Summarize the arguments both for and against allowing genetically altered meats into the United States.

Can u please help!?
:⊃

Answers

Answer 1

Answer:Through "gene escape" they can pass on to other members of the same species and perhaps other species. Genes introduced in GMOs are no exception, and interactions might occur at gene, cell, plant and ecosystem level. Problems could result if, for example, herbicide-resistance genes got into weeds. So far, research on this is inconclusive, with scientists divided - often bitterly. But there is scientific consensus that once widely released, recalling transgenes or foreign DNA sequences, whose safety is still subject to scientific debate, will not be feasible.

Explanation: i don't really know, don't come at me please


Related Questions

Five observable properties for separating mixtures are ______________, _______________, ______________, _____________, ______________.

Answers

Five observable properties for separating mixtures are particle size, colour, texture, shape, magnetic attraction.

Mixtures are compounds that are made up of two or more chemical compounds which are not linked to each other chemically. They can be easily separated.

The mixtures can be separated by properties like particle size, colour, density, shape, magnetic attraction.

Sieving can be used to separate compounds based on particle size. Chromatography can be used to separate compounds based on colour as each colour would have differences in properties. Flotation can be used to separate compounds based on density like oil in water. Centrifugation can be used to separate compounds based on shape. Magnetic separation can be used to separate metals from non-metal compounds in a mixture.

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A certain red light has a wavelength of 680 nm.
a. What is the frequency of the light?

Answers

A certain red light has a wavelength of 680 nm. then, The frequency of the light is 4.4×10^14 s^-1 .

Given,

A certain red light had a wavelength = 680nm

frequency is given by,

f =c/λ

where, f = frequency

c = speed of light = 3×10^8 m/s

λ = wavelength = 680nm

f = (3×10^8 ) /(680× 10^-9 )

f = 0.0044×10^17 = 4.4×10^14 s^-1

Hence, the frequency of the light is 4.4×10^14 s^-1 .

What is wavelength?

The distance between the two crests or troughs of the light wave is known as the wavelength of light. Using the Greek letter lambda (), it is identified. As a result, wavelength refers to the separation between one wave's crest or dip and the following wave.

The formula for wavelength is given by,

wavelength= speed of light /frequency

What is frequency?

According to the definition of frequency, it is the quantity of full wave cycles that pass a spot in a unit of time.

Hertz is the SI unit for frequency (Hz).

The number of full oscillations that any wave element makes in one unit of time is the frequency of a sinusoidal wave.

Frequency is in periodic motion; after going through a number of different situations or postures and then returning to its initial place, it has completed one cycle.

The reciprocal of a wave's period is equal to the wave's frequency.

The frequency mathematical expression is:

frequency = speed of light / wavelength

The length of time it takes for any string element to complete an oscillation is known as a wave's oscillation period.

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identify the conditions for a standard electrochemical cell. select one or more: pressure of 1 atm temperature of 298 k solution concentrations of 1 m pressure of 5 atm solute masses of 1 g temperature of 273 k

Answers

The conditions for a standard electrochemical cell. select one or more : pressure of 1 atm temperature of 298 k solution concentrations of 1 M.

The electrochemical cell is the cell that is capable of generating the electrical energy from the chemical reactions or by the use of the electrical energy to cause the chemical reaction. The conditions for a standard electrochemical cell. select one or more : pressure of 1 atm temperature of 298 k solution concentrations of 1 M.  

There are the two types of the electrochemical cells is as follows : the galvanic called the electrolytic cells. the galvanic cell is also called as the voltaic cell.

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Limewater is calcium hydroxide solution. In an experiment to find the concentration of calcium hydroxide in limewater, 25.0 cm³ of limewater needed 18.8 cm³ of 0.0400 mol/dm³ hydrochloric acid to neutralise it.
Ca(OH)₂(aq) + 2HCl(aq) → CaCl₂(aq) + 2H₂O(1)
Calculate the concentration of the calcium hydroxide in:
a mol/dm³
b g/dm³
(A: H= 1, O=16, Ca = 40)

Answers

To find the concentration of calcium hydroxide in limewater, we need to use the balanced chemical equation and stoichiometry to determine the number of moles of calcium hydroxide that reacted with the hydrochloric acid.

From the balanced equation, we can see that 1 mole of calcium hydroxide reacts with 2 moles of hydrochloric acid. Therefore, the number of moles of calcium hydroxide in the limewater is:

moles of Ca(OH)₂ = (0.0400 mol/dm³) × (18.8 cm³ / 1000 cm³) × (1/2) = 0.00376 mol

a) The concentration of calcium hydroxide in mol/dm³ is:

concentration of Ca(OH)₂ = moles of Ca(OH)₂ / volume of limewater in dm³

We are given the volume of limewater as 25.0 cm³, which is equivalent to 0.025 dm³. Therefore,

concentration of Ca(OH)₂ = 0.00376 mol / 0.025 dm³ = 0.150 mol/dm³

b) The molar mass of calcium hydroxide is:

Ca(OH)₂ = (1 × 40.08 g/mol) + (2 × 16.00 g/mol) + (2 × 1.01 g/mol) = 74.10 g/mol

To convert the concentration from mol/dm³ to g/dm³, we need to multiply by the molar mass. Therefore,

concentration of Ca(OH)₂ = 0.150 mol/dm³ × 74.10 g/mol = 11.1 g/dm³

So, the concentration of calcium hydroxide in limewater is 0.150 mol/dm³ or 11.1 g/dm³.
The balanced chemical equation for the reaction is:

Ca(OH)₂(aq) + 2HCl(aq) → CaCl₂(aq) + 2H₂O(l)

From the equation, we see that one mole of Ca(OH)₂ reacts with two moles of HCl.

a) We can use the given information to calculate the number of moles of HCl that reacted with the Ca(OH)₂ in the 25.0 cm³ of limewater:

Number of moles of HCl = concentration × volume
Number of moles of HCl = 0.0400 mol/dm³ × 18.8 cm³/1000 cm³
Number of moles of HCl = 0.000752 mol

Since two moles of HCl react with one mole of Ca(OH)₂, we have:

Number of moles of Ca(OH)₂ = 0.000752 mol / 2
Number of moles of Ca(OH)₂ = 0.000376 mol

The volume of the limewater used is 25.0 cm³, which is equivalent to 0.0250 dm³. Therefore, the concentration of calcium hydroxide in the limewater is:

Concentration of Ca(OH)₂ = number of moles / volume
Concentration of Ca(OH)₂ = 0.000376 mol / 0.0250 dm³
Concentration of Ca(OH)₂ = 0.015 mol/dm³

Therefore, the concentration of the calcium hydroxide in the limewater is 0.015 mol/dm³.

b) To calculate the concentration of Ca(OH)₂ in g/dm³, we need to use the molar mass of Ca(OH)₂:

Molar mass of Ca(OH)₂ = 1 × 40.08 g/mol (for Ca) + 2 × 16.00 g/mol (for O) + 2 × 1.01 g/mol (for H)
Molar mass of Ca(OH)₂ = 74.10 g/mol

The mass of Ca(OH)₂ in 25.0 cm³ of limewater can be calculated using the number of moles we previously calculated:

Mass of Ca(OH)₂ = number of moles × molar mass
Mass of Ca(OH)₂ = 0.000376 mol × 74.10 g/mol
Mass of Ca(OH)₂ = 0.0279 g

The volume of the limewater used is 25.0 cm³, which is equivalent to 0.0250 dm³. Therefore, the concentration of calcium hydroxide in the limewater in g/dm³ is:

Concentration of Ca(OH)₂ = mass / volume
Concentration of Ca(OH)₂ = 0.0279 g / 0.0250 dm³
Concentration of Ca(OH)₂ = 1.12 g/dm³

Therefore, the concentration of the calcium hydroxide in the limewater is 1.12 g/dm³

A chemical reaction is carried out in a closed container. the energy absorbed by the chemical reaction is 100 kj. What is the energy liberated from the air or the walls of the container?


A. 100 kJ

B. 50 kJ

C. 25 kJ

D. 75kJ

Answers

Answer:

Option A

Explanation:

The total heat absorbed during the chemical reaction is the total heat released by the surrounding.

Net change of heat is equal to zero

Hence, the energy liberated from the air or the walls of the containers would be equal to the energy absorbed by the chemical reactions is equal to 100 Kj

Thus, option A is correct

Dry ice changes from a solid to a gas in a process known as A. Melting B. Freezing C.sublimation

Answers

Answer:

c

Explanation:

solid to gas directly

1.

Archaeologists have discovered the legendary Golden Igloo of the Pribiloff Islands, a structure consisting of a

halfspherical shell with an inner diameter of 1.25 m and an out diameter of 1.45 m. What is the value of this antiquity,

given that gold currently sells for $1,263/ounce and has a density of 19.3 g/cm3? (Note that 1 ounce = 31.1034768 g)

Answers

Answer:

The value of the Golden Igloo is $227.4 million.

Explanation:

First, we need to find the inner and the outer volume of the half-spherical shell:

\( V_{i} = \frac{1}{2}*\frac{4}{3}\pi r_{i}^{3} \)

\( V_{o} = \frac{1}{2}*\frac{4}{3}\pi r_{o}^{3} \)

The total volume is given by:

\( V_{T} = V_{o} - V_{i} \)

Where:

\( V_{i} \): is the inner volume

\(r_{i}\): is the inner radius = 1.25/2 = 0.625 m

\( V_{o} \): is the outer volume

\(r_{o}\): is the outer radius = 1.45/2 = 0.725 m

Then, the total volume of the Igloo is:

\( V_{T} = \frac{2}{3}\pi r_{o}^{3} - \frac{2}{3}\pi r_{i}^{3} = \frac{2}{3}\pi [(0.725 m)^{3} - (0.625 m)^{3}] = 0.29 m^{3} \)

Now, by using the density we can find the mass of the Igloo:

\( m = 19.3 \frac{g}{cm^{3}}*0.29 m^{3}*\frac{(100 cm)^{3}}{1 m^{3}} = 5.60 \cdot 10^{6} g \)

Finally, the value (V) of the antiquity is:

\( V = \frac{\$ 1263}{oz}*5.60 \cdot 10^{6} g*\frac{1 oz}{31.1034768 g} = \$ 227.4 \cdot 10^{6} \)  

Therefore, the value of the Golden Igloo is $227.4 million.

I hope it helps you!  

Lana drew the diagram below to model asexual reproduction. Based on Lana's diagram, which statement explains the results of asexual reproduction? A. The offspring are not genetically identical to the parent, because each offspring receives only half of the chromosomes from a single parent. B. The offspring are not genetically identical to the parents, because two parents each contribute half of their chromosomes to each offspring. C. The offspring are genetically identical to the parent, because each offspring receives a complete copy of a single parent's chromosomes. D. The offspring are genetically identical to the parents, because two parents each contribute a complete copy of their chromosomes to each offspring.

Answers

Based on Lana's diagram, the correct statement that explains the results of asexual reproduction is C. The offspring are genetically identical to the parent, because each offspring receives a complete copy of a single parent's chromosomes.

What happens in asexual reproduction?

In the diagram, the parent cell divides into two identical daughter cells, each of which contains a complete copy of the parent cell's genetic material.

This type of reproduction, where a single parent produces offspring that are genetically identical to itself, is called asexual reproduction. It is the process by which many unicellular organisms, such as bacteria and some protists, reproduce.

