The black hole in the galaxy M87 has a mass of about 3 billion solar masses. Let us assume that most of that mass flowed into the black hole through an acretion disk that radiated 10% of the mass-energy passing through it. (a) In that case, what would be the total amount of energy radiated by the accretion disk during the history of the black hole? (b) What would be the average luminosity (in solar luminosities) of the accretion disk, if it that energy over a period of 10 billion years? (c) How does that average huminosity compare with the luminosity of the Milky Way?

Since the lift force must act vertically upward, we can conclude that the lift force created by the propellers is acting vertically upward.

Since the helicopter is flying horizontally at a constant speed, we know that the net force acting on it must be zero.

The weight of the helicopter can be calculated as :

weight = mass x gravity

weight = 2750 kg x 9.81 m/s²

weight = 26977.5 N

Since the net force acting on the helicopter is zero, we can write:

forward force - backward force + lift force + weight = 0

Substituting the given values, we get

forward force - 7510 N + lift force + 26977.5 N = 0

Simplifying the equation, we get:

forward force + lift force = 7510 N - 26977.5 N

forward force + lift force = -19467.5 N

Since the helicopter is flying at a constant speed, we know that the forward force created by the propellers must be equal in magnitude to 7510 N. Therefore, we can write:

7510 N + lift force = -19467.5 N

Solving for the lift force, we ge:

lift force = -26977.5 N

Since the lift force must act vertically upward, we can conclude that the lift force created by the propellers is acting vertically upward.

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Answer:kinetic energy

Explanation:

Answer:

it depends on the wind and any other conditions but if you have a controlled environment it should take 1 second to get 40 meters but it could go higher in which it could take about 5 seconds to go 200 meters

Explanation:

hope it helped

:)

Answer:

25.5 pounds per square inch are equivalent to 1.735 atmospheres.

Explanation:

An atmosphere equals 14.695 pounds per square inch. We find the equivalent of given pressure in atmospheres by means of simple rule of three:

\(x = 25.5\,\frac{lb}{in^{2}} \times \frac{1\,atm}{14.695\,\frac{lb}{in^{2}} }\)

\(x = 1.735\,atm\)

25.5 pounds per square inch are equivalent to 1.735 atmospheres.

Answer:

Explanation:

The speed in meters per second is ...

  (90 km/h)(1000 m/km)(1 h/(3600 s)) = 25 m/s

The braking acceleration can be found from ...

  a = v²/(2d) = (25 m/s)²/(2×50 m) = 6.25 m/s²

Then the braking force is ...

  F = Ma = (1800 kg)(6.25 m/s²) = 11,250 N

The torque on the center of gravity is ...

  T = (11,250 N)(0.90 m) = 10,125 N·m

__

If we let x and y represent the normal forces on the front and rear wheels, respectively, then we have ...

  x + y = (10 m/s²)(1800 kg) = 18000 . . . . . newtons

  1.7x -1.3y = 10,125 . . . . . . . . . . . . . . . . . . . newton-meters

The latter equation balances the torque due to the wheel normal forces with the torque due to braking forces.

Multiplying the first equation by 1.3 and adding that to the second, we have ...

  3.0x = (1.3)(18,000) + 10,125

  x = 33,525/3 = 11,175 . . . . . . . . . . . newtons normal force on front tyres

  y = 18000 -11175 = 6,825 . . . . . . . .newtons normal force on back tyres

The least coefficient of friction is the ratio of horizontal to vertical acceleration, 6.25/10 = 0.625.

Answer:

Distance = 13.9 meters

Explanation:

Given the following data;

Maximum speed = 150 km/hr to meters per seconds = 150 * 1000/3600 = 41.67 m/s

Decelerating speed = 3m/s

To find the distance travelled with this speed;

Distance = maximum speed/decelerating speed

Distance = 41.67/3

Distance = 13.9 meters

Therefore, the bus would travel a distance of 13.9 meters before stopping.

Time period of a wave is the inverse of its frequency. The period of the wave with a frequency of 2.09 Hz is 0.47 seconds.

Frequency of a wave is the number of wave cycles per unit time. Frequency is the inverse of the time period of the wave. Hence, it has the unit of s⁻¹ which is equivalent to Hz.

The higher frequency of a wave indicates more number of wave cycles in a short time. Frequency is directly proportional to the energy and inversely proportional to the  wavelength.

Given the time period of the wave = 2.09 Hz

then frequency = 1/2.09 Hz = 0.47 s.

Therefore, the time period  of the wave is 0.47 seconds.

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Answer:

Explanation:

Key point: the vertical motion is free fall, the horizontal motion remains at uniform speed of 100 m/s (because there is no force in the horizontal direction if we neglect air resistance.)

The time of free fall can be calculated first:

h = 1/2 g t^2 => t = sqrt(2 h /g) = sqrt(2 * 300 m / 9.81 s) = 7.82 seconds.

In that time, the horizontal displacement will be

s = v_horizontal * t = 100 m/s * 7.82 s = 782 m.

So the box will land 782 m further than the point it was dropped from (and 300 m lower of course)

Answer:

pls first attach the fig.

The graph in the figure shows the position of a particle as it travels along the x-axis. The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s. Therefore, option B is correct.

The term average speed is defined as the total distance traveled by the object in a particular time interval.

In the kinematics studies the movement of bodies, give the relationships between position, velocity and acceleration. In the special case that the acceleration is zero the motion is known as uniform motion.

       v = Δ x / Δt

Where v is the velocity, Δx is the position variation and Δt is the time variation in the analyzed interval.

Therefore,

v =  2.0 - ( - 2.0 ) / 4.0 - 1.0

v = 1.33 m / s          

Thus, The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s, option B is correct.

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Your question is incomplete, most probably your question was

The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s?

Please help!! The graph in the figure shows the position - 1, Graph is attache below in image.

Answer:

Beige to black.

Explanation:

:)

Answer: The lowest outside temperature for which the sleeping bag provides adequate protection is approximately 89.61°C below the hiker's skin temperature of 34°C.

Explanation:

To find the lowest outside temperature for which the sleeping bag provides adequate protection, we need to determine the rate of heat loss through conduction and compare it to the heat loss the hiker can safely tolerate.

The rate of heat loss through conduction can be calculated using the formula:

Q = (k * A * ΔT) / d

Where:

Q is the rate of heat transfer (in Watts)

k is the coefficient of thermal conductivity (0.019 Wm¹¹°C-¹ in this case)

A is the surface area (1.3 m² in this case)

ΔT is the temperature difference (in this case, the difference between the skin temperature and the outside temperature)

d is the thickness of the sleeping bag (30 mm, which needs to be converted to meters by dividing by 1000)

Let's plug in the values:

Q = (0.019 * 1.3 * ΔT) / (30 / 1000)

The hiker can safely lose 85 W of heat, so we can set up the equation:

85 = (0.019 * 1.3 * ΔT) / (30 / 1000)

To solve for ΔT, we can rearrange the equation:

ΔT = (85 * (30 / 1000)) / (0.019 * 1.3)

ΔT ≈ 89.61°C

Tidal energy is the form of energy used to generate electrical energy.

The form of the energy is used to generate electrical energy in a tidal power station is kinetic energy.

Kinetic energy is the energy that an object has as a result of its movement. If we intend to accelerate an object, we should indeed apply force to it. Using force requires us to put in effort.

After work is completed, energy is transmitted to the object, and the object moves at a new constant speed.

Tidal energy is generated by the movement of our tides and oceans, where the intensity of the water from tide rise and fall is a type of kinetic energy.

Tidal power is related to gravitational hydropower, which uses water movement to propel a turbine and generate electricity.

Thus, kinetic energy is used to generate electrical energy in a tidal power station.

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the car will be more damaged and fly backward faster than the truck.

In an accident, the car will be more damaged and fly backward faster than the truck. This is because the car has less mass than the truck, so it will experience more force upon impact. Additionally, the car is moving at a faster velocity than the truck, which means that it will have more kinetic energy upon impact. Therefore, the car will be subjected to a greater force upon impact, which will cause more damage to the vehicle and cause it to fly backward faster than the truck.

It's important to note that this is a simplified analysis, and in reality, the outcome of the collision will depend on various factors such as the speed, direction, angle, and point of impact of the vehicles, the road conditions, the safety features of the vehicles, etc. A more accurate analysis would require detailed information and calculations of the specific variables involved in the accident.

Answer: The car will be more damaged and fly backward faster than the truck.

Explanation: In an accident, the car will be more damaged and fly backward faster than the truck. This is because the car has less mass than the truck, so it will experience more force upon impact. Additionally, the car is moving at a faster velocity than the truck, which means that it will have more kinetic energy upon impact. Therefore, the car will be subjected to a greater force upon impact, which will cause more damage to the vehicle and cause it to fly backward faster than the truck.

Answer:

your answers is option d 75 ohms

Answer:

i think the answer is c

Explanation:

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A free body diagram consists of a diagrammatic representation of a single body or a subsystem of bodies isolated from its surroundings showing all the forces acting on it.

"A body is said to be "free" when it is singled out from other bodies for the purposes of dynamic or static analysis." The object does not have to be "free" in the sense of being unforced, and it may or may not be in a state of equilibrium; rather, it is not fixed in place and is thus "free" to move in response to forces and torques it may experience.

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Answer:

Explanation:

Vector add the two forces

If we assume the forces lie on a unit circle

25cos180 + 10cos0 = -15 or 15cos180 N

The magnitude of -15 = |-15| = 15 N

The two forces acting from opposite directions will cancel each other in magnitude. The net force acting on the box is 15 N to the left.

Force is an external agent acting on a body to deform it or to change its state of rest or motion. Force is a vector quantity and its characterised by its magnitude and direction.

If two forces acting on a body from the same directions, then the net force will be the sum of these two  forces. If these forces are acting from opposite directions, they will cancel each other in magnitude.

Here, 10 N is acting to right and 25 N to the left. Hence, the net force will be 25 -10 = 15 N to the right, because the greater force is to the right. Hence, option B is correct.

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The projectile launch relations allow finding the results for the different questions are:

     1. Rise time is 2.35 s

    2. The maximum height is 27 m

    3. The initial velocity is 26 m / s

    4. The launch angle is 62.3º

The launch of projectiles is an application of kinematics to the movement of objects near the earth's surface, in this case there is no acceleration on the x-axis and the acceleration is the gravity acceleration on the y-axis.

In the attachment we have a movement diagram of the football ball

1.  As the acceleration is constant, the time it takes the body to go up is equal to the time it takes to go down, therefore, as the total time affects, the time it takes to go up is half.

         \(t_u =\frac{t_{total} }{ 2}\)  

          t_u = 4.70 / 2

          t_u = 2.35 s

2. How high does the ball reach?

At the point of maximum height the vertical velocity is zero

        \(v_y = v_{oy} - g t\\0= v_{oy} - gt\\v_{oy} = gt\)

       \(v_{oy}\) = 9.8 2.35

        \(v_{oy}\) = 23 m / s

Now we can use the equation.

         \(v_y^2 = v_{oy}^2 - 2 g y\\0 = v_{oy}^2 - 2 g y\\\\y = \frac{v_{oy}^2}{2g}\)

        y = \(\frac{23^2}{2 \ 9.8}\)

        y = 27 m

2. What is the initial velocity?

The initial vertical velocity is 23 m / s

We look for the horizontal speed.

            \(v_x = \frac{x}{t}\)

They indicate the throw range is 57 m in the time of 4.70 s

            vₓ = 57.0 / 4.70

            vₓ = 12.1 m / s

To calculate the magnitude we use the Pythagorean Theorem

            v₀ = \(\sqrt{v_{ox}^2 + v_{oy}^2}\)  

            v₀ = \(\sqrt{12.1^2 + 23^2}\)  

            v₀ = 26 m / s

3. The launch angle

Let's use trigonometry

          tan θ = \(\frac{v_{oy}}{v_{ox}}\)  

          θ = tan⁻¹ \(\frac{v_{oy}}{ v_{ox}}\)

          θ = tan⁻¹  \(\frac{23}{12.1}\)

          θ = 62.3º

In conclusion, using the projectile launch relatios we can find the results for the different questions are:

     1. The rise time is 2.35 s

    2. The maximum height is 27 m

    3. The initial velocity is 26 m / s

    4. The launch angle is 62.3º

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Answer:

Initial Momentum - 4000 kg*m/s

Final Momentum - 0 kg*m/s

Impulse: -4000 kg*m/s

Explanation:

The equation for momentum is P = mv

Initial Momentum

200kg * 20m/s = 4000 kg*m/s

Final Momentum

200kg * 0m/s = 0kg*m/s

Impulse = ΔP

Pfinal - Pintial = Impulse

0-4000 = -4000 kg*m/s

Explanation:

T = 2π√(m/k)

T = 2π√(16 kg / 4 N/m)

T = 4π s

T ≈ 12.6 s

Answer:

The graph of the velocity of an object in free fall would look like a straight line sloping downward. As the object falls, its velocity increases at a constant rate, so the graph of its velocity versus time will be a straight line with a negative slope. This is because acceleration due to gravity is a constant -9.8 meters per second squared, so the velocity of a free-falling object will increase by 9.8 meters per second every second.

Therefore, the graph that shows the change in velocity of an object in free fall is a straight line with a negative slope. Here is an example of such a graph:

Free Fall Velocity Graph

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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Answer:

2

Explanation:

pulling force because of it force

Answer:

5.9 cm

Explanation:

f: frequency of oscillation

frequency of oscillationk: spring constant

frequency of oscillationk: spring constantm: the mass

\(f = \frac{1}{2\pi} \sqrt{ \frac{k}{m} } \)

in this problem we know,

F= 1.4 Hz

m= 0.26 kg

By re-arranging the formula we get

\(k = {(2\pi \: f )}^{2} m = {(2\pi(1.4hz))}^{2} 0.26kg = 20.1 \frac{n}{m} \)

The restoring force of the spring is:

F= kx

where

F= 1.2 N

k= 20.1 N/m

x: the displacement of the block

\(x = \frac{f}{k} = \frac{1.2 \: n}{20.1 \frac{n}{m} } = 0.059m \: = 5.9 \: cm\)

Answer:

the pressure of the water at the given depth is 196,200 N/m².

Explanation:

Given;

density of the water, ρ = 1000 kg/m³

depth of the water, h = 20 m

acceleration due to gravity, g = 9.81 m/s²

The pressure at the given depth of the water is calculated as;

P = ρgh

P = 1000 x 9.81 x 20

P = 196,200 N/m²

Therefore, the pressure of the water at the given depth is 196,200 N/m².

Given:

The force between the masses M and M is F and the distance between them is d

The distance between masses 2M and 2M is 2d

To find:

The force between the masses 2M and 2M.

Explanation:

From Newton's law of gravitation, the gravitational force between two objects is proportional to the product of the masses and inversely proportional to the square of the distance between the objects.

Thus the force between the masses M and M is given by,

The force between the masses 2M and 2M is

From equations (i) and (ii),

Final answer:

The force of gravity in the second diagram is F.

Thus the correct answer is option B.

a) The ratio of the slit separation to the slit width is 2.  

b) There are four bright fringes within the first side peak.

a) The ratio of the slit separation to the slit width is 2. This is because the second side peak of the diffraction envelope is located at an angle of

2λ/d, where λ = wavelength of light and d = slit width.

The diffraction minima coincide with the two-slit interference maxima, which are located at angles of λ/d.

Therefore, the ratio of the slit separation to the slit width is 2.

(b) There are four bright fringes within the first side peak. This is because the first side peak of the diffraction envelope is located at an angle of

λ/d, where λ = wavelength of light and d = slit width.

The diffraction minima coincide with the two-slit interference maxima, which are located at angles of λ/d.

Therefore, there are 4 bright fringes within the first side peak.

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The string's angle of deflection  is useful for quantitatively comparing the amount of charge on each sphere.

The angles of trajectory that all of your strings take across and behind the nut and saddles of your instrument are, in a nutshell, what is meant by this term. The string's angle, which are located above the headstock, are the downward angles your strings make when they travel through the nut slot, emerge over the fingerboard, and exit the rear edge of the nut to the string wraps on the machine head posts. It is the angle that the string makes at the bridge between your saddle and the spot where the ball end of your string is located.

The string's ability to transfer downward stresses into the guitar is governed by break angles.

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A) Moving the three-particle system from A to D has no effect on its electric potential energy.

B) When a particle is transferred from A to D, the total electric force exerted on it produces negative work.

C) When your force is shifted from A to D, it does not produce any work.

D) The values will be zero, negative, and zero if the particle is transferred from B to C.

The total energy resulting because of all the charges present in the system determines the total potential energy for moving a charge from one location to another. Therefore, total potential energy is positive for two positive charges.

or work done, we just take into account the polarity of charges. The effort completed for equal polarity is found to have a positive regardless of its value. Our force's course determines the job that is accomplished by our force. The work done will be negative for the opposing path and force direction.

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The complete question is -

The figure shows a system of three charged particles. If you move the particle of charge from point A to point D, are the following quantities positive, negative, or zero: (a) the change in the electric potential energy of the three-particle system, (b) the work done by the net electric force on the particle you moved (that is, the net force due to the other two particles), and (c) the work done by your force? (d) What are the answers to (a) through (c) if, instead, the particle is moved from B to C?

If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.

To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.

Given:

Mass of the box, m = 210 kg

Tension in the string, T = 1300 N

The angle of inclination, θ = 35°

Frictional force, f = 100 N

Initial speed, u = 0 m/s

Final speed, v = 10 m/s

First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:

T_parallel = T * cos(θ)

Next, let's calculate the net force acting on the box along the incline. The net force is given by:

Net force = T_parallel - f

Now, using Newton's second law, we can calculate the acceleration (a) of the box:

Net force = m * a

From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):

v^2 = u^2 + 2as

Rearranging the equation, we get:

s = (v^2 - u^2) / (2a)

Now, let's plug in the given values and calculate the distance covered:

T_parallel = 1300 N * cos(35°) ≈ 1067.35 N

Net force = 1067.35 N - 100 N = 967.35 N

a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2

s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m

Therefore, the distance covered by the box is approximately 10.89 meters.

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Answer:

Below

Explanation:

Kinetic Energy = 1/2 * m * v^2

                        = 1/2 * .45 * .2^2 = .009 J

Important Formulas:

\(KE=.5mv^2\)

Kinetic Energy(measured in joules) = .5 * mass(measured in kg) * velocity(measured in m/s)^2

__________________________________________________________

Given:

\(m=0.45kg\)

\(v=0.20m/s\)

\(KE=?\)

__________________________________________________________

\(KE=.5mv^2\)

\(KE=.5(0.45)(0.20)^2\)

__________________________________________________________

\(\fbox{KE = 0.009J}\)

Answer:

Theres no given?

Explanation:

Well, whatever.

I observed the shift of their sunset time.

Examples like:

January to June = their sunset time increased while

July to December = their sunset time decreased