Substantial objects, resembling asteroids in size and composition, which built up early in the development of the solar system are referred to as

Answers

Answer 1

Smaller planetesimals that never grew large enough to become planets are still present in the solar system today as asteroids, comets, and other minor bodies.

Substantial objects, resembling asteroids in size and composition, which built up early in the development of the solar system are referred to as planetesimals.What are planetesimals?Planetesimals are the building blocks of planets and they formed by the accumulation of dust and ice in the protoplanetary disk.

They are essentially small planetary objects that existed in the early stages of the formation of the solar system and were accumulated by the force of gravity into planets. They are thought to have been composed primarily of rock and metal, but could have also included ices such as water, methane, and ammonia.

The planetesimals in the early solar system collided and combined to form the planets we see today. The largest planetesimals eventually became protoplanets, which continued to grow through the accretion of smaller bodies until they became full-sized planets.

Asteroids, comets, and other tiny bodies are still found in the solar system today as smaller planetesimals that never grew big enough to become planets.

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Related Questions

What is the charge of an electron and charge of neutron

Answers

Answer:

The charge of a neutron is 0  

The charge of an electron is -1

Explanation:

Answer:

The charge of Neutrons is: 0

The charge of Electrons is: -1

Explanation:

Neutrons are uncharged and Electrons are negatively charged. The negative charge of one electron balances the positive charge of one proton. Both protons and neutrons have a mass of 1, while electrons have almost no mass.

Why capillary happen.

Answers

This doesn’t mark any sense

What is the direction of the magnetic force on this wire due to the magnet?.

Answers

To determine the direction of the magnetic force on a wire due to the magnet, you need to use the right-hand rule.

Hold your right hand with your thumb pointing in the direction of the current in the wire.

Then, curl your fingers around the wire in the direction of the magnetic field lines (from north to south).

The direction your fingers point is the direction of the magnetic force on the wire.

If the current is flowing downward in the wire and the magnetic field is pointing into the page, then the magnetic force on the wire would be to the left.

Conversely, if the current is flowing upward in the wire and the magnetic field is pointing into the page, then the magnetic force on the wire would be to the right.

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hiii please help i’ll give brainliest if you give a correct answer please thanks!

hiii please help ill give brainliest if you give a correct answer please thanks!

Answers

The tension force transmitted through the chains.

Answer:

I would say tension force the last one because the gravitational force brinsg it down more.

Explanation:

Dont mind if its wrong im sorry

A car with a mass of 1. 2 × 103 kilograms starts from rest and attains a speed of 20 meters/second in 5 seconds. What net force acted on the car to cause that acceleration? A. 3. 0 × 102 newtons B. 6. 0 × 102 newtons C. 1. 2 × 103 newtons D. 4. 8 × 103 newtons E. 1. 2 × 104 newtons.

Answers

Answer:

The formula for force according to Newton's second law of motion is F=ma or force for an object to move is equal to mass times acceleration.

Acceleration or average acceleration defined as change in velocity per time.

F=ma

F=1.2x10³kg*(20m/s)(1/5s)=4.8x10³  Newtons

Explanation:

fthat's not the answer then i'm sorry

Were people able to make weather predictions before thermometers and radar were invented?

1. yes

2. no

Answers

Answer:

Yes

Explanation:

I just guess

yes.

explanation: based on the appearance of clouds and optical phenomena such as haloes

A massless disk or radius R rotates about its fixed vertical axis of symmetry at a constant rate omega. A simple pendulum of length l and particle mass m is attached to a point on the edge of the disk. As generalized coordinates, let theta be the angle of the pendulum from the downward vertical, and let be the angle between the vertical plane of the pendulum and the vertical plane of the radial line from the center of the disk to the attachment point, where positive is in the same sense as omega. a) Find T_2, T_2 and T_0. b) Use Lagrange's equations to obtain the differential equations of motion. c) Assume R = l, omega_2 = g/2l, theta(0) = 0, theta(0) = 0. Find theta_max.

Answers

A pendulum of length l and mass m is attached to a massless disk of radius R rotating at constant rate omega. Lagrange's equations yield the differential equations of motion

Equations of motion

a) To solve this problem, we need to find the tension forces acting on the pendulum at its point of attachment to the rotating disk. There are two tension forces to consider:

\(T_0\), which is the tension force due to the weight of the pendulum and\(T_1\), which is the tension force due to the centripetal force acting on the pendulum as it rotates around the disk.

We can use the fact that the disk is massless to infer that there is no torque acting on the disk, and therefore the tension force \(T_2\) acting at the attachment point is constant.

To find \(T_0\), we can use the fact that the weight of the pendulum is mg and it acts downward, so \(T_0\) = \(mg $ cos \theta\).

To find \(T_1\), we can use the centripetal force equation \(F = ma = mRomega^2\),

where

a is the centripetal acceleration and R is the radius of the disk.

The centripetal acceleration can be found from the geometry of the problem as \(Romega^2sin \beta\),

where

beta is the angle between the radial line and the vertical plane of the pendulum.

Thus, we have \(F = mRomega^2sin \beta\), and the tension force \(T_1\) can be found by projecting this force onto the radial line, giving \(T_1\) = \(mRomega^2sin\beta cos \alpha\),

where

alpha is the angle between the radial line and the vertical plane of the disk.

Finally, we know that the net force acting on the pendulum must be zero in order for it to remain in equilibrium, so we have \(T_2 - T_0 - T_1 = 0\). Thus, \(T_2 = T_0 + T_1\).

b) The Lagrangian of the system can be written as the difference between the kinetic and potential energies:

\(L = T - V\)

where

\(T = 1/2 m (l^2 \omega_1^2 + 2 l R \omega_1 \omega_2 cos \beta + R^2 \omega_2^2)\)

\(V = m g l cos \theta\)

Here, \(\omega_1\) is the angular velocity of the pendulum about its own axis and \(\omega_2\) is the angular velocity of the disk.

The generalized coordinates are theta and beta, and their time derivatives are given by:

\(\theta = \omega_1\)

\(\beta = (l \omega_1 sin \beta) / (R cos \alpha)\)

Using Lagrange's equations, we obtain the following differential equations of motion:

\((m l^2 + m R^2) \theta + m R l \omega_2^2 sin \beta cos \beta - m g l sin \theta = 0\)\(l^2 m \omega_1 + m R l \beta cos \beta - m R l \beta^2 sin \beta + m g l sin \theta = 0\)

c) When \(R = l\) and \(\omega_2 = g/2l\), we have \(\beta = \omega_1\), and the Lagrangian simplifies to

\(L = 1/2 m l^2 (2 \omega_1^2 + \omega_2^2) - m g l cos \theta\)

The corresponding Lagrange's equations of motion are

\(l m \theta + m g sin \theta = 0\)\(l^2 m \omega_1 + g l \theta = 0\)

Using the small angle approximation, \(sin \theta ~ \theta and \omega_1 ~ - \omega_1\), the differential equation for theta can be written as

\(\theta + (g/l) \theta = 0\)

which has the solution

\(\theta(t) = A cos \sqrt{(g/l) t + B}\)

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What assumption is violated when a refracted sound wave is processed ?
a. waves travel directly to and from a reflector
b. sound travels at an average speed of 1.54 mm/us
c. sound travels in a straight line
d. the acoustic imaging plane is very thin

Answers

Option C is Correct. The assumption that is violated when a refracted sound wave is processed is that sound travels in a straight line. Refraction occurs when sound waves pass through a medium with varying densities, causing the path of the wave to bend. T

Means that the assumption that sound travels in a straight line is no longer valid when dealing with refracted sound waves.

The refractive index, also called the index of refraction, is a number that is determined by comparing the speeds of light in a vacuum with a medium with a higher density. The letter n or n' is most usually used to indicate the refractive index variable in mathematical computations and descriptive language.

The index of refraction makes a sound.

We calculate the index of refraction of a material for sound waves as the ratio of the speed of sound in the material to the speed of sound in the air.

The sound waves are reflected back when a bat's sound waves strike an object.

For echolocation, bats used sound reflection to detect the location of adjacent objects.

They also utilise it to gauge an object's size and shape.

Echolocation is the process by which bats utilise sound to pinpoint their location.

The bat projects the location of its targets by picking up the reflected sound.

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Calculate the gel/space ratio and theoretical strength of a sample of concrete made with 500 gram of cement with 0.5 water/cement ratio, on fully hydration and at 60 percent hydration?

Answers

In the case of fully hydrated concrete, the gel/space ratio would be 0.678 which can be calculated by using the formula.

The gel/space ratio of concrete refers to the ratio of the volume of the solid material (the gel) to the volume of the voids (the space) in the material.

Gel-space ratio = (0.657C)/(0.319C+Wo)

where C is the cement weight measured in grams

Wo is volume of water that is to be mixed

C = 600 gm is value given to us

W0 is product of Water-cement ratio and cement weight

= 0.65 * 600 = 390 ml

Therefore,

Gel-space ratio = (0.657 * 600)/(0.319*600+390) = 0.678

Therefore, gel/space ratio will be 0.678

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Answer:

Explanation:

To calculate the gel/space ratio and theoretical strength of a sample of concrete, we need additional information such as the density of the cement, the properties of the aggregate used, and the mix proportions of the concrete (including the amount of aggregate and water).

Without specific information, we cannot accurately calculate the gel/space ratio and theoretical strength. These parameters depend on various factors, including the type and quality of the cement, the aggregate grading, the water-cement ratio, and the curing conditions.

It is important to note that the gel/space ratio represents the ratio of the volume of cementitious gel (hydration product) to the total void space in the concrete mixture. The theoretical strength is influenced by the water-cement ratio, aggregate properties, curing conditions, and other factors.

To provide a meaningful calculation, please provide additional information about the specific mix design, including the properties of the aggregate and the density of the cement, as well as any other relevant details about the concrete mixture.

The velocity of a particle moving along the x axis is given for 1> 0 by v: = (32.0t - 2.00t^3) m/s,
where t is in s. What is the acceleration of the particle when (after t = 0) it achieves its maximum
displacement in the positive x direction?

Answers

The acceleration of the particle when it achieves its maximum displacement in the positive x-direction is 32 m/s²

To calculate the acceleration of the particle, we need to differentiate the expression for the velocity.

 

Given:

v = 32t-2t³

differentiate v with respect to t

dv/dt = a = 32+2(3)t²dv/dt = 32+6t²................... Equation 1

When the particle achieves its maximum displacement,

t = 0 s

Substitute these value of t into equation 1

dv/dt = 32+6(0²)dv/dt = 32 m/s²

Hence The acceleration of the particle when it achieves its maximum displacement in the positive x-direction is 32 m/s²

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Friends tell you that on a recent trip their average velocity was +20 m/s. Is it possible that at any time during their trip their velocity was -20 m/s? Explain, and give an example to justify your answer. PLEASE HELP

Answers

Answer: Yes. Please find the answer in the explanation.

Explanation:

Yes. Since velocity is a vector quantity, that is, it has both magnitude and direction.

If the displacements covered are not of the same direction, the velocity will not also of the same direction.

Take for instance, if the velocity in a positive is 40 m/s and velocity in the opposite direction is - 20 m/s . Then, the resultant velocity will be 40 - 20 = 20 m/s

Therefore,  it is possible that at any time during their trip their velocity was -20 m/s.

The moon revolves around Earth. The moon travels at a speed of about 1 km/s. What keeps the moon in orbit around Earth?

A.Nuclear Fusion
B.Gravity
C.Magnetism
D.Ocean Tides

Answers

Answer:

I know its not A or D so its B or C and the more logical answer would be B. gravity

Explanation:

which type of image is formed by convex lens on a screen?​

Answers

Answer:

The type of image formed on a screen by a convex lens is real, enlarged and inverted.

Explanation:

A lens can be defined as a transparent optical instrument that refracts rays of light to produce a real image.

Basically, there are two (2) main types of lens and these includes;

I. Diverging (concave) lens.

II. Converging (convex) lens.

A converging lens refers to a type of lens that typically causes parallel rays of light with respect to its principal axis to come to a focus (converge) and form a real image.

Basically, the type of image formed on a screen by a converging (convex) lens is real, enlarged and inverted because it is usually thick across the middle (causing rays of light to converge) but thin at the lower and upper edges.

