The magnitude of the work done on the electron is 6,700 J. The speed of the electron at x = 20 m is 29.9 m/s
How to analyze electric potential and field?The magnitude of the work done on the electron by the electric field can be calculated by integrating the force exerted by the electric field over the distance traveled. In this case, the work done is 40,200 J.
The speed of the electron at x = 20 m can be determined by using the conservation of mechanical energy. The speed is found to be 20 m/s.
The x-component of the electric field can be derived by taking the negative derivative of the electric potential equation with respect to x. It is given by Ex(x) = 4αx + β.
The graph of the acceleration of the electron as a function of position x is a linear graph, starting at a negative value and gradually decreasing to zero as x increases.
The graph of the kinetic energy of the electron as a function of position x is a parabolic graph, starting at zero, reaching a maximum value, and then decreasing as x increases.
An electron released from rest will move in the negative x direction at x = -2 m and x = +3 m. At x = +1 m, the electron will move in the positive x direction. This can be justified by evaluating the electric potential at these positions and determining the direction of the electric field.
The potential difference from x = 0 m to x = 20 m caused by the combination of the original electrical potential and the electric field of the charged object is 5,600 V. This can be calculated by subtracting the electric potential at x = 0 m from the electric potential at x = 20 m.
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How long does it take light to travel from jupiter to earth?.
What is the centripetal acceleration acting on a 19 kg ball if it is being spun around by a tension force of 125 N?
Answer:
Explanation:
The centripetal acceleration:
aₙ = F /m = 125 /19 ≈ 6.6 m/s²
In the figure below, the vector r_1 points to the location of object 1 and q points to the location of object 2. Both vectors lie in the xy plane. (Express your answers in vector form.) Calculate the position of object 2 relative to object 1, as a relative position vector. r21 = m Calculate the position of object 1 relative to object 2, as a relative position vector. r12 = m
The position of object 2 relative to object 1 is r21, which is equal to the vector q - r_1.
The vector q - r_1 points from object 1 to object 2. Therefore, r21 = q - r_1.
The position of object 1 relative to object 2 is r12, which is equal to the vector r_1 - q.
The vector r_1 - q points from object 2 to object 1. Therefore, r12 = r_1 - q.
To calculate these relative position vectors, we subtract the vector pointing to the location of object 2 (q) from the vector pointing to the location of object 1 (r_1) to get r21, and then subtract the vector pointing to the location of object 1 (r_1) from the vector pointing to the location of object 2 (q) to get r12.
Both of these vectors lie in the xy plane and can be expressed in vector form.
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A car moves in a straight line along the x-axis. The velocity of the car vx as a function of time t is shown in the graph above. The position x of the car at t=0 is x0. The average velocity of the car during the interval of 0 to 10 is most nearlya. +4.0m/s b. +0.40m/s c. -1.4m/sd. +1.4m/s e. +1.8m/s
The average velocity of the car during the interval of 0 to 10 is most nearly +1.4 m/s.
Determine the average velocity?To calculate the average velocity, we need to find the displacement of the car during the given time interval and divide it by the duration of the interval. Since the velocity of the car is given as a function of time, we can determine the displacement by finding the area under the velocity-time graph.
In this case, the area under the graph between t=0 and t=10 represents the displacement of the car during that time interval. By measuring the area and considering the direction of motion (positive or negative), we can determine the average velocity.
Based on the given graph, the area under the curve from t=0 to t=10 is positive and approximately equal to 14 m. Dividing this displacement by the duration of 10 seconds gives us an average velocity of approximately +1.4 m/s.
Therefore, the car's average velocity from 0 to 10 is approximately +1.4 m/s.
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An object is oscillating on a spring with a period of 4.60 s. At time t = 0.00 s the object has zero speed and is at x = 8.30 cm. What is the acceleration of the object at t = 2.50 s?
A) 14.9 cm/s^2
B) 1.33 cm/s^2
C) 11.5 cm/s^2
D) 0.00 cm/s^2
E) 0.784 cm/s^2
The acceleration of the object at t = 2.50 s is 1.33 cm/s².The correct answer is option B.
To determine the acceleration of the object at time t = 2.50 s, we first need to find the equation that describes the motion of the object on the spring. The equation for simple harmonic motion (SHM) is given by:
x(t) = A * cos(2πt/T + φ)
Where:
- x(t) is the displacement of the object at time t.
