The graph below could be the graph of which exponential function

Distance is increasing with a speed of 0.2 Miles/Min

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

Time in Minutes      Distance in Miles

0                              0.0

2                              0.4

4                              0.8

6                              1.2

8                              1.6

Here, Myra’s distance is increasing as time increase with a constant Speed.

Now, In every 2 mins distance traveled = 0.4 Miles

Hence, In every 1 min Distance traveled = 0.4/2 = 0.2 Miles/Min

Thus, Distance is increasing with a speed of 0.2 Miles/Min.

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Answer:

\(3 + 3 + 3 =9 \)

\(5 + 5 + 5 + 5 =20 \)

\(5 + 5 + 3 =13 \)

\(3 + 3 + 3 + 5 = 14\)

\(5 + 5 + 5 =15 \)=15

\(5 + 5 + 3 - 3 =10 \)

\(5 + 5 + 3 + 3 + 3 =19 \)

Answer:

Step-by-step explanation:

3+3+3=9

5+5+5+5=20

3+3+3+5=14

5+5+5=15

5+5+3-3=10

5+5+3+3+3=19

Answer: 140%

Step-by-step explanation:

Answer:

140%

Step-by-step explanation:

BRAINLIEST PLSSSS

Answer:

it is 4.7 I did the math and it's right

Answer:

$4.70

Step-by-step explanation:

28-4.50=23.50

23.50/5=4.70

Answer:

a. x = 14 (see explanation)

b. the arrows along the lines

Step-by-step explanation:

The relationship of these two expressions is Same Side, which means their sum is 180.

plugging in

108 + 4x + 16 = 180 | Given

124 + 4x = 180 | Add the numbers

4x = 56 | Subtract 124 from both sides

x = 14 | Divide both sides by 4

Answer:

87.55 \(cm^2\)

Step-by-step explanation:

a) True, b) False, c) False, d) True, e) False, f) False, g) True

a) The statement is true. The symbol "∅" represents the empty set, which does not contain any elements. Since 0 is not an element of the empty set, the statement "0 ∈ ∅" is false.

b) The statement is false. The symbol "{0}" represents a set containing the element 0. The empty set, represented by "∅", does not contain any elements. Therefore, the empty set is not an element of the set {0}.

c) The statement is false. The symbol "{0}" represents a set containing the element 0. However, the empty set, represented by "∅", does not contain any elements. Therefore, the set {0} is not a subset of the empty set.

d) The statement is true. The empty set, represented by "∅", does not contain any elements. Every set is a subset of the empty set, including the set {0}.

e) The statement is false. The symbol "{0}" represents a set containing the element 0. In this case, {0} is not an element of itself. Therefore, the statement "{0}∈{0}" is false.

f) The statement is false. The symbol "{0}" represents a set containing the element 0. In this case, {0} is not a proper subset of itself. Therefore, the statement "{0}⊂{0}" is false.

g) The statement is true. The symbol "{∅}" represents a set containing the empty set. In this case, {∅} is a subset of itself because it contains the element ∅. Therefore, the statement "{∅} ⊆ {∅}" is true.

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Answer:

1.58113883 i

Step-by-step explanation:

√-2.5 is error

1.58113883 i

i the square root of negative one.

Any number times itself is a positive number (or zero), so you can't ever get to a negative number by squaring. Since square roots undo squaring, negative numbers can't have square roots.

Answer:

\(1.58\ i\)

Step-by-step explanation:

Step 1:  Determine the square root of -2.5

The \(\sqrt{-1}\) is equal to i so we can say that \(\sqrt{(-1)^2}\) is equal to \(\sqrt{i^2}\) which is then equal to \(i\).  This means that we have \(i\sqrt{2.5}\).

We can then take the square root of 2.5 which is rounded to \(1.58\ i\)

Answer:  \(1.58\ i\)

ANSWER

ITS ANSWER IS 1730

Answer:

1730

Step-by-step explanation:

Check out the image below!

1)The pdf of U is f(u) = (1/(2√u)) exp(-u/2) for u > 0 and f(u) = 0 otherwise.

2)U follows a gamma-distribution with parameter a = 3/2 or a = 1/2.

3)x = (y²/2) and dx = y dy using exponential distribution

We can rewrite the integral as:

I(1/2) = ∫₀^∞ y exp(-y²) dy

       = 1/2 ∫₀^∞ exp(-u/2) du

This is the same as the integral for f(u) when u = 1/2.

Therefore, we have:

I(1/2) = V1

(1) For U = Z², we can use the method of transformations.

Let g(z) be the transformation function such that

U = g(Z)

   = Z².

Then, the inverse function of g is given by h(u) = ±√u.

Thus, we can apply the transformation theorem as follows:

f(u) = |h'(u)| g(h(u)) f(u)

     = |1/(2√u)| exp(-u/2) for u > 0 f(u) = 0 otherwise

Therefore, the pdf of U is given by:

f(u) = (1/(2√u)) exp(-u/2) for u > 0 and f(u) = 0 otherwise.

(2) We are given that f(1/2) = VT, where V is a constant.

We can substitute u = 1/2 in the pdf of U and equate it to VT.

Then, we get:VT = (1/(2√(1/2))) exp(-1/4)VT

                            = √2 exp(-1/4)

This gives us the value of V.

Now, we can use the pdf of the gamma distribution to find the parameter a such that the gamma distribution matches the pdf of U.

The pdf of the gamma distribution is given by:

f(u) = (u^(a-1) exp(-u)/Γ(a)) for u > 0 where Γ(a) is the gamma function.

We can use the following relation between the gamma and the factorial function to simplify the expression for the gamma function:

Γ(a) = (a-1)!

Thus, we can rewrite the pdf of the gamma distribution as:

f(u) = (u^(a-1) exp(-u)/(a-1)!) for u > 0

We can now equate the pdf of U to the pdf of the gamma distribution and solve for a.

Then, we get:

(1/(2√u)) exp(-u/2) = (u^(a-1) exp(-u)/(a-1)!) for u > 0 a = 3/2

Therefore, U follows a gamma distribution with parameter

a = 3/2 or equivalently,

a = 1/2.

(3) We need to show that I(1/2) = V1.

Here, I(1) = ∫₀^∞ exp(-x) dx is the integral of the exponential distribution with rate parameter 1 and V is a constant.

We can use the change of variables y = √(2x) to simplify the expression for I(1/2) as follows:

I(1/2) = ∫₀^∞ exp(-√(2x)) dx

Now, we can substitute y²/2 = x to obtain:

x = (y²/2) and

dx = y dy

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Answer: b= (0,4)

Step-by-step explanation:

The 'b' value in a line is the y-int. of a linear equation. That means you need to determine where the linear equation intersects with the y-axis. In this scenario it intersects at the point (0,4)

The probability of at least one error occurring in one billion divisions with this chip is approximately 0.1841, or 18.41%.

The probability of at least one error occurring in one billion divisions with this chip can be calculated using the binomial distribution. Let p be the probability of an error occurring in one division, which is 1/5 billion, and q be the probability of no error occurring in one division, which is 1 - p. Then, the probability of at least one error occurring in one billion divisions can be calculated as 1 - (q)^1,000,000,000, where the exponent is the number of trials.

Plugging in the values, we get:

p = 1/5 billion

q = 1 - p = 4,999,999,999/5 billion

n = 1 billion

P(at least one error) = 1 - (4,999,999,999/5 billion)^1,000,000,000 = 0.1841

Therefore, the probability of at least one error occurring in one billion divisions with this chip is approximately 0.1841, or 18.41%.

The binomial distribution is used to model the number of successes in a fixed number of independent trials with a constant probability of success. In this case, the number of successes is the number of errors, and the probability of success is the probability of an error occurring in one division. We calculate the probability of at least one error occurring by subtracting the probability of no errors from 1. We use the exponentiation rule of exponents to calculate the probability of no errors occurring in one billion divisions, which is the probability of no errors occurring in one division raised to the power of the number of divisions. Finally, we use the formula to get the probability of at least one error occurring in one billion divisions with this chip.

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Answer:

9.8 * 10^-11

Step-by-step explanation:

The exponent will be negative as the number is less than 1.

After the decimal point there are 11 digits up to and including the 9.

Answer:

Step-by-step explanation:

⇒o 2/-3  Doesn't matter where the minus is as long as there an odd numbere of them.

o -3/-2

o -2/-3

⇒o - 2/3   This is given. Is it really listed.

o -3/2

o -2/2

There really are only 2 of them. 3/2 in any form is not equal to 2/3.

-2/2 = - 1 not -2/3

-2/-3 There are an even number of - signs. The answer is 2/3

Answer:

m= -1

Use: y = mx + b

Answer:

Pfffttttt- Amateurs, it is quite simple really. Take a nice long look. In the picture is he answer. And I was just joking around, even I had to use a calculator for the answer.

Step-by-step explanation:

Put the x's together, the negatives and the positives.

Under the given transformation, the image of the set S = {(u, v) | 0 ≤ u ≤ 3, 0 ≤ v ≤ 2} is the set {(x, y) | 0 ≤ x ≤ 12, -2 ≤ y ≤ 3}.

To find the image of the set S under the given transformation, we substitute the bounds of S into the equations for x and y and determine the resulting range of values.

The set S is defined as {(u, v) | 0 ≤ u ≤ 3, 0 ≤ v ≤ 2}. We will find the image of each boundary point and then determine the range of values for the transformed set.

For u = 0 and v = 0:

x = 2(0) + 3(0) = 0

y = 0 - 0 = 0

The point (0, 0) is transformed to (0, 0).

For u = 3 and v = 0:

x = 2(3) + 3(0) = 6

y = 3 - 0 = 3

The point (3, 0) is transformed to (6, 3).

For u = 0 and v = 2:

x = 2(0) + 3(2) = 6

y = 0 - 2 = -2

The point (0, 2) is transformed to (6, -2).

For u = 3 and v = 2:

x = 2(3) + 3(2) = 12

y = 3 - 2 = 1

The point (3, 2) is transformed to (12, 1).

