-4y-1
Step-by-step explanation:
If you subtract \({ \green{ \tt{8y + 7}}} \)from \({ \red{ \tt{4y - 8}}}\) then the resultant answer will be as follows
\( \: \: \: \: \: { \red{ \tt{4y - 8}}} \\ - \ \: { \green{ \tt{8y + 7}}} \\ = -{ \blue{ \tt{ 4y - 1}}}\)
(a) (i) What conditions should be satisfied to use image averaging method for noise reduction? (ii) Using mathematical expressions, characterize the noise in the resultant image when K images are averaged, as K becomes large. (iii) Would you select spatial averaging or temporal image averaging when either method can be used for noise reduction? Explain your selection in detail.
(a)image averaging is a very effective method of reducing noise in images. Image averaging reduces noise by adding multiple images of the same scene together and then dividing by the number of images added.The conditions that must be fulfilled for the image averaging method are as follows:-
(i) The background of the image must not move between each image capture.- The noise present in the image must be random.- The source of the noise must be consistent.
(ii)The mathematical expression that characterizes the noise in the resultant image when K images are averaged, as K becomes large is given by;sigma_n^2/K
Where;sigma_n^2 is the variance of the noise and K is the number of images that have been averaged.
Therefore, as K increases, the variance of the noise in the resultant image reduces, and thus, the noise reduces.When either method can be used for noise reduction, the temporal image averaging method would be the preferred method to select.
(iii)This is because it uses a sequence of images that are taken at different times, usually at high speeds, to produce a single image that is free of noise. This method is best when dealing with fast-moving objects, and it can be used in situations where the camera cannot be stabilized and is experiencing unwanted vibration or shaking.
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3.Write the equation of a parabola with focus (-2, 4) and directrix y = 2. Show your work, including a sketch.
In this problem, we need to find the equation and the graph of a parabola given the focus and the directrix.
Sometimes it's best to start with graphing the given information to determine if the graph is a horizontal or vertical parabola. So, we'll have:
Since the focus is always inside the parabola and the directrix is outside the parabola, we know this will be a vertical parabola. Depending on the text, this standard formula may look different. For our purposes, the standard form of a vertical parabola is:
\((x-h)^2=4p(y-k)\)Where (h,k) is the vertex.
The vertex is typically the same distance from both the focus and the directrix, so we can find the distance between them and divide by 2.
The vertex will be at (-2,3):
Now we can substitute the vertex into our standard form knowing (h,k) = (-2, 3):
\(\begin{gathered} (x-(-2))^2=4p(y-3) \\ (x+2)^2=4p(y-3) \end{gathered}\)Next, we need to find the value of p for our equation.
P is the distance from the vertex to the focus. Since our vertex is at (-2,3) and our focus is at (-2,4), the difference between the y-values shows a distance of 1.
Since p=1,
\(\begin{gathered} (x+2)^2=4(1)(y-3) \\ (x+2)^2=4(y-3) \end{gathered}\)Our final graph is:
2. Polygon EFGH is a scaled copy of Polygon ABCD.
Name the segment in the scaled copy that
corresponds to segment AB.
1A
The name of the segment in the scaled copy that corresponds to segment AB is segment EF
How to name the segment in the scaled copy that corresponds to segment AB?The given parameters are:
Polygon EFGH is a scaled copy of Polygon ABCD.
This means that the corresponding points are
E = A
F = B
G = C
H = D
Remove points C and D
So, we have
E = A
F = B
Hence, the name of the segment in the scaled copy that corresponds to segment AB is segment EF
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Suppose that tan 0=-5/12 and 90° <0<180°.
Find the exact values of sin
0/2 and
tan
O/2
The exact values of sin θ/2 and tan θ/2 given below as:
sin θ/2 = 0.9806tan θ/2 = 4.99What is the exact values of sin θ/2 and tan θ/2 given that tan θ = -5/12?Given that tan θ = -5/12 and θ lies between 90° and 180°, the values of sin θ/2 and tan θ/2 can be found as follows:
tan θ = -5/12
θ = 180 -tan⁻¹-(5/12)
θ = 157.38
sin θ/2 = sin 157.38/2
sin θ/2 = 0.9806
tan θ/2 = tan 157.38/2
tan θ/2 = 4.99
In conclusion, the values of the sine and tangent are found from the given values.
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what is the perimeter of rhombus ABCD ?
Answer:
20
Step-by-step explanation:
Since you can use the Pythagorean theorem to calculate the length of the hypotenuse, each side can be found to be 5. There are four equal sides, so it is 20.
I need to know the transformation of the shape
Answer:
is there anything underneath it? it says which of the following
Step-by-step explanation:
ANSWER THIS QUESTION QUICKLY PLS!
A committee of five people is formed by selecting members from a list of 10 people.
How many different committees can be formed?
Enter your answer in the box.
Answer:
How much is 100×4 please
What is the vortex of the quadratic function fox (x-8)(x-2)?
Answer:
Vertex is (5,-9)
Step-by-step explanation:
Answer: The vertex is (5,-9).
Step-by-step explanation:
Emily says that the negative sign means opposite of, so -(-45) means the opposite of negative 45, which is 45. Is Emily correct?
Answer: Yes, No Submit ·
Step-by-step explanation:
How much time would it take for an airplane to reach its destination if it traveled at an average speed of 250 m/s for a distance of 500,000 meters?
Answer:
2000 seconds which is 33.33minutes
Step-by-step explanation:
PLEAZE HELPP 50 POINTS If the function f(x) =-3x3 +7x represents the movement of a whale in meters what is the average rate of change of the whale for x=1 and X=3 seconds label your answer
Answer:
The average rate of change of a function over an interval is found by taking the difference between the function's values at the endpoints of the interval and dividing by the length of the interval. In this case, we have:
f(1) = -3(1)^3 + 7(1) = -3 + 7 = 4
f(3) = -3(3)^3 + 7(3) = -27 + 21 = -6
The average rate of change over the interval from x=1 to x=3 is therefore (-6 - 4) / (3 - 1) = -10 / 2 = -5.
To label your answer, you could write something like: "The average rate of change of the whale's movement over the interval from x=1 to x=3 seconds is -5 meters/second."
The conversion of stored potential energy into kinetic energy can also be harnessed to power homes, factories and entire cities. Which example from the text supports this conclusion?
A the softball pitcher
B the slingshotting comet
C the archer
D the Hoover Dam
NO BOTS or SCAM PLS
HELP ASAP!!!! I need to do this quick.
Answer:
the domain will be \(x\neq -4\)
Step-by-step explanation:
(-inf, -4) U (--4, inf)
x<-4; x>-4
Which of the following relations doesnot represent a function?A {(4,4),(5,4), (6,4)}B {(4,4),(4,5),(4, 6)C {(4,5), (5,5), (6,5)}D {(4,4),(5,5), (6,6)}
In a set of ordered pairs,
To be considered a function, each x-value must be paired with a corresponding UNIQUE y-value.
We want to select the "relation" from the choices, not the function.
A. Represents a function. Each x value paired with unique y value.
B. Doesn't represent a function. "4" is paired up with mutliple values of y.
C. Represents a function. Each x value paired with unique y value.
D. Represents a function. Each x value paired with unique y value.
AnswerBThe only information you have about a certain function f[x] is:
-1 ≤ f[x] ≤ 1
for all the x's between -[infinity] and [infinity].
Is it possible for a plot of a partial expansion of f[x] to share ink with the plot of f[x] all the way from -[infinity] to + [infinity]?
Why?
Yes, it is possible for a plot of a partial expansion of f[x] to share ink with the plot of f[x] all the way from -[infinity] to + [infinity].
Explanation:
We can approximate f(x) as a Fourier series, as follows:
\($$f(x) = \sum_{n=0}^{\infty}a_n\cos\left(\frac{n\pi x}{L}\right)+\sum_{n=1}^{\infty}b_n\sin\left(\frac{n\pi x}{L}\right)$$\)
If f(x) is an odd function, the cosine terms are gone, and if f(x) is an even function, the sine terms are gone.
We can create an approximation for f(x) using only the first n terms of the Fourier series, as follows:
\($$f_n(x) = a_0 + \sum_{n=1}^{n}\left[a_n\cos\left(\frac{n\pi x}{L}\right)+b_n\sin\left(\frac{n\pi x}{L}\right)\right]$$\)
For any continuous function f(x), the Fourier series converges uniformly to f(x) on any finite interval, as given by the Weierstrass approximation theorem.
However, if f(x) is discontinuous, the Fourier series approximation does not converge uniformly.
Instead, it converges in the mean sense or the L2 sense. The L2 norm is defined as follows:
\($$\|f\|^2 = \int_{-L}^{L} |f(x)|^2 dx$$\)
Hence, it is possible for a plot of a partial expansion of f(x) to share ink with the plot of f(x) all the way from -[infinity] to + [infinity].
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HELP.................................................................
Answer:
A. \(\frac{1}{6^{2} }\)
Step-by-step explanation:
A. \(\frac{1}{6^{2} } = \frac{1}{36} = 0.02777\)
B. \(6^{-3} = 0.004629\)
C. \(\frac{1}{216} = 0.004629\)
D. \(\frac{1}{6^{3} } = \frac{1}{216} = 0.004629\)
Answer:
I think it is A because B or D is not it so I was left with A and C. So I am pretty sure that is A.
how would i solve number 60
Answer:
you would solve it by using the factoring method or the quadratic formula
Maddy works at Burgers R Us. Her boss tells her that if she stays with the company for five years, she will receive a bonus of $4,400.