- A is the amplitude of the motion.
- T is the period of the motion.
- φ is the phase constant.
In this case, we are given the period T = 4.60 s and the displacement x = 8.30 cm at t = 0.00 s. Since the object has zero speed at t = 0.00 s, it is at the maximum displacement, so A = 8.30 cm.
Substituting the values into the equation, we have:
x(t) = 8.30 * cos(2πt/4.60 + φ)
To find the phase constant φ, we use the initial condition x(0) = 8.30 cm:
8.30 = 8.30 * cos(2π * 0/4.60 + φ)
1 = cos(φ)
Since the cosine function equals 1 when the angle is 0 degrees, we can determine that φ = 0.
Now, we can differentiate x(t) with respect to time to find the velocity v(t) and then differentiate v(t) to find the acceleration a(t). The velocity v(t) is given by:
v(t) = dx(t)/dt = -A * (2π/T) * sin(2πt/T + φ)
Substituting the known values, we have:
v(t) = -8.30 * (2π/4.60) * sin(2πt/4.60)
At t = 2.50 s, the velocity v(2.50) is:
v(2.50) = -8.30 * (2π/4.60) * sin(2π * 2.50/4.60)
Finally, we differentiate v(t) to find the acceleration a(t):
a(t) = dv(t)/dt = -A * (2π/T)^2 * cos(2πt/T + φ)
Substituting the known values, we have:
a(t) = -8.30 * (2π/4.60)^2 * cos(2πt/4.60)
Now we can calculate the acceleration at t = 2.50 s:
a(2.50) = -8.30 * (2π/4.60)^2 * cos(2π * 2.50/4.60)
Using a calculator, we find that a(2.50) ≈ -1.33 cm/s².
Therefore, the acceleration of the object at t = 2.50 s is approximately -1.33 cm/s².
The correct answer is B) 1.33 cm/s².
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What is the period of a wave with a wavelength of 8 cm and a frequency of 0.5 hertz?(1 point)
0.125 seconds
2 seconds
4 seconds
0.0625 seconds
Answer:2 seconds
Explanation:
a rock hits the ground at a speed of 15 m/s and leaves a hold 50 cm deep. after it hits the ground, what is the magnitude of the rock's (assumed) uniform acceleration?
The magnitude of the rock's (assumed) uniform acceleration is v² - 225.
Initial speed, u = 15 m/s
Displacement, s = 50 cm = 0.5 m
Magnitude of acceleration, a = ?
We know, v² - u² = 2as
Let's substitute the given values into the above formula. v² - u² = 2as (v is the final velocity)
Final velocity, v = ?u = 15 m/s (Initial velocity)
s = 0.5 m (Displacement)
a = ?
v² - u² = 2as (v² - u²)/2s = a(v+u)/2(a = (v² - u²)/2s)
(a = (v² - u²)/2s)(a = (v² - (15 m/s)²)/2(0.5 m))(a = (v² - 225)/1)(a = v² - 225)
Therefore, the magnitude of the rock's uniform acceleration is v² - 225, given that a rock hits the ground at a speed of 15 m/s and leaves a hold 50 cm deep after it hits the ground.
The magnitude of the rock's uniform acceleration is v² - 225.
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A vector
of magnitude 5 units and another vector ū of magnitude 3 units point in directions
differing by 60°. Find out (a) the scalar product of the two vectors and (b) the vector product of the two vectors
Answer:
7.5 units
13 units
Explanation:
\(|v|=5\ \text{units}\)
\(|u|=3\ \text{units}\)
\(\theta\) = Angle between the vectors = \(60^{\circ}\)
Scalar product is given by
\(u\cdot v=|u||v|\cos\theta\\ =3\cdot 5\cdot \cos60^{\circ}\\ =7.5\ \text{units}\)
The scalar product of the vectors is 7.5 units.
Vector product is given by
\(u\times v=|u||v|\sin\theta\\ =3\times 5\sin60^{\circ}\\ =13\ \text{units}\)
The vector product of the vectors is 13 units.
Circle the contact forces from the list:
Magnetism
Air resistance
Weight
Upthrust
Reaction
two converging lenses, each of focal length 14.8 cm, are placed 39.7 cm apart, and an object is placed 30.0 cm in front of the first lens. where is the final image formed? the image is located cm ---location--- what is the magnification of the system?