Now, let's consider the range of transformed points for the x and y coordinates.

For the x-coordinate, we observe that the minimum value is 0 (from point 1) and the maximum value is 12 (from point 4). Therefore, the range of x is [0, 12].

For the y-coordinate, we observe that the minimum value is -2 (from point 3) and the maximum value is 3 (from point 2). Therefore, the range of y is [-2, 3].

Combining the ranges of x and y, we have the image of set S as:

{(x, y) | 0 ≤ x ≤ 12, -2 ≤ y ≤ 3}

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The answer for the missing piece is to 'find' the variable.

What is the effective tax rate if the assessment rate is 50% and the property tax rate is $34.89 per $1000?
The effective tax rate can be calculated by multiplying the assessment rate with the property tax rate. In this case, the assessment rate is 50% or 0.5, and the property tax rate is $34.89 per $1000. To calculate the effective tax rate, we need to multiply the assessment rate by the property tax rate.

The effective tax rate is calculated as follows:
Effective tax rate = Assessment rate * Property tax rate

In this case, the assessment rate is 50% (or 0.5) and the property tax rate is $34.89 per $1000.

So, the effective tax rate would be:

Effective tax rate = 0.5 * $34.89 = $17.445 per $1000.

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Answer:

ASA

Step-by-step explanation:

The required equation for the cost of renting a moving van is

            y = $39.99 + $0.19 m

According to the question we have been given that

     Rental fee = $39.99

 Additional charge = $0.19

Let the y represent the cost of renting a moving van  

and m represent the number miles driven by the van.

The expression can be formed as

            y = (fixed charge) + m*(additional charge)

            y = $39.99 + $0.19 m

hence the required equation for the cost of renting a moving van is

            y = $39.99 + $0.19 m

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Answer:

square root of 8 is approximately 2.828

Any function whose graph is NOT a line is said to be nonlinear. It has the equation f(x) = ax + b. With the exception of the form f(x) = ax + b, its equation can take any form. Any two points on the curve have the same slope.

To ascertain whether a table of values is a linear function, follow these steps:

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When the price is $22, the rate of change in sales volume is roughly -0.014 (thousands of units per dollar). This suggests that the sales volume is likely to decline by 0 units for every $1 rise in price, demonstrating a negligible impact of price on volume.

To find the rate of change in sales volume when the price is $22, we need to calculate the derivative of the sales volume function with respect to the price and evaluate it at the given price.

The sales volume function is given by:

\(y = \frac{32}{{(3p + 1)}^{-\frac{2}{5}}}\)

To find the derivative, we can use the chain rule. Let's denote the derivative as \(\frac{dy}{dp}\):

\(\frac{dy}{dp} = \left(-\frac{2}{5}\right) \cdot 32 \cdot (3p + 1)^{-\frac{2}{5} - 1} \cdot (3)\)

Simplifying the expression, we have:

\(\frac{{dy}}{{dp}} = \frac{{-64}}{{5 \cdot (3p + 1)^{\frac{{7}}{{5}}}}}\)

Now, we can evaluate the derivative at the price p = $22:

\(\frac{{dy}}{{dp}} = \frac{{-64}}{{5 \cdot (3 \cdot 22 + 1)^{\frac{{7}}{{5}}}}}\)

\(= \frac{{-64}}{{5 \cdot (66 + 1)^{\frac{{7}}{{5}}}}}\)

\(= \frac{{-64}}{{5 \cdot (67)^{\frac{{7}}{{5}}}}}\)

Calculating this expression to three decimal places, we get:

\(\frac{{dy}}{{dp}}\) ≈ -0.014

(a) The rate of change in sales volume when the price is $22 is approximately -0.014 (thousands of units per dollar).

(b) Interpretation: If the price increases by $1, the sales volume will decrease by approximately 0.014 (thousands of units). Rounded to the nearest whole number, we can say that the sales volume will decrease by 0 units. This suggests that a small increase in price has negligible impact on the sales volume.

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The area of the sector is 11.75 metres squared.

The area of the sector can be calculated as follows:

area of a sector = ∅ / 360 × πr²

where

Therefore,

r = 3 metres

∅= 150 degrees

Therefore,

area of the sector = 150 / 360 × 3.14 × 3²

area of the sector = 150 / 360 × 3.14 × 9

area of the sector = 4239 / 360

area of the sector = 11.775 metres squared

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Answer:

Domain= neg infinite, pos infinite

range= neg infinite, 4

The required point is located two units to the right of points (2, 5), and on the same horizontal line is (4, 5).

Coordinate, is represented as the values on the x-axis and y-axis of the graph. while the coordinate x is called abscissa and the coordinate of the y is called ordinate.

Here,
If we want to locate a point that is two units to the right of point (2, 5) on the same horizontal line, then the y-coordinate of the new point should be the same as the y-coordinate of (2, 5), which is 5.

To find the x-coordinate of the new point, we can add 2 units to the x-coordinate of (2, 5), which gives:

2 + 2 = 4

Therefore, the coordinates of the new point are (4, 5).

So the answer is (4, 5).

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Answer:

\(c = \pi d\)

circumference = pi * diameter