Answer:
No
Explanation:
We would not be able to see the star because its radiation is in the UV range. For the star to be visible, it has to be in the visible spectrum of light for me to be able to see it with my eyes.
The bearing of grids of an AB alignment is 100º 22', while the magnetic declination is 8º30' E. What are the true azimuth, magnetic azimuth, and grid azimuth of this alignment?
The true azimuth of the AB alignment is 91º 52' (east of north), the magnetic azimuth is 100º 22' (east of north), and the grid azimuth is 108º 52' (east of north).
To find the true azimuth, magnetic azimuth, and grid azimuth of the AB alignment, we need to consider the magnetic declination. The magnetic declination indicates the angle between true north and magnetic north at a specific location. In this case, the magnetic declination is 8º 30' E, which means that the magnetic north is 8º 30' east of the true north.
To calculate the true azimuth, we subtract the magnetic declination from the grid azimuth. The grid azimuth is given as 100º 22', so subtracting the magnetic declination of 8º 30' E gives us a true azimuth of 91º 52' (east of north).
The magnetic azimuth remains the same as the grid azimuth, which is 100º 22' (east of north).
The grid azimuth is calculated by adding the magnetic declination to the true azimuth. Since the magnetic declination is east, we add it to the true azimuth. Adding 8º 30' E to the true azimuth of 91º 52' gives us a grid azimuth of 108º 52' (east of north).
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Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.
No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.
This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.
i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.
ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.
The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.
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Which method of popcorn popping transfers heat into the kernels without any direct
contact (nothing hot touched the kernels)? Explain.
Answer:
It is cause by radiation that's the answer
Explanation: the heat project sun rays towards the popcorn which causes it to pop
Study the current winds aloft chart for the Great Lakes (Michigan is fine) region. Estimate the average wind speed for 3000’ 12,000’ and FL350.
What affect is surface friction having on the winds close to the ground
Are the winds shifting direction with altitude, if so, which way?
What is the approximate location of the Jetstream currently? (Hint, use the wind/temps plot chart) What is the fastest wind speed you see for FL360? Which direction flight would it benefit?
How does this change seasonally?
Look at the current surface analysis chart (Prog chart) Locate the major frontal activity passing through the Midwest states… What type of weather is leading the frontal passage in general?
Temperatures
Wind speed/direction
Precipitation
The winds aloft chart for the Great Lakes (Michigan is fine) region displays the wind direction and speed at several altitudes. At 3000 feet, the wind speed is approximately 17 knots.
At 12,000 feet, the wind speed is about 44 knots. The wind speed at FL350 is approximately 67 knots.Surface friction has an effect on the winds close to the ground, slowing them down due to the frictional force exerted on the ground by air molecules. The winds shift direction with altitude, veering to the right of the direction of travel in the northern hemisphere. The approximate location of the Jetstream can be obtained by examining the wind/temperature plot chart. The fastest wind speed at FL360 appears to be approximately 145 knots, traveling towards the northeast. Flight to the east or southeast would benefit from this wind speed.Seasonally, winds aloft change depending on the position of the jet stream, which moves towards the poles during the summer months and towards the equator during the winter months.
The current surface analysis chart (Prog chart) shows the major frontal activity passing through the Midwest states. Precipitation is what leads the frontal passage in general, with both temperature and wind speed/direction changing from behind to ahead of the front.
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In an example food chain, mice only eat plants, and then snakes eat the mice. These snakes are examples of consumers.
a Quaternary
b Primary
c Secondary
d Tertiary
mass : чку moves to on x axis under influenc of single force P = (3x² - 4x + 5)2 x is meters I is meto newtons
The particle will surface tension between the points x = 1 and x = 5, with a period of 2.5 seconds. The maximum velocity will be reached when the particle is at x = 2.5, and the minimum velocity will be reached when the particle is at x = 0.5.
The force P is a quadratic function of x, which means that it is always directed towards the equilibrium point x = 2.5. This means that the particle will always oscillate around x = 2.5, with a period of 2.5 seconds.
The maximum velocity of the particle will be reached when the force is at its maximum, which is when x = 2.5. The minimum velocity of the particle will be reached when the force is at its minimum, which is when x = 0.5.
Here is the solution:
The equation for the force is P = (3x² - 4x + 5)². We can differentiate this equation to find the velocity of the particle:
```
v = dx/dt = 6x(3x² - 4x + 5)
```
We can set this equation equal to zero to find the equilibrium points of the particle:
```
0 = 6x(3x² - 4x + 5)
```
This equation has two solutions: x = 0 and x = 2.5. The equilibrium point x = 0 is unstable, while the equilibrium point x = 2.5 is stable. This means that the particle will always oscillate around the equilibrium point x = 2.5.
The period of the oscillation can be found by using the following formula:
```
T = 2π√(m/k)
```
where m is the mass of the particle and k is the spring constant. In this case, the mass of the particle is 1 kg and the spring constant is 6. The period of the oscillation is then:
```
T = 2π√(1/6) = 2.5 seconds
```
The maximum velocity of the particle can be found by substituting x = 2.5 into the equation for the velocity:
```
v_max = 6(2.5)(3(2.5)² - 4(2.5) + 5) = 15 m/s
```
The minimum velocity of the particle can be found by substituting x = 0 into the equation for the velocity:
```
v_min = 6(0)(3(0)² - 4(0) + 5) = 0 m/s
```
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Energy is dissipated from a rollercoaster cart as it mo es along the track.
What forms of energy does the mechanical energy transform into? Identify
two examples of energy transformation. What obser ations would you
make that would indicate this transformation took place?
An overhead East-West transmission line carries a current of 250. A in each of two parallel wires. The two wires are separated by 1.20 m, the northern wire carries current to the east, and the southern wire carries current to the west. (a) Please find the magnitude and the direction of the magnetic field at a point midway between the two wires. (Ignore the carth's magnetic field.) (b) Please find the magnitude and the direction of the magnetic field at a point that is 2.00 m below the point of part (a). (lgnore the earth's magnetic field.)
Answer: (a) The magnitude of the magnetic field at a point midway between the two wires is 1.20 × 10⁻⁵ T and the direction of the magnetic field is out of the page.
(b) The magnitude of the magnetic field at a point that is 2.00 m below the point of part (a) is 2.93 × 10⁻⁷ T and the direction of the magnetic field is out of the page.
(a) The magnitude of the magnetic field at a point midway between the two wires is 1.20 × 10⁻⁵ T and the direction of the magnetic field is out of the page. Between two parallel current-carrying wires, the magnetic field has a direction that is perpendicular to both the direction of current flow and the direction that connects the two wires.
According to the right-hand rule, we can figure out the direction of the magnetic field. The right-hand rule says that if you point your thumb in the direction of the current and curl your fingers, your fingers point in the direction of the magnetic field. As a result, the northern wire's magnetic field is directed up, while the southern wire's magnetic field is directed down. Since the two magnetic fields have the same magnitude, they cancel each other out in the horizontal direction.
The magnetic field at the midpoint is therefore perpendicular to the plane formed by the two wires, and the magnitude is given by: B = (μ₀I)/(2πr) = (4π × 10⁻⁷ T · m/A) × (250 A) / (2π × 0.600 m) = 1.20 × 10⁻⁵ T.
The magnetic field is out of the page because the two magnetic fields are in opposite directions and cancel out in the horizontal direction.
(b) The magnitude of the magnetic field at a point that is 2.00 m below the point of part (a) is 2.93 × 10⁻⁷ T and the direction of the magnetic field is out of the page.
The magnetic field at a point that is 2.00 m below the midpoint is required. The magnetic field is inversely proportional to the square of the distance from the wires.
Therefore, the magnetic field at this point is given by: B = (μ₀I)/(2πr) = (4π × 10⁻⁷ T · m/A) × (250 A) / (2π × √(1.20² + 2²) m) = 2.93 × 10⁻⁷ T. The magnetic field at this point is out of the page since the wires are so far apart that they can be treated as two separate current sources. The field has the same magnitude as the field created by a single wire carrying a current of 250 A and located 1.20 m away.
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Johann squeezes a bagel too hard at the supermarket, and it does not return to its original shape when he removes his hand. The bagel has been __________ deformed. What word completes the sentence to show that the bagel has been permanently changed?
Answer:
permanent set
.............
Johann squeezes a bagel too hard that it is not able to return to its original shape. The bagel has Plastic deformation.
What is Plastic Deformation?Plasticity, also referred to as plastic deformation, is the property of a solid material to undergo permanent deformation, a non-reversible change in shape in response to applied forces.
It is a concept used in physics and materials science. For instance, plasticity is demonstrated when a solid piece of metal is bent or pounded into a new shape because the material itself undergoes lasting modifications. Engineering professionals use the term yield to describe the change from elastic to plastic behavior.
Most materials, especially metals, soils, rocks, concrete, and foams, show signs of plastic deformation.
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Calculate the amount or work done on a 25 N box that is lifted 1.5m off the floor. dont forget the units
So the amount of work done by us needed to displace the object at the
height of 1.5m is W=37.5J
(WILL GIVE BRAINLEST)A rock is resting on the ground. You decide to pick it up. The rock has a mass of 3 kg. You raise it up 1.5 m. How much energy does the rock have now, how much work did you do to pick it up? (HINT: The force is equal to the weight.)
According to the question the rock now has a potential energy of 4.5kJ.
What is potential energy?Potential energy is a type of energy that is stored and held by an object or system due to its position or configuration. This type of energy has the potential to do work or to transfer to other objects when the stored energy is converted into kinetic energy. Potential energy can be found in many forms, such as gravitational potential energy, elastic potential energy, chemical potential energy, electrical potential energy, and nuclear potential energy.
To calculate this, we use the equation for potential energy: PE = mgh (mass x gravity x height). In this case, the mass is 3kg, the gravity is 9.8 m/s2, and the height is 1.5 m.
So
, \(PE = (3 kg)(9.8 m/s^2)(1.5 m)\\= 4.5 kJ.\)
The work done to pick up the rock is also 4.5kJ. This is calculated using the equation W = Fd (force x distance). Since the force is equal to the weight, we can use the same equation for PE (mgh) to calculate the work done.
So,
\(PE = (3 kg)(9.8 m/s^2)(1.5 m)\\= 4.5 kJ.\)
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100 J of work was done to lift a 10-N rock and set it at Position A near the edge of a cliff.
1. If the 100 Joules of work lifted the rock to the top of the cliff, how much potential energy did the rock gain?
2. At point C, the rock's potential energy will be
3. The rock's kinetic energy at point A is
4. At point B, some of the rock's potential energy will be changed to Kinetic energy
5. What is the mass of the rock?
6. What is the rock's velocity just before it hits the ground?
The rock to the right is sitting at the top of a ramp. I wonder how much work it required to get that rock up there.
Can you figure it out?
Please show work!
Please Help!!
By using the concept of work and energy, the below are the answers
1. 100J
2. 100J
3. 0
4. Total energy = K.E + P.E
5. 1.02 kg
6. 14 m/s
Given that 100 J of work was done to lift a 10-N rock and set it at Position A near the edge of a cliff.
1. If the 100 Joules of work lifted the rock to the top of the cliff, how much potential energy did the rock gain?
Work is the product of force and the distance.
The potential energy gained by the rock will be equal to work done in lifting up the rock which is 100 J
2. At point C, the rock's potential energy will be equal to the work done.
That is, at point C, P.E = 100J
3. The rock's kinetic energy at point A is Zero.
That is, at point A, K.E = 0
4. At point B, some of the rock's potential energy will be changed to Kinetic energy. Yes. Because the Total energy = K.E + P.E
5. What is the mass of the rock?
Weight W = mg
where g = 9.8m/s^2
W = 10N
Substitute both into the formula
10 = 9.8m
make m the subject of the formula
m = 10/9.8
m = 1.02 kg
6. What is the rock's velocity just before it hits the ground
Work done = Energy
That is, Work done = maximum P.E = maximum K.E
100 = 1/2m\(v^{2}\)
Substitute mass into the formula
200 = 1.02\(V^{2}\)
V = \(\sqrt{196}\)
V = 14 m/s
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A car is moving with a constant speed of 15 meters per second. What total
distance does the car travel in 90 seconds?
Answer:
1350 meters
Explanation:
this is easy
15 meters per second
90 seconds
90 * 15 = 1350
When is a hypothesis developed in the scientific method?
after a question has been identified and observations are made
after an experiment
if the experiment justifies one
before there is a question
Answer: The scientific method is a useful way of guiding scientists through an investigation. A hypothesis is developed from an idea or question based on an observation.
Explanation:
The element lanthanum has an isotope with an atomic mass of 138. 9 amu and an abundance of 99. 91%. A second isotope has an atomic mass of 137. 9 amu and an abundance of 0. 9%. What is the average atomic mass of lanthanum?.
The average atomic mass of lanthanum that has an isotope with an atomic mass of 138.9 amu and an abundance of 99.9 1% and a second isotope with an atomic mass of 137.9 amu and an abundance of 0.09 % is
Average atomic m = Sum of product of atomic m and % abundance / 100
For isotope 1,
Atomic mass = 138.9 amu
% abundance = 99.91 %
For isotope 2,
Atomic mass = 137.9 amu
% abundance = 0.09 %
Average atomic mass = ( 138.9 * 99.91 ) + ( 137.9 * 0.09 ) / 100
Average atomic mass = 13877.5 + 12.41 / 100
Average atomic mass = 138.9 amu
The average atomic mass or average atomic weight of an element is the weighted average mass or weight of atoms in a naturally occurring sample ( i.e., isotopes ) of the element.
Therefore, the average atomic mass of lanthanum is 138.9 amu
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To launch a 100 kg human so that he leaves a cannon moving at a speed of 4 m/s, you need a spring with an appropriate spring constant. This spring will be compressed 2.0 m from its natural length to launch the person. Which spring constant do you need? o 200 N/m o 400 N/m o 1600 N/m o 800 N/m
To launch a 100 kg human with a velocity of 4 m/s using a spring, we can use the conservation of energy.
The energy stored in the spring when it is compressed is given by:
E = 1/2 kx^2
where k is the spring constant, x is the compression of the spring from its natural length.
The total energy required to launch the person is the sum of the potential energy stored in the compressed spring and the kinetic energy of the person after being launched. This is given by:
E = 1/2 mv^2
where m is the mass of the person, and v is the velocity at which the person is launched.
Since energy is conserved, we can equate the two expressions for energy:
1/2 kx^2 = 1/2 mv^2
Substituting the given values, we get:
1/2 k(2.0 m)^2 = 1/2 (100 kg)(4 m/s)^2
Simplifying the equation, we get:
k = (100 kg)(4 m/s)^2 / (2.0 m)^2 = 1600 N/m
Therefore, the spring constant required to launch the person is 1600 N/m. The correct answer is o 1600 N/m.
Crickets can jump with a vertical velocity of up to 14 ft/s. which equation models the height of such a jump, in feet, after t seconds? h(t) = –16t2 v0t h0 h(t) = –16t2 v0t 14 h(t) = –16t2 14t h(t) = –16t2 14t 14
The correct answer is option B.
Why is Option B the correct option?
It is given that crickets can jump with a vertical velocity of up to 14 ft/s.
It is also given that the equation that models the height of a jump after t seconds is given by
\(h(t)=-16t^{2} + V0+h0\)
where \(v0\) is the initial velocity
\(h0\) is the initial height
Since, it is given that \(v0=14\) and \(h0=0\)
Substituting these values in the equation ,we get,
\(h(t)=-16t^{2} +14t+0\)
\(h(t)=-16^{2} +14t\)
Thus option B is the correct answer.
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Answer:
h(t) = –16t2 + 14t
Explanation:
A solenoid of 100 turns has a length of 50.0 cm and a cross-sectional area of 0.385m^2. a) Find the self-inductance of the solenoid. b) Suppose the current in the solenoid increases according to the following formula. I(t)=(5.00A)e^t/2.00s
Find the induced emf in the solenoid when t=20.0 s.
Length of the solenoid, l = 50.0 cm = 0.50 mA = 0.385 m²µ₀ = 4π x 10⁻⁷ H/m. L = (µ₀N²A)/lL = [4π x 10⁻⁷ H/m × (100)² × 0.385 m²]/0.50 mL = 7.87 x 10⁻⁴ H. The induced emf in the solenoid when t=20.0 s is -4.13 V
a) Find the self-inductance of the solenoid.
A solenoid is a type of electromagnet, the wire coiled up such that it produces a magnetic field when electric current passes through it.
The self-inductance of the solenoid can be given by the formula:
L= (µ₀N²A)/
lwhere µ₀ is the permeability of free space
N is the number of turns of the solenoid
l is the length of the solenoid
A is the cross-sectional area of the solenoid
Given that, Number of turns, N = 100
Length of the solenoid, l = 50.0 cm = 0.50 mA = 0.385 m²µ₀ = 4π x 10⁻⁷ H/m. L = (µ₀N²A)/lL = [4π x 10⁻⁷ H/m × (100)² × 0.385 m²]/0.50 mL = 7.87 x 10⁻⁴ H.
b) Find the induced emf in the solenoid when t = 20.0 s.
The induced emf (ε) can be calculated by the formula;
ε = -L dI/dt
where L is the self-inductance of the solenoid and dI/dt is the time rate of change of the current given by;
I(t)=(5.00A)e^t/2.00s
Differentiating I(t) with respect to t gives; dI/dt = 5e^t/2 V/s (Volts per second)Given that L = 7.87 x 10⁻⁴ HWhen t = 20.0s; ε = - L dI/dt = -7.87 × 10⁻⁴ H × (5e^20/2) = -4.13 V
Therefore, the induced emf in the solenoid when t=20.0 s is -4.13 V.
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A group of people are pushing a stalled car with a mass of 700kg. If they push with a net force of 200 Newtons for 8 seconds, what is the cars final velocity
A 700 kg car that has stalled is being pushed by a group of people. The final velocity of the car will be 2.28 seconds if they push with a net force of 200 Newtons for 8 seconds.
What does a change in momentum mean?The change in momentum (Δp ) is defined as the change in the product of an object's mass and velocity. A force is required to change the momentum of an object. The momentum of the item may change due to the applied force, as well as its direction.
Why is an impulse a change in momentum?Any moving object can have momentum because momentum is defined as mass in motion. The impulse of an item is equal to its change in momentum. Impulse is defined as a force multiplied by a time period. Instead of being the same as momentum, impulse is the change in momentum of an object.
Impulse = Impulsive force x Impact time
Impulse = 200N x 8s = 1600Ns
To calculate final velocity of car,
Impulse = change in momentum
1600 = 700 (v-0)
1600 = 700v
v = 1600/700
v = 2.28 m/s
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Two identical twins hold on to a rope, one at each end, on a smooth, frictionless ice surface. They skate in a circle about the center of the rope (the center of mass of the two-body system) and perpendicular to the ice. The mass of each twin is 83.0 kg. The rope of negligible mass is 4.5 m long and they move at a speed of 4.10 m/s.
(a) What is the magnitude of the angular momentum (kg-m2/s) of the system comprised of the two twins?
(b) They now pull on the rope and move closer to each other so that the rope between them is now half as long. Determine the speed (in m/s) with which they move now.
(c) The two twins have to do work in order to move closer to each other. How much work (in J) did they do?
In the case, the magnitude of the angular momentum of the system comprised of the two twins is 1.22 × 10³ kg m²/s, the speed with which they move now is 18.5 m/s, and the value work is 6.97 × 10³ J.
The magnitude of the angular momentum (kg-m2/s) of the system comprised of the two twins.
Let us begin with the formula for angular momentum, i.e.,
L = Iω.
I = Moment of Inertia = m(r^2)/2
ω = angular velocity
I = 2 × (83/2)(4.5/2)^2
ω = (v/r)
Therefore,
L = Iω= 1.22 × 10³ kg m²/s
They now pull on the rope and move closer to each other so that the rope between them is now half as long. Determine the speed (in m/s) with which they move now.
In the beginning, the length of the rope was 4.5m.
After they move closer, the length of the rope is now 2.25m.Before moving closer:
v = 4.10 m/sr = 4.5/2 = 2.25 m
After moving closer: r = 2.25 m
Therefore, rω = constant, which implies that v = rω.
Since r decreases, ω must increase to keep the product constant.
ω1r1 = ω2r2v1 = r1ω1 ; v2 = r2ω2v2 = (2.25m)(8.20 rad/s)= 18.5 m/s
The two twins have to do work in order to move closer to each other.
How much work (in J) did they do?
To calculate the work done, let us begin with the equation of kinetic energy, K = (1/2)Iω².
K = (1/2)I1ω1² = (1/2)I2ω2²
I1 = 2(83.0/2)(4.5/2)^2I2 = 2(83.0/2)(4.5/4)^2
Therefore, the work done W = (1/2)(I2ω2² - I1ω1²)= 6.97 × 10³ J
Therefore, the work done by the twins is 6.97 × 10³ J.
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Places where particles of the medium spread farther apart are called
Rarefactions are areas where the medium's particles have spread further apart.
A rarefaction is a localized decrease in the density of a medium caused by an increase in pressure or temperature. This decrease in density causes the particles of the medium to spread farther apart. This phenomenon is typically observed in sound waves but can also be seen in other forms of wave propagation, such as in light and water waves. As sound waves move through a medium, they cause the particles of the medium to compress, or come closer together. This creates a region of high pressure. As the wave continues to move, the pressure decreases, and the particles spread farther apart. This creates a rarefaction region. Rarefactions can also be caused by a decrease in temperature, which reduces the pressure of the medium, causing the particles to spread farther apart.
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If the electrons in an atom were stationary, they would be ___ the nucleus
Answer:
Matter in the universe is made up of atoms, particles if electrons were to be stationary, they would have fallen into the nucleus because of electrostatic force acting on them destroying very existence of an atom we know.
A ball was dropped and had a mass of .2 kg and was falling with a force of 2 N, what was its acceleration?
Answer:
10m/s I believe
Explanation:
F=MA
A=F/M
A=2/0.2
A=10m/s
Un auto se mueve con MRU y recorre un espacio de 5km en un cuarto de hora (15 minutos) calcule la velocidad en m/s
Explanation:
5 km en 15 min.
= 5000 metros en 900 segundos
dividimos
la velocidad es de 5,56m/s
Espero que te sirva
A box is being pulled to the right. The free body diagram is shown.
A free body diagram with 4 forces. The first pointing north labeled 438 N, the second pointing northeast labeled 125 N, the third pointing south labeled 500 N, and the fourth pointing west labeled 25 N.
What is the magnitude of the kinetic frictional force?
25 N
125 N
375 N
500 N
Answer:
25N
Explanation:
Answer:
the answer is A
A is 25N
What is the ratio of the orbital velocity of a terrestrial planet orbiting at 5.00 AU from its star to that of a giant planet orbiting at 19.00 AU? NOTE: You may assume circular orbits.
The ratio of the velocities of the two planets is 0.482
The velocity v of the planet in its circular orbit can be calculated using the following formula: v = 2πr/T
So, v = 2πr/ T
Where T is the time period of revolution of the planet around the star, r is the radius of the circular orbit, and v is the velocity of the planet in its orbit.
Since we can assume circular orbits, we have v ∝ r^-1/2.
Therefore, the ratio of velocities of the two planets is given as follows:
V1 / V2 = (r1 / r2)^(1/2)
Where, V1 is the velocity of the terrestrial planet orbiting at 5.00 AU, r1 is the radius of the orbit of the terrestrial planet around the star, V2 is the velocity of the giant planet orbiting at 19.00 AU, and r2 is the radius of the orbit of the giant planet around the star.
Therefore, substituting r1 = 5.00 AU, r2 = 19.00 AU, we get the ratio of the velocities of the two planets as:
V1 / V2 = (5/19)^(1/2)
V1 / V2 = 0.482
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how many sig figs does 0.009 have?
Jenny was applying her makeup when she drove into the student parking lot last Friday morning . Unaware that Cheryl was stopped in her lane aheadJenny rear ended Cheryl's car. Jenny's 1300-kg car was moving at 11 m/s and stopped in 0.14 seconds . Determine the magnitude of the force experienced by Jenny's car .
Answer: F = 102141N
Explanation: Newton's 2nd Law states that a force can change the motion of a body. The relation is given by
F = m.a
whose units are:
[F] = N
[m] = kg
[a] = m/s²
Jenny's car, at the moment of the break, had acceleration:
\(a=\frac{\Delta v}{\Delta t}\)
\(a=\frac{11}{0.14}\)
a = 78.57 m/s²
Then, Force is
F = 1300*78.57
F = 102141 N
Jenny's car experienced a force of magnitude 102141N.
the radiation belts around jupiter are much stronger than those found around earth because? a) Jupiter has larger storms than Earth;
b) Jupiter is colder than Earth;
c) Jupiter rotates faster than Earth;
d) Jupiter has a stronger magnetic field than Earth.
The radiation belts around Jupiter are much stronger than those found around Earth because: d) Jupiter has a stronger magnetic field than Earth.
Jupiter possesses a significantly stronger magnetic field compared to Earth, which contributes to the intensification of its radiation belts. The planet's powerful magnetic field interacts with charged particles from various sources, such as the solar wind and its own volcanic moon Io, trapping and accelerating them. These charged particles become trapped in the magnetic field, forming the radiation belts.
The combination of Jupiter's strong magnetic field and its interaction with energetic particles results in the generation of highly energetic radiation belts around the planet. These belts are composed of charged particles, including electrons and ions, that are accelerated to high speeds within Jupiter's magnetic field. This makes Jupiter's radiation belts much more intense than those found around Earth.
Factors such as larger storms, colder temperatures, or faster rotation do not directly contribute to the strength of Jupiter's radiation belts. It is primarily the planet's robust magnetic field that accounts for the enhanced intensity of its radiation belts.
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Your cat has a mass of 4.5 kg. He is sitting on top of the refrigerator ready to pounce. The refrigerator is 1.8 meters tall. What is his potential energy?
Answer:
79.38 J
Explanation:
W = mgz = 4.5*9.8*1.8 (with g = 9.8 m/s^2)
= 79.38 K