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Please help How many moles of a gas sample are in 5.0 L container at 215 K and 342 kPa(The gas constant is 8.31 L kPa/mol K) Round your answer to one decimal place and enter the number only with no units.

Please help How many moles of a gas sample are in 5.0 L container at 215 K and 342 kPa(The gas constant

Answers

Answer

1.0 mol

Explanation

Given:

Volume, V = 5.0 L

Temperature, T = 215 K

Pressure, P = 342 kPa

The gas constant, R = 8.31 L kPa/mol K

What to find:

The number of moles of the gas sample.

Step-step-solution:

The number of moles of the gas can be determine using the ideal gas equation formula:

\(PV=nRT\)

Put the given values into the formula and calculate for n:

\(\begin{gathered} 342\times5.0=n\times8.31\times215 \\ 1710=1786.65n \\ \text{Divide both sides by 1786.65} \\ \frac{1710}{1786.65}=\frac{1786.65n}{1786.65} \\ n=0.9571\text{ mol} \\ To\text{ one decimal place,} \\ n=1.0\text{ mol} \end{gathered}\)

The number of moles of the gas sample is 1.0 mol.

calculate ∆s°rxn for the following reaction. the s° for each species is shown below the reaction. c2h2(g) h2(g) → c2h4(g) s°(j/mol⋅k) 200.9 130.7 219.3

Answers

The ∆s°rxn for the given reaction is -112.3 J/mol⋅K.

To calculate ∆s°rxn for the given reaction, we need to use the following formula:
∆s°rxn = Σs°(products) - Σs°(reactants)
Here, the reactants are C2H2(g) and H2(g), and the product is C2H4(g). The values of s° for each species are given as follows:
s°(C2H2) = 200.9 J/mol⋅K
s°(H2) = 130.7 J/mol⋅K
s°(C2H4) = 219.3 J/mol⋅K
Now, we can substitute these values into the formula and get:
∆s°rxn = [s°(C2H4)] - [s°(C2H2) + s°(H2)]
∆s°rxn = [219.3] - [200.9 + 130.7]
∆s°rxn = [219.3] - [331.6]
∆s°rxn = -112.3 J/mol⋅K

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A 0.5998 g sample of a new compound has been analyzed and found to contain the following masses of elements: carbon, 0.1565 g; hydrogen, 0.02627 g; oxygen, 0.4170 g. Calculate the empirical formula of the compound.

Answers

The empirical formula of the compound is CH2O.

To find the empirical formula of the compound, we need to determine the ratios of the atoms in the compound. To do this, we need to find the number of moles of each element present in the compound.

The molar mass of carbon is 12.01 g/mol, the molar mass of hydrogen is 1.008 g/mol, and the molar mass of oxygen is 16.00 g/mol. The number of moles of carbon in the sample is:0.1565 g × 1 mol/12.01 g ≈ 0.0130 mol. The number of moles of hydrogen in the sample is:0.02627 g × 1 mol/1.008 g ≈ 0.0261 molThe number of moles of oxygen in the sample is:

0.4170 g × 1 mol/16.00 g ≈ 0.0261 mol

Now that we know the number of moles of each element, we can determine the simplest whole number ratio of the elements in the compound. We can do this by dividing each number of moles by the smallest number of moles. In this case, the smallest number of moles is 0.0130 mol.

We get:

Carbon: 0.0130 mol ÷ 0.0130 mol = 1

Hydrogen: 0.0261 mol ÷ 0.0130 mol = 2

Oxygen: 0.0261 mol ÷ 0.0130 mol = 2

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manganese is a transition metal. consider the isotope: mn-59. how many protons are in an atom of mn-59 if the atom has a charge of 5?

Answers

The atomic number of an element represents the number of protons in an atom of that element. Since the isotope given is Mn-59, the atomic number of manganese (Mn) remains the same, which is 25.

If an atom of Mn-59 has a charge of +5, it means that it has lost 5 electrons. The number of protons in an atom is equal to its atomic number, and the number of electrons is equal to the number of protons in a neutral atom. Therefore, if the atom has lost 5 electrons, the number of protons remains the same, which is 25.

So, an atom of Mn-59 with a charge of +5 has 25 protons.

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The figure shows a tank with two immiscrble liquid is andar. The vacuum gauges hown indicates a reading of 17.17KPo Determire a) Absolut pressure at point [ b) Relative pressure atpoint F, with respect to the ain in the tank; that is, if said air were the environrent of the instrument of measurerest Patm =77.17[kpa​]g=81​ g=9.81[m(s2] Environmental temperatice: 20[∘C] δ=0.68δ=0.8​

Answers

a) The absolute pressure at point B cannot be determined based on the given information.

b) The relative pressure at point F, with respect to the air in the tank, is also indeterminable with the provided information.

a) The absolute pressure at point B cannot be determined because the information about the liquid levels or the densities of the liquids in the tank is not provided.

The absolute pressure depends on the height of the liquid column and the density of the liquid, which are missing from the given data. Without this information, it is not possible to calculate the absolute pressure at point B.

b) The relative pressure at point F, with respect to the air in the tank, is also indeterminable. To calculate the relative pressure, we need to know the absolute pressure at point F and subtract the atmospheric pressure.

However, the absolute pressure at point F is not given, so we cannot determine the relative pressure. Additionally, the value of atmospheric pressure (Patm) provided is not relevant to calculating the relative pressure at point F.

In order to determine the absolute pressure at point B or the relative pressure at point F, we would need additional information such as the liquid levels in the tank, the densities of the liquids, and possibly the atmospheric pressure at point F.

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The statement that energy cannot be created or destroyed is part of the law of____?

Answers

Law of conservation

Edg. 2023
Can't find the answer anywhere else

Edg. 2023Can't find the answer anywhere else

Answers

The temperature of the gas is 294.15 K and volume of the gas is 1.55 cm³.

How to calculate gas temperature and volume?

To calculate the temperature of gas in Kelvin, add 273.15 to the Celsius temperature:

Temperature of gas: 21°C + 273.15 = 294.15 K

To calculate the volume of the gas using the formula V = πr²h, first calculate the radius using the given information. The radius is given as 5 cm. Therefore:

r = 0.5 cm

The height of the column of gas is given as 6.2 cm. Therefore:

h = 6.2 cm

Now substitute these values into the formula:

V = πr²h

V = π(0.5 cm)²(6.2 cm)

V = π(0.25 cm²)(6.2 cm)

V = 1.55 cm³

Therefore, the volume of the gas at room temperature is approximately 1.55 cm³.

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Answer: 294.15 K and 1.55 cm³

Explanation:

:)

gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated naoh(aq). calculate the amount of ga(s) that can be deposited from a ga(iii) solution using a current of 0.560 a that flows for 70.0 min. mass:

Answers

The mass of gallium (Ga) that can be deposited is 1.96 grams.

Using Faraday's equation of electrolysis, which states that the mass of a substance deposited or liberated during electrolysis is directly proportional to the amount of electricity passing through the electrolyte, we may determine the mass of gallium that can be deposited from a Ga(III) solution.

First, we need to calculate the total charge (Q) passed through the electrolyte using the formula
Q = I × t,
where I is the current (0.560 A) and
t is the time(70.0 min × 60 s/min).

The next step is to divide the charge by Faraday's constant (F = 96,485 C/mol), which will give us the number of moles of electrons that were transported.

We will deposit one mole of gallium for every mole of electrons transported since gallium has a 3+ charge.

As a result, the amount of electrons transported and the amount of gallium deposited are equal.

The mass of gallium deposited is then calculated by dividing the number of moles of gallium by its molar mass (69.72 g/mol).

After performing the computations, we discover that 1.96 grammes of gallium can be deposited.

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What is the greenhouse effect?
The cooling of Earth due
to air pollution
The heating of a solid,
such as a rock
The warming of a planet
due to trapped radiation.

Answers

Answer:

the trapping of the sun's warmth in a planet's lower atmosphere, due to the greater transparency of the atmosphere to visible radiation from the sun than to infrared radiation emitted from the planet's surface.

Answer:

The warming of a planet due to trapped radiation.

Describe how innate behaviors and learned behaviors differ? If you tell me the answer i will give you a brainliest answer :)

Answers

Answer:

The difference between an innate behavior and a learned one is that innate behaviors are those an animal will engage in from birth without any intervention. Learned behavior is something an animal discovers through trial, error and observation.

Explanation:

what type of bonding is occuring in the compound below?​

what type of bonding is occuring in the compound below?

Answers

Answer:

D.Metallic

Explanation:

The metallic model is often characterized as a "sea of electrons". This is because the electrons delocalize from the ion's orbitals, allowing them to roam freely around the substance. This is what the model is showing.

If this helped, a brainliest would be greatly appreciated!

Remove the solvent using the square-tip Pasteur pipette filtration method. Rinse the crystals with approximately 0.5 mL of ice-cold water and remove the rinse with the Pasteur pipette. Scrape the wet crystals onto a piece of filter paper and allow them to dry before determining the weight and melting point. Before leaving the laboratory, Also record your partner's results in your laboratory notebook. Put your product in an appropriate container Neutralize the filtrate with 1 N your sulfuric acid to destroy any remaining reducing agent. Put the aqueous filtrate in the appropriate liquid waste container. Dispose of all contaminated Pasteur pipettes melting point and TLC capillaries, and TLC plates in the container for chemically contaminated laboratory debris. CHEMICAL SAFETY NOTE sulfuric acid is corrosive. if any solution containing sulfuric acid comes in contact with your skin, flush the affected area immediately with water for at least five minutes and have another student notify the instructor immediately. Discuss the fact that there is more than one possible stereoisomeric product from the reduction of (plusminus)-benzoin. Discuss the reduction of benzyl and identify the products that are possible from this reaction. Based on your and your partner's results, which product(s) was formed? If one product appeared to be favored, speculate as to why this was the case. Why did you need to make two mixed melting point determinations? Did these help you identify the major product? If so, explain how. Discuss and explain the similarities and differences between the reactions run in 2-propanol, methanol, and 95% ethanol.

Answers

Rinse the crystals with approximately 0.5 mL of ice-cold water and remove the rinse with the Pasteur pipette.

What are the major steps should be taken before leaving the laboratory?

Before leaving the laboratory, also record your partner's results in your laboratory notebook. Put your product in an appropriate container Neutralize the filtrate with 1 N your sulfuric acid to destroy any remaining reducing agent.

Put the aqueous filtrate in the appropriate liquid waste container. Dispose of all contaminated Pasteur pipettes melting point and TLC capillaries, and TLC plates in the container for chemically contaminated laboratory debris.

Therefore, Rinse the crystals with approximately 0.5 mL of ice-cold water and remove the rinse with the Pasteur pipette.

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Find the ClO− concentration of a mixture that is 0. 300 M in HF and 0. 150 M in HClO. Express your answer using 2 significant figures

Answers

The concentration of ClO⁻ in the mixture is 0.055 M, rounded to two significant figures, calculated with the help of equilibrium constant.

The reaction between HF and ClO⁻ is:

HF + ClO⁻ → HClO + F⁻

The equilibrium constant expression for this reaction is:

K = [HClO][F⁻]/[HF][ClO⁻]

We are given the initial concentrations of HF and HClO, but not the concentration of F⁻. However, since HF and HClO react to form F⁻, the concentration of F⁻ is equal to the concentration of HF that has reacted. Let x be the concentration of F⁻ and let y be the concentration of ClO⁻. Then, we have:

[HClO] = 0.150 M - x

[F⁻] = x

[HF] = 0.300 M - x

[ClO-] = y

Substituting these concentrations into the equilibrium constant expression, we get:

K = (0.150 - x)(x)/(0.300 - x)(y)

At equilibrium, the reaction quotient Q is equal to the equilibrium constant K. Therefore, we can set Q = K and solve for y:

K = Q = (0.150 - x)(x)/(0.300 - x)(y)

y = (0.150 - x)(x)/(0.300 - x) / K

We are not given a value for K, so we need to calculate it. The value of K for this reaction can be found in a chemistry reference book or online. According to the CRC Handbook of Chemistry and Physics, the value of K for this reaction is 3.5 x 10⁻⁴ at 25°C.

Substituting this value for K and x = [F⁻] into the equation for y, we get:

y = (0.150 - x)(x)/(0.300 - x) / K

y = (0.150 - x)(x)/(0.300 - x) / 3.5 x 10⁻⁴

y = 0.041 x/(0.300 - x)

Substituting the initial concentration of HF into the expression for x, we get:

x = [F⁻] = [HF] reacted = 0.300 M - 2x

Substituting this expression for x into the expression for y, we get:

y = 0.041(0.300 - 2x)/(0.300 - x)

y = 0.041(0.300 - 2(0.300 - x))/(0.300 - (0.300 - x))

y = 0.041(2x - 0.150)/x

Simplifying this expression, we get:

y = 0.0828 - 0.274x

Substituting the value of x = 0.100 M (which is half of the initial concentration of HF that has reacted), we get:

y = 0.0552.

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Answer the question - How many moles
of Ozare needed to combine with 8.5
moles of H2S?
5.6 moles of 02
12.6 moles of 02
8.4 moles of O2

Answers

Answer:

PRACTICE MULTIPLE CHOICE QUESTIONS FROM UNIT 10

1.) A cylinder is filled with 2.00 moles of nitrogen, 3.00 moles of argon, and 5.00 moles of helium. If

the gas mixture is at STP, what is the partial pressure of the argon?

(A) 152 torr (B) 228 torr (C) 380. torr (D) 760. torr

2.) Compared to the average kinetic energy of 1 mole of water at 0 oC, the average kinetic energy

of 1 mole of water at 298 K is

(A) the same, and the number of molecules is the same

(B) the same, but the number of molecules is greater

(C) greater, and the number of molecules is greater

(D) greater, but the number of molecules is the same

3.) If the pressure on a given mass of gas in a closed system is increased and the temperature

remains constant, the volume of the gas will

(A) decrease (B) increase (C) remain the same

4.) Which gas has approximately the same density as C2H6 at STP?

(A) NO (B) NH3 (C) H2S (D) SO2

5.) At a temperature of 273 K, a 400. milliliter gas

The number of moles of oxygen gas needed to combine with 8.5 moles of H₂S is equal to 12.6 moles. Therefore, option (B) is correct.

What is a mole?

A mole can be explained as the standard unit for measurement of a large number of quantities of atoms, ions, molecules, or other particular particles. The atomic mass can be expressed as the mass of the one mole of any element while molar mass is the mass of one mole of any compound.

The number of elementary units in 1 mole of a compound was found to be equal to 6.023 × 10 ²³ is called Avogadro’s constant.

Given, the reaction of hydrogen sulfide and oxygen can be represented as:

\(2H_2S + 3O_2 \longrightarrow 2H_2O +2SO_2\)

It means, 2 moles of hydrogen sulfide react with oxygen = 3 mol

8.5 moles of hydrogen sulfide reacts with oxygen = (3/2) × 8.5 = 12.7 mol

Therefore, 12.7 moles of oxygen gas are needed to combine with 8.5 moles of H₂S.

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I’ll really appreciate it if you help me out on this one .

Ill really appreciate it if you help me out on this one .

Answers

1.
-Water levels are dangerously high for wildlife and humans.
-Animals seem to be lost, like the cow and the sheep especially.

2.
-There are not many trees near the water, meaning less areas for wildlife to live.
-There is not much wildlife in general.

Inferences
1. The wildlife shown will move relocate and adapt to another area.
2. Industry — emissions are visible in top left— will continue to hurt the environment. CO2 emissions will increase.

Good luck!

A woman’s roommate borrowed her coat and was then involved in a crime that left textile evidence behind. Could investigators be able to distinguish between the woman involved in the crime and the owner of the coat?

Answers

Yes, hair samples, dna, dandruff,

Predict the major product for the reaction. The starting material is an alkene where carbon 1 has a cyclohexyl and methyl substituent, and carbon 2 has a methyl and hydrogen substituent. This reacts with C l 2 in the presence of ethanol. Draw the major product.

Answers

The major product of the reaction will be the 1,2-dichloroalkane .

The reaction is likely a halogenation reaction, where the alkene reacts with \(Cl_2\) in the presence of ethanol as a solvent. Specifically, the double bond in the starting material will undergo electrophilic addition to one of the chlorine atoms, forming a carbocation intermediate. This intermediate can then undergo a nucleophilic attack by the chloride ion, resulting in substitution of the original double bond with a new carbon-chlorine bond.

In this case, the major product of the reaction will be the 1,2-dichloroalkane, where both carbons of the original double bond have been replaced with chlorine atoms.  

The reaction can be represented as follows:

\(CH_3\)
  |
\(CH_3C\) -- \(CH(C_6H_1_1)Cl\) + \(Cl_2\) + EtOH → \(CH_3C\) --\(CH(C_6H_1_1)Cl_2\) + HCl + EtOH
  |
 H

Therefore, The cyclohexyl and methyl substituents on carbon 1 and the methyl and hydrogen substituents on carbon 2 will remain unchanged in the final product. Hence, the major product of the reaction will be the 1,2-dichloroalkane .

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what are the coefficients that will balance the skeleton equation​

Answers

Answer:

When the following equation is balanced, what is the coefficient for HCl? Mg(s) + HCl(aq) -> MgCl2(aq) + H2(g) . 2. What are the coefficients that will balance the skeleton equation below? AlCl3 + NaOH -> Al(OH)3 + NaCl.

Which of the following is an example of a behavioral trait that
is likely to increase reproductive success?
O colorful feathers
O a dance
O tail length

Answers

Answer:

The answer is option A

Colorful feathers

Hope this helps you

3. if the initial amount of radionuclide is 50 mci and the half-life is 75 days, what is the activity remaining after 200 days?

Answers

If the initial amount of radionuclide is 50 mci and the half-life is 75 days. Then, the activity remaining after 200 days is approximately 2.19515 mCi.

To determine the activity remaining after a certain time, we can use the radioactive decay equation;

A = A₀ × \((1/2)^{(t}\) / T₁/₂)

Where; A is the remaining activity after time t

A₀ is the initial activity

T₁/₂ is the half-life of the radionuclide

Given; A₀ = 50 mCi (millicuries)

T₁/₂ = 75 days

t = 200 days

Plugging in the values into the equation, we get;

A = 50 mCi × (1/2)²⁰⁰ / 75)

Calculating this expression, we find;

A ≈ 50 mCi × 0.043903

A ≈ 2.19515 mCi

Therefore, the activity remaining after 200 days will be 2.19515 mCi.

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Name the following ether: CHCH2OCH3

A. Diethyl ether B. Propanol
C. Dimethyl ether C. Ethyl Methyl Ether

Answers

Answer:

ethyl methyl ether

Explanation:

when naming ethers name the alkyl rings, in this case we have methyl and ethyl( make sure they are in alphabetical order) followed by the word ether, so it becomes ethyl methyl ether

2) If you
move 50 meters in 10 seconds, what is your velocity?

Answers

Answer:

5 meter/second.

Explanation:

You dived the seconds, 10, by the meters, 50.

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