With an annual discount rate of 8%, calculate the value today of receiving $4,400 in five years. (FV of $1, PV of $1, FVA of $1, and PVA of $1) (Use appropriate factor(s) from the tables provided. Round your answer to 2 decimal places.)
what will the present value be?
The present value of the $4,400 in five years at an annual discount rate of 8% would be $2,999.44.
Maddy's bonus of $4,400 would not be worth $4,400 in today's dollars because the value of money changes over time. In other words, money is worth more in the present than it is in the future. In finance, this principle is known as the time value of money.
As a result, we must determine the present value (PV) of Maddy's $4,400 bonus.
Future value (FV) = $4,400
Discount rate = 8%
Time period = 5 years
Present value (PV) = ?
We can use the PV of $1 table to determine the appropriate factor.
Using the table, we can find the PV factor for 5 years and 8% rate as 0.681.
So, the present value of $4,400 will be PV factor * FV i.e 0.681 * $4,400 = $2,999.44.
The present value of the $4,400 in five years at an annual discount rate of 8% would be $2,999.44.
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Based on the graph, how many distinct real number solutions does the equation x3 – 3x2 4 = 0 have? no real number solution one real number solution two real number solutions three real number solutions.
Answer:two real number solutions
Step-by-step explanation:
Mr. shaw graphs the function f(x) = –5x 2 for his class. the line contains the point (-2, 12). what is the point-slope form of the equation of the line he graphed? y – 12 = –5(x 2) y – 12 = 2(x 2) y 12 = 2(x – 2) y 12 = –5(x – 2)
Answer:
y - 12 = -5(x + 2)
Step-by-step explanation:
please help me
covert 2km to m
convert 3 decimeter to mm
covert 1km to cm
Answer:
2,000 m
300 mm
100,000 cm
Step-by-step explanation:
Answer:
2 km converted to meters is 2000 meters
3 decimeters converted to millimeters is 300 mm
1 km converted to centimeters is 100,000 centimeters
She selects 150 trees at random from her orchard and uses this fertilizer on those trees and estimates the following regression: Y
^
i
=600+4.93X i
, where Y
^
i
denotes the predicted number of apricots obtained from the I th tree and X i
denotes the number of units of fertilizer used on the I th tree. A. H 0
:β 1
≥5.14 and H 1
:β 1
<5.14. B. H 0
:β 1
>4.93 and H 1
:β 1
≤4.93. C. H 0
:β 1
=5.14 and H 1
:β 1
=5.14. D. H 0
:β 0
=4.93 and H 1
:β 0
=4.93. Suppose the standard error of the estimated slope is 0.74. The t-statistic associated with the test Wendy wishes to conduct is (Round your answer to two decimal places. Enter a minus sign if your answer is negative.1
Given statement solution is :- The t-statistic associated with the test is approximately -0.28.
The t-statistic, which is used in statistics, measures how far a parameter's estimated value deviates from its hypothesised value relative to its standard error. Through the Student's t-test, it is utilised in hypothesis testing. In a t-test, the t-statistic is used to decide whether to accept or reject the null hypothesis.
To find the t-statistic associated with the test, we need to calculate the test statistic using the estimated slope coefficient, the null hypothesis, and the standard error.
The estimated slope coefficient is 4.93.
The null hypothesis is H₀: β₁ ≥ 5.14 (stating that the true slope coefficient is greater than or equal to 5.14).
The predicted slope's standard error is 0.74.
The formula to calculate the t-statistic is:
t = (estimated slope - hypothesized slope) / standard error
Plugging in the values:
t = (4.93 - 5.14) / 0.74
t = -0.21 / 0.74
t ≈ -0.28 (rounded to two decimal places)
Therefore, the t-statistic associated with the test is approximately -0.28.
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in triangle ABC, AB = 6 cm, BC = 13cm and angle ACB = 23 degrees. Calculate angle BÁC, which is obtuse.
Answer:
\(\angle BAC=180^{\circ}-\frac{13\sin 23^{\circ}}{6}\)
Step-by-step explanation:
\(\frac{\sin(\angle BAC)}{13}=\frac{\sin 23^{\circ}}{6} \\ \\ \sin \angle BAC=\frac{13\sin 23^{\circ}}{6} \\ \\ \angle BAC=180^{\circ}-\frac{13\sin 23^{\circ}}{6}\)
Ye uhm help please :))))
Reggie plans to have a garden with 36 plants. He wants the ratio of tomato plants to cucumber plants to be 4:5. How many cucumber plants will be in Reggie's garden?
Answer:
20
Step-by-step explanation:
Total no of plants in a garden = 36
The ratio of tomato plants to cucumber plants to be 4:5.
