The distance from arias home to the science museum is 0.72 mile which fraction is equivalent to this distance in miles.

Answer:

47.1 ft

Step-by-step explanation:

C = πd

C = 3.14 · 15

C = 47.1

C ≈ 47.1 ft

Answer:

b. To find the probability a customer who ordered pancakes came to thediner late, we need to look at the intersection of the "pancakes" row and the "late" column. This gives us a probability of 0.1, or 10%

c. To determine whether breakfast choice and meal time are independent, we need to see if the probability of one event changes based on the occurrence of the other event. In this case, it seems that breakfast choice and meal time are not independent, as the probability of being late seems to differ based on what breakfast item the customer chose. For example, the probability of being late is higher for customers who ordered pancakes compared to those who ordered cereal. Therefore, the choice of breakfast item appears to be related to the probability of being late, and so breakfast choice and meal time are not independent.

Step-by-step explanation:

The distance between two lines measured along a perpendicular line to the line is always the same is called as equidistant .

Given :

The distance between two lines measured along a perpendicular line to the line is always the same.

What is Equidistant ?

Distances between two points from a common points are equal then it is called as equidistant .

Formulas :

Midpoint = ( x1 + x2 / 2 , y1 + y2 / 2 )

Distance = \(\sqrt{(x2 - x1 )^2 - (y2 - y1)^2 }\)

These are two main formulas are used to find whether equidistant or not.

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Answer:

24 ⅓

Step-by-step explanation:

27-2 is equal to

25

25-⅔ Is equal to

24 ⅓

Answer:

26^1/3

Step-by-step explanation:

I don't know how they got 25 because there is no -2 in the equation so i hope this helps! It was correct for me!!

Answer: b+95+34=180, b+129=180, 51

Step-by-step explanation:

b+95+34=180 works because the angles add to form a straight angle.

From this, we can obtain b+129=180 by adding the two constants.

Subtracting 129 from both sides, we get b=51.

Answer:

k i all uc la if u do this now nu will fry ud hedbhedbhgebcyhegfyebc

Step-by-step explanation:

bcyhebvcvbehcbe nhbdwgef che bhcb hsg ge hdbhuj eh

Answer:

0.1

Step-by-step explanation:

Just take 24/24 which is 1 and move the decimal one place to the left because there is an extra 0 on the denominator

If he has 3 gallons of juice ad we want to pour equal amount in 5 juices we have to divide 5 into 5

So he has to pour 0.6 gallons of juice in each glass

Answer:

...............

Step-by-step explanation:

...............

a)   The velocity of the object at t = 10.0 s is 645.9 m/s.

b)    The object is at rest at t = -0.87 s and t = 0.62 s.

c)    The acceleration of the object at t = 0.50 s is 7.20 m/s^2.

A. To find the velocity of the object at t = 10.0 s, we need to take the derivative of the position function with respect to time:

v(t) = 3At^2 + 2Bt + C

Plugging in the given constants, we get:

v(10.0) = 3(2.10)(10.0)^2 + 2(1.00)(10.0) - 4.10

v(10.0) = 630.0 + 20.0 - 4.10

v(10.0) = 645.9 m/s

Therefore, the velocity of the object at t = 10.0 s is 645.9 m/s.

B. The object is at rest when its velocity is zero. So, we need to find the value(s) of t that make v(t) = 0. Using the same velocity function from part (A), we can set it equal to zero and solve for t:

3At^2 + 2Bt + C = 0

Plugging in the given constants, we get a quadratic equation:

6.30t^2 + 2.00t - 4.10 = 0

Using the quadratic formula, we can solve for t:

t = (-2.00 ± sqrt(2.00^2 - 4(6.30)(-4.10))) / (2(6.30))

t = (-2.00 ± sqrt(104.80)) / 12.60

t = (-2.00 ± 10.24) / 12.60

t = -0.87 s or 0.62 s

Therefore, the object is at rest at t = -0.87 s and t = 0.62 s.

C. To find the acceleration of the object at t = 0.50 s, we need to take the derivative of the velocity function with respect to time:

a(t) = 6At + 2B

Plugging in the given constants, we get:

a(0.50) = 6(2.10)(0.50) + 2(1.00)

a(0.50) = 7.20 m/s^2

Therefore, the acceleration of the object at t = 0.50 s is 7.20 m/s^2.

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(a) The values of Q1 as 2 and Q3 as 35.

(b) The dataset was arranged in ascending order, and since the total number of observations (n) is odd (13), the median was found to be the middle value, which is 5.

(c) The upper adjacent value was determined by adding 1.5 times the IQR to Q3, resulting in 87.5.

(d) The box plot of the data is illustrated below.

(a) Finding Q1 and Q3:

To determine Q1 and Q3 from the given dataset, we can start by arranging the data in ascending order: 0, 2, 3, 4, 4, 5, 6, 7, 35, 2677, 33478.

Next, we count the total number of observations (n) which is 13 in this case. We use the following formulas to calculate the position of Q1 and Q3:

Q1 = (1 * n) / 4

Q3 = (3 * n) / 4

Substituting the value of n into the formulas:

Q1 = (1 * 13) / 4 = 3.25 (approximately)

Q3 = (3 * 13) / 4 = 9.75 (approximately)

Now, we need to identify the values in the dataset that correspond to these positions. For Q1, we take the value at the position immediately below 3.25, which is 2. For Q3, we take the value at the position immediately below 9.75, which is 35.

Therefore, the values of Q1 and Q3 for the given dataset are 2 and 35, respectively.

(b) Finding the Median:

The median represents the middle value of a dataset when it is arranged in ascending or descending order. If the dataset has an odd number of observations, the median is the middle value itself. If the dataset has an even number of observations, the median is the average of the two middle values.

Arranging the given dataset in ascending order: 0, 2, 3, 4, 4, 5, 6, 7, 35, 2677, 33478.

Since the total number of observations (n) is odd (13), the median will be the middle value. In this case, the middle value is the 7th observation, which is 5.

Therefore, the median for the given dataset is 5.

(c) Finding the Adjacent Values:

Adjacent values, also known as whiskers in a boxplot, indicate the minimum and maximum values within a certain range. The range is determined using the interquartile range (IQR), which is the difference between Q3 and Q1.

For the given dataset, the IQR is calculated as follows:

IQR = Q3 - Q1 = 35 - 2 = 33

The adjacent values are determined by extending the whiskers 1.5 times the IQR below Q1 and above Q3.

Lower adjacent value = Q1 - 1.5 * IQR

Upper adjacent value = Q3 + 1.5 * IQR

Substituting the values:

Lower adjacent value = 2 - 1.5 * 33 = -47.5

Upper adjacent value = 35 + 1.5 * 33 = 87.5

Therefore, the adjacent values for the given dataset are -47.5 and 87.5.

(d) Determining the Correct Modified Boxplot:

To determine the correct modified boxplot, we need additional information or options to compare against the given dataset. Unfortunately, the options are not provided in your question. Please provide the options or any additional information related to the modified boxplot so that I can assist you further in choosing the correct one.

Remember, the boxplot is a graphical representation of the dataset using its quartiles, median, adjacent values, and outliers, if any. It provides a visual summary of the distribution and identifies any potential outliers or extreme values.

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Answer:

Step-by-step explanation:

y=10

The p-value for this hypothesis test is 0.263.

The percentage of parents who feel overwhelmed has decreased from the pandemic/stay at home era, we can use a hypothesis test with the following null and alternative hypotheses:

Null hypothesis: The percentage of parents who feel overwhelmed is still 70%.

Alternative hypothesis: The percentage of parents who feel overwhelmed has decreased from 70%.

We can use a one-sample proportion test to test this hypothesis. The test statistic is calculated as:

z = (p - p0) / sqrt(p0 * (1 - p0) / n)

where p is the sample proportion, p0 is the hypothesized population proportion, and n is the sample size.

In this case, the sample proportion is:

p = 335 / 500 = 0.67

The hypothesized population proportion is:

p0 = 0.70

The sample size is:

n = 500

We can calculate the test statistic as:

z = (0.67 - 0.70) / sqrt(0.70 * (1 - 0.70) / 500) = -1.44

Using a standard normal distribution table or calculator, we can find the p-value associated with this test statistic.

For a two-tailed test with a significance level of 0.05, the p-value is approximately 0.1492.

This means that if the null hypothesis is true, there is a 14.92% chance of obtaining a sample proportion as extreme as 0.67 or more extreme in favor of the alternative hypothesis.

Since the p-value is greater than the significance level of 0.05, we fail to reject the null hypothesis.

Therefore, we do not have enough evidence to conclude that the percentage of parents who feel overwhelmed has decreased from the pandemic/stay at home era.

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if he started working in 45 min he can make time for it

movie started at 2.55 pm

As per the question

Movie start at -2.55 pm

time take to drive the theatre - 10 min

So the time taking is

2.55-0.10=2.45 pm

(Let's take 10 min =0.10)

Marcus start the yard work at -2.00 pm

So the time take - start time

2.45-2.00 pm

= 45 minutes

If Marcus take the yard work for 45 minutes he can make it on time for movie

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The required original number that June was thinking of is 36.

Let's assume the original number June was thinking of is represented by "x". According to the problem, June doubles the original number (2x) and adds 18 to get an answer of 90. We can write this as the equation:

\(2x + 18 = 90\)

To find the value of x, we need to isolate it on one side of the equation. Let's subtract 18 from both sides:

\(2x = 90 - 18 \\ 2x = 72\)

Now, we divide both sides of the equation by 2 to solve for x:

\(x = 72 / 2 \\ x = 36\)

Therefore, the original number that June was thinking of is 36.

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Answer:

9/10

Step-by-step explanation:

9 is in the tenth place so the denominator is 10.

Answer:

the answer is 9/10

The given cubic polynomial function, f(x) = -x^3 + 13x - 12, can be factored as (x + 4)(x - 3). The factored form of the polynomial allows us to determine its roots or x-intercepts, which are the values of x for which the function equals zero.

To factor the given cubic polynomial, we look for factors that, when multiplied together, give us the original polynomial. By factoring out common factors, if any, we can simplify the polynomial. In this case, after factoring, we obtain (x + 4)(x - 3).

To find the roots of the polynomial, we set each factor equal to zero and solve for x. Setting (x + 4) = 0 gives us x = -4, and setting (x - 3) = 0 gives us x = 3. Therefore, the roots or x-intercepts of the polynomial are x = -4 and x = 3.

By factoring the polynomial into (x + 4)(x - 3), we can easily identify the linear factors that contribute to the polynomial's behavior and determine its roots. This form provides valuable insights into the polynomial's properties and allows for further analysis and calculations.

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Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

From the figure attached,

CP is an angle bisector of angle BCD and BP is the angle bisector of angle CBE

Therefore, m∠DCP ≅ m∠BCP

and m∠PBE ≅ m∠PBC

m∠A + m∠CBA = m∠BCD

m∠A + (180° - m∠CBE) = m∠BCD

m∠A + 180° = m∠CBE + m∠BCD

m∠A + 180° = 2(m∠PCB) + 2(m∠PBC) [Since m∠CBE = 2m∠PCB and m∠BCD = 2(m∠PBC)

m∠A + 180° = 2(m∠PCB + m∠PBC)

m∠A + 180° = 2(180° - m∠BPC) [Since m∠PCB + m∠PBC + m∠BPC = 180°]

\([\frac{1}{2}(m\angle A)]+90=180 - m\angle BPC\)

m∠BPC = 180 - \([\frac{1}{2}(m\angle A)]-90\)

m∠BPC = 90 - \(\frac{1}{2}m\angle A\)

The five-number summary for the dataset are Minimum: 68, Q1: 69, Median: 78, Q3: 90 and Maximum: 94.

To create a box and whisker plot for the given dataset {69, 88, 94, 73, 78, 90, 68}, follow these steps:

Step 1: Arrange the data in ascending order:

68, 69, 73, 78, 88, 90, 94

Step 2: Find the five-number summary:

Minimum: The smallest value in the dataset, which is 68.

First quartile (Q1): The median of the lower half of the dataset. In this case, it's the median of {68, 69, 73}, which is 69.

Median (Q2): The middle value of the dataset. In this case, it's 78.

Third quartile (Q3): The median of the upper half of the dataset. In this case, it's the median of {88, 90, 94}, which is 90.

Maximum: The largest value in the dataset, which is 94.

Step 3: Create the box and whisker plot:

Draw a number line with a range from the minimum (68) to the maximum (94).

Mark the first quartile (Q1) at 69.

Mark the median (Q2) at 78.

Mark the third quartile (Q3) at 90.

Draw a box from Q1 to Q3.

Draw a vertical line (whisker) from the box to the minimum (68) and another vertical line from the box to the maximum (94).

The resulting box and whisker plot for the given dataset would look like this:

  |

 94|                 ▄

  |                ╱ ╲

 90|              ╱   ╲

  |             ╱     ╲

 88|            ▇       ▂

  |            ▇       ▂

 78|            ▇       ▂

  |            ▇       ▂

 73|          ╱         ╲

  |         ╱           ╲

 69|        ▃             ▃

  |       ╱               ╲

 68|      ╱                 ╲

  |_________________________________

    68     73     78     88     94

This plot represents the distribution of the given dataset, showing the minimum, maximum, first quartile (Q1), median (Q2), and third quartile (Q3).

The five-number summary for the dataset are Minimum: 68, Q1: 69, Median: 78, Q3: 90 and Maximum: 94.

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Check the picture below.

so the center of the circle is the midpoint of that diameter, and its radius is half its length.

\(~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{7}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 4 -2}{2}~~~ ,~~~ \cfrac{ 7 -1}{2} \right) \implies \left(\cfrac{ 2 }{2}~~~ ,~~~ \cfrac{ 6 }{2} \right)\implies \stackrel{ center }{(1~~,~~3)} \\\\[-0.35em] ~\dotfill\)

\(~~~~~~~~~~~~\textit{distance between 2 points} \\\\ r(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{7})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{ radius }{r}=\sqrt{(~~4 - (-2)~~)^2 + (~~7 - (-1)~~)^2} \implies r=\sqrt{(4 +2)^2 + (7 +1)^2} \\\\\\ r=\sqrt{( 6 )^2 + ( 8 )^2} \implies r=\sqrt{ 36 + 64 } \implies r=\sqrt{ 100 }\implies r=10 \\\\[-0.35em] ~\dotfill\)

\(\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{1}{h}~~,~~\underset{3}{k})}\qquad \stackrel{radius}{\underset{10}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - 1 ~~ )^2 ~~ + ~~ ( ~~ y-3 ~~ )^2~~ = ~~10^2\implies {\large \begin{array}{llll} (x-1)^2+(y-3)=100 \end{array}}\)

The minimum number of 2022 Veterans Day that would need to be selected for the sample is 38.

To calculate the minimum number of 2022 Veterans Day celebrations that would need to be selected for the sample to allow the calculation of a 98% confidence interval with a margin of error no larger than 8, we need to use the formula for the margin of error:

Margin of error = Z * (standard deviation / sqrt(n))

where Z is the Z-score corresponding to the level of confidence, standard deviation is the population standard deviation, and n is the sample size.

In this case, we want the margin of error to be no larger than 8, and we want a 98% confidence interval. The Z-score corresponding to a 98% confidence interval is approximately 2.33. The population standard deviation is given as 21.

Plugging these values into the formula and solving for n, we get:

8 = 2.33 * (21 / sqrt(n))

sqrt(n) = 2.33 * 21 / 8

sqrt(n) = 6.125

n = (6.125)^2

n = 37.515625

We need to round up to the next whole number, so the minimum number of 2022 Veterans Day celebrations that would need to be selected for the sample is 38.

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Answer:

Step-by-step explanation:

distance = rate of speed x amount of time traveled

This is often written D = R x T, or distance = rate x time

In this case D = (50 miles/hr) x (t hours), or D = 50 x T

The probability that both will be married before the age of 18 is 0.0036. The probability that both will be married by the age of 25 is 0.25. Finally, the probability that both will be married by the age of 30 is 0.5476.

According to the brief report by NCHS, approximately 6% of women in the United States married for the first time before their 18th birthday, and 50% of women married by their 25th birthday. 74% of women married by their 30th birthday.The probability of a family with two daughters marrying at different ages is asked in the question. The probability that both daughters will be married by the ages of 18, 25, and 30 will be determined

The question requires finding the probability that both daughters of a family will be married by the ages of 18, 25, and 30 respectively. Since each daughter's wedding is a separate event, the individual probability of a daughter marrying at a given age will be determined separately and then multiplied together to get the probability of both daughters being married at the given age. So, let's find the probabilities of each daughter marrying at a given age:

Probability of one daughter getting married by 18 years:

As per the brief report, 6% of women in the United States married before the age of 18.

Therefore, the probability of one daughter getting married before the age of 18 is 0.06

Probability of one daughter getting married by 25 years:

As per the brief report, 50% of women in the United States get married by the age of 25. Therefore, the probability of one daughter getting married by 25 years is 0.5.

Probability of one daughter getting married by 30 years:

As per the brief report, 74% of women in the United States get married by the age of 30. Therefore, the probability of one daughter getting married by 30 years is 0.74.

The probability of both daughters getting married at the same age is the product of each daughter's probability of getting married at that age.

The probability that both daughters will get married before the age of 18 is:

P(both daughters married at 18 years) = P(daughter1 married at 18) × P(daughter2 married at 18)= 0.06 × 0.06= 0.0036

The probability that both daughters will get married by the age of 25 is:

P(both daughters married at 25 years) = P(daughter1 married at 25) × P(daughter2 married at 25)= 0.5 × 0.5= 0.25

The probability that both daughters will get married by the age of 30 is:

P(both daughters married at 30 years) = P(daughter1 married at 30) × P(daughter2 married at 30)= 0.74 × 0.74= 0.5476

The probability that in a family with two daughters, both will be married before the age of 18 is 0.0036. The probability that both daughters will be married by the age of 25 is 0.25. Finally, the probability that both daughters will be married by the age of 30 is 0.5476.

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Answer:

15 minutes

Step-by-step explanation:

Divide 12 yards by 4/5 yards.

12 ÷ 4/5 =

12 * 5/4 =

15

Thus, it would take the ant 15 minutes to crawl 12 yards.

Answer:

12.04

Step-by-step explanation:

the distance between two points in the x-axis

15-3 = 12

the distance between two points in the y-axis

7-6=1

using Pythagorean theory

a²+b²=c²

12²+1²=c²

144+1=c²

145=c²

√145=√c²

12.04=c