The final image is formed by two converging lenses at 15.3 cm in front of the second lens and the magnification of the system is -0.99.
To find the location of the final image, we can use the lens formula:
1/f = 1/do + 1/di
where f is the focal length of the lens, do is the object distance, and di are the image distance.
For the first lens, f = 14.8 cm and do = 30.0 cm. Plugging these values into the lens formula gives:
1/14.8 = 1/30 + 1/di
Solving for di, we get:
di = 20.1 cm
This means that the first lens forms an image 20.1 cm behind it, which serves as the object for the second lens.
Using the lens formula again for the second lens, f = 14.8 cm and do = 39.7 - 20.1 = 19.6 cm. Plugging these values into the lens formula gives:
1/14.8 = 1/19.6 + 1/di
Solving for di, we get:
di = 9.1 cm
Therefore, the final image is formed 9.1 cm behind the second lens.
To find the magnification of the system, we can use the formula:
m = - di/do
where m is the magnification, di is the image distance, and do is the object distance.
Plugging in the values we found, we get:
m = -9.1/30.0 = -0.303
Therefore, the magnification of the system is -0.303, which indicates that the image is inverted and smaller than the object.
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For the circuit shown in Figure 5.98, Find R. Figure 5.98 Express your answer in Ohms. For the circuit shown in Figure 5.98, Find V1Express your answer in Volts. For the circuit shown in Figure 5.98, Find V2. Express your answer in Volts.
In the circuit, the value of resistor R is approximately 62.6 Ω. The voltage drop across resistor R (V1) is approximately 8.22 V, and the voltage drop across the other resistor (V2) is approximately 3.41 V.
In order to find the value of R, use the equation: `R = V1 / I1`
Where, `I1` is the current passing through resistor R. As the circuit is in series, the current passing through each resistor is equal. Therefore, `I1 = I2 = I3`.
Total resistance of the circuit, `Rt = R1 + R2 + R3`=`25 + 50 + R`=`75 + R`
According to Kirchhoff's voltage law,
V = V1 + V2
V1 = V(R1 / Rt)
And V2 = V(R3 / Rt)
Where `V` is the voltage drop across the entire circuit.
V = V1 + V2 = IR
tI = 12V / Rt
Now, substituting the value of `I` in the equation `R = V1 / I1`R = V1 / I1 = V1 / I = V1 / (12 / (75 + R))
= V1 * (75 + R) / 12
So, V1 = IR1 = 12V * 25Ω / (25Ω + 50Ω + R)
= 300Ω / (2 + R / 75)
Therefore, V2 = IR3
= 12V * R / (25Ω + 50Ω + R)
To find the value of `R`, equate V1 and V2.
V1 = V2= 300Ω / (2 + R / 75) = 12V * R / (25Ω + 50Ω + R)
Solve for `R`.
300Ω (25Ω + 50Ω + R) = 12V R (2 + R / 75)22500 + 300R = 240R + 4R²/75
Simplifying the above expression,
4R² - 720R + 337500 = 0
Solving the above quadratic equation using the quadratic formula,
`R = (720 ± √(720² - 4(4)(337500)) / (2 × 4)`= 62.6 Ω or 107.4 Ω
Therefore, the value of R is 62.6 Ω (rounded to one decimal place).
Now that we have the value of R, let's calculate the value of V1 and V2.
V1 = 300Ω / (2 + 62.6 / 75)= 8.22 V (rounded to two decimal places)
And, V2 = 12V * 62.6Ω / (25Ω + 50Ω + 62.6Ω)= 3.41 V (rounded to two decimal places)
Therefore, the value of V1 is 8.22 V and the value of V2 is 3.41 V.
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A wave has a wavelength of 1.2 m and a frequency of 3 Hz. What is the wave
speed?
A. 4.2 m/s
B. 2.5 m/s
C. 1.8 m/s
D. 3.6 m/s
Answer:
D. 3.6m/s
Explanation:
The equation for wave speed can be used to calculate the speed of a wave when both wavelength and wave frequency are known. Consider an ocean wave with a wavelength of 1.2 meters and a frequency of 3 hertz. The speed of the wave is: Speed = 1.2m x 3wave/s = 3.6 m/s
An iguana crawls from a position of 5.0m to a position of -18m. If it completes this in 9.0s, what was its average velocity?
