The vector 2A has
A. twice the magnitude and opposite
direction as vector A.

B. same magnitude and twice the direction
of vector A.

C. twice the magnitude and twice the
direction of vector A.

D. twice the magnitude and the same
direction as vector A.

The baseball can be spun at a maximum speed of approximately 3.45 m/s before the tension in the string exceeds 7.7 N and causes the string to break.

The baseball of mass m = 0.55 kg spun vertically on a massless string of length l = 0.85 m with a maximum tension of t(max) = 7.7 N:

First, we need to find the maximum speed at which the baseball can be spun before the string breaks. We will use the formula for centripetal force: F(c) = mv² / r, where F(c) is the centripetal force, m is the mass, v is the linear speed, and r is the radius (equal to the length of the string in this case).

We know that the maximum tension,t(max) is equal to the centripetal force at the point of breaking, F(c) = t(max), so we can rewrite the equation as:

t(max) = mv² / r

Now, we can plug in the given values:

7.7 N = (0.55 kg) * v² / 0.85 m

To solve for v, first, multiply both sides of the equation by 0.85 m:

6.545 kg*m²/s² = 0.55 kg * v²

Now, divide both sides by 0.55 kg:

11.9 m²/s² = v²

Finally, take the square root of both sides:

v ≈ 3.45 m/s

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Answer:

The force the man applied is 80 N

Explanation:

weight of the load, L = 800 N

distance traveled by the load, a = 10 m

distance traveled by the effort, b = 100 m

Output work = load x distance moved by the load

Output work = 800 x 10 = 8000 J

Input work = Effort x distance moved by effort

Input work = Effort x 100 m

Assuming an ideal machine; no friction effect, the input work will be equal to output work.

Effort x 100 m = 8000 J

Effort = 8000 / 100

Effort = 80 N

Therefore, the force the man applied is 80 N

The electrical force between 2 objects is 400 N. According to Coulomb's law, if both charges are doubled, the electrical force will be 1600 N.

The electrical force between 2 charged objects is directly proportional to their charges and inversely proportional to the square of the distance between them.

The electrical force between 2 objects is 400 N. Due to the direct proportionality, if the charge of both objects is doubled (multiplied by 2), the total force will be multiplied by 4.

F = 2 × 2 × 400 N = 1600 N

The electrical force between 2 objects is 400 N. According to Coulomb's law, if both charges are doubled, the electrical force will be 1600 N.

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The appearance of a sight glass filled with vapor and liquid is different, and they can be distinguished based on their transparency or opacity. false

A sight glass that is full of vapor or liquid does not look the same.
In a sight glass, which is a transparent window or tube used to visually inspect the contents of a system, the appearance will vary depending on whether it is filled with vapor or liquid.
When the sight glass is filled with vapor, it will appear as a transparent or translucent gas. The vapor may be less dense and may not fill the entire sight glass, allowing visibility through it.
On the other hand, when the sight glass is filled with liquid, it will appear as a continuous, opaque fluid. The liquid will block visibility through the sight glass, and its level or presence can be clearly observed.
Therefore, the appearance of a sight glass filled with vapor and liquid is different, and they can be distinguished based on their transparency or opacity.

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Answer: it's a scorching hot temperature with a smaller core

Explanation:

                             .

................

.

.

.

                                .

The average velocity is given by

Where d is the distance covered and t is the time taken.

For the given case, we have

d = 75 m

t = 8.9 s

Therefore, the average speed of the hockey player is 8.43 m/s

The hockey player is moving at a speed of 9.5 m/s.

When light travels in a certain medium and falls on the surface of another medium a part of it turns back in the same medium This phenomenon is called Reflection.

A wavefront may alter its course at an interface between two different media and return to the first medium, a phenomenon known as reflection. Common examples are the reflection of light, sound, and water waves.

Reflection of light refers to the occurrence where light strikes an item and bounces back off its surface. Examples: using a flat mirror to reflect. by a spherical mirror's reflection. There are essentially two types of reflection that apply to light. While diffuse reflection is caused by rough surfaces that tend to reflect light in all directions, specular reflection is described as light reflected off a smooth surface at a specific angle.

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Answer:

Option (b).

Explanation:

Two forces are acting perpendicularly on an object. We have, F₁ = 8.2 N and F₂ = 20.6 N

We need to find the net force acting on the object. When two forces are acting in perpendicular to each other, the net force on it is given by :

\(F=\sqrt{F_1^2+F_2^2} \\\\=\sqrt{8.2^2+20.6^2} \\\\=22.17\ N\)

or

F = 22 N

Let \(\theta\) is the angle. It can be given by :

\(\tan\theta=\dfrac{F_1}{F_2}\\\\\tan\theta=\dfrac{8.2}{20.6}\\\\=21.7^{\circ}\)

or

\(\theta=22^{\circ}\)

So, the net force is 22 N and the direction is 22° counterclockwise from F₁. Hence, the correct option is (b).

East to West is the direction of the current. One meter below the electricity line is the point. Consequently, the magnetic field is directed southward in accordance with Maxwell's right-hand thumb rule.

By using the right-hand thumb rule, we may determine that the magnetic field is going from north to south at a position below the wire. Just above the wire, the magnetic field is oriented from south to north.

As a result, in this instance, the fingers at a position above will point north while the thumb points from east to west. Hence, the magnetic field will point northward.

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Answer:

potentiometer is a device used to measure potential difference across the circuit

Answer:

because they are not standard unit(accepted globally)

Explanation:

hope its help

Because outside of your local group, nobody will know what you're talking about.

My people originally used the sha'ah, yom, and khelek for time, the amah for length, the tchum shabbat for distance, and the epha, omer, baytsa, log, and kazayit for volume.

See what I mean ?

Answer:

Explanation:

I think that you to run more than 12 miles

Answer:

Explanation:

We know the frequency and the velocity, both of which have good units. All we have to do is rearrange the equation and solve for

λ

:

λ

=

v

f

Let's plug in our given values and see what we get!

λ

=

340

m

s

440

s

−

1

λ

=

0.773

m

Answer: Force

In physical science, a force is something that acts on an object by pushing or pulling it. If the force is strong enough, it changes the position or shape of the object. Forces such as friction, air resistance and simple physical contact touch the object directly, while forces like gravity, magnetism and electrostatics act on the object from a distance. Force is a vector quantity, meaning you can measure both its strength and its direction. The formula to find the measure of a force is force = mass times acceleration, written as f = ma.

Velocity

The faster something is moving, the higher its velocity.

When an object is moving, one way to measure how fast it is moving is by finding its velocity, which is the rate at which it is changing position. Like force, velocity is a vector quantity, so it includes direction. To find the average velocity of an object, divide the change in its position by the time the movement took, and state its direction. For example, if a car is driving north and in one hour's time it travels 30 miles, its velocity is 30 miles per hour, north.

\_:Peepato1234:_/

Answer:

b

Explanation:

Answer:

B

Explanation:

We can confirm that Dylan was pushing back with a force of at least 221N, and it would take 18 students to push Dylan if she was withstanding 300N.

This has to do with the force being applied by each student. The question states that the students were each applying a force of 17 N , and Dylan will be withstanding 300, so we can divide these numbers and round up to arrive at the number of students needed, which equates to 18 students.

Therefore, we can confirm that Dylan was pushing back with a force of at least 221N, and it would take 18 students to push Dylan if she was withstanding 300N.