Let tomato plants are 4x and cucumber plants is 5x.
ATQ,
4x+5x=36
9x = 36
x = 4
For cucumber plant, 5x = 5(4) = 20
So, there are 20 cucumber plants will be in Reggie's garden
the price of a videotape is $13.20 after a 40% discount. Whats the original price?
Answer:
$22
Step-by-step explanation:
So if a videotape was on a 40% discount, then the person who is buying it pays 60% of the original price (100 - 40 = 60)
call "x" the original price, then set up a proportion to explain the relationship
13.2/x = 60/100
simplify
13.2/x = 3/5
solve using cross products
13.2/x = 3/5
13.2 * 5 = 3 * x
66 = 3x
22=x
HW IS DUE SOON PLS HELP
Each day you do HW for "m" minutes and watch TV for 30 minutes. Write an expression that you can use to find out how many minutes you do both activities in 5 days. (pls use like terms to complete the equation thank you)
The expression for the time for which a person does both activities in 5 days is 5(m+30) minutes.
We have to write an expression that can help to find out the minutes for which a person does both the activities (homework and TV) each day. Let the time for which the person does homework each day be m minutes.
Therefore, the expression for time for which a person does both the activities each day is (m+30) minutes.To find out the time for which a person does both the activities for 5 days, we need to multiply the time for which the person does both the activities each day by 5.
Hence, the expression for the time for which a person does both activities in 5 days is:5(m+30) minutes
We have been given that each day, a person does homework for m minutes and watches TV for 30 minutes. We have to find an expression that can help to find out the minutes for which the person does both the activities each day.
Let us begin by defining variables. Let the time for which a person does homework each day be m minutes. Therefore, the expression for time for which a person does both the activities each day is (m+30) minutes.
Now we need to find the time for which the person does both activities in 5 days. To do so, we need to multiply the time for which the person does both the activities each day by 5.
Hence, the expression for the time for which a person does both activities in 5 days is:5(m+30) minutes.Now let’s consider an example to understand this better.Suppose the time for which a person does homework each day is 60 minutes.
Therefore, the expression for time for which a person does both the activities each day is (60+30) minutes = 90 minutes.
In this case, the time for which the person does both activities in 5 days is:
5(60+30) minutes = 5 x 90 minutes = 450 Minutes Therefore, in 5 days, a person will do both activities for 450 minutes.
The expression to find the minutes for which a person does both activities each day is (m+30) minutes. The expression for the time for which a person does both activities in 5 days is 5(m+30) minutes.
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A water balloon is thrown upward from a height of 5 feet with an initial velocity of 35 feet per second. The quadratic function \large h\left(t\right)=-16t^2+35t+5 represents the height of the balloon, h, in feet t seconds after it is thrown. When does the water balloon reach the height of 20 feet? round your answer to the nearest thousandth.
Since, The equation of the height with the time is provided and the balloon is thrown upwards against gravity from 5 feet, The answer is 0.255 sec.
What do you mean by equation?A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions. The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two equations 3x + 5 and 14, which are separated by the 'equal' sign.
What is initial and final velocity?When gravity first exerts force on an object, its initial velocity defines how quickly the object moves. The final velocity, on the other hand, is a vector number that gauges a moving body's speed and direction after it has reached its maximum acceleration.
initial height = 5
final height =20
height to travel =20-5 =15
\(15 = 16t^{2}+35t+5\\16t^{2}+35t-10 =0\)
solving we get, t = 0.255 or -2.44
since, -2.44 is not possible,
t = 0.255 seconds.
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Please Help me - You will get 60 points for the rapid reply- Use isosceles trapezoid ABCD to determine the following measurements-
Answer:
1) AD = 9 in
2) DE = 9.25 in
3) ∠EDC = 36°
4) ∠AEB = 108°
5) 11.5 in
Step-by-step explanation:
1) AD = BC = 9in
2) AC = BD (diagonals are equal)
⇒ BD = 14.25
⇒ BE + DE = 14.25
⇒ 5 + DE = 14.25
DE = 9.25
3) Since AB ║CD,
∠ABE = ∠EDC = 36°
4) ∠ABE = ∠BAE = 36°
Also ∠ABE + ∠BAE + ∠AEB = 180 (traingle ABE)
⇒ 36 + 36 + ∠AEB = 180
∠AEB = 108
5) midsegment = (AB + CD)/2
= (8 + 15)/2
11.5
How many solutions does the equation 5x + 3x − 4 = 10 + 8x have? (4 points)
a
No Solution
b
One
c
Two
d
Infinitely many
Step-by-step explanation:
\(5x + 3x - 4 = 10 + 8x \\ 8x - 4 = 10 + 8x \\ 8x - 8x = 10 + 4 \\ = 14\)
Since x has been eliminated (8x-8x = 0), there are no solutions in this equation.