Trucks stopping on a wet or slippery surfaces can increase stopping distance by how much?

Answer: In the direction of the first car.

Explanation:

Let the initial velocity of the first car be equal to U1 and the initial velocity of the second car be equal to U2

Given that the car is travelling with a positive velocity, and after it collides with another car moving with a negative velocity, the momentum before collision will be

M1U1 - M2U2

If the first car is still moving with a positive velocity, the second car will also be moving in the direction of the first car if the collision is inelastic collision.

Therefore, the direction of the second car will be positive direction if the collision is inelastic collision.

The three pairs of equal part in Triangles ADB and ADC are:

AB=AC

BD=CD

Angle B= Angle C

AB = AC in both triangles indicates that the lengths of these sides are identical. To put it differently, the length of the side opposite angle B in triangle ADB is equivalent to the length of the side opposite angle C in triangle ADC.

The equality of BD and CD in the two triangles signifies that these two sides have identical lengths. This implies that the length of the adjacent side to angle B in triangle ADB is the same as the length of the adjacent side to angle C in triangle ADC.

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The presence of raw sewage in surface waterways can be determined by measuring biochemical oxygen demand (BOD). This is a measure of the amount of oxygen used by microbes in decomposing organic matter.

In water contaminated with raw sewage, there is an abundance of organic matter that is broken down by bacteria, resulting in high levels of BOD. High BOD levels indicate an increased amount of organic matter in the water, indicating the presence of raw sewage. In addition, when BOD levels are high, the oxygen levels in the water decrease, which can be detrimental to fish and other aquatic organisms.

Therefore, measuring BOD is an effective way to determine if raw sewage is present in surface waterways.

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The statement is true, the gravitational force that Pluto exerts on Charon acts as a centripetal force for Charon to be able to orbit around Pluto. This is because centripetal force is the force that keeps an object moving in a circular path.

In the case of celestial bodies, such as Pluto and Charon, their mutual gravitational attraction serves as the centripetal force that keeps Charon in its orbit around Pluto. As Charon orbits Pluto, it is constantly changing its direction of motion, which means there is an acceleration towards the center of its circular path (Pluto). This acceleration requires a force, and in this case, that force is the gravitational pull between Pluto and Charon. The gravitational force ensures that Charon maintains its circular orbit and doesn't fly off into space or crash into Pluto.

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Answer:

Problem 1-

The acceleration = 5 m/s²

Problem 2 -

The acceleration = 3.\(\overline 3\) m/s²

Problem 3 -

The acceleration = 2.5 m/s²

Problem 4-

The force applied = 7.5 N

Problem 5-

The mass of the object,  = 0.5 kg.

Explanation:

Problem 1-

The mass of the ball, m = 0.5 kg

The force (applied) with which it was hit, F = 2.5 N

The acceleration, a = Force/Mass = 2.5 N/(0.5 kg) = 5 m/s²

The acceleration = 5 m/s²

Problem 2 -

The mass of the box, m = 15 kg

The force (applied) with which it was hit, F = 50 N

The acceleration, a = Force/Mass = 50 N/(15 kg) = 10/3 = 3.\(\overline 3\) m/s²

The acceleration = 3.\(\overline 3\) m/s²

Problem 3 -

The mass of the object, m = 2.0 kg

The force (applied) with which it was hit, F = 5.0 N

The acceleration, a = Force/Mass = 5.0 N/(2.0 kg) = 2.5 m/s²

The acceleration = 2.5 m/s²

Problem 4-

The mass of the object, m = 3.0 kg

The acceleration, a, of the object = 2.5 m/s²

The force applied to it, F = Mass × Acceleration = 3.0 kg × 2.5 m/s² = 7.5 N

The force applied = 7.5 N

Problem 5-

The acceleration, a, of the object = 12 m/s²

The force applied, F = 6.0 N

The mass of the object, m = Force/Acceleration = 6.0 N/(12 m/s²) = 0.5 kg

The mass of the object,  = 0.5 kg.