A progressive wave equation is represented by y=Asin2π(0. 15t-0. 1x). Find the
period,
amplitude,
frequency,
wavelength,
velocity

Answers

Given that the progressive wave equation is represented by y=Asin2π(0.15t-0.1x). Let's find the period, amplitude, frequency, wavelength, and velocity.

The wave equation is represented by y=Asin2π(0.15t-0.1x). The standard wave equation can be written asy = Asin(kx-ωt + Φ)Where,k = wave numberω = angular frequencyΦ = phase angle for the given equation, k = 0.1 and ω = 0.15.Amplitude:

Amplitude = A = maximum displacement from the mean position.A = 1Frequency: Frequency is the number of complete oscillations made by a point on the wave in one second. It is denoted by f.f = ω/2πFrequency, f = 0.15/2π = 0.0238 HzPeriod: Period is the time taken by one complete oscillation.

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Q2: The RMS potential difference of an AC household outlet is 117 v.
a) What is the maximum potential difference across a lamp connected to the outlet?
b) If the RMS current through the lamp is 5.5 A, what is the lamp's maximum current?

Answers

Answer:

(a) 165.46 V

(b) 7.78 A

Explanation:

(a) From the question,

Vrms = V₀/√2...................... Equation 1

Where V₀ = maximum potential difference across a lamp connected to the outlet.

make V₀ the subject of the equation.

V₀ = √2(Vrms)............... Equation 2

Given: Vrms = 117 V.

Substitute into equation 2

V₀ = (√2)(117)

V₀ = 165.46 V.

(b) Similarly,

I₀ = √2(Irms)....................... Equation 3

Given: Irms = 5.5 A

Substitute into equation 3

I₀ = (√2)(5.5)

I₀ = 7.78 A.

when two bodies of different temperatures are in contact, what is the overall direction of heat transfer

Answers

When two bodies of different temperatures are in contact, heat transfers from the body with higher temperature to the body with lower temperature.

Heat transfer occurs due to the temperature difference between the two bodies. According to the second law of thermodynamics, heat naturally flows from regions of higher temperature to regions of lower temperature until thermal equilibrium is reached. This process is known as heat transfer by conduction.

Conduction is the transfer of heat through direct contact between the particles of the two bodies. The particles with higher thermal energy (higher temperature) transfer some of their energy to the particles with lower thermal energy (lower temperature), resulting in an overall transfer of heat from the hotter body to the colder body.

This heat transfer process continues until both bodies reach the same temperature, establishing thermal equilibrium. At this point, there is no net heat transfer between the bodies.

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Resolve the weight of the box to find the component of the weight acting parallel to the slope.
W = 50N
30

Resolve the weight of the box to find the component of the weight acting parallel to the slope.W = 50N30

Answers

Answer:

here's your answer below

Explanation:

sorry something went wrong

.

refers to a specific factor that has a range of possible values.
A(n)
A. hypothesis
B. method
C. variable
D. observation
Please select the best answer from the choices provided
Ο Α
0 в
OD

Answers

Answer:the real answer is c. Variable

Explanation:

I tried D and it was wrong:(

Answer:

c

Explanation:

got it right

How to survive zombie apocalypse?

Answers

All you really need is food and supplies and you good

Some sort of base either underground or really high in the air. Zombies are unintelligent so locking your doors and having a safe unreachable location will give you time to relax.

Wear protective gear when going out so that zombies cannot get you. Gas mask, armor, and a weapon to fight with are good.

Collect food, water, and oxgen in your base. Sharing is not caring and feel free to stock material in order to survive.

a ball is whirled on the end of a string with constant speed when the string breaks. which path will the ball take (assuming no gravity)?

Answers

When the string breaks, a ball is twirled at a consistent pace on the end of it. If the string snaps, the ball flies off in a straight line in the direction it was travelling when the string snapped.

What is Projectile motion?

A projectile is any object thrown into space with gravity serving as the only acting force. Gravity is the principal force acting on a projectile. This is not to say that other forces do not act on it; rather, their impact is limited when compared to gravity. A trajectory is the path that a projectile takes. A baseball that has been batted or thrown is an example of a projectile.