The average velocity of Iguana is -2.55m/s when it crawls from 5m to -18m in 9 seconds.
Average velocity of a body is defined as the total displacement divided by the total time taken by the body.
Here, initial position of iguana is 5m and the final position of the iguana is -18m.
Total displacement D is,
D = final position - initial position.
D = -18-5
D = -23m
Total time taken by the iguana is 9.0 seconds.
Average velocity(V) = total displacement/total time taken.
Putting values,
V = -23/9
V = -2.55m/s.
So, the average velocity of the iguana is -2.55m/s.
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10 points urgent due in 10
What wave properties are involved in a glass knocking over?
Answer:
Kinetic energy waves
Explanation:
the kinetic energy moves from your hand into the glass, knocking it over.
a horizontal force f of 12 lb pushes a block weighing 5.0 lb against a vertical wall. the coefficient of static friction between the wall and the block is 0.60 and the coefficient of kinetic friction is 0.40. assume the block is not moving initially. will the block start moving?
The applied horizontal force (F) of 12 lb is greater than the maximum static friction force (F_static_max) of 3.0 lb, the block will overcome static friction and start moving.
To determine if the block will start moving, we need to compare the force of static friction with the maximum possible static friction.
The maximum static friction force (F_static_max) can be calculated using the formula;
F_static_max = μ_static × N
where μ_static will be the coefficient of static friction and N is the normal force acting on the block.
The normal force (N) is equal to the weight of the block, which is 5.0 lb in this case.
N = 5.0 lb
Plugging in the values, we can calculate the maximum static friction force:
F_static_max = 0.60 × 5.0 lb
F_static_max = 3.0 lb
The maximum static friction force is 3.0 lb.
Since the applied horizontal force (F) of 12 lb is greater than the maximum static friction force (F_static_max) of 3.0 lb, the block will overcome static friction and start moving. Therefore, the block will start moving.
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The small capillaries in the lungs are in close contact with the alveoli. A red blood cell takes up oxygen during the 0. 75 s that it squeezes through a capillary at the surface of an alveolus. What is the diffusion time for oxygen across the 2. 0- μm -thick membrane separating air from blood? Assume that the diffusion coefficient for oxygen in tissue is 1. 1×10−11m2/s?
The diffusion time for oxygen across the 2.0-μm-thick membrane separating air from blood is approximately 3.64 × 10^-5 s.
The Oxygen Diffusion Time.The diffusion time for oxygen across the 2.0-μm-thick membrane can be calculated using Fick's law of diffusion:
J = -D * (ΔC/Δx)
Where:
J = rate of diffusion
D = diffusion coefficient
ΔC/Δx = concentration gradient
Assuming that the concentration gradient across the membrane is constant, we can simplify the equation to:
t = x^2 / (2D)
Where:
t = diffusion time
x = thickness of the membrane
Substituting the given values:
t = (2.0 × 10^-6 m)^2 / (2 × 1.1 × 10^-11 m^2/s)
t = 3.64 × 10^-5 s
Therefore, the diffusion time for oxygen across the 2.0-μm-thick membrane separating air from blood is approximately 3.64 × 10^-5 s.
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You accidentally drop a book down a stairwell. Assuming no air resistance,
how fast will the book be moving after 0.75 seconds?
Answer:
if we drop it and not throw it then
after 0.75 how fast the book is falling is given by its velocity as
v= at
= 9.8 × 0.75
=7.35 m/s
What elements in the periodic table are metals?
Answer:
here it is
Explanation:
Sodium Potassium Aluminum Calcium Lithium Mercury Arsenic Indium Magnesium Copper Iron Lead Germanium Beryllium Francium Polonium Radium Barium Strontium Tin
43.5 kg. Shawn rides his bike 1.3 km in
10.4 min at a constant velocity.
The acceleration of gravity is 9.8 m/s^2.
What is Shawn’s kinetic energy?
Answer in units of J.
Answer:
K.E is 90.625 J
Explanation:
Data:
Mass = m = 43.5kg
Distance = d = 1.3km = 1300 m
Time = t = 10.4 min = 624 sec
Accelaration = a or g = 9.8
Formula for kinrtic energy
K.E = 1/2mv²
Find velocity
V = d/t = 1300/624 = 2.0833333333333 m/s
Put values in formula
K.E = 1/2 (43.5)(2.084)² = 90.624999999995
Mark brainliest if you understand it
define liquid in matter
Answer:
A liquid is a nearly incompressible fluid that conforms to the shape of its container but retains a (nearly) constant volume independent of pressure. A liquid is made up of tiny vibrating particles of matter, such as atoms, held together by intermolecular bonds.
What current flows through the bulb of a 3.00 v flashlight when itshot resistance is 3.60 ohm?
The current flowing through the bulb of a 3.00 V flashlight with a resistance of 3.60 ohms is 0.833 A (amperes).
Divide the voltage by the resistance to find the current. As a result, 0.833 A of current is flowing through the light bulb (amperes).
According to Ohm's law, the current flowing through a conductor is inversely proportional to the resistance of the conductor and directly proportional to the voltage applied across it. The applied voltage in this instance is 3.00 V, while the bulb's resistance is 3.60 ohms. I = V/R can therefore be used to compute the current passing through the lightbulb.
Amperes (A), which measure the amount of electric charge passing through a conductor per unit of time, are the unit of current. The bulb is currently undergoing a 0.833 A current flow, which translates to 0.833 coulombs of charge passing through the bulb each second. This current is within a flashlight bulb's typical operating range and will produce enough light.
In conclusion, the outcome of utilizing Ohm's law to determine the current flowing through the bulb of a 3.00 V flashlight with a resistance of 3.60 ohms is 0.833 A. This current value falls within the typical flashlight bulb operating range and offers acceptable illumination.
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use the concept of energy to explain why ideal mechanical advantage is not the same as mechanical advantage for real machines.
Answer:
The ideal mechanical advantage, IMA, is the same but in absence of FRICTION! In this case you can use the concept known as CONSERVATION of ENERGY.
Explanation:
There i hope u i like it.
The quantity of times a machine enhances an input force is referred to as its mechanical advantage. The ratio of the output force to the input force is the true mechanical advantage. The mechanical advantage a machine has when there is no friction is its ideal mechanical advantage.
What concept of energy using ideal mechanical?The ratio of output force to input force is what determines the true mechanical advantage. The mechanical advantage in an ideal environment is the mechanical advantage now. It's the product of the input and output distances.
The mechanical benefit currently exists because it would exist in a perfect situation. The input and output distances were combined to create it. The optimal mechanical advantage of a machine is the one it has when there is no friction.
Therefore, The mechanical advantage of a perfect machine, or IMA, is one in which there is no loss of productive work resulting from friction between moving parts.
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How much force is needed to accelerate a. 15 kg mass at 20 m/s2.
Answer:
F = 300 N
Explanation:
This is an example of Newton's second Law
F = m * a
F = ?
m = 15 kg
a = 20 m^2
F = 20 * 15
F = 300 Newtons.
what type of device can be used to erase contents of a hard drive using a magnetic field
A degausser device can be used to erase the contents of a hard drive using a magnetic field.
A degausser is a tool that generates a strong magnetic field that can erase the data stored on magnetic media such as hard drives, tapes, and floppy disks. This is done by exposing the media to a changing magnetic field that effectively randomizes the data, making it unrecoverable. Degaussers are often used by organizations that need to dispose of sensitive data securely, such as government agencies or financial institutions.
It is important to note that not all hard drives can be effectively erased using a degausser, and other methods such as physical destruction or software-based wiping may be necessary in some cases.
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An Olympic sprinter runs towards you while holding a green glow stick. Assuming you had sensitive enough equipment, the light from the glow stick will appear: Blueshifted Greenshifted As a blackbody O Redshifted
The light from the green glow stick held by the Olympic sprinter will appear redshifted.
The phenomenon of redshift occurs when the source of light is moving away from the observer. In this case, as the sprinter is running towards you, the distance between you and the glow stick is decreasing over time. This decrease in distance causes a Doppler shift in the frequency of the light emitted by the glow stick.
Since the light is redshifted, its wavelength increases and the frequency decreases compared to its original emitted frequency. As a result, the light that reaches your eyes appears more towards the red end of the visible spectrum.
It is important to note that the color of the glow stick itself remains the same, but due to the relative motion between the source (the sprinter) and the observer (you), the light undergoes a change in frequency and appears redshifted.
This phenomenon is similar to the redshift observed in cosmology, where the light from distant galaxies appears to be redshifted due to the expansion of the universe.
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When you put a 9. 0 V battery across a bulb, 0. 1 A of current
flows through the bulb. Calculate the resistance of the bulb
When a 9.0 V battery is connected to a bulb and 0.1 A of current flows through it, the resistance of the bulb is 90 ohms.
When a 9.0 V battery is connected to a bulb and 0.1 A of current flows through the bulb, we can calculate the resistance of the bulb using Ohm's Law. Ohm's Law states that the current flowing through a conductor is directly proportional to the voltage applied across it and inversely proportional to its resistance.
To find the resistance, we can rearrange Ohm's Law equation (V = IR) to solve for R, where V is the voltage, I is the current, and R is the resistance.
First, let's plug in the given values:
V = 9.0 V (voltage)
I = 0.1 A (current)
Now, we can rearrange the equation to solve for R:
R = V / I
Substituting the given values:
R = 9.0 V / 0.1 A
Dividing 9.0 V by 0.1 A, we get:
R = 90 ohms
Therefore, the resistance of the bulb is 90 ohms.
In summary, when a 9.0 V battery is connected to a bulb and 0.1 A of current flows through it, the resistance of the bulb is 90 ohms.
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What type of material is least likely to be transported as suspended load?
The type of material that is least likely to be transported as suspended load is gravel.
Gravel is made up of large, irregularly shaped particles that are too heavy to be suspended in water for long periods of time. Instead, gravel is typically transported as bed load, which means that it rolls and slides along the bottom of a stream or river. Other materials that are less likely to be transported as suspended load include sand and pebbles. These particles are smaller than gravel, but they are still too heavy to be suspended for long periods of time. However, they can be transported as suspended load if the water is flowing quickly enough. The type of material that is most likely to be transported as suspended load is clay. Clay particles are very small and have a high surface area. This makes them very effective at absorbing water, which makes them buoyant and allows them to be suspended in water for long periods of time.
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. A car starts to move from rest has an acceleration of 3m/s².what will be the velocity and distance travelled by the car after 50sec.
Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :
Step 1: Calculate the velocity using the equation:
\(v = u + at\)
where:
- \(v\) is the final velocity
- \(u\) is the initial velocity (0 m/s, as the car starts from rest)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)
Step 2: Calculate the distance traveled using the equation:
\(s = ut + \frac{1}{2}at^2\)
where:
- \(s\) is the distance traveled
- \(u\) is the initial velocity (0 m/s)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)
Now, let's simplify these equations:
\(v = 3 \times 50\)
\(s = \frac{1}{2} \times 3 \times 50^2\)
Calculating the results:
\(v = 150\) m/s
\(s = 3750\) meters
Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.
a truck is pulling an 85-kg rock attached by a rope. the coefficient of friction between the rock and the ground is 0.32. the truck applies 295 n of force to the rock. determine the net force and the acceleration.
Answer:
Net Force = 28.44 N
Acceleration = 0.33 \(\frac{m}{s^2}\)
Explanation:
First, solve for the force of friction:
\(f=\mu N\)
For this problem, let
\(\mu\) = 0.32
\(N=mg\\N=(85\ kg)(9.8\ \frac{m}{s^2})\\N=833\ N\)
So, the force of friction can be calculated as
\(f=(0.32)(833\ N)\\f=266.56\ N\)
Because the force of friction opposes the motion, the net force can be found by subtracting the force of friction from the force applied by the truck.
\(F_t=F_T-F_N\)
\(F_t=295\ N\\F_N=266.56\ N\\F_t=295\ N-266.56\ N\\F_t=28.44\ N\)
Finally, rearrange Newton's second law of motion (F=ma) to find the rock's acceleration:
\(a=\frac{F_t}{m}\\a=\frac{28.44\ N}{85\ kg}\\a=0.33\ \frac{m}{s^2}\)
8. Determine the density of a cube that has a mass of 40.5g and a volume of 9cm3 .
Answer:
d = 2.70 g/mL
Explanation:
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