Answer:

17.56 N

Explanation:

Given that,

Mass of a crate, m = 5 kg

It is on a 21.0° hill

We need to find the y component of the weight.

y component = mgsinθ

Put all the values,

y-component = 5×9.8×sin(21)

= 49×sin(21)

= 17.56 N

So, the y-component of the weight is 17.56 N.

Answer:

-45.745

Explanation:

it is negative because it is downwards.

Based on the given options, the advantage that the calculations suggest electrons have compared to photons is to obtain the same level of resolution, electrons require multiple orders of magnitude less energy than photons. The correct answer is option 2.

This is because the wavelength of electrons is much smaller than that of photons, which means that electrons can be used to observe smaller objects or features with higher resolution than photons. Additionally, electrons have a charge, which means that they can be focused using magnetic fields, allowing for even higher resolution. This is the principle behind electron microscopes, which can achieve much higher magnification and resolution than optical microscopes that use photons. So option 2 is correct.

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--The complete Question is, what advantage do your calculations suggest electrons have compared to photons?

1. using photons with a microscope distorts the image due to the relativistic effect of length contraction, whereas using electrons does not shrink the image, because their speed is only about a tenth the speed of light.

2. to obtain the same level of resolution, electrons require multiple orders of magnitude less energy than do photons.

3. electrons can provide a clearer image than photons at the same magnification because their momenta impact observed particles less than photons' momenta.

4. an electron's charge allows it to attach to observed particles, whereas a photon's electric neutrality prevents it from moving close enough to the observed particles to keep them in focus. --

The correct statement regarding the double-slit test is a process wherein you possibly can display the wave nature of light.

Via feeding mild of the appropriate wavelength through a couple of slits with separation distances corresponding to the light wavelength, then interference styles will occur with various intensities that reduce as one measure in addition to the slits. If the slit together with the light supply is moved in the direction of the double slits, the brilliant fringes produced are brighter because the depth of the light passing through the double slit is more.

As the wave passes through each slit, it basically splits into two new waves, every spreading out from one of the slits. these two waves then intrude on each other. At some factors, in which a top meets a trough, they will cancel each different out. The smaller the wavelength is to the slits the nearer the fringes could be. were W=wavelength, D=distance from the slit to the display a=distance among the slits and x is the space between the slits. So x=WD/a in order for the wavelength to decrease so does the perimeter spacing.

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Answer:

480

Explanation:

resistance equals to potential difference divide by electric current

120÷0.25

=480

Answer:

\(\mathsf {480 \Omega}\)

Explanation:

\(\textsf {Formula used for calculating resistance :}\)

\(\mathsf {Resistance = \frac{Voltage}{Current} }\)

\(\textsf {This is otherwise known as Ohm's Law, hence the unit of resistance.}\\\)

\(\textsf {Solving :}\)

\(\implies \mathsf {R = \frac{120}{0.25}}\)

\(\implies \mathsf {R = 480\Omega}\)

\(\textsf{If the fan uses higher current at higher speeds, then}\\\textsf{the resistance would decrease as it is inversely}\\\textsf {proportional to the current.}\)

Answer:

The joule is the standard unit of energy in electronics and general scientific applications. One joule is defined as the amount of energy exerted when a force of one newton is applied over a displacement of one meter. One joule is the equivalent of one watt of power radiated or dissipated for one second.

Hope it helps ^^

Option a. When the elevator reaches the 1st floor and comes to a halt, your apparent weight will be less than your true weight.

The apparent weight of an object in an elevator is affected by the force of gravity, the mass of the object, and the acceleration of the elevator. In this case, the elevator is decelerating from the 50th floor to the 1st floor, which means the acceleration is negative. When the elevator reaches the 1st floor and comes to a halt, your apparent weight will be less than your true weight.

To illustrate this concept, consider Newton's Second Law of Motion which states that

Force = Mass x Acceleration (F = ma).

In this case, the force exerted by gravity on the object remains the same (its true weight) but the acceleration changes as the elevator descends. As the acceleration decreases, the apparent weight decreases accordingly.

Therefore, option a is correct.

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The area which touches the sand floor of 4 feet of the bull is less than the man.

because the area of surface of contact is more in bull than in man. More is the area of contact, leads is the force or pressure affected.

