Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 5 minutes. Determine the probability that the child must wait between 4 and 6 minutes on the bus on a given morning.
a) 0.3519
b) 0.8519
c) 0.3481
d) 0.4493
e) 0.1481
f) None of the above

Answers

Answer 1

The answer is (c) 0.3481.

The probability density function of the waiting time is given by:

f(x) = (1/5) * e^(-x/5), for x >= 0

To find the probability that the child must wait between 4 and 6 minutes, we need to integrate the probability density function over this interval:

P(4 <= x <= 6) = ∫(4 to 6) f(x) dx

= ∫(4 to 6) (1/5) * e^(-x/5) dx

= [-e^(-x/5)] from 4 to 6

= -e^(-6/5) + e^(-4/5)

Using a calculator, we get:

P(4 <= x <= 6) ≈ 0.3481

Therefore, the answer is (c) 0.3481.

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Related Questions

Help help help fast plz plz this is graded

Help help help fast plz plz this is graded

Answers

Answer:

120

Step-by-step explanation:

First, you notice that both the angles add up to 180 degrees because it is a straight line.  Therefore, 2x+x+90=180.  Now you have an equation to solve!  Subtract 90 from both sides and combine like terms.  3x=90.  Therefore, x=30.  Now you plug x back in to find out m<DBC.  DBC=x+90 which is 30+90= 120.  

(2x)+ (x+90) = 180

3x + 90 = 180

180-90 = 90

3x = 90

x = 30

angle DBC = (30)+90

angle DBC = 120 degrees

A school day starts at 08:50 hrs. and ends at 15:00 hrs. There are two breaks. One lasting 20 minutes and the other 1 hour. How much time is devoted to school activities?

Answers

Answer:

4:50 hrs to school activities

Step-by-step explanation:

the entire school day 6:10 hrs (with breaks)

so if we remove the breaks (which are 1:20hrs in total) we'll have 4:50hrs.

the equation would be: (the time the full day is)-(the total of breaks)= the school activity time.

so: 6:10hrs-1:20hrs= 4:50hrs

there's your answer. 4:50 hrs

*just remember i am working in the hrs format meaning 60 mins= 1hrs*

What is x=(15)(sin(45°))

Answers

Answer:

x  =  10.60660171

x  =  15 √ 2  over 2

Step-by-step explanation:

I need help with this!

I need help with this!

Answers

Answer:

-0.5

Step-by-step explanation:

\(\frac{f}{g} =\frac{f(n)}{g(n)} = \frac{4n}{n^2-3n}\)

\(\frac{4(-5)}{(-5)^2-3(-5)} =\frac{-20}{40} =\frac{-1}{2}\)

5 minus 5 is 2 of 2 plus 2/2

the sum of 8 and -13.

Answers

Answer:

-104 is the answer .....

(a) What can yoU say about a solution of 'the equation y' (1/2)y2 just by looking at the differential equation? The function Y must be decreasing (or equal to 0) on any interval on which it is defined. The function Y must be increasing (or equal to 0) on any interval on which it is defined_ (b) Verify that all members of the family y = 2/(x + C) are solutions of the equation in part (a)_ (c) Find a solution of the initial-value problem: y? . y (0) = 0.5 y (1)

Answers

The solution to the initial-value problem y' = (1/2)y2, y(0) = 0.5y(1) is y = -2/x + 4.

a. Differential equations are used to model change. They represent the change in a variable y with respect to the change in another variable x. By looking at the differential equation of the form y' = ky, where k is a constant, you can say that the solution of the equation y is decreasing (or equal to 0) on any interval on which it is defined.

b. The given family of solutions y = 2/(x + C) is of the form y = k/(x + C), where k = 2 is a constant and C is the arbitrary constant of integration. The derivative of y with respect to x is y' = -k/(x + C)

2. Substituting this into the given differential equation y' = ky, we have:-k/(x + C)2 = k/k(x + C)y, which simplifies to y = 2/(x + C).

Therefore, all members of the family y = 2/(x + C) are solutions of the given differential equation.

c. To find a solution of the initial-value problem y' = (1/2)y2, y(0) = 0.5y(1), we need to solve the differential equation and use the initial condition y(0) = 0.5y(1).

Separating the variables and integrating both sides, we get:

dy/y2 = (1/2)dx.

Integrating both sides, we get:-1/y = (1/2)x + C, where C is the constant of integration.

Solving for y, we get:

y = -1/(1/2)x - C = -2/x - C.

We know that y(0) = 0.5y(1), so substituting x = 0 and x = 1 in the solution above, we get:-2/C = 0.5y(1), and y(1) = -2 - C.

Substituting C = -4, we have y = -2/x + 4. Therefore, the solution to the initial-value problem y' = (1/2)y2, y(0) = 0.5y(1) is y = -2/x + 4.

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(a) Given differential equation is `(1/2) y²`. For a solution of differential equation `y = f(x)`, the function `y = f(x)` must satisfy the differential equation.  

By looking at the differential equation, we can say that the function Y must be decreasing (or equal to 0) on any interval on which it is defined. Thus, the correct option is (A).

The differential equation is `(1/2) y²`. Let `y = f(x)`, then `(1/2) y²` can be written as,`dy/dx = y dy/dx`Dividing by `y²`, we get,`dy/y² = dx/2`Integrating both sides, we get,`-1/y = (x/2) + C`

Where C is the constant of integration. Rearranging the terms, we get,`y = -2/(x + C)`

This is the general solution of the differential equation. Now, we need to verify that all members of the family `y = 2/(x + C)` are solutions of the equation in part (a).(b) Let `y = 2/(x + C)`, then `y' = -2/(x + C)²`.

Substituting these values in the differential equation, we get,`(1/2) [2/(x + C)]² (-2/(x + C)²) = -1/(x + C)²`Simplifying, we get,`-1/(x + C)² = -1/(x + C)²`This is true for all values of x.

Hence, all members of the family `y = 2/(x + C)` are solutions of the equation in part (a).(c) We need to find a solution of the initial-value problem: `y' = y²/2, y(0) = 0.5 y(1)`.

We know that `y = 2/(x + C)` is the general solution of the differential equation. To find the particular solution that satisfies the initial condition, we substitute `x = 0` and `y = 0.5 y(1)` in the general solution, we get,`0.5 y(1) = 2/(0 + C)`or, `C = 4/y(1)`

Substituting this value of C in the general solution, we get,`y = 2/(x + 4/y(1))`

Hence, the solution of the initial-value problem is `y = 2/(x + 4/y(1))`.

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Jesse has a 20 cm tall can of juice concentrate with a base that has a diameter of 7.5 Cm. The instructions say to mix the contents of the can with three cans of water. How many liters of juice can Jesse make?

Answers

Jesse can make 3.3141 liters of juice.

First, we need to calculate the volume of the can of juice concentrate:

The radius of the circular base is half the diameter, so r = 7.5 / 2 = 3.75 cm

The volume of a cylinder is V = πr^2h, where h is the height of the cylinder.

So, the volume of the can is

V = π(3.75 cm)^2(20 cm) ≈ 4,418.77 cubic centimeters.

Next, we need to calculate the volume of one can of water. We know that Jesse needs to mix the contents of the can of juice concentrate with three cans of water, so the total volume of the juice will be four times the volume of the can of juice concentrate.

To convert cubic centimeters to liters, we divide by 1000. So, the volume of the can of juice concentrate in liters is V = 4,418.77 / 1000 = 4.41877 liters.

Divide this by 4 to get the volume of one can of juice: 4.41877 / 4 = 1.1047 liters.

Therefore, Jesse can make 3 cans of water x 1.1047 liters per can = 3.3141 liters of juice.

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Helllllppppppppppppp brainliest will happen if right

Helllllppppppppppppp brainliest will happen if right

Answers

12 + 1(h) = the average amount

h = hour (how many hours it’s snowed)


You are given that f(x)=x²+4 and g(x)=3 x-1 .

c. What is the domain of your answer to part (b)?

Answers

The required domain of g ( x ) = 3 x - 1 is R ( real nos . ) .

Given : g ( x ) = 3 x - 1

To find : Domain of function

Domain : The set of all possible values of input variable  ( x in this case ) is called the domain of the function .

Calculating domain :

g ( x ) = 3 x - 1

Since , it is a polynomial function with degree 1 , therefore it's domain will be real nos .

Hence , domain of g ( x ) = 3 x - 1 is R .

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Varuns monthly income is 18000 he spends 1/5 of his income for house rent and 3/5 of his income on other expenditure how much does he save every month

Answers

Answer:

$3600

Step-by-step explanation:

Given:

Total income T = $18,000

Fraction of income spent on house rent f1 = 1/5

Fraction of income spent on other expenditures f2 = 3/5

Fraction of income saved is;

f = 1 - (1/5+3/5) = 1 - 4/5

f = 1/5

The Amount he save is A;

A = fraction saved × total amount = f × T

Substituting the values

A = 1/5 × $18,000

A = $3,600

The Amount he save is $3,600

Answer: Varun saves 3,600 every month

Step-by-step explanation: Varun's income in the first instance is fixed at 18000, and out of this amount he spends 1/5 on house rent. We shall now determine the amount represented by 1/5 as follows;

Total income = 18000

House rent = 1/5

Rent expense = 1/5 of 18000

Rent expense = 1/5 * 18000

Rent expense = 3600

he also spends 3/5 on other expenditure

Other expenditure = 3/5 of 18000

Other expenditure = 3/5 * 18000

Other expenditure = (3 * 18000)/5

Other expenditure = 54000/5

Other expenditure = 10800

His expenses therefore have been derived as

Total expenditure = 3600 + 10800

Total expenditure = 14400

His savings per month therefore is derived as;

Total income - total expenditure = savings

18000 - 14400 = savings

3600 = savings

Therefore, Varun saves 3,600 every month

A direct relationship between two variables is reflected in a(n) _____ correlation coefficient.

Answers

A direct relationship between two variables is reflected in a "POSITIVE" correlation coefficient.

Correlation is a statistical technique for measuring and describing the relationship between two variables.

The variables move in the same direction when they have a positive correlation. In other words, as one variable increases, so does the other, and conversely, as one variable decreases, so does the other.

Typically, the two variables are simply observed rather than manipulated. Two scores from the same individuals are required for the correlation.

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What is the angle of elevation to the nearest tenth of a degree to the top of a 55ft building from 95ft away? Please help fast.

What is the angle of elevation to the nearest tenth of a degree to the top of a 55ft building from 95ft

Answers

Answer:

30.1°

Step-by-step explanation:

Let A = angle of elevation

tan A = 55/95

A = arctan 55/95

    = 30.1°

According to the Centers for Disease Control and Prevention, 21. 4% of school-aged children

aged 6-11 years, were overweight in 2010. [Correct your answers to 4 decimal places]

a) Show that the shape of the sampling proportion is approximately normal for 98 school-aged

children, aged 6-11 years. [3 pts. ]

b) State the mean and the standard deviation of the sampling proportion if a random sample of 98

school-aged children aged 6-11 years were sampled. [4 pts. ]

c) In a random sample of 98 school-aged children, aged 6-11 years, what is the probability that at least

23% are overweight? [4 pts. ]

d) Suppose a random sample of 98 school-aged children, aged 6-11 years results in 20 overweight

children. What might you conclude? [4 pts. ]

e) Find the margin of error E that corresponds to a 95% confidence level of the 98 school-aged

children aged 6-11 years? [4 pts. ]

2 | P a g e

f) Find the 95% confidence interval estimate of the population proportion p? [4 pts. ]

g) Based on the results in f) can we safely conclude that more than 28% of school-aged children, aged

6-11 are overweight? Explain. [4 pts. ]

h) Assuming that you are a newspaper reporter, write a brief statement that accurately describes the

results in g) and includes all of the relevant information. [4 pts. ]

i) What sample size of school-aged children, aged 6-11 years should be obtained by CDC if they wish

to estimate the percentage to be within 3 percentage points with 90% confidence? [4 pts. ]

j) Assume that we have no prior information suggesting a possible value of the proportion of schoolaged children, aged 6-11 years who are overweight. What sample size should be used with 90%

confidence?

Answers

The proportion of school-aged children who are overweight is  108.

a) We are given that 21.4% of school-aged children aged 6-11 years are overweight.

The shape of the sampling proportion is approximately normal, i.e., the sampling distribution of the sample proportion can be approximated by a normal distribution since the sample size is greater than 30 (98 > 30).

b) Mean = µp = 21.4%

= 0.214

Standard deviation = σp

= sqrt [p(1 - p) / n]

= sqrt [(0.214)(1 - 0.214) / 98]

= 0.0456c)

In a random sample of 98 school-aged children, the probability that at least 23% are overweight is found using the formula:

z = (x - µ) / σp

= (0.23 - 0.214) / 0.0456

= 0.3509

Using the z-table, the probability that at least 23% are overweight is:

P(z > 0.3509) = 0.3632d)

A random sample of 98 school-aged children resulted in 20 overweight children.

The sample proportion is:

p = x / n = 20 / 98 = 0.204

The sample proportion (0.204) is close to the population proportion (0.214).

E = z(α/2) * sqrt [p(1 - p) / n]

= 1.96 * sqrt [(0.214)(1 - 0.214) / 98]

= 0.0929 ≈ 0.093f)

E = z(α/2) * sqrt [p(1 - p) / n]n

= [z(α/2) / E]2 * p(1 - p)

= [1.645 / 0.03]2 * 0.214(1 - 0.214)

= 763.05

≈ 764 (rounded up)j)

The sample size (n) that should be used with 90% confidence assuming no prior information suggesting a possible value of the proportion of school-aged children who are overweight is found using the formula:

n = [z(α/2) / E]2

= [1.645 / 0.05]2

= 107.18

≈ 108 (rounded up)

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If two coplanar lines are cut by _________ so that a pair of alternate interior angles are _,_____ then the two lines are parallel.

Answers

If two coplanar lines are cut by a transversal so that a pair of alternate interior angles are equal then the two lines are parallel.

The four sets of opposing angles that each have their own vertex point, are on different sides of the transversal and are both either internal or exterior are called alternate angles.

In geometry, a transversal line is one that cuts across the plane in two places. It does so at two spots where two lines meet. Many right angles are produced when two transverse lines meet. There are four types of similar angles: matching, alternative interior, alternate exterior, and co-interior.

In geometry, two lines are considered parallel if and only if all pairs of alternative interior angles in any transversal are equal.

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What is the equation in y=mx+b form that represents the function in the graph?

What is the equation in y=mx+b form that represents the function in the graph?

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

point 1 (0 , 0 ) x1 = 0 y1 = 0

point 2 (2 , -3) x2 = 2 y2 = -3

equation of the line = ?

Step 02:

Slope formula

\(m\text{ = }\frac{y2-y1}{x2-x1}=\frac{-3-0}{2-0}=\frac{-3}{2}\)

Slope-intercept form of the line

y = mx + b

b = y-intercept = 0

m = - 3/2

y = -3/2 x + 0

y = -3/2 x

The answer is:

y = -3/2 x

cynthia is in a bike race and her pace is currently 68 miles in 2 hours. if she keeps up the pace, about how many hours will she finish the race which is a total of 248 miles?

Answers

If Cynthia keeps up her pace, she will finish the 248-mile bike race in approximately 7.29 hours.

To determine how many hours Cynthia will finish the 248-mile bike race given her pace of 68 miles in 2 hours, follow these steps:

1. Calculate her speed by dividing the distance by the time:

speed = 68 miles / 2 hours

speed = 34 miles per hour.

2. Divide the total distance of the race (248 miles) by her speed (34 miles per hour) to find the time:

time = 248 miles / 34 miles per hour

time ≈ 7.29 hours.

Thus, we can state that if Cynthia keeps up her pace, she will finish the 248-mile bike race in approximately 7.29 hours.

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If (x+2,5)=(3y+2)find x and y​

Answers

Answer:

X = 7

Step-by-step explanation:

because of you do 5+2 = 7 then you minus 3 which you get 4.

the. if you have a production of around 10 you will get 7.

or you can do.

3+2 which is 5 and then you multiply that by 2 which is 10 and then you comprised that number therefore you will get 6 but you have to find X so we youndelie (think that's how u spell it) X which will equal to 1 and 6+1 is 7. once you get it it's quite simple

Please help me fast!

Please help me fast!

Answers

Answer:

150u+90

Step-by-step explanation:

..

Answer:

In (5u+3) 5 is a constant

Step-by-step explanation:

pls help, it is due now. Thank You so much to whoever helps!​

pls help, it is due now. Thank You so much to whoever helps!

Answers

Answer:

(7, -1)

Step-by-step explanation:

3x + 7y = 14

y = x - 8

3x + 7(x - 8) = 14

3x + 7x - 56 = 14

10x - 56 = 14

Add 56 to both sides.

10x = 70

Divide both sides by 10.

x = 7

3(7) + 7y = 14

21 + 7y = 14

Subtract 21 from both sides.

7y = -7

Divide both sides by 7.

y = -1

(7, -1)

Evaluate 7) + j - k when j = 2 and k = 1.

Answers

Answer:

i believe it's 8

Step-by-step explanation:

if the problem is 7+j-k

7+2-1

=8

hope this helps

please mark brainiest

What is the answe please help me

What is the answe please help me

Answers

Answer:

Opcion C

Step-by-step explanation:

I think Maybe it could be

The price of bronze has increased by 10% per year from 2000. In the year 2000, Harry brought a bronze medal for $120. Which of the following equations can be used to represent the price of the medal x years after 2000 ?

Answers

B 3.980
Explainable- just took this text .

What is the equation of the line that is parallel to the line y=2/3x−4/5 and passes through the point (−3,2)?
A. 2x−3y=−12
B. 3x+2y=4
C. 2x−3y=−6
D. 3x+2y=8

Answers

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

\(y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x-\cfrac{4}{5}\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\)

so we're really looking for the equation of a line whose slope is 2/3 and that it passes through (-3 , 2) in standard form

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

\((\stackrel{x_1}{-3}~,~\stackrel{y_1}{2})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{ \cfrac{2}{3}}(x-\stackrel{x_1}{(-3)}) \implies y -2= \cfrac{2}{3} (x +3)\)

\(\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-2)=3\left( \cfrac{2}{3} (x +3) \right)}\implies 3y-6=2(x+3)\implies 3y-6=2x+6 \\\\\\ 3y=2x+12\implies -2x+3y=12\implies {\Large \begin{array}{llll} 2x-3y=-12 \end{array}}\)

Find the product mentally.
(r - s)^2

A) r^2 - 2 rs + s^2
B) r^2 - rs + s^2
C) 2 r^2 - rs - s^2

Answers

Step-by-step explanation:

A is the answer to the question

A) r^2 - 2rs+s^2

...............................

A rectangular tile is 2 inches by 3 inches. What is the LEAST number of tiles that are needed to completely cover a square region 2 feet on each side?

Answers

We need at least 96 rectangular tiles of dimensions 2 inches by 3 inches to cover a square region that is 2 feet on each side.

First, we need to convert the dimensions of the square region from feet to inches. Since there are 12 inches in a foot, a square region that is 2 feet on each side would be 24 inches on each side (2 feet x 12 inches/foot = 24 inches).

To find the least number of tiles needed to cover the square region, we need to determine how many tiles can fit horizontally and vertically on the 24-inch side of the square.

Since the tiles are 2 inches by 3 inches, we can fit 12 tiles horizontally (24 inches ÷ 2 inches per tile = 12 tiles). Similarly, we can fit 8 tiles vertically (24 inches ÷ 3 inches per tile = 8 tiles).

Therefore, we need at least 12 x 8 = 96 tiles to completely cover the square region.

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what is the probability that you reach into the jar and randomly grab a quarter and then, without replacement, a nickel? express your answer as a fraction or a decimal number rounded to four decimal places.

Answers

0.688 will be the probability of getting a nickel from the jar.

Given,

Probability;-

Simply put, probability is the likelihood that something will occur. When we don't know how an event will turn out, we can discuss the likelihood or likelihood of several outcomes. Statistics is the study of events that follow a probability distribution.

Here,

The number of fortunate situations divided by the total number of coins would be the product between the probability of each occurrence and the likelihood of each event.

Therefore,

P(nickel) = 19/69

P(penny) = 17/68

That is,

P = 19/69 × 17/68

P = 323/4692

P = 0.0688

That is,

The probability of getting nickel from the jar is 0.06888

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In baseball, each time a player attempts to hit the ball, it is recorded. The ratio of hits compared to total attempts is their batting average. Each player on the team wants to have the highest batting average to help their team the most. For the season so far, Jana has hit the ball 12 times out of 15 attempts. Tasha has hit the ball 9 times out of 10 attempts. Which player has a ratio that means they have a better batting average?

Tasha, because she has the lowest ratio since 0.9 > 0.8
Tasha, because she has the highest ratio since 27 over 30 is greater than 24 over 30
Jana, because she has the lowest ratio since 0.9 > 0.8
Jana, because she has the highest ratio since 27 over 30 is greater than 24 over 30

Answers

Answer: Tasha

Step-by-step explanation:

9/10 = .900 avg

12/15 = .800 avg

If you standardize the ratios to 30, then:

27/30 = .900 avg

24/30 = .800 avg

find the area of the figure below, composed of a rectangle and semicircle. Round it to the nearest tenth.

find the area of the figure below, composed of a rectangle and semicircle. Round it to the nearest tenth.

Answers

Answer:

Step-by-step explanation:

radius of semicircle = 5

area of semicircle = πr² = 25π

area of rectangle = 10×14 = 140

total area = 140 + 25π ≅ 218.54 square units

Let’s think about another type of scenario. What if you were told that a bracelet requires 10 beads and 10 minutes to make while a necklace requires 20 beads and takes 40 minutes to make. The craftsman has 1000 beads to work with and he has 1600 minutes in which to work. If a bracelet costs $5 and a necklace costs $7.50, what is the maximum revenue that the craftsman can take in?


There are four inequalities in this situation. Let b be the number of bracelets made and n be the number of necklaces made. The system of inequalities for this situation is:

Answers

Hi, your question appears to be unclear. However, I inferred this to be a linear programming problem.

Answer:

$500

Step-by-step explanation:

To begin we need to state the system of inequalities for this situation (constraints):

For the number of available beads:  \(10b + 20n \leq 1000\) where b represents the number of bracelets made, and n represents the number of necklaces made.For the available time to make the jewelry: \(10b+40n\leq 1600\)\(b\geq 0\)\(n\geq 0\)

From the question, we note we are required to find the maximum revenue that the craftsman can take in. In other words, the optimization equation is \(5b+7.5n\) = maximum revenue (taking note that a bracelet costs $5 and a necklace costs $7.50)

Next, we are to plot the inequalities on a graph to determine the feasible region: Doing so should give us these main vertices: (0,0) (0,40) (40,30 (100,0).

By substituting the vertices into the optimization equation (replacing b, and n) we can determine which quantity gives the maximum revenue:

For (0,40) ⇒ 5(0) + 7.5(0) = $0

For (0,40) ⇒ 5(0) + 7.5 (40) = $300

For (40, 30) ⇒ 5(40) + 7.5 (30) = $425

For (100, 0) 5(100)+7.50(0) = $500

We notice that at point  (100, 0) we have a maximum revenue of $500.

Find the solution of this system of equations.
Separate the x- and y-values with a comma.
x = -10 + y
-16x – 2y = -2

Find the solution of this system of equations.Separate the x- and y-values with a comma.x = -10 + y-16x

Answers

16+ 44 so I =60 hdndmoaoaoajebdbvdjjssksk
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