Tetraphosphorus trisulfide (P4S3) is used in the match heads of some matches. If 75.0-g of P4 is reacted with 55.0-g of S8, which is the limiting reactant and which is the excess reactant?8P4 + 3S8 ⇨ 8P4S3

As the compound has alkyne as the functional group the correct option is A.

Functional group is defined as a substituent or a group of atoms or an atom due to which chemical reactions are carried out. Each functional group will react in the same way regardless to the parent carbon chain to which it is attached.This helps in prediction of chemical reactions.

The reactivity of functional group is increased by making modifications in the functional group .Atoms that  are present in functional groups are linked to each other by means of covalent bonds.They are named along with the organic compounds according to IUPAC nomenclature.

As the compound has alkyne as the functional group the correct option is A.

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The Ca2+ concentration in a groundwater that is in equilibrium with calcite and has a PCO2 of 10-2.5 (atm) is 1.6 × 10-3 M.

The equilibrium expression for the dissolution of calcite (CaCO3) in water, assuming that CO2 is the only acidic gas present, is : CaCO3(s) + H2O + CO2(g) ↔ Ca2+(aq) + 2HCO3-(aq)

The equation for the relationship between the PCO2 of a gas and the concentration of dissolved CO2 in a solution in equilibrium with the gas is as follows : PCO2 = K(H2CO3) × [H2CO3] where,

K(H2CO3) is the Henry's law constant for CO2

H2CO3 is the concentration of dissolved CO2 in equilibrium with the gas.

We can estimate the concentration of H2CO3 as follows :

H2CO3 = α(CO2) × PCO2 where α(CO2) is the solubility coefficient of CO2 in water, which is a function of temperature, pressure, and salinity.

To solve the problem, we need to know the values of the following constants :

K(H2CO3) at 25 °C is 1.20 × 10-3 atm/(mol/L).

α(CO2) at 25 °C is 3.37 × 10-2 mol/L/atm.

Substitute the values into the equation :

PCO2 = K(H2CO3) × [H2CO3]10-2.5 atm = (1.20 × 10-3 atm/(mol/L)) × [H2CO3]

H2CO3 = (10-2.5 atm) / (1.20 × 10-3 atm/(mol/L)) = 8.33 × 10-3 M

Substitute the value of H2CO3 into the equilibrium expression and solve for the concentration of Ca2+ :

Ksp = [Ca2+][HCO3-]2 = 4.86 × 10-9

Ksp = [Ca2+][HCO3-]2[Ca2+] = Ksp / [HCO3-]2[Ca2+] = (4.86 × 10-9) / (8.33 × 10-3)2 = 1.6 × 10-3 M

Therefore, the Ca2+ concentration in a groundwater that is in equilibrium with calcite and has a PCO2 of 10-2.5 (atm) is 1.6 × 10-3 M.

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The atomic mass of manganese atom​ : 55

Given

Manganese (Mn) atom has 30 neutrons

atomic number 25

Required

the atomic mass

Solution

The atomic mass=number of protons+number of neutrons

The atomic number = number of protons=number of electrons

The number of protons=25, so the atomic mass :

\(\tt =ptotons+neutrons\\\\=25+30\\\\=55\)

Answer:

pH = 14

Explanation:

pOH = -log[OH-] = -log1,0 = 0

pH + pOH = 14

pH = 14 - pOH = 14 - 0 = 14

Answer:

Explanation:

hope it helps

The number of photons required with a wavelength of 749 nm are needed to melt 445 g of ice is 5.12 × 10²³.

The energy of one photon is given as,

E = (h × C) / λ

E = (6.626 × 10⁻³⁴ × 3 × 10⁸ m/s) / (749 nm × 10⁻⁹ nm/m)

⇒ E = 0.02653 × 10⁻¹⁷ = 2.65 × 10⁻¹⁹ J

The enthalpy of fusion of water is 333.55 J/g.

To melt 445 g of ice, the energy needed = 445 g × 333.55 J/g = 135755 J

Hence, the number of photons required = (135755 J) / (2.65 × 10⁻¹⁹)

                                                                   = 51228.301 × 10⁻¹⁹

                                                                   = 5.12 × 10²³

Hence the number of photons required is 5.12 × 10²³.

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Answer:

6

What do AIA, SAG, AFP and AMA all stand for? Select four options.

American Institute of Architects

American Society of Mechanical Engineers

American Medical Association

Screen Actors Guild

Association for Finance Professionals

Professional Colleges

Answer:    q = 64 kJ

Explanation:

As you know, a substance's specific heat tells you how much heat is required to increase the temperature of  

1 g

of that sample by  

1

∘

C

.

In water's case, you know that its specific heat is equal to  

4.18

J

g

∘

C

. This tells you that in order to increase the temperature of  

1 g

of water by  

1

∘

C

, you need to supply  

4.18 J

of heat.

How much heat would you need to increase the temperature of  

200 g

of water by  

1

∘

C

?

Well, if you need  

4.18 J

per gram to increase its temperature by  

1

∘

C

, it follows that you will need  

200

times more heat to get this done.

Likewise, if you were to increase the temperature of  

1 g

of water by  

76

∘

C

, you'd need  

76

times more heat than when increasing the temperature of  

1 g

by  

1

∘

C

.

Combine these two requirements and you get the total amount of heat required to increase the temperature of  

200 g

of water by  

76

∘

C

.

Mathematically, this is expressed using the following equation

q

=

m

⋅

c

⋅

Δ

T

, where

q

- heat absorbed/lost

m

- the mass of the sample

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

Plug in your values to get

q

=

200

g

⋅

4.18

J

g

∘

C

⋅

(

100

−

24

)

∘

C

q

=

63536 J

I'll leave the answer rounded to two sig figs and expressed in kilojoules

q

=

64 kJ

Biomass combustion is referred to as a process in which organic materials are burnt and their remains are used to produce energy.

The process of combustion is very simple it refers to the burning of biomass which include wood, farm waste, and crops which are further used to produce or generate energy in the form of electricity and also heat, it can be termed as renewable energy that utilized the energy of biomass to produce another form of energy.

The Grate furnace method is one of the common methods used for biomass combustion and comprises several steps for the recovery of energy.    

The first step consists of drying up the biomass by removing all the moisture using heat. The next step includes the production of flames and heat by combusting hydrogen present in it. After that, the remaining solid waste will undergo combustion in the presence of oxygen.

The last step includes the disposal of ash which gets accumulated due to incombustible materials like sand.

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Answer:

A. (g)

Explanation:

Since it asks for a gas, it is A.

Answer:

A (g)

Explanation:

Therefore, 16.6 grams of water when supplied with 348 J of heat will gain a temperature of 5.2°C.

To determine the number of grams of water (4.182 J/g°C) when supplied with 348 J of heat that will gain a temperature of 5.2°C,

we can use the formula,Q = m × c × ΔT,

where Q is the heat energy absorbed by the water,

m is the mass of water,

c is the specific heat capacity of water,

and ΔT is the change in temperature of the water.

We are given that Q = 348 J, c = 4.182 J/g°C, and ΔT = 5.2°C.

Substituting these values into the formula, we have:

348 J = m × 4.182 J/g°C × 5.2°C

So,m = 348 J / (4.182 J/g°C × 5.2°C)= 16.6 g

Therefore, 16.6 grams of water when supplied with 348 J of heat will gain a temperature of 5.2°C.

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The most likely volume of the sugar-water solution is 200 mL.

A solution is a homogeneous mixture composed of two or more substances that are uniformly distributed. In a solution, the particles of the different substances mix at a molecular level, resulting in a uniform appearance throughout the mixture.

In the given scenario, a student dissolves 40 mL of salt in 200 mL of water. When salt is added to water, it dissolves and forms a solution. The resulting volume of the solution is 240 mL.

To determine the most likely volume of the sugar-water solution, we need to consider that the initial volume of water was 200 mL. Since the salt is added to the water, it does not contribute to the total volume of the solution. Therefore, the volume of the sugar-water solution would be equal to the initial volume of water, which is 200 mL.

Based on the information provided, the most likely volume of the sugar-water solution is 200 mL. This is because the initial volume of water used to dissolve the sugar remains unchanged, and the salt added does not affect the overall volume of the solution.

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If the density of nickel is 8.9 g/cm3, it occupies 0.15 cubic decimeters in 1335 grams of nickel.

Density is defined as the mass of a unit volume of a material substance, the space occupied by the unit mass of a material. It is the degree of compactness measured by the quantity of mass per unit  volume.

density = mass/ volume

volume = mass/ density

here the given mass is = 1335 grams

and the density given is = 8.9

=1335/8.9

=150

therefore volume calculated is 150 cubic centimeter

1 cubic centimeter is equal to 0.001 cubic decimeter

150 cubic centimeter is equal to 0.15 cubic decimeter

If the density of nickel is 8.9 g/cm3, it occupies 0.15 cubic decimeters in 1335 grams of nickel.

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The depth (h) of the liquid in the spherical tank can be calculated using the formula: h = r - √(r² - v(3/(4πr³))).

The volume of a sphere is given by:

V = (4/3)πr³

If the sphere is filled with a volume v of liquid, then the volume of the liquid is equal to the volume of the sphere minus the volume of the empty space in the tank. The volume of the empty space in the tank is equal to the volume of a sphere with radius r - h.

The volume of the liquid in the tank is given by:

v = (4/3)πr³ - (4/3)π(r - h)³

Expanding the right-hand side of this equation, we get:

v = (4/3)πr³ - (4/3)πr³ + 4πrh² - 4πr³h

Combining like terms, we get:

v = 4πrh² - 4πr³h

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Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 3.5mole of Zn(NO\(_3\))\(_2\) form 7.0 mol AgNO\(_3\) is produced.

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.

The balanced equation for 7.0 mol AgNO\(_3\) reaction with 3.0 mol Zn in

a single replacement reaction is

2AgNO\(_3\) + Zn → 2Ag + Zn(NO\(_3\))\(_2\)

moles of AgNO\(_3\) = 7.0 mol

The mole ratio between AgNO\(_3\) and Zn(NO\(_3\))\(_2\) is 2:1

from 2 moles of AgNO\(_3\), 1 mole of Zn(NO\(_3\))\(_2\)

from 1 moles of AgNO\(_3\), 1/2 mole of Zn(NO\(_3\))\(_2\)

from 7.0 moles of AgNO\(_3\), (1/2)× 7.0=3.5mole of Zn(NO\(_3\))\(_2\)

Therefore, 3.5mole of Zn(NO\(_3\))\(_2\) form 7.0 mol AgNO\(_3\) is produced.

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Answer:

wow ok have fun

Explanation:

Answer:

hiiiiiiiii

Explanation:

thank you

aqueous Magnesium Chloride reacts with liquid Bromide to form aqueous Magnesium Bromide and Chlorine gas

Answer:

It is important to identify it because the two types of crust are made up of two different types of rock

Explanation:

Have a nice day

Answer:

The atomic weight Ar, of M is 64

Explanation:

The formula of the given compound is M(OH)₂

Mr, is the molecular weight of a compound and for the given compound, Mr is equal to 98.

Ar, is the atomic weight of the elements in the compound

The molecular weight, Mrof a compound is the mass of one mole mole of that compound. It can be obtained by summing the atomic masses of all elements in that compound. For elements that has more than one atom in the compound, the atomic weight of that element is multiplied by the number of atoms of the element present in the compound and then the sum of the weight of each element gives the molecular weight of the compound.

Onnthe compound above,the atomic weight of the unknown element M, is to be obtained.

Ar of the other elements inn he compound is given : Ar of O = 16, Ar of H = 1.

Molecular weight of the compound, Mr = 98

Calculating for the Ar of M:

(M × 1) + (16 × 2) + (1 × 2) = 98

M +32 + 2 = 98

M + 34 = 98

M = 98 -34

M = 64

Therefore, the atomic weight Ar, of M is 64

Answer:

C. Calorimeter

Explanation:

Pipette transfers liquid, a hot plate heats things up like a stovetop, and a tripple-beam balance is a scale.

Answer:

It is a Calorimeter. 100%

The group 1 element; the alkali metals which are lithium, sodium and potassium have a pattern of reactivity such that they produce alkali when they dissolve in water.

The chemical equation is given below:

Na(s) + H2O(l) --- NaOH(aq) + H2(g)

K(s) + H2O(l) --- KOH(aq) + H2(g)

These are the metals which belong to the group 1 of the periodic table. They are called alkali metals because when they react with water, they produce soluble hydroxide known as alkali. For this reason, they are referred to as alkali metals.

So therefore, the group 1 element; the alkali metals which are lithium, sodium and potassium have a pattern of reactivity such that they produce alkali when they dissolve in water.

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The fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

Fugacity is a measure of the escaping tendency of a component in a mixture, which is defined as the pressure that the component would have if it obeyed ideal gas laws. It is used as a correction factor in the calculation of equilibrium constants and thermodynamic properties such as chemical potential. Here we need to determine the fugacity in atm for pure ethane at 310 K and 20.4 atm and the change in the chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm. So, using the formula of fugacity: f = P.exp(Δu/RT) Where P is the pressure of the system, R is the gas constant, T is the temperature of the system, Δu is the change in chemical potential of the system.  Δu = RT ln (f / P)The chemical potential at the initial state can be calculated using the ideal gas equation as: PV = nRT    

=>  P

= nRT/V

=> 20.4 atm

= nRT/V

=> n/V

= 20.4/RT The chemical potential of the system at the initial state is:

Δu1 = RT ln (f/P)

= RT ln (f/20.4) Also, we know that for a pure substance,

Δu = Δg. So,

Δg1 = Δu1 The change in pressure is 24 atm – 20.4 atm

= 3.6 atm At the second state, the pressure is 24 atm.

Using the ideal gas equation, n/V = 24/RT The chemical potential of the system at the second state is: Δu2 = RT ln (f/24) = RT ln (f/24) The change in chemical potential is Δu2 – Δu1 The change in chemical potential is

Δu2 – Δu1 = RT ln (f/24) – RT ln (f/20.4)

= RT ln [(f/24)/(f/20.4)]

= RT ln (20.4/24)

= - 0.0911 RT Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is:

f = P.exp(Δu/RT)

=> f

= 20.4 exp (-Δu1/RT)

=> f

= 20.4 exp (-Δg1/RT) And, the change in the chemical potential between this state and a second state of ethane where the temperature is constant but pressure is 24 atm is -0.0911RT. Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

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The NaOH solution has a 2.39 M concentration.

The proportion of the solute that is dissolved in a solution is indicated by the solution's concentration. This formula can be used to determine a solution's concentration: Concentration is calculated as Volume of Solute multiplied by 100 and Volume of Solution. (ml).

First, by dividing the mass of NaOH by its molar mass, we may determine how many moles of NaOH there are:

NaOH has a molar mass of 40.0 g/mol (23.0 g/mol for Na, 16.0 g/mol for O, and 1.0 g/mol for H).

moles of NaOH = 95.7 g / 40.0 g/mol

moles of NaOH = 2.39 mol

the volume of the solution in liters:

concentration of NaOH solution = moles of NaOH / volume of solution

concentration of NaOH solution = 2.39 mol / 1.00 L

concentration of NaOH solution = 2.39 M

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Answer: Whats ur Question?

Explanation:

The energy of a photon whose wavelength is 0.61 μm is 3.25 * 10⁻¹⁹J.

The energy that a single photon carries is known as photon energy.

Energy is inversely correlated with wavelength because it is directly proportional to the electromagnetic frequency of the photon. The energy of a photon increases with its frequency.

The formula for calculating the energy of a photon, E, is given below:

E = hc/λ

where:

h is Planck's constant = 6.626 * 10⁻³⁴ Js

c is the speed of light = 3.0 * 10⁸m/s

λ is the wavelength of the photon = 0.61 μm or 6.10 * 10⁻⁷ m

E = 6.626 * 10⁻³⁴ * 3.0 * 10⁸ / 6.10 * 10⁻⁷ m

E = 3.25 * 10⁻¹⁹J

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Answer:

2.38 g of oxygen (O2).

Explanation:

What is given?

Mass of potassium chlorate (KClO3) = 6.06 g.

Molar mass of KClO3 = 122.4 g/mol.

Molar mass of oxygen (O2) = 32 g/mol.

Step-by-step solution:

First, let's state the balanced chemical equation. Remember that the decomposition of a compound produces two or more products:

Now, let's convert 6.06 g of KClO3 to moles using its molar mass:

You can see in the chemical equation that 2 moles of KClO3 produce 3 moles of O2. By doing a rule of three with this data, we obtain that:

The final step is to convert from 0.0743 moles of O2 to grams using its molar mass, like this:

The answer is that we will produce 2.38 g of oxygen (O2) from the decomposition of 6.06 g of potassium chlorate (KClO3).

Perchlorate is used in rocket fuel affects the thyroid gland.

Perchlorate, a chemical substance used in rocket fuel, fireworks, fertilisers, and other products, is one such contaminant.

Since it prevents the sodium/iodide symporter (NIS), a protein that transports iodide into the thyroid and other tissues, perchlorate is associated with thyroid disorders. Hypothyroidism, which can be brought on by decreased iodide uptake, can be extremely harmful for infants since it directly impacts how they develop in numerous ways.

Thyroxine (also known as T4), a relatively inactive prohormone, and triiodothyronine, a highly active hormone, are both produced by the thyroid gland (referred to as T3). The thyroid hormones are thyroxine and triiodothyronine taken together.

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The complete question is

Which chemical used in rocket fuel affects the thyroid gland?

A. Reproductive hormones

B. DDT

C. PCBs

D. PBDEs

E. Perchlorates

Answer:

C: checking your email

Explanation:

I believe that C would be impossible, as you cannot use wireless networks without radio waves

Answer:

A, And D

Explanation:

I did this before and i got it right ❤