Answer:
I would say it would float do to the density a weight is not heavy enough to sink
Explanation: ✪ ω ✪ Hope Dis Helped!
which is right
A.
B.
C.
D.
Answer:
A
Explanation:
because the glass contain the ice cubes
C5H12() + 502(9)=
5CO2(g) + 6H2(9)
A. Decomposition
B. Combustion
C. Neutralization
D. Precipitation
What makes up soil and where do these main components come
from? ASAP
Answer:
Soil is a mixture of minerals, dead and living organisms (organic materials), air, and water.
Explanation:
Dead organisms decompose(kind of like fertilizer)
water comes from nearby watersheds, precipitation processes, etc.
Answer:
Soil is made up of three main components – minerals that come from rocks below or nearby, organic matter which is the remains of plants and animals that use the soil, and the living organisms that reside in the soil. The proportion of each of these is important in determining the type of soil that is present.
fill in the blank. "Hydrophobic colloids __________.
a. will separate into two phases if they are stabilized
b. can be stabilized by adsorption of ions
c. are those that contain water
d. are those that do not contain water
e. can be stabilized by coagulation"
b. can be stabilized by adsorption of ions
Hydrophobic colloids option b- can be stabilized by adsorption of ions.
Hydrophobic colloids are colloidal particles that repel water molecules and tend to aggregate or coagulate in aqueous solutions. To stabilize hydrophobic colloids, surfactants or stabilizing agents are added to the system.
These surfactants have hydrophobic and hydrophilic regions that can adsorb onto the surface of the colloidal particles, forming a protective layer that prevents their aggregation. This adsorption of surfactant molecules on the particle surface is commonly referred to as "stabilization by adsorption of ions".
The surfactant molecules adsorb onto the particle surface with their hydrophobic tails pointing inward towards the particle surface and their hydrophilic heads pointing outward towards the solvent, creating a stable colloidal dispersion. This stabilization mechanism is commonly used in the formulation of emulsions, suspensions, and other colloidal systems.
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What will have the slowest onset time in an allergic reaction: injected, ingested, inhaled, touch. Why?
Inhaled allergies will have the slowest onset time in an allergic reaction.
Inhaled allergies are also known as delayed-type hypersensitivity of allergic reactions because they occur after at least 24 hours of exposure to an allergen.
These reactions usually occur 48 to 72 hours or more to get exposure after contact with the allergen. Respiratory allergies are the most common type of allergy. Symptoms may include:
sneezing runny nose watery eyes itchy eyesMany people with inhaled allergies only have symptoms at certain times of the year. Pollen, grass, and mold are the most common triggers for seasonal allergies.
Many types of airborne allergens are prevalent indoors.
Fungi Molds Animal dander MitesMany long-term infectious diseases, such as tuberculosis and fungal infections are its examples.
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The process in which the nucleus of an atom splits into two lighter atoms, releasing a large amount of energy, is nuclear ______ Fusion Fission Radiation Energy.
Answer:
B. Fission
Explanation:
On edge
Explain why decomposition of sugar on heating is an irreversible change.
Sugar, sucrose (C12H22O11: a disaccharide, composed of the two monosaccharides: glucose and fructose), is odorless, that is, it lacks odor. When heated a phase change occurs resulting in melting of a thick syrup.
what is the hydronium ion concentration in a solution of hcl that has a ph of 4.65? round to the nearest hundredth.
2.2387×10⁻⁵ M is the concentration of hydronium ion in a solution of HCL that has a ph of 4.65.
What is a hydronium ion?The term "hydronium" refers to the sort of oxonium ion created by protonating water, the aqueous cation H3O+. When an Arrhenius acid is dissolved in water, it is frequently thought of as the positive ion present since the surrounding water molecules get a proton from the Arrhenius acid molecules.
Hence, 2.2387×10⁻⁵ M is the concentration of hydronium ion in a solution of HCL that has a ph of 4.65.
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Need help im kinda stuck ;-;
Answer:
the answer is the third figure from left
A substance can change into a new kind of molecule when:
Answer:
Chemical changes cause a substance to change into an entire substance with a new chemical formula. Chemical changes are also known as chemical reactions. The “ingredients” of a reaction are called reactants, and the results are called products.
Hope it helps
Positive oxidation number suggest that the element wants to ____ (lose/gain) electrons?
Answer:
lose
Explanation:
its lose because if its positive, assume the electron is a person who has already eaten, theyre full and dont want more, therefore they would want to lose the weight, so its lose.
determine the volume of 0.142 m naoh that is required to reach the stoichiometric point in the titration of 36 mL of 0.18 M C6H5COOH(aq). The Ka of benzoic acid is 6.5×10−5.
To determine the volume of 0.142 M NaOH required to reach the stoichiometric point in the titration of 36 mL of 0.18 M benzoic acid, we use the equation: moles of acid = moles of base. Since benzoic acid and NaOH react in a 1:1 ratio, we can write: (C6H5COOH) × (volume of C6H5COOH) = (NaOH) × (volume of NaOH).
Using the given concentrations and volume, we have: (0.18 mol/L) × (0.036 L) = (0.142 mol/L) × (volume of NaOH). Solving for the volume of NaOH, we get approximately 0.0455 L or 45.5 mL. Therefore, 45.5 mL of 0.142 M NaOH is required to reach the stoichiometric point in this titration.
In this titration, we are trying to determine the volume of 0.142 M NaOH required to reach the stoichiometric point with 36 mL of 0.18 M C6H5COOH (benzoic acid).
To start, we need to determine the number of moles of benzoic acid in 36 mL of 0.18 M solution. Using the formula M = moles/volume, we can calculate this to be 0.00648 moles.
Since NaOH and benzoic acid react in a 1:1 ratio, we know that 0.00648 moles of NaOH will be required to reach the stoichiometric point.
Now, we can use the formula V = n/M to calculate the volume of NaOH needed. Plugging in the values, we get:
V = 0.00648 moles / 0.142 M = 0.0456 L or 45.6 mL.
Therefore, 45.6 mL of 0.142 M NaOH is required to reach the stoichiometric point in the titration of 36 mL of 0.18 M benzoic acid.
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For+the+reaction+H2+++I2+-+2HI+the+equilibrium+constant,+kc+is+49+at+a+fixed+temperature.+Two+mole+of+hydrogen+and+two+moles+of+iodine+are+allowed+to+reach+equilibrium+at+this+temperature.+What+is+the+concentration+of+hydrogen+iodide+at+equilibrium?
Answer : The initial concentration of HI and concentration of HI at equilibrium is, 0.27 M and 0.386 M respectively.
Solution : Given,
Initial concentration of H_2 and I_2 = 0.11 M
Concentration of H_2 and I_2 at equilibrium = 0.052 M
Let the initial concentration of HI be, C
The given equilibrium reaction is,
H_2(g)+I_2(g)\rightleftharpoons 2HI(g)
Initially 0.11 0.11 C
At equilibrium (0.11-x) (0.11-x) (C+2x)
As we are given that:
Concentration of H_2 and I_2 at equilibrium = 0.052 M = (0.11-x)
The expression of K_c will be,
K_c=\frac{[HI]^2}{[H_2][I_2]}
54.3=\frac{(C+2(0.058))^2}{(0.052)\times (0.052)}
By solving the terms, we get:
C = 0.27 M
Thus, initial concentration of HI = C = 0.27 M
Thus, the concentration of HI at equilibrium = (C+2x) = 0.27 + 2(0.058) = 0.386 M
What is ANFO made of
Answer:
(AN) Ammonium nitrate ( 94% )
(FO) Diesel fuel ( 6% )
Explanation:
i have a question on y=mx+b which is the y?
Answer:
the b is the y-intercept of the line :D
consider the following elementary reactions: a) no o3 no2 o2 b) cs2 cs s c) o o2 n2 o3 n2 identify the molecularity of each reaction respectively.
The reaction is given below:O + O2 + N2 ⟶ O3 + N2Here, three molecules of O, O2, and N2 are involved in the reaction. Hence, the molecularity of the reaction is trimolecular.
Molecularity can be defined as the number of atoms, ions, or molecules taking part in an elementary reaction. Given below are the molecularities of the given elementary reactions:a) no o3 no2 o2Molecularity of the given reaction is unimolecular.b) cs2 cs sMolecularity of the given reaction is bimolecular.c) o o2 n2 o3 n2Molecularity of the given reaction is trimolecular.
In the first reaction, no molecule reacts with O3 molecules to form NO2 and O2 molecules. The reaction is given below:NO + O3 ⟶ NO2 + O2Here, only one molecule of NO is involved in the reaction. Hence, the molecularity of the reaction is unimolecular.In the second reaction, CS2 molecules react with CS atoms to form S atoms. The reaction is given below:CS2 + CS ⟶ 2SHere, two molecules of CS2 are involved in the reaction.
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Given that there are more possible combinations for amino acids than amino acids themselves, what does this imply about the number of codes for each amino acid?
The fact that there are more possible combinations for amino acids than the number of amino acids themselves implies that each amino acid can be encoded by multiple codons.
A codon is a sequence of three nucleotides in DNA or RNA that corresponds to a specific amino acid.
There are 20 standard amino acids used to build proteins in living organisms. However, there are 64 possible three-letter combinations of nucleotides (4³) that can be used to form codons. This means that on average, there are more than three codons that can encode each amino acid.
To calculate the number of codons per amino acid on average, we divide the total number of codons (64) by the number of amino acids (20). Therefore, the average number of codons per amino acid is 64/20 = 3.2.
This indicates that there is a degeneracy or redundancy in the genetic code, where multiple codons can specify the same amino acid.
For example, the amino acid leucine is encoded by six different codons (UUA, UUG, CUU, CUC, CUA, CUG), while methionine and tryptophan are each encoded by a single codon.
In conclusion, the existence of more possible combinations for amino acids than amino acids themselves means that the genetic code is degenerate, allowing for redundancy and flexibility in protein synthesis.
This redundancy helps to protect against errors in DNA replication and transcription and allows for evolution to occur through the accumulation of genetic variations.
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What is the wavelength of electromagnetic radiation with a frequency of 5.00 x 10^12 Hz? What kind of electromagnetic radiation is this?
Answer: 5.98 × 10⁻⁵ m (Infrared)
Explanation:
wavelength = speed of light ÷ frequency
wavelength = (2.99 × 10⁸ m/s) ÷ (5.00 x 10¹² /s)
= 5.98 × 10⁻⁵ m
Since radiation in the range, 10⁻³ to 7 × 10⁻⁷ is considered Infrared radiation, then the wave is an infrared wave.
1. how many grams of solute are in 360 ml of 2.11 m al(no3)3 solution?
2.How many moles of solute are in 115 mL of 2.5 M solution?
3.How many grams of solute are in 740 mL of 1.40 M MgI2 solution?
4.How many mL of 6.0 M stock solution are needed to make 500 mL of 1.25 M solution?
5.What concentration of stock solution is needed if 25.0 mL of it are diluted to the final concentration of 0.502 M and final volume of 50.6 mL?
To calculate the grams of solute in a solution, you need to multiply the volume of the solution (in liters) by the molarity of the solute (in moles per liter).
First, convert the volume from milliliters to liters by dividing by 1000: 360 mL ÷ 1000 mL/L = 0.360 L. Then, multiply the volume in liters by the molarity of the solution: 0.360 L × 2.11 mol/L = 0.7596 mol. Finally, multiply the moles of solute by the molar mass of the solute (in grams per mole) to get the grams of solute: 0.7596 mol × molar mass of Al(NO3)3.
To calculate the moles of solute in a solution, you need to multiply the volume of the solution (in liters) by the molarity of the solute (in moles per liter). First, convert the volume from milliliters to liters by dividing by 1000: 115 mL ÷ 1000 mL/L = 0.115 L. Then, multiply the volume in liters by the molarity of the solution: 0.115 L × 2.5 mol/L = 0.2875 mol.
To calculate the grams of solute in a solution, you need to multiply the volume of the solution (in liters) by the molarity of the solute (in moles per liter). First, convert the volume from milliliters to liters by dividing by 1000: 740 mL ÷ 1000 mL/L = 0.740 L. Then, multiply the volume in liters by the molarity of the solution: 0.740 L × 1.40 mol/L = 1.036 mol. Finally, multiply the moles of solute by the molar mass of the solute (in grams per mole) to get the grams of solute: 1.036 mol × molar mass of MgI2.
To calculate the mL of stock solution needed to make a desired concentration, you can use the dilution formula C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, C2 is the desired concentration, and V2 is the final volume of the diluted solution. Rearranging the formula to solve for V1, we get V1 = (C2V2)/C1. Plugging in the given values, we get V1 = (1.25 M × 500 mL) / 6.0 M.
To calculate the concentration of the stock solution needed for a desired final concentration, you can use the dilution formula C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution used, C2 is the desired final concentration, and V2 is the final volume of the diluted solution. Plugging in the given values, we get C1 = (C2V2)/V1 = (0.502 M × 50.6 mL) / 25.0 mL.
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Please help ASAP! PLEASE DO NOT GIVE ME A RANDOM GIBBERISH ANSWER OR ELSE I WILL REPORT YOU AND GIVE YOU A LOW RATING!!!
If you're unsure of the answer just type it in the comments.
QUESTIONS:
QUESTION 1:
If the mass and volume of an object is very HIGH will the object sink or float?
QUESTION 2:
If the mass and volume of an object if very LOW will the object sink or float?
Please answer this as soon as possible, as these questions need to be done right now!
Answer:
if an object weighs more than an equal volume of water, it is more dense and will sink, and if it weighs less than an equal volume of water, it is less dense and will float.
Explanation:
Hope that helps
In the classical free electron model, the name(s) given to the neglect of electron ion interaction is/are
i. The independent electron approximation
ii. The free electron approximation
iii. The Drude electron - ion approximation
(i) Only
(ii) Only
(i) and (ii)
(iii) Only
in the classical free electron model, the neglect of electron-ion interaction is referred to as the free electron approximation. The correct option is (ii) Only.
This approximation assumes that the interaction between electrons and ions can be ignored, treating the electrons as free particles moving in a periodic potential without any significant influence from the ions. The independent electron approximation, on the other hand, assumes that the behavior of each electron can be considered independently of the others. The Drude electron-ion approximation incorporates electron-ion interactions and is not part of the classical free electron model. Therefore, the correct option is (ii) Only.
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How many particles are in 42g of CO
Answer: One mole of any element/compound has a mass equal to its gram atomic/molecular mass.
We know that Carbon has an atomic mass equal to 12g, I. E. One mole of carbon atoms weighs 12g.
We know that one mole of any substance contains 6.0225X10^23 particles(atoms, molecules, ions, etc.).
Thus 12g of Carbon contains 6.0225X10^23 atoms of Carbon. Therefore 1g Carbon will contain (6.0225X10^23)/12 atoms of Carbon.
Answer= 5.01875 X 10^22 atoms
Water is called the ____ ______
Water is called the universal solvent
Please mark as brainliest
what is the name of the element of atomic no 114
Answer:
Flerovium
Explanation:
Answer:
Fl or flerovium. Atomic number is the number above the element on a periodic table.
briefly describe a green chemistry success story
Scientists at NatureWorks of Minnetonka, Minnesota, makes food containers from a polymer called polylactic acid, made using microorganisms to convert cornstarch into a resin. The resulting polymer is used to replace rigid petroleum-based plastic used in yogurt containers and water bottles.
what is the difference between copernicus's and kepler's description of planetary orbits
How many of the following species are diamagnetic?
K Zr2⁺ Al3⁺ Zn2⁺
A) 1 B) 3 C) 0 D) 2 E) 4
A species is diamagnetic or not, we need to consider its electron configuration and the presence of unpaired electrons. Diamagnetic species have all their electrons paired, while paramagnetic species have unpaired electrons. 2 out of the 4 species listed are diamagnetic (Al³⁺ and Zn²⁺). Therefore, the correct answer is D) 2.
Let's examine each species:
1. K (potassium): The electron configuration of K is [Ar] 4s¹. It has one unpaired electron, so it is paramagnetic.
2. Zr²⁺ (zirconium ion): Zr²⁺ has the electron configuration [Kr] 4d². Since it has two unpaired electrons, it is paramagnetic.
3. Al³⁺ (aluminum ion): The electron configuration of Al³⁺ is [Ne]. It has no unpaired electrons, so it is diamagnetic.
4. Zn²⁺ (zinc ion): The electron configuration of Zn²⁺ is [Ar] 3d¹⁰. Since it has a completely filled d orbital with no unpaired electrons, it is diamagnetic.
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A local hamburger shop sold a combined total of 620 hamburgers and cheeseburgers on Wednesday. There were 70 more cheeseburgers sold than hamburgers. How many hamburgers were sold on Wednesday?
The number of hamburgers sold on Wednesday is 275.
Let's assume the number of hamburgers sold is x.
According to the given information, the number of cheeseburgers sold is 70 more than the number of hamburgers. So, the number of cheeseburgers sold can be expressed as x + 70.
The total number of hamburgers and cheeseburgers sold is given as 620, so we can set up the following equation:
x + (x + 70) = 620
Combining like terms, we get:
2x + 70 = 620
Subtracting 70 from both sides of the equation:
2x = 550
Dividing both sides by 2:
x = 275
Therefore, the number of hamburgers sold on Wednesday is 275.
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There is 100 mCi of Cs-137 and 300 mCi of Co-60. Calculate the time it will take for both isotopes to decay
until their activities are equal.
Rationale:
Use the decay function for both isotopes and set
them equal to each other. (Cs-137 decay = Co-60
decay) Solve for t.
It will take approximately 35.4 years for both Cs-137 and Co-60 isotopes to decay until their activities are equal.
To determine the time it takes for both Cs-137 and Co-60 isotopes to decay until their activities are equal, we can use the decay function for each isotope and set them equal to each other.
The decay function for a radioactive isotope is given by:
A(t) = A₀ * exp(-λt)
Where:
A(t) is the activity at time t,
A₀ is the initial activity,
λ is the decay constant,
t is the time.
The decay constant (λ) can be calculated using the half-life (T₁/₂) of the isotope:
λ = ln(2) / T₁/₂
For Cs-137, the half-life is approximately 30.17 years, and for Co-60, the half-life is approximately 5.27 years.
Let's denote the time it takes for both activities to be equal as t_eq.
For Cs-137:
A(Cs-137) = 100 * exp(-0.693 / 30.17 * t_eq)
For Co-60:
A(Co-60) = 300 * exp(-0.693 / 5.27 * t_eq)
Setting the two equations equal to each other and solving for t_eq:
100 * exp(-0.693 / 30.17 * t_eq) = 300 * exp(-0.693 / 5.27 * t_eq)
Simplifying the equation:
1/3.0 * exp(-0.693 / 30.17 * t_eq) = exp(-0.693 / 5.27 * t_eq)
Taking the natural logarithm (ln) of both sides:
-0.693 / 30.17 * t_eq = -0.693 / 5.27 * t_eq
Solving for t_eq:
t_eq ≈ 35.4 years
It will take approximately 35.4 years for both Cs-137 and Co-60 isotopes to decay until their activities are equal. This calculation assumes that there is no other source of radiation or decay affecting the activities of the isotopes.
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The naproxen (Aleve) molecule has a carboxylic acid with a pka = 4.15. Blood pH is 7.4; stomach pH is 1.2. Which statement correctly describes the predominant form of naproxen molecules in these different environments?A. anion in bloodB. anion in stomachC. cation in stomach cation in blood D. neutral, but polar in both stomach and blood
A. anion in blood is the correct solution to this problem.
In blood, which has a pH of 7.4, the carboxylic acid group on the naproxen molecule will be deprotonated, forming the anion form of the molecule.
In the stomach, which has a pH of 1.2, the carboxylic acid group will remain protonated, forming the cation form of the molecule.
The statement "anion in stomach" is correct because at a low pH (such as in the stomach), the carboxylic acid group on the naproxen molecule is protonated and exists predominantly in the form of its conjugate acid, which is the anion. This is because the acid is donating a proton (H+) to the surrounding environment that has a high concentration of H+ ions. In contrast, in the blood, which has a higher pH, the naproxen molecule exists predominantly in its neutral form as the carboxylic acid group is deprotonated and does not donate a proton to the environment. Therefore, the statement "anion in stomach" correctly describes the predominant form of naproxen molecules in the stomach.
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