Answer:
hi
Explanation:
The structures with the most neurons in the human brain are the cerebral cortex, cerebellum, and brainstem.
What are neurons?Neurons are specialized cells in the nervous system that are responsible for transmitting information throughout the body. They are the basic building blocks of the nervous system and are important for all brain and bodily functions.
Neurons contain a cell body, dendrites, and an axon. The cell body consists of the nucleus and other organelles needed for the neuron to function properly. The dendrites are branch-like structures that receive information from other neurons, while the axon is a long projection that transfers information to other cells.
When a neuron receives a signal from another neuron, it generates an electrical impulse that travels down the axon. This electrical impulse triggers the release of chemicals called neurotransmitters, which cross the synapse and bind to receptors on the dendrites of other neurons.
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what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees
Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:
You have the initial velocity (v): 35 m/s
You have the launch angle (θ): 45 degrees
We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.
To calculate vx (horizontal component):
vx = v * cosθ
vx = 35 * cos(45) = 24.7 m/s
To calculate vy (vertical component):
vy = v * sinθ
vy = 35 * sin(45) = 24.7 m/s
We can calculate the horizontal distance (d) traveled using:
d = vx * t (where t is time)
Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:
t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)
t = 24.7 / 9.8 = 2.52 seconds
Now we can calculate the full horizontal distance traveled:
d = vx * t
d = 24.7 * 2.52
= 62.3 meters
So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.
Let me know if you have any other questions!
Answer:
To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.
The horizontal component of the motion remains constant throughout the trajectory and is given by:
Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)
In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.
The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:
Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)
Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.
The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.
Using these calculations, we can find the horizontal distance traveled by the object.
Let's calculate step by step:
Step 1: Calculate the time of flight
Vertical displacement = 0 (at the highest point)
0 = (35 * sin(45))^2 / (2 * 9.8)
0 = (24.75^2) / 19.6
0 = 616.0125 / 19.6
0 = 31.43
Step 2: Calculate the time of flight
Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2
0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2
0 = 24.75 * time - 4.9 * time^2
4.9 * time^2 - 24.75 * time = 0
time * (4.9 * time - 24.75) = 0
time = 0 (initial point) or 24.75 / 4.9
time = 5.05 seconds
Step 3: Calculate the horizontal distance
Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)
Horizontal distance = 35 * 5.05 * cos(45)
Horizontal distance = 35 * 5.05 * (sqrt(2)/2)
Horizontal distance = 88.96 meters
Therefore, when an object is thrown at 35 m/s at an angle of 45 degrees, the full distance traveled is approximately 88.96 meters.Convert 56,340,040 meters into scientific notation?
Answer:
5.634004 × 10^7
Explanation:
the number 7 is for the numbers before the number 5
A crate with a mass of 35.0 kg is pushed with a horizontal force of 150 N. The crate moves at a constant speed across a level, rough surface a distance of 5.85 m
(a) The work done by the 150 N force is 877.5 Joules.
(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.
To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.
(a) The applied force's work may be estimated using the following formula:
Work = Force * Distance * cos(theta)
where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.
As a result, the applied force's work is:
Work = 150 N * 5.85 m * cos(0) = 877.5 J
So, the work done by the 150 N force is 877.5 Joules.
(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.
The frictional work may be estimated using the following formula:
Work = Force of Friction * Distance * cos(theta)
The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.
Thus, the work done by friction is:
Work = 150 N * 5.85 m * cos(180) = -877.5 J
Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.
The coefficient of kinetic friction may be calculated using the following equation:
Friction Force = Kinetic Friction Coefficient * Normal Force
The normal force equals the crate's weight, which may be computed as:
Normal Force = mass * gravity
where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.
Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N
Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:
Force of Friction = coefficient of kinetic friction * Normal Force
150 N = coefficient of kinetic friction * 343 N
coefficient of kinetic friction = 150 N / 343 N ≈ 0.437
As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.
In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.
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What might Earth be like if it had never been hit by the theoretical protoplanet Orpheus?
Answer:
If Earth hadn't been hit by Orpheus, it would be covered by ocean, with perhaps a few mountaintops emerging through the water. There would be no humans, but there could be other forms of life. Earth would rotate rapidly, as the moon would not be present to produce the tidal friction that slows Earth's rotation today
What is the process where light bounces back from an object at the same angle and intensity as it. is received by the object?
Answer: It is Reflection
Explanation: Reflection occurs when incoming solar radiation bounces back from an object or surface that it strikes in the atmosphere, on land, or water, and is not transformed into heat.
Image shows question, please help
Jonathan needs to maintain a separation of 0.543 mm between the plates to get the desired charge, and a dielectric constant of 92.6 to achieve a separation of 5 mm with a dielectric.
(a) Using the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage, we can solve for the capacitance: C = Q/V =\((8.15 x 10^-9 C) / (50 V) = 1.63 x 10^-10 F.\)
Then, using the formula for capacitance of parallel plate capacitors: C = ε0A/d, where ε0 is the permittivity of free space, A is the area of the plates, and d is the separation distance, we can solve for the separation distance: d =\(_{3}OA/C = (8.85 x 10^-12 F/m) x (0.01 m^2) / (1.63 x 10^-10 F) = 0.543 mm.\)
(b) To find the dielectric constant, we can use the formula for capacitance of a parallel plate capacitor with a dielectric: C = εrε0A/d, where εr is the relative permittivity or dielectric constant of the material. Solving for εr, we get: εr = Cd / ε0A = \((1.63 x 10^-10 F)\) x (0.005 m) / \((8.85 x 10^-12 F/m)\) x \((0.01 m^2)\) = 92.6.
Therefore, Jonathan should use a dielectric with a relative permittivity of 92.6 to achieve a separation of 5 mm.
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A crass host pours the remnants of several bottles of wine into a jug after a party. He then inserts a cork with a 1.80 cm diameter into the bottle, placing it in direct contact with the wine. He is amazed when he pounds the cork into place and the bottom of the jug (with a 18.0 cm diameter) breaks away. Calculate the extra force (in N) exerted against the bottom if he pounded the cork with a 120 N force.
We would consider the hydraulic lift where the pressure is the same on the
master ad slave cylinder but force changes with the change in cross section area. We would apply the Pascal's princile which is expressed as
F1/A1 = 2/A2
where
F1 is the force applied to the master cylinder and A1 is thecross sectional area of the master cylinder
F2 is the force created at each of the slave cylinder and A2 is the cross sectional area of slave cylinder.
In this scenario, the cork works as master cylinder and the jug as slave cylinder. From the information given,
F1 = 120
Cross sectional area of cork is
A1 = πr1^2
where r1 is the radius of the cork
Given that diameter of cork = 1.8,
radius = diameter/2 = 1.8/2
r1 = 0.9
A1 = π * 0.9^2 = 0.81π
Cross sectional area of bottle, A2 = πr2^2
where r2 is the radius of the bottom of the jug.
Given that diameter of the bottom of the jug = 18,
r2 = 18/2 = 9
A2 = π * 9^2 = 81π
From the first equation.
F2 = A2F1/A1
By substituting the given values, we have
F2 = 81π * 120/ 0.81π
F2 = 12000 N
Extra force = F2 - F1 = 12000 - 120
Extra force = 11880 N
The extra force against the bottom is 11880 N
What is Sound? How can you produce a loud sound?
Answer:
Sound is a type of energy made by a vibrating object.
Explanation:
You can create sounds by:
- A string plucked with force has greater amplitude
- A vibrating guitar string makes the sound, if you pluck the string harder, it will make a louder sound.
Besides being asleep and being awake list the different states of consciousness
Answer:
bias.
Consciousness.
Hypnosis.
Priming.
Sleep.
Trance.
Explanation:
what is the momentum of a bowling ball whose mass is 4 0 kg rolling at a rate of 2 5 ms
The overall momentum of the ball is 100kgm/s.
The impact on the induced velocity in the propeller plane is most pronounced close to the blade tips. The original blade element momentum theory does not account for the effect of vortices emitted from the blade tips into the slip stream on the induced velocity field. The induced velocity dispersion along the propeller is greatly influenced by these tip vortices, which produce a number of helical structures in the wake. It uses a tip-loss or correction factor, F, to make up for this shortcoming.
\(P= Mv\\\\P=25 * 4\\\\P=100Kgm/s\)
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I need help, please!
Answer:
can u send pictures again it's unclear.
David is driving a steady 25.0m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 2.60m/s2at the instant when David passes.
How far does Tina drive before passing David?
What is her speed as she passes him?
Tina's speed as she passes David is 25.0 m/s, which is the same as David's speed. To solve this problem, we can use the kinematic equations of motion:
Position as a kinematic equations of time: x = x0 + v0t + (1/2)at^2
Final velocity as a function of time: v = v0 + at
First, let's find out how long it takes for Tina to catch up to David. We can use the second equation above to find the time it takes for Tina to reach David's speed:
v = v0 + at
25.0 m/s = 0 + 2.60 m/s^2 * t
t = 9.62 s
Now we can use the first equation to find how far Tina travels during that time:
x = x0 + v0t + (1/2)at^2
x = 0 + 0 + (1/2)(2.60 m/s^2)(9.62 s)^2
x = 120.3 m
Therefore, Tina drives 120.3 meters before passing David. To find her speed as she passes David, we can use the second equation above:
v = v0 + at
v = 0 + 2.60 m/s^2 * 9.62 s
v = 25.0 m/s is the final velocity.
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A 1 kg rock is sitting at the edge of a cliff 100 meters high. What is the rock's gravitational potential energy?
Answer:
000.83
Explanation:
i dont know how to explain it bt i did something on paper for it
At the end of the _____ era matter and antimatter annihilate each other. Because of a small imbalance in the ratio, the universe is left with only ______.
At the end of the Electroweak era, matter and antimatter annihilate each other. Because of a small imbalance in the ratio, the universe is left with only matter.
What is baryogenesis process?The baryogenesis process refers to the hypothetical mechanism or mechanisms that generated the observed baryon asymmetry in the universe which refers to the fact that there is much more matter than antimatter
If the universe were perfectly symmetric between matter and antimatter the particles and antiparticles would have annihilated each other completely leaving behind only radiation.
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While watching a movie a spaceship explodes and there is a loud bang and flash of light. What is wrong with this scene? Explain how you know using evidence and scientific reasoning from the lesson.
Hold a spoon such that the water will hit the back of the spoon. The handle of the spoon will be horizontal. Turn on the water, but not full strength though.
This is an experiment that explains the Bernoulli principle. According to this principle, at the bottom of the spoon, there will be a reduction in pressure.
Explanation of the Bernoulli principleSo the pressure at the bottom of the spoon reduces because the velocity of the water is larger and the height of the column of water is smaller at this part.
So the spoon is attracted to the water at the point of lowest pressure because objects gravitate to low-pressure points.
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During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive force of 125 N to the tire's rim. The mass of the wheel is 1.50 kg and, for the purpose of this problem, assume that all of this mass is concentrated on the outside radius of the wheel. The diameter of the wheel is 60.0 cm. A chain passes over a sprocket that has a diameter of 8.50 cm. In order for the wheel to have an angular acceleration of 4.50 rad/s2, what force, in Newtons, must be applied to the chain
Answer:
896.647 N
Explanation:
Given data:
Tangential resistive force ( Fr )= 125 N
mass of the wheel ( M ) = 1.50 kg
diameter of wheel ( D1 )= 60 cm
R1 = 30 cm = 0.3 m
diameter of chain ( D2 ) = 8.5 cm
R2 = 0.0425 m
Angular acceleration ( ∝ ) = 4.50 rad/s^2
Determine the Force to be applied to Chain
First ; calculate for the moment of Inertia of the wheel
I = M*R1 ^2 = 1.50 * (0.3)^2 = 0.135 kg*m^2
Next determine the net force on the wheel due to torque
τ = F*R2 - Fr *R1 = F (0.0425) - 125 * 0.3 ---- ( 1)
note that Torque ( τ ) = I * ∝ ----- ( 2 )
Equate; equation ( 1 ) and equation ( 2 )
F( 0.0425 ) - 37.5 = 0.135 * 4.5
∴ F = 38.1075 / 0.0425 = 896.647 N ( force to be applied to chain )
A pendulum built from a steel sphere with radius r cm 5 and density stl kg m S 3 7800 is attached to an aluminum bar with length l m 1 thickness t cm 0 8. and width w cm 4 and density . al kg m S 3 2820 a. Calculate the mass moment of inertia of the pendulum about its center of mass, . cm I b. Calculate the mass moment of inertia of the pendulum about its pivot point, o
Answer:
1) I_ pendulum = 2.3159 kg m² , 2) I_pendulum = 24.683 kg m²
Explanation:
In this exercise we are asked to calculate the moment of inertia of a physical pendulum, let's start by calculating the center of mass of each elements of the pendulum and then the center of mass of the pendulum
Sphere
They indicate the density of the sphere roh = 37800 kg / m³ and its radius
r = 5 cm = 0.05 m
we use the definition of density
ρ = M / V
M = ρ V
the volume of a sphere is
V = 4/3 π r³
we substitute
M = ρ 4/3 π r³
we calculate
M = 37800 4/3 π 0.05³
M = 19,792 kg
Bar
the density is ρ = 32800 kg / m³ and its dimensions are 1 m,
0.8 cm = 0.0008 m and 4cm = 0.04 m
The volume of the bar is
V = l w h
m = ρ l w h
we calculate
m = 32800 (1 0.008 0.04)
m = 10.496 kg
Now we can calculate the center of mass of the pendulum, we use that the center of mass of the sphere is its geometric center, that is, its center and the center of mass of the bar is where the diagonals intersect, in this case it is a very bar. long and narrow, whereby the center of mass is about half the length. It's mass scepter of the pendulum is
r_cm = 1 / M (M r_sphere + m r_bar)
M = 19,792 + 10,496 = 30,288 kg
r_cm = 1 / 30,288 (10,496 0.5 + 19.792 (1 + 0.05))
r_cm = 1 / 30,288 (5,248 + 20,7816)
r_cm = 0.859 m
This is the center of mass of the pendulum.
1) Now we can calculate the moment of inertia with respect to this center of mass, for this we can use the theorem of parallel axes and that the moments of inertia of the bodies are:
Sphere I = 2/5 M r2
Bar I = 1/12 m L2
parallel axes theorem
I = I_cm + m D²
where m is the mass of the body and D is the distance from the body to the axis of rotation
Sphere
m = 19,792 ka
the distance D is
D = 1.05 -0.85
D = 0.2 m
we calculate
I_sphere = 2/5 19.792 0.05 2 + 19.792 0.2 2 = 0.019792 +0.79168
I_sphere = 0.811472 kg m²
Bar
m = 10.496 kg
distance D
D = 0.85 - 0.5
D = 0.35 m
I_bar = 1/12 10.496 0.5 2 + 10.496 0.35 2 = 0.2186 + 1.28576
I_bar = 1.5044 kg m²
The moment of inertia is a scalar quantity whereby the moment of inertia of the body is the sum of the moment of the parts
I_pendulum = I_sphere + I_bar
I_pendulum = 0.811472 +1.5044
I_ pendulum = 2.3159 kg m²
this is the moment of inertia of the pendulum with respect to its center of mass located at r = 0.85 m
2) The moment is requested with respect to the pivot point at r = 0 m
Sphere
D = 1.05 m
I_sphere = 2/5 M r2 + M D2
I_sphere = 2/5 19.792 0.05 2 + 19.792 1.05 2 = 0.019792 +21.82
I_sphere = 21.84 kg m²
Bar
D = 0.5 m
I_bar = 1/12 10.496 0.5 2 + 10.496 0.5 2 = 0.21866 + 2.624
I_bar = 2,84266 kg m 2
The pendulum moment of inertia is
I_pendulum = 21.84 +2.843
I_pendulum = 24.683 kg m²
This moment of inertia is about the turning point at r = 0 m
Help with both questions I’ll mark brainliest
Which best describes what happens when light traveling through air enters water at an angle?
It moves along straight lines in air and changes direction when it enters water.
O It moves in a curve in air and moves in straight lines when it enters water.
O It moves along straight lines in air and continues along the same lines when it enters water.
O It moves in a curve in air and continues moving in the same curve when it enters water.
Mark this and return
Save and Exit
Next
Submit
Answer:
When light traveling through air enters water at an angle, it moves in a curve in air and changes direction when it enters water. This bending of light is known as refraction. The angle at which the light bends depends on the difference in the refractive indices of the two media, which is why the light bends when it enters the denser medium of water.
4.2 Determine the reactions of the loads L and R. ↓ 5m
↓ 7 kN 6m 3 kN 4m R (8)
The reaction of load L is 0 (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).
How to find reaction?To determine the reactions of the loads L and R, consider the equilibrium of the forces acting on the structure.
First, analyze the vertical equilibrium. The sum of the vertical forces must be zero:
ΣFy = R − 7 kN − 3 kN
ΣFy = 0
This gives:
R = 10kN
Next, analyze the horizontal equilibrium. The sum of the horizontal forces must be zero:
ΣFx = L
ΣFx = 0
This indicates that there is no horizontal force acting on the structure.
Therefore, the reaction of load L is zero (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).
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How much thermal energy is required for liquid water to turn in to a gas on
Mars?
O 100°C
O 10°C
0 212°C
O 50°C
Answer:
thanks you too for boys sweater in parallel and remember word on mangal I can do a few
Explanation:
free download in every way you are you sure about my experience with the same you for the following information to facilitate this answer and I can do the same to your email program I was not understand you want with you on Monday to Thursday morning I was speaking and listening at a later flight andIf you have a 14 ounce glass of water at 71 F how much ice do you need to add to cool it down to 32 F? Give your answer in kg
Answer:
0.10072 kg
Explanation:
To solve this problem, we need to use the heat equation:
Q = mcΔT
where Q is the heat transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
First, let's calculate the heat transferred when cooling the water from 71 F to 32 F. We will assume that the specific heat capacity of water is 4.184 J/(g°C) and the heat of fusion of ice is 333.55 J/g.
Q = (14 oz) x (28.35 g/oz) x (4.184 J/(g°C)) x (71-32) F
Q = 67,576.28 J
To calculate the mass of ice needed, we need to know the final temperature of the water after adding the ice. Assuming all the ice melts and the mixture reaches 32 F, we can use the following equation:
Q = mL + mcΔT
where L is the heat of fusion of ice and m is the mass of ice added.
Substituting the known values, we get:
67,576.28 J = m(333.55 J/g) + (14 oz) x (28.35 g/oz) x (4.184 J/(g°C)) x (71-32) F
Solving for m, we get:
m = 100.72 g or 0.10072 kg
Therefore, we need to add about 0.10072 kg of ice to cool the water from 71 F to 32 F.
Determine the Mutual Inductance per unit length between two long solenoids, one inside the other, whose radii are r1 and r2 (r2 < r1) and whose turns per unit length are n1 and n2.
Answer:
M' = μ₀n₁n₂πr₂²
Explanation:
Since r₂ < r₁ the mutual inductance M = N₂Ф₂₁/i₁ where N₂ = number of turns of solenoid 2 = n₂l where n₂ = number of turns per unit length of solenoid 2 and l = length of solenoid, Ф₂₁ = flux in solenoid 2 due to magnetic field in solenoid 1 = B₁A₂ where B₁ = magnetic field due to solenoid 1 = μ₀n₁i₁ where μ₀ = permeability of free space, n₁ = number of turns per unit length of solenoid 1 and i₁ = current in solenoid 1. A₂ = area of solenoid 2 = πr₂² where r₂ = radius of solenoid 2.
So, M = N₂Ф₂₁/i₁
substituting the values of the variables into the equation, we have
M = N₂Ф₂₁/i₁
M = N₂B₁A₂/i₁
M = n₂lμ₀n₁i₁πr₂²/i₁
M = lμ₀n₁n₂πr₂²
So, the mutual inductance per unit length is M' = M/l = μ₀n₁n₂πr₂²
M' = μ₀n₁n₂πr₂²
When a piece of wood is put in a graduated cylinder containing water the level of water rises from 17.7cm cubic to 18.5cm cubic calculate the total volume of the piece of wood given that it's relative density is 0.60
The total volume of the piece of wood is 1.33\(cm^3\).
To calculate the total volume of the piece of wood, we can use the principle of displacement.
1. First, we need to find the difference in volume between the two water levels. The initial volume is 17.7 \(cm^3\), and the final volume is 18.5 cm^3. The difference is 18.5 \(cm^3\) - 17.7 \(cm^3\) = 0.8 \(cm^3\).
2. Now, we need to find the volume of water displaced by the piece of wood. Since the relative density of the wood is 0.60, it means that the wood is 0.60 times denser than water.
3. The volume of water displaced by the wood is equal to the difference in volume divided by the relative density of the wood. So, the volume of water displaced is 0.8 cm^3 / 0.60 = 1.33 \(cm^3\).
4. Finally, the total volume of the piece of wood is equal to the volume of water displaced. Therefore, the total volume of the piece of wood is 1.33 \(cm^3\).
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1 point
Nuclear equations like the one below show "parent" and "daughter” nuclei.
What is the mathematical relationship between the superscripts on the
left-hand side and the superscripts on the right-hand side of the nuclear
equation?
27
27
0
12 Mg
13 AL +
je
Answer:
Mg- 27 means isotope with 12 protons and 15 neutrons.
Also 27 is mass number which express sum of protons and neutrons.
In nucleus one neutrn decays to electron and proton. Mass number remain same but Al-27 nucleus contain 13 protons and 14 neutrons. Electron is ejected out from nucleus.
A block is attached to a spring and executes
simple harmonic motion according to x = 2.0
cos(50t), where x is in meters and t is in
seconds. The spring constant is k = 100 N/m.
What is the mass of the block?
Answer:
.04 kg
Explanation:
The equation for simple harmonic motion is x = A*cos(ωt), where A is the amplitude, ω is the angular frequency, and t is the time.
Comparing the given equation x = 2.0cos(50t) with the equation for simple harmonic motion, we see that A = 2.0 meters and ω = 50 radians/second.
The angular frequency is related to the spring constant and mass by the equation ω = sqrt(k/m), where sqrt denotes the square root.
Substituting the values given, we get:
50 = sqrt(100/m)
Squaring both sides and solving for m, we get:
m = 100/2500 = 0.04 kg
A 68 kg
man's arm, including the hand, can be modeled as a 79-cm
-long uniform cylinder with a mass of 3.3 kg. In raising both his arms, from hanging down to straight up, by how much does he raise his center of gravity?
Answer:
Explanation:
We can calculate the change in the man's center of gravity by considering the initial and final positions of the center of gravity of his arms.
Assuming the man's arms are initially hanging down by his sides, the center of gravity of his arms is located at the midpoint of the cylinder, which is at a distance of L/2 = 79/2 = 39.5 cm from the shoulder joint.
When the man raises his arms straight up, the center of gravity of his arms is located at the top of the cylinder, which is at a distance of L = 79 cm from the shoulder joint.
The change in the man's center of gravity is therefore:
Δh = h_final - h_initial
= L - L/2
= 79 cm - 39.5 cm
= 39.5 cm
Therefore, the man raises his center of gravity by 39.5 cm when he raises both his arms from hanging down to straight up.
A rock falls to the ground with a force of 300N and air resistance pushes back up on the rock with a
force of 45N. Which is true of the rock?
Answer:
what are the choices
Explanation:
don't worry i'll edit it
A hummingbird gains a significant electric charge while flying and feeding. This has consequences: When a charged bird approaches a flower (Figure 1), the stamens of the flower bend toward the bird, even though the stamans are uncharged. Part A Explain how this happens Drag the terms on the left to the appropriate blanks on the right to complete the sentences. Reset Help toward The charge of the hummingbird ____ the stamen polarizes The charged opposite to the bird's charge particles of the stamen move ___ the bird, and like charged particles move ____the bird Therefore, the net electric force on the stamen is directed ____the hummingbird Submit Request Answer
When a hummingbird is flying and feeding, it gains a significant electric charge. When a charged bird approached a flower, the stamens of the flower (the part that produces pollen) bent toward the bird because it got polarized. This electrostatic charge is useful for a flower's reproduction process. Charged pollen can settle more effectively.
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