the uniform slender bar is released from rest in the horizontal position shown. determine the value of x for which the angular acceleration is a maximum, and determine the corresponding
Answers
The value of x for which the angular acceleration is maximum is 0.1804 m, with a corresponding angular acceleration of 0.271 rad/s².
To solve this problem, let's assume that the slender bar is a uniform rod with a length of 625 mm (or 0.625 m) and is released from rest in the horizontal position. We'll also assume that the rotation occurs at about one end of the bar.
To determine the value of x for which the angular acceleration is maximum, we need to consider the torque acting on the bar. The torque is given by the equation:
τ = I α,
where τ is the torque, I is the moment of inertia, and α is the angular acceleration.
For a slender bar rotating about one end, the moment of inertia is given by:
I = (1/3) m L²,
where m is the mass of the bar and L is its length.
Now, we need to consider the forces acting on the bar. When the bar is in the horizontal position, only the weight acts on it, creating a torque. The torque due to the weight is given by:
τ = m g x,
where g is the acceleration due to gravity and x is the horizontal distance of the center of mass from the rotation axis.
Setting these two torque equations equal, we have:
m g x = (1/3) m L² α.
Canceling out the mass, we can solve for α:
g x = (1/3) L² α.
Now, we can see that α is directly proportional to x. Therefore, to maximize α, we need to maximize x.
Given that L = 0.625 m, we can calculate the maximum value of x using the equation above. Plugging in the values:
9.8 * x = (1/3) * 0.625² * α.
Simplifying further:
x = (1/3) * 0.625² * α / 9.8.
To find the corresponding angular acceleration, we can substitute the value of x into the equation:
α = g x / [(1/3) L²].
Plugging in the known values:
α = 9.8 * x / [(1/3) * 0.625²].
Now we can calculate the values:
x = (1/3) * 0.625² * α / 9.8
x = (1/3) * (0.625)² * 0.271 / 9.8
x ≈ 0.1804 m (rounded to four decimal places)
α = 9.8 * x / [(1/3) * 0.625²]
α = 9.8 * 0.1804 / [(1/3) * (0.625)²]
α ≈ 0.271 rad/s² (rounded to three decimal places)
Therefore, the value of x for which the angular acceleration is maximum is approximately 0.1804 m, and the corresponding angular acceleration is approximately 0.271 rad/s².
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The question is incomplete, I think the question is,
The uniform slender bar is released from rest in the horizontal position shown. Determine the value of x for which the angular acceleration is a maximum, and determine the corresponding angular acceleration of 625 mm.
Related Questions
Write two conversion factors for the following unit equalities. The first example hasbeen completed for you.b. 1 mile = 1.61 kilometerc. 4 cups = 1 quart
Answers
Take into account that any conversion factor can be written as a fraction in which you have the equivalence in the numerator and denominator.
b. 1 mile = 1.61 kilometer
By using the abbreviated form mi as mile and km as kiometer, you can write:
\(\frac{1mi}{1.61\operatorname{km}},\frac{1.61\operatorname{km}}{1mi}\)c. 4 cups = 1 quart
\(\frac{4\text{cups}}{1qt},\frac{1qt}{4\text{cups}}\)suppose that at midnight you observe the moon due south on the meridian. where will it be two nights later at the same time? group of answer choices
Answers
Suppose that at midnight you observe the Moon due south on the meridian. It will be about 26 degrees east of my meridian two nights later at midnight. Therefore, option (b) It will be about 26 degrees east of my meridian, is correct.
When you observe the moon due south on the meridian, it is at the highest point it can be in the sky at your position. The moon's movement in the sky is from east to west. As a result, two nights later at midnight, it will be about 26 degrees east of your meridian. On Earth, the sky is divided into 24 time zones, with each time zone spanning 15 degrees of longitude. The sky can be seen in its entirety over a period of one year by an observer in Bellingham. The sky is constantly changing as the earth rotates on its axis, causing the stars to appear in different positions each night. In Bellingham, the observer can see roughly half of the overall sky over the course of one year.
