The desired product will not form if a strong base is applied to the starting material right away in reaction 1. why does this synthetic route fail to product the desired alkene product?

Answer:

Warmer air can hold more water vapor than colder air.

Explanation:

Weather can be defined as the atmospheric conditions of a particular area over a short period of time.

The elements of weather include precipitation, wind, temperature, atmospheric pressure, relative humidity, cloud, and wind speed.

Temperature can be defined as a measure of the degree of coldness or hotness of a physical object (body).

On the other hand, humidity refers to the concentration (amount) of water vapor that is present in the air. It is high when there's a lot of water vapor in the air and low when the level of water vapor is small.

The relationship between air temperature and humidity is that warmer air can hold more water vapor than colder air because as the air cools, its molecules move closer together while the molecules move farther apart as the air become hot.

Additionally, at constant humidity, relative humidity is inversely proportional to temperature i.e as the temperature decreases, relative humidity increases.

In some plants such as Cactuses, the stem is flattened and green and carries out the function of the leaf. Such a stem, adapted for the manufacture of food is called phylloclade. The leaves here are reduced or modified into spines to lessen the transpiring surface.

Answer:

Atoms consist of a nucleus made of protons and neutrons orbited by electrons.

Isotopes are atoms that have same number of protons but they differ in the number of neutrons and in atomic mass.

Answer:

Isotopes are atoms that have the same numbers of protons but different numbers of neutrons. An ion is an atom that has gained or lost electrons, so it now has more or fewer electrons than it does protons. So an ion has a negative or positive charge.

Hope it helps :)

The number of moles of each reactant involved in the reaction are 1 mole of lead (II) nitrate and 2 moles of potassium iodide.

A chemical reaction is a process that transforms one or more chemicals into others by breaking or creating interatomic connections.

The following is how potassium nitrate and lead iodide mix to generate lead (II) nitrate and potassium nitrate:

Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃

One mole of lead nitrate and two moles of potassium iodide can produce 1 moles one mole lead(II) iodide and 2 moles of Potassium nitrate.

Therefore, the number of moles of each reactant involved in the reaction are 1 mole of lead (II) nitrate and 2 moles of potassium iodide.

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Reactions vs. Products Quick Check

1. The number of atoms of each element in the reactants is the same as the number of atoms of each element in the products.

2. 2 moles

3. H2SO4

4. 1 moles of lead (II) nitrate and 2 moles of potassium iodide

5. There will be 1 mole of silver (Ag) in the product.

Calculating Mass Quick Check

1. The mass of the reactants must be equal to the mass of the products. The total number of moles of the reactants can be more or less than the total number of moles of the products.

2. Divide the mass of the reactant by its molar mass to find the number of moles of the reactant. Use the chemical equation to find the number of moles of the product. Multiply the number of moles of the product by its molar mass to find the mass of the product.

3. 2(108 g/mol)+32 g/mol=248 g/mol; (248 g/mol)(0.02 mol)=4.96 g

4. 19.5 g

5. 853.5 g

Specific Mass Conversions Quick Check

1. It compares the mass of the products to the mass of the reactants.

2. For every 3 moles of hydrogen gas, the reaction produces 2 moles of ammonia.

3. 56

4. 32 g/mol

5. 4

Mass and Atoms Quick Check

1. It can be used to find the number of molecules, atoms, or ions.

2. Identify the molar masses of H and O.

3. 5 g×1 mol/17.03 g

4. 2.71×10^23

5. The sum of the mass of the Mg2+ ions and the mass of the Cl– ions must be equal to the mass of MgCl2.

Conservation of Mass Unit Test

1. Matter may be lost to or gained from the surroundings.

2. Yes, it supports the claim because the equation is balanced.

3. The bubbling indicates a gas was formed, so some atoms formed gas; therefore, mass was transferred to the atmosphere.

4. one-twelfth the mass of a neutral carbon atom.

5. Mass is conserved because the number of each atom in the reactants equals the number of each atom in the products.

6. 129.59 g/mol.

7. the number of atoms in the reactants.

8. 2Fe2O3

9. 112 g CaO and 88 g CO2

10. 274 g

11. For every 3 moles of carbon dioxide produced, 5 moles of oxygen react.

12. 96

13. 1.776 x 10^22

14. Short answer (don't plagiarize)

15. Short answer (please don't plagiarize)

16. Short answer (pretty please don't plagiarize)

Hope this helps. Like if this helped you.

Approximately 12.45 grams of solid silver chromate will precipitate when 150 mL of 0.500 M silver nitrate solution is added to excess potassium chromate.

To determine the number of moles of AgNO3 present in 150 mL of a 0.500 M AgNO3 solution, we can use the formula:

moles = concentration × volume

Given:

Concentration of AgNO3 solution = 0.500 M

Volume of AgNO3 solution = 150 mL

First, we need to convert the volume from milliliters (mL) to liters (L) since the concentration is given in moles per liter (M).

1 L = 1000 mL

Therefore, the volume of the AgNO3 solution in liters is:

150 mL × (1 L / 1000 mL) = 0.150 L

Now we can calculate the moles of AgNO3 using the formula:

moles = concentration × volume

moles = 0.500 M × 0.150 L

moles = 0.075 mol

So, there are 0.075 moles of AgNO3 present in 150 mL of the 0.500 M AgNO3 solution.

Now, let's proceed to determine how many grams of solid silver chromate (Ag2CrO4) will precipitate when the AgNO3 solution reacts with excess potassium chromate (K2CrO4).

From the balanced chemical equation:

2AgNO3(aq) + K2CrO4(aq) → Ag2CrO4(s) + 2KNO3(aq)

We can see that the molar ratio between AgNO3 and Ag2CrO4 is 2:1. Therefore, for every 2 moles of AgNO3, we will form 1 mole of Ag2CrO4.

Since we have 0.075 moles of AgNO3, we can calculate the moles of Ag2CrO4 formed:

moles of Ag2CrO4 = 0.075 mol / 2 = 0.0375 mol

To determine the mass of Ag2CrO4, we need to multiply the moles by its molar mass. The molar mass of Ag2CrO4 is calculated by summing the atomic masses of each element in the compound:

Ag2CrO4 = 2(Ag) + 1(Cr) + 4(O) = 2(107.87 g/mol) + 1(52.00 g/mol) + 4(16.00 g/mol) = 331.87 g/mol

mass of Ag2CrO4 = moles of Ag2CrO4 × molar mass of Ag2CrO4

mass of Ag2CrO4 = 0.0375 mol × 331.87 g/mol = 12.45 g

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Answer:

erythrocytes, leukocytes, platelets

The grams of SO₂ that would be dissolved in 100 g of 40 degree water to make a saturated solution can be calculated by making solubility curve.

Mass is the quantity of matter of a physical body.

If you want to calculate the mass of Sulfur dioxide in 100 g of 40 degree, you have to make a solution curve.

With the increase in temperature, the solubility increases as well

Thus, the grams of SO₂ that would be dissolved in 100 g of 40 degree water to make a saturated solution can be calculated by making a solubility curve.

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Answer:

In physics and chemistry, ionization energy or ionisation energy, is the minimum amount of energy required to remove the most loosely bound electron of an isolated neutral gaseous atom or molecule.

I hoped this helped :D

Explanation:

Explanation:

A single replacement reaction is defined as a chemical reaction where one element replaces another element in one compound. The shape of this kind of reaction is:

A + BC ----> AB + C

If we consider our options, they are all double replacement reaction except from:

Zn (s) + H₂SO₄ (aq) ----> ZnSO₄ (aq) + H₂ (g)

Where zinc is replacing hydrogen in sulfuric acid.

Answer: C) Zn (s) + H₂SO₄ (aq) ----> ZnSO₄ (aq) + H₂ (g)

ANSWER

All reactants

OPTION D

STEP-BY-STEP EXPLANATION:

Firstly, you need to know the meaning of the solution

Solution: Solution is defined as a homogenous mixture of two or more components in which particle size is smaller than 1nm.

Solution = solute + solvent

The solute is a substance that is dissolved in the solvent.

An aqueous solution is defined as a solution in which its solvent is water

As you can see from the above-balanced chemical equation, the solutions in the reaction have a subscript (aq) attached to them.

Also, from the reaction, the compounds that are in reactions are the reactants only which are HClO (aq) and HCl (aq)

Hence, the answer is all reactants -------- OPTION D

In the experiment, sodium bisulfite (NaHSO3) in water is used to destroy any unreacted bromine (Br2) or to trap the Br2 and not allow it to escape from the reaction setup. The reaction is shown below but cannot be described using conventional organic curved-arrow pushing.

The resulting mixture is placed in acid waste for the following reasons:

Sodium bisulfite's addition to the reaction mix in the procedure is done to destroy any unreacted bromine (Br2) or to trap the Br2 and prevent it from escaping the reaction setup. Following the reaction, it is necessary to neutralize the mixture with sodium carbonate or another base. After that, the neutralized mixture should be properly disposed of in an acid waste container. Thus, the resulting mixture is placed in acid waste.

Sodium bisulfite is used in excess to the amount of bromine to ensure that all of the bromine is captured or reacted. The resulting mixture is extremely acidic as a result of the reaction. As a result, the mixture must be neutralized before being disposed of.

The most straightforward approach to neutralizing it is to add a basic substance like sodium carbonate, which reacts with the acidic mixture to create water and sodium sulfate (Na2SO4).

As a result, when sodium bisulfite is added in the procedure, the resulting mixture is put into acid waste.

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Answer:

N,I and F

hope this helps

Explanation:

Arrhenius :

acid: a compound that releases H⁺ ions in water

base: a compound that releases OH⁻ ions in water

H2S Arrhenius acid

RbOH Arrhenius base.

Mg(OH)2  Arrhenius base.

H3PO4 Arrhenius acid

First of all, Z is unknown. I hope it is a mistake.

        Now, it is given that the element X has nineteen electrons. This proves that X is actually Potassium.

        As per the periodic table, both Potassium and Lithium belongs to group 1 as their valency is 1 because of the presence of only one electron in the outermost shell of electrons i.e., they lose an electron during a chemical reaction to form a stable compound. Furthermore, both are metallic.

        Magnesium belongs to group 2 and hence its valency is two, which is different from potassium though it is metallic. Similiarly, bromine belongs to group 17 and gains one electron during a reaction in contrast to potassium.

( No internal links available for reference. For clarification, check the periodic table).

Answer:

C₂H6

Explanation:

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A

A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:

A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.

B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.

D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.

In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A

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The atomic theory have been developed over the years by the works of many scientists.

The atomic theory is the series of postulations that sought to explain the behavior of the atom. The study of the atom started as far back as the time of Democritus and Aristotle.

The first empirical study of the nature of the atom started with the work of John Dalton when he proposed the famous Dalton's theory. Further empirical work was carried out by J.J Thompson which gave rise to the plum pudding model of the atoms.

The work of Ernest Rutherford introduced the planetary model of the atom which was latter replaced by the Bohr model based on energy levels. Today, the work of Erwin Schrödinger has led us to the appreciation of the wave mechanical model of the atoms which is the mot accepted model for the atom today.

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Answer:

About $5.65x10^15 or $5,650,000,000,000,000

Explanation:

Given:

Volume of seawater: 2.3 mL

Grams of gold: 4.0 x 10^-10

Total volume of the ocean: 1.5 x 10^21

Price of gold: $21.66/g

Need:

1000 mL = 1 L

Find:

Dollar worth of all the gold in the world's oceans

Steps:

1. We know that there is 4.0 x 10^10 g of gold in 2.3 mL of seawater, therefore we can write it like this:

2. In order to find the amount of gold in the entire ocean we need to cancel out the 2.3 mL of seawater on the bottom. To do this we will use the volume of the entire ocean (1.5 x 10^21 L). Before we plug it into the equation, we have to match the units of the mL and the L. We will use the 1000mL = 1 L to accomplish this. The formula should now look like this:

\(\frac{4.0*10^{-10}g }{2.3mL} \frac{1000mL}{1L} \frac{1.5*10^{21}L}{1}\)

3. Solve the equation to find the amount of gold in all the oceans:

\(\frac{4.0*10^{-10}g }{2.3mL} \frac{1000mL}{1L} \frac{1.5*10^{21}L}{1} = 2.61 x 10^{14} g\)

4. Now since we found the amount of gold in all the oceans we can use this to find the total worth of all of it. We can do this by multiplying all the grams of the gold by the price of gold per gram. It can be represented like this:

\(\frac{21.66 dollars}{1 gram} \frac{2.61*10^{14}g }{1}\)

5. Get the answer:

\(\frac{21.66 dollars}{1 gram} \frac{2.61*10^{14}g }{1} = 5.65 x 10 ^ {15}dollars\)

There ya go!

1) List the values we have.

Normal solution = 0.009 g/mL NaCl

Volume =3.5 L

Grams of NaCl = ?

2) Set the equation

3) Convert L into mL

4) Replace know values

Grams of NaCl = 0.009g/mL*3500 mL= 31.5 g of NaCl.

To form a dipeptide between Alanine and Leucine, we have to join the carboxyl group (COOH) of Alanine with the amino group (NH₂) of Leucine via a peptide bond. The resulting molecule will have a zwitterionic form. The zwitterionic form of the dipeptide will have both a positive and a negative charge.

A dipeptide is a molecule made up of two amino acid residues joined together via a peptide bond. A peptide bond is a bond between the amino group (NH₂) of one amino acid and the carboxyl group (COOH) of another amino acid. Amino acids are the building blocks of proteins. Alanine and Leucine are two of the twenty common amino acids found in nature.

A zwitterion is a molecule that has a positive charge on one part of the molecule and a negative charge on another part of the molecule. Zwitterions are electrically neutral overall. They are formed when a molecule that has both acidic and basic functional groups is dissolved in a solvent. The acidic and basic groups react with each other to form a neutral molecule that has both positive and negative charges. The zwitterionic form of an amino acid is the form that is found in proteins.

The chemical formula for Alanine is C₃H₇NO₂, and the chemical formula for Leucine is C₆H₁₃NO₂. To form a dipeptide between Alanine and Leucine, we have to join the carboxyl group (COOH) of Alanine with the amino group (NH₂) of Leucine via a peptide bond. The resulting molecule will have a zwitterionic form. The zwitterionic form of the dipeptide will have both a positive and a negative charge.

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Hydrogen can be expected to escape significantly faster rate than sulfur dioxide through a porous container due to its smaller molecular size.

The rate at which a gas escapes through a porous container depends on several factors, including the size of the gas molecules and the size of the pores in the container. Generally, smaller gas molecules can escape more quickly through smaller pores.

Hydrogen has a smaller molecular size compared to sulfur dioxide . The molecular weight of hydrogen is 2 g/mol, while the molecular weight of sulfur dioxide is 64 g/mol. Due to its smaller size, hydrogen molecules can pass through smaller pores more easily than sulfur dioxide molecules.

The exact ratio of how much faster hydrogen escapes compared to sulfur dioxide would depend on the specific conditions and the properties of the porous container.

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Nitinol, a shape memory alloy, is unique in its response to temperature compared to other metals.

Nitinol is composed of a nickel-titanium (Ni-Ti) alloy and exhibits a phenomenon called shape memory effect and superelasticity. These properties arise from the unique crystal structure and phase transitions of the alloy.

One key characteristic of Nitinol is its ability to undergo a reversible transformation between two crystal structures, known as austenite and martensite, in response to temperature changes. The transition temperature at which this transformation occurs is called the martensitic transformation temperature.

At temperatures below its martensitic transformation temperature, Nitinol exhibits a soft and easily deformable martensitic phase. However, when heated above its transformation temperature, Nitinol rapidly reverts to its rigid and predefined shape of the austenitic phase.

This temperature-dependent behavior of Nitinol is in contrast to other metals that do not exhibit such reversible shape memory effects or superelasticity. While most metals undergo gradual changes in their physical properties with temperature, Nitinol's unique alloy composition allows it to exhibit significant and reversible changes in shape and mechanical properties based on temperature fluctuations.

The distinct response of Nitinol to temperature makes it a valuable material in various applications, including biomedical devices, aerospace engineering, and robotics.

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a. The chemical formula for this hydrate is determined by comparing the change in mass before and after heating. The initial mass of the hydrated salt (0.821 g) minus the mass of the dried salt (0.448 g) gives the mass of water lost during heating, which is 0.373 g. To find the molar ratio between the anhydrous salt and water, we divide the mass of the anhydrous salt by its molar mass (NiCl2).

Assuming all the water is lost and the anhydrous salt is left, the molar mass of NiCl2 is 129.6 g/mol. So, (0.448 g / 129.6 g/mol) gives us the number of moles of NiCl2.

Using the molar ratio between the anhydrous salt and water, we can determine the number of moles of water lost during heating, which is (0.373 g / 18.02 g/mol). Simplifying the ratio between the anhydrous salt and water gives us the chemical formula for this hydrate, which is NiCl2 · 6H2O.

b. The IUPAC name for this hydrate is determined based on the number of water molecules associated with the anhydrous salt. In this case, since there are 6 water molecules attached to each NiCl2, the IUPAC name for this hydrate is nickel(II) chloride hexahydrate.

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Acetanilide has a higher ratio of polar surface area (SA) to total SA compared to trans-cinnamic acid, which allows it to form stronger interactions with water molecules and be more soluble.

Acetanilide and trans-cinnamic acid have different solubility behaviors in warm water due to their molecular structures and the relative ratios of their polar surface area (SA) to total SA.

Acetanilide contains an amide functional group (-CONH2), which contributes to its polar nature. The amide group has a partial positive charge on the carbon and a partial negative charge on the oxygen and nitrogen atoms. This polar group increases the ratio of polar SA to total SA in acetanilide, allowing it to form stronger hydrogen bonds and interact more favorably with water molecules, making it soluble in warm water. On the other hand, trans-cinnamic acid contains a carboxylic acid functional group (-COOH), which is also polar but to a lesser extent compared to the amide group. The lower polar SA to total SA ratio in trans-cinnamic acid results in weaker interactions with water molecules, leading to lower solubility in warm water.

Thus, the differences in the ratios of polar SA to total SA between acetanilide and trans-cinnamic acid explain their contrasting solubility behaviors in warm water.

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The correct coefficients for the equation D + Cl\(_2\)→ DCl\(_3\) is 2,3,2. the correct option is option A.

The balanced equation is indeed a chemical reaction equation in which the overall charge and the amount of atoms for every element inside the reaction are identical for both the products and the reactants.

In those other words, both mass as well as the charge were balanced on the both sides of something like the reaction.

D + Cl\(_2\)→ DCl\(_3\)

The atom of chlorine on left is 2 while on right side, it is 3

2D +3 Cl\(_2\)→2 DCl\(_3\)

Therefore, the correct coefficients for the equation D + Cl\(_2\)→ DCl\(_3\) is 2,3,2. the correct option is option A.

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Aqueous Solution - The expected precipitate would consist of Cu(OH)2.

What is aqueous solution?

An aqueous solution is one in which water serves as the solvent. Chemical equations typically illustrate it by adding (aq) to the appropriate chemical formula. For instance, Na+(aq) + Cl would be used to represent a solution of table salt, as well as sodium chloride (NaCl), throughout water (aq). The word aqueous, which derives from the word aqua, means that it is dissolved in or related to water. Water is a common solvent in chemistry due to its superior solvent properties and natural abundance. Since water is frequently used as a solvent in experiments, unless the solvent is specified, the word "solution" refers to an aqueous solution. A solution wherein the solvent is a liquid but not water is referred to as a non-aqueous solution.

Because:

salt:    copper(II) hydroxide
Ksp:    1.8 × 10-19

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Answer:

Explanation:

A .

Answer: The ratio of carbon dioxide molecules to oxygen molecules is 20 :31

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced combustion reaction is,:

\(2C_{10}H_{22}(l)+31O_2(g)\rightarrow 20CO_2(g)+22H_2O(g)\)

Thus the ratio of carbon dioxide molecules to oxygen molecules is 20 : 31

To determine the empirical formula and molecular formula of the compound, we first need to find the molar ratios of carbon and hydrogen.

Step 1: Calculate the moles of carbon and hydrogen.

Moles of carbon = mass of carbon / molar mass of carbon

Moles of carbon = 7.99 g / 12.01 g/mol

Moles of carbon = 0.665 mol

Moles of hydrogen = mass of hydrogen / molar mass of hydrogen

Moles of hydrogen = 2.01 g / 1.008 g/mol

Moles of hydrogen = 1.996 mol

Step 2: Divide the moles by the smallest mole value.

Dividing both moles by 0.665 (smallest mole value), we get approximately:

Carbon: 0.665 mol / 0.665 = 1 mol

Hydrogen: 1.996 mol / 0.665 = 3 mol

Step 3: Determine the empirical formula.

Based on the molar ratios, the empirical formula is CH3.

Step 4: Calculate the empirical formula mass.

Empirical formula mass = (molar mass of carbon × number of carbon atoms) + (molar mass of hydrogen × number of hydrogen atoms)

Empirical formula mass = (12.01 g/mol × 1) + (1.008 g/mol × 3)

Empirical formula mass = 12.01 g/mol + 3.024 g/mol

Empirical formula mass = 15.034 g/mol

Step 5: Calculate the ratio of the molar mass of the compound to the empirical formula mass.

Ratio = molar mass of the compound / empirical formula mass

Ratio = 30.07 g/mol / 15.034 g/mol

Ratio = 2

Step 6: Multiply the subscripts in the empirical formula by the ratio calculated in Step 5 to obtain the molecular formula.

Molecular formula = (C1H3) × 2

Molecular formula = C2H6

Therefore, the empirical formula of the compound is CH3, and the molecular formula is C2H6.

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he specific heat of a 26 grams sample of metal at 82.25 degrees is 0.971 J/g°C.

Given that

Initial temperature of liquid water = 24.0°C

Final temperature of water = 28.34°C

Final temperature of metal = 28.34°C

Mass of water = 75.0 grams

Mass of metal = 26.0 grams

Specific heat capacity of water = 4.18 J/g°C

To find the specific heat of the metal:

Mathematically, heat capacity or quantity of heat is given by the formula;

Where:

Q represents the quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity.

∅ represents the change in temperature.

Heat lost by water = Heat gained by metal.

75 ( 4.18) ( 28.34 - 24) = 26c (82.25 - 28.34)

313.5 ( 4.34) = 26 ( 53.91) c

1360.59 = 1401.66 c

c = 1360.59 / 1401.66

Specific heat of metal, c = 0.971 J/g°C.

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Answer:

yep

Explanation:

yes it is