Answer:

kinetic energy

Explanation:

I know the answer because Im built differen

Work is equal to energy. Since your braking distance is 10.8 m. you will not stop before you hit the oil spill

Energy is the ability to do work. The work done on an object is tantamount to energy used on the object.

If you are first place in Mario Kart at the moment. Your 5.0 kg Mario Kart is moving at 5.5 m/s when you see an oil spill 10 m ahead. If your maximum braking force is 7.0 N, will you stop before you hit the oil spill? What is your braking distance?

By using the concepts of work and energy, that is,

1/2mv² = F × s

Where

Substitute all the parameters into the formula

1/2 × 5 × 5.5² = 7 × s

75.625 = 7s

s = 75.625/7

s = 10.8 m

Since the calculated distance is greater than the given distance (10 m), you will not stop before you hit the oil spill. And your braking distance will be 10.8 m

Therefore,  you will not stop before you hit the oil spill.

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Answer: Soils with smaller particles (silt and clay) have a larger surface area than those with larger sand particles, and a large surface area allows a soil to hold more water. In other words, a soil with a high percentage of silt and clay particles, which describes fine soil, has a higher water-holding capacity.

Silty clay loam: 1.80-2.00

Texture: Inches of water storage per foot of soil .

Explanation: hope this helps!!!!

When amplitude of motion increases to 2a the time period remains the same.

The formula for spring mass system is given by

                          T = 2π√m/k

 where,            k = spring constant

                         m= mass of spring

                         T = time period

So, from here we get to know that time period is independent of amplitude, so we increase or decrease the amplitude of system there will be no effect on Time period of spring mass system.  

Thus, when amplitude of motion increases to 2a the time period remains the same.  

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Answer:

V = 61.74m/s

Explanation:

Given the following data;

Acceleration due to gravity = 9.8m/s²

Time, t = 6.3 secs

Since it's a free fall, initial velocity = 0

Thus, to find the final velocity, we would use the first equation of motion;

\( V = U + at\)

Substituting into the equation, we have;

\( V = 0 + 9.8 * 6.3\)

V = 61.74m/s

Therefore, the final velocity is 61.74m/s

The answer is 200 joules.

Answer:

Its answer is 200joule.

Explanation:

Hope it's helpful for you

The answer would be B.) Electric Energy

Answer:

b.electric energy

we need electric energy to make the heater work.

Explanation:

I hope it helped U

stay safe stay happy

Explanation:

Hey there!

Here,

Pascal is a unit of pressure.

\(pressure = \frac{f}{a} \)

Now, As per the formula the units are:

kg, m and s^2.

Hope it helps...

Answer:

positions of motion is the answer as moving is a motion

the initial speed that the kid gave the rock when throwing it downward is approximately 5.75 m/s.

To determine the initial speed that the kid gave the rock when throwing it down, we can use the equations of motion for free fall.

When the rock is dropped:

The time taken (t) is 4.0 seconds, and we assume the initial velocity (u) is 0 (since the rock was dropped without an initial upward or downward velocity). We can use the equation:

s = ut + (1/2)gt^2

where s is the distance fallen, u is the initial velocity, t is the time taken, and g is the acceleration due to gravity.

When the rock is thrown:

The time taken (t) is 3.0 seconds, and we need to find the initial velocity (u). We can use the same equation as above:

s = ut + (1/2)gt^2

Since the rock was thrown downward, the initial velocity (u) will be negative.

Now, we can set up the equations:

For dropping the rock:

0 = 0 + (1/2)g(4.0)^2

For throwing the rock:

s = ut + (1/2)gt^2

Substituting the given values:

s = ut + (1/2)gt^2

0 = u(3.0) + (1/2)g(3.0)^2

Simplifying the equations:

(1/2)g(4.0)^2 = (3.0)u + (1/2)g(3.0)^2

8g = 6u + 4.5g

Rearranging the equation:

6u = 8g - 4.5g

6u = 3.5g

Dividing both sides by 6:

u = (3.5g) / 6

Substituting the approximate value for the acceleration due to gravity (g ≈ 9.8 m/s^2):

u ≈ (3.5 * 9.8) / 6

Calculating the value:

u ≈ 5.75 m/s

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PE = 6.40625 J

Pre-Algebra

Order of Operations: BPEMDAS

Energy

SI Unit: Newton per meter N/m = Joules J

Elastic Potential Energy:  PE = 1/2k(Δx)²

Step 1: Define

Spring Constant K = 205 N/m

Δx = 0.25 m

Step 2: Find Potential Energy

Our Potential Elastic Energy would be 6.40625 Joules.

Answer:

\(\boxed {\boxed {\sf 6.40625 \ Joules}}\)

Explanation:

Elastic potential energy can be found using the following formula.

\(U=\frac{1}{2} kx^2\)

Where U is the elastic potential energy, k is the elasticity constant, and x is the extension/spring stretch length.

We know the elasticity constant is 205 N/m and the spring is deformed by 0.25 meters.

\(k= 205 \ N/m \\x=0.25 \ m\)

Substitute the values into the formula.

\(U=\frac{1}{2}(205 \ N/m) *(0.25 \ m )^2\)

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

First, solve the exponent.

\(U=\frac{1}{2} (205 \ N/m)(0.0625 \ m^2)\)

Multiply 205 and 0.0625.

\(U=\frac{1}{2}(12.8125 \ N/m)\)

Multiply 12.8125 and 1/2 or divide 12.8125 by 2.

\(U=6.40625 \ N/m\)

\(U= 6.40625 \ J\)

The elastic potential energy is 6.40625 Joules.

Answer:

The reading will be the same.

Explanation:

Mass does not depend upon anything and it remains the same anywhere. What changes is the weight of the body because it depends upon gravity and is different at different places.

Giving me the brainest will be helpful.

The reading on the scale during free-fall will be the same. reading on the scale is independent of the external environment.

A weighing scale known as a balance is a device used to quantify weight or mass. The classic scale is made up of two plates or bowls that are suspended at equal distances from a fulcrum.

A person with a mass of 70kg is standing on a scale in an elevator suddenly the cable snaps, The reading on the scale during free-fall will be the same as the initial elevator condition.

Hence the reading on the scale during free-fall will be the same. reading on the scale is independent of the external environment.

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Answer:

The graph for 7a is shown in the attachment. For question 7b she walks a distance of 16 meters. (m)

Explanation:

Answer:

Alpha decay forms new element with two fewer protons and two fewer neutrons, Beta decay forms new element with one more proton and one fewer neutron. Gamma decay forms NO new element, but now the element has less energy because energy is released as gamma rays.

Explanation:

ANSWER AND EXPLAINATION:
Gamma decay differs from alpha and beta decay in several ways:

1. Particle emitted: In gamma decay, no particles are emitted. Instead, a high-energy photon called a gamma ray is released. Alpha decay involves the emission of an alpha particle, which consists of two protons and two neutrons. Beta decay involves the emission of either a beta-minus particle (an electron) or a beta-plus particle (a positron).

2. Mass and charge: Gamma decay does not change the mass or atomic number of the nucleus since no particles are emitted. Alpha decay reduces the atomic number by 2 and the mass number by 4, as an alpha particle is emitted. Beta decay changes the atomic number, with beta-minus decay increasing it by 1 and beta-plus decay decreasing it by 1. The mass number remains the same in beta decay.

3. Penetrating power: Gamma rays have the highest penetrating power among the three types of decay. They can pass through most materials and require dense shielding (e.g., lead or concrete) to attenuate them. Alpha particles have low penetrating power and can be stopped by a sheet of paper or a few centimeters of air. Beta particles have intermediate penetrating power and can be stopped by a few millimeters of aluminum.

4. Energy release: Gamma decay releases energy in the form of high-energy photons. Alpha decay releases a significant amount of energy since an alpha particle carries substantial kinetic energy. Beta decay releases energy in the form of the kinetic energy of the emitted beta particle.

gamma decay is a process that involves the emission of high-energy photons, while alpha and beta decay involve the emission of particles with mass and charge. Gamma rays have higher penetrating power and do not cause changes in the mass or atomic number of the nucleus, distinguishing them from alpha and beta particles.