The specific heat(c) of copper is 0.39 J/g °C. What is the temperature change(∆t) when 200 Joules of heat(Q) is added to 10 grams?
Answers
Answer:
7.8 J/g °C
Explanation:
0.39 J/g °C x 200 J / 10g
= 7.8 J/g °C
Answer:
above is the answer to your question.
Related Questions
Why is thermal energy classified as kinetic energy?
Answers
Answer:
Thermal energy is an example of kinetic energy, as it is due to the motion of particles, with motion being the key. Thermal energy results in an object or a system having a temperature that can be measured. Thermal energy can be transferred from one object or system to another in the form of heat.
Explanation:
Answer:
Thermal energy is an example of kinetic energy, as it is due to the motion of particles, with motion being the key. Thermal energy results in an object or a system having a temperature that can be measured. Thermal energy can be transferred from one object or system to another in the form of heat.
Explanation:
2. A student drew the diagram below to model the movement of an object orbiting the Sun. Which object was she most likely modeling? a meteor a planet a comet an astroid
Answers
Answer:
A comet
Explanation:
The picture is of an elliptical orbit of a comet. You can tell it is a comet because of the tail. Also, I just took the test and it was a comet.
Where is the energy in a glucose molecule stored?
Answers
Answer:
Energy is stored in the bonds between atoms
Answer:
Energy is stored in the bonds between atoms
Explanation:
Ape-x
what is the -40 dbc (bessel approximation) bandwidth of an fm transmitter having a deviation () of 2 khz and an information frequency of 2 khz? (enter your answer in khz.)
Answers
The -40 dbc bandwidth of the FM transmitter is 8 kHz.
To calculate the -40 dbc bandwidth of an FM transmitter with a deviation of 2 kHz and an information frequency of 2 kHz, we can use Carson's rule formula:
BW = 2(Δf + f_m)
Where:
Bandwidth is the -40 dBc bandwidth.
Δf is the frequency deviation.
f_m is the maximum frequency of the modulating signal.
Bandwidth = 2 x (deviation + information frequency)
In this case, the frequency deviation (Δf) is given as 2 kHz, and the information frequency (f_m) is also 2 kHz.
Plugging in these values into the formula:
Bandwidth = 2 * (2 kHz + 2 kHz)
= 2 * 4 kHz
= 8 kHz
Therefore, the -40 dbc bandwidth of the FM transmitter is 8 kHz.
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Joe and Jim start at rest at the starting line of a race track. Both runners accelerate at the same rate, but Joe accelerates for twice as long as Jim. Describe the final speed of Joe compared to Jim.
Answers
Answer:
Vf₂ = 2 Vf₁
It shows that final speed of Joe is twice the final speed of Jim.
Explanation:
First, we analyze the final speed of Jim by using first equation of motion:
Vf₁ = Vi + at
where,
Vf₁ = final speed of Jim
Vi = initial speed of Jim = 0 m/s
a = acceleration of Jim
t = time of acceleration for Jim
Therefore,
Vf₁ = at ---------------- equation (1)
Now, we see the final speed of Joe. For Joe the parameters will become:
Vf = Vf₂
Vi = 0 m/s
a = a
t = 2t
Therefore,
Vf₂ = 2at
using equation (1):
Vf₂ = 2 Vf₁
It shows that final speed of Joe is twice the final speed of Jim.
A 2.0 kg rock is dropped from a height of 125 m. What is the momentum of the object just before it strikes the ground (Use g=10 m/s2)?
Answers
Answer:
100Ns
Explanation:
find velocity and then plug into momentum formula momentum=(velocity)(mass)
Answer:
5,000 kg-m/s going south
Explanation:
Since you're only given mass and height, not velocity. You have to find velocity first. The equation for velocity is v=2gh. We know gravity is 10 since it's given & height is also given which is 125m. After doing the math, it's 2,500. Now that you have velocity, you can plug velocity into the formula for momentum which is p=mv. 2.0 times 2,500 = 5,000 kg-m/s going south.
multiple choice
15) A coiled spring used to help a door close has ________ ________energy when the door is open.
16) After braking, a bicycle's tires increase in temperature as friction causes some of the
mechanical energy to transfer to ________ energy.
Answers
According to conservation of energy, the energy of interacting bodies in a closed system remains constant. The total energy of an isolated system remains constant; it is said to be conserved over a period of time.
Elastic energy is the mechanical implicit energy stored in the configuration of a material or physical system as it's subjected to elastic distortion by work performed upon it. Elastic energy occurs when objects are impermanently compressed, stretched or generally misshaped in any manner.
The mechanical energy is never lost forever , rather it gets converted to thermal energy because of the friction .
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PLEASE ANSWER THESE I NEED HELP!!!
Which properties are characteristic of metalliods?
1. high electrical conductivity and a high melting point
2. low electrical conductivity and a low melting point
3. intermediate conductivity and a high melting point
4. intermediate conductivity and a low melting point
Answers
Hope I helped :) mark as brainliest**
Answer:
1 high electrical conductivity and high melting point
PLS HELP MEEEE (NO LINKS PLEASE)
The difference between visible light and gamma rays is that
a.
the amplitude of visible light is greater.
c.
they travel through a different medium.
b.
the speed of gamma rays is greater.
d.
the frequency of gamma rays is greater.
Answers
Answer:
Gamma rays occupy the short-wavelength end of the spectrum; they can have wavelengths smaller than the nucleus of an atom. Visible light wavesare one-thousandths the width of human hair--about a million times longer than gamma rays. Radio waves, at the long-wavelength end of the spectrum, can be many meters long.
Answer:D "the frequency of gamma rays is greater."
Explanation:Trust
help me please oml 2 one
Answers
Color: Both the bromine gas and steak have a brownish color.
What is bromine gas?Bromine gas is a reddish-brown, nonflammable, and highly toxic gas with a very strong, unpleasant odor. It is composed of two heavy, diatomic, halogen molecules, Br2, and is the only nonmetal element that exists as a liquid at room temperature. Bromine gas is denser than air and is soluble in water and organic solvents.
Texture: The bromine gas is a gas and therefore has no texture, while the steak is solid and has a firm texture.
Temperature: The bromine gas is a gas and therefore has a lower temperature than the steak, which is at room temperature.
Bromine Gas and Juice:
Color: The bromine gas is brownish and the juice is a yellowish or orange color.
Texture: The bromine gas is a gas and therefore has no texture, while the juice is a liquid and has a smooth texture.
Temperature: The bromine gas is a gas and therefore has a lower temperature than the juice, which is at room temperature.
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true or false
As the moon orbits Earth, the absolute positions of the moon,
Earth, and the sun change
Answers
Answer:
FALSE
Explanation:
as the moon orbits earth, the ABSOLUTE position of the moon, earth, and the sun change. the moons orbit around earth is ABSOLUTELY STRAIGHT with respect to earths orbit around the sun. the amount of the moon's surface that is lit by the sun changes.following the inelastic collision of the carts, the two carts fuse into an object with double the mass of the original cart. there is then a frictional section of the track to slow the cart to a stop over 20 meters. describe the amount of work due to friction and frictional force exerted to stop both carts over 20 meters. calculate the work due to friction and frictional force. in your calculations, be sure to explicitly state the equations you use and what values you will be substituting to calculate the final value.
Answers
In the inelastic collision of the carts, the two carts fuse into an object with double the mass of the original cart. The works due to friction and the frictional force exerted to stop the two carts over 20 meters is 980 Joules.
What is inelastic collision?Generally, To calculate the work due to friction and the frictional force exerted to stop the two carts over 20 meters, we will need to know the coefficient of friction between the carts and the track, the mass of the two carts, and the acceleration due to gravity.
The equation for work due to friction is:
Work = Friction force * Distance
The equation for the friction force is:
Friction force = Coefficient of friction * Normal force
The normal force is equal to the mass of the two carts multiplied by the acceleration due to gravity:
Normal force = Mass * Gravity
We can substitute these equations into the equation for work to get:
Work = (Coefficient of friction * Mass * Gravity) * Distance
To calculate the work, we need to substitute in the values for the coefficient of friction, mass, gravity, and distance. Let's say the coefficient of friction is 0.5, the mass of the two carts is 10 kilograms, and the acceleration due to gravity is 9.8 meters per second squared. The distance the carts travel is 20 meters.
Substituting these values into the equation for work, we get:
Work = (0.5 * 10 * 9.8) * 20
Solving this equation gives us a final value for the work of: 980 Joules.
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A uniform electric field of magnitude 1.1 x 104 N/C is perpendicular to a square sheet with sides 2.0 m long. What is the electric flux through the sheet?
Answers
The electric flux through the square sheet is \(4.4 * 10^4 Nm^2/C\), when a uniform electric field of magnitude \(1.1 * 10^4 N/C\) is perpendicular to a square sheet with sides 2.0 m long.
The electric flux through a closed surface is given by the formula:
\(\[ \Phi = \mathbf{E} \cdot \mathbf{A} \]\)
where \(\(\Phi\)\) is the electric flux, \(\(\mathbf{E}\)\) is the electric field, and \(\(\mathbf{A}\)\) is the area vector of the surface. In this case, the electric field \(\(\mathbf{E}\)\) is perpendicular to the square sheet, and the magnitude of the electric field is given as \(1.1 * 10^4 N/C\).
The area of the square sheet is \(\(A = (2.0 \, \text{m})^2 = 4.0 \, \text{m}^2\)). Since the electric field is perpendicular to the surface, the angle between the electric field and the area vector is 0 degrees.
Substituting the values into the formula, we have:
\(\[ \Phi = (1.1 \times 10^4 \, \text{N/C}) \cdot (4.0 \, \text{m}^2) = 4.4 \times 10^4 \, \text{N} \cdot \text{m}^2/\text{C} \]\)
Therefore, the electric flux through the square sheet is \(4.4 * 10^4 Nm^2/C\).
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what is the current through a long straight wire if the magnetic field at a point 3.70 cm away is 1.70 t?
Answers
The current through the long straight wire is 45.7 A.
The magnetic field produced by a long straight wire carrying a current is given by the formula B = (μ0I)/(2πr), where B is the magnetic field, μ0 is the permeability of free space, I is the current, and r is the distance from the wire. Rearranging the formula to solve for I, we get I = (2πrB)/μ0.
Substituting the given values, we have B = 1.70 T and r = 0.0370 m. The permeability of free space μ0 is a constant equal to 4π × 10⁻⁷ T·m/A. Thus, we can calculate the current I as I = (2π0.0370 m1.70 T)/(4π × 10⁻⁷ T·m/A) = 45.7 A.
Therefore, the current through the long straight wire is 45.7 A.
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Which aspect of health is best illustrated by the following example? I work well in a group and
respect my other classmates.
O social
O physical
O emotional
Answers
Not affected by acids a physical or chemical?
Answers
A neutron star is:__-.
a. always a pulsar. they are the same thing.
b. left over from the death of a massive star.
c. imaginary.
d. full of protons.
Answers
Left over from the death of a massive star.
What are neutron stars?A neutron famous person is the collapsed middle of a big supergiant celebrity, which had a complete mass of among 10 and 25 sun hundreds, possibly more if the megastar was specially metallic wealthy.
Except for black holes and some hypothetical objects (e.g., white holes, quark stars, and peculiar stars), neutron stars are the smallest and densest presently regarded class of stellar items.
Neutron stars have a radius at the order of 10 kilometers and a mass of approximately Four sun masses.
They end result from the supernova explosion of a large superstar, blended with gravitational collapse, that compresses the center beyond white dwarf famous person density to that of atomic nuclei.
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Some one plz help me I am so confused
Answers
Answer:
1. the attractive force that holds atoms or ions together
2. the average distance between the nucleus of two bonded atoms
3. the angle formed by two bonds to the same atom
20. There is a bell at the top of a tower that is 45 m high. The bell weighs 19 kg. The bell has
energy. Calculate it.
Answers
Explanation:
Find an energy is E =mgh, so E = 45*10*19=8550j
an 6.80 kg ball, hanging from the ceiling by a light wire 150 cm long, is struck in an elastic collision by a 2.60 kg ball moving horizontally at 6.50 m/s just before the collision.ind the tension in the wire just after the collision
Answers
By the law of conservation of momentum and conservation of kinetic energy, the tension in the wire just after the collision is 40.5 N.
To solve this problem, we can use the law of conservation of momentum and the law of conservation of kinetic energy. Before the collision, the only moving object is the 2.60 kg ball. Its momentum is given by \(p = mv = (2.60 kg)(6.50 m/s) = 16.90 kg·m/s.\)When the collision occurs, momentum is conserved. This means that the total momentum before the collision is equal to the total momentum after the collision. After the collision, both balls are moving, but we don't know their velocities yet. Let's call the velocity of the 6.80 kg ball v1 and the velocity of the 2.60 kg ball v2. Then, we can write:p_before = p_after
\((2.60 kg)(6.50 m/s) = (6.80 kg)v1 + (2.60 kg)v2\)We also know that the collision is elastic, which means that kinetic energy is conserved. This means that the total kinetic energy before the collision is equal to the total kinetic energy after the collision. Before the collision, the 2.60 kg ball has kinetic energy given by KE = (1/2)mv^2 = (1/2)(2.60 kg)(6.50 m/s)^2 = 56.95 J. After the collision, the total kinetic energy is the sum of the kinetic energies of the two balls:
KE_after = \((1/2)(6.80 kg)v1^2 + (1/2)(2.60 kg)v2^2\)Now, we can use these two equations to solve for v1 and v2. First, let's solve for v2:
\(v2 = (2.60 kg)(6.50 m/s) - (6.80 kg)v1 / 2.60 kg\)Next, let's substitute this expression for v2 into the equation for KE_after:
KE_after = \((1/2)(6.80 kg)v1^2 + (1/2)(2.60 kg)[(2.60 kg)(6.50 m/s) - (6.80 kg)v1 / 2.60 kg]^2\)
Simplifying this equation, we get:
KE_after = \((1/2)(6.80 kg)v1^2 + (1/2)(2.60 kg)(6.50 m/s)^2 - (6.80 kg)\)(2.60 \(kg)(6.50 m/s)v1 / (2.60 kg)^2 + (6.80 kg)^2 v1^2 / (2.60 kg)^2\)Now, we can solve for v1 by setting KE_after equal to the initial kinetic energy of the 2.60 kg ball:
\(56.95 J = (1/2)(6.80 kg)v1^2 + (1/2)(2.60 kg)(6.50 m/s)^2 - (6.80 kg)(2.60 kg)(6.50 m/s)v1 / (2.60 kg)^2 + (6.80 kg)^2 v1^2 / (2.60 kg)^2\)
Solving this equation, we get:
v1 = 0.735 m/sNow that we know v1 and v2, we can use the equation for momentum conservation to solve for v2:
p_before = p_after
\((2.60 kg)*(6.50 m/s) = (6.80 kg)*(0.735 m/s) + (2.60 kg)v2= v2 = 2.50 m/s\)Finally, we can use the equation for tension in a hanging object to solve for the tension in the wire just after the collision:
\(T = mg - mv^2 / LT = (6.80 kg)*(9.81 m/s^2) - (6.80 kg)*(0.735 m/s)^2 / 1.50 m\)
T = 40.5 NTherefore, the tension in the wire just after the collision is 40.5 N.
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According to the lab manual, what information does the computer need to determine the ball’s speed at the laser gate? a. the time the laser gate is blocked by the ball b. the time between pressing "d" and the ball passing through the gate c. the diameter of the ball d. Answers a and c. 10.
Answers
The main answer is that the computer needs two pieces of information in order to determine the ball’s speed at the laser gate: the time the laser gate is blocked by the ball and the diameter of the ball. (D)
This is due to the fact that the speed of the ball is directly proportional to the time it takes for the ball to pass through the laser gate, and inversely proportional to the diameter of the ball. In other words, the smaller the diameter of the ball, the faster it will travel in a given time interval.
Thus, by measuring the time it takes for the ball to pass through the laser gate and its diameter, the computer can accurately calculate the speed of the ball.
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Keeping the ending level at 2, try different starting orbits.What happens to the wavelength of the photon when the difference is small?When it is large?
Answers
When the difference is small, that is the starting orbit is just one level above the ending orbit, the wavelength of the photon will have a relatively small value.
Atomic emission is the process of light emission from an atom that occurs when the atom gets excited by either heating, bombarding with electrons, or a discharge of electric current. When an atom is excited, the electrons gain energy and move to a higher energy level or shell. When they return to the lower energy state, they emit energy in the form of electromagnetic radiation or light.