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Correct question:
Suppose that at midnight you observe the Moon due south on the meridian. Where will it be two nights later at midnight?
a.It will be about 26 degrees west of my meridian.
b.It will be about 26 degrees east of my meridian.
c.It will be about 26 degrees north of my meridian.
d.It will be about 26 degrees south of my meridian.
Over a period of one year, how much of the overall (night) sky would a Bellingham observer be able to see?
23. In an experiment to determine the density of a lead using a density bottle, the following readings were obtained (a) Mass of empty density bottle = 13.2g (b) Mass of density bottle filled with water = 53.2g (c) Mass of a partially filled density bottle with lead shots only = 126.1g (d) Mass of density bottle with lead shots filled up with water = 166.lg Calculate iii) iv) v) Volume of water that fills the density bottle 40g Capacity of the density bottle Mass of lead shots 112.99 Volume of lead shots Density of lead (2 marks) (1 mark) (1 mark) (1 mark) (2 marks)
Answers
Answer:To calculate the required values, we can use the formula for density: density = mass/volume.
i) Volume of water that fills the density bottle = mass of water/density of water
Mass of water = Mass of density bottle filled with water - Mass of empty density bottle = 53.2g - 13.2g = 40g
Density of water = 1g/cm³ (at room temperature and pressure)
Volume of water = 40g/1g/cm³ = 40cm³
ii) Capacity of the density bottle = Volume of water + Volume of lead shots
Volume of water = 40cm³ (calculated above)
Volume of lead shots = Volume of density bottle filled up with lead shots and water - Volume of water
Volume of density bottle filled up with lead shots and water = Mass of density bottle with lead shots filled up with water - Mass of empty density bottle
= 166.1g - 13.2g = 152.9g
Volume of lead shots and water = Volume of density bottle filled up with lead shots and water - Volume of water
Volume of lead shots and water = 152.9cm³ - 40cm³ = 112.9cm³
Assuming that the volume of water in the partially filled density bottle is negligible, we can take the volume of lead shots to be equal to the volume of the partially filled density bottle.
Capacity of the density bottle = Volume of water + Volume of lead shots = 40cm³ + 112.9cm³ = 152.9cm³
iii) Mass of lead shots = Mass of density bottle with lead shots filled up with water - Mass of density bottle filled with water
= 166.1g - 53.2g = 112.9g
iv) Volume of lead shots = Mass of lead shots/density of lead
Density of lead = 11.34 g/cm³ (at room temperature and pressure)
Volume of lead shots = 112.9g/11.34 g/cm³ = 9.96 cm³ (approximately)
v) Density of lead = Mass of lead shots/Volume of lead shots
Density of lead = 112.9g/9.96cm³ = 11.32 g/cm³ (approximately)
Therefore, the required values are:
iii) Mass of lead shots = 112.9g
iv) Volume of lead shots = 9.96cm³ (approximately)
v) Density of lead = 11.32 g/cm³ (approximately)
Explanation:
Kinematics
A ball is dropped from rest from the top of a
building with height h and strikes the ground with a
speed v. From ground level, a second ball is thrown
straight upward at the same instant that the first
ball is dropped. The initial speed of the second ball
is v0 = v, the same speed with which the first ball
will eventually strike the ground. Ignoring air
resistance, the balls cross paths:
a. at half the height of the building.
b. above the halfway point of the building.
c. below the halfway point of the building.
d. there is not enough information to determine
where they cross.
Answers
The balls cross paths at above the halfway point of the building.
Let us consider the ball dropped down as ball A and the ball thrown up as ball B. The initial speed of ball B is same as that of final velocity of ball A meaning that both balls have same average velocity. So they both cover same distance ( meaning the ball B reaches the top of the roof ) at same time. But the instantaneous velocities differs which means that they cross at halfway point.
The ball A starts slowly and the speed keeps increasing as it goes farther. The ball B starts faster and the speed keeps decreasing as it goes farther. So when the ball B reaches the halfway mark, the ball A still hasn't reached the halfway mark. This means that the ball B kept rising and at some point above the halfway point, the ball B crosses the ball A.
Therefore, the balls cross paths at above the halfway point of the building ( B ).
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ASAP will do brainiest 22 points PLSS HELP
Sports such as football, baseball, soccer, horseback riding, tennis, volleyball, skateboarding, and surfing (to name a few) are full of examples of Newton’s Three Laws of Motion. To answer this question: 1. Choose any sport. Write down the name of the sport. 2. In your own words, state each of Newton’s 3 Laws of Motion and give a clear, specific example of how each law applies to the sport you have chosen.
Answers
Answer:
tenis
Tenis applies to each of Newton's 3 Laws of Motion because with the first law if a tenis ball is at rest it will stay at rest unless acted on by an unbalanced force which would be playing tenis in which it would stay in motion. The second law applies since the acceleration at which it is hit times the mass equals the force it has. The third law applies since when hitting a tenis ball back and forth with racquets the reaction may be equal or opposite
A laboratory experiment produces a double-slit interference pattern on a screen. The point on the screen marked with a dot is how much farther from the left slit than from the right slit?.
Answers
The point on the screen marked with a dot 2.0 farther from the left slit than from the right slit.
The double-slit experiment shows that matter and light can exhibit traits of both classically defined waves and particles. It also illustrates how quantum mechanical events are fundamentally probabilistic in nature. Thomas Young conducted the first experiment of this kind utilising light to show how light behaves like a wave in 1802. At the time, it was believed that light was made up of waves or particles. A century or so later, with the advent of modern physics, it became clear that light might in fact exhibit behaviour resembling that of both waves and particles. Davisson and Germer established in 1927 that electrons exhibit the same behavior, which was later expanded to include atoms and molecules. The light experiment by Thomas Young belonged to classical physics.
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the work function of a metal blankthe amount of kinetic energy of the photoelectron emitted after the metal is illuminated. this means that metal 1 would emit electrons with blankkinetic energy compared to metal 2. so, photoelectrons from metal 1 are
Answers
The work function of a metal is the amount of energy required to remove an electron from the surface of the metal.
The kinetic energy of the photoelectron emitted after the metal is illuminated is dependent on the difference between the energy of the incident photon and the work function of the metal. Therefore, if the work function of metal 1 is lower than that of metal 2, it would require less energy to remove an electron from the surface of metal 1. This means that photoelectrons from metal 1 would have higher kinetic energy compared to metal 2.
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MUSIC
Progressions can start on any number of chords but usually end on the I.
true or false
Answers
Answer:
true
Explanation:
Answer:
false
Explanation:
Describe where x-rays are found on the ems compared to the other six forms of radiation.
Answers
Incoming X-ray photons ionize atoms in a gas-filled space in a Geiger-Müller tube, also known as a Geiger counter.
Accelerating electric charges emit electromagnetic waves according to the classical electromagnetism theory. An electron beam with high energy collides with a solid target in the X-ray tube, the most popular terrestrial source of X-rays. The rapidly moving electrons in the beam repeatedly deflect and slow down as they come into contact with the electrons and nuclei of the target atoms.The different types of EM radiations include gamma rays, x-rays, ultraviolet, visible, infrared, microwave, and radiowave. Between 100 and 1000 m is the range of frequency for microwave radiation. As a result of having the second-lowest frequency range among all radiations, they also have the second-lowest energy, and their wavelength is greater than that of all other types of radiations other than radiowaves.To know more about Geiger counter-
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saturn is select an answer and submit. for keyboard navigation, use the up/down arrow keys to select an answer. a exactly the same size as jupiter. b about half the size of jupiter c much larger than jupiter. d about 90% as large as jupiter.
Answers
Saturn is About 90% as large as Jupiter
Is Saturn almost as large as Jupiter?Saturn is our Solar System’s second biggest planet. Only Jupiter is a bigger planet. Saturn’s diameter is approximately 75,000 miles (120,000 km), or almost 10 times that of Earth. Saturn could accommodate 764 Earths within.
Saturn is the second biggest planet in the solar system. Only Jupiter is bigger, weighing nearly three times as much. Saturn’s gorgeous rings, visible even with a low-cost telescope, making it a popular night sky object.
Saturn is home to 83 moons. The International Astronomical Union has confirmed and named 63 moons, while another 20 moons are pending confirmation of finding and formal designation (IAU). The moons of Saturn range in size from bigger than the planet Mercury – the giant moon Titan – to as small as a sports arena
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Answer
Explanation
If an electron (with a charge of 1.6 x10−19c) Experiences a force of 500 N at a certain point in an electric field, then find the strength of the electric field in that location
Answers
Answer:
3.125×10²¹ N/C
Explanation:
Electric Field: This can be defined as the force experienced per unit charge. The S.I unit of electric Field is N/C
Applying,
E = F/q.................. Equation 1
Where E = Electric Field, F = Force experienced, q = Charge of an electron.
From the question,
Given: F = 500 N, q = 1.6×10⁻¹⁹ C
Substitute these values into equation 1
E = 500/(1.6×10⁻¹⁹)
E = 312.5×10¹⁹
E = 3.125×10²¹ N/C
Does the law of conservation of energy apply to open systems? Explain.
Answers
No, law of conservation of energy is not applicable to open systems.
Law of conservation of energy states that energy present anywhere can neither be created nor be destroyed by any means, it can only be converted from one form of energy to other form of energy. It means total energy of an isolated system remains same.
An open system is a system that can exchange energy and matter from the surroundings. The flow of energy takes places in an open system. Therefore, the law of conservation does not apply to an open system as it can lose or gain energy, hence its total energy will not be constant and will violate law of conservation of energy.
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As the diameter of the wire increases, the AWG number_____, and the resistance of the conductor_____.
Answers
As the diameter of the wire increases, the AWG number decreases, and the resistance of the conductor decreases.
AWG (American Wire Gauge) is a standard used to measure the diameter of wires, with smaller numbers indicating larger wire diameters.
Resistance is a measure of how difficult it is for an electric current to flow through a wire, with higher resistance causing a reduction in the amount of current that can pass through the wire.
When the wire diameter increases, the cross-sectional area of the wire also increases, which means there is more space for the electric current to flow through, resulting in lower resistance.
Therefore, a larger diameter wire has a lower AWG number and lower resistance, making it a more efficient conductor of electric current.
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A lamp has a current of 2.0 amperes at 6.0 volts. What is the resistance of lamp?
Answers
Answer: B 3.0
Explanation:
the wavelength of the sound wave of 15 hz, frequency is 0.0022 m. what is its speed?
Answers
Answer:
0.033 m/sExplanation:
The speed of the wave given only it's frequency and wavelength can be found by using the formula
\(c = f \times \lambda\)
where
c is the velocity of the wave in m/s
\( \lambda\) is the wavelength in m
f is the frequency in Hz
From the question we have
c = 15 × 0.0022 = 0.033
We have the final answer as
0.033 m/sHope this helps you
An airplane accelerates from a velocity of 25.88 m/s at a constant rate of 4.21 m/s2 over 590.39 m. What is its final velocity?
Answers
The final velocity of the airplane is 75.1 m/s.
What is velocity?Velocity can be defined as the measurement of rate and direction of motion.
The velocity of a moving object changes with time. Thus, a moving object will have an initial velocity as well as a final velocity.
The formula for final velocity, V is given by the formula below:
v = √(u² + 2as)
where
u = initial velocitya = accelerations = distance or displacementThe values are as follows:
u = 25.88 m/s
a = 4.21 m/s²
s = 590.39 m
Substituting the values
v = √{(25.88)² + 2 * 4.21 * 590.39)}
v = 75.1 m/s
Therefore, the final velocity, v is 75.1 m/s
In conclusion, the final velocity of the airplane is derived from the initial velocity, acceleration, and distance of travel.
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at a certain point the speed of the bucket begins to change. the bucket now has an upward constant acceleration of magnitude 3 m/s2 m / s 2 . what is the tension in the rope now? view available hint(s)
Answers
Therefore, the tension in the rope is 4 times the weight of the bucket, or 4mg.
What is speed?Speed is a scalar quantity that measures the rate at which an object covers distance. It is defined as the distance traveled per unit of time. The SI unit of speed is meters per second (m/s), although other units such as kilometers per hour (km/h) and miles per hour (mph) are also commonly used. Speed can be measured using various methods, such as radar, GPS, and speedometers in vehicles. The instantaneous speed of an object at a particular moment in time is called its instantaneous velocity. The average speed of an object over a certain period of time is calculated by dividing the total distance traveled by the object by the total time taken.
Here,
To find the tension in the rope when the bucket has an upward constant acceleration of magnitude 3 m/s², we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration:
Fₙ = ma
where Fₙ is the net force, m is the mass of the object, and a is the acceleration.
In this case, the bucket is being pulled upward by the tension in the rope, and its weight is pulling it downward. Since the bucket is accelerating upward, the tension in the rope must be greater than the weight of the bucket. Therefore, we can write:
Fₙ = T - mg
where T is the tension in the rope, m is the mass of the bucket, and g is the acceleration due to gravity (9.81 m/s²).
The net force is equal to the mass times the upward acceleration, so we have:
Fₙ = ma
= m(3 m/s²)
= 3m
Setting these two expressions for Fₙ equal to each other, we can solve for the tension in the rope:
T - mg = 3m
T = 4mg
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What is the difference between speed and velocity?
Answers
\( \huge \sf \underline{ \color{green}Ⱥnswɇɍ : }\)
Speed is a scalar quantity.Speed ascertain how fast a body moves.\( \large \sf \: Speed = \frac{distance}{time} \)____________________________
Velocity is a vector quantity.Velocity Ascertain the object speed & the director on it takes while moving.\( \large \sf \: velocity = \frac{displacement}{time} \)Hope Helps~The difference between the two concepts lies in the type of magnitude they represent, speed is a scalar magnitude, while velocity is a vectorial magnitude.
What is speed?It is the variation of distance in a certain time as a consequence of the movement of a mobile element.
What is velocity?It is the vectorial magnitude that shows and expresses the variation in terms of position of an object and as a function of time.
Therefore, we can conclude that speed is a scalar magnitude that determines the ratio of the distance traveled by a body and velocity is a vectorial magnitude that expresses the relationship between the space traveled by an object, the time used for it and its direction.
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The Sun appears to be the largest star in our sky. It is hard to imagine that the Sun is actually only-
Responses
A not actually a star at all.not actually a star at all.
B a very large star.a very large star.
C a very small star.a very small star.
D a medium-sized star
Answers
The Sun appears to be the largest star in our sky. It is hard to imagine that the Sun is actually only a very large star. so option b is correct
In the heart of our solar system, the Sun, a 4.5 billion year old yellow dwarf star, is a hot, glowing ball of hydrogen and helium. Our solar system's sole star is located around 93 million miles (150 million kilometres) from Earth. Life as we know it would not be possible on our home planet without the energy of the Sun.
The Sun may appear to be a constant source of heat and light in the sky from our vantage point on Earth. The Sun, on the other hand, is a dynamic star that changes continually and radiates energy into space. Heliophysics is the field of research concerned with the Sun and the solar system as a whole.
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A highway curves to the left with a radius of curvature of 46 m and is banked at 27o, so that cars can take this curve at higher speeds. Consider a car of mass 1664 kg whose tires have a static friction coefficient 0.61 against the pavement. How fast can the car take this curve without skidding to the outside of the curve? The acceleration of gravity is 9.8 m/s2. Answer in units of m/s.
Answers
The car can take the curve at a speed of 32.11 m/s without skidding to the outside of the curve.
To calculate the maximum speed at which the car can take the curve, we need to first determine the maximum force of static friction that can act on the car. This can be calculated using the formula:
F_friction = friction coefficient * normal force
The normal force is equal to the weight of the car and can be calculated using the formula:
N = m * g (where m is the mass of the car and g is the acceleration of gravity)
So:
N = 1664 kg * 9.8 m/s^2 = 16,297.2 N
F_friction = 0.61 * 16,297.2 N = 9,941.33 N
Next, we need to determine the centripetal force required to keep the car moving in a circle of radius 46 m. This can be calculated using the formula:
F_centripetal = m * a
Where a is the centripetal acceleration and can be calculated using the formula:
a = v^2 / r
So we have to find v:
v = sqrt(F_friction*r /m)
v = sqrt(9,941.33 N * 46 m / 1664 kg) = 32.11 m/s
So, the car can take the curve at a speed of 32.11 m/s without skidding to the outside of the curve.
It's important to mention that this is a theoretical speed, it's always recommended to drive at lower speeds for safety reasons.
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an athlete completes one round of a circle track of diameter 70m in 30s. what will be the distance covered and the displacement at the end of 45s respectively
Answers
So, 2200 metres were travelled, and 200 metres were moved.
The athlete will be in the exact opposite posture after his motion is finished. That is, 200 m equals 200 x diameter.
How do you determine the length of a circled track?Multiplying the circle's diameter by (pi) yields the circumference of the circle. Additionally, the circumference may be determined by multiplying the 2radius by pi (=3.14).
Simply draw a vector from your beginning point to your destination location, solve for the length of this line, and you can determine displacement. If your beginning and finishing positions are identical, as they are if you are running a circular 5K course, your displacement is 0. Displacement in physics is symbolised by the symbol s.
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I kinda don’t know how to solve this I need help.
Answers
Answer:
the answer is 11 N left
Explanation:
there is more force being applied in the direction left, so the ball will move left. to find the net force that the ball will move in that direction subtract the force being applied in the opposite direction. so, 16N-5N=11N. your answer in 11 N left.
Circle the correct word(s) in brackets to complete each sentence.
i) Hooke's Law works for ( springs only / all materials / some materials ).
ii) Hooke's Law only applies ( up to / over ) a certain force.
iii) The force at which Hooke's Law stops working for springs is
( higher / lower ) than
for most other materials?
Answers
Answer:
i) Hooke's Law works for some materials
ii) Hooke's Law only applies up to a certain force
iii) The force at which Hooke's Law stops working for springs is lower than for most materials
Explanation:
Hooke's Law of elasticity states that the deformation of an elastic material is proportional to the applied for small deformations
The law is applicable to elastic materials whose values of deformation or extension as well as the applied load or stress are expressible by a single real number
Hooke's Law is applicable when the force and the extension of the elastic material are proportional, at larger force, the elastic material is observed to expand more than as expected based on Hooke's Law
The nature of springs is such that its elastic limit is reached by a much lower force than for most materials. Therefore, Hooke's law stops working for springs at a lower force than for most materials.
The scatterplot shows the energy in watts and the light output in lumens per watt of several lightbulbs
Answers
The statements D best represents the relationship between the energy and light output.
What is scatter plot ?A scatter plot is a form of plot displays values for two variables for a collection of data using coordinates system.
The scatter plot depicts the energy input and light output in lumens per lightbulb. The statements D best represents the relationship between the energy and light output.
There is no apparent association between the energy and light output, shows the relationship between the energy and light output.
Hence,statement D is correct.
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A 1200 kg car collides with a 160 kg deer (don't worry, the deer survives and goes on to cause several more car crashes). The collision results in an acceleration ("deceleration") of 2.5 m/(sec)^2 for the car. Find the acceleration of the deer during the collision.
Answers
Answer:
18.75
Explanation:
p=mv, where p is momentum, m is mass, and v is velocity. For the car:
p=1200*2.5=3000
For the deer:
3000=160*v
v=18.75m/s
Hope this helps!
batteries are used to power flashlights the energy stored in batteries is converted to light energy given off by flashlights what happens to the energy as it changes form? A) all of the energy is transformed into light energy. B) some of the energy transforms to thermal energy C) half of the energy is transformed to thermal energy. D) half of the energy is transformed to light energy.
Answers
Answer:
some of the energy is transformed to thermal energy
Answer:
some of the energy transforms to thermal energy
Explanation:
In materials such as metals, the outer shell electrons are loosely bound to the nuclei of their atoms and are free to move from one atom to another. These materials are good conductors. Is this true or false?
Answers
In materials such as metals the outer most electrons are loosely bound and therefore their movement is chaotic, this allows for the transportation of energy in form of electricity therefore, this materials are good conductors. The statement is true.
The weight of a subducting plate helps pull it into a subduction zone in which process?
A. slab pull
C. slab push
B. ridge push
D. ridge pull
Answers
The weight of a subducting plate helps pull it into a subduction zone through the process known as (A) "slab pull."
Slab pull is the gravitational force exerted on a subducting plate as it sinks into the mantle beneath an overriding plate. As the dense subducting plate descends, its weight generates a pulling force that contributes to the motion of the subduction process.
In contrast, "slab push" refers to the force exerted by the upwelling asthenosphere that pushes the subducting plate from behind. "Ridge push" is the gravitational force created by the elevated position of a mid-ocean ridge, which can contribute to the motion of tectonic plates.
"Ridge pull" refers to the gravitational force created by the cooling and densifying lithosphere at the spreading ridges, causing it to sink and pull the plates behind it.
Therefore, the correct answer in this context is (A) slab pull.
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A cube has height of 3cm. What is the volume of the cube?
Answers
Answer:
27\(cm^{3}\)
Explanation:
The formula to find the volume of a cube is Volume=height cubed(or to the power of 3) so you would replace height with 3cm and get the equation Volume= 3 to the power of 3. So 3 x 3 x 3 = 27. So your answer would be:
27\(cm^{3}\)
a particle is projected from the surface of earth with a speed equal to 3 times the escape speed. when it is very far from earth, what is its speed?
Answers
Answer:
1/2 m v^2 = G M m / R speed of object at surface of earth
v^2 = 2 G M / R escape speed needed
V = 3 v if original speed = 3 * escape speed
v^2 / 9 = 2 G M / R
v^2 = 18 G M / R where v is initial speed
v^2 = G M / R * (18 - 2) = 16 G M / R very far from earth
v = (16 G M / R)^1/2
v = (16 * 6.67E-11 * 5.98E24 / 6.37E6)^1/2
v = 31650 m/s = 19.7 mi/sec
When a particle is projected from the surface of Earth with a speed equal to 3 times the escape speed, its final speed when very far from Earth will be 2 times the escape speed.
The escape speed is the minimum speed required for an object to overcome Earth's gravitational pull and move indefinitely away from it.
When a particle is projected with a speed 3 times the escape speed, it has more than enough energy to escape Earth's gravity.
As the particle moves away from Earth, it loses some of its kinetic energy due to Earth's gravitational force. Eventually, when the particle is very far from Earth, it will have lost an amount of kinetic energy equal to the escape speed.
Summary: When a particle is projected with a speed 3 times the escape speed and reaches a point very far from Earth, its speed will be 2 times the escape speed.
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