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Answer:

Vf = Vi + a t       fundamental equation

-60 m/s= Vi - 9.8 m/s^2 * 6 sec      taking upward direction as positive

Vi =58.8 m/s - 60  m/s = -1.2 m/s   so the coin was initially thrown downward

As a check take the downward direction as positive

Vf = 1.2 m/s + 58.8 m/s = 60 m/s  

Answer:

4.61 seconds

Explanation:

Given data

Initial velocity= 12m/s

acceleration= -2.6m/s^2

From the given data

we can find the time t

we know that

Acceleration= velocity/time

time= velocity/acceleration

time= 12/2.6

time= 4.61 seconds

Answer: coefficient of friction, ratio of the frictional force resisting the motion of two surfaces in contact to the normal force pressing the two surfaces together. It is usually symbolized by the Greek letter mu (μ). Mathematically, μ = F/N, where F is the frictional force and N is the normal force.

Explanation:

The amount of heat that is gained by water is equal to the amount of heat loss by the ice. Therefore, we have the following relationship:

Where "Qw" is the heat of water and "Qi" is the heat of ice. The heat of water is given by:

The amount of heat of ice must be calculated for the two states, solid and liquid. For the solid-state the temperature will be from -30 degrees to 0 degrees, therefore, we have:

Where Ci is the specific heat of ice in solid-state and is equal to:

Replacing the values:

Solving the operations we get:

Now we need to determine the amount of heat that needs the ice to convert into liquid. This is given by:

Lf is the latent heat of ice and is equal to:

Replacing the values we get:

Solving the operations:

Now we need the amount of heat of liquid ice to its final temperature, this is given by:

Applying the relationship:

Cw is the specific heat of water and is equal to:

And the specific heat of ice is:

Replacing the values. The first two terms on the right side we already calculated and the final temperature is the same for both:

Solving operations:

Now we solve for the final temperature:

Subtracting 19835 to both sideS:

Now we add 1673Tf to both sides:

Now we divide both sides by 1882.2

Therefore, the final temperature is 20.57 °C. This value can be converted into Kelvin using the following relationship:

Replacing the temperature:

Therefore, the final temperature is 293.72 K.

So, the car's speed after it has traveled 25 meters is most nearly 22.36 m/s.

The equation for acceleration is a = (v_f - v_i) / t, where a is acceleration, v_f is final velocity, v_i is initial velocity (in this case, zero), and t is time. We know that a = 10 m/s^2 and we want to find v_f after the car has traveled 25 meters. So we need to rearrange the equation to solve for v_f:

a = (v_f - v_i) / t
10 m/s^2 = (v_f - 0) / t
10 m/s^2 * t = v_f

Now we need to find t. We can use the equation d = v_i * t + 1/2 * a * t^2, where d is distance. We know that d = 25 meters, v_i = 0, and a = 10 m/s^2, so we can plug those values in and solve for t:

25 meters = 0 * t + 1/2 * 10 m/s^2 * t^2
25 meters = 5t^2
t^2 = 5 meters
t = sqrt(5) meters (since t has to be positive)

Now we can plug in t to find v_f:

v_f = 10 m/s^2 * sqrt(5) meters
v_f = 22.36 m/s (rounded to two decimal places)

So the car's speed after it has traveled 25 meters is most nearly 22.36 m/s.
A car initially at rest accelerates at 10 m/s² and travels 25 meters. To find its speed after traveling this distance, we can use the equation:

v² = u² + 2as

where v is the final velocity, u is the initial velocity (0 m/s in this case), a is the acceleration (10 m/s²), and s is the distance traveled (25 m).

v² = 0² + 2(10)(25)
v² = 0 + 500
v² = 500

Now, we'll take the square root of both sides to find the final velocity:

v = √500
v ≈ 22.36 m/s

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The acceleration of a particle is a= (-1.6 v1/2) m/s². The initial velocity of the particle is u = 8 m/s.

Now, let's use the formula: 2as = v² - u², where a = (-1.6v^(1/2)) m/s², u = 8 m/s, and v = 0 m/s 2 × (-1.6v^(1/2)) × s = 0 - 8²s = 64 / (2 × 1.6v^(1/2)) = 20v^(1/2)/4 = 5v^(1/2) meters.

This is the distance travelled by the particle before it stops.

We know that the final velocity of the particle is 0 m/s. The initial velocity of the particle is 8 m/s.

