A weight suspended from a spring bobs up and down over a distance of 1 meter in two seconds. Its frequency is

Answer: The relationship between current, voltage and resistance is expressed by Ohm's Law. This states that the current flowing in a circuit is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit, provided the temperature remains constant.

Explanation:

Answer:

Sling Psychrometer

Explanation:

A sling psychrometer measures relative humidity through the process of evaporation. It contains two thermometers. The cloth around one of the thermometers is wetted and slung around in the air so the moisture evaporates, which has a cooling effect. The relative humidity is then calculated using the difference in temperature for the two thermometers.

Answer:

330 Hz

Explanation:

edg2020

The best estimate of the frequency Suzy hears after the car passes her is govern by doppler effect and it is 330 Hz.

Frequency is the number of occurrences of a repeating event per unit of time.

The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source.

According to the Doppler Effect, the frequency observed by an observer decreases for source going away.

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Answer:

d=s×t 2.5*10^4×580N=14500000

Explanation:

they are called derived quantities. which includes:

pressure, stress, work, acceleration, velocity,density,force

A centrifuge is a device in which a small container of material is rotated at a high speed on a circular path: The sample is making approximately 278 revolutions per minute.

To determine the number of revolutions per minute the sample is making, we need to relate the centripetal acceleration, radius, and angular velocity.

Centripetal acceleration (a_c) is related to the radius (r) and angular velocity (ω) by the formula: a_c = rω².

Given that the centripetal acceleration of the sample is 7.98 x 10³ times the acceleration due to gravity (g), we can write: a_c = 7.98 x 10³g.

We know that the acceleration due to gravity is approximately 9.8 m/s².

Substituting the values, we have: 7.98 x 10³g = rω².

Rearranging the equation to solve for ω, we get: ω = sqrt((7.98 x 10³g) / r).

The radius is given as 6.07 cm, which is 0.0607 m.

Substituting the values, we find: ω = sqrt((7.98 x 10³ * 9.8) / 0.0607).

Calculating this expression, we find ω ≈ 511.26 rad/s.

To convert this angular velocity to revolutions per minute, we can use the conversion factor: 1 revolution = 2π radians.

Thus, the number of revolutions per minute is approximately ω / (2π) * 60, which is approximately 278 revolutions per minute.

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a) $$E_1 = \frac{(9.0 \times 10⁹ N m²/C²)(2.6 \times 10⁻⁶C)}{(3.0 m)²} \approx 7.80 \times 10⁵ N/C$$, direction is to the right ; b) $$E_2 = \frac{(9.0 \times 10⁹ N m²/C²)(1.4 \times 10⁻⁶ C)}{(4.0 m)²} \approx 3.94 \times 10⁵ N/C$$, electric field is directed towards point charge so, direction is to the left  c) $$|\vec{E}| = \√{E_1² + E_2²} \approx 8.86 \times 10⁵ N/C$$ and its direction is up.

Charge that exists in a body that has fewer electrons than protons is known as positive electrons.

a. To find the electric field at the origin due to charge Q1, we can use the formula for the electric field due to point charge:

$$E_1 = \frac{k Q_1}{r_1²}$$

k is Coulomb constant (k = 9.0 × 10⁹ N m²/C²), Q1 is the charge, and r1 is the distance from the charge to the point where we want to find the electric field.

Q1 = 2.6 μC and r1 = 3.0 m (since x1 = -3.0 m is the distance from Q1 to the origin).

$$E_1 = \frac{(9.0 \times 10⁹ N m^2/C²)(2.6 \times 10⁻⁶C)}{(3.0 m)²} \approx 7.80 \times 10⁵ N/C$$

The electric field is directed away from point charge, so direction of the electric field at the origin due to Q1 is to the right (positive x direction).

b. Similarly, to find the electric field at the origin due to charge Q2, we use the same formula:

$$E_2 = \frac{k Q_2}{r_2²}$$

where Q2 = 1.4 μC and r2 = 4.0 m (since x2 = 4.0 m is the distance from Q2 to the origin).

$$E_2 = \frac{(9.0 \times 10⁹ N m²/C²)(1.4 \times 10⁻⁶ C)}{(4.0 m)²} \approx 3.94 \times 10⁵ N/C$$

The electric field is directed towards point charge, so direction of the electric field at the origin due to Q2 is to the left.

c. $$\vec{E} = \vec{E_1} + \vec{E_2}$$

$\vec{E_1}$ is the electric field due to Q1 and $\vec{E_2}$ is the electric field due to Q2.

net electric field at the origin is: $$|\vec{E}| = \√{E_1² + E_2²} \approx 8.86 \times 10⁵ N/C$$ and its direction is up.

