The gray whale travels an average of 120 km per day as it migrates

Answer:

Explanation:

atomic number

Answer:

same

Explanation:

They both have the same volume....so they both displace an equal amount of water and thus experience the same buoyancy force

Answer:

About 4-5in

Explanation:

The force required to hold the ping pong ball completely under the water is 36,189.98 dyne.

Diameter of ball = 4.18 cm

The radius of the ball = 2.09 cm

The volume of the ball can be calculated as   V=    \(\frac{4}{3}\)π r³                      

Therefore, the volume of the ball = 38.26 cm³

The net force required to completely submerge a ball under water = (Buoyant force) - (the weight of the ball)

If ρ₁ is used for the density of water. Then, the value of ρ₁ is 1 g cm⁻³.

Buoyant force = ρ₁gV

                      = 1 × 980 × 38.26

                      = 37494.80 dyne

Here, ρ₂ = density of ball = 0.0348 1 g cm⁻³.

                 Weight of ball = ρ₂gV

                                           = 0.0348 × 980 × 38.26

                                          = 1304.82 dyne

Therefore, the net force required to completely submerge a ball under water    = 37494.80 - 1304.82 = 36,189.98 dyne or 0.362 N

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A) The modulation index is undefined. B) The lower-side band (LSB) frequency is 99,500Hz. C) Percentage modulation = 20%

a) The modulation index (m) may be calculated through the usage of the formulation:

m = (Vmax - Vmin) / (Vmax + Vmin)

where Vmax and Vmin are the most and minimum amplitudes of the modulating signal, respectively.

In this case, the modulating sign is vi(t) = 90cos(2π500t) V. The most amplitude (Vmax) is 90 V, and the minimum amplitude (Vmin) is -90 V (for the reason that the cosine feature varies between -1 and 1).

Therefore, the modulation index is:

m = (Vmax - Vmin) / (Vmax + Vmin) = (90 - (-90)) / (90 + (-90)) = 180 / 0 = undefined

b) The carrier frequency is fc =100,000 Hz.

The higher-aspect band (USB) frequency is given via:

fUSB = fc + fm =100,000 Hz + 500 Hz = 100,500 Hz

The decrease-aspect band (LSB) frequency is given by way of:

fLSB = fc - fm = 100,000 Hz - 500 Hz = 99,500 Hz

c) If vi(t) = 120cos(2π500t) V, we will calculate the share modulation using the components:

Percentage modulation = (Vm - Vc) / Vc * 100%

in which Vm is the peak amplitude of the modulating sign and Vc is the peak amplitude of the service signal.

In this situation, Vm = 120 V and Vc = 100 V.

Percentage modulation = (Vm - Vc) / Vc * 100% = (120 - 100 ) / 100  * 100% = 20%

Increasing the modulation amplitude increases the percentage modulation. This outcome is in a larger version within the amplitude of the AM signal, which could result in extended sidebands and a more said modulation impact. The audio content of the modulating signal turns more distinguished, ensuing in a more potent modulation effect inside the AM signal.

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Answer:

The answer is D.

Use sarcasm and verbal cues to improve messages

Answer:

d

Explanation:

Answer:

dis mans newton says if a body is at rest or moving at a constant speed in a straight linne it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force

Answer:

Newtons first law of motion states that"A body will continue to its state of rest or motion unless external force acted upon it.

Answer:

Moved away from the nucleus

Answer:

rock

Explanation:

The capacitance of an air-filled parallel-plate capacitor is 4.0 pf. Wax is placed between the pieces as they are double separated. The dielectric constant of the wax is approximately 0.903.

The capacitance of an air-filled parallel-plate capacitor is given by:

C = ε0 × A / d

where C is the capacitance, ε0 is the permittivity of free space, A is the area of the plates, and d is the distance between the plates.