The energy of the emitted photon or light is directly proportional to the difference in the energy levels of the atom before and after the emission process. The relationship is given by:E=hfwhere E is the energy of the emitted photon, h is the Planck's constant, and f is the frequency of the emitted photon. The frequency of the emitted photon can be calculated using the formula:f=c/λwhere c is the speed of light and λ is the wavelength of the photon.
Thus, for an atom to emit radiation of a particular wavelength, the difference in energy levels of the atom must correspond to that wavelength. If the difference is small, the wavelength of the emitted photon will also be small, and if the difference is large, the wavelength of the emitted photon will be large.
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describe the reflection of the pulse from a fixed point
Answers
When a pulse encounters a fixed point, such as a wall or a rigid boundary, it undergoes reflection. Reflection occurs when the pulse bounces back upon reaching the fixed point.
During reflection, the pulse experiences a change in direction but retains its original shape and properties. The incident pulse approaches the fixed point and interacts with it. As a result, an equal and opposite pulse is generated and travels back in the opposite direction.
The behavior of the reflected pulse depends on the nature of the incident pulse and the properties of the medium it travels through. If the pulse is inverted (upside-down) before reflection, the reflected pulse will also be inverted. Similarly, if the incident pulse is right-side-up, the reflected pulse will maintain the same orientation.
The reflection process follows the law of reflection, which states that the angle of incidence (the angle between the incident pulse and the normal to the fixed point) is equal to the angle of reflection (the angle between the reflected pulse and the normal). This law ensures that energy and momentum are conserved during the reflection process.
In conclusion, when a pulse encounters a fixed point, it undergoes reflection, resulting in the generation of an equal and opposite pulse traveling in the opposite direction. The reflected pulse retains the same shape and properties as the incident pulse, following the law of reflection.
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You slowly back away from a plane mirror at a speed of 0.10 m/s With what speed does your image appear to be moving away from you?
Answers
The speed at which your image appears to be moving away from you is 0.20 m/s.
When you back away from a plane mirror, the apparent motion of your image is determined by the concept of relative motion. The speed at which your image appears to move away from you is equal to twice the speed at which you are moving towards or away from the mirror.
In this case, since you are backing away from the mirror at a speed of 0.10 m/s, your image will appear to be moving away from you at a speed of 0.20 m/s.
This is because the light rays reflecting off your body and reaching the mirror have to travel the distance you move plus the distance your image appears to move, resulting in the doubling of apparent speed.
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1)
How much time does it take to lift a box using 18.0 J of work and 20.89 Watt of power?
Answers
Answer:.
Explanation:
Z
Which latitude receives the least amount of heat per unit area from the Sun?
a. 0 degrees
b. 30 degrees north
c. 30 degrees south
d. 66.5 degrees north
Answers
Answer:
D
Explanation:
At 66.5 degrees north of the equator, the sun's rays will be less direct ( the sun will not be as high in the sky)
multipling vectors
what's the answer of this
a= 3cm, 90°
b=4cm, 0°
A×B vector=??
Answers
Answer:
12
Explanation:
A x B = |A||B|sin ©
A x B = 3x4 sin 90
= 12
When the velocity of an object Changes it is acted upon by a
Answers
When the velocity of an object changes, it is acted upon by a force
Encuentre la presion en la otra seccion estrecha si las velocidades en las secciones son de 0.50m\sy 2m\s
Answers
Answer:
ΔP = 1875 Pa, P₂ = P₁ - 1875
Explanation:
Let's use Bernoulli's equation, with the subscript 1 for the widest Mars and the subscript 2 for the narrowest part, suppose that the pipe is horizontal
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂
P₁ -P₂ = ½ ρ (v₂² - v₁²)
suppose the fluid is water
P₁ - P₂ = ½ 1000 (2² - 0.5²)
ΔP = 1875 Pa
this is the pressure difference between the two sections
the pressure in the narrowest section is
P₂ = P₁ - 1875
Radio waves are a type of______
wave and can travel through space whereas sound waves cannot travel through space because they need to travel through _____
Answers
Answer:
I already know the first one is electromagnetic but I don't know the second one sorry
Explanation: