Answers
The electrical mobility of charged particles in a fluid under an applied electric field includes particular instances such as electron and hole mobility.
Electrons or holes make up the charge carriers?Most electric circuits and devices use negatively charged electrons as their charge carriers, which move when subjected to a voltage to produce an electric current.
Which carrier mobility for electrons and holes is highest?Mobile charge carriers include electrons and holes. Electrons can move around 2.5–3 times as quickly as holes can. Their effective masses affect both electron and hole mobility. Due to their greater mobility than holes due to their lower effective mass than holes, electrons.
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Related Questions
what is a hyponyms and a what is its meaning
Answers
A hyponym is a word or phrase whose semantic field is more specific than its hypernym. ... For example, verbs such as stare, gaze, view and peer can also be considered hyponyms of the verb look, which is their hypernym. Hypernyms and hyponyms are asymmetric.
Which best describes earth's magnetic field lines?
Answers
Answer:
The field lines go out of Earth near Antarctica, enter Earth in northern Canada, and are not aligned with the geographic poles.
Explanation:
Answer: the field lines go out of earth near the north pole, enter earth in the south pole, and are not aligned with the geographic poles.
Explanation: just took the test on edge 2020.
How much potential energy does a person of mass 50 kg have if they are standing at the top of a building that is 54.8 m high? Submit your answer in exponential form.
Answers
ANSWER:
2.69 x 10^4 J
STEP-BY-STEP EXPLANATION:
Given:
Mass (m) = 50 kg
Height (h) = 54.8 m
The potential energy is calculated by the following formula:
\(E=m\cdot g\cdot h\)We replace and determine the value of the energy:
\(\begin{gathered} E=50\cdot9.8\cdot54.8 \\ \\ E=26852=2.69\cdot10^4\text{ J} \end{gathered}\)The potential energy is equal to 2.69 x 10^4 joules.
Which law of thermodynamics does each of the following scenarios violate (if any)?
A machine that can create 1000J of heat from 100J of electricity
1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed
Answers
The scenario described violates option 2. the second law of thermodynamics.
The second law of thermodynamics states that in any energy transfer or transformation, the total entropy of an isolated system always increases or remains constant, but it never decreases. Entropy can be thought of as a measure of the disorder or randomness in a system.
In the given scenario, the machine is claimed to create 1000J of heat energy from only 100J of electrical energy. Heat energy is a form of random molecular motion, and the conversion of electrical energy to heat involves an increase in entropy. According to the second law, energy transfers or transformations must always lead to an overall increase in entropy.
However, in this scenario, the machine appears to violate the second law by creating a significant amount of heat energy from a relatively small amount of electrical energy. This would imply a decrease in entropy, which contradicts the fundamental principle of the second law.
In reality, no machine can achieve 100% efficiency, meaning it cannot convert all the input energy into the desired output energy without any energy losses. Some energy will always be lost as waste heat due to inefficiencies in the conversion process. This waste heat contributes to the increase in entropy.
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What is Solar Energy used for? Use in your own words.
Answers
Answer:
TO POWER ELECTRIC GADGETS AND SAVE EARTH FROM POLLUTION
Explanation:
An electric iron is Mark 120 volts and 500 Watts to units consumed by it in using it for 24 hours will be
Answers
An electric iron is marked 120 volts and 500 Watts. The units consumed by it in using it for 24 hours can be calculated using the formula:Power (in watts) = Voltage (in volts) x Current (in amperes)P = V x I
Using the above formula, we can find the current drawn by the electric iron as follows:I = P/VI = 500/120I = 4.17 ATherefore, the power consumed by the electric iron in 24 hours is:P = VI x tP = 120 x 4.17 x 24P = 120 x 100.08P = 12010.56 watt-hoursTo convert watt-hours to kilowatt-hours, we divide by 1000: Energy consumed = 12010.56 / 1000Energy consumed = 12.01 kWhHence, the units consumed by the electric iron in 24 hours is 12.01 kilowatt-hours.For such more question on Voltage
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Select the correct answer from each drop-down menu. Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. Complete the passage summarizing the collision. On colliding, the truck applies a force on the stationary car, and the stationary car applies and opposite force on the truck. The front of the truck is designed to crumple in order to , which protects the well-being of the passengers.
Answers
The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.
Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.
During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.
The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.
By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.
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Scientists might make a computer model of volcanic eruptions. What is the
biggest benefit of this model?
Answers
Answer:
Computer Model May Help to More Accurately Predict Volcano Eruptions. Scientists at the GFZ German Research Center in Potsdam, Germany, have developed a computer model which they say boosts the accuracy of volcanic eruption prediction.
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A sleigh is being pulled horizontally by a train of horses at a constant speed of 6.38 m/s. The magnitude of the normal force exerted by the snow-covered ground on the sleigh is 7.50 ✕ 103 N.
(a) If the coefficient of kinetic friction between the sleigh and the ground is 0.26, what is the magnitude of the kinetic friction force experienced by the sleigh?
N
(b) If the only other horizontal force exerted on the sleigh is due to the horses pulling the sleigh, what must be the magnitude of this force?
N
Answers
Answer:
(a). The kinetic friction force is 1950 N.
(b). The magnitude of force will be equal of friction force
Explanation:
Given that,
Constant speed = 6.38 m/s
Force \(F=7.50\times10^{3}\ N\)
Kinetic friction = 0.26
(a). We need to calculate the friction force
Using formula of friction force
\(f_{k}=\mu F_{N}\)
Put the value into the formula
\(f_{k}=0.26\times7.50\times10^{3}\)
\(f_{k}=1950\ N\)
(b). If the only other horizontal force exerted on the sleigh is due to the horses pulling the sleigh,
We need to calculate the magnitude of this force
According to given data,
The same force will be applied to keep constant velocity.
Hence, (a). The kinetic friction force is 1950 N.
(b). The magnitude of force will be equal of friction force.
(a). The kinetic friction force is 1950 N.
(b). The magnitude of force will be equal of friction force
The calculation is as follows;a. The magnitude of the kinetic friction force experienced by the sleigh is
\(= 0.76 \times 7.50 \times 10^3\)
= 1950 N
b. It should be equivalent to the friction force.
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Wrecking balls are used to demolish old buildings. A 850 kg steel ball is suspended from a 10m-long cable on a crane. A hook on the crane slowly pulls the ball back, then releases it. The ball's speed at the lowest point in its arc, just before striking the building, is 4.5 m/s
At the lowest point in the ball's arc, (pick one)
1. the tension in the cable is less than mg because the ball is moving down.
2. the tension in the cable is equal to mg because tension and gravity are the only forces and they balance.
3. the tension in the cable is greater than mgbecause there has to be a net upward force.
What is the tension in the cable when the ball is at its lowest point?
Answers
The ball is briefly at rest and has zero acceleration at the lowest point of its arc. When the ball is at its lowest position, there is 8330 N of tension in the cable.
What does tension feel like at its greatest and lowest points?There won't be any tension and weight will act downward and centrifugal force upward at the highest position. (as stated). As a result, the tension is 6 mg at the lower point and zero at the higher point.
Is there tension in the rope when the ball is at its lowest point?Is the tension in the string higher, lower, or equal to the weight of the ball at its lowest point? The weight of the ball is outweighed by the strain in the string.
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PLS HELP THIS IS MY LAST QUESTION :)
Answers
Answer:
All of the above
Explanation:
At start it has only PE
PE is converted to KE
at bottom all of the PE is now KE
KE and PE along the way = PE at the start
a car travelling at 18 km/hr accelerates uniformly at 2m per seconds square. calculate its velocity in km/hr in 5 seconds
Answers
1 km = 1000 m
1 hr = 3600 s
So, 18 km/hr = (18 * 1000) / (3600) m/s = 5 m/s
And 2 m/s^2 = 2 m/s^2
Now, we can use the formula for final velocity (v) when an object starts with an initial velocity (u) and accelerates at a constant rate (a) for a given time (t):
v = u + at
Plugging in the values, we get:
v = 5 + (2 * 5) m/s v = 15 m/s
To convert this back to km/hr, we use the inverse conversions: v = (15 * 3600) / (1000) km/hr v = 54 km/hr
Therefore, the car’s velocity in km/hr after 5 seconds is 54 km/hr.
The nuchal ligament in a horse supports the weight of the horse's head. This ligament is much more elastic than a typical ligament, stretching from 15% to 45% longer than its resting length as a horse's head moves up and down while it runs This stretch of the ligament stores energy, making locomotion more efficient. Measurements on a segment of ligament show a linear stress-versus-strain relationship until the strain approaches 0.80. Smoothed data for the stretch are shown in (Figure 1).
The segment of ligament tested has a resting length of 40 mm.
How long is the ligament at a strain of 0.60?
Answers
Answer:
Explanation:The nuchal ligament in a horse supports the weight of the horse's head. This ligament is much more elastic than a typical ligament, stretching from 15% to 45% longer than its resting length as a horse's head moves up and down while it runs This stretch of the ligament stores energy, making locomotion more efficient. Measurements on a segment of ligament show a linear stress-versus-strain relationship until the strain approaches 0.80. Smoothed data for the stretch are shown in (Figure 1).
The segment of ligament tested has a resting length of 40 mm.
How long is the ligament at a strain of 0.60?
Unfortunately, there is no image or data provided for "Figure 1" in the given question. Therefore, it is impossible to determine the length of the ligament at a strain of 0.60. Can you please provide more information or context for this question?
Hyper Hamza
The nuchal ligament in a horse supports the weight of the horse's head. This ligament is much more elastic than a typical ligament, stretching from 15% to 45% longer than its resting length as a horse's head moves up and down while it runs This stretch of the ligament stores energy, making locomotion more efficient. Measurements on a segment of ligament show a linear stress-versus-strain relationship until the strain approaches 0.80. Smoothed data for the stretch are shown
The segment of ligament tested has a resting length of 40 mm.
How long is the ligament at a strain of 0.60?
Assuming we have the data for the stress-strain relationship of the nuchal ligament in a horse, we can use the linear relationship between stress and strain to determine the length of the ligament at a strain of 0.60.
Let's say that the stress-strain data for the nuchal ligament is given by the equation:
stress = m * strain + c
where m is the slope of the line and c is the y-intercept.
Since the stress-strain relationship is linear, we can determine the slope and y-intercept using two points on the line. We can use the resting length of the ligament (40 mm) and the strain at which the linear relationship breaks down (0.80) to determine the slope and y-intercept.
At a strain of 0, the length of the ligament is the resting length (40 mm). At a strain of 0.80, the length of the ligament is:
Length at strain 0.80 = resting length * (1 + strain) = 40 mm * (1 + 0.80) = 72 mm
So we have two points on the line: (0, 40) and (0.80, 72). Using these two points, we can calculate the slope:
m = (y2 - y1) / (x2 - x1) = (72 - 40) / (0.80 - 0) = 90
And the y-intercept:
c = y1 - m * x1 = 40 - 90 * 0 = 40
Now we can use the equation of the line to find the length of the ligament at a strain of 0.60:
stress = m * strain + c
stress = 90 * 0.60 + 40
stress = 94
At a strain of 0.60, the stress in the ligament is 94. We can use this stress value and the slope of the line to find the corresponding length of the ligament:
stress = m * strain + c
94 = 90 * 0.60 + 40
94 = 94
Therefore, the length of the ligament at a strain of 0.60 is 64 mm.
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Examine the image and assess the relationship of the atoms shown by
Answers
The reactants in the given chemical equation are methane (CH₄) and oxygen (O₂), while the products are carbon dioxide (CO₂) and water (H₂O).
During a chemical reaction, the atoms of the reactants reorganize to form new compounds in the products. A chemical change is this atomic rearrangement.
What is a change in chemistry?A chemical change is the transformation of one or more substances into new ones with distinct chemical and physical properties. New substances are created when the original substances' atoms are rearranged and new chemical bonds are formed during a chemical change.
Typically, a transfer of energy in the form of heat, light, or sound occurs in conjunction with this kind of change. Reactions like combustion, oxidation, decomposition, and synthesis are all examples of chemical changes. Physical changes, on the other hand, involve alterations in a substance's physical properties without altering its chemical composition.
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2(a)Find the density of air filled in polythene container with mass of 0.419kg when it is empty. When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times
Answers
When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.
The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.
Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:
Mass of air = Mass of filled container - Mass of empty container
= 0.428 kg - 0.419 kg
= 0.009 kg
Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:
Volume of air = Volume of perplex box * Number of times air inside
= 1000 cm³ * 7.2
= 7200 cm³
Convert the volume of air to cubic meters (m³) by dividing by 1000000:
Volume of air = 7200 cm³ / 1000000
= 0.0072 m³
Calculate the density of air using the formula:
Density = Mass / Volume
Density = 0.009 kg / 0.0072 m³
≈ 1.25 kg/m³
Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.
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What amount of force is required to accelerate a 20 gram toy car at 5 m/s²?
O 150 N
O 100 N
O 50 N
Ο ΟΝ
Answers
Answer:
100
Explanation:
F = m * a
Given that the mass (m) of the toy car is 20 grams (or 0.02 kilograms, since 1 kilogram = 1000 grams) and the acceleration (a) is 5 m/s^2, we can plug these values into the formula to calculate the force (F):
F = 0.02 kg * 5 m/s^2 = 0.1 N
So, the amount of force required to accelerate the 20 gram toy car at 5 m/s^2 is 0.1 N, which is equivalent to 100 N when rounded to the nearest whole number. Therefore, the correct answer is 100 N.
a unit of time yr is defined as 365.25 days . how many seconds are there in 1.40yr
Answers
There are 44180640 seconds in 1.40 year .
What is a year?365 or 366 days, divided into 12 months or 52 weeks, make up the time from 1 January to 31 December, or a year.
1 year equals to 365.25 days
1.40 years equal to (1.40 × 365.25 days)
= 511.35 days.
1 day equals to 24 hours.
1 hour equals to 60 minute.
1 day equals to (24 × 60 × 60) second = 86400 seconds.
511.35 days equals to (511.35 × 86400 seconds) = 44180640 seconds
So, 1.40 years equal to 44180640 seconds.
Hence, There are 44180640 seconds in 1.40yr .
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a machine
of efficiency of 70% is used to raise
a body of
mass 80 kg through
a vertical distance of 3m in
40 seconds. Calculate the power input. (Take g = 10 m/s²)
Answers
Answer:
Power_input = 85.71 [W]
Explanation:
To be able to solve this problem we must first find the work done. Work is defined as the product of force by distance.
\(W =F*d\)
where:
W = work [J] (units of Joules)
F = force [N] (units of Newton)
d = distance [m]
We need to bear in mind that the force can be calculated by multiplying the mass by the gravity acceleration.
Now replacing:
\(W=m*g*d\)
\(W=80*10*3\\W=2400[J]\)
Power is defined as the work done over a certain time. In this way by means of the following formula, we can calculate the required power.
\(P=W/t\)
where:
P = power [W] (units of watts)
W = work [J]
t = time = 40 [s]
\(P=W/t\\P=2400/40\\P=60 [W]\)
The calculated power is the required power. Now as we have the efficiency of the machine, we can calculate the power that is introduced, to be able to do that work.
\(Effic=0.7\\Effic=P_{required}/P_{introduced}\\P_{introduced}= 60/0.7\\P_{introduced}=85.71[W]\)
which statement would need to be true for astrology to be considered a science?
Answers
A. Experimental evidence is collected that supports that astrology is to be considered a science.
Which statement best describes that the astrology is the part of science?Through experiments and researches, we can collect a lot of evidences about the relationship between science and astrology. If the evidences are in favour of astrology so we can say that astrology is to be considered as science. The invention of the astrology was made in Babylon far back in antiquity. An astrology is not considered to be the part of the science, because there is no evidence present in the history that the astrology is the part of the science. But the main thing is that the astrology contains the logics, and logics is present in the science. So there is a very small relation between the astrology and the science.
So we can conclude that Experimental evidence is collected that supports it is the correct statement.
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A. Experimental evidence is collected that supports it.
B. The majority of people believe that its claims are true.
C. Its explanations are supported by a scientific law.
d. Government funding is used to support it.
Which of the following solar phenomena is likely to have the most negative impact on Earth?
A solar flare as it may cause brief radio blackouts
An aurora as it may damage communication networks
An aurora as it may cause worldwide transmission problems
A solar flare as it may harm satellites and aircrafts flying near poles
Answers
Answer:
A solar flare as it may harm satellites and aircrafts flying near poles
Explanation:
Since solar flare is electro magnetic waves going to Earth the waves will mostly get absorbed by the north and south poles resulting in the aurora borealis, but if the solar flare is strong enough it may stop communications and engines in satellites and aircrafts and in result harming them
Answer:
A solar flare as it may harm satellites and aircrafts flying near poles
Explanation:
An orange of mass 3kg falls from a height 50m. When its height is H, its speed is
4m/s?
Write an expression that describes the conservation of energy with the given
numbers and H. You don't have to solve for H.
Answers
Answer:
(10 m/s²) (50 m) = (10 m/s²) H + ½ (4 m/s)²
Explanation:
Initially, the orange has only gravitational potential energy.
As the orange falls, it has a combination of potential energy and kinetic energy.
Energy is conserved, so initial energy = final energy:
PE₀ = PE + KE
mgH₀ = mgH + ½ mv²
gH₀ = gH + ½ v²
Plugging in values:
(10 m/s²) (50 m) = (10 m/s²) H + ½ (4 m/s)²
A uniform solid cylindrical flywheel has a mass of 50 kg and a radius of 40 cm. The flywheel begins to rotate faster with an acceleration of 1.5 rad/s2. The kinetic energy of the flywheel after 1 minute of rotation is:
A. 16.2 KJ
B. 180 KJ
C. 40.5 KJ
D. 32.4 KJ
Answers
The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)
How do I determine the kinetic energy?We'll begin by obtaining the velocity of the flywheel. This is shown below:
Radius (r) = 40 cm = 40 / 100 = 0.4 mAcceleration (a) = 1.5 rad/s² = 1.5 × 0.4 = 0.6 m/s²Time (t) = 1 minute = 1 × 60 = 60 sVelocity (v) = ?v = at
v = 0.6 × 60
v = 36 m/s
Finally, we shall determine the kinetic energy of the flywheel. Details below:
Mass (m) = 50 KgVelocity (v) = 36 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 50 × 36²
KE = 25 × 1296
KE = 32400 J
Divide by 1000 to express in KJ
KE = 32400 / 1000
KE = 32.4 KJ
Thus, the kinetic energy is 32.4 KJ (Option D)
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Calculate the pressure in pascals if a 560N is applied to an area of 1.6m².
Answers
Answer:
P = 350 [Pa]
Explanation:
The pressure is calculated by knowing the force and area. By means of the following formula can be calculated by means of the following equation.
Units of 1 [Pa] = 1 [N/m²]
P = F/A
where:
P = pressure [Pa]
F = force = 560 [N]
A = area = 1.6 [m²]
P = 560/1.6
P = 350 [Pa]
You put your book on the bus seat next to you. When the bus stops suddenly the book slides forward off the seat. Why?
A.) The book received a push from the seat hitting it.
B.) The force applied by the bus caused it to accelerate forward.
C.) The book's inertia carried it forward.
D.) The book could never slide forward to begin with.
Answers
Answer:
C) The book's inertia carried it forward.
When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.
1. Which distance is the greatest?
O 7000 meters
O 99.99 meters
O 4.5 x 10³ meters
O 9.0 x 10² meters
Answers
Answer:
7000 meters
Explanation:
obviously 99.99 is less than 7000
10 cubed is 10 × 10 × 10, 1000, × 4.5 is 4500, which is less than 7000
10 squared is 100, which × 9 is only 900, which is also less than 7000
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The displacement x of a particle varies with time t as x = 4t 2 -15t + 25. Find the position,
velocity and acceleration of the particle at t = 0. When will the velocity of the particle becomes
zero? Can we call the motion of the particle as one with uniform acceleration?
Answers
Answer:
x = 4 t^2 - 15 t + 25 displacement of particle
dx / dt = 8 t - 15 velocity of particle
d^2x / dt^2 = 8 acceleration of particle
If 8 t -15 = o then t = 8 / 15
Since acceleration is a constant 8 then motion has uniform acceleratkon
: Activity: A liquid of unknown specific heat at a temperature of 20°C wa: 80°C in a well-insulated container. The final temperature was measure combined mass of the two liquids was measured to be 240g. In a se both liquids at the same initial temperatures, 20 g less of the liquid of was poured into the same amount of water as before. This time the ec was found to be 52°C. Determine the specific heat of the liquid. The s 4187 J/Kg°C or 1 kcal/kg°C.
Answers
Answer:
Specific heat capacity of unknown liquid is given as,
\(S_{liq} =7.77J/g\)°\(C\)
Explanation:
Let the mass of unknown liquid is "m"
Now when unknown liquid is mixed with water then heat given by water is equal to the heat absorbed by unknown liquid
So we have
Msliq ( 50 - 20 ) = (240 - m) (4.2)(80-50)
Now again we did the same experiment but this time the mass of unknown liquid is "m - 20"
so we have
(m-20)Sliq(52-20)=(220-m)(4.2)(80-52)
now from above two equations
m(30)/(m-20)32 = (240-m)30/(220-m)/28
Now we have
30m * 28 (220 - m) = 32 ( m- 20) * 30 ( 240 - m)
so we have
m = 84.2g
Now we have
Sliq = 240-84.2/84.2 (4.2)
Sliq = 7.77J/g°C
what is the value of the x component of the car's average velocity, in meters per second, during the given time interval
Answers
To find the component of car's average velocity along X-axis, the angle between the the direction of the velocity and the X-axis must be known.
The value of x component of the car's average velocity is Vcosx.
Calculation of the x component of the car's average velocityLet the angle be = x
The X-component of the car's average velocity = Vcosx.
V is the magnitude of the velocity.
To calculate the y component of the car's average velocity
The Y-component of the velocity = Vsinx
What does the phrase "average velocity" actually mean in context?The difference between the change in position or displacement (x) and the time periods (t) during which the displacement happens is known as average velocity. Depending on the direction of the displacement, the average velocity could be either positive or negative. Meters per second (m/s or ms-1) is the SI unit of measure for average velocity.
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Please help! Will give a lot of points
Answers
Chemical and Biological weathering.
Explanation:
Processes that break down and weaken earth minerals are known as weathering. Over time, this can lead to erosion, in which huge sections of rock and stone are carried away, changing landscapes. Physical weathering alters the material structure of rocks, while chemical weathering alters their chemical structure.
Vector A points in the negative y direction and has a magnitude of 5 units. Vector B has twice the magnitude and points in the positive x direction tion. Find the direction and magnitude of (a) A + B (b) A - B and (c) B - A
Answers
Draw a diagram of the vectors A and B:
Using the unit vector notation:
\(\begin{gathered} A=-5\hat{j} \\ B=10\hat{i} \end{gathered}\)Remember that when a vector is written in terms of its components:
\(V=V_x\hat{i}+V_y\hat{j}\)Then, its magnitude is given by:
\(|V|=\sqrt[]{V^2_x+V^2_y}\)And its direction is given by the following rule depending on the sign of the horizontal component:
\(\begin{gathered} \theta=\tan ^{-1}(\frac{V_y}{V_x})\text{ if }V_x>0 \\ \theta=180+\tan ^{-1}(\frac{V_y}{V_x})\text{ if }V_x<0 \end{gathered}\)a) A+B
\(\begin{gathered} A+B=(-5\hat{j)}+(10\hat{i}) \\ =10\hat{i}-5\hat{j} \end{gathered}\)Since the horizontal component is positive, then:
\(\begin{gathered} |A+B|=\sqrt[]{(10)^2+(-5)^2} \\ =\sqrt[]{125} \\ =5\cdot\sqrt[]{5} \\ \approx11.18 \end{gathered}\)\(\begin{gathered} \theta_{A+B}=\tan ^{-1}(\frac{-5}{10}) \\ =-26.565\ldotsº \\ =333.43º \end{gathered}\)b) A-B
\(\begin{gathered} A-B=(-5\hat{j})-(10\hat{i}) \\ =-10\hat{i}-5\hat{j} \end{gathered}\)Since the x component is negative, then:
\(\begin{gathered} |A-B|=\sqrt[]{(-10)^2+(-5)^2} \\ =\sqrt[]{125} \\ =5\cdot\sqrt[]{5} \\ \approx11.18\ldots \end{gathered}\)\(\begin{gathered} \theta_{A-B}=180º+\tan ^{-1}(\frac{-5}{-10}) \\ =180º+26.565\ldotsº \\ =206.565\ldotsº \end{gathered}\)c) B-A
Notice that B-A is equal to -(A-B). Then, the magnitude is the same and the direction is the opposite (substract 180º from the direction of A-B to find the direction of B-A):
\(\begin{gathered} |B-A|=5\cdot\sqrt[]{5}\approx11.18 \\ \theta_{B-A}=26.565\ldotsº \end{gathered}\)