multiplied or divided by a negative number
When an inequality is multiplied or divided by a negative number, the inequality sign will flip, meaning it will change its direction. For example, if you have a > b and you multiply or divide both sides by a negative number, the inequality will become a < b. This is because the relationship between the values reverses when multiplied or divided by a negative number.
Explanation:
When an inequality is multiplied or divided by a negative number, the direction of the inequality sign is flipped. This is because multiplication or division by a negative number, results in a reversal of the order of the numbers on the number line.
To see why this happens, consider the following example:
Suppose we have the inequality x < 5. If we multiply both sides of this inequality by -1, we get -x > -5. Notice that we have flipped the inequality sign from "<" to ">". This is because multiplying by -1 changes the sign of x to its opposite, and also changes the sign of 5 to its opposite, resulting in a reversal of the order of the numbers on the number line.
Similarly, if we divide both sides of the inequality x > 3 by -2, we get (-1/2)x < (-3/2). Here, we have again flipped the inequality sign from ">" to "<". This is because dividing by a negative number also changes the order of the numbers on the number line.
In general, if we have an inequality of the form a < b or a > b, where a and b are real numbers, and we multiply or divide both sides by a negative number, we obtain:
If we multiply by a negative number, the inequality sign is flipped. For example, if a < b and c < 0, then ac > bc.
If we divide by a negative number, the inequality sign is also flipped. For example, if a > b and c < 0, then a/c < b/c.
Therefore, it is important to be mindful of the signs of the numbers involved when performing operations on inequalities. If we multiply or divide by a negative number, we must flip the direction of the inequality sign accordingly.
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In 1994, the sports league introduced a salary cap that limits the amount of money spent on players' salaries. The quadratic model y=0.2313x^2 + 2.600x + 35.17 approximates this cap in millions of dollars for the years 1994-2009, where x = 0 represents 1994 x = 1 represents 1995, and so on. Complete parts a and b.(A) Approximate the sports league salary cap in 2004.The approximate sports league salary cap in 2004 is $ 84.3 million(Completed)(Round to the nearest tenth as needed.)(B) According to the model, in what year did the salary cap reach 65 million dollars?According to the model, in ____ the salary cap reached 65 million dollars.(Round down to the nearest year.)Part A is completed so I just need help with Part B.
B) Given
\(y=0.2313x^2+2.600x+35.17\)Set y=65 and solve for x, as shown below
\(\begin{gathered} y=65 \\ \Rightarrow0.2313x^2+2.600x+35.17=65 \\ \Rightarrow0.2313x^2+2.600x-29.83=0 \end{gathered}\)Then, solve the quadratic equation using the quadratic formula,
\(\begin{gathered} x=\frac{-2.600\pm\sqrt{(2.600)^2-4*0.2313*-29.83}}{2*0.2313} \\ \Rightarrow x=-18.2915,7.05065 \end{gathered}\)The function is not valid for negative values of x; therefore, the solution can only be x=7.05065 which can be rounded to x=7. Furthermore, x=7 corresponds to the year 2001. The answer to part B is 2001.
The level of significance in hypothesis testing is the probability of
a. accepting a true null hypothesis
b. accepting a false null hypothesis
c. rejecting a true null hypothesis
d. could be any of the above, depending on the situation
9. (1 point)
In hypothesis testing, the critical value is
a. a number that establishes the boundary of the rejection region
b. the probability of a Type I error
c. the probability of a Type II error
d. the same as the p-value
The level of significance in hypothesis testing is the probability of: c. rejecting a true null hypothesis. In hypothesis testing, the critical value is:
a. a number that establishes the boundary of the rejection region.
Probability is a branch of mathematics in which the chances of experiments occurring are calculated. It is by means of a probability, for example, that we can know from the chance of getting heads or tails in the launch of a coin to the chance of error in research. In statistics , a null hypothesis is a statement that one seeks to nullify with evidence to contrary most commonly it is a statement that the phenomenon being studied produces no effect on makes no difference.
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x+(-4)=-12 111111111
Answer:x+(-4)=12 the answer is 8
Step-by-step explanation:
Answer:
can you please explain the different way
Step-by-step explanation:
13. The company you work for has downsized and you have lost your job. You receive a severance package of $65 000 and decide to invest it for retirement, earning an average of 7% per year. It has been suggested that you should be able to retire comfortably with $500 000 in savings. If your investment can be modelled with the equation y = 65000(1.07)^x how many years will pass before you reach $500 000?
Answer:
31 years
Step-by-step explanation:
65000*(1.07) ^31 is around $529000
however, 65000*(1.07) ^30 is around $491000
so you would need 31 years to gain more than $500,000.
It will take approximately 30 years to reach $500,000 in savings with an investment that earns an average of 7% per year.
To determine the number of years it will take to reach $500,000 in savings with an investment that earns an average of 7% per year, we can use the given investment model equation: y = 65000(1.07)ˣ.
We need to find the value of x, which represents the number of years.
Setting y = $500,000, we can solve for x:
500,000 = 65,000(1.07)ˣ
500,000/65,000 = (1.07)ˣ
100/13 = (1.07)ˣ
To solve for x, we take the logarithm of both sides:
ln 100/13 = ln (1.07)ˣ
ln 100/13 = x ln (1.07)
x = (ln 100/13)/(ln (1.07))
x = 30
Therefore, it will take approximately 30 years to reach $500,000 in savings with an investment that earns an average of 7% per year.
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Solve problems 1 and 4 ONLY with the rules given on the paper.
The solution to the equations obtained using inverse trigonometric function values are;
1. x ≈ 0.65
4. x ≈ 0.95
What are trigonometric functions?Trigonometric functions indicates the relationships between the angles in a right triangle and two of the sides of the triangle. Trigonometric functions are periodic functions.
The value of x is obtained from the inverse trigonometric function of the output value of the trigonometric function, as follows;
The inverse function for sine is arcsine
The inverse function for cosine is arccosine
The inverse function for the tangent of an angle is arctangent
1. sin(x) = 0.6051
Therefore; x = arcsine(0.6051) ≈ 0.65 radians
The value of x in the interval [0·π, 2·π] is x ≈ 0.65
4. tan(x) = 1.3972
Therefore, x = arctan(1.3972) ≈ 0.95
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(-4z+1) (5z-2)=
solution plz.
Answer:
-20z² + 13z - 2.
Step-by-step explanation:
hello !
you use the F.O.I.L method to multiply these two. first, you multiply the first terms, which are:
(-4z)(5z) = -20z²
then, the outside terms, which are:
(-4z)(-2) = 8z
then, the inside terms, which are:
(1)(5z) = 5z
then, lastly, the last terms, which are:
(1)(-2) = -2
Therefore, we get:
-20z² + 8z + 5z - 2.
combine like terms, and the answer is:
-20z² + 13z - 2.
Can the triangles be proven similar using the SSS or SAS?
The triangles ΔKLM and ΔEFG can be proven similar using both SSS and SAS similarity theorems.
In this question, we need to determine whether the triangles can be proven similar using the SSS or SAS similarities theorems.
For given diagrams,
the ratio of the corresponding sides is:
KM/EG = 8/24
= 1/3
KL/EF = 6/18
= 1/3
and ML/GF = 5/15
= 1/3
The sides of both triangles is proportional .
So by SSS similarity theorem, we have ΔKLM ≈ ΔEFG
Also, ML/GF = 1/3
∠L ≅ ∠F
KL/EF = 1/3
So by SAS similarity theorem, we have ΔKLM ≈ ΔEFG
Therefore, the triangles can be proven similar using both SSS and SAS
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The figure associated to given question is as shown below.
Select the correct answer.Solomon is planning to recover a lampshade. How much fabric does he need?12 cm16 cm12 cmA. 912 cm²B. 2,304 cm²C. 768 cm²D. 1;056 cm²
Answer:
C - 768cm for Plato
Step-by-step explanation:
Students were surveyed to determine what they are most afraid of. The results are shown in the bar graph below
30
25
20
15
10
5
07
What is the average number of students who are afraid of spiders and snakes?
09
O 15
Spiders Snakes Public Flying
Speaking
O 30
The
Dark
From the given bar graph, the average number of students who are afraid of spider and snakes is of 15.
What does a bar graph show?A bar graph shows the absolute frequency of each observation in the data-set, that is, the number of times that each variable is observed.
Hence, in the context of this problem, from the bar graph on the image, the number of students that are afraid of each thing are:
Spiders: 18.Snakes: 12.Public Speaking: 25.Flying: 10.The Dark: 15.The average between two values is given by the sum of the two values divided by two.
Hence, the average number of students who are afraid of spiders and snakes is calculated as follows:
M = (18 + 12)/2 = 30/2 = 15.
Missing InformationThe bar graph is missing and is given by the image at the end of the answer.
More can be learned about bar graphs at https://brainly.com/question/24741444
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Answer:
15
Step-by-step explanation:
got it right on quiz
please hand solve and show steps
(a) Find the dual of the LP .
(b) Find the standard form of the LP and dual.
(c)Optimal solution for the primal problem is: x ∗ 1 = 20, x∗ 2
= 60, s∗ 1 = 0, s∗
objective m constraints n decision variables Consider the following LP. Primal and Dual pair min b₁y₁+ max C₁x₁++GX+ CnXn 8/1X1 +2X2 + + ax ≤ bi ax1 + a2x2 + +anxn bi a/1X1 + a2x2 + +anxn 2
(a) Find the dual of the LP.Primal problem isminimize \($b_1y_1+C_1x_1+...+C_nx_n$\) subject to \($a_{11}x_1+a_{12}x_2+...+a_{1n}x_n \leq\) \(b_1$...$a_{m1}x_1+a_{m2}x_2+...+a_{mn}x_n \leq b_m$ and $x_1, x_2,\)..., x_n\(\geq 0$\)
Let us find the dual of the above primal problem.
Dual problem ismaximize \($b_1y_1+...+b_my_m$\)subject to \($a_{11}y_1+a_{21}y_2+...+a_{m1}y_m \leq\)\(C_1$...$a_{1n}y_1+a_{2n}y_2+...+a_{mn}y_m \leq C_n$\)
and\($y_1, y_2, ..., y_m \geq 0$\)
(b) Find the standard form of the LP and dual.Standard form of the primal problem isminimize \($b_1y_1+C_1x_1+...+C_nx_n$\)subject to \($a_{11}x_1+a_{12}x_2+...+a_{1n}x_n +s_1 = b_1$...$a_{m1}x_1+a_{m2}x_2+...+a_{mn}x_n +s_m = b_m$\) and\($x_1, x_2, ..., x_n, s_1, s_2, ..., s_m \geq 0$\)
Standard form of the dual problem ismaximize \($b_1y_1+...+b_my_m$\)subject to \($a_{11}y_1+a_{21}y_2+...+a_{m1}y_m \leq 0$...$a_{1n}y\)
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