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Answer:

\(approx.= 25\frac{m}{s}\)

Explanation:

Centripetal acceleration (a) is defined as the square of an object's velocity (V^2) divided by the distance of the object from it's point/axis of revolution (r). So:

\(a=\frac{V^{2} }{r}\)

which allows us to solve for the velocity:

\(V=\sqrt{ar}\\ Since: a=3.04g=(3.04)(9.81),r=21;\\V=\sqrt{(3.04)(9.81)(21)} =25.02...\)

Answer:

25 m/s

Explanation:

A = v^2r

The square root of Ar = v

V = square root of 3.04 x 21 x 9.8 = 25m/s

Make sure to add 9.8 as acceleration is 3.04g or 3.04 x 9.8

Answer:

A. like poles repel or push apart

At t = 6 s, the point that was initially at the bottom of the wheel will be at an angle of approximately **9.4 radians** relative to the positive x-axis.

To determine the angular position of the point at a given time, we need to consider the angular acceleration, initial angular velocity, and time.

Given that the wheel starts from rest, the initial angular velocity is 0 rad/s. The angular acceleration is constant at 5 rad/s².

We can use the following equation to find the angular position (θ) at a given time (t):

θ = θ₀ + ω₀t + (1/2)αt²,

where θ₀ is the initial angular position, ω₀ is the initial angular velocity, α is the angular acceleration, and t is the time.

In this case, since the point was initially at the bottom of the wheel, the initial angular position is π radians (180 degrees).

By substituting the given values into the equation, we can calculate the angular position at t = 6 s.

θ = π + 0 + (1/2)(5 rad/s²)(6 s)²

θ ≈ 9.4 radians.

Therefore, at t = 6 s, the point that was initially at the bottom of the wheel will be at an angle of approximately 9.4 radians relative to the positive x-axis.

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Answer:

Josie's ball faster than T

The goose will take 8.55 hours to travel 550 km at their average speed of 64.3km/h.

The goose average speed is around 40 mph or 64.3 km/h, but in good weather and wind conditions this speed can go up to 70 mph or 112 km/h

Considering the formula:

x = v.t

were x=space, v=speed and t= time. Clearing the equation, to find the hours of flight:

t = x/v = 550km / 64.3km/h = 8.55 hours

Average speed is a useful concept in many fields, including physics, engineering, and transportation. It can be used to calculate travel times, estimate fuel consumption, and analyze the performance of machines and vehicles. However, it is important to note that average speed does not take into account changes in direction or acceleration, which can affect the overall performance of an object.

Average speed is a measure of how quickly an object moves over a certain distance. It is defined as the total distance traveled divided by the time it takes to travel that distance. The units of average speed are usually expressed as distance per unit time, such as kilometers per hour, miles per hour, or meters per second.

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Answer:

Atomic Mass

Explanation:

The distance from the center of fringe e to the left slit is the same as the distance to the right slit.

d = (m * λ * D) / (y * D +/- x)

\(x_{left} - x_{right}\)= (m * λ * D) / y - (m * λ * D) / y = 0

The term "fringe" can have several different meanings depending on the context. However, one of the most common uses of this term refers to the interference pattern that occurs when waves, such as light or sound, interact with each other. For example, when light passes through a narrow slit or a diffraction grating, it spreads out and produces a pattern of bright and dark fringes on a screen behind it. This pattern is caused by the constructive and destructive interference of the waves passing through the slit or grating.

Fringe can also refer to the edge or border of an object, as in the case of the fringes of a hologram or the fringes of a diffraction pattern. In some cases, the term "fringe" is also used to describe phenomena that are on the boundary or at the limits of our understanding, such as fringe science or fringe theories.

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Those who favor the free trade policies would most likely believe that restrictions harm consumers.

A trade policy known as "free trade" does not impose import or export quotas. It also can be thought of as the market economy concept used in global trade. Political parties with economic liberal stances generally support free trade while protectingionism, which is the antithesis of free trade, is typically backed by parties with economic nationalism and left-wing stances.

The International Commerce Organization's international trade deals currently include the majority of countries as members.

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Answer:

The moth can be detected by the bat when it is about 21 meters away.

Explanation:

This is because the sound waves travel at about 340 meters per second, so it takes about 70 milliseconds for the sound waves to travel from the bat to the moth and back again.

The current flowing in each circuit arrangement depends on the total resistance of the circuit.

To calculate the total resistance of each circuit, we can use the formula:

Total Resistance = R1 + R2 + R3

a. To create a current of 1 ampere, we can use the following circuit:

  (check image 1)

b.  To create a current of 2 amperes, we can use the following circuit:

(check image 2)

The total resistance of this circuit is:

1 ohm + 2 ohm + 1 ohm = 4 ohms

Using Ohm's Law, we can calculate the voltage required to create a current of 2 amperes:

V = IR

V = 2A x 4 ohm = 8V

Therefore, we need to connect three batteries in series to create a voltage of 4.5V, and another three batteries in series to create a voltage of 4.5V, and connect both sets of batteries in parallel to create a voltage of 9V.

c. To create a current of 3 amperes, we can use the following circuit:

(check image 3)

The total resistance of this circuit is:

1 ohm + 1 ohm + 1 ohm = 3 ohms

Using Ohm's Law, we can calculate the voltage required to create a current of 3 amperes:

V = IR

V = 3A x 3 ohm = 9V

Therefore, we need to connect all four batteries in series to create a voltage of 6V, and then connect two sets of these batteries in parallel to create a voltage of 12V.

d. To create a current of 6 amperes, we cannot use these components as they will create a circuit with a total resistance of less than 0.25 ohms, which will exceed the maximum current that can flow through the components and may damage them. In order to create a circuit with a higher resistance that can handle a current of 6 amperes, we would need to add additional resistors in series with the bulbs.

For example, we could add a 1 ohm resistor in series with the 3 ohm bulb to create a circuit with a total resistance of 7 ohms:

(check image 4)

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The new orbital speed after friction from the earth's upper atmosphere is 8674.15 m/s.

When the work done by a force does not depend on the choice of path, the force is called the conservative force. Some examples are a gravitational force, elastic spring force and electric force. On the other hand, when the work done by a force relies on the choice of the path of the motion, it is called non-conservative force.

The net work done by non-conservative force is W = ΔK + ΔP ----(1)

Given that, work done W = -7.5 * 10⁹ J

Change in kinetic energy = (Kf - Ki)

Final kinetic energy Kf = 1/2* m * Vf²

Initial kinetic energy Ki = 1/2* m * Vi²

Mass of the satellite m = 848 kg

Vf = Final speed

Vi = Initial speed = 9640 m/s

Change in gravitational potential energy ΔP = 0

Substituting the values in (1),

1/2* m (Vf² - Vi²) = W

1/2 * 848( Vf² -9640²) = W

Making Vf as subject,

Vf = √( 2W/m + Vi²)

⇒ √( -2* 7.5 * 10⁹/848 + 9640²)

⇒ 8674.15 m/s

Thus, the final speed decreases due to friction.

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Sure, here are four possible information technology (IT) security controls for the bank scenario along with the rationale for each choice:

Encryption Control: Encrypting sensitive information such as customer data, financial transactions, and other confidential information can protect against unauthorized access and tampering. By encrypting this information, even if it is intercepted by an unauthorized party, it will be unreadable and thus useless to them.

Preventing Misuse through Access Control User Policies: Implementing strong access control policies can prevent employees, contractors, and other authorized users from misusing the bank's IT systems and data. This includes setting restrictions on what users can do with the systems and data, setting time and location restrictions, and regularly monitoring user activity for unusual behavior.

Hardening of all Available Systems: Hardening refers to the process of securing IT systems by reducing vulnerabilities and eliminating unnecessary features, services, and applications. This can help prevent unauthorized access and protect against attacks, as it makes the systems less attractive targets for attackers.

Hardware and Software Controls using Hardware Firewalls: Firewalls can be used to control network traffic and monitor incoming and outgoing traffic to the bank's IT systems. This can help protect against unauthorized access and block malicious traffic, such as malware, from entering the bank's networks.

Communication and Email: The bank should have secure communication and email systems to ensure that confidential information is protected during transmission. This includes implementing secure protocols for email, such as SSL/TLS, and implementing encryption for email attachments and other sensitive information.

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Complete Question

The complete question is shown on the first uploaded image

Answer:

The derivative is  \(v(r)' =  \sqrt{\frac{D}{r} }\)

The correct option is option 1

Explanation:

From  the question we are told that

   The equation of the speed of the wave of invasion is  \(v(r)  = 2 \sqrt{Dr}\)

=>  \(v(r)  = 2 (Dr)^{\frac{1}{2} }\)

=>  \(v(r)  = 2 * D^{\frac{1}{2} } r^{\frac{1}{2} }\)

    Here r is the reproductive rate and the D is the parameter qualifying dispersal

Generally the derivative of this speed is mathematically represented as

         \(v(r)' = \frac{2}{2}  *  D^{\frac{1}{2} } *  r^{-\frac{1}{2} }\)

=>     \(v(r)' =  \sqrt{\frac{D}{r} }\)  

This derivative of the speed represents the rate of change of the invasive speed with respect to the the reproductive rate of an individual

From conservation of momentum we have that:

Therefore the velocity of the 1 kg ball after the collision is 2 m/s to the left.

The types of potential energy are:

Potential energy is the energy that an object possesses by virtue of its position or configuration. It is energy that is stored and can be converted into other forms of energy such as kinetic energy (the energy of motion) when the object is set in motion.

The amount of potential energy an object has depends on its position relative to other objects and/or forces acting on it. For example, a ball held at a certain height above the ground has potential energy due to its position relative to the Earth's gravitational field. Similarly, a stretched or compressed spring has potential energy due to its position relative to its relaxed state.

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Answer: For a sound wave with a speed 1481 m/s and wavelength of 23 m, the frequency is 64.391 Hz

Explanation:

We know that v = λ x f

where v ⇒ velocity of the wave

λ ⇒ wavelength

f ⇒ frequency

Here, λ = 23 m and v = 1481 m/s

Hence,

f = v /  λ

f = (1481 / 23) Hz

f = 64.391 Hz

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Answer:

There is some sort of "rollers" on the trail part that is used to make the roller coaster move when it is going up. Then because of that, the speed gets quicker when it drops down, so then it could move for a longer time until it reaches the next arch.

Explanation:

hope this helps :)

When the stored potential energy in a fault is suddenly released after building up for many years, an earthquake occurs.

An earthquake is a shaking of the earth's surface that results from the release of stored potential energy in the Earth's crust and mantle. This potential energy is stored as strain energy in rocks in the crust and mantle. Rocks can store strain energy when they are deformed by tectonic forces over long periods of time. As the strain energy accumulates, the rocks become more and more stressed until they reach a breaking point. When the breaking point is reached, the stored potential energy is suddenly released, causing the rocks to fracture and move. The sudden movement of the rocks produces seismic waves that travel through the Earth, causing the ground to shake. Earthquakes can be very destructive, causing damage to buildings, infrastructure, and the natural environment. In addition, earthquakes can trigger other hazards, such as landslides and tsunamis, which can add to the destruction.

Therefore, it is important to study earthquakes and understand the geology of the Earth's crust and mantle in order to better prepare for and mitigate the effects of future earthquakes.

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Answer:

45 degrees

Explanation:

angle of launch=arctan(vertical velocity/ horizontal velocity)

angle = arctan(30/30) = 45 degrees

The choice of whether to use radians or degrees depends on the type of problem that you are working on. For most physics problems, it is recommended to use radians.

Radians are a measure of angles that are based on the radius of a circle. One radian is equal to the angle that is formed when the length of the arc of a circle is equal to the radius of the circle. In contrast, degrees are based on dividing a circle into 360 equal parts.

One of the main advantages of using radians in physics is that it simplifies calculations involving angles. In particular, it makes it easier to perform calculations involving trigonometric functions like sine, cosine, and tangent. This is because the derivatives of these functions are simpler when the angles are expressed in radians.

In addition to simplifying calculations, using radians in physics also makes it easier to work with certain physical laws. For example, the angular frequency of an object that is undergoing simple harmonic motion is given by the formula:

ω = 2πf

where ω is the angular frequency, and f is the frequency of the motion. This formula shows that the angular frequency is given in terms of radians per second, so if you are working with this formula, you will need to use radians for your angle measurements.

Another reason why radians are preferred in physics is that they make it easier to work with calculus. When you are dealing with derivatives or integrals involving angles, it is much simpler to use radians. This is because the derivative of sine is cosine, the derivative of cosine is negative sine, and the derivative of tangent is the square of secant. These relationships hold true only when the angles are measured in radians.

In conclusion, it is recommended to use radians in physics, as it simplifies calculations involving angles, makes it easier to work with certain physical laws, and makes it easier to work with calculus. However, if you are working on a problem that involves degrees, make sure to convert your angles to radians before performing any calculations involving trigonometric functions or calculus.

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Answer:

THE 2ND ONE HOPE THIS HELPED GOD BLESS U

Explanation: