the chemical symbol for phosphorus is
A po
B p
C pt
D k​

Washing soda, Na2CO3·10H2O, has a molar mass of 286 g/mol. Anhydrous sodium carbonate, Na2CO3, has a molar mass of 106 g/mol.Cost per mole of washing soda = Rs 40 / (286/1000) = Rs 140.06 per moleCost per mole of anhydrous Na2CO3 = Rs 100 / (106/1000) = Rs 943.40 per mole

Therefore, the cost per mole of washing soda is less than that of anhydrous Na2CO3.

As a result, washing soda is less expensive to purchase than anhydrous Na2CO3.

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When talking about a column of the periodic table the word we use is (B). Group

A group in a periodic table is a column in the periodic table of chemical elements.

In a group, all the chemical elements have similar properties which include; atoms of the same vacancy in valence and valence electron.

Groups have similar physical  and chemical properties.

Groups in a periodic table are numbered from number 1 to number 8, and it is numbered from the left to the right side of the periodic table.

In conclusion, When talking about a column of the periodic table the word we use is Group

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The reduction of the ketone in D would yield 2-methyl-3 pentanol

When hydrogen (H2) is added to the aldehyde functional group during the reduction of an aldehyde to an alkanol, an alcohol is created.

Normally, a reducing agent like sodium borohydride (NaBH4) or lithium aluminum hydride (LiAlH4) is used to carry out this reduction reaction. The carbonyl group (C=O) in the aldehyde can be changed into a hydroxyl group (C-OH) by these reducing agents by donating hydride ions (H).

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Out of the chemicals listed, the only one that is considered an irritant is A. HCI. HCI, or hydrochloric acid, is a strong acid that can cause irritation and burns if it comes into contact with the skin or eyes.

NaHCO3, or sodium bicarbonate, is a mild alkaline compound commonly used in baking and is not typically considered an irritant. T-pentyl chloride is a type of organic compound that can be harmful if ingested or inhaled but is not necessarily considered an irritant. Therefore, the correct answer to the question is A.

HCI. It's important to handle all chemicals with caution and to be aware of their potential hazards and safety guidelines when working with them, especially when handling substances.

Among the chemicals listed, A. HCl (hydrochloric acid) is considered an irritant. When in contact with skin, eyes, or respiratory system, HCl can cause irritation, burns, or other harmful effects. The other chemicals, B. NaHCO3 (sodium bicarbonate) and C. t-pentyl chloride, are not considered irritants in the same way. Sodium bicarbonate is a mild alkali used in various applications, including baking and antacids, while t-pentyl chloride is an organic compound used as a reagent in laboratories. Thus, the correct answer to your question is A. HCl.

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Answer: Scientific reasoning

Explanation:

A scientific reasoning can be defined as the justification which connects the evidence with that of the claim and it rules out all those claims that are not supported by any evidence. It explains the fact that how evidence can support a claim and scientifically acceptable conclusion can be drawn. An argument is always based on one or more claims which can either be true or evidentially proved.

Answer:

Evaporation

Explanation:

because the ammonia is left unclosed

The smell of ammonia has been spread from a corner to entire room by the process of diffusion. Thus, option B is correct.

Ammonia has been the liquid compound with the formula \(\rm NH_4\). It has a pungent smell. Ammonia has been used in several synthesis reactions, and in various industrial processes.

The diffusion has been the process of transfer of molecules from higher concentration to lower concentration. The smell of ammonia has been spread in the entire laboratory from a corner.

The ammonia molecules in the bottle are at higher concentration while there has been lower concentration of ammonia in the environment. With the process of diffusion there has been the transfer of ammonia molecules in the environment.

Thus, diffusion has been responsible for spreading the smell of ammonia in the laboratory from a corner. Thus, option B is correct.

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Answer:

6 gallons of gasoline for $14.45 is the best price

Explanation:

26.29/11=2.39 $ per gallon

14.45/11=1.31 $ per gallon

Answer:

I believe the answer is A. Have a good day :)

Explanation:

Answer:There is colder and drier air coming

Explanation:

Answer:

Cold fronts generally move from northwest to southeast. The air behind a cold front is noticeably colder and drier than the air ahead of it. When a cold front passes through, temperatures can drop more than 15 degrees within the first hour.

Explanation:

Based on the information provided, it is not possible to fill in the blanks with certainty. In order to complete the sentence, Effective collisions are those collisions in which the reactant molecules collide with enough energy.

In general, the frequency of collision between reacting particles can have a significant impact on the rate of a chemical reaction. As the frequency of collision increases, there is a greater likelihood that reactant molecules will collide with sufficient energy and proper orientation to result in a chemical reaction. This can lead to an increase in the rate of the reaction.However, it is also important to note that factors such as temperature, concentration, and the presence of catalysts can also affect the rate of a chemical reaction. Therefore, a more specific description of the conditions of the reaction is needed to accurately complete the sentence.

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Answer:

A. prokaryotic cell

Explanation:

We can easily identify the diagram as prokaryotic cell by the capsule shown. These organisms mostly have capsules.

The diagram that shows what has occurred is diagram D

If a substance changes color during the reaction, it can be a sign that a chemical change has occurred.

We can see from the image that we have been told that there is change in the color of the system and then when that happens, it would be clear that the molecules in the reactants must have stick together so that we can have the products of the reaction as shown.

Thus the image that shows a chemical reaction is image D

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Answer:

In terms of heat transfer,radiation is the emission of thermal energy in the form of infrared waves,

Answer:

Preparation and Standardization of 0.1 M Ferrous Ammonium...

Dissolve 40 g of ferrous ammonium sulfate in a previously cooled mixture of 40 ml of sulphuric acid and 200 ml of water.

Dilute with sufficient freshly boiled and cooled water to produce 1000 ml.

Standardize the solution in the following manner.

Explanation:

Therefore, the mass fraction of calcium bicarbonate is 16.2%.

Calcium bicarbonate, which is represented by the formula Ca(HCO3)2, is a white crystalline powder that is highly soluble in water. When dissolved in water, calcium bicarbonate produces a weakly alkaline solution.

The solubility of this salt in water is increased by increasing the pressure. The hardness of the water is measured in mg/L as CaCO3, and in this case, it is measured to be 162 mg/L.

The molar concentration of HCO3- ions is calculated using the following formula:

Molarity = (mg/L × 1000)/(MW × V)

Lets substitute the given values in the above equation and calculate the molar concentration of HCO3- ions.

Molarity = (162 mg/L × 1000)/(162.11 g/mol × 1 L)

Molarity = 0.999 M

Consequently, the molar concentration of HCO3- ions in the water is 0.999 M.

The normality of Ca2+ ions is given by the formula:

Normality = Molarity × Equivalence factor

Since the equivalence factor of Ca2+ is 2,

let's substitute the above value and calculate the normality of Ca2+ ions.

Normality = 0.999 M × 2

Normality = 1.998 N

Thus, the normality of Ca2+ ions is 1.998 N.

The mass fraction of calcium bicarbonate is calculated as follows:

Mass fraction = (Mass of Ca(HCO3)2 in 100 g of water) × 100%

Let's substitute the given values and calculate the mass fraction of calcium bicarbonate.

Mass of Ca(HCO3)2 in 100 g of water = (162 mg/L × 100 g)/1000 g

Mass of Ca(HCO3)2 in 100 g of water = 16.2 g/100 g of water

Now, substituting the above value in the formula for mass fraction,

Mass fraction = (16.2 g/100 g of water) × 100%

Mass fraction = 16.2%.

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A company that is trying to gain competitive advantage over a company in their same industry is most likely going to refer to the Porter's Five Forces strategic model.

Porter's Five Forces strategic model, developed by Michael E. Porter, is a widely used framework to analyze an industry's competitive landscape. It consists of five forces: the threat of new entrants, the bargaining power of suppliers, the bargaining power of buyers, the threat of substitute products or services, and the intensity of competitive rivalry.

By understanding and addressing these forces, a company can develop effective strategies to position itself favorably within the industry. This model helps organizations identify potential opportunities and weaknesses, enabling them to take actions to improve their competitive position and outperform their rivals. Overall, Porter's Five Forces is a valuable tool for companies aiming to achieve a competitive advantage in their industry.

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When pyruvate is converted to acetyl CoA in the link reaction each pyruvate molecule loses one carbon atom with the release of carbon dioxide.

In the link reaction, each pyruvate molecule loses one carbon atom in the form of carbon dioxide during the conversion to acetyl CoA. This decarboxylation step is a key part of the process.

The steps involved:

1. Transport into the mitochondria: Pyruvate molecules generated from glycolysis in the cytoplasm are transported into the mitochondrial matrix.

2. Decarboxylation: Within the mitochondrial matrix, each pyruvate molecule undergoes decarboxylation, resulting in the removal of a carboxyl group (-COOH) from pyruvate. This process releases one molecule of carbon dioxide (CO₂) as a by product.

3. Formation of acetyl CoA: The remaining two-carbon fragment combines with coenzyme A (CoA) to form acetyl CoA. Coenzyme A acts as a carrier molecule for the acetyl group. The reaction is catalyzed by the enzyme pyruvate dehydrogenase complex.

Therefore, during the link reaction, pyruvate loses one carbon atom in the form of carbon dioxide (CO₂) through decarboxylation, and the remaining two-carbon fragment combines with coenzyme A (CoA) to form acetyl CoA. This process is essential for connecting glycolysis and the citric acid cycle in cellular respiration and plays a vital role in energy production.

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Answer:

x = 25.02 or 25°c

Explanation:

Given:

mass of water : 7.50×10² =750 gm

Ccal = 8.20× 10² = 820 J/°c

Let assume final temp = x°c

then, heat gained by the water + heat gained by calorimeter

= 25400 J

⇒ Mw × Cw× ΔTw+ Ccal ×ΔT = 25400

⇒ 750× 4.184 × (x - 18.6) + 820 ×(x-18.6) = 25400

⇒ x = 25.02 or 25°c

Answer:

Like about 5-6 days in the fridge.

Explanation:

Gasohol is a blend of gasoline and ethanol. To determine the maximum work that can be obtained by burning 1.003 mol of C2H5OH at 25°C and 1 atm, the Gibbs free energy equation can be utilized. What is Gibbs free energy equation? Gibbs free energy equation is a thermodynamic equation that quantifies the maximum quantity of work that may be obtained during a chemical reaction. T

he equation is as follows: ΔG = ΔH - TΔSThe values of ΔH and ΔS are calculated from thermodynamic tables or by calculating the enthalpy and entropy of the products and reactants, and the temperature, T, is usually specified in Kelvin. The change in Gibbs free energy, ΔG, is the maximum amount of energy that can be obtained from the reaction in the form of useful work if the reaction takes place at constant pressure and temperature. The reaction will proceed spontaneously if ΔG is negative. And if ΔG is positive, the reaction will not take place spontaneously. The solution to this problem is shown below:

First, let's figure out how much heat is produced when one mole of C2H5OH is burnt.ΔHrxn = [2(moles of CO2)(-393.5 kJ/mol) + 3(moles of H2O)(-285.8 kJ/mol)] - [(moles of C2H5OH)(-277.7 kJ/mol)]ΔHrxn = [2(2.006 mol)(-393.5 kJ/mol) + 3(3.009 mol)(-285.8 kJ/mol)] - [1.003 mol(-277.7 kJ/mol)]ΔHrxn = -2043.5 kJ/mol. Now, we'll figure out the entropy change for the reaction.ΔSrxn = [2(moles of CO2)(213.8 J/mol-K) + 3(moles of H2O)(69.9 J/mol-K)] - [(moles of C2H5OH)(160.7 J/mol-K)]ΔSrxn = [2(2.006 mol)(213.8 J/mol-K) + 3(3.009 mol)(69.9 J/mol-K)] - [1.003 mol(160.7 J/mol-K)]ΔSrxn = -104.3 J/mol-KThe temperature in Kelvin is 25°C.273 + 25 = 298 KΔG = ΔH - TΔSΔG = -2043.5 kJ/mol - (298 K)(-104.3 J/mol-K)/1000ΔG = -2032.6 kJ/mol. Therefore, the maximum work that can be obtained by burning 1.003 mol of C2H5OH is 2032.6 kJ/mol, which is the value of ΔG.

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Answer:

yes it is balanced equation

hope it helps

and your day will be full of happiness

Answer:

1 × 10²⁴ atoms O

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

30 g O

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of O - 16.00 g/mol

Step 3: Convert

\(30 \ g \ O(\frac{1 \ mol \ O}{16.00 \ g \ O} )(\frac{6.022 \cdot 10^{23} \ atoms \ O}{1 \ mol \ O} )\) = 1.12913 × 10²⁴ atoms O

Step 4: Check

We are given 1 sig fig. Follow sig fig rules and round.

1.12913 × 10²⁴ atoms O ≈ 1 × 10²⁴ atoms O

The notation for the enthalpy of the solution is ∆Hsol. The correct answer is option ∆Hsol.

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Answer:

55

Explanation:

According to the law of conservation properties of Matter in a closed system the mass of reactants is equal to the mass of products. Because there is no lose of matter or energy in closed system

Mass of tin = moles of tin x molar mass of tin

Mass of tin = 0.020 mol x 118.7 g/mol

Mass of tin = 2.37 g

Therefore, the mass of tin in the chemical reaction is 2.37 g.

If tin is heated, it cracks. This is caused by crystals rubbing against each other. This characteristic crackle is heard if a piece of tin is simply bent. Tin is very malleable and ductile.

Some properties of tin is that it amphoteric. On reacting with both strong bases and strong acids with the evolution of hydrogen occurs. With sodium hydroxide solution, tin forms Na2[Sn(OH)6]. The reaction with acids is slow in the absence of oxygen.

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One example of two organisms and their adaptations are the polar bear and the arctic fox, both of which inhabit the harsh, icy environment of the Arctic.

The polar bear has a thick layer of insulating fur, which helps it retain body heat in the cold temperatures. It also has large paws that act like snowshoes, allowing it to move over snow and ice more easily.

The polar bear's sense of smell is also highly developed, allowing it to detect prey from far distances. These adaptations help the polar bear survive in its cold, snowy habitat by keeping it warm and aiding in its ability to hunt for food.

The arctic fox also has several adaptations that allow it to survive in the Arctic. Its fur changes color from brown in the summer to white in the winter, providing camouflage against the snow. The fox's paws are covered in fur to provide insulation and better traction on the slippery ice.

The fox's diet is also highly adaptable, allowing it to survive on a variety of prey, from lemmings to birds to fish. These adaptations help the arctic fox survive in the harsh Arctic environment by helping it blend in, move more efficiently, and find food.

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