The acceleration of the particle is a = (-1.6v^(1/2)) m/s².

Let's use the formula to calculate the time it takes to stop the particle. It is:v = u + at 0 = 8 + (-1.6v^(1/2)) × t t = 8 / (1.6v^(1/2)) t = 5 / v^(1/2) seconds.

This is the time taken by the particle to come to rest.

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The particle travels approximately 12.5 meters before it comes to a stop. It takes approximately 5 seconds for the particle to reach zero velocity.

To determine the distance traveled before the particle comes to a stop, we need to integrate the velocity function over time. The given deceleration is expressed as a = -1.6√v , where v is the velocity in m/s. Since the initial velocity is 8 m/s, we can write the deceleration as a = -1.6√8. Integrating the acceleration with respect to velocity gives us the equation: ∫dv/(-1.6√v ) = ∫dt. Simplifying the integral and solving for t gives us t = 5 seconds.

To find the distance traveled, we integrate the velocity function with respect to time. The velocity function is given by dv/dt = -1.6√v. Separating variables and integrating, we get ∫dv/√v  = ∫-1.6dt. Evaluating the integral and substituting the limits (from v = 8 m/s to v = 0), we find √v = -1.6t + C. Applying the initial condition v(0) = 8, we can solve for C and obtain C = √8. Plugging in the values for t and C, we get √v = -1.6t + √8. Squaring both sides and solving for v, we find v = \((1.6t - \sqrt{8} )^{2}\). Integrating the velocity function again with respect to time, we get ∫\((1.6t - \sqrt{8} )^{2}\) dt = ∫ds. Evaluating the integral and substituting the limits, we find s = 12.5 meters.

Therefore, the particle travels approximately 12.5 meters before coming to a stop.

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When a 53 kg gymnast climbs a rope, if she accelerates upward at a rate of 1.5 m/s^2 then the tension in the rope is: 824.5 N.

To calculate the tension in the rope, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = ma).

In this case, the mass of the gymnast is given as 53 kg, and the acceleration is 1.5 m/s^2 (upward). Plugging in these values into the equation, we can find the tension in the rope.

Tension = mass * acceleration

Tension = 53 kg * 1.5 m/s^2

Tension = 79.5 N

Therefore, the tension in the rope when the gymnast accelerates upward at a rate of 1.5 m/s^2 is 79.5 N.

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The closest answer to maximum acceleration is 2.5 m/s^2. Option A is correct.

Let's assume that the force exerted by the tow truck is F and the force of friction between the road and the bus-truck system is f. According to Newton's second law of motion, the net force on the system will be,

F - f = M*a, where a is the acceleration of the system.

The force of friction f can be calculated as the product of the coefficient of friction μ and the normal force N, where N = M*g is the weight of the system and g is the acceleration due to gravity,

f = μN = μM*g

Substituting the value of f in the first equation,

F - μMg = M*a

The maximum acceleration a_max will occur when the force F is maximum. Since the tow truck has a maximum acceleration of 3.0 m/s^2, we can assume that the force F is also maximum when the tow truck is accelerating at this rate. Thus, we have:

F = ma_max = 3m3.0 m/s^2 = 9m

Substituting the value of F in the previous equation and solving for a_max,

a_max = (F - μMg)/M = (9m - μ3mg)/3m

Since we don't have the value of the coefficient of friction, we can't determine the exact value of a_max. However, we can determine the maximum value of a_max by assuming that the coefficient of friction is zero (i.e., the road is frictionless). In this case, the maximum acceleration a_max will be,

a_max = 9m/3m = 3.0 m/s^2

Since the actual coefficient of friction between the road and the bus-truck system will be greater than zero, the actual maximum acceleration will be less than 3.0 m/s^2. Therefore, the closest answer choice is 2.5 m/s^2, which is option A.

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Answer:

Hiya your answer's up

Down

6- dioxide

Answer:

the speed of light, the difference in frequency between the radio waves that receive back by the gun.

Explanation: