The atomic emission spectrum of hydrogen includes four visible colors of light: red, blue-green, indigo, and violet. Which color of light corresponds with the smallest electron transition?VioletRedblue-greenIndigo

Answer:

See attached figure.

Explanation:

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In this case, according to the given substances, we recall the concept of Lewis structure as such showing the bonds and valence electrons each atom has in the molecule. Thus, since chlorine atoms have seven valence electrons, carbon atoms four of them, hydrogen atoms have 1 and oxygen atoms 6, we are able to draw such Lewis dot structures, by obeying the octet as shown on the attached figure.

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The decomposition of aspirin (acetylsalicylic acid,\(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)).

The decomposition of aspirin (acetylsalicylic acid, \(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)). To determine the moles of each product formed, we need to consider the balanced chemical equation for the reaction:

\(C_{9} H_{8} O_{4} = > C_{7} H_{6}O_{3} +CH_{3} COOH\)

From the equation, we can see that for every 1 mole of aspirin, 1 mole of salicylic acid and 1 mole of acetic acid are produced.

Therefore, the moles of salicylic acid and acetic acid formed will be equal to the number of moles of aspirin that decomposes. If we know the amount of aspirin in moles, we can directly calculate the moles of each product based on stoichiometry.

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\(\\ \rm\longmapsto Density=\dfrac{Mass}{Volume}\)

\(\\ \rm\longmapsto Mass=Density\times Volume\)

\(\\ \rm\longmapsto Mass=8(10)\)

\(\\ \rm\longmapsto Mass=80g\)

Experiment: Does it Dissolve?

Materials Needed:

Step 1: Form a question before starting the experiment.

Step 2: Make a hypothesis for each substance.

Step 3: Scoop a teaspoon of each substance in the jars, only adding one substance per jar. Stir it up!

Step 4: Observe whether or not each substance dissolves and record the findings.

Answer:

The resulting solution is basic.

Explanation:

The reaction that takes place is:

First we calculate the added moles of HNO₃ and KOH:

As there are more KOH moles than HNO₃, the resulting solution is basic.

The resulting solution is basic.

• It is known that KOH is a base and HNO3 is an acid, so when they mix they undergo a neutralization reaction.  

• The reaction between there will be,  

HNO3 + KOH ⇔ KNO3 + H2O

Based on the given information,

• The volume of HNO3 is 12.5 ml and the molarity is 0.280 M, and the volume of KOH is 5 ml and the molarity is 0.920 M.

Now 1 mole of HNO3 completely reacts with 1 mole of KOH,

The millimoles of HNO3 is,

\(= Molarity * Volume (in ml)\\= 0.280 * 12.5\\= 3.5 mmol\)

The millimoles of KOH is,

\(= Molarity * Volume (in ml)\\= 0.920 * 5.0\\= 4.6 mmol\)

Now it can be seen that 3.5 millimoles of HNO3 completely reacts with 3.5 millimoles of KOH. Now we are left with 4.6-3.5 = 1.1 mmol of KOH.

Thus, KOH is in excess amount present in the solution, and as it is basic in nature, therefore, the resultant solution would be basic in nature.

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The statement that is true of a Lewis base is that a Lewis base donates electron pairs (option A).

A Lewis base is any nucleophylic compound that can donate a pair of electrons and form a coordinate covalent bond.

On the other hand, a Lewis acid is any electrophylic compound that can accept a pair of electrons and form a coordinate covalent bond.

This means that a Lewis base can donate a pair of electrons to a Lewis acid to form a product containing a coordinate covalent bond. This product is also referred to as a Lewis adduct.

Therefore, option A is correct about Lewis base

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Answer:

In a combustion reaction, a substance reacts with oxygen from the air. Combustion reactions happen at high temperatures, and transfer energy to the surroundings as light and heat. ... Since methane is made up of atoms of carbon and hydrogen, the products of its combustion reaction are oxides of carbon and hydrogen.

Explanation:

Answer:

Option D

Explanation:

Because we know the relationship between no of moles and volume

Option D

Answer:

Option B is correct.

4

Explanation:

We know that an atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example, if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

In given problem we are given with 2 neutrons of helium. We know that the atomic number of He is 2. Thus Mass number of He is,

Number of neutrons + number of proton

2 + 2 = 4

Thus, option B is correct.

Electrons are transferred from atoms of sodium to atoms of phosphorous The sodium atom looses electron and the phosphorus atoms gains electrons.

The electron is a subatomic particle with an elementary electric charge of -1. Electrons are the first generation of the lepton particle family and are widely regarded as elementary particles due to the lack of known components or substructure.

This transfer causes the sodium atoms  to acquire positive charge and phosphorous to acquire negative charge .

Thus, the sodium and phosphorus atoms strongly attract with each other.

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Your question is incomplete, most probably, your question was

Complete the paragraph about the formation of sodium phosphide.

Electrons are transferred from atoms of

and the phosphorus atoms

to atoms of

C. This transfer makes the sodium atoms

As a result, the sodium and phosphorus atoms strongly

each other.

To solve this we must be knowing each and every concept related to mole and  and its calculations. Therefore, 83.17g is the grams of  CaCl\(_2\) would it take to make 1.5 moles of KCl. The correct option is option B.

A mole is merely a measuring unit. In reality, it is one of International System of Units' seven foundation units (SI). When basically determines are insufficient, new units are created.

Chemical reactions frequently occur at levels that use grams would be inappropriate, but using actual figures of atoms/molecules/ions would also be misleading.

It's much easier to write' mole' than '6.02x10²³' whenever you wish to refer to a huge number of things. That is essentially why and how this particular component was created.

2K\(_3\)N + 3CaCl\(_2\) → 6KCl + Ca\(_3\)N\(_2\)

mole ratio between CaCl\(_2\) and KCl is 1:2

2 mole of KCl requires 1 mole of CaCl\(_2\)

1 mole of KCl requires 1/2 moles of CaCl\(_2\)

1.5 moles of KCl requires (1/2)×1.5= 0.75 moles of CaCl\(_2\)

mass of CaCl\(_2\) =  0.75 moles ×110.9g/mol

                        = 83.17g

Therefore, 83.17g is the grams of  CaCl\(_2\) would it take to make 1.5 moles of KCl.

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Answer:

true

it is more dense

The climatic change in Earth's history that has resulted in glaciers is the cold climate.

During the last 2.6 million years, the Earth has experienced a series of ice ages, or periods of colder global climate, which have led to the growth of glaciers in regions with sufficient snowfall.

These colder periods are associated with changes in the Earth's orbit, tilt, and precession, which affect the amount and distribution of solar radiation received by the Earth. These climatic changes have had significant impacts on the Earth's surface and have influenced the evolution of life on our planet.

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Answer:

the answer above is correct

Explanation:

Answer: Refract

Explanation:

Answer:The two kinds of trace fossils mentioned in the options are:

tracks

burrowsTracks and burrows are both examples of trace fossils, which are fossils thatprovide evidence of an organism's activity, rather than the organism itself.Tracks are impressions left by an organism's feet or other body parts as itmoved across soft sediment, while burrows are tunnels or other structurescreated by an organism as it burrowed into the sediment. Both types of tracefossils can provide valuable information about an organism's behavior, habitat, and interactions with other organisms.

The pH of acid is between 0-7 on pH scale while for base pH range is from 7-14. Therefore, the pH of buffer is 10.5. pH is a unitless quantity.

pH is a measurement of amount of hydronium ion H₃O⁺ in a given sample. More the value of hydronium ion concentration, more will be the solution acidic.

On subtracting pH from 14, we get pOH which measures the concentration of hydroxide ion in a given solution. pH depend on the temperature. At room temperature pH scale is between 0 to 14. pH of neutral solution is 7.

CH\(_3\)NH\(_2\) + H\(_2\)O(aq) \(\rightarrow\) CH\(_3\)NH\(_3\) ⁺(aq) + OH⁻(aq)

Kb = [CH\(_3\)NH\(_3\) ⁺] x[OH⁻] =3.7x 10⁻⁴

[CH\(_3\)NH\(_2\)]= 0.2 / 1.00 =0.2M

Kb = (0.2M) x [OH⁻] = 3.7x 10⁻⁴

[OH-] = 3.15 x 10⁻⁴

pOH=-log[OH-]

      = -log[3.15 x 10⁻⁴]

pOH=3.5

pH+pOH=14

pH = 10.5

Therefore, the pH of buffer is 10.5.

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Answer:

Covalent bond is a chemical bond is a strong attraction between two or more atoms.

Answer:

Ionic

Explanation:

An ionic chemical bond is a strong attraction between two or more atoms. Two atoms are more strongly attracted by ionic bonds.

From the reaction given, 47.4 kJ evolved when 5.91 grams of Na(s) reacted with H2O(l). The value of ΔrH for this equation is: - 23.7 kJ/mol.

Before calculating the enthalpy changes, we should know the moles of Na first:

n of Na = mass / molar mass

n = 46.4 g / 23 g/mol

n = 2 moles.

Now, the equation given is:

2Na(s) + 2H₂O(l) —> 2NaOH(aq) + H₂(g)    ΔH = - 47.4 kJ

The value of ΔrH has to state the enthalpy changes of one mol reactant. So, we need to divide the coefficient by 2:

Na(s) + H₂O(l) —> NaOH(aq) + ½ H₂(g)    ΔH = - 23.7 kJ/mol

Hence, the value of ΔrH is - 23.7 kJ/mol.

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The student needs to add approximately 83.3 mL of 12 M HCl solution to the existing 1 L of 2 M HCl solution to increase the concentration to 3 M. It is important to handle concentrated acids with caution and follow proper safety procedures.

To increase the concentration of a 1 L solution of 2 M HCl to 3 M, the student needs to calculate the volume of concentrated HCl needed and add it to the existing solution. Here's how the calculation can be done:

Given:

Initial concentration of HCl solution = 2 M

Final concentration desired = 3 M

Initial volume of HCl solution = 1 L

Step 1: Calculate the moles of HCl in the initial solution.

Moles of HCl = Initial concentration × Initial volume = 2 M × 1 L = 2 moles

Step 2: Calculate the moles of HCl needed for the desired concentration.

Moles of HCl needed = Final concentration × Final volume = 3 M × 1 L = 3 moles

Step 3: Calculate the moles of HCl to be added.

Moles of HCl to be added = Moles needed - Moles present = 3 moles - 2 moles = 1 mole

Step 4: Convert the moles of HCl to the required volume of concentrated HCl.

To calculate the volume, we need to know the concentration of the concentrated HCl solution. Assuming it is 12 M, we can use the following formula:

Volume of concentrated HCl = Moles of HCl to be added / Concentration of concentrated HCl

Volume of concentrated HCl = 1 mole / 12 M = 0.0833 L or 83.3 mL

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Answer: paleotempestology.

When NaHCO\(_3\) completely decomposes, the mass of Na\(_2\)CO\(_3\) and H\(_2\)CO\(_3\) are 1.995g and  1.17g respectively.

It is the most fundamental characteristic of matter and one of the fundamental quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilogramme (kg) is the SI unit of mass. A body's bulk remains constant at all times. only in rare instances where a significant quantity of energy is supplied to or taken away from a body.

2NaHCO\(_3\) → Na\(_2\)CO\(_3\) + H\(_2\)CO\(_3\)

moles of NaHCO\(_3\)= 3.24/84=0.038moles

According to stoichiometry  

moles of Na\(_2\)CO\(_3\) = 0.038/ 2= 0.019moles

mass of Na\(_2\)CO\(_3\) =0.019×105

                          = 1.995g

moles of H\(_2\)CO\(_3\)=  0.019

mass of H\(_2\)CO\(_3\) =  0.019×62

                         = 1.17g

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Answer:

i got u bro bro is a bit long tho

Explanation:

A. To determine the theoretical yields of each product (Na2CO3 and H2CO3) when 3.24 grams of NaHCO3 decomposes, we first need to calculate the molar masses of NaHCO3, Na2CO3, and H2CO3.

Molar mass of NaHCO3:

Na: 22.99 g/mol

H: 1.01 g/mol

C: 12.01 g/mol

O: 16.00 g/mol

Molar mass of NaHCO3 = 22.99 + 1.01 + 12.01 + (3 * 16.00) = 84.02 g/mol

Now, let's use stoichiometry to find the theoretical yields of Na2CO3 and H2CO3:

From the balanced chemical equation, we see that 2 moles of NaHCO3 produce 1 mole of Na2CO3 and 1 mole of H2CO3.

Calculate the moles of NaHCO3 in the sample:

Moles of NaHCO3 = Mass (g) / Molar mass (g/mol) = 3.24 g / 84.02 g/mol ≈ 0.0386 moles

Calculate the moles of Na2CO3 and H2CO3 that should be produced:

Moles of Na2CO3 = 0.0386 moles * (1 mole Na2CO3 / 2 moles NaHCO3) = 0.0193 moles Na2CO3

Moles of H2CO3 = 0.0386 moles * (1 mole H2CO3 / 2 moles NaHCO3) = 0.0193 moles H2CO3

Calculate the mass of each product:

Mass of Na2CO3 = Moles * Molar mass = 0.0193 moles * (2 * 22.99 g/mol + 12.01 g/mol + 3 * 16.00 g/mol) = 2.82 grams (rounded to two decimal places)

Mass of H2CO3 = Moles * Molar mass = 0.0193 moles * (2 * 1.01 g/mol + 12.01 g/mol + 3 * 16.00 g/mol) = 2.20 grams (rounded to two decimal places)

So, the theoretical yield of Na2CO3 is approximately 2.82 grams, and the theoretical yield of H2CO3 is approximately 2.20 grams.

B. If the measured mass of one of the products was 2.01 grams, it is most likely H2CO3 (carbonic acid) because its theoretical yield is close to this value (2.20 grams), while the theoretical yield of Na2CO3 is significantly higher (2.82 grams).

C. To calculate the percent yield of H2CO3 (carbonic acid), use the formula:

Percent Yield = (Actual Yield / Theoretical Yield) * 100%

Percent Yield = (2.01 grams / 2.20 grams) * 100% ≈ 91.36%

The percent yield of H2CO3 is approximately 91.36%.

Answer:

B. energy, but not matter

Answer:

Uranium-238 undergoes alpha decay to form Thorium-234 as daughter product.

Explanation:

Alpha decay is indicative of loss of the equivalents of a helium particle emission. The reaction equation for this reaction is shown below:

\(_{92} ^{238} U_{}\)→ \(_{90} ^{234} Th_{} + _{2} ^{4} He_{}\)

I hope this explanation is clear and explanatory.

The amount of oxygen needed in the reaction to burn the octane is higher than necessary. Octane is hence the reaction's limiting agent.

The limiting reactant, also known as the limiting reagent, is the reactant that is used up first during a chemical reaction, hence restricting the amount of product that can be produced during the course of the reaction.

A chemical reaction's limiting reagent is the one that will totally consume all of the reactants. The reaction can't continue once there is no more of a reactant. Hence, it prevents the reaction from intensifying and continuing further. If the other reactant hadn't been used up completely, the surplus reagent would have continued to react, and the reaction would also have continued.

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Explanation:

To determine the molar mass of the gas, we need to use the ideal gas law equation:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature. We can rearrange this equation to solve for the number of moles:

n = (PV) / (RT)

We are given the mass of the gas (0.643 g), the volume (125 mL), the pressure (60. cm Hg), and the temperature (25°C). To use these values in the ideal gas law equation, we need to convert the volume to liters and the pressure to atmospheres (atm) and the temperature to Kelvin (K):

V = 125 mL = 0.125 L

P = 60. cm Hg = 0.789 atm (using the conversion factor 1 atm = 760 mm Hg and 1 cm Hg = 1.33322 mm Hg)

T = 25°C + 273.15 = 298.15 K

Substituting these values into the ideal gas law equation and solving for n gives:

n = (PV) / (RT) = (0.789 atm x 0.125 L) / (0.0821 L·atm/mol·K x 298.15 K) = 0.00314 mol

To find the molar mass, we can use the formula:

molar mass = mass of sample / number of moles

molar mass = 0.643 g / 0.00314 mol = 204.46 g/mol

Therefore, the molar mass of the gas is approximately 204.46 g/mol.

Answer:

To determine the molar mass of the gas, we need to use the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. We can rearrange this equation to solve for n:

n = PV/RT

First, we need to convert the pressure to atmospheres (atm) and the volume to liters (L):

cm Hg = 0.788 atm (using the conversion factor 1 atm = 760 mm Hg)

125 mL = 0.125 L

Next, we can substitute the given values into the equation and solve for n:

n = (0.788 atm)(0.125 L)/(0.0821 L·atm/mol·K)(298 K) = 0.00472 mol

Finally, we can calculate the molar mass by dividing the mass of the sample by the number of moles:

molar mass = 0.643 g/0.00472 mol = 136 g/mol (rounded to three significant figures)

Therefore, the molar mass of the gas is approximately 136 g/mol.