Tell me something funny and I’ll mark you brainliest!

Answer:

8 could be the answer of this but im not sure

Answer:

.

Step-by-step explanation:

1st option. -27. is the answer

Answer: -22.5

Step-by-step explanation:

-12.5+(-10)=

-12.5-10=

-22.5

Using normal distribution,

1. The z-score of 90 is -0.67 for the population mean of 100 and standard deviation of 15.

2. The proportion of scores below 128 is approximately 0.9693 or 96.93%.

1. To find the z-score of 90 using the population mean of 100 and standard deviation of 15, we can use the formula:

z = (x - μ) / σ

where x is the value we want to convert to a z-score, μ is the population mean, and σ is the population standard deviation.

Plugging in the values, we get:

z = (90 - 100) / 15 = -0.67

Therefore, the z-score of 90 is -0.67.

2. To find the proportion of scores below 128 using the population mean of 100 and standard deviation of 15, we need to first find the z-score of 128 and then use a z-table to find the proportion below that z-score.

The z-score of 128 is:

z = (128 - 100) / 15 = 1.87

Using a standard normal distribution table or calculator, we can find that the proportion below a z-score of 1.87 is approximately 0.9693.

Therefore, the proportion of scores below 128 is approximately 0.9693 or 96.93%.

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Answer:

Awwww

Step-by-step explanation:

Thank you! I hope you know that as well :). I really needed that today so thank you

Answer:

(-7, 3)

Step-by-step explanation:

-6-1=-7  2+1=3

Answer:

The number has to be less than 3.

Step-by-step explanation:

Some examples:

3 - (-5) = 3 + 5 = 8, a positive difference

3 - 0 = 3, a positive difference

3 - 1 = 2, a positive difference

3 - 3 = 0, NOT a positive difference. 3 is where the difference switches from positive to negative.

3 - 4 = -1, NOT a positive difference.

The general solution of the given differential equation:

1. \(y(t) = C_1 cos(t) + C_2 sin(t) - ln|sec(t)|\),

2. \(y(t) = C_1 + C_2 e^t + C_3 e^{-t} + t\),

3. \(y(t) = C_1 e^{-t)} + C_2 e^t + (1/10) e^{4t} - (1/5) t e^{4t}\),

4. \(y(t) = C_1 e^t + C_2 e^{-t} + (1/2) e^{sin(t)} - 17\).

1. For the differential equation y" + y' = tan(t), the general solution using the method of variation of parameters is:

  \(y(t) = C_1 cos(t) + C_2 sin(t) - ln|sec(t)|\)

2. For the differential equation y'"' - y' = 1, the general solution using the method of variation of parameters is:

  \(y(t) = C_1 + C_2 e^t + C_3 e^{-t} + t\)

3. For the differential equation \(y'' - 2y" - y' + 2y = e^{4t}\), the general solution using the method of variation of parameters is:

  \(y(t) = C_1 e^{-t)} + C_2 e^t + (1/10) e^{4t} - (1/5) t e^{4t}\),

4. For the differential equation \(y'' - y" + y - y = e^{-sin(t)} - 17\), the general solution using the method of variation of parameters is:

  \(y(t) = C_1 e^t + C_2 e^{-t} + (1/2) e^{sin(t)} - 17\).

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Answer:

Step-by-step explanation:

step 2, addition

step 4 multiplication

Answer:

x=-3

Step-by-step explanation:

The correct option is (C) Isosceles. An Isosceles triangle can be constructed with a 50° angle between two 8-inch sides.

This is because isosceles triangle having two sides that are equal in length, and have 50° angle, which is acute angle, that is less than 90°. This state that the remaining angle in the triangle must also be acute triangle, as the sum of all angles in a triangle must equal 180°.

This means that the remaining angle must be 80° (i.e. 180 - 50 = 80). An isosceles triangle is triangle consisting of  two sides of equal length and two angles of equal measure. The two equal sides that make up the isosceles triangle are referred to as the base and the remaining side is height or altitude.

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Using probability we know that there is a 43% chance that the 27th person in the line would be a boy.

Probability is simply the possibility that something will happen. When we don't know how something will turn out, we can talk about the possibility of one outcome or the likelihood of several.

The study of events that fit into a probability distribution is known as statistics.

So, we know that:

The boys are 17.

The girls are 22.

Probability formula: P(E) = Favourable events/Total events

Then, the probability that the 27th person is a boy:

P(E) = Favourable events/Total events

P(E) = 17/39

P(E) = 0.43

P(E) = 43%

Therefore, using probability we know that there is a 43% chance that the 27th person in the line would be a boy.

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Answer: 105

Step-by-step explanation: Skate World offers birthday parties for a fee of $180 plus $2 per person. If you can spend no more than $210 on

your party, what is the maximum number of people who (can) attend?

The keyword "can" is telling us to basically tell us to find how much people (can) attend. Not how much will attend.

210/2=105

The given series is ∑(n=0 to infinity) ((-1)^n * 5^n * x^4n) / n!. This is the Maclaurin series expansion of the function f(x) = e^(-5x^4).

By comparing with the Maclaurin series expansion of e^x, we can see that the sum of the given series is f(1) = e^(-5).
Therefore, the sum of the series is e^(-5).
The given series is a sum of terms in the form:
Σ(−1)^n * 5n * x^(4n) * n! for n = 0 to ∞
Unfortunately, this series does not have a closed-form expression or a simple formula for finding the sum, since it involves alternating signs, factorials, and exponential terms. To find an approximate sum, you can calculate the first few terms of the series and observe the behavior or use numerical methods to estimate the sum.

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From the formula of expansion series for \(e^x\), the sum of series, \(\sum_{n = 0}^{\infty} (-1)^n \frac{5^n x^{4n}}{n!} \\ \) is equals to the \( e^{-5x⁴}\).

A series in mathematics is the sum of the serval numbers or elements of the sequence. The number or elements are called term of sequence. For example, to create a series from the sequence of the first five positive integers as 1, 2, 3, 4, 5 we will simply sum up all. Therefore, the resultant, 1 + 2 + 3 + 4 + 5, form a series. We have a series, \(\sum_{n= 0}^{\infty} (-1)^n \frac{5^n x^{4n}}{n!} \\ \).

The sum of a series means the total list of numbers or terms in the series sum up to. Using the some known formulas of series, like \(1 + x + \frac{x²}{2!} + ... + \frac{x^n}{n!}+ ... = \sum_{n = 0}^{\infty } \frac{ x^n}{n!} = e^x \\ \) Similarly, \(1 - x + \frac{x²}{2!} - ... + \frac{x^n}{n!}+ ... = \sum_{n = 0}^{\infty } (-1)^n \frac{ x^n}{n!} = e^{-x } \\ \) Rewrite the expression for provide series as \(\sum_{n = 0}^{\infty} (-1)^n \frac{(5x⁴)^n}{n!} \\ \). Now, comparing this series to the series of e^{-x}, here x = 5x⁴ so, we can write the sum of series as \(\sum_{n = 0}^{\infty} (-1)^n \frac{(5x⁴)^n}{n!} = e^{-5x⁴} \\ \). Hence, required value is \(e^{ - 5x^{4} } \).

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Complete question:

find the sum of the series

\(\sum_{n = 0}^{\infty} (-1)^n \frac{5^n x^{4n}}{n!} \\ \).

The value of opposite side of angle θ would be,

⇒ EF

Since, A triangle is a three sided polygon, which has three vertices and three angles which has the sum 180 degrees.

We have to given that,

A right triangle EFD is shown in figure.

And, At angle E, right angle is shown.

We know that;

The Opposite side of a angle is called perpendicular side.

Hence, The value of opposite side of angle θ would be,

⇒ EF

Thus, Option A is true.

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The maximum strut load is 70.87 kN. The maximum strut load can be calculated using the following equation: Maximum strut load = 2 * unit weight * gravity * depth * sin(friction angle) * cos(friction angle)

In this case, the unit weight is 20 kN/m3, the gravity is 9.81 m/s^2, the depth is 7.5 m, and the friction angle is 36°. Plugging these values into the equation, we get the following:

Maximum strut load = 2 * 20 * 9.81 * 7.5 * sin(36°) * cos(36°) = 70.87 kN

Therefore, the maximum strut load is 70.87 kN.

The maximum strut load occurs at the first row of struts, which is installed at a depth of 0.5 m below ground surface. The strut load decreases with depth, and the maximum strut load is reached at the first row of struts.

The strut load is caused by the weight of the soil above the struts. The soil above the struts exerts a lateral force, which is resisted by the struts. The maximum strut load occurs when the lateral force is at its maximum.

The maximum strut load is an important design consideration for braced cuts. The strut load must be able to be safely carried by the struts. If the strut load is too high, the struts may buckle or fail.

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Answer:

$0.33 per ball

Step-by-step explanation:

haha we meet again.

Divide 1.33 by 4

1.33/4=0.3325

Round to the nearest tenth

0.33

The length of time for one individual to be served at a cafeteria follows an exponential distribution with a mean of 4 minutes.

In an exponential distribution, the probability density function (PDF) is given by:

f(x) = (1/μ) * e^(-x/μ)

Where μ is the mean of the distribution. In this case, the mean is 4 minutes. Therefore, the PDF for the length of time for one individual to be served at the cafeteria can be expressed as:

f(x) = (1/4) * e^(-x/4)

The exponential distribution is commonly used to model the time between events in a Poisson process. In this case, it represents the time it takes for an individual to be served at the cafeteria, with an average of 4 minutes.

The exponential distribution is characterized by the property of memorylessness, which means that the probability of an event occurring in the next interval of time is independent of how much time has already elapsed. In the context of the cafeteria, this property implies that the probability of an individual being served in the next minute is the same, regardless of how much time has already passed.

It's important to note that the exponential distribution is only valid for non-negative values of x, as it represents a continuous random variable. The distribution is skewed to the right, with a longer tail on the positive side. The mean (μ) and standard deviation (σ) of the exponential distribution are equal and can be calculated as 1/λ, where λ is the rate parameter of the distribution.

In summary, the length of time for one individual to be served at the cafeteria follows an exponential distribution with a mean of 4 minutes. The probability density function (PDF) for this distribution is given by f(x) = (1/4) * e^(-x/4), where x represents the time in minutes.

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The value of ACD of a trapezium is 26.56°.

Let ABCD be a trapezoid with BCǀǀAD and AB=BC=CD= ½ AD.

ACD can be determined by using the Pythagorean theorem or using the theorem of Pythagoras.

The theorem of Pythagoras states that if you draw a right-angled triangle with the hypotenuse as c and the legs a and b.

The sum of squares of the legs (a and b) equals the square of the hypotenuse (c).

Therefore, by using the Pythagorean theorem ; AC² = AB² + BC²

=> AC² = (1/2 AD)² + (1/2 AD)²

=> AC² = 1/4 AD² + 1/4 AD²

=> AC² = 1/2 AD².

Hence,AC² = 1/2 AD²

ACD is a right-angled triangle where AC is the hypotenuse.

Thus, using the theorem of Pythagoras, we can write: AD² = AC² + CD²

=> AD² = [√(1/2 AD²)]² + (AD/2)²

=> AD² = 1/2 AD² + 1/4 AD²

=> AD² = 3/4 AD²=> AD = √4/3 AD

Thus, ACD=ACD = tan¯¹(√1/2 AD²/AD/2) = tan¯¹(√2/4) = 26.56°

Therefore, ACD is 26.56°.

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Answer:

He has 7

Step-by-step explanation:

5 plus 2 equals 7

Answer:

7 apples

Step-by-step explanation:

5 + 2 = 7

The number of tractors lent by the first, second and third stations results in a system of three simultaneous equations which indicates;

The first originally station had 39 tractors, the second station had 21 tractors and the third station originally had 12 tractors

Simultaneous equations are a set of two or more equations that have common variables.

Let x represent the number of tractors at the first station, let y represent the number of tractors at the second tractor station, and let z, represent the number of tractors at the third tractor station

According to the details in the question, after the first transaction, we get

Number of tractors at the first station = x - y - z

Number of tractors at the second station = y + y = 2·y

Number of tractors at the third station = z + z = 2·z

After the second transaction, we get;

Number of tractors at the first station = 2·x - 2·y - 2·z

Number of tractors at the second station = 2·y - (x - y - z) - 2·z = 3·y - x - z

Number of tractors at the third station = 2·z + 2·z = 4·z

After the third transaction, we get;

Number of tractors at the first station = 2 × (2·x - 2·y - 2·z) = 4·x - 4·y - 4·z

Number of tractors at the second tractor station = 6·y - 2·x - 2·z

Number of tractors at the third tractor station = 4·z - (2·x - 2·y - 2·z) - (3·y - x - z) = 7·z - x - y

The three equations after the third transaction are therefore;
4·x - 4·y - 4·z = 24...(1)

6·y - 2·x - 2·z = 24...(2)

7·z - x - y = 24...(3)

Multiplying equation (2) by 2 and subtracting equation (1) from the result we get;

12·y - 4·x - 4·z - (4·x - 4·y - 4·z) = 16·y - 8·x = 48 - 24 = 24

16·y - 8·x = 24...(4)

Multiplying equation (3) by 2 and multiplying equation (2) by 7, then adding both results, we get;

14·z - 2·x - 2·y = 48

42·y - 14·x - 14·z = 168

42·y - 14·x - 14·z + (14·z - 2·x - 2·y) = 48 + 168

40·y - 16·x = 216...(5)

Multiplying equation (4) by 2 and then subtracting the result from equation (5), we get;

40·y - 16·x - (32·y - 16·x) = 216 - 48 = 168

8·y = 168

y = 168/8 = 21

The number of tractors initially at the second station, y = 21

16·y - 8·x = 24, therefore, 16 × 21 - 8·x = 24

8·x = 16 × 21 - 24 = 312

x = 312 ÷ 8 = 39

The number of tractors initially at the first station, x = 39

7·z - x - y = 24, therefore, 7·z - 39 - 21 = 24

7·z = 24 + 39 + 21 = 84

z = 84/7 = 12

The number of tractors initially at the third station, z = 12

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Answer:

Can you reformat?

So far, 0 is a solution to none of these.

Answer:

1. nope

2. not sure

3. nope

Step-by-step explanation:

1.

-3(y - 1) > 3

-3y + 3 > 3

-3y > 0

y > 0

0 is not a solution since 0 is not greater than 0

2.

I'm not sure what this question means, is there a \(\geq or \leq\) between the 4 and the 0?

3.

y + 8 < 2y + 8

8 < 2y - y + 8

8 - 8 < y

0 < y

0 is not a solution because 0 is not greater than 0

im confused- I prolly got something wrong.

Answer:

-10 3/4

Step-by-step explanation:

I think it's that

Answer:

-10 3/4:)

Step-by-step explanation:

Answer:

I dont now what is that?????

Answer:

67%

Step-by-step explanation:

This is because 67% is basically 67/100 as a fraction and 3/5 is only 60%, all you need to know is the facts about fraction to percentage

The chance model asserts that the long-run proportion of an event is equal to the probability of that event. In other words, if we repeatedly conduct an experiment under the same conditions, the proportion of times that the event occurs over the long run should converge to the probability of the event.

For example, if we flip a fair coin many times, the chance model asserts that the proportion of heads should approach 0.5 as the number of coin flips increases. This is because the probability of flipping heads on a fair coin is 0.5, and over the long run, the proportion of heads should converge to this probability.

The chance model is a fundamental principle in probability theory, and it is used to make predictions about the outcomes of random events. It provides a way to quantify the uncertainty associated with an event and to reason about the likely outcomes of an experiment.

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Answer:

The first x is 9

The second x is -5

Step-by-step explanation:

Problem 1.

The initial sample of deer was 70, and all were tagged. The second event captured 30 and found 7 out of them tagged. Therefore, if we consider that 7 out of 30 was the ratio that represents the proportion of tagged to total, then we can write the following proportion to estimate the number(X) of deer in the population:

7 / 30 = 70 / X

where X can be solve by cross multiplying:

X = 70 * 30 / 7 = 300 deer.

Problem 2.

34% of 785 students ride theit bicycles to school, That is (recalling that 34% is written as 0.34 in decimal form):

0.34 * 785 = 266.9 so about 267 students ride their bicycles to school

We can conclude that neither of the quadrilaterals is a scaled copy of the other, for the given side lengths.

Quadrilateral a has side lengths 2, 3, 5 and 6 and Quadrilateral b has side lengths 4, 5, 8 and 10. We need to check if one of the quadrilaterals is a scaled copy of the other.

A scaled copy is an object with the same shape but a different size. That means the angles in the shape are the same, and the sides are proportional to one another.

A quadrilateral with side lengths 2, 3, 5 and 6 can be constructed using two pairs of sides with equal length, but the two pairs are not equal in length.

So, the quadrilateral with side lengths 2, 3, 5 and 6 cannot be a scaled copy of the quadrilateral with side lengths 4, 5, 8 and 10.

For the quadrilateral to be a scaled copy of the other, all the sides of one must be proportional to the corresponding sides of the other. But this is not the case in the given problem because the sides in both quadrilaterals are not proportional to each other.

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