Given that the initial capacitance of the capacitor is 4.0 pF, we can rearrange the equation to solve for the initial plate separation:

d = ε0 × A / C1

where C1 is the initial capacitance. Substituting the given values, we have:

d = (8.85 x 10^-12 F/m) × A / 4.0 pF

= 2A × 10^-3 m

Next, we are told that the plate separation is doubled and wax is inserted between the plates, resulting in a new capacitance of 8.0 pF. We can use the same equation to find the new plate separation:

d' = ε0 × A / C2

where C2 is the new capacitance. Substituting the given values, we have:

d' = (8.85 × 10^-12 F/m) × A / 8.0 pF

= A × 10^-3 m

To find the dielectric constant of the wax, we can use the formula:

C2 = εr × ε0 × A / d'

where εr is the relative permittivity (dielectric constant) of the wax. Substituting the values we have calculated, we get:

8.0 pF = εr × (8.85 × 10^-12 F/m) × A / (A × 10^-3 m)

Simplifying, we get:

εr = 8.0 / 8.85 = 0.903

It's worth noting that this calculation assumes that the area of the plates remains constant when the wax is inserted. In practice, the insertion of the wax may affect the plate geometry, which could affect the capacitance. Additionally, the dielectric constant of the wax may depend on factors such as temperature and frequency.

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Let x be the amount of Kool-Aid in Lake Alpha t hours after the crash. We can use the law of conservation of mass to determine the incremental change in the amount of Kool-Aid in Lake Alpha over time.

At any given time t, the amount of Kool-Aid in Lake Alpha is x kilograms. The Kool-Aid in Lake Alpha is flowing into Lake Beta at a rate of 400 liters per hour, so the concentration of Kool-Aid in Lake Alpha is decreasing by 400x / (500,000 liters) = 0.0008x kilograms per hour. At the same time, Lake Beta is flowing into Lake Alpha at a rate of 400 liters per hour, so the concentration of Kool-Aid in Lake Alpha is increasing by 0.0008y kilograms per hour, where y is the amount of Kool-Aid in Lake Beta at time t. Therefore, the incremental change in the amount of Kool-Aid in Lake Alpha over a small time period Δt can be approximated by: Δx ≈ (-0.0008x + 0.0008y) Δt. Note that this is an approximation since the concentration of Kool-Aid in Lake Beta also changes over time, but it should be accurate enough for small time periods.

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Answer:

294 mAmps

Explanation:

The two resistors are equal to   22 * 75 / ( 22+ 75) = 17.01 ohm

V = IR

V/R = I

5 / 17.01 = .294 A

The resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

To calculate the effective stress in the aquifer, we need to subtract the fluid pressure from the total stress.

Given:

Pressure head in the aquifer = 100 ft (or 30.48 m)

The pressure head in the aquifer is directly proportional to the fluid pressure, which can be calculated using the formula:

Fluid pressure (P) = ρ * g * h

Where:

ρ = density of the fluid (water) = approximately 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = pressure head

Fluid pressure = 1000 kg/m³ * 9.8 m/s² * 30.48 m ≈ 298,440 N/m² (or Pa)

The total stress in the aquifer is the sum of the fluid pressure and the effective stress. Therefore, the effective stress can be calculated by subtracting the fluid pressure from the total stress.

Now, let's consider the changes in the hydraulic head due to pumping:

Change in hydraulic head = -12 ft (or -3.66 m)

The resulting changes in each parameter will be as follows:

1. Pressure head:

The pressure head will be reduced by 12 ft, so the new pressure head will be 100 ft - 12 ft = 88 ft (or 26.82 m).

2. Fluid pressure:

The fluid pressure does not change, as it depends on the density of the fluid and the acceleration due to gravity, which remain constant.

3. Effective stress:

The effective stress can be calculated as the total stress minus the fluid pressure. Since the fluid pressure remains constant, the effective stress will also remain constant unless there are other factors affecting it.

4. Total stress:

The total stress is the sum of the fluid pressure and the effective stress. As mentioned earlier, the fluid pressure remains constant, so the total stress will decrease by the same amount as the effective stress, assuming no other factors affect the total stress.

Therefore, the resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

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When the elevator is going up, though, you are accelerating, which adds more force to the scale and increases your apparent weight. When the elevator is going down, the same is true, but the acceleration is negative, subtracting force from the scale and decreasing your apparent weight.

The proportional equation that matches the context of a 33-inch candle burning down in 12 hours is b = 2.75t.

A candle that is 33 inches long is called a 33-inch candle. Candles are a popular decorative item that is commonly used for lighting, as decoration for weddings, and parties, or to create an aromatic atmosphere. B represents the length of the candle that has burned away at any time given in hours, t.

To find the proportional equation for b in terms of t that matches the context of a 33-inch candle burning down in 12 hours, the following steps should be followed:

Identify the given informationThe length of the candle (l) = 33 inchesThe time taken for the candle to burn down (t) = 12 hours

Determine the rate of burning The rate of burning of the candle is given by l/t. Therefore, the rate of burning = 33/12 = 2.75 inches per hour.

The proportional equation for b in terms of t is given by b = rt where r is the rate of burning. Therefore, b = 2.75t.

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In basin and range topography, the lowest areas are frequently occupied by a(n)  basin.

Basin and range topography is a geological feature characterized by alternating mountain ranges and elongated valleys or basins. The formation of this topography is attributed to the stretching and faulting of the Earth's crust, which leads to the uplift of mountains and the subsidence of adjacent basins.

The lowest areas in this type of topography are often occupied by basins, which are elongated depressions or low-lying regions. These basins typically collect sediment and water, forming flat or gently sloping landscapes. They can range in size from small valleys to extensive lowland areas.

The basins are important features of the basin and range topography and contribute to the unique landscape and hydrological characteristics of the region.

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Answer:

They transfered more energy in the morning.

Explanation:

This is because, let me put this in simple words, you have more energy, you can run more laps around the track, right? This is the same with  the waves. They have more energy, so they can crash aganst the shore more!

Answer:

You would weigh much less on the moon then what you weigh on earth.

Explanation:

This happens because earth has a stronger gravitational pull than the moon. that's why when people are on the moon they can jump much higher and float around because there is less gravity so you would be lighter on the moon then you are on earth.

The most common injury related to electrical hazards are Electrical burns.

What are electrical hazards?

An electrical burn is a type of skin burn that develops when your body comes into contact with electricity. It is possible for electricity to pass through your body when it comes into contact with it. When this occurs, the voltage has the potential to harm tissues and organs.

Hence, The most common injury related to electrical hazards are Electrical burns.

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The delay vector for node F as follows:

F: [5, 2, ∞, ∞, ∞, 0, ∞, ∞]

This means that the estimated delay from node F to node A is 5, to node B is 2 and to node F itself is 0. And all other nodes are unreachable.

The Distance Vector Routing algorithm, also known as Bellman-Ford algorithm, is used to calculate the shortest path from a given source node to all other nodes in a network.

To calculate the new estimated delays from node F, we first initialize the delay vector for node F as follows:

F: [0, ∞, ∞, ∞, ∞, ∞, ∞, ∞]

Next, we update the delay vector for node F using the delay vectors received from its neighbors. For example, using the information provided in here, we can update the delay vector for node F as follows:

F: [5, 2, ∞, ∞, ∞, 0, ∞, ∞]

This means that the estimated delay from node F to node A is 5, to node B is 2 and to node F itself is 0. And all other nodes are unreachable.

We then repeat this process of updating the delay vector until the estimates converge and no further updates are required.

This is a simplified process and in real world scenario there will be more number of nodes and edges, and also the cost of each edge will be different.

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Answer:

No not at all. A car speeding up is an example of acceleration.

Answer:

No.

Explanation:

Its a example of decceleration because its slowing down not speeding up. If the car were to go faster then it would be an example of acceleration. Hope this helps :)

The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A

The work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).

The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:

T = Y * (ΔL / L)

where Y is the Young's modulus of the material of the wire.

Now, let's calculate the work done to stretch the wire:

dW = T * dL

Integrating this expression from L to L + ΔL:

W = ∫ T * dL = ∫ Y * (ΔL / L) * dL

W = Y * ΔL * ∫ (dL / L)

W = Y * ΔL * ln(L) + C

Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.

Finally, the expression for the energy stored in the wire (E) is:

E = W = Y * ΔL * ln(L)

or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:

E = Y * e * ln(L) * A

Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:

E = Y * e * ln(L) * A

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The maximum load that can be supported by the cylinder-shaped steel beam can be calculated using the ultimate strength of steel and circumference of beam. The maximum load is 4.88 x 10^9 pounds.

The formula for stress is stress = force / area, where force is the load applied and area is the cross-sectional area of the beam. The cross-sectional area of a cylinder is given by the formula A = πr^2, where r is the radius of the cylinder.

To calculate the radius, we can use the circumference formula C = 2πr and solve for r: r = C / (2π).

Substituting the given circumference of 3.5 inches, we have r = 3.5 / (2π) ≈ 0.557 inches.

Next, we calculate the cross-sectional area: A = π(0.557)^2 ≈ 0.976 square inches.

Now, to find the maximum load, we can rearrange the stress formula as force = stress x area. Given the ultimate strength of steel as 5 x 10^9 Pa, we can substitute the values to find the maximum load:

force = (5 x 10^9 Pa) x (0.976 square inches) ≈ 4.88 x 10^9 pounds.

Therefore, the maximum load that can be supported by the beam is approximately 4.88 x 10^9 pounds.

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Fracking has become widely used in the US, raising worries about its effects on the environment and public health. Large volumes of wastewater are produced, along with greenhouse gases like methane, hazardous air pollution, and noise.

Fracking, also known as hydraulic fracturing, is a technique for obtaining gas and oil through shale rock. With the help of a high-pressure injection of water, sand, and chemicals into bedrock, gas and oil can flow into a well and be collected for sale.

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Explain any environmental issue that arose from fluid technology.

Answer : Gretchen's rate of speed is 72.5 kilometers per hour.

What is the distance?

-- Distance is defined as the product of speed and time.

-- Since there are 3600 seconds in an hour, we can divide the time it takes -- Gretchen to travel 5500 meters by 3600 to find the number of hours it takes her:

⇒ 275 seconds / 3600 seconds/hour = 0.0763888889 hours.

Next, we need to convert the distance she travels to kilometers.

-- Since there are 1000 meters in a kilometer, we can divide the distance Gretchen travels by 1000 to find the number of kilometers she travels:

⇒ 5500 meters / 1000 meters/kilometer = 5.5 kilometers.

Now that we have the distance Gretchen travels and the time it takes her to travel that distance in the appropriate units, we can divide the distance by the time to find her rate of speed in kilometers per hour:

⇒ 5.5 kilometers / 0.0763888889 hours = 72.5 kilometers/hour.

Thus, Gretchen's rate of speed is 72.5 kilometers per hour.

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Double-slit time diffraction at optical frequencies is a phenomenon where light is passed through two narrow slits that are placed close together.

As the light waves pass through the slits, they interfere with each other and create an interference pattern on a screen placed behind the slits. This pattern is created due to the diffraction of light waves, which causes them to bend around the edges of the slits and interfere with each other.

This phenomenon is particularly important in optics, as it allows us to study the behavior of light waves and their interaction with matter.

 Double-slit diffraction at optical frequencies refers to the interference pattern produced when light waves of optical frequencies pass through two closely spaced slits. The pattern results from the superposition of light waves, creating areas of constructive and destructive interference, which correspond to bright and dark bands respectively. This phenomenon demonstrates the wave nature of light and is a fundamental concept in the study of optics and wave physics.

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Answer:

A person must be "voluntary".

Explanation:

The research project has so far been implementing this very same factual information on either the basis of results for such an induced conformational.

The measures in the context of this problem are given as follows:

1. Mass of the continent: 2.39 x 10^21 kg.

2. Kinetic energy of the continent: 3829 J..

3. Speed of the jogger: 7.62 m/s.

The density of an object is given by the equation presented as follows:

d = m/V.

In which the variables are:

The continent is represented by a rectangular prism with square base, with sides of 4950 km and depth of 34 km, hence it's volume is calculated as follows:

V = 4950 x 4950 x 34 = 833,085,000 km³ = 8.33 x 10^8 km³ = 8.33 x 10^17 m³

The density is of 2870 kg/m³, hence the mass is calculated as follows:

m = d x V

m = 2870 x 8.33 x 10^17

m = 2.87 x 10³ x 8.33 x 10^17

m = 2.39 x 10^21 kg.

The kinetic energy of an object is obtained according to the following equation:

K = 0.5mv².

In which the variables are as follows:

For the continent, the values of these parameters are given as follows;

m = 2.39 x 10^21 kg, v = 4 cm/year = 0.04 m/year.

The number of seconds in a year is:

365 x 24 x 60 x 60 = 31,536,000

Hence the velocity is:

v = 0.04 m/ 31,536,000 s = 1.79 x 10^(-9) m/s.

Hence the kinetic energy is:

K = 0.5 x 2.39 x 10^21 x (1.79 x 10^(-9))² = 1.195 x 3.2041 x 10^21 x 10^-18 = 3.829 x 10³ J = 3829 J.

For the jogger, the parameters are given as follows:

K = 3829, m = 66.

Hence his velocity is calculated as follows:

3829 = 0.5 x 66 x v²

v² = 3829/66

v = sqrt(3829/66)

v = 7.62 m/s.

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