When a particle is hurled obliquely near the earth's surface, it proceeds along a curved route with constant acceleration towards the earth's centre (we assume the particle stays close to the earth's surface). The path of such a particle is referred to as a projectile, and the motion is referred to as projectile motion.

If the string snaps, the ball flies off in the direction it was travelling at the time the string snapped.

Newton's First Law

Newton's first law asserts that unless driven to alter its condition by the operation of an external force, every object will stay at rest or in uniform motion in a straight line. Inertia is the tendency to resist changes in a condition of motion.

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Draw a wave that has a wavelength of 3 cm and an amplitude of 1 cm. Label the wavelength, the amplitude, the rest position, and the crest and trough of your wave.

Answers

Answer:

Please find attached, the required wave drawn with MS Excel

Explanation:

Functions that represent waves is given as follows

A general form of the wave equation is A·sin(B·x) + D

Where;

B = 2·π/T

T = The period of the wave = 1/f

D = The vertical shift of the wave = 0

A = The amplitude of the wave = 1 for sine wave

v = The wave velocity

λ = The wavelength of the wave

f = The frequency of the wave

v = f·λ

At constant v, λ ∝ 1/f  

∴ λ ∝ T

Where T = 3, we have;

B = 2·π/T

∴ B = 2·π/3

Therefore, we have the wave with an amplitude of 1 cm, and wavelength, 3 cm, given as follows

y = sin((2·π/3)·x)

Plotting the above wave with MS Excel, we can get the attached wave

Draw a wave that has a wavelength of 3 cm and an amplitude of 1 cm. Label the wavelength, the amplitude,

How does temperature affect Brownian motion

Answers

Answer:

Explanation:

Temperature is the measure of average kinetic energy or energy in motion in a molecules. Brownian motion measure kinetic energy or how energetic the motion is and it is proportional to temperature.

Therefore, an increase in Temperature will bring about increase in kinetic energy of brownian motion. It will speed it up.

I NEED THIS ANSWER QUICK!

About how much precipitation in the water cycle occurs over the ocean?
A) 15 percent
B) 50 percent
C) 78 percent
D) 100 percent

Answers

Answer:

Hello, I'm here to help you.

↬ 78%

Explanation:

↬ Think that about 70% of the area of the earth is covered by the ocean.

↬ So the precipitation that falls on it is a smiliar percentage.

How much time does it take a car travelling south at 12 m/s to increase its velocity to 26 m/s south if it accelerates at 3.5 m/s south? Show the equation used and all steps. 9. The acceleration of a freely falling object (near Earth), when we assume no air resistance, is (remember units). 10. The assumption of no air resistance is never totally true, but is often close enough to make pretty accurate calculations. Discuss cases where this is a really good assumption and when it isn't. 11. A stone is dropped from a cliff. What is it's velocity after 1 second? After 2 seconds? 12. A ball is thrown straight up into the air at 14 m/s. How long does it take for the ball to slow down to an upward velocity of 6.0 m's? Show the equation used and all steps. 13. If you throw a rock up into the air, when is its velocity zero? What is the acceleration when the velocity is zero? 14. A rock is thrown downwards with an initial velocity of 8.0 m's. What is the velocity of the rock after 1.5 s?

Answers

The velocity of the rock after 1.5 seconds is 22.7 m/s downward. It takes 4 seconds for the car to increase its velocity from 12 m/s to 26 m/s while accelerating at 3.5 m/s^2 south.

a) To determine the time it takes for the car to increase its velocity, we can use the equation:

v = u + at

Where:

v = final velocity (26 m/s)

u = initial velocity (12 m/s)

a = acceleration (3.5 m/s^2)

t = time

Rearranging the equation to solve for time:

t = (v - u) / a

Substituting the given values:

t = (26 m/s - 12 m/s) / 3.5 m/s^2

t = 14 m/s / 3.5 m/s^2

t = 4 seconds

Therefore, it takes 4 seconds for the car to increase its velocity from 12 m/s to 26 m/s while accelerating at 3.5 m/s^2 south.

b) The acceleration of a freely falling object near Earth, assuming no air resistance, is approximately 9.8 m/s^2 downward. This value is often denoted as "g" and represents the acceleration due to gravity.

c) The assumption of no air resistance is a good approximation in cases where the object's motion is not significantly affected by air resistance. This is typically true for objects with small surface areas or objects moving at low speeds. For example, when studying the motion of objects like baseballs, rocks, or projectiles in vacuum-like conditions, the assumption of no air resistance can be reasonably accurate.

However, in cases where the object has a large surface area or is moving at high speeds, air resistance becomes significant and cannot be ignored. Examples include objects like parachutes, airplanes, or objects falling through the atmosphere. In such cases, the assumption of no air resistance would lead to inaccurate calculations.

d) When a stone is dropped from a cliff, its velocity after 1 second can be determined using the equation:

v = u + gt

Where:

v = final velocity

u = initial velocity (0 m/s as it is dropped)

g = acceleration due to gravity (approximately 9.8 m/s^2)

t = time (1 second)

Substituting the values:

v = 0 m/s + 9.8 m/s^2 * 1 s

v = 9.8 m/s

Therefore, the stone's velocity after 1 second of free fall is 9.8 m/s downward.

To calculate the velocity after 2 seconds, we use the same equation with a time of 2 seconds:

v = 0 m/s + 9.8 m/s^2 * 2 s

v = 19.6 m/s

Thus, the stone's velocity after 2 seconds of free fall is 19.6 m/s downward.

e) To find the time it takes for the ball to slow down to an upward velocity of 6.0 m/s, we can use the equation:

v = u + gt

Where:

v = final velocity (6.0 m/s)

u = initial velocity (14 m/s)

g = acceleration due to gravity (-9.8 m/s^2, negative since the ball is moving upward against gravity)

t = time

Rearranging the equation to solve for time:

t = (v - u) / g

Substituting the given values:

t = (6.0 m/s - 14 m/s) / -9.8 m/s^2

t = -8.0 m/s / -9.8 m/s^2

t ≈ 0.82 seconds

Therefore, it takes approximately 0.82 seconds for the ball to slow down to an upward velocity of 6.0 m/s.

f) The velocity of a rock thrown up into

the air is zero at its maximum height. This occurs when the rock reaches the highest point of its trajectory and begins to fall back down. At that moment, the rock's velocity changes from positive (upward) to negative (downward).

When the velocity is zero, the acceleration is equal to the acceleration due to gravity, which is approximately 9.8 m/s^2 downward near the Earth's surface. The negative sign indicates that the acceleration is in the opposite direction of the initial upward motion.

g) Given that the rock is thrown downwards with an initial velocity of 8.0 m/s, we can use the equation:

v = u + gt

Where:

v = final velocity

u = initial velocity (8.0 m/s)

g = acceleration due to gravity (9.8 m/s^2)

t = time (1.5 s)

Substituting the values:

v = 8.0 m/s + (9.8 m/s^2) * (1.5 s)

v = 8.0 m/s + 14.7 m/s

v = 22.7 m/s

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The speed of light is around 3.000E5 km/s. It takes approximately 9.221 seconds for light reflected from the moon Vega to reach planet Xartan. What is the average distance from the moon Vega to the planet Xartan?

Answers

Answer:

\(d=2.77\cdot 10^6\ Km\)

Explanation:

Speed

The speed is calculated as the ratio of the distance d by the time t:

\(\displaystyle v=\frac{d}{t}\)

If we need to calculate the distance, the equation is solved for d:

d=v*t

The speed of light is

\(v=3\cdot 10^5\ Km/s\)

It takes t=9.221 seconds for light reflected from the moon Vega to reach planet Xartan.

We can calculate the average distance the light traveled:

\(d=3\cdot 10^5\ Km/s*9.221\)

\(d=2,766,300\ Km\)

Or, in scientific notation:

\(\mathbf{d=2.77\cdot 10^6\ Km}\)

Liquid/vapor saturation pressure Psat Psat is often represented as a function of temperature by the Antoine equation, which can be written in the form: log⁡10Psat/(torr)=a−bt/∘C+clog10​Psat/(torr)=a−t/∘C+cb​ Here, parameters a, b, and c are substance-specific constants. Suppose this equation is to be rewritten in the equivalent form: ln⁡Psat⁡/kPa=A−BT/K+ClnPsat/kPa=A−T/K+CB​ Show how the parameters in the two equations are related.

Answers

The two equations' parameters have the following relationships: A = a, B = -b / c*ln(10), and C = c*log10(kPa/torr). In general, a parameter is any feature that aids in describing or categorising a certain system.

By utilising logarithmic conversions, it is possible to determine the connection between the parameters in the two versions of the Antoine equation. The following formula connects the natural logarithm (ln) with log base 10 (log10): Log10(x) = ln(x) / log10 (e)

where e is the natural logarithm's base. This formula may be used to change the log10 term in the first equation into a natural logarithm term.

The units must then be changed from torr to kPa. The pressure in kPa may be calculated by multiplying the torr pressure by 0.13332.

Finally, the terms in the equation can be rearranged to relate the parameters. The equation that results looks like this:

a - (b / c) = ln(Psat / kPa). b / c * log10(torr) + c * log10(kPa / torr) = ln(10)

A = a, B = -b / c*ln(10), and C = c*log10(kPa/torr), respectively. This demonstrates the relationships between the parameters in the two versions of the Antoine equation.

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If a dog ran at 5 m/s how far would it run in 45 s

Answers

Answer:

225 m//s

Explanation:

It ran 5m/s so 5x45=225

Answer:

225 meters

Explanation:

If it is running 5 meters per seconds, and it ran 45 seconds, you would need to multiple the seconds it ran by the speed per second: 5 • 45

5 • 45 = 225

What units are used to measure the magnitude of a vector?
-Grams
-Newtons
-Liters
-Pounds

Answers

Answer:

Newtons

Explanation:

Its units are newtons because force has both magnitude and direction.

4) A 3.0 uF capacitor and 6.0 uF capacitor are connected is series and the combination is connected in parallel with an 8.0 uF capacitor. What is the equivalent capacitor of this combination

Answers

The 3.0 uF and 6.0 uF capacitors in series can be combined using the formula 1/Ceq = 1/C1 + 1/C2, where C1 and C2 are the capacitance values of the two capacitors. Thus, 1/Ceq = 1/3.0 + 1/6.0 = 0.5. Solving for Ceq, we get Ceq = 2.0 uF.

The 2.0 uF equivalent capacitor and the 8.0 uF capacitor are connected in parallel, so their capacitances add up. Thus, the equivalent capacitance of the entire combination is 2.0 uF + 8.0 uF = 10.0 uF.

In summary, the equivalent capacitance of the combination of a 3.0 uF capacitor and a 6.0 uF capacitor connected in series, which are then connected in parallel with an 8.0 uF capacitor, is 10.0 uF.

Step 1: Find the equivalent capacitance of the series capacitors (3.0 uF and 6.0 uF)
Use the formula: 1/C_eq_series = 1/C1 + 1/C2
1/C_eq_series = 1/3.0 + 1/6.0
1/C_eq_series = (6.0 + 3.0) / (3.0 * 6.0)
1/C_eq_series = 9.0 / 18.0
C_eq_series = 18.0 / 9.0
C_eq_series = 2.0 uF

Step 2: Find the equivalent capacitance of the parallel combination (2.0 uF and 8.0 uF)
Use the formula: C_eq_parallel = C1 + C2
C_eq_parallel = 2.0 + 8.0
C_eq_parallel = 10.0 uF

So, the equivalent capacitance of this combination is 10.0 uF.

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How can an object move with respect to an observer so that the sound from it is not shifted in frequency?

Answers

For an object's sound to not be shifted in frequency, the object must be either stationary or moving directly towards or away from the observer at a constant speed.

The Doppler effect causes a change in the perceived frequency of the sound waves received by the observer, which can make the sound appear higher or lower in pitch depending on the direction of the relative motion.

To ensure that the sound from an object is not shifted in frequency, the object and the observer must have no relative motion with respect to each other. This means that the object must either be stationary with respect to the observer or moving directly towards or away from the observer at a constant speed.

If the object is moving towards the observer, the frequency of the sound waves will appear higher than the original frequency, but if the object is moving away from the observer, the frequency of the sound waves will appear